Answer:
it is the Hubble law
Explanation:
Hubble's law, also known as the Hubble–Lemaître law, is the observation in physical cosmology that galaxies are moving away from the Earth at speeds proportional to their distance. In other words, the farther they are the faster they are moving away from Earth.
Answer:
The hubble law
is the observation in physical cosmology that galaxies are moving away from the Earth at speeds proportional to their distance. In other words, the farther they are the faster they are moving away from Earth.
A horizontal net force F is exerted on an object at rest. The object starts at x=0 m and has a speed of 4.0 m/s after moving 4.0 m along a horizontal frictionless surface. The net force F as a function of the object's position x is shown below
Explanation:
The solution is be found in the attachment.
A horizontal net force F is exerted on an object at rest. The object starts at x = 0 m and has a speed of 4.0 m/s after moving 8.0 m along a horizontal frictionless surface. The net force F as a function of the object's position x is shown below.
What is the mass of the object?
Answer: 30 kg
How would you describe your appetite over the past couple of weeks? Have your eating habits altered in any way?
Answer:
no im in a rehab program so we eat the sam shi every day
Explanation:
brainlest?
Explanation:
During lockdown, I ate LOADS OF JUNK FOOD. TRUST ME!!
I gained 14 kg of weight and became 68 kg
just due to junk food.I am 13 btw and at that time I was 5 feet 4 so definitely fat. all those pizzas and burgers and all.then I realised that I have gained weight. I have to REDUCE MY WEIGHT. I am quite determined on what I say. it took me 3 months or so and I finally got back to my original weight. How? just by going for a stroll everyday, eating healthy and constantly working out. eating less is not the solution,eating less calories is the solution.Also, by eating healthy food,I grew taller. I am 5 feet 6 now. So yes, definitely it helps put alot and keep eating healthy food and you will definitely be healthy.
Thank You.
Is the potential energy on the surface of Earth zero?If not,what will be it's value?
Answer:
Potential energy does not have an absolute measurement. It is always relative to some reference point. Gravitational potential always increases when you go up and decreases when you go down. But the choice of a zero point is arbitrary.
If you’re dropping objects onto the ground, then choosing the ground as a zero point makes the calculations easier. But you could just as easily make the zero point the top of Mt. Everest, and all the answers would turn out the same. Up still means more energy and down means less, but now the PE of an object at sea level would have a negative sign, but not as negative as an object ten meters above sea level.
So everything would still work fine.
In fact, planetary astronomers take this idea to extremes. Instead of the top of Mt. Everest, they set the zero point for potential energy as infinitely high—so far “up” that gravity is so weak that going “up” another kilometer doesn’t gain you any energy. Then the value for potential energy everywhere else in the universe anywhere near a planet has a negative sign, but just as before, all the answers in relative terms turn out fine.
Explanation:
PLEASE MARK ME AS BRAINLIEST
A fault is formed by the movement of a ___ plate boundary
A.convergent
B.traditional
C.divergent
D.transform
A person on a daily diet of 2,500 calories should get no_more than
calories from fat each day.
Answer:
35%
Explanation:
Answer:
its 83
Explanation:
PLEASE PLEASE HELPPP!
Select all that apply!
Answer:
1 AND 3
Explanation:
True or False. The fulcrum of a first class lever is between the output force and an input force.
Answer:
True
Explanation:
A first-class lever is a lever in which the fulcrum is located between the input effort and the output load. In operation, a force is applied (by pulling or pushing) to a section of the bar, which causes the lever to swing about the fulcrum, overcoming the resistance force on the opposite side
The law of universal gravitation describes the relationships between
Group of answer choices
A. unbalanced force, balanced force, and net force.
B. speed, distance, and time.
C. speed, velocity, and acceleration.
D .force, mass, and distance.
Answer:
D force mass and distance
Whats the word for when "velocity equals 0 and direction changes" Its 14 letters, and I have _ _ _ _ i _ _ _ _ _ h_ i _ _ t
Answer:
Maximum Height
Explanation:
The maximum height is the highest point reached by a projected body. At this point, final velocity, v of the body is equal to 0; because upward motion is at its peak and the body start to fall again.
