In the morning 134 books were checked out from the library.in the afternoon 254 books were checked out and 188 books were checked out in the evening.how many books were checked out in the library that day?

Answer: -8

Step-by-step explanation:

When the input is 4, according to the input-output table, the output is -8.

Plugging 4 into the function f(x) = 2x - 10 directly also gives the same result:

f(4) = 2(4) - 10 = 8 - 10 = -2

So the output of William's function when the input is 4 is -8.

The possible expression that can be a rule for the number sequence is:[tex]$a_n = 4n + 1$[/tex],

As an illustration, the expression x + y is one where x and y are words with an addition operator in between. There are two types of expressions in mathematics: numerical expressions, which only comprise numbers, and algebraic expressions, which also include variables.

One possible expression that can be a rule for the number sequence is:

[tex]$a_n = 4n + 1$[/tex], where n is the position of the term in the sequence.

Using this expression, we can find the values of the first few terms as follows:

[tex]$a_1 = 4(1) + 1 = 5$[/tex]

[tex]$a_2 = 4(2) + 1 = 9$[/tex]

[tex]$a_3 = 4(3) + 1 = 13$[/tex]

[tex]$a_4 = 4(4) + 1 = 17$[/tex]

[tex]$a_5 = 4(5) + 1 = 21$[/tex]

Thus, possible expression that can be a rule for the number sequence is:[tex]$a_n = 4n + 1$[/tex],

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Answer:

5n, where n is equal to 0, 1, 2, 3, 4

Step-by-step explanation:

5, 9, 13, 17, 21,

Answer:

36

Step-by-step explanation:

The classification of student class designation (freshman, sophomore, junior, senior) is an example of a categorical random variable.  The correct option is A.

A random variable is a numerical or categorical quantity whose value is unknown but whose behavior can be forecast based on data that has been measured or observed. Random variables are typically used to represent quantities that fluctuate over time or are subject to chance occurrences.

The types of random variables are as follows:

i) Categorical random variable: This type of variable contains categorical data or data that are descriptive in nature. It is used to classify items or events into categories, which can be named or identified. For example, a set of data that includes categories like gender, eye color, or country of origin.

ii) Discrete random variable: This type of variable takes on discrete values, which means it can only take on whole numbers. For example, the number of cars sold at a dealership on any given day is a discrete random variable because it can only take on integer values.

iii) Continuous random variable: This type of variable takes on continuous values, which means it can take on any value within a given range. For example, the temperature in a room can take on any value between a certain minimum and maximum value.

Therefore, the correct option is A.

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The hotel served 306 gallons of orange juice this year.

To find the amount of orange juice served this year, we need to add 70% more of the amount served last year to the amount served last year. Let's denote the amount served last year as "x". Then we can set up the equation:

Simplifying this equation gives us:

We know from the problem that the amount served last year was 180 gallons. Plugging this into our equation, we get:

Simplifying this equation gives us:

Therefore, the hotel served 306 gallons of orange juice this year.

In summary, we used the information given in the problem to set up an equation and solve for the amount of orange juice served this year. We first found the amount served last year, and then added 70% more of that amount to get the total amount served this year.

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The equation of the line perpendicular to y = 1/3x - 9 that passes through the point (-6, 10) is y = -3x - 8.

The given equation is in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.

So, we can see that the slope of the given line is 1/3.

A line perpendicular to this line will have a slope that is the negative reciprocal of the slope of the given line.

The negative reciprocal of 1/3 is -3.

Now, we have the slope of the perpendicular line and a point that it passes through. We can use point-slope form to find the equation of the line.

Point-slope form, y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope.

Substituting the values we have

y - 10 = -3(x - (-6))

y - 10 = -3(x + 6)

y - 10 = -3x - 18

y = -3x - 8

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The given question is incomplete, the complete question is:

Write the equation of a line perpendicular to y = 1/3x - 9 that passes through the point (-6, 10)

New points of graph A'B'C'D' are A'(-2, -2), B'(-2, 0), C'(-4, 0), D'(-4, -1)

In graph theory, the term "translation" refers to a type of operation that moves all the vertices and edges of a graph by a fixed distance in a given direction. Specifically, a translation of a graph involves shifting every vertex a certain distance horizontally and/or vertically, without changing the shape or connectivity of the graph.

