Answer:
75.7m^2
Step-by-step explanation:
[tex] \frac{30}{360} \times \pi {r}^{2} \\ \frac{30}{360} \times \frac{22}{7} \times {17}^{2} \\ \frac{1}{12} \times \frac{22}{7} \times 289 \\ 75.6904761905 = 75.7[/tex]
describe when it is and when it is not necessary to use a common denominator when adding, subtracting, multiplying, and dividing rational expressions.
Step-by-step explanation:
For Adding and Subtraction:
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator).
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.3. Find the new numerator (top number) for each fraction. To find the new numerators for each fraction, compare the denominator of each of the original fractions to the LCD and write down everything different about the LCD in the numerator of the fraction. (you should also consider using the letters "LCD" in the denominator instead of the actual LCD as it will be less tempting to reduce them).
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.3. Find the new numerator (top number) for each fraction. To find the new numerators for each fraction, compare the denominator of each of the original fractions to the LCD and write down everything different about the LCD in the numerator of the fraction. (you should also consider using the letters "LCD" in the denominator instead of the actual LCD as it will be less tempting to reduce them). 4. combine the fraction by adding or subtracting the numerators and keeping the LCD. When subtracting, notice that the subtraction sign is moved into the numerator so it can be distributed later if needed.
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.3. Find the new numerator (top number) for each fraction. To find the new numerators for each fraction, compare the denominator of each of the original fractions to the LCD and write down everything different about the LCD in the numerator of the fraction. (you should also consider using the letters "LCD" in the denominator instead of the actual LCD as it will be less tempting to reduce them). 4. combine the fraction by adding or subtracting the numerators and keeping the LCD. When subtracting, notice that the subtraction sign is moved into the numerator so it can be distributed later if needed. 5. simplify the numerator by distributing and combining like terms.
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.3. Find the new numerator (top number) for each fraction. To find the new numerators for each fraction, compare the denominator of each of the original fractions to the LCD and write down everything different about the LCD in the numerator of the fraction. (you should also consider using the letters "LCD" in the denominator instead of the actual LCD as it will be less tempting to reduce them). 4. combine the fraction by adding or subtracting the numerators and keeping the LCD. When subtracting, notice that the subtraction sign is moved into the numerator so it can be distributed later if needed. 5. simplify the numerator by distributing and combining like terms. 6. Factor the numerator if can and replace the letters "LCD" with the actual LCD.
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.3. Find the new numerator (top number) for each fraction. To find the new numerators for each fraction, compare the denominator of each of the original fractions to the LCD and write down everything different about the LCD in the numerator of the fraction. (you should also consider using the letters "LCD" in the denominator instead of the actual LCD as it will be less tempting to reduce them). 4. combine the fraction by adding or subtracting the numerators and keeping the LCD. When subtracting, notice that the subtraction sign is moved into the numerator so it can be distributed later if needed. 5. simplify the numerator by distributing and combining like terms. 6. Factor the numerator if can and replace the letters "LCD" with the actual LCD. 7. simplify or reduce the rational expression of you can. Remember, to reduce rational expressions, the factors must be exactly the same in both the numerator and the denominator.
To Multiply:
first determine the GCF of the numerator and denominator. Then, regrouping the fractions to make fractions equal to One. Then, multiply any remaining factors.To Divide:
First, rewriting the division as multiplication by the reciprocal of the denominator. The remaining steps are the same for multiplication.9514 1404 393
Answer:
necessary: addition and subtractionnot necessary: multiplication and divisionStep-by-step explanation:
For multiplication and division, the denominator of the result is developed as part of the algorithm for performing these operations on rational expressions. For example, ...
(a/b)(c/d) = (ac)/(bd)
(a/b)/(c/d) = (ad)/(bc)
It is not necessary to make the operands of these operations have a common denominator before the operations are performed. That being said, in some cases, the division operation can be simplified if the operands do have a common denominator or a common numerator:
(a/b)/(c/b) = a/c
(a/b)/(a/c) = c/b
__
If the result of addition or subtraction is to be expressed using a single denominator, then the operands must have a common denominator before they can be combined. That denominator can be developed "on the fly" using a suitable formula for the sum or difference, but it is required, nonetheless.