Hence, final velocity v is always 0 at this maximum point and the direction of motion changes from upward to downward.
Final velocity at this maximum height is zero because of the directional change experied by the object and the fact that upward motion of the body terminates at this point.
how high is the pole from which the lamp fell freely if it hits the ground at a speed of 15 m/s
Answer & Explanation:
The acceleration due to gravity is about 10 m/s^2.
That means a the speed of a falling object will increase by 10 m/s every second that it falls.
We know that the lamp hits the ground at 15 m/s.
That means the lamp has been falling for
[tex]\frac{15 m/s}{10 m/s^{2} } = 1.5 s[/tex]
Now we use the formula [tex]h = \frac{1}{2} gt^{2}[/tex] to calculate the height, where
h is the height
g is the acceleration due to gravity and
t is the time taken to fall a height of h.
h = 1/2 x 10 x 1.5^2 = 11.25 m
The less mass an object has, the --- its gravitational f
Answer:
The less mass an object has, the less its gravitational [force.]
Explanation:
Newton's Law of Gravity states that [tex]F_G=\frac{Gm_1m_2}{r^{2}}[/tex]. The two m values are the objects' masses, G is the gravitational constant, and r is the distance between the objects' centers. Notice how the mass values are in the fraction's numerator? That means increasing the mass of one or both objects increases [tex]F_G[/tex]. That also implies the inverse; decreasing the mass of one or both objects decreases [tex]F_G[/tex]!
I hope this helps you understand this concept a little more! Have yourself a fantastic day, 'kay?
Which statement describes the difference between ionic bonds and Van der
Waals forces?
A. Ionic bonds involve the sharing of electrons between atoms, while
Van der Waals forces involve the attraction of nonpolar molecules.
B. Ionic bonds involve the transfer of electrons between ions, while
Van der Waals forces involve the sharing of electrons between
atoms.
C. lonic bonds involve the transfer of electrons between ions, while
Van der Waals forces involve the attraction of nonpolar molecules.
D. Ionic bonds involve the attraction of nonpolar molecules, while
Van der Waals forces involve the transfer of electrons between
ions.
Answer:
C. lonic bonds involve the transfer of electrons between ions, while
Van der Waals forces involve the attraction of nonpolar molecules.
Explanation:
Just did it
Why is physical activity important?
O It helps keep you healthy.
It helps control your weight
It helps imcove your balance and coordination
All of the Above
at least one activity you can enjoy to help you get your 60 min
Answer:
All of the Above
walking
The molecules of a substance in a particular state of matter move freely with random motion. The average speed of the molecules is increasing. What is being described?
Answer:
A gas
Explanation:
1
A cat walks 4 meters north, 7 meters east, 4 meters south, and then 3
meters west. What is the cat's displacement? *
Answer:90+80+90=360
Explanation:10x+60–50
TRUE OR FALSE
1. TRUE OR FALSE: The higher the frequency, the closer the waves are together and the LOWER the energy carried by the waves will be.
2. TRUE OR FALSE: The greater the force that produces a wave, the greater the amplitude of the wave and the greater the energy carried by the wave.
3. TRUE OR FALSE: In a transverse wave the higher the wave, the LOWER the amplitude
4. Wavelength is a measure of the distance from the crest on one wave to the crest on the very next wave.
5. TRUE OR FALSE: Speed is a measure of the distance a wave travels in an amount of time
6. TRUE OR FALSE: As a wave enters a different medium, the wave’s speed changes. Waves travel at different speeds in different media
7. TRUE OR FALSE: The highest point of a transverse wave is the crest and the lowest point is called a trough.
Answer:
Explanation:
true true fauls true fauls fauls
1 . The higher the frequency, the closer the waves are together and the LOWER the energy carried by the waves will be. FALSE
2. The greater the force that produces a wave, the greater the amplitude of the wave and the greater the energy carried by the wave. TRUE
3. In a transverse wave the higher the wave, the LOWER the amplitude FALSE
4.Wavelength is a measure of the distance from the crest on one wave to the crest on the very next wave, TRUE
5. Speed is a measure of the distance a wave travels in an amount of time TRUE
6. As a wave enters a different medium, the wave’s speed changes. Waves travel at different speeds in different media TRUE
7. The highest point of a transverse wave is the crest and the lowest point is called a trough. TRUE
What is Wave ?A wave is a disturbance in a medium that carries energy and as well as momentum. Energy can be transferred in the form of wave in the medium. there are two types of wave,
longitudinal wave : in which, vibration of the medium (particle) is parallel to propagation of the wave as shown in the fig.1. Sound wave is a longitudinal wave.
