It is the gametes formation of a sex cells or reproductive cells.​

Answer:

double displacement reaction

Answer:

a. 408g de NH3 son necesarios

b. 2.42x10²³ moléculas de agua se obtienen

Explanation:

a. Basados en la reacción, 2 moles de NH3 producen una mol de (NH2)2CO. Para resolver esta pregunta debemos convertir la masa de (NH2)2CO a moles. Estas moles a moles de NH3 y su respectiva masa:

Moles (NH2)2CO -Masa molar: 60.06g/mol-

720g * (1mol / 60.06g) = 11.99 moles (NH2)2CO

Moles NH3:

11.99 moles (NH2)2CO * (2mol NH3 / 1mol (NH2)2CO) = 23.98 moles NH3

Masa NH3 -17.031g/mol-:

23.98 moles NH3 * (17.031g / mol) = 408g de NH3 son necesarios

b. 1mol de CO2 produce  1mol de agua. Se debe convertir el volumen a moles usando PV = nRT. Estas moles = Moles de agua. 1mol = 6.022x10²³ moléculas:

Asumiendo STP:

PV = nRT; PV / RT = n

Donde P = 1atm a STP

V = 9L

R = 0.082atmL/molK

T = 273.15K a STP

1atm*9L / 0.082atmL/molK*273.15K = n

n = 0.402 moles CO2 = Moles H2O

Moléculas:

0.402 moles agua * (6.022x10²³ moléculas / 1mol) =

Answer:

CaC0³ scientific name is Calcium carbonate

Explanation:

Have a great summer :)

Answer:

External stimulus of thirst

Answer:

your answer is:         the external stimulus of thirst

Explanation:

I took the test :)) hope this helps!!!!!!

Answer:

B. Cation

Explanation:

As an electron is removed from the atom it is then converted into a positively charged ion known as a Cation.

Hope this helps u

Answer:

STP is 101.325 kPa pressure and 273K temperature

Also, at STP, 1 mol of an ideal gas = 22.4 L

Since the question states that 22.4 L are needed at STP, we know that ONE MOLE is needed.  Now, the question is, how many moles are actually present?

V = 25.0 L

P = 101.5 kPa

T = 373K

n = ?

R = 8.31 L-kPa/Kmol

Solving the ideal gas law for n (moles) and comparing that to 1 mole, we have...

n = PV/RT = (101.5)(25.0)/(8.31)(373)

n = 0.82 moles of gas.  THIS IS NOT ENOUGH as it is less than the ONE mole required.

Explanation:

Answer:

The answer is c

Answer:

2As + 6NaOH =2Na3AsO3 +3H2

Explanation:

2As + 6e- = 2As³ ,this is an oxidation reaction

6H¹ +6e- =6H⁰ ,this is reduction process

the above reaction exhibit a redox redox reaction As acts as a reducing agent while NaOH acts as an oxidizing agent.

Answer:

121 aprox.

Explanation:

mass/molar mass = Q/CF

where mass=?

molar mass of Al=27

Q=It = 15×24×60×60

C=3

F=96500

Answer:

125 ohms

Explanation:

since they're parallel we do

1/total resistance = (1/250 ohms) + (1/250 ohms)

then you get 2/250 ohms

then you flip it so it's equal to total resistance/1

250÷2= 125

Answer:

The empirical formula is: CH2

Th powder is not vainillin

Explanation:

We can find empirical formula of a compound CₐHₓOₙ knowing that moles CO2 = Moles C, 2 Moles H2O = Moles H and that we can find the mass of oxygen by the difference of masses of the atoms:

Moles C = Moles CO2 -Molar mass: 44.01g/mol-

5.875g * (1mol/44.01g) = 0.1335 moles C * (12.01g/mol) = 1.60gC

Moles H2O and moles H -Molar mass: 18.01g/mol-

2.41g H2O * (1mol / 18.01g) = 0.1339 moles H2O * (2mol H / 1mol H2O) =

0.2676 moles H * (1g/mol) = 0.27g H

The empirical formula of this compound is the ratio of C:H:

0.2676 moles H / 0.1335 moles C = 2

The empirical formula is:

CH2

In vainillin, the moles of Carbon = Moles of Hydrogen. the experiment shows the moles of hydrogen are twice the moles of carbon. Thus, the powder is not vainillin

Answer:

it should be powdered zinc with high concentration of sulfuric acid

Answer:

0.13 molL-1

Explanation:

We must first obtain the number of moles of sodium carbonate as follows;

Number of moles = mass/molar mass

Number of moles = 21.2 g/106 g/mol

Number of moles= 0.2 moles

Number of moles = concentration × volume

Volume = 1.50 L

Concentration = number of moles/volume

Concentration = 0.2 moles/1.5 L

Concentration = 0.13 molL-1

Answer:

so in one mole of atom there are 6.02×10^23.

answers to B is 2.41×10^24

Explanation:

use this equation

number of particle=moles X 6.02×10^23

=4 X 6.02 ×10^23

=2.41×10^24

hope this make sense:)

The number of particles present in 4 moles of a substance is 24.088 particles.

Moles is a unit to express the amount of any substance and in one mole of any substance 6.022 × 10²³ particles of that substance are present and this number is known as Avogadro's number.

As in 1 mole = 6.022 × 10²³ particles are present

In 4 moles = 4 × 6.022 × 10²³ = 24.088 particles are present

Hence, 24.088 particles are present in 4 moles.

