If a projectile is fired with an initial speed of vo ft/s at an angle α above the horizontal, then its position after t seconds is given by the parametric equations x=(v0cos(α))t andy=(v0sin(α))t−16t2
(where x and y are measured in feet).
Suppose a gun fires a bullet into the air with an Initial speed of 2048 ft/s at an angle of 30 o to the horizontal.
(a) After how many seconds will the bullet hit the ground?
(b) How far from the gun will the bullet hit the ground? (Round your answer to one decimal place.)
(c) What is the maximum height attained by the bullet? (Round your answer to one decimal place.)

Answers

Answer 1

Answer:

a) The bullet hits the ground after 64 seconds.

b) The bullet hits the ground 113,511.7 feet away.

c) The maximum height attained by the bullet is of 16,384 feet.

Step-by-step explanation:

Equations of motion:

The equations of motion for the bullet are:

[tex]x(t) = (v_0\cos{\alpha})t[/tex]

[tex]y(t) = (v_0\sin{\alpha})t - 16t^2[/tex]

In which [tex]v_0[/tex] is the initial speed and [tex]\alpha[/tex] is the angle.

Initial speed of 2048 ft/s at an angle of 30o to the horizontal.

This means that [tex]v_0 = 2048, \alpha = 30[/tex].

So

[tex]x(t) = (v_0\cos{\alpha})t = (2048\cos{30})t = 1773.62t[/tex]

[tex]y(t) = (v_0\sin{\alpha})t - 16t^2 = (2048\sin{30})t - 16t^2 = 1024t - 16t^2[/tex]

(a) After how many seconds will the bullet hit the ground?

It hits the ground when [tex]y(t) = 0[/tex]. So

[tex]1024t - 16t^2 = 0[/tex]

[tex]16t^2 - 1024t = 0[/tex]

[tex]16t(t - 64) = 0[/tex]

16t = 0 -> t = 0 or t - 64 = 0 -> t = 64

The bullet hits the ground after 64 seconds.

(b) How far from the gun will the bullet hit the ground?

This is the horizontal distance, that is, the x value, x(64).

[tex]x(64) = 1773.62(64) = 113511.7[/tex]

The bullet hits the ground 113,511.7 feet away.

(c) What is the maximum height attained by the bullet?

This is the value of y when it's derivative is 0.

We have that:

[tex]y^{\prime}(t) = 1024 - 32t[/tex]

[tex]1024 - 32t = 0[/tex]

[tex]32t = 1024[/tex]

[tex]t = \frac{1024}{32} = 32[/tex]

At this instant, the height is:

[tex]y(32) = 1024(32) - 16(32)^2 = 16384[/tex]

The maximum height attained by the bullet is of 16,384 feet.


Related Questions

If the domain of a function that is reflected over the x-axis is (1, 5), (2, 1), (-1, -7), what is the range?
A. (1, -5), (2, -1), (-1, 7)

B. (5, 1), (1, 2), (-7, -1)

C. (-5, -1), (-1, -2), (7, 1)

D. (-1, 5), (-2, 1), (1, -7)

Answers

Answer:

A. (1, -5), (2, -1), (-1, 7)

Step-by-step explanation:

Reflecting a function over the x-axis:

When a function is reflected over the x-axis, the x-value stays the same, while y changes the signal, so the transformation rule is:

[tex](x,y) \rightarrow (x,-y)[/tex]

To find the range:

We apply the transformation to the points in the domain. Thus:

[tex](1,5) \rightarrow (1,-5)[/tex]

[tex](2,1) \rightarrow (2,-1)[/tex]

[tex](-1,-7) \rightarrow (-1,-(-7)) = (-1, 7)[/tex]

Thus the correct answer is given by option a.

Answer:

It is letter A and please give me brainliest

Step-by-step explanation:

Will give brainliest answer

Answers

Answer:

the x-intercepts are at

x = -3

x = 0

x = 1

Step-by-step explanation:

ask the points, where the functional value is 0.

