Answer:
True
Step-by-step explanation:
The volume of an object is the amount of matter the shape can hold, so finding how much water the tank can hold is finding the volume of the tank.
Have a great day! Hope this helps!
Answer:
True hope this helps
Question: Edwin usually makes 20 cookies with this recipe, but only wants 5 cookies.
How much is 1/2 teaspoon of vanilla to make 5 cookies?
(PLEASE HELP!!)
Answer:
1/8 teaspoon of vanilla is needed to make 5 cookies
Step-by-step explanation:
1) 1/2 teaspoon of vanilla makes 20 cookies
2) you only need 5 cookies which is 1/4 as many cookies as before
3) you must 1/4 your recipe
4) 1/2 divided by 4 = 1/8
Does 23^-1 (mod 1000) exist? If yes solve it.
Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).
Let x be the inverse. Then x is such that
23x ≡ 1 (mod 1000)
Use the Euclidean algorithm to solve for x :
1000 = 43×23 + 11
23 = 2×11 + 1
→ 1 ≡ 23 - 2×11 (mod 1000)
→ 1 ≡ 23 - 2×(1000 - 43×23) (mod 1000)
→ 1 ≡ 23 - 2×1000 + 86×23 (mod 1000)
→ 1 ≡ 87×23 - 2×1000 ≡ 87×23 (mod 1000)
→ 23⁻¹ ≡ 87 (mod 1000)
When the new principal on a loan is $79,946.13 and the interest rate is 8 percent, the monthly payment is $587.20. Find the interest, the payment to principal, and the new balance. STEP 1: Find the interest.
9514 1404 393
Answer:
to interest: $532.97to principal: $54.23new balance: $79,891.90Step-by-step explanation:
The interest is found by multiplying the monthly rate by the balance on the loan. For the first month, the balance is the loan amount.
$79,946.13 × 0.08 ×(1/12) . . . . . one month = 1/12 year
= $532.97
The interest amount in the first payment is $532.97.
__
The amount of the first payment that goes to principal is what is left after the interest is paid:
$587.20 -532.97 = $54.23 . . . amount to principal
__
The new balance is the previous balance less the amount to principal:
$79,946.13 -54.23 = $79,891.90 . . . new balance
A car is running with the velocity of 72km/h . what will be its velocity after 5s if its acceleration is -2m/s square ?
Answer:
92 km
Step-by-step explanation:
by calculator hope it gelps
Is 3/4 closer to 0 or 1?
Answer:
It is closer to 1
Step-by-step explanation:
3/4 is 1/4 away from 1, whereas 0 is 3/4 away from 3/4. So, 1 is closer.
The fraction 3/4 is closer to 1.
We have,
To determine whether the fraction 3/4 is closer to 0 or 1, we can compare the distances between 3/4 and 0, and between 3/4 and 1.
The distance between 3/4 and 0 is 3/4.
The absolute value of the difference is |3/4 - 0| = 3/4.
The distance between 3/4 and 1 is 1 - 3/4 = 1/4.
Since the distance between 3/4 and 1/4 (which is 1/4) is smaller than the distance between 3/4 and 0 (which is 3/4), we can conclude that 3/4 is closer to 1 than to 0.
In other words, if we were to plot the fractions 0, 3/4, and 1 on a number line, the distance between 3/4 and 1 would be smaller than the distance between 3/4 and 0.
Therefore,
The fraction 3/4 is closer to 1.
Learn more about fractions here:
https://brainly.com/question/24370499
#SPJ2
Mr. Shand had $59.75 in his bank account, but then he bought some new ties and some pancakes. After the purchase, he was in debt $75.10. Which of the following rational numbers best shows the change in Mr. Shand’s account balance?
STEP BY STEP EXPLINATION PLEASE!
Answer:
Ok so first he bought the road and pancakes with means he speant 134.85 dollars which mean he out himself in the negatives after he bought the his items
What is the difference of the rational expressions below?
6x _ 5
X-2 X
A. 6x2 -5x - 10
x(x - 2)
B. 6x-5
2X-2
c. 6x^2 -5x +10
x(x-2)
D. 6x-5
-2
I'm
C.) 6x^2-5x+10/x(x-2)
point a and point b are placed on a number line point a is located at -20 and point b is 5 less then point a Wich statement about point b is true
Answer:
Step-by-step explanation:
D beause less then 5 that means it gose down the grid
which is a graph of the equation y = 2x - 4
Answer:
The 3rd one
Step-by-step explanation:
Find the measure of 43.
43
75
43 = [?]
Answer:
<3=105°
Step-by-step explanation:
The angle directly to the right of the 75° angle is 105°, as the angles along a straight line add to 180.
