If angle 4 = 100, what is angle 6?

If Angle 4 = 100, What Is Angle 6?

Answers

Answer 1

Answer: 100

Step-by-step explanation:

Because the two horizontal lines are parallel and diagonal splits them, 4 and 6 are congruent so they have the same angle.

4, 2, 8 and 6 all have the same angles.

1, 3, 5 and 7 all have the same angles as well.

Answer 2
100 because it is the same angle as 4 and is reflected

Related Questions

9. 2 less than 3 times a number is the same as 2114. What is the number?

Enter your answer as a decimal or simplified mixed number in the box. The number is.

Answers

Answer:

705.3 repeated I don't know if that's what you want but

3 times of 705.33 and 2 subtracted is equal to 2114.

What is Simplification?

Simplification in mathematical terms is a process to convert a long mathematical expression in simple and easy form.

Given that,

2 less than 3 times a number equal to 2114.

Let the required number is x.

According to given condition,

3x - 2 = 2114

3x = 2114 + 2

3x = 2116

x = 2116 / 3

x = 705.33

The required number is 705.33.

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Please help xxxxxxxx

Answers

Answer:

a. [tex]\bold{45000\times \:10^7}[/tex]b. [tex]\bold{3500}[/tex]

Step-by-step explanation:

a. [tex]\left(5\times \:10^3\right)\left(9\times \:10^7\right)[/tex]

[tex]5\times 10^3 = 5000\\\\5000\times \:9\times \:10^7[/tex]

[tex]\mathrm{Multiply\:the\:numbers:}\:5000\times \:9=45000[/tex]

[tex]=45000\times \:10^7[/tex]

b. [tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)[/tex]

[tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)=\frac{7\times \:10^5}{2\times \:10^2}[/tex]

[tex]\frac{10^5}{10^2} = 10^3[/tex]

[tex]\frac{7\times \:10^3}{2}[/tex]

[tex]\mathrm{Factor}\:\: 10^3 : 2^3\times5^3[/tex]

[tex]\frac{7\times \:2^3\times \:5^3}{2}[/tex]

[tex]\frac{2^3}{2}=2^2[/tex]

[tex]7\times \:2^2\times \:5^3=3500[/tex]

Which of the following tables does not represent a function?


x y
-1 1
-2 1
-3 1

x y
-5 1
-5 -2
-5 -5

x y
-4 0
2 0
5 7

x y
-5 1
-3 -2
-1 -5

Answers

Step-by-step explanation:

the second one (with the -5 as x values) is not a function, because the valid x value -5 has more than one associated different solution value y.

for a function a valid x value can lead only to exactly one result y value.

Write the equation for 5x + 2y = 3 in slope-intercept form..

Answers

Answer:

[tex]y=-\frac{5}{2}x+\frac{3}{2}[/tex]

Step-by-step explanation:

[tex]5x+2y=3\\\\2y=-5x+3\\\\y=-\frac{5}{2}x+\frac{3}{2}[/tex]

Answer:

Step-by-step explanation:

Slope-intercept from: y = mx + b

5x + 2y = 3

       2y = -5x + 3

Divide the whole equation by 2

[tex]\dfrac{2y}{2}=\dfrac{-5x}{2}+\dfrac{3}{2}\\\\y=\dfrac{-5}{2}x +\dfrac{3}{2}[/tex]

How many months would it take the bamboo plant shown in the graph to be 66 inches tall

Answers

Answer:

18 months

Step-by-step explanation:

c

1.) -3x-8=-14
2.) 4x-6=14
3.)-3-3x=-30
4.) -5x+5=5

Answers

-3x-8=-14 Answer: x=2
4x-6=14 Answer x=5
-3-3x=-30 Answer x=9
-5x+5=5 Answer x=0

Answer:

1.) x = 2

2.) x = 5

3.) x = 9

4.) x = 0

Step-by-step explanation:

1.) -3x - 8 = -14

-3x = -6

x = 2

2.) 4x - 6 = 14

4x = 20

x = 5

3.) -3 - 3x = -30

-3x = -27

x = 9

4.) -5x + 5 = 5

-5x = 0

x = 0

Three partners are investing a total of $900,000 to open a garden and landscaping store. Their investments are in the ratio of 2:3:5. .

Answers

The first investor you invested $180,000 the second $270,000 and the third $450,000.
Solution:
2+3+5=10
900,000/10=90,000
90,000x2=180,000
90,000x3=270,000
90,000x5=450,000

Which of the following best describes the graph shown below?

Answers

I believe it is C since it’s shape Is not linear so it cannot be A, and it is a function.