2x³ + 4x² - 6x = 0

we see that every term contains an expression of x. so, we can simplify this

x × (2x² + 4x - 6) = 0

so, one solution is plainly visible : x=0

for the other solutions we need to solve the square equation

2x² + 4x - 6 = 0

or even simpler

x² + 2x - 3 = 0

the solution of a square equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a=1

b=2

c=-3

x = (-2 ± sqrt(2² - 4×1×-3))/(2×1) = (-2 ± sqrt(4 + 12))/2 =

= (-2 ± sqrt(16))/2 = (-2 ± 4)/2 = -1 ± 2

x1 = -1 + 2 = 1

x2 = -1 - 2 = -3

A company decides to drain the water heater to flush out sediments. The water heater has a capacity of 500 gallons. It drains 100 gallons in 20 minutes. After 20 minutes, they open another drain valve and it drains 200 gallons in the next 20 minutes. The drain valves are closed for 10 minutes, while the workers take a break and then the water heater is drained until the water heater is completely empty.

What are the domain and the range of this relation?

Answers

Answer:

≤ y ≤ 70 and 0 ≤ x ≤ 500

Step-by-step explanation:

In this relation we have two things to analyze, the number of gallons of water in the heater, that is 500 gallons, and the time that it took to empty the heater.

Let's count the time.

First, there are 20 minutes in wich 100 gallons are drained.

then, another drain valve is opened, so in 20 minutes they drain 200 gallons of water.

now, the wait for 10 minutes.

Now there are 200 gallons remaining, so the workers must wait for the other 20 minutes to drain the 200 gallons remaining.

The total amount of time is 70 minutes.

So if we have a relationship of water in the heater vs time, where X is the water remaining and Y is the time, the correct domains are:

Y from 0 minutes to 70 minutes

X from 0 gallons to 500 gallons  

So the correct options are C and E.

0 ≤ y ≤ 70 and 0 ≤ x ≤ 500

For an analysis of variance comparing three treatment means, H0 states that all three population means are the same and H1 states that all three population means are different.
A. True
B. False

Answers

Answer:

False

Step-by-step explanation:

The analysis of variance may be described as an hypothesis test which is used to make comparison between variables of two or more independent groups. The null hypothesis is always of the notion that there is no difference in the means. While the alternative hypothesis is the opposite, for two independent groups, the alternative hypothesis is that both means are different, or not equal or not the same. However. When we have more than 2 independent groups, then the alternative hypothesis is stated as : 'the means are not all equal'. This means that the means of each group does not all have to be different, but the mean of one group may be different from that of the other groups or the mean of two groups are different from the other groups and so on.

???????????????????????????

Answers

Answer:

y-(-20)=1(x-(-10))

Step-by-step explanation:

If you're really in college you should know this, but here's the explanation:

m= -9-(-20)

      1-(-10)

  = 11

     11

m = 1

The equation is y-y^1=m(x-x^1)

Replace the y^1, m, and x^1 from the first point

You get y-(-20)=1(x-(-10))

Or simplify that into y+20=x+10

You can also simplify it more but I don't think you need that for that question

i’ll give brainliest to right answer please hurry

Answers

Answer:

Scientific notation uses exponential notation. When a number is written in scientific notation, the exponent tells you if the term is a large or a small number. A positive exponent indicates a large number and a negative exponent indicates a small number that is between 0 and 1.

Answer:

Look at the exponitial factor. If it is like 10^2 or like 10^10 the number is very big because it is raised to a very big power. Oppisitely, when it is rasied to a negative number, the number producted will have many decimal places. For example 10^-1 is literaly 0.1.

Step-by-step explanation:

Yes I got u

If m and n are positive integers and m^2 - n^2 = 9, which of the following could be the value of
n?
A) 1
B) 16
C) 9
D) 4

Answers

Answer:

4

Problem:

If m and n are positive integers and m^2 - n^2 = 9, which of the following could be the value of

n?

A) 1

B) 16

C) 9

D) 4

Step-by-step explanation:

One approach would be to plug in the choices and see.

If n=1, then we have m^2-1=9.

This would give m^2=10 after adding 1 on both sides. There is no integer m when squared would give us 10. ( Square root of 9 is a decimal )

If n=16, then we would have m^2-256=9.

This would give m^2=265 after adding 256 on both sides. There is no integer m when squared would give us 265. ( Square root of 265 is a decimal )

If n=9, then we would have m^2-81=9.

This would give m^2=90 after adding 81 on both sides. There is no integer m when squared would give us 90. ( Square root of 90 is a decimal )

If n=4, then we would have m^2-16=9.

