Answer:
0
Step-by-step explanation:
When a number is not included or used, it can be considered 0.
This makes sense, because if it had a actualy value, it would effect the polynomial, and change the answer.
The only time it would not effect the polynomial is when it 0.
Hope this makes sense :D
pls help pls help pls help pls help
Answer:
The difference is 3 for 4-7, and 39 for 52-91. So basically its a change of 3 for every 4-7 I think this is what you ask for. Let me explain and show results and then pick what you need.
Step-by-step explanation:
So, we know 4 to 7 is 3.
52 to 91 is 39.
So one is a change in 3. the other is a change is 39.
However, could these be the same, just bigger?
Lets divide the 52 to 91 with a change of 39 by 4 to 7 with a change of 3:
52/4 to 91/7 with a change of 39/3 =
13 to 13 with a change of 13.
So this tells us that the 52 to 91 with a chang eof 3 is 13 times bigger than 4 to 7 with a change of 3.
Hope this helps!
20 POINTS
The function f(x)=45x represents the number of jumping jacks j(x) you can do in x minutes. How many jumpibg jacks can you do in 10 minutes
Answer:
450 jumping jacks
Step-by-step explanation:
f(10) = 45 (10)
45 * 10 is just 450 :)
Answer:
450.
Step-by-step explanation:
f(10) = 45 * 10 = 450 jumping jacks.
Solve for x. ЗХ - 14 = 46
Answer:
Step-by-step explanation:
3x - 14 = 46
+ 14 +14
3x = 60
3x/3 = 60/3
x = 20
Brainliest, 19 points (Running out of points to give)
Answer:
x^2-2x+5
Step-by-step explanation:
5x^2 -4x +8 + -4x^2 +2x -3
Combine like terms
5x^2-4x^2-4x+2x+8-3
x^2-2x+5
8 + (9 · 2 – 3) : 25 – 4 2 : 2
Answer:
14 : -17 : 2
Step-by-step explanation:
8 + (9 · 2 – 3) : 25 – 4 2 : 2
= 14 : -17 : 2
Answer:
- 12.4
Step-by-step explanation:
[tex]8 + \frac{9 * 2 - 3}{25} - \frac{42}{2}[/tex]
[tex]8 + \frac{18 - 3}{25} - 21[/tex]
[tex]8 + \frac{15}{25} - 21[/tex]
[tex]8 + \frac{3}{5} - 21[/tex]
[tex]8 \frac{3}{5} - 21[/tex]
[tex]-12 \frac{2}{5}[/tex]
The surface of an air hockey table has a perimeter of 32 feet its area is 60 ft.what are the dimensions of the air hockey table
(Correct answers only)
A
B
C
Or D
Answer:
Division property of equality
Step-by-step explanation:
7q=49
Divide each side by 7
7q/7 = 49/7
q = 7
How do you perform constructions related to circles? What theorems and explanations can be used to justify these constructions? How do you perform constructions related to circles? What theorems and explanations can be used to justify these constructions?
Answer and explanation:
To construct a circle, draw a line that represents the diameter of the circle. Bisect the line so that it is a perpendicular bisector of the diameter of the circle. Place your compass at the bisection point/midpoint and draw an arc or better still the whole circle.
Theorem: the perpendicular bisector of a chord passes through the center of a circle.
Note: a diameter of a circle is a chord that passes through the center of a circle.
HELP ASAP NEED HELP. WILL GIVE BRAINIEST AND 100 POINTS.
Algebra 1
Use the function f(x) = 4x^2 - 7x - 15 to answer the questions.
Part a: completely factor f(x).
Part b: what are the x-intercepts of the graph of f(x)? Show your work.
Part C: describe the end behavior of the graph of f(x). Explain.
Part D: what are the steps you would use to graph f(x)? Justify that you can use the answers obtained in part B and part C to draw the graph.
Answer:
A: [tex]f(x)=(4x+5)(x-3)[/tex]
B: [tex](-\frac{5}{4} , 0)[/tex] and [tex](3, 0)[/tex]
C: They are parallel, which means they have no endpoint.
work out the circumfrance of this cirlce take pi to be 3.142 and write down all the digits given by your calculator raduis 10cm
Answer:
[tex]C=68.4[/tex]
Step-by-step explanation:
[tex]Circumference=2\pi r[/tex]
Pi = 3.142
r (radius) = 10 cm
[tex]C=2(3.142)(10)[/tex]
[tex]C=(6.84)(10)[/tex]
[tex]C=68.4[/tex]
Therefore, circumference of a circle with 10 cm radius is 68.4.