Answer: D

Step-by-step explanation:

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Question ~}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Prove that ~

[tex] \dfrac{d}{dx}\sec(x) = \sec(x) \tan(x) [/tex]


by using first principle of differentiation ~​

Answers

Answer:

METHOD I:

(by using the first principle of differentiation)

We have the "Limit definition of Derivatives":

[tex]\boxed{\mathsf{f'(x)= \lim_{h \to 0} \{\frac{f(x+h)-f(x)}{h} \} ....(i)}}[/tex]

Here, f(x) = sec x, f(x+h) = sec (x+h)

Substituting these in eqn. (i)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \{\frac{sec(x+h)-sec(x)}{h} \} }[/tex]

sec x can be written as 1/ cos(x)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{1}{cos(x+h)} -\frac{1}{cos(x)} \} }[/tex]

Taking LCM

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{cos(x)-cos(x+h)}{cos(x)cos(x+h)} \} }[/tex]

By Cosines sum to product formula, i.e.,

[tex]\boxed{\mathsf{cos\:A-cos\:B=-2sin(\frac{A+B}{2} )sin(\frac{A-B}{2} )}}[/tex]

=> cos(x) - cos(x+h) = -2sin{(x+x+h)/2}sin{(x-x-h)/2}

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{2sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{sin(\frac{h}{2} )}{h} }[/tex]

I shifted a 2 from the first limit to the second limit, since the limits ar ein multiplication this transmission doesn't affect the result

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{2sin(\frac{h}{2} )}{h} }[/tex]

2/ h can also be written as 1/(h/ 2)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{1\times sin(\frac{h}{2} )}{\frac{h}{2} } }[/tex]

We have limₓ→₀ (sin x) / x = 1.

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: 1 }[/tex]

h→0 means h/ 2→0

Substituting 0 for h and h/ 2

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+0)}{cos(x+0)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)}\times \frac{1}{cos x} }[/tex]

sin x/ cos x is tan x whereas 1/ cos (x) is sec (x)

[tex]\implies \mathsf{f'(x)= tan(x)\times sec(x) }[/tex]

Hence, we got

[tex]\underline{\mathsf{\overline{\frac{d}{dx} (sec(x))=sec(x)tan(x)}}}[/tex]

-  - - - -  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

METHOD II:

(by using other standard derivatives)

[tex] \boxed{ \mathsf{ \frac{d}{dx} ( \sec \: x) = \sec x \tan x }}[/tex]

sec x can also  be written as (cos x)⁻¹

We have a standard derivative for variables in x raised to an exponent:

[tex] \boxed{ \mathsf{ \frac{d}{dx}(x)^{n} = n(x)^{n - 1} }}[/tex]

Therefore,

[tex] \mathsf{ \frac{d}{dx}( \cos x)^{ - 1} = - 1( \cos \: x) ^{( - 1 - 1} } \\ \implies \mathsf{\ - 1( \cos \: x) ^{- 2 }}[/tex]

Any base with negative exponent is equal to its reciprocal with same positive exponent

[tex] \implies \: \mathsf{ - \frac{1}{ (\cos x) {}^{2} } }[/tex]

The process of differentiating doesn't just end here. It follows chain mechanism, I.e.,

while calculating the derivative of a function that itself contains a function, the derivatives of all the inner functions are multiplied to that of the exterior to get to the final result.

The inner function that remains is cos x whose derivative is -sin x.

[tex] \implies \mathsf{ - \frac{1}{ (\cos x )^{2} } \times ( - \sin x) }[/tex]

cos²x can also be written as (cos x).(cos x)

[tex] \implies \mathsf{ \frac{ \sin x }{ \cos x } \times ( \frac{1}{cos x} ) }[/tex]

sin x/ cos x is tan x, while 1/ cos x is sec x

[tex] \implies \mathsf{ \tan x \times \sec x }[/tex]

= sec x. tan x

Hence, Proved!

write a peacewise function for the graph
please help me

Answers

Answer:

[tex]\left \{ {{y=x; \ \ x\le 0} \atop {y=4+ \frac12x;\ \ x>0}} \right.[/tex]

Step-by-step explanation:

If you look at the graph you see that:

before 0, the graph has same y as it has x, or y=x.

after 0, the graph starts at 4, and increases by 1 every 2 steps horizontally, or has a slope of 1/2.

Finally, the 0 has to be included in the blue part of the graph based on where the solid dot is.

find the value of x. only type the “number”

Answers

Step-by-step explanation:

5x - 6 = 3x + 2

5x - 3x = 2 + 6

2x = 8

x = 8/2

x = 4

work out 4 1/2 - 1 1/3

Answers

Answer:

3 1/6

brainliest?