This would give m^2=25 after adding 16 on both sides. There is an integer m when squared would give us 25. ( Square root of 25 is a 5)

convert 65 kg into gram .​

Answers

Answer:

65000

Step-by-step explanation:

65x 1000

1000 because 1kg= 1000

Cathy is planning to take the Certified Public Accountant Examination (CPA exam). Records kept by the college of business from which she graduated indicate that 73% of students who graduated pass the CPA exam. Assume that the exam is changed each time it is given. Let n = 1, 2, 3, ... represent the number of times a person takes the CPA test until the first pass. (Assume the trials are independent).
(a) What is the probability that Cathy passes the CPA test on the first try?
(b) What is the probability that Cathy passes the CPA test on the second or third try?

Answers

Answer:

The responses to these question can be defined as follows:

Step-by-step explanation:

For point a:

[tex]\to P(1) = 0.73[/tex]

For point b:

[tex]\to P(2\ or\ 3) = P(2) + P(3)[/tex]

                    [tex]= 0.27 \times 0.73 + 0.27\times 0.27\times0.73\\\\=0.1971+0.1971\times 0.27\\\\=0.1971+0.053217\\\\=0.250317[/tex]

______are used to represent an unknown quantity in a mathematical expression.

Answers

Answer:

Variables are used to represent an unknown quantity in a mathematical expression.

Step-by-step explanation:

Variables are used to represent an unknown quantity in a mathematical expression.For example : x + 2 = 4, here x is the variable.We can denote variable by any alphabet i.e, a,b,c,d etc.

A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with two hoses. Let X denote the number of hoses being used on the self-service island at a particular time, and let Y denote the number of hoses on the full-service island in use at that time. The joint pmf of X and Y appears in the accompanying tabulation.

Y
p(x,y) 0 1 2
x 0 0.10 0.04 0.02
1 0.08 0.20 0.06
2 0.06 0.14 0.30

a. What is P(X = 1 and Y = 1)?
b. Compute P(X ≤ 1 and Y ≤ 1).
c. Give a word description of the event {X ≠ 0 and Y ≠ 0}, and compute the probability of this event.
d. Compute the marginal pmf of X and of Y. Using pX(x), what is P(X ≤ 1)?
e. Are X and Y independent rv’s? Explain.

Answers

Answer:

a. 0.2

b. 0.42

c. 0.7

d. the solution is in the explanation

e. x and y are not independent

Step-by-step explanation:

a. from the joint probability mass function table,

p(x=1) and p(Y= 1)

= p(1,1) = 0.2

b. prob(0,0)+prob(0,1)+prob(1,0)+prob(1,1)

= 0.10 + 0.04 + 0.08 + 0.20

= 0.42

P(X ≤ 1 and Y ≤ 1) = 0.42

c. prob {X ≠ 0 and Y ≠ 0}

= prob(1,1) + prob(1,2) + prob(2,1) + prob(2,2)

= 0.20 + 0.06 + 0.14 + 0.30

= 0.7

d. we have to calculate the marginal pmf of x and y here.

we have the x values as 0,1,2

prob(x=0) = 0.1 + 0.04 + 0.02

= 0.16

prob(x=1) = 0.08 + 0.2 + 0.06

= 0.34

prob(x=2) = 0.06+0.14+0.3

= 0.50

we have y values as 0,1,2

prob(y=0) = .1+.08+.06

= 0.24

prob(y=1) = .04+.2+.14

= 0.38

prob(y = 2) = 0.02+0.06+0.3

= 0.38

P(X ≤ 1) = prob(x=0)+prob(x=1)

= 0.34+0.16

= 0.50

e. from the joint table we have this,

prob(1,1) = 0.2

prob(x=1) = 0.34

prob(y=1) = 0.38

then prob(x=1)*prob(y=1)

= 0.34*0.38

= 0.1292

therefore prob(1,1) is not equal to prob(x=1)*prob(y=1)

0.2≠0.1292

x and y are not independent

Please help!! How do I solve for x?

Answers

The line in the middle is half the length of the line on the outside. Multiply the middle line by 2 and set it equal to the outside line.

2(x-3) = x + 6

Simplify:

2x -6 p x + 6

Add 6 to both sides

2x = x + 12

Subtract x from both sides:

X = 12

The answer is B) 12

What value of b will cause the system to have an infinite number of solutions?