Translation: 4 left and 2 down

Start with a point at its original location and then move it 4 units to the left and 2 units down. This can be done by subtracting 4 from the x-coordinate and subtracting 2 from the y-coordinate of the point or shape.

Given points in a graph ABCD are, A(2, 0), B(2, 2), C(0, 2), D(0, 1)

Subtract 4 from the x-coordinate and subtract 2 from the y-coordinate, resulting in a new points of graph A'B'C'D' are A'(-2, -2), B'(-2, 0), C'(-4, 0), D'(-4, -1)

The figure shown in below diagram.

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Answer:

Size 3 ‍♀️

Step-by-step explanation:

In the US, the average shoe size for 10-Year-Old is USA Size 3.

-Jul 12, 2020

Julie will have driven a total distance of 289 miles if she travels from York to Corby via Derby.

Starting from York, Julie needs to travel to Derby. The distance between York and Derby is given as 89 miles. So, we know that Julie will have driven 89 miles once she reaches Derby.

Next, Julie needs to travel from Derby to Corby, but the given information is a bit tricky here. The distance from Derby to Corby is not given directly. Instead, we are given two distances - Derby to Dory and Dory to Corby.

To find the distance from Derby to Corby, we need to add the distances between Derby and Dory, and Dory and Corby. From the question, we know that the distance between Derby and Dory is 127 miles and the distance between Dory and Corby is 73 miles. Adding these two distances gives us the total distance from Derby to Corby, which is 200 miles.

Finally, we can add up the distances traveled between each location to find the total distance traveled by Julie. Adding the distances of each leg of the journey, we get:

89 miles (York to Derby) + 200 miles (Derby to Corby via Dory) = 289 miles

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Complete Question:

If Julie drives from York to Corby via Dory how many miles will she have driven?

York 89

Derby 127 73

Corby

Answer:

D. -1/8

Step-by-step explanation:

Look at the coordinates on the graph

(-4,8)

(-2,1)

(0,0)

(2,-1)

(4,-8)

These will correspond to

y = kx^3

=> k = y/x^3

When you substitute the coordinates, you find k = -1/8

y = -1/8x^3

Answer:

$196

Step-by-step explanation:

1 lb = 16oz

28 lbs x 16 = 448 ozs (in 28 lb bag)

448/8 = 56 (8 oz portions)

56 x $3.50= $196

The length of the third side of the actual patio is 15.75 feet.

In order to solve issues requiring proportional connections between the sides of two triangles, it is crucial to understand the idea of triangle similarity. If the matching sides and angles of two triangles are identical, then two triangles are said to be similar. When referring to similarities, the symbol is used.

Let us suppose the length of third side = x.

Given that, blueprint of a triangular patio has side lengths 3.5 in., 3.5 in., and 5.25 in.

Thus, the blueprint and the actual patio form two similar triangles.

The sides of the similar triangles are equal in ratio thus,

3.5/5.25 = 10.5/x

3.5x = 5.25 * 10.5

x = (5.25 * 10.5) / 3.5

x = 15.75

Hence, the length of the third side of the actual patio is 15.75 feet.

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The area of the quadrilateral is 161.24 cm².

We can see that we can divide the quadrilateral into two triangles: ABD and CBD. We know that the height of ABD is 6 cm and the height of CBD is 8 cm. We also know that BD is 15 cm. To find the area of each triangle, we need to find the base of each triangle. We can do this using the Pythagorean theorem.