The ratio of two numbers is 7:2. If the greater number is 28, find the smaller one.​

Answers

Answer:

Answer:

8

Step-by-step explanation:

7   : 2

We know the larger number is  28

28 : x

We multiply 7 * 4 = 28, so multiply the first ratio by 4

7*4   : 2*4

28  : 8

The second number is 8

Please give brainliest

Have a nice day!

1.) From a group of 8 people, 5 will each win $1,000. How many different winning groups are
possible?
A.) 56
B.) 6720
C.) 168
D.) 336

Answers

Anwser 6720 ways different

Step-by-step explanation:

In this case, we must calculate the different ways using the permutation formula:

nPr = n! / (n - r)!

where n is the total number of people and r would come being the group of person that you want to put together the groups, therefore n = 8 and r = 5

replacing:

8P5 = 8! / (8 - 5)!

8P5 = 6720

That is to say that there are 6720 ways different winning groups are possible

Monique wants to check out as many books by her favorite author as possible. She can check out 3 books at a time from her library, where there are 6 books available written by her favorite author. How many different sets of 3 of these books can Monique choose

Answers

Monique can choose 20 different sets of 3 of the books

What is a combination?

The set of books she can select from the library is an illustration of combination (or selection)

The expression that represents combination is represented as:

[tex]^nC_r = \frac{n!}{(n - r)!r!}[/tex]

Where:

The total number of books [tex]n = 6[/tex]The set of books to check out [tex]r = 3[/tex]

So, we have:

[tex]^6C_3 = \frac{6!}{(6 - 3)!3!}[/tex]

Evaluate the differences

[tex]^6C_3 = \frac{6!}{3!3!}[/tex]

Evaluate the factorials

[tex]^6C_3 = \frac{720}{6 \times 6}[/tex]

Evaluate the products

[tex]^6C_3 = \frac{720}{36}[/tex]

Divide 720 by 36

[tex]^6C_3 = 20[/tex]

Hence, Monique can choose 20 different sets of 3 of the books

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Answer:

it is in fact 20 (for khan)

Step-by-step explanation:

credit goes to person above

The Sydney Harbour Bridge is approximately 1200 metres long. A model of the bridge is built with a scale of 1:6000. What is the length of the model?
Pick one:
5cm
20cm
200cm
720cm

Answers

Answer:

20cm

Step-by-step explanation:

The Sydney Harbour Bridge is approximately 1200 metres long. A model of the bridge is built with a scale of 1:6000. What is the length of the model?

Pick one:

5cm

20cm

200cm

720cm

--------------------

scale = 1:6000

so

1200 : 6000 =  0.2m

0.2m = 20 cm

Answer:

20cm

Step-by-step explanation:

«A scale of 1:6000» means the model is smaller than the bridge by a factor of 6000. We can also make up a proportion [tex]\dfrac{1}{6000}=\dfrac{x}{1200}[/tex], where the left side is the scale, x is the model length, 1200 is the bridge length (in meters). So, finding x or just dividing 1200 by 6000, we get 0.2 meters. Provided 1 m = 100 cm, 0.2 m is 0.2 × 100 = 20 cm.

what is the answers to 10% of 50 i multiply 10 x 50

Answers

NO!!!!!!!!!!

10% of 50 is 50/100x10 0r simply 50/10, so the answer is 5

Answer:

5

Step-by-step explanation:

10%×50=10/100×50

            =5

w + 12 = 20 *


ANSWER ASAP PLS​

Answers

Answer:

the nwser is 8 please mark brainliest

Step-by-step explanation:

Write 2.04 × 10 ⁴ as an ordinary number

Answers

Answer:

20400

Step-by-step explanation:

its 2.03x10x10x10x10 so first ten: 20.4 and ten: 204 3rd ten: 2040 last ten :20400

2x2-5x-2 solve by quadratic formula 9leave answers in simplest radical form)

Answers

Answer:

-5x+2

Step-by-step explanation:

1. Multiply number 2 and 2=4 so it is

4-5x-2

2. Combine like terms

-5x+4-2

3. Subtract the numbers

-5x+2

What is the 4th equivalent fraction to 1/12?

Answers

Answer:

Where's the Answer? There's No

Hello there!

Remember that equivalent fractions have the same value.

[tex]\frac{1}{2} , \frac{2}{24} ,\frac{3}{36}, \frac{4}{48}[/tex]

Therefore, the 4th equivalent fraction to 1/12 is [tex]\frac{4}{48}[/tex]

Hope this helps you!