V = 6x + b
-3 x + 1/2 V = -3

Answers

Answer:

-6

Step-by-step explanation:

V = 6x + b

 1/2 V -3 x = -3

V - 6x = -6

V - 6x  =  b

Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the extreme values of the function subject to the given constraint.
(a) f (x, y) = x^2 - y^2; x^2 + y^2 = 1
Max of 1 at (plusminus 1, 0), min of - 1 at (0, plusminus l)
(b) f (x, y) = 3x + y; x^2 + y^2 = 10
Max of 10 at (3, 1), min of - 10 at (- 3, - 1)
(c) f (x, y) = xy; 4x^2 + y^2 = 8
Max of 2 at plusminus (1, 2), min of - 2 at plusminus (l, - 2)

Answers

Answer:

a) f(x,y) = - 1    minimum  at   P ( 0 ; -1 )

b) f (x,y) = 10  maximum at   P ( 3 , 1 ) and   f (x,y) = - 10 minimum at       Q ( - 3 , - 1 )

c)  Max  f ( x , y ) = 2   for points    P ( 1, 2 )  and T ( -1 , -2 )

Min  f ( x , y ) =  -2   for points   Q ( 1 , - 2 )  and R  ( -1 , 2 )

Step-by-step explanation:

A)  f(x,y) = x² - y²         subject to   x² + y² = 1      g(x,y) = x² + y²- 1

δf(x,y)/ δx  = 2*x                                                 δg(x,y)/ δx  =    2*x                      

δf(x,y)/ δy  = - 2*y                                                 δg(x,y)/ δy  =    2*y

δf(x,y)/ δx  = λ* δg(x,y)/ δx

2*x = λ*2*x

δf(x,y)/ δy  = λ* δg(x,y)/ δy

- 2*y = λ*2*y

Then, solving

2*x = λ*2*x           x = λ*x      λ = 1

- 2*y = λ*2*y         y = - 1

x² + y²- 1 = 0         x²  + ( -1)² - 1 = 0      x = 0    

Point  P ( 0 ; -1 )  ; then at that point

f(x,y) = x² - y²             f(x,y) = 0 - ( -1)²     f(x,y) = - 1    minimum

b)  f( x, y ) =  3*x  + y            g ( x , y )  = x² +  y²  = 10

  δf(x,y)/ δx  = 3                   δg(x,y)/ δx  =  2*x

 δf(x,y)/ δy   = 1                   δg(x,y)/ δy  =   2*y

δf(x,y)/ δx  =   λ * δg(x,y)/ δx      ⇒   3 = 2* λ *x    (1)

δf(x,y)/ δy   =  λ *  δg(x,y)/ δy     ⇒    1 = 2*λ * y    (2)

                                                           x² +  y²  - 10 = 0  (3)

Solving that system

From ec (1)     λ  =  3/2*x      From ec (2)     λ  = 1/2*y

Then    (3/2*x )  = 1/2*y          3*y  =  x

x²  +  y²  = 10     ⇒   9y²  + y²  = 10      10*y² = 10

y² = 1       y  ± 1       and    

y  =  1      x  = 3       P  ( 3 , 1  )       y  = - 1    x = -3    Q  ( - 3 , - 1 )

Value of  f( x , y )  at   P   f (x,y) = 3*x + y      f (x,y) =    3*(3) +1  

f (x,y) = 10  maximum at  P ( 3 , 1 )

Value of  f( x , y )  at  Q     f (x,y) = 3*x + y    f (x,y) =  3*(- 3) + ( - 1 )

f (x,y) = - 10 minimum at Q ( - 3 , - 1 )

c)  f( x, y ) =  xy                       g ( x , y )  =  4*x² + y² - 8

δf(x,y)/ δx  = y                         δg(x,y)/ δx  = 8*x

δf(x,y)/ δy = x                          δg(x,y)/ δy  =  2*y

δf(x,y)/ δx  =  λ * δg(x,y)/ δx   ⇒   y  =  λ *8*x    (1)

δf(x,y)/ δy =   λ * δg(x,y)/ δy   ⇒   x  =  λ *2*y    (2)

                                                      4*x² + y² - 8 = 0   (3)

Solving the system

From ec (1)  λ = y/8*x    and From ec (2)      λ = x/2*y        Then    y/8*x  =  x/2*y

2*y² = 8*x²       y² = 4*x²    

Plugging that value in ec (3)