I hope this helps......
The private school enrolled 1050 new students last year and the number of students enrolled this year decreased to 798.What was the percentage decrease in the number of students enrolled?
Answer:
Step-by-step explanation:
Decreased students = 1050 - 798 = 252
Decreased percentage = (decreased students ÷ number of last year students) * 100
= [tex]\frac{252}{1050}*100[/tex]
= 24%
Answer:
24%
Step-by-step explanation:
% change = [tex]\frac{difference}{original amount}[/tex] x 100
; 1050 - 798 = 252
% change = [tex]\frac{252}{1050}[/tex] x 100
% change = 0.24 x 100
% change = 24
the percentage decrease in the number of students enrolled is 24%
Find the Value of X in this Triangle
Answer:
x = -6
Step-by-step explanation:
All three angles are equal, so all three sides are equal, making this an equilateral triangle
5x+10 = 2x-8
Subtract 2x from each side
5x-2x +10 = 2x-8-2x
3x+10 = -8
Subtract 10 from each side
3x+10-10 = -8-10
3x = -18
Divide by 3
3x/3 = -18/-3
x = -6
Plse help my grades go in tomorrow and I am currently struggling!!
C⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Help please !!!!!!!!’
Step-by-step explanation:
everything can be found in the picture
Translate into an inequality.
Negative nine is greater than or equal to the sum of two-fifths times a number and seven
Answer:
-9 ≥ (2/5x) + 7Step-by-step explanation:
the sign must have a line underneath itself to show that it can be equal and unequal. 2/5 times a number (from my understanding) is 2/5 times a variable, plus 7.
Translation into inequality of negative nine is greater than or equal to the sum of two-fifths times a number, and seven is -9 ≥ (2/5x) + 7.
What is inequality?The relationship between two non-equal values is defined by inequalities. Equal does not mean unequal, though. In most cases, the "not equal sign" is used.
Negative nine is greater than or equal to the sum of two-fifths times a number, and seven can be written as,
-9 ≥ (2/5x) + 7
Therefore, Translation into inequality of negative nine is greater than or equal to the sum of two-fifths times a number, and seven is -9 ≥ (2/5x) + 7.
To know more about inequality:
https://brainly.com/question/2038369
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It cost Josiah $4.48 to send 112 text messages. What is the cost of sending text
messages, in dollars per text?
Answer:
4 cents
Step-by-step explanation:
4.48 divided by 112 = 0.04
If y=-0.8 when x=2 find the y when x=3
Solve the quadratic equation by using a graphic approach. Round your answer to the hundredths place.
x² - 2x - 4= 0
a. x= 3.24 or x = -1.24
c. x = 4.24 or x = -0.24
b. x = 2.73 or x = -0.73
d. x= 5.24or x = -1.24
Pls explain I’m having a hard time understanding the lesson
Answer:
x = 3.24, x = -1.24
Step-by-step explanation:
The standard form for a quadratic equation is [tex]ax^2+bx+c=0[/tex]. For your equation a = 1, b = -2, c = -4. The quadratic formula you will be using is [tex]x=\frac{-b\pm \sqrt{b^{2} -4ac} }{2a}[/tex].
Plug in a = 1, b = -2, and c = -4 into the formula.
[tex]=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-4\right)}}{2\cdot \:1}[/tex]
We'll do the top part first:
[tex]\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-4\right)}[/tex]
Apply rule [tex]- (-a) = a[/tex]
[tex]=\sqrt{\left(-2\right)^2+4\cdot \:1\cdot \:4}[/tex]
Apply exponent rule [tex](-a)^{n} =a^n[/tex] if [tex]n[/tex] is even
[tex](-2)^2=2^2[/tex]
[tex]=\sqrt{2^2+4\cdot \:1\cdot \:4}[/tex]
Multiply the numbers
[tex]=\sqrt{2^2+16}[/tex]
[tex]2^2=4[/tex]
[tex]=\sqrt{4+16}[/tex]
Add
[tex]=\sqrt{20}[/tex]
The prime factorization of 20 is [tex]2^2*5[/tex]
20 divides by 2. 20 = 10 * 2
[tex]=2*10[/tex]
10 divides by 2. 10 = 5 * 2
[tex]=2* \:2*5[/tex]
2 & 5 are prime numbers so you don't need to factor them anymore
[tex]=2*2*5[/tex]
[tex]=2^2*5[/tex]
[tex]=\sqrt{2^2\cdot \:5}[/tex]
Apply radical rule [tex]\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}[/tex]
[tex]=\sqrt{5}\sqrt{2^2}[/tex]
Apply radical rule [tex]\sqrt[n]{a^{n} } =a[/tex]; [tex]\sqrt{2^2} =2[/tex]
[tex]=2\sqrt{5}[/tex]
[tex]=\frac{-\left(-2\right)\pm \:2\sqrt{5}}{2\cdot \:1}[/tex]
Because of the [tex]\pm[/tex] you have to separate the solutions so that one is positive and the other is negative.