To know more about Avogadro's number, visit the below link:
https://brainly.com/question/10614569

Answer:

2.34 %

Explanation:

Since the density of the Jello, ρ = 1.14 g/mL and ρ = m/v where m = mass of jello and v = volume of jello = 475 mL.

So, m = ρv

substituting the values of the variables into the equation, we have

m = ρv

m = 1.14 g/mL × 475 mL = 541.5 g

Since we have 13 g of sugar in the jello, the total mass present is 13 g + 541.5 g = 554.5 g

So, the percentage by mass of sugar present % m/m = mass of sugar present/total mass × 100 %

= 13 g/554.5 g × 100 %

= 0.0234 × 100 %

= 2.34 %

So, the percentage by mass of sugar present % m/m = 2.34 %

Answer:

hope it help u !!!!

Explanation:

Stoichiometry is the relationship between the relative quantities of substances taking part in a reaction or forming a compound, typically a ratio of whole integers

Answer:

3132 is the answer

Explanation:

3BaCl2 + Al2S3 → 3BaS + 2AlCl3

Answer:

Explanation:

Hope this helps u !!

Answer:

The answer is the first option 0.37 moles

Explanation:

the ideal gas law is PV = nRT, so in the terms of n,

n = PV/RT (divide both sides by RT to let n stand alone)

given: P = 700 kpa, V = 2L, T = 450 K , R = 8.31

n = (700 * 2) / (8.31 * 450)

= 1400/3739.5

= 0.34

Answer:

this link not hacl belive me

https://www.flinnsci.com/api/library/Download/18ce587821c24fb3b0ad7d878bd6a3d9Explanation:

Answer:

The given molecules are:

(A) CO2 (B) H2O (C) CH4 (D) C2H4 (E) PH3

Which one has trigonal pyramidal geometry?

Explanation:

According to VSEPR (valence shell electron pair repulsion) theory, a molecule with a central atom having hybridization sp3 and with one lone pair of electrons has trigonal pyramidal geometry.

Among the given molecules,

CO2 has central atom carbon with sp hybridization without lone pairs.

So, it is a linear molecule.

H2O, the central atom is oxygen with sp3 hybridization and oxygen has two lone pairs. So, its geometry is V-shape or bent.

CH4 has central atom carbon with sp3 hybridization and no pairs.

So, its geometry is tetrahedral.

C2H4 ethene has carbon atoms as the central atoms with sp2 hybridization and carbon has no lone pairs.

So, its geometry is trigonal planar.

Answer:

PH3 has central atom P with sp3 hybridization.

P has one lone pair on it.

Hence, the geometry of PH3 is trigonal pyramidal.

Hello. You have not presented the image that presents the two elements mentioned in the question. This makes it impossible for your question to be answered. However, I will try to help you as best I can.

To say whether the compounds obey the law of multiple proportions, you should observe whether one of the elements, formed from the compounds, maintains a fixed mass, while the other element presents the mass in a varied amount of small, whole numbers, spread across the formed compounds .

This is because the law of multiple proportions states that an element must have a fixed mass when reacting with another element to create compounds. This reaction will allow this element to keep the mass fixed, while the other element will generate different compounds, where each one presents a part of the mass of the forming element, in small and whole numbers.

Answer:

See explanation

Explanation:

The interior of the atom is composed of electrons which move around in orbits and the nucleus. The nucleus contains protons and neutrons. The electrons are negatively charged while the protons are positively charged, the neutrons have no charge at all.

The atom is held together by electrostatic interaction between the electrons and protons in the nucleus. The protons and neutrons account for most of the mass of the atom.

The greatest wonder that I will like to really understand in the interior of the atom is the nature of the interaction between the neutrons and protons in the atomic nucleus which holds the nucleons together. The neutrons have no charge while the protons are positively charged. What sort of interaction could exist between an uncharged particle and a charged particle? That is what I will like to understand better as a result of my travels into the interior of the atom.

Answer:

help

Explanation:

Answer:

[tex]\boxed {\boxed {\sf 81.4 \ g\ KOH}}[/tex]

Explanation:

We are asked to convert 1.45 moles of potassium hydroxide (KOH)  to grams.

The molar mass is the mass in grams of 1 mole of a substance. The values are found on the Periodic Table. They are the same as the atomic masses but the units are grams per mole (g/mol) instead of atomic mass units (amu).

We have the compound KOH. Look up the molar masses of the individual elements.

The formula for the compound has no subscripts, so there is 1 mole of each element in 1 mole of the compound. We can simply add the molar masses.

Based on the molar mass, there are 56.105 grams of KOH in 1 mole. Create a ratio using this information.

[tex]\frac {56.105 \ g\ KOH}{ 1 \ mol \ KOH}[/tex]

We are converting 1.45 moles of KOH to grams, so we multiply by this value.

[tex]1.45 \ mol \ KOH *\frac {56.105 \ g\ KOH}{ 1 \ mol \ KOH}[/tex]

The units of moles of KOH cancel.

[tex]1.45\ *\frac {56.105 \ g\ KOH}{ 1 }[/tex]

[tex]81.35225 \ g\ KOH[/tex]

The original measurement of moles has 3 significant figures, so our answer must have the same.

For the number we calculated, that is the tenths place. The 5 in the hundredths place (81.35225) tells us to round the 3 up to a 4.

[tex]81.4 \ g\ KOH[/tex]

Approximately 81.4 grams of potassium hydroxide are represented by 1.45 moles.

Explanation:

The haem is in turn split into iron , which forms chemical compounds as part of the blood iron pool available for future hemoglobin synthesis...

hope this help !!