4*x²  +  4*x² - 8 = 0

8*x² = 8     x² = 1        x ± 1      And y² = 4*x²

Then:

for x  = 1      y² =  4     y = ± 2

for x  = -1     y² =  4     y = ± 2

Then we get     P (  1 ; 2 )   Q  ( 1 ; - 2)

                          R ( - 1 ; 2 )  T  ( -1 ; -2)

Plugging that values in f( x , y ) = xy

P (  1 ; 2 )  f( x , y ) = 2            R ( - 1 ; 2 )  f( x , y ) = - 2

Q ( 1 ; - 2)  f( x , y ) = -2           T ( -1 ; -2 )  f( x , y ) = 2

Max  f ( x , y ) = 2   for points    P and T

Min  f ( x , y ) =  -2   for points   Q and R

determine the general solution of cos2X -7cosX -3=0​

Answers

Answer:

x=2pi/3 +2pi n, 4pi/3 +2pi n for all integar of n.

Step-by-step explanation:

2x+2y=38 y=x+3 solve by the solution

Answers

Answer:

x = 8 , y = 11

Step-by-step explanation:

[tex]2x + 2y = 38 => x + y = 19 - -- ( 1 ) \\\\y = x + 3 ---- ( 2 ) \\\\Substitute \ ( 2 ) \ in \ ( 1) :\\\\ x + y = 19\\\\x + ( x+ 3) = 19\\\\2x + 3 = 19\\\\2x = 19 - 3 \\\\2x = 16 \\\\x = \frac{16}{2} = 8\\\\Substitute \ x = 8 \ in \ ( 1 ) : \\\\x + y = 19\\\\8 + y = 19\\\\y = 19 - 8 = 11[/tex]

Which of the following are not polynomials?

Answers

Answer:

A, C and D are not polynomials

Step-by-step explanation:

A because the variable has a negative power.

C because the variable is in the denominator

D because the variable has a root.

When a variable has a root, it's power is 1/2 which does not count as an ideal polynomial. You might be wondering then that why E is a polynomial?

E is a polynomial because because the root is not on the variable but on the constant.

B and E are polynomials while A,C and D are not.

Please mark me as brainliest.

Ben starts walking along a path at 3 mi/h. One and a half hours after Ben leaves, his sister Amanda begins jogging along the same path at 7 mi/h. How long (in hours) will it be before Amanda catches up to Ben?



Enter the exact answer.
Hint: The distance formula is that distance = rate * time, so for example in one and a half hours, Ben has walked 3 * 1.5 miles.

Amanda catches up to Ben in ____________ hours.

Answers

Answer:

1.125 hours

Step-by-step explanation:

Given :

Ben's speed = 3 mi/hr

Time before Amanda starts = 1.5 hours

Amanda's speed = 7 mi/hr

Time before Amanda catches up with Ben

Recall :

Distance = speed * time

Distance already covered by Ben before Amanda starts :

(3 * 1.5) = 4.5

Hence, we can setup the equation :

Ben's distance = Amanda's distance

Let time taken = x

4.5 + 3x = 7x

4.5 = 7x - 3x

4.5 = 4x

x = 4.5 / 4

x = 1.125 hours

1.125 * 60 = 67. 5 minutes

6/10 > _ > 1/3 which fraction goes in the blank?

Answers

Step-by-step explanation:

6/10 > _ > 1/3

3/5 > _ > 1/3

Taking the average of both the fraction

½(⅗+)

½(9+5/15)

½(14/5)

=7/15

6/10 > 7/15 > 1/3

Answer:

7/15

Step-by-step explanation: 10 and 3 LCM is 30

6/10 x 3 =18/30 and 1/3x 10= 10/30

10/30 and 18/30 average is 14/30 which simplified is 7/15

The answer is 7/15

Hope it helps

Last year Nancy weighted 37 5/8 pounds. This year she weighed 42.7 pounds. How much did she gain?

Answers

Answer:

Nancy gained 5.075 pounds.

Step-by-step explanation:

5/8=0.625

37.625

42.7-37.625=5.075

Nancy gained 5 more pounds

Assume that 300 births are randomly selected and 5 of the births are girls. Use subjective judgment to describe the number of girls as significantly​ high, significantly​ low, or neither significantly low nor significantly high.g

Answers

Answer:

Following are the response to the given choice.

Step-by-step explanation:

Please find the complete question in the attached file.

Subjective opinion = Question of opinion.