(a/b) ± (c/d) = (ad ± bc)/(bd)
This formula is equivalent to converting each operand to a common denominator prior to addition/subtraction:
[tex]\dfrac{a}{b}\pm\dfrac{c}{d}=\dfrac{ad}{bd}\pm\dfrac{bc}{bd}=\dfrac{ad\pm bc}{bd}[/tex]
Note that the denominator 'bd' in this case will not be the "least common denominator" if 'b' and 'd' have common factors. Even use of the "least common denominator" is no guarantee that the resulting rational expression will not have factors common to the numerator and denominator.
For example, ...
5/6 - 1/3 = 5/6 -2/6 = 3/6 = 1/2
The least common denominator is 6, but the difference 3/6 can still be reduced to lower terms.
If we were to use the above difference formula, we would get ...
5/6 -1/3 = (15 -6)/18 = 9/18 = 1/2
Convert the following equation into slope-intercept form.
x-26y=52
2^5 + 10=?????????????
Answer:
Answer is 42
Step-by-step explanation:
2^5 + 10
2*2*2*2*2 + 10
32 + 10
42
1. Find the length of X (in the picture) plssss I need help.
Step-by-step explanation:
[tex] \frac{5}{4} = \frac{x}{6} \\ 4x = 30 \\ x = 7.5[/tex]
Match the metric measurement on the left with an equivalent unit of measurement on the right
Answer:
ans:
0.3 hectoliter = 3000 centiliters0.03 liter = 30 milliliterMatch the metric measurement on the left with an equivalent unit of measurement on the right are as follows;
0.3 hectoliter 3 deciliters
0.03 liters 30 milliliters
30 centimeter 3 Deciliters
3000 Milliliters 0.3 Decaliters
What is the unit measurement?A standard unit of measurement is a quantifiable language that describes the magnitude of the quantity.
Match the metric measurement on the left with an equivalent unit of measurement on the right is determined in the following steps given below.
1. 0.3 hectoliter = 0.3 × 10 = 3 deciliters
2. 0.03 liters = 0.03 × 1000 = 30 mililiters
3. 3 Centiliters = 0.3 Deciliters then 30 centimeter = 3 Deciliters
4. 3000 Milliliters = 0.3 Decaliters
Learn more about unit measurement here;
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What is the distance between the points (2, 1) and(6, 7)?
Answer:
[tex]\displaystyle d = 2\sqrt{13}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Coordinates (x, y)Algebra II
Distance Formula: [tex]\displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]Step-by-step explanation:
Step 1: Define
Identify
Point (2, 1)
Point (6, 7)
Step 2: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d
Substitute in points [Distance Formula]: [tex]\displaystyle d = \sqrt{(6 - 2)^2 + (7 - 1)^2}[/tex][√Radical] (Parenthesis) Subtract: [tex]\displaystyle d = \sqrt{4^2 + 6^2}[/tex][√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{16 + 36}[/tex][√Radical] Add: [tex]\displaystyle d = \sqrt{52}[/tex][√Radical] Simplify: [tex]\displaystyle d = 2\sqrt{13}[/tex]Katy spent $2834 on a washing machine and a dryer. The dryer cost $875 less than the washing machine. How much did the dryer cost ?
Answer:
the answer is 1959
Step-by-step explanation:
2834-875=1959
The pie chart below shows the percentage of total revenue that a publisher receives from various types of publications. Use this chart to answer the questions
below.
Answer:
a. Cookbooks
b. 50%
c. 30%
Step-by-step explanation:
According To the Question,
We have a total revenue of a publisher describe in a circle (360°).a. Now, Approximately Cookbooks & Textbooks revenue Form 180°, but textbook revenue is more than cookbooks as clearly visible in the diagram
Thus, cookbooks are less than 90°.