Transverse wave : in which, vibration of the medium (particle) is perpendicular to propagation of the wave as shown in the fig.2. Light wave is a longitudinal wave.
1. E = hυ where υ is a frequency which shows direct relation between Energy E and frequency υ. Hence it is false.
2. True
3. In a transverse wave the higher the crest in the wave, the higher the amplitude. FALSE
4. True
5. True, Speed = Distance÷Time
6. due to change in refractive index, velocity changes TRUE
7.True
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Please answer quick! Thanks guys!
Answer:
wire By please mark my answer in brain list
Answer:
Remove wire G, if the wire after it is F. Remove wire A as C is connecting to it already.
A 0.225 kg sample of tin initially at 97.5°c is dropped into 0.115 kg of water. the initial temperature of the water is 10.0°c. if the specific heat capacity of tin is 230 j/kg • °c, what is the final equilibrium temperature of the tin-water mixture
Answer:
The final equilibrium temperature of the tin-water mixture is approximately 18.468 °C
Explanation:
The parameters of heat energy transfer from the tin to the water are given as follows;
The mass of the sample of tin, m₁ = 0.225 kg
The initial temperature of the tin, T₁ = 97.5 °C
The mass of the water into which the tin is dropped, m₂ = 0.115 kg
The initial temperature of the water, T₂ = 10.0 °C
The specific heat capacity of tin, c₁ = 230 J/(kg·°C)
The specific heat capacity of water, c₂ = 4,200 J/(kg·°C)
Let 'T' represent the final equilibrium temperature of the tin-water mixture, we have;
The heat lost by the tin, ΔQ[tex]_{tin}[/tex] = The heat gained by the water ΔQ[tex]_{water}[/tex]
∴ ΔQ[tex]_{tin}[/tex] = ΔQ[tex]_{water}[/tex]
Where;
ΔQ[tex]_{tin}[/tex] = m₁·c₁·(T₁ - T)
ΔQ[tex]_{water}[/tex] = m₂·c₂·(T - T₂)
By substitution, we have;
ΔQ[tex]_{tin}[/tex] = 0.225 kg × 230 J/(kg·°C) × (97.5°C - T)
ΔQ[tex]_{water}[/tex] = 0.115 kg × 4,200 J/(kg·°C) × (T - 10.0°C)
From ΔQ[tex]_{tin}[/tex] = ΔQ[tex]_{water}[/tex], we have;
0.225 kg × 230 J/(kg·°C) × (97.5°C - T) = 0.115 kg × 4,200 J/(kg·°C) × (T - 10.0°C)
∴ 5,045.625 J - 51.75 J/°C × T = 483 J/°C × T - 4,830 J
5,045.625 J + 4,830 J = 534.75 J/°C × T
∴ 534.75 J/°C × T = 9,875.625 J
T = 9,875.625 J/(534.75 J/°C) = 18.4677419 °C ≈ 18.468 °C
The final equilibrium temperature of the tin-water mixture, T ≈ 18.468 °C.
A bullet (m = .005 kg) moving at 500 m/s strikes
and sticks in a block of wood (m = 5 kg). What is
the final velocity of the wood/bullet mass?
Answer:
fif = 0.01 x 5000 = 50 N
Explanation:
u=150 m/s
v=0
m-10 y =0.01 kg
t=0.03s
s
v=utat
o= 150+a (0.03)
therefore a= -5000 m/s power 2
v power 2 = u power 2 + 2as
0=150 power 2+ 2 x (-5000) x s
therefore f=2.25 m
what best decribes the science method
A 4kg object is moving at 5 m/s . A 10-N force is applied in the direction of motion and if the object has a final velocity 10m /s. calculate the distance that the object moves
Answer:
Distance, S = 15m
Explanation:
Given the following data;
Mass = 4kg
Force = 10N
Initial velocity = 5m/s
Final velocity = 10m/s
To find the distance;
First of all, we would calculate the acceleration
Force = mass * acceleration
10 = 4*acceleration
Acceleration = 10/4
Acceleration = 2.5m/s²
Now to find the distance, we would use the third equation of motion.