<3=105° because they are corresponding angles
Answer:
Solution given:
<3+75=180[co- interior angle]
<3=180°-75°=105°
<3=105°
Can someone help me simplify and write in power form and show me step by step how to do it for both problem 8 and 9?
Answer:
[tex]\frac{-1.1x^{25} }{-1.1x^{11} }[/tex] [tex]\frac{mx^{67} }{mx^{37} }[/tex]
Step-by-step explanation:
Sine (-1.1) is the same as (-1.1) you just put them together and if the numbers are by each other you just add up the exponents. But if the question says this [tex]\frac{-1.1x^{2} }{-1.1x^{3} }[/tex] than you subtract the exponents.
·[tex](-1.1)x^{13}X (-1.1)x^{12} = add\\\frac{-1.1x^{2} }{-1.1x^{2} } = subtract[/tex]
Hope this helps. Have a blessed day :)
Help me with my homework, please
Answer:
150°
Step-by-step explanation:
We know each angle in a equilateral triangle is 60° and that of a rectangle is 90° . So ,
[tex]\implies \angle ABC = \angle DBC + \angle ABD \\\\\implies \angle ABC = 90^o + 60^o \\\\\implies \boxed{\boxed{ \angle ABC = 150^o }}[/tex]
When electricity (the flow of electrons) is passed through a solution, it causes an oxidation-reduction (redox) reaction to occur. If the solution contains a metal cation such as Ag+, the flow of electrons will reduce the silver ion, causing solid silver to plate onto the electrode. The amount of metal plated depends on the number of electrons passed. The total charge of a mole of electrons is 96, 485 coulombs (C) and 1 ampere = 1 coulomb/second (C/s).
What mass of Cu(s) is electroplated by running 28.5 A of current through a Cu2+ (aq) solution for 4.00 h? Express your answer to three significant figures and include the appropriate units.
How many minutes will it take to electroplate 37.1 g of gold by running 5.00 A of current through a solution of Au+(aq)? Express your answer to three significant figures and include the appropriate units.
Answer:
a. 135 g
b. 60.6 min
Step-by-step explanation:
a. What mass of Cu(s) is electroplated by running 28.5 A of current through a Cu2+ (aq) solution for 4.00 h? Express your answer to three significant figures and include the appropriate units.
The chemical equation for the reaction is given below
Cu²⁺(aq) + 2e⁻ → Cu(s)
We find the number of moles of Cu that are deposited from
nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 28.5 A and t = time = 4.00 h = 4.00 × 60 min/h × 60 s/min = 14,400 s
So, n = It/F = 28.5 A × 14,400 s/96485 C/mol = 410,400 C/96485 C/mol = 4.254 mol
Since 2 moles of electrons deposits 1 mol of Cu, then 4.254 mol of electrons deposits 4.254 mol × 1 mol of Cu/2 mol = 2.127 mol of Cu
Now, number of moles of Cu = n' = m/M where m = mass of copper and M = molar mass of Cu = 63.546 g/mol
So, m = n'M
= 2.127 mol × 63.546 g/mol
= 135.15 g
≅ 135 g to 3 significant figures
b. How many minutes will it take to electroplate 37.1 g of gold by running 5.00 A of current through a solution of Au+(aq)?
The chemical equation for the reaction is given below
Au⁺(aq) + e⁻ → Au(s)
We need to find the number of moles of Au in 37.1 g
So, number of moles of Au = n = m/M where m = mass of gold = 37.1 g and M = molar mass of Au = 196.97 g/mol
So, n = m/M = 37.1 g/196.97 g/mol = 0.188 mol
Since 1 mol of Au is deposited by 1 moles of electrons, then 0.188 mol of Au deposits 0.188 mol of Au × 1 mol of electrons/1 mol of Au = 0.188 mol of electrons
We find the time it takes to deposit 0.188 mol of electrons that are deposited from
nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 5.00 A and t = time
So, t = nF/It
= 0.188 mol × 96485 C/mol ÷ 5.00 A
= 18173.30 C/5.00 A
= 3634.66 s
= 3634.66 s × 1min/60 s
= 60.58 min
≅ 60.6 min to 3 significant figures
Mia's birthday party will cost $12 if she invites 4 guests. What is the maximum number of guests there can be if Mia can afford to spend a total of $15 on her birthday party?