Now, we have to find 1/5th of total publisher revenue which is 360°/5= 72°. & the Cookbooks is nearest to 72° ( less than 90°)
So, Answer For (a) is Cookbooks
b. Here in Diagram Clearly Visible that The Cookbooks & Textbooks Revenue Form 180° which is Approximately 50% of total Publisher's Revenue.
So, the Total Revenue Comes From Textbooks & Cookbooks is 50%.
c. Now We know the Cookbooks + Textbooks Revenue form 180° Approximately & Cookbook is approximately equal to 72° (as we solve above)
So, textbooks are 180°-72° = 108°, which is 30% of 360° ∴ 30% Revenue Come From Textbooks.
Use the formula below to find the relative pressure inside the can in psi
Answer:
b
Step-by-step explanation:
you have to have psi to have p-e-n-i-s sand you get a jack hammer
22 hours. A
Silas ran 100 m race at a speed of 8 m/s. How long did it take him to com-
plete the race?
Answer:
100/8 = 12.5 (s)
Step-by-step explanation:
hmm bro
Answer:
[tex]{ \boxed{ \tt{formular : { \bf{ \green{time = \frac{distance}{speed} }}}}}} \\ time = \frac{100}{8} \\ { \boxed{time = 12.5 \: seconds}} \\ \\ { \underline{ \blue{ \tt{becker \: jnr}}}}[/tex]
Find x
x³ + 3x - 14 = 0
x³ + x² - x² - x + 4x + 4 = 18
x²(x + 1) - x(x + 1) + 4(x + 1) = 18
(x + 1)(x² - x + 4) = 18
x² - x + 4 = 18/(x + 1)
x² - x + 4 - 6 = 18/(x + 1) - 6
x² - x - 2 = 18/(x + 1) - 6
(x - 2)(x + 1) = (18 - 6(x + 1))/(x + 1)
(x - 2)(x + 1) = (18 - 6x - 6)/(x + 1)
(x - 2)(x + 1) = (12 - 6x)/(x + 1)
(x - 2)(x + 1) = (-6(x - 2))/(x + 1)
x + 1 = (-6(x - 2))/(x + 1)(x - 2)
x + 1 = -6/(x + 1)
(x + 1)² = -6
x² + 2x + 8 = 0
x = (-b +- √(b² - 4ac))/2a
x = (-2 +- √(4 - 32))/2
x = (-2 +- √(-28)/2
x = (-2 +- i√28)/2
Something's wrong.
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: x = - 1 \: + \: i \sqrt{6} \:(or) \: \: x = - 1 \: -\: i \sqrt{6} }}}}}}[/tex]
And[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {x\:=\:2}}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex] \: {x}^{3} + 3x - 14 = 0[/tex]
➺[tex] \: {x}^{2} (x + 1) - x(x + 1) + 4(x + 1) = 18[/tex]
➺[tex] \: (x + 1)( {x}^{2} - x + 4) = 18[/tex]
➺[tex] \: {x}^{2} - x + 4 = \frac{18}{(x + 1)} [/tex]
➺[tex] \: {x}^{2} - x + 4 - 6 = \frac{18}{(x + 1)} - 6[/tex]
➺[tex] \: (x - 2)(x + 1) = \frac{18 - 6(x + 1)}{(x + 1)} [/tex]
➺[tex] \: (x - 2)(x + 1) = \frac{18 - 6x - 6}{(x + 1)} [/tex]
➺[tex] \: (x - 2)(x + 1) = \frac{12 - 6x}{(x + 1)} [/tex]
➺[tex] \: (x - 2)(x + 1) = \frac{ - 6(x - 2)}{(x + 1)} [/tex]
➺[tex] \: (x + 1 )² = \frac{ - 6(x - 2)}{(x + 1)(x - 2)} [/tex]
➺[tex] \: (x + 1)² = \frac{ - 6}{(x + 1)} [/tex]
[tex]\sf\pink{Error\:corrected\:here. }[/tex]
➺[tex] \: {x}^{2} + 2x + 1 = - 6[/tex]
➺[tex] \: {x}^{2} + 2x + 7 = 0[/tex]
By quadratic formula, we have
➺[tex] \: x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]
➺[tex] \: x = \frac{ - 2± \sqrt{ {2}^{2} - 4.1.7} }{2 \times 1} [/tex]