Therefore this requires only just opinion and we don't have to do any actual calculations.

Does this seem like a great number of girls, a little number of girls, or a decent number of girls to you but if 1,300 babies were born, 5 of whom were females?

This is a small number of beautiful gals, in my honest opinion. We anticipate boys and girls to be produced about the very same frequency, thus I expect some half of them to be females if there are 1 300 newborns. You should have roughly 650 girls if 50% of the infants are girls, but now we only have five. That appears to me to be considerably low. which is your own opinion.

A cylinder has a radius of 2.5 inches (in.) and a height of 11 in., as shown.
2.5 in.
11 in.
What is the surface area, in square inches, of the cylinder?

Answers

Answer:

212.06

Step-by-step explanation:

can't really explain since the formula is fricking long but trust me that's uts 212.06 in²

How long will it take money to double if it is invested at 25 % compounded continuously ?

Answers

Answer:

Is it anual or monthly?

Step-by-step explanation:

the time it takes a runner to complete a race is inversely related to the speed of the runner if a runner can complete a race in 40 minutes while running at 8 mph how long will it take the runner to complete the race running at 9 mph t

Answers

35.6 minutes

S = v*t = 8 * 40/60 = 16/3 m
=> t = s/v = 16/(3*9) = 35.555555 minutes

Because of high tuition costs at state and private universities, enrollments at community colleges have increased dramatically in recent years. The following data show the enrollment (in thousands) for Jefferson Community College for the nine most recent years.


Year Period (t) Enrollment (1,000s)
2001 1 6.5
2002 2 8.1
2003 3 8.4
2004 4 10.2
2005 5 12.5
2006 6 13.3
2007 7 13.7
2008 8 17.2
2009 9 18.1

Required:
a. What type of pattern exists in the data?
b. Use simple linear regression analysis to find the parameters for the line that minimizes MSE for this time series.
c. What is the forecast for year 10?

Answers

Answer:

a. A linear pattern exists in the data.

b. The parameters for the line that minimizes MSE for this time series are as folows:

ß1 = Estimated slope = 1.4567

ß0 = Estimated intercept = 4.7165

Also, we have:

MSE = Mean squared error = 0.4896

c. Forecast for year 10 is 19,280.

Step-by-step explanation:

a. What type of pattern exists in the data?

Note: See Sheet1 of the attached excel file for the line graph.

From the line graph, it can be observed that a linear pattern exists in the data.

b. Use simple linear regression analysis to find the parameters for the line that minimizes MSE for this time series.

Note: See Sheet2 of the attached excel file for all the calculations to obtain the following:

Sample size = 9

Total of X = 45

Total of Y = 108

Mean of X = Total of X / Sample size = 45 / 9 = 5

Mean of Y = Total of X / Sample size = 108 / 9 = 12

SSxx = Total of (X - Mean of X)^2 = 60

SSyy = Total of (Y - Mean of Y)^2 = 130.74

SSxy = Total of (X - Mean of X) * (Y - Mean of Y) = 87.40

Therefore, we have:                

ß1 = Estimated slope = SSxy/SSxx = 87.4 / 60  = 1.4567

ß0 = Estimated intercept = Mean of Y – (ß1 * Mean of X) = 12 - (5 * 1.4567) = 4.7165

Therefore, the parameters for the line that minimizes MSE for this time series are as folows:

ß1 = Estimated slope = 1.4567

ß0 = Estimated intercept = 4.7165

Regression equation which also used in the attached excel is as follows:

Y = ß0 + ß1X =

Y = 4.7165 + 1.4567X …………………. (1)

SSE = Sum of squared error = Total of (Y - Y*)^2 = 3.4273

Therefore, we have:

MSE = Mean squared error = (SSE/(n-2)) = (3.4273 / (9 - 2)) = 0.4896

c. What is the forecast for year 10?

This implies that X = 10

Substitute X = 10 into equation (1), we have:

Y = 4.7165 + (1.4567 * 10) = 19.28

Since it is 1,000s, we have:

Y = 19.28 * 1,000 = 19,280

Therefore, forecast for year 10 is 19,280.

You play basketball at your school's
indoor stadium. You have two payment
options. Option A is to buy a membership
card for $20 and pay $2 each time you
go to the gym, t. Option B is to pay $4
each time you go. Write a a linear
equation to show how many trips to the
gym would the cost be the same?