[tex] V^{2} = U^{2} + 2aS [/tex]
Where;
V represents the final velocity measured in meter per seconds. U represents the initial velocity measured in meter per seconds. a represents acceleration measured in meters per seconds square.S represents the displacement measured in meters.
Substituting into the equation, we have;
10² = 5² + 2*2.5*S
100 = 25 + 5S
5S = 100 - 25
5S = 75
Distance, S = 75/5
Distance, S = 15m
9. In a closed circuit made of a battery, a wire, a lightbulb, and a switch which part's main responsibility is allowing electricity to flow over a distance?
A: battery
B: light bulb
C: switch
D: wire
Answer:
d
Explanation:
Answer:
D: wire
Explanation:
The illustration shows the forces in Newtons (N) acting on three different blocks. Which
boxes will move under these conditions?
Answer:a
Explanation:because I know
Answer:
B & C
Explanation:
the first block will not move
Which of these would have the highest temperature?
ice
water
water vapor
Answer:
Water vapor
Explanation:
Water Vapor has the highest temperature, due to its being in a gas state, and gases usually have very high temperatures, for example steam when you boil pasta.
Hope this helps you! Have a nice day!
Someone plz help I’m on a time limit :(
What patterns occur in the Earth-Sun-Moon system that allow us to identify the cause of
eclipses?
Answer:
Earth's rotation and orbit and the Moon's orbit cause observable patterns (Day and night, seasons, phases of the Moon, tides).
a clay ball with a mass of 0.35 kg hits another 0.35 kg ball at rest and the two stick together. The first balls intial speed us 4.2m/s.
What are the balls final speed?
Answer:
4.2 m/s
the balls final speed is V (m/s)
because the clay ball hits another and the two stick together
=> 0,35.4,2 + 0,35.4,2 = (0,35 + 0,35).V
<=> 2,94 = 0,7V
<=> V = 2,94/0,7 = 4,2
For a clay ball with a mass of 0.35 kg, the ball's final speed is mathematically given as
V2= 4.2
What is the balls final speed?Question Parameter(s):
A clay ball with a mass of 0.35 kg
Hits another 0.35 kg ball at rest and the two stick together.
The first ball's initial speed is 4.2m/s.
Generally, the equation for the conservation of momentum is mathematically given as
M1v1=m2v2
Therefore
0.35*4.2 + 0.3*5.4.2 = (0.35 + 0.35)*V
2,94 = 0,.7V
V2 = 2.94/0.7
V2 = 4.2
In conclusion
V2= 4.2
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Rain and wind place which type of load on structures?
A) Dynamic load
B) Soft load
C) Gradual load
D) Static load
Write down the use of light pipe.???
An object with a mass of 2.0 kg accelerates 2.0 m/s 2when an unknown force is applied to it. What is the amount of force?
Answer:
4 N
Explanation:
mass = 2 kg
acceleration = 2 m/s^2
Force = mass * acceleration
= 2 *2
= 4 N
What is the charge on an object that experiences a force of 5 Newtons in an electric field of 50 Newtons per coulomb?
Answer:
Explanation:
F = qE
F is the force in Newtons
q is the test charge
E is the electrical field produced by the source charge
[tex]5=q(50)\\q=1*10^-^1Coulombs[/tex]
The magnitude of charge on the object is of 0.1 C.
Given Data:
The magnitude of electric field is, E = 50 N/C.
The magnitude of Electric force is, F = 5 N.
The region where any particle feels the effect of electric force on itself, due to other charged entities, is known as Electric field. And the relation between the electric force and electric field is given as,
F = E × q
Here,
q is the magnitude of charge on the object.
Solving as,
q = F/E
q = 5 / 50
q = 0.1 C
Thus, we can conclude that the magnitude of charge on the object is of 0.1 C.
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