➺[tex]x = \frac{ - 2± \sqrt{ - 24} }{2 } [/tex]
➺[tex] \: x = \frac{ - 2± \sqrt{ - 1 \times 4 \times 6} }{2} [/tex]
➺[tex] \: x = \frac{ - 2± \sqrt{ - 1} \times \sqrt{4} \times \sqrt{6} }{2} [/tex]
➺[tex] \: x = \frac{ - 2 \: ± \: i \times 2 \times \sqrt{6} }{2} [/tex]
➺[tex] \: x = \frac{ - 2 \: ± \:i \: 2 \sqrt{6} }{2} [/tex]
➺[tex] \: x = \frac{ 2 \: ( - 1 \: ± \: i \: \sqrt{6}) }{2} [/tex]
➺[tex] \: x = - 1 \: ± \: i \sqrt{6} [/tex]
Therefore, the two values of [tex]x[/tex] are ([tex] \: - 1 \: + \: i \sqrt{6}[/tex]) and ([tex] \: - 1 \: -\: i \sqrt{6}[/tex]).
Let us look at another method.[tex]x[/tex]³ + 3 [tex]x[/tex] - 14 = 0
➼ [tex]x[/tex]³ + 3 [tex]x[/tex] = 14
➼ [tex]x[/tex] ( [tex]x[/tex]² + 3 ) = 14
Factors of 14 = 1, 2, 7 and 14.
a) Substituting [tex]x\:=\:1[/tex], we have
➼ 1 ( 1 + 3 ) ≠ 14
➼ 1 x 4 ≠ 14
➼ [tex]\boxed{ 4\: ≠ \:14 }[/tex]
b) Substituting [tex]x\:=\:2[/tex], we have
➼ 2 ( 2² + 3 ) = 14
➼ 2 ( 4 + 3 ) = 14
➼ 2 x 7 = 14
➼ [tex]\boxed{ 14 \:= \:14 }[/tex]
c) Substituting [tex]x\:=\:7[/tex], we have
➼ 7 ( 7² + 3 ) ≠ 14
➼ 7 ( 49 + 3 ) ≠ 14
➼ 7 x 52 ≠ 14
➼ [tex]\boxed{ 364\: ≠ \:14 }[/tex]
d) Substituting [tex]x\:=\:14[/tex], we have
➼ 14 ( 14² + 3 ) ≠ 14
➼ 14 x 199 ≠ 14
➼ [tex]\boxed{ 2786\: ≠ \:14 }[/tex]
Hence, our only real solution is 2.
[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]
A video store charges $8 per movie, and the fifth movie is free. How much do you actually pay per movie?
Answer:
$6.40 per movie
Step-by-step explanation:
Since the fifth movie is free, find the total cost by multiplying 8 by 4:
8(4)
= 32
Find how much you actually pay per movie by dividing this by 5:
32/5
= 6.4
So, you are actually paying $6.40 per movie
Answer:
$6.40
Step-by-step explanation:
If you buy five movies, but only pay for the first four, then that is the first amount we need to find. Paying $8 for four movies means you are paying $32. If you are paying $32 for five movies, then you are paying $6.40 per movie.
Math:
8 + 8 + 8 + 8 + 0 = 32
32/5 = 6.4
please calculate this limit
please help me
Answer:
We want to find:
[tex]\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}[/tex]
Here we can use Stirling's approximation, which says that for large values of n, we get:
[tex]n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n[/tex]
Because here we are taking the limit when n tends to infinity, we can use this approximation.
Then we get.
[tex]\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} = \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}[/tex]
Now we can just simplify this, so we get:
[tex]\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\[/tex]
And we can rewrite it as:
[tex]\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}[/tex]
The important part here is the exponent, as n tends to infinite, the exponent tends to zero.