For triangle ABD:

AB² = AD² + BD²

AB² = (6 cm)² + (15 cm)²

AB² = 261 cm²

AB = [tex]\sqrt(261) cm[/tex]

For triangle CBD:

BC² = CD² + BD²

BC² = (8 cm)² + (15 cm)²

BC² = 289 cm²

BC = 17 cm

Now we can find the areas of the triangles:

Area of ABD =[tex]\frac{1}{2}[/tex] * AB * 6 cm

Area of ABD = [tex]\frac{1}{2}[/tex] * [tex]\sqrt(261) cm[/tex] * 6 cm

Area of ABD = 93.24 cm^2

Area of CBD = [tex]\frac{1}{2}[/tex] * BC * 8 cm

Area of CBD = [tex]\frac{1}{2}[/tex] * 17 cm * 8 cm

Area of CBD = 68 cm²

Finally, we can find the area of the quadrilateral by adding the areas of the triangles:

Area of ABCD = Area of ABD + Area of CBD

Area of ABCD = 93.24 cm² + 68 cm²

Area of ABCD = 161.24 cm²

Therefore, the area of the quadrilateral is 161.24 cm².

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The scientific and standard notation and clue obtained from the clue sheet are;

1. Name starts with; J

2. Difference = 145 million miles = Weight = 145 lbs

3. Height: 5 ft, 6 in

4. I. 2.54 × 10⁸ miles corresponding to letter I

II. 0.0005825 corresponds to letter G

III. 5.0432 × 10⁶ corresponds to letter N

IV. 1.547 × 10³ corresponds to letter R

V. 4.977 × 10⁻² corresponds to letter W

VI. 1.3 × 10¹⁰ light years away; corresponds to letter D

VII. 5.04 × 10⁻⁵ corresponds to letter A

The suspects hubby is DRAWING

Scientific notation is a format used to express very large or very small numbers such that they are much easier to work with. The scientific notation format is; a × 10ⁿ, where; a is the coefficient, which is a number between 1 and 10 (10 excluded), and n is an integer.

1. G = (6.07 × 10⁷)/(7.035 × 10³) ≈ 8628.29

J = (6.03 × 10⁻³)/(5.05 × 10⁻⁷) ≈ 11940.59

Therefore; J > G

The suspects name starts with J

2. The distance the telescope in the laboratory allows the viewer to see = 1.5 × 10⁹ miles away

The distance the other telescope a few hours away allows the viewer to see = 1.355 × 10⁹ miles away

The difference between the distances = (1.5 - 1.355) × 10⁹ miles = 1.45 × 10⁸ miles

The difference in the distance is 1.45 × 10⁸ miles = 145 million miles

The suspect weight is 145 lbs

3. The numbers are;

Feet; 532.063 × 10³ = 5.32063 × 10⁵

Inches; 5,030,045 = 5.030045 × 10⁶

The height of the suspect is 5 feet 6 inches (5'6'') = 5.5 feet

Height; = 5 ft, 6 in

4. I. The difference in distances between Earth and Saturn can be found as follows;

The difference in the distances = (1000 - 746) million miles = 254 million miles apart

Scientific notation is the expression of numbers in the form consisting of a number between 1 and 10, multiplied by 10 raised to a power

254 million miles = 2.54 × 10⁸ miles

The corresponding letter from the code cracker is; I

II Standard notation is the expression of numbers in the standard form without the use of exponents or special symbols

The number 5.825 × 10⁻⁴ in standard notation is; 0.0005825

The corresponding letter from the code cracker is; G

III. The number 504.32 × 10⁴ in scientific notation can be obtained by moving the decimal point two places to the left followed by increasing the index of 10 by 2 as follows;

504.32 × 10⁴ = 5.0432 × 10⁶

The corresponding letter from the code cracker is; N

IV. The sum of the numbers 1.202 × 10³ and 3.45 × 10² can be obtained by expressing both numbers to the same power of 10 as follows;