~Just a felicitous girlie

#HaveASplendidDay

[tex]SilentNature :)[/tex]

find the value of:
64 x (1/4)³

A. 1
B. 4
C. 15
D.64
brainliest if correct!!

Answers

Answer:

The answer is A. 1

you're welcome

a radioactive substance has a half-life of 2 seconds. A scientist begins with a sample of 20 grams. How much of the substance remains after 8 seconds?

Answers

Answer:

1.25 g

Step-by-step explanation:

you start with 20g at 0 seconds.

divide by half after 2 seconds and you have 10g.

at 4 seconds you have 5g.

at 6 seconds you have 2.5g.

at 8 seconds you have 1.25g.

The size of the substance after 8 seconds will be 1.25 g

What is an expression?

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that a radioactive substance has a half-life of 2 seconds. A scientist begins with a sample of 20 grams.

Start with 20g at 0 seconds and divide by half after 2 seconds and you have 10g.

4 seconds you have 5g.

6 seconds you have 2.5g.

8 seconds you have 1.25g.

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solve pls brainliest

Answers

Answer:

64%

Step-by-step explanation:

Step 1: Divide 16 by 25

-> [tex]\frac{16}{25}[/tex] -> [tex]0.64[/tex]

Step 2: Multiply quotient by 100.

[tex]0.64 * 100[/tex] [tex]6.4 * 10[/tex] [tex]64[/tex] 64%

Therefore, 16/25 as a percentage is 64%.

Answer:

Well you can make a proportion

Percentage means ”Out of a hundred”

So you can make a proportion with any fraction Equal to x/100 since

X is the unknown perctange.

in this case it’s 16/25

16/25 = x/100

So cross multiply To solve for X

1600= 25x

x= 64

So 64 Percent

In this case you can use benchmarks. If you do it more or long enough, you’d memorize them.

In this case 25 is a bench mark of 1/4 or 25. 25 goes into 100 4 times so you can multiply 16 by 4 to get your percentage since if you do multiply 4, you have to do it to both the numerator and the Denominator.

so 16/25

16*4= 64

25*4=100

64/100 or 64 percent.

Common benchmarks for percentages

5, 10, 20, 25, 50

5 is always multiply by 20

10 is always multiply by 10

20 is always multiplied by 5

25 is always multiplied by 4

50 is always multiplied by 2

Which ratio is equivalent to 7:3?
217
49:9
12: 8
28:12

Answers

Answer:

i think it is 49:9

Step-by-step explanation:

because number going in 49:9 by which multiple it is 7x7 is 49 3x3 is 9 so the answer is 49:9

Answer:

28:12

Step-by-step explanation:

Multiply both 7 and 3 by 4 and you get the ratio 28:12.

Write in slope-intercept form an equation of the line that passes through the given points. (0,−1),(−8,−2)

Answers

y=8x+14

0-(-8)/-1-(-2)= 8/1 =8
8=m

-2=2(-8)+b
-2=-16+b
+16 +16
14=b

At an electronics store, Tim earns $15 per hour, plus a 6% commission on his sales. If he works 6 hours and sells $800 in merchandise, how much does he earn in total?A)$138B)$154C)$172D)$196

Answers

Answer:

A. 138

Step-by-step explanation:

Total money earned by Tim is $138. Therefore, option A is the correct answer.

Given that, Tim earns $15 per hour, plus a 6% commission on his sales.

What is a unitary method?

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Tim works 6 hours and sells $800 in merchandise.

So, total income = 15×6 + 6% of 800

=90+0.06×800

=90+48

=$138

Total money earned by Tim is $138. Therefore, option A is the correct answer.

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A car is moving at 12 m/s and has a mass of 600 kg. What is the kinetic energy of the car? (Formula: KE = 1/2mv^2) WILL GIVE BRAINLEST

Answers

Answer:

The kinetic energy of the car is 43,200 Joules.

Step-by-step explanation:

KE = (1/2)mv^2

KE = (1/2)(600 kg)(12 m/s)^2

KE = (1/2)(600 kg)(144 m^2/s^2)

KE = 43,200 kg*m^2/s^2 = 43,200 Joules

Answer:

Step-by-step explanation:

KE= 1/2mv^2

KE = 1/2(600) 12^2

KE = 300 * 144 = 43200J

if y varies inversely as n and m = 8 when n = 3 find m whenn =12

Answers

Answer:

24

Step-by-step explanation:

m=8x4 n=3x4 so that is the answer

1. When do we use the method of Difference of two squares?
*
(Factoring polynomials)

Answers

Answer:

a

Step-by-step explanation:

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