Thus:
[tex]\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}[/tex]
Find the coefficient of the t4
term in the expansion of
(4t – 375
a
9514 1404 393
Answer:
-3840t^4
Step-by-step explanation:
The k-th term, counting from k=0, is ...
C(5, k)·(4t)^(5-k)·(-3)^k
Here, we want k=1, so the term is ...
C(5, 1)·(4t)^4·(-3)^1 = 5·256t^4·(-3) = -3840t^4
__
The program used in the attachment likes to list polynomials with the highest-degree term last. The t^4 term is next to last.
a tank is 2m long, 1.4m wide and 1.8m high.find the volume of water in the tank when it is half full.
Answer:
2.52m³
Step-by-step explanation:
volume=L x W x H
V=2 x 1.4 x 1.8
V=5.04
WE DIVIDE 5.04m³ by 2 to get 2.52m³
Have a nice day
you arrive in Mexico City with $360 how many pesos can you buy?
Answer:
7 442,84
Step-by-step explanation:
An American tourist visits South Africa with $3000. The exchange rate when she arrives is
$1 = 12.90. She changes all her dollars into rands and then spends R900 per day for seven
days. She changes the rands she has left back into dollars at a rate of $1 = R12.93. How much
does she get in dollars? show your working.
9514 1404 393
Answer:
$2505.80
Step-by-step explanation:
After the first exchange, the tourist has ...
$3000(12.90 R/$) = R38,700
After 7 days, she has ...
R38,700 -7(R900) = R32,400
After the second exchange, she has ...
R32,400 × ($1/R12.93) = $2505.80
She gets $2505.80 at the second exchange.
11. f(x) = 4x4 - x2 + 9. Find f(-4).
Answer:
f ( -4 ) = 1024 + 8 + 9
Step-by-step explanation:
f ( x ) = 4x⁴ - x² + 9
If f ( - 4 ) then we get
f ( -4 ) = 4 ( -4)⁴ - ( - 4)² + 9
Expand the exponents
f ( - 4 ) = 4 ( 256 ) + 8 + 9
multiply the numbers
f ( -4 ) = 1024 + 8 + 9
Equation of lines acellus pls help ofooehhenxkdoke
Answer:
Firstly you must find the slope of two point
Step-by-step explanation:
m=(y2-y1)/(x2-x1) m=-8/4 = -2 after this step you should choose one point. I want to choose (3,1) y-1=2*(x-3). our equation y=2x-7
The Home Cleaning Company charges $312 to power-wash the siding of a house plus
$12 for each window. Power Clean charges $36 per window, and the price includes
power-washing the siding. How many windows must a house have to make the total
cost from The Home Cleaning Company less expensive than Power Clean?
Answer:
14
Step-by-step explanation:
take 312 + 12×14 then take 36×14
which number line represents the solution set for the inequality ? HELP PLEASE
Step-by-step explanation:
if you need any explanation you can ask
In the last six months, Sonia's family used 529, 499, 651, 652, 1,163, and 310 minutes on their cell phone plan. To save money, Sonia's family wants to keep their mean cell phone usage below 600 minutes per month.
By how many minutes did they go over their goal in the last six months?
Answer:
They went over their goal for the last six months by 34 minutes per month.
Step-by-step explanation:
Mean of a data-set:
The mean of a data-set is the sum of all values in the data-set divided by the size of the data-set.
529, 499, 651, 652, 1,163, and 310 minutes on their cell phone plan.
The mean is:
[tex]M = \frac{529+499+651+652+1163+310}{6} = 634[/tex]
By how many minutes did they go over their goal in the last six months?
The mean was of 634 minutes, and they wanted to keep it below 600. So
634 - 600 = 34
They went over their goal for the last six months by 34 minutes per month.
..........................................................
How to solve this math question
Answer:
x = 16
y = 5
Step-by-step explanation:
The three sides of an equilateral triangle are equal. Therefore:
3x + 1 = 49
Solve for x.