1.202 × 10³ + 3.45 × 10² = 12.02 × 10² + 3.45 × 10² = 15.47 × 10²

15.47 × 10² = 1.547 × 10³

Therefore; 1.202 × 10³ + 3.45 × 10² = 1.547 × 10³

The corresponding letter from the code cracker is; R

V. The difference of the numbers can be obtained as follows;

5.023 × 10⁻² - 4.6 × 10⁻⁴ = 502.3 × 10⁻⁴ - 4.6 × 10⁻⁴ = 497.7 × 10⁻⁴

497.7 × 10⁻⁴ = 4.977 × 10⁻²

Therefore; 5.023 × 10⁻² - 4.6 × 10⁻⁴ = 4.977 × 10⁻²

The corresponding letter from the code cracker is; W

VI. 13 billion light years = 13 × 10⁹ light years = 1.3 × 10¹⁰ light years

The distance a standard telescope can allow to be seen is 1.3 × 10¹⁰ light years away

The corresponding letter from the code cracker is; D

VII. 0.0000504 in scientific notation is; 5.04 × 10⁻⁵

The corresponding letter from the code cracker is; A

IGNRWDA

The suspects favorite hubby is DRAWING

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Based on the following sorted 20 values for age, the possible split points are {20, 21, 23, 25, 27, 29. 5, 31. 5, 32. 5, 34, 37. 5, 41, 42. 5, 44, 46, 48, 49. 5, 51, 52, 54, 56} (option a).

Option A suggests that the split points are {20, 21, 23, 25, 27, 29.5, 31.5, 32.5, 34, 37.5, 41, 42.5, 44, 46, 48, 49.5, 51, 52, 54, 56}. Notice that every split point falls between two consecutive ages in the original list. For example, the first split point is 20 because it is between 20 and 22. The second split point is 21 because it is between 20 and 22 as well.

Option B suggests that the split points are {21, 23, 25, 27, 29.5, 31.5, 32.5, 34, 37.5, 41, 42.5, 44, 46, 48, 49, 51, 52.5, 54, 56, 57}. Notice that the only difference between this option and Option A is that the last split point is 57 instead of 49.5.

Option C suggests that the split points are {0, 21, 23, 25, 27, 29.5, 31.5, 32.5, 34, 37.5, 41, 42.5, 44, 46, 48, 49, 51, 52.5, 54, 56}. Notice that the first split point is 0, which is not a possible age in the original list.

Option D suggests that the split points are {21, 23, 25, 27, 29.5, 31.5, 32.5, 34, 37.5, 41, 42.5, 44, 46, 48, 49.5, 51, 52.5, 54, 56}. Notice that the only difference between this option and Option A is that the split point after 49 is 49.5 instead of 49.5.

In summary, the correct answer is Option A because it provides all the possible split points that fall between the ages in the original list. When working with split points, it's important to consider the specific context and criteria for dividing the data.

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Answer: Not D

Step-by-step explanation:

Answer not available, but it is definitely not D.

Your welcome.

The expression's value is when x 0, and since |x| = -x when x 0, x + |x| simplifies to 0. In this case, x + |x| = x + (-x) = 0 for x 0.

When the variables and constants in a mathematical expression are given values, the outcome of the computation it describes is the expression's value. The value of a function, given the value(s) assigned to its argument, is the sum that the function assumes for these input values (s).

For x =7,x+|x| =7+|7| =14

For x =10,x+|x|= 10+|10| =20

For x = 0,x+|x| =0+|0| =0

For x = -3, x + |x| = -3 + |-3| = 0

For x = -8, x + |x| = -8 + |-8| = 0

The expression's value is when x 0, and since |x| = -x when x 0, x + |x| simplifies to 0. In this case, x + |x| = x + (-x) = 0 for x 0.

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The B) constant variance assumption requires that all variation around the regression line should be equal at all possible values (levels) of the independent variable.

The constant variance assumption, also known as homoscedasticity, requires that the variance of the residuals (i.e., the differences between observed and predicted values) should be approximately the same across all levels of the independent variable.

This assumption is necessary for valid statistical inference in linear regression analysis because violations of constant variance can result in biased estimates of the regression coefficients and incorrect hypothesis tests.