[tex]x=\frac{-\left(-2\right)+2\sqrt{5}}{2\cdot \:1},\:x=\frac{-\left(-2\right)-2\sqrt{5}}{2\cdot \:1}[/tex]
Positive x:
[tex]\frac{-\left(-2\right)+2\sqrt{5}}{2\cdot \:1}[/tex]
Apply rule [tex]-(-a)=a[/tex]
[tex]=\frac{2+2\sqrt{5}}{2\cdot \:1}[/tex]
Multiply
[tex]=\frac{2+2\sqrt{5}}{2}[/tex]
Factor [tex]2+2\sqrt{5}[/tex] and rewrite it as [tex]=2\cdot \:1+2\sqrt{5}[/tex]. Factor out 2 because it is the common term. [tex]=2\left(1+\sqrt{5}\right)[/tex].
[tex]=\frac{2\left(1+\sqrt{5}\right)}{2}[/tex]
Divide 2 by 2
[tex]x=1+\sqrt{5}[/tex] or [tex]x=3.24[/tex] (You'll probably have to use a calculator for the square root of 5)
^Repeating the process of positive x for negative x in order to get [tex]x=1-\sqrt{5}[/tex] or [tex]x=-1.24[/tex]
factor the following
(a²+b²)²-18(a²+b²)-88
Answer:
[tex] \rm\displaystyle( {a}^{2} + {b}^{2} - 22)( {a}^{2} + {b}^{2} + 4)[/tex]
Step-by-step explanation:
we would like to factor the following:
[tex] \rm\displaystyle ( {a}^{2} + {b}^{2} {)}^{2} - 18( {a}^{2} + {b}^{2} ) - 88[/tex]
let a²+b²=x
thus substitute:
[tex] \rm\displaystyle x {}^{2} - 18x- 88[/tex]
rewrite the middle term as 4x-22x:
[tex] \rm\displaystyle x^{2} + 4x - 22x - 88[/tex]
factor out x:
[tex] \rm\displaystyle x( x^{} + 4)- 22x - 88[/tex]
factor out -22:
[tex] \rm\displaystyle x( x^{} + 4)- 22(x + 4)[/tex]
group:
[tex] \rm\displaystyle( x- 22)(x + 4)[/tex]
substitute back:
[tex] \rm\displaystyle( {a}^{2} + {b}^{2} - 22)( {a}^{2} + {b}^{2} + 4)[/tex]
and we are done!
Find the number from which (– 66) is subtracted to get a difference of 100.
Answer:
-166
Step-by-step explanation:
Given that a*b = 2a - 3b, then 2*(-3) =
Answer:
2*(-3)= -6
Step-by-step explanation:
I do not see how "a*b=2a-3b" would change the fact 2 times negative 3 is -6
The manufacturer id number for proctor and gamble is (037000) and the item number for a box of bounce fabric softener is (80049). What is the valid upc? A- 0-37000-80049-9 B-0-37000-80049-1 C-1-37000-80049-1 D-1-80049-37000-0
Answer:
A. [tex]UPC = 0-03700-80049-9[/tex]
Step-by-step explanation:
Given
[tex]ID = 037000[/tex]
[tex]Item\ Number = 80049[/tex]
Required
The valid UPC
First, the UPC is represented as:
UPC = ID followed by item number followed by the checksum
So, we have:
[tex]upc = 0-03700-80049-X[/tex]
To calculate X (the checksum)
Add up digits at odd positions
[tex]Odd = (0 + 7 + 0) + (8 + 0 + 9)[/tex]
[tex]Odd = 24\\[/tex]
Multiply by 3
[tex]Product = Odd * 3[/tex]
[tex]Product = 24 * 3[/tex]
[tex]Product = 72[/tex]
Add up digits at even positions
[tex]Even = (3 + 0 + 0) + (0 + 4)[/tex]
[tex]Even = 7[/tex]
Add the product and the sum of even
[tex]Result = Product + Even[/tex]
[tex]Result = 72+7[/tex]
[tex]Result = 79\\[/tex]
The last digit of the UPC is 9.