3x + 1 - 1 = 49 - 1
3x = 48
3x/3 = 48/3
x = 16
Also
18y - 41 = 49
Solve for y.
18y - 41 + 41 = 49 + 41
18y = 90
18y/18 = 90/18
y = 5
5 is subtracted from the sum of 8 and 7.
Answer:
10
Step-by-step explanation:
Sum of 8 and 7 = 8 + 7 = 15
5 subtracted from sum of 8 and 7 = 15 - 5 = 10
The answer to this question = 10
What do you mean by a sum?The sum is the result of the addition of two or more numbers.
What do you mean by subtraction?The difference between the two numbers is called subtraction.
How do we evaluate the given question?First, we find the sum of 8 and 7
8 + 7 = 15
Now, we subtract 5 from 15
15 - 5 = 10
∴ The result to the given question = 10
Learn more about the Addition/Subtraction at
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plz answer I don't have a long time
Answer: x=52
Step-by-step explanation:
x+72=34+90
x+72=124
124-72=x
x=52
what does $42,690e(0.03)(20) equal
Answer:
77,786.251
Step-by-step explanation:
Solve the equation by completing the square. Round to the nearest hundredth x^2 + 2x = 15
Answer:
x = 3, x = -5
Step-by-step explanation:
A perfect square trinomial is represented in the form a^2 + 2ab + b^2. We are already given the a^2 term, x^2, and the 2ab term, 2x. From this we can say:
a^2 = x^2
a = x
Now, we can substitute x for a in the other expression to create the equation:
2ab = 2x
2(x)b=2x
b = 1
From this, b^2 is one, so, to get our trinomial all on one side, we add 1 to both sides:
x^2 + 2x = 15
x^2 + 2x + 1 = 16
Now, we can factor. The perfect square trinomial factors into (a + b)^2. In this case, a is x, and b is one. We can factor and get:
(x + 1)^2 = 16
Now, we take the square root of both sides:
x + 1 = ± 4
We can separate this into two equations and solve:
x + 1 = 4
x = 3
x + 1 = -4
x = -5
Answer:
Step-by-step explanation:
x^2 + 2x = 15
x^2 + 2x + [1/2(2)]^2 = 15 + [1/2(2)]^2
(x + 1/2(2) )^2 = 15 + [(1/2)(2)]^2
(x + 1)^2 = 15 + 1^2
(x + 1)^2 = 15 + 1
(x+1)^2 = 16 Take the square root of both sides.
sqrt( (x + 1)^2 ) = sqrt(16)
x + 1 = +/- 4
x + 1 = 4
x = 4 - 1 = 3
x + 1 = -4
x = -4 - 1
x = - 5
So the roots are 3 and - 5
w= 2hx - 11x Solve for X. Please and Thank you
Answer:
[tex]{ \tt{ w = 2hx - 11x}} \\ \\ { \bf{w = x(2h - 11)}} \\ \\ { \bf{x = \frac{w}{2h - 11} }}[/tex]
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: x = \frac{w}{(2h - 11)} }}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex]w = 2hx - 11x[/tex]
[tex]✒ \: w = x \: (2h - 11)[/tex]
[tex]✒ \: x = \frac{w}{(2h - 11)} [/tex]
[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]
WILL GIVE BRAINLIEST IF CORRECT
Answer:
The second answer.
Step-by-step explanation:
Tim is correct. Absolute value is just the distance away from 0. In this case, both P and Q are 3/8 away from zero, even though they have opposite signs. In fact, opposites signs of the same number will always have the same absolute value because they are the same distance from 0.
So, it is the second one.
Hope this helps!
Answer:
2nd answer choice:
Tim, because each point is 3/8 unit away from 0
Step-by-step explanation:
The absolute value of a number is how far it is from 0 in the number line, not including direction.
On this number line, point P is -3/8 and point Q is 3/8.
In the number line, count how many units each point is away from 0. You will find that they each have a distance of 3/8 from the number line. Therefore they have the same absolute values.
PS: absolute values are NEVER negative.
Hope this helps!