The independent variable is the variable that is used to predict the dependent variable. The constant variance assumption applies to the residuals at all possible values of the independent variable. Therefore, the correct answer is B. constant variance, independent.

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There are 48 toy soldiers, which is 6 x 8 of them.

The anger Eminem expresses in "Like Toy Soldiers" is a result of his personal beefs with rappers Ja Rule and Benzino, who was the editor of The Source at the time. The song, "Toy Soldiers," by Martika, was sampled on the 2004 release Encore.

Let's name Leo's collection of toy soldiers "x" the amount.

As a result of the problem statement, we are aware of:

There are no more when he arranges them in groups of four, proving that x is divisible by four.

Six remain after he divides them into groups of seven, proving that (x - 6) is divisible by seven.

He organizes them into fives. If there are still 3 after multiplying by 5, (x - 3) can be divided by 5.

We may create a system of equations based on these three conditions:

x = 4a (from the first condition)

x - 6 = 7b (from the second condition)

x - 3 = 5c (from the third condition)

where a, b, and c are integers.

4a - 6 = 7b

4a - 3 = 5c

Now we need to solve for a, b, and c.

7b = 4a - 6

7b + 6 = 4a

Since 7 and 4 are relatively prime, we know that (7b + 6) must be divisible by 4. Therefore, we can write:

7b + 6 = 4k

where k is some integer. Solving for b, we get:

b = (4k - 6) / 7

Since b is an integer, k must be 2, which gives us:

b = (4(2) - 6) / 7 = -1

We can try the next possible value of k, which is 3:

b = (4(3) - 6) / 7 = 0

x - 3 = 5c

6 - 3 = 5c

c = 1

6 divided by 4 is 1 with no remainder.

(6 - 6) divided by 7 is 0 with a remainder of 0.

(6 - 3) divided by 5 is 1 with a remainder of 0.

Therefore, the answer is 48, which is 6 times 8.

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the simplified expression is 129.

To simplify the expression 8² + 9(12 ÷ 3 × 2) - 7, we follow the order of operations, which is:

Parentheses (do the calculations inside parentheses first)

Exponents (do the calculations involving exponents)

Multiplication and Division (do these operations from left to right)

Addition and Subtraction (do these operations from left to right)

Using these rules, we can simplify the expression step by step as follows:

8² + 9(12 ÷ 3 × 2) - 7 (Apply parentheses first)

= 8² + 9(4 × 2) - 7 (Evaluate 12 ÷ 3 as 4 and then 4 × 2 as 8 inside the parentheses)

= 8² + 9(8) - 7 (Evaluate 9 times 8 as 72)

= 64 + 72 - 7 (Evaluate 8² as 64)

= 129 (Perform the final subtraction and add the remaining terms)

Therefore, the simplified expression is 129.

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The sum of the angles of an N-sided convex figure is (n-2)*180 - a simple proof of which is just to decompose the figure into triangles, each of which has all of its vertices the same as three of the vertices of the original figure. (Cut a quadrilateral into two triangles along a diagonal, for instance).

So, a 7-sided figure has angles totaling 5*180 = 900. Now set up a simple equation:

3x + 4(x+15) = 900

7x + 60 = 900

7x = 840

x = 120

The figure has three angles of 120 degrees, and four angles of 135 degrees.

Let a sample space be partitioned into three mutually exclusive and exhaustive events, B1, B2, and, B3.We have to complete the following probability table, prior probabilities, conditional probabilities, joint probabilities, and posterior probabilities, and also we have to round our answers to 2 decimal places.

Given information:Probability of B1, P(B1) = 0.11 Probability of A given B1, P(A | B1) = 0.45 Probability of A intersection B1, P(A ∩ B1) = ?

Probability of B1 given A, P(B1 | A) = ?     Probability of B2, P(B2) = ?     Probability of A given B2, P(A | B2) = 0.62, Probability of A intersection B2,  P(A ∩ B2) = ?     Probability of B2 given A, P(B2 | A) = ?

Probability of B3, P(B3) = 0.38.    Probability of A given B3, P(A | B3) = 0.85.   Probability of A intersection B3,

P(A ∩ B3) = ?

Probability of B3 given A, P(B3 | A) = ?

Total probability of A, P(A) = ?

Total probability of sample space = 1.     Let's complete the probability table:Prior probabilities, Conditional probabilities, Joint probabilities, Posterior probabilities      P(B1) = 0.11P(A | B1) = 0.45P(A ∩ B1) = P(A | B1) * P(B1) / P(A)P(B1 | A) = P(A | B1) * P(B1) / P(A)P(B2) = 1 - (P(B1) + P(B3)) = 1 - (0.11 + 0.38) = 0.51P(A | B2) = 0.62P(A ∩ B2) = P(A | B2) * P(B2) / P(A)P(B2 | A) = P(A | B2) * P(B2) / P(A)P(B3) = 0.38P(A | B3) = 0.85P(A ∩ B3) = P(A | B3) * P(B3) / P(A)P(B3 | A) = P(A | B3) * P(B3) / P(A)Total = 1P(A) = P(A ∩ B1) + P(A ∩ B2) + P(A ∩ B3) = 0.11 * 0.45 + 0.51 * 0.62 + 0.38 * 0.85 = 0.6579.  So, the probability table is as follows:Prior probabilities,Conditional probabilities,Joint probabilities,Posterior probabilities

P(B1) = 0.11P(A | B1) = 0.45P(A ∩ B1) = 0.0495P(B1 | A) = 0.3419P(B2) = 0.51P(A | B2) = 0.62P(A ∩ B2) = 0.3162P(B2 | A) = 0.4857P(B3) = 0.38P(A | B3) = 0.85P(A ∩ B3) = 0.3217P(B3 | A) = 0.1724Total = 1P(A) = 0.6579

Hence, the completed probability table is as shown above.

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The temperature of the cup of water is approximately 180°F after 6 minutes.

Using the given formula, we can write:

T = Ta + (To - Ta) * e^(-kt)

where Ta = 73°F (the temperature of the room), To = 201°F (the initial temperature of the water), and T = 189°F (the temperature of the water after 3 minutes).

We can solve for the decay constant k as follows:

(T - Ta) / (To - Ta) = e^(-kt)

ln[(T - Ta) / (To - Ta)] = -kt

k = -ln[(T - Ta) / (To - Ta)] / t

Substituting the given values, we get:

k = -ln[(189°F - 73°F) / (201°F - 73°F)] / 3 minutes

k = -ln[116 / 128] / 3 minutes

k ≈ 0.0434 minutes^-1 (rounded to the nearest thousandth)

Now we can use this value of k to find the temperature of the water after 6 minutes:

T = Ta + (To - Ta) * e^(-kt)

T = 73°F + (201°F - 73°F) * e^(-0.0434 minutes^-1 * 6 minutes)

T ≈ 180°F (rounded to the nearest degree)

Therefore, the temperature of the cup of water is approximately 180°F after 6 minutes.

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Therefore, with a 95% confidence interval, we can estimate the true mean length of the drive shafts to be between 992.16 mm and 1007.84 mm.

The true mean length of the drive shafts can be estimated using a 95% confidence interval. The margin of error is calculated as 2*1.96*2 = 7.84 mm. The lower bound of the confidence interval is 1000 - 7.84 = 992.16 mm and the upper bound is 1000 + 7.84 = 1007.84 mm.

This confidence interval states that there is a 95% probability that the true mean length of the drive shafts falls within the range of 992.16 mm to 1007.84 mm. The relationship between the two probabilities is that the probability of the true mean length falling within the confidence interval is 95%. If the sample size was increased, the margin of error would decrease, resulting in a tighter range and higher probability that the true mean would fall within the confidence interval.
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Number of cylindrical cans of paint does he need to paint 75 ​ornaments is 20.