Hence, the UPC is:
[tex]UPC = 0-03700-80049-9[/tex]
please help me!!!!! i need help with this, very urgent! ASAP
Step-by-step explanation:
QR--DE
RS--- EF
RQ-----DE
If two lines are intersected by a third line, is the third line necessarily a transversal?
No, The third line does not necessarily be a transversal.
What is Equation of line?
The equation of line with slope 'm' and y intercept at point 'b' is given as;
⇒ y = mx + b
Given that;
Two lines intersected by a third line.
Since, When two lines are parallel to each other and two lines intersected by a third line then, third lines are transversal.
So, Here it is not given two lines are parallel.
Thus, Third line is not necessarily a transversal.
Hence, The third line does not necessarily be a transversal.
Learn more about the transversal visit:
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Alex’s paycheck for the last two weeks totaled $239.64. He owes the cell phone company $44.87. How much money does he have left
Answer:
the answer would be 193.77
Step-by-step explanation:
literally, subtract 45.87 from 239.64.
you get 193.77.
(you put 44 instead of 45, so the sum with 44 would be 194, that is incorrect.)
Una caja en forma de prisma rectangular tiene 10cm3 de volumen.Si la longitud de cada arista se multiplica por 4, ¿cual sera el volumen de la caja?
Can someone tell the answer, no one else seemed to know it.
Answer:
it is right bro x+ 2 .......mark me brainiest please
The width of a rectangle is 5 3/4 inches. The length is three times its width. What is the perimeter?
Answer:
perimeter=46.5 inches
Step-by-step explanation:
[tex]width=2\frac{3}{4}[/tex]
[tex]=\frac{5*4+3}{4}[/tex]
=[tex]=\frac{23}{4}[/tex]
[tex]length=3(\frac{23}{4} )[/tex]
[tex]=\frac{23*3}{4}[/tex]
=[tex]\frac{69}{4}[/tex]
perimeter of rectangle =2(l+b)
[tex]=2(\frac{69}{4} +\frac{24}{4} )[/tex]
[tex]=2(\frac{69+24}{4} )[/tex] (since their denominator are same u can add their numerator)
[tex]=2(\frac{93}{4})[/tex]
[tex]=\frac{93*2}{4}[/tex]
[tex]=\frac{186}{4}[/tex]
[tex]=46.5[/tex] inches
Write an equation to model the given scenario, then solve:
Each year the local country club sponsors a tennis tournament. Play starts with 128 participants. During each
round, half of the players are eliminated. How many players remain after 5 rounds?
Given:
Initial number of participants = 128
During each round, half of the players are eliminated.
To find:
The number of players remain after 5 rounds.
Solution:
It is given that, the initial number of participants is 128 and during each round, half of the players are eliminated.
If half of the players are eliminated, then half of the players are remained.
So, the initial value is 128 and the decay factor is [tex]\dfrac{1}{2}[/tex].
The general exponential decay model is:
[tex]y=a(b)^x[/tex]
Where, a is the initial value and b is the decay factor.
Putting [tex]a=128[/tex] and [tex]b=\dfrac{1}{2}[/tex] in the above model, we get
[tex]y=128\left(\dfrac{1}{2}\right)^x[/tex]
Here, y is the number of remaining players after x rounds.
Substituting [tex]x=5[/tex], we get
[tex]y=128\left(\dfrac{1}{2}\right)^5[/tex]
[tex]y=128\left(\dfrac{1}{32}\right)[/tex]
[tex]y=4[/tex]
Therefore, the required model is [tex]y=128\left(\dfrac{1}{2}\right)^x[/tex] and the number of players remain after 5 rounds is 4.
When should a heart rate monitor be used?
Answer:
There are two simple, compelling reasons to use a heart-rate monitor: to train and race at the best pace for you. The table below shows you how to find your perfect paces for: (1) the three most important workouts in any training program; and (2) the four most popular road-race distances.
Step-by-step explanation:
Hope this helps :)