Point B has rectangular coordinates (-5, 12)
Write the coordinates (r, e) for point B. (O in degrees)
Answer:
(13, -67.4°)
Step-by-step explanation:
In the general case, for a point (x, y), the same point written in polar coordinates is (r, θ), such that:
r = √(x^2 + y^2)
θ = Atg(y/x)
Then if we have the point with coordinates (-5, 12)
The polar coordinates will be:
r = √((-5)^2 + 12^2) = 13
θ = Atg(12/-5) = -67.4°
Then the polar coordinates are:
(13, -67.4°)
help please!!!!!!!!!!!!!!!!!!! very important
Answer:
i got B for my answer
A right triangle has a hypotenuse of 15 cm. What is the length for the missing leg if one of the two legs of the triangle is 5?
Answer:
The other leg is 12 cm long.
Step-by-step explanation:
c
2
=
a
2
+
b
2
,
where:
c
is the hypotenuse, and
a
and
b
are the other two sides (legs).
Let
a
=
9 cm
Rearrange the equation to isolate
b
2
. Plug in the values for
a
and
c
, and solve.
b
2
=
c
2
−
a
2
b
2
=
(
15 cm
)
2
−
(
9 cm
)
2
Simplify.
b
2
=
225 cm
2
−
81
cm
2
b
2
=
144 cm
2
Take the square root of both sides.
b
=
√
144 cm
2
Simplify.
b
=
12 cm
Answer:
14.14 cm
Step-by-step explanation:
using the Pythagorean theorem:
?² = 15² - 5² = 225 - 25 = 200
? = √200 = 14.14 cm
A crowd-sourced review platform believes that more and more customers are writing reviews online. The crowd-sourced review platform would like to test the claim that the percent of customers who leave a review online is greater than 72%. They decide to complete a hypothesis test at a 1% significance level. They sample 30 customers, and determine the sample percent to be 90%. The following is the data from this study: Sample size =30 customers Sample proportion =0.90 Identify the null and alternative hypothesis for this study by filling in the blanks with the correct symbol (=,≠,<, or > to represent the correct hypothesis.)
Answer:
H0 : P = 0.72
H1 : P > 0.72
Step-by-step explanation:
Claim is to test that percentage of customers who leave a review is greater than 72%
From the information given :
P0 = 72/100 = 0.72
The null hypothesis, H0 : P = 0.72
Alternative hypothesis claims the proportion is greater than 0.72 and from the sampling result obtained, phat = 0.90
Hence,
Alternative hypothesis, H1 : P > 0.72
Find the indicated side of the
right triangle.
60°
х
7
30°
x = [?]
Enter
Here's the solution,
By using Trigonometry :
=》
[tex] \sin(30) = \dfrac{7}{x} [/tex]
=》
[tex] \dfrac{1}{2} = \dfrac{7}{x} [/tex]
=》
[tex]x = 14[/tex]
hence, the value of x = 14 units
Answer:
14
Step-by-step explanation:
Describe how to transform the graph of g(x)=ln(x) in the graph of f(x) = ln(-x)-9
Answer:
the answer is d because it's reflects
One-third of the candidates for a job were 25 years old or younger. Two-sevenths of the candidates were at least 50 years old. If 84 people applied for the job, how many were between 25 and 50?
Answer:
1/3 * 84 = 28 were under 25
2/7 * 84 = 24 were at least 50
28 + 24 = 52
84-52 = 32 were between 25 and 50
Step-by-step explanation:
pls help
its was on khan academy
i will mark u brainiest!!!
Answer:
[tex]14 units[/tex]
Step-by-step explanation:
[tex]Solution:-[/tex]
[tex]A(5,1)B(7,1)[/tex]
[tex]\sqrt{(x_{1}-x_{2} ) ^{2}(y_{2} -y_{1}x^{2} }[/tex]
[tex]AB=\sqrt{(7-5)^{2} +(1-1)^{2} }[/tex]
[tex]= \sqrt{2^{2} } =2[/tex]
[tex]BC=\sqrt{7-7^{2}+(6-1)^{2} }[/tex]
[tex]=\sqrt{5^{2} } =5[/tex]
[tex]perimeter=2(AB)+2(BC)[/tex]
[tex]= 2(2)+2(5)\\[/tex]
[tex]= 4+10= 14[/tex]
[tex]-----------[/tex]
hope it helps...
have a great day!!
A sample of 68 college students yields a mean annual income of $3248 and a standard deviation of $885. Find the margin of error in estimating μ at the 99% level of confidence.
Answer:
can put this solution on YOUR website!
margin of error is t(0.995 df=67)*s/sqrt(n)
t=2.65
the margin of error is 2.65*885/sqrt(68)=$284.40
HELP ME PLEASEEEEEEEEE
Answer:
1.7 pounds
Step-by-step explanation:
7.9 - 6.2= 1.7
2. The rectangles below are similar. Solve for the AREA of the larger rectangle. *
The product of two numbers is 75
one of the two numbers is a perfect squar. The other is a prime number. Find the