The total area that the cylinder's curved surface and round bases enclose is referred to as its surface area. The cylinder's total surface area consists of the curving surface as well as the areas of the two bases, each of which is shaped like a circle. A cylinder is a 3D solid object made up of two circular bases connected by a curving face.

Surface Area of Cylinder = 2πrh+2πr²

where , r is radius of cylinder=4.6cm

H is height of cylinder=2*6.5cm=13cm

A=2×π×4.6×13+2×π×4.6²≈508.68668cm²

Total Number of cans of paint needed to paint 75 ​ornaments=75×508.68668

/1900=20.

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The probability that at least 2 people believe that they have seen a ufo is 0.1937102445. The probability that exactly 1 person believes that he or she has seen a ufo is problem: P(X = 1) = 10C₁ (0.10) (0.90)⁹= 0.3874204890.

The probability that at least 2 people believe that they have seen a UFO would be 0.1937102445. For this we use the binomial distribution formula.

P(X ≥ 2) = 1 − P(X = 0) − P(X = 1)P(X = 0) = (9/10)¹⁰

P(X = 1) = 10C₁ (0.10) (0.90)⁹= 0.3874204890 (rounded to 10 decimal places)

P(X ≥ 2) = 1 − 0.3874204890 − 0.3486784401 = 0.1937102445 (rounded to 10 decimal places)

The probability that 2 or 3 people believe that they have seen a UFO would be 0.1937102445. Using the formula of binomial distribution again we can solve for the probability of this event.

P(2 ≤ X ≤ 3) = P(X = 2) + P(X = 3)P(X = 2) = 10C₂ (0.10)² (0.90)⁸= 0.1937102445 (rounded to 10 decimal places)

P(X = 3) = 10C₃ (0.10)³ (0.90)⁷= 0.0573956280 (rounded to 10 decimal places)

P(2 ≤ X ≤ 3) = 0.1937102445 + 0.0573956280 = 0.2511058725 (rounded to 10 decimal places)

The probability that exactly 1 person believes that he or she has seen a UFO would be 0.3874204890. Using the binomial distribution formula to solve this problem:

P(X = 1) = 10C₁ (0.10) (0.90)⁹= 0.3874204890 (rounded to 10 decimal places)

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The length οf line FG is 12 cm, If  Figure EFGH is a parallelοgram.

A parallelοgram is a type οf quadrilateral with twο pairs οf parallel sides. The οppοsite sides οf a parallelοgram are equal in length and parallel tο each οther.

Since EFGH is a parallelοgram, we knοw that the οppοsite sides are parallel and equal in length. Therefοre, the length οf line FG is equal tο the length οf line EH.

We can find the length οf EH by using the Pythagοrean theοrem οn right triangle EFG:

[tex]EF^2 + FG^2 = EG^2[/tex]

Since EF = 5 cm, EG = 13 cm, and angle FEG is a right angle (as οppοsite angles in a parallelοgram are equal), we can sοlve fοr FG:

[tex]FG^2 = EG^2 - EF^2[/tex]

[tex]FG^2 = 13^2 - 5^2[/tex]

[tex]FG^2 = 144[/tex]

[tex]FG = \sqrt{(144)[/tex]

[tex]FG = 12 cm[/tex]

Therefοre, the length οf line FG is 12 cm.

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Answer:

We can use the formula for compound interest to solve the problem:

A = P(1 + r/n)^(nt)

where A is the final amount, P is the principal, r is the annual interest rate, n is the number of times interest is compounded per year, and t is the number of years.

In this case, we know that P = $2,000, A = $6,883.55, n = 4 (quarterly compounding), and t = 16. We can solve for r by rearranging the formula as follows:

r = n[(A/P)^(1/nt) - 1]

Substituting the values, we get:

r = 4[(6,883.55/2,000)^(1/(4*16)) - 1] = 0.0522 or 5.22%

Therefore, the annual interest rate is approximately 5.22%