Answers

Answer:

20 + 2x = 4x

Step-by-step explanation:

So you are setting the two expressions equal to each other.

buying a membership card  and paying each time looks like this: 20 + 2x where x is the number of times you go to the gym.  20 dollars base then 2 each time you go.

4 each time you go is just 4x

so just set the two equal to each other.

20 + 2x = 4x

If you solve it you will get x = something, which would be the number of times to make the two equal.  

In any triangle ABC,Prove by vector method c^2=a^2+b^2-2abcosC​

Answers

Answer:

Let be [tex]\vec A[/tex], [tex]\vec B[/tex] and [tex]\vec C[/tex] the vector of a triangle so that [tex]\vec C = \vec A + \vec B[/tex]. By definition of Dot Product:

[tex]\vec C \,\bullet\,\vec C = (\vec A + \vec B) \,\bullet \vec C[/tex]

[tex]\vec C \,\bullet \,\vec C = (\vec A\,\bullet \,\vec C) + (\vec B \,\bullet \,\vec C)[/tex]

[tex]\|\vec C\|^{2} = [\vec A \,\bullet \,(\vec A + \vec B)] + [\vec B\,\bullet \,(\vec A + \vec B)][/tex]

[tex]\|\vec C\|^{2} = \vec A \,\bullet \, \vec A + \vec B\,\bullet \vec B + 2\cdot (\vec A \,\bullet \, \vec B)[/tex]

[tex]\|\vec C\|^{2} = \|\vec A\|^{2} + \|\vec B\|^{2} + 2\cdot \|\vec A\|\cdot \|\vec B\|\cdot \cos\theta_{C}[/tex]

Step-by-step explanation:

Let be [tex]\vec A[/tex], [tex]\vec B[/tex] and [tex]\vec C[/tex] the vector of a triangle so that [tex]\vec C = \vec A + \vec B[/tex]. By definition of Dot Product:

[tex]\vec C \,\bullet\,\vec C = (\vec A + \vec B) \,\bullet \vec C[/tex]

[tex]\vec C \,\bullet \,\vec C = (\vec A\,\bullet \,\vec C) + (\vec B \,\bullet \,\vec C)[/tex]

[tex]\|\vec C\|^{2} = [\vec A \,\bullet \,(\vec A + \vec B)] + [\vec B\,\bullet \,(\vec A + \vec B)][/tex]

[tex]\|\vec C\|^{2} = \vec A \,\bullet \, \vec A + \vec B\,\bullet \vec B + 2\cdot (\vec A \,\bullet \, \vec B)[/tex]

[tex]\|\vec C\|^{2} = \|\vec A\|^{2} + \|\vec B\|^{2} + 2\cdot \|\vec A\|\cdot \|\vec B\|\cdot \cos\theta_{C}[/tex]

Solve the inequality. |X-15|>9

Answers

Answer:

X<6 or X>24

Step-by-step explanation:

A sprinkler releases water st a rate of 150 liters per hour. If the sprinkler operated for 80 minutes how many liters of water will be released

Answers

200 liters for 80 minutes of run time

The amount of water released from the sprinkler for 80 minutes is 200 L

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the amount of water from the sprinkler for 80 minutes be = A

Now , the value of A is given by the equation

A sprinkler releases water st a rate of 150 liters per hour

So , 60 minutes = 150 Liters of water

80 minutes = 1/60 hours

80 minutes = 1.333 hours

The amount of water released for 1.333 hours A = 150 x 1.333

On simplifying the equation , we get

The amount of water released for 1.333 hours A = 200 L

Therefore , the value of A is 200 L

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A papaya is accidentally dropped from a bridge, which is 30 m above the water. Ignoring air resistance, the papaya's speed just before it hits the water will be __________ m/s.

Answers

Answer:

24 .30ms is the answer I think so if the answer is correct plz mark me as brainliest.

The papaya's speed just before it hits the water will be 24.24 m/s.

What is speed?

The rate at which objects moves is called speed. It is given by

[tex]s = \frac{d}{t}[/tex]

An object held above the ground has a potential energy related to the height at which it is held,

PE = mgh

If you drop the object, its potential energy will become the kinetic energy of motion:

KE = ½ mv²

½ mv² = mgh

v  = √(2gh)

v =  √(2*9.8*30)

v =  24.24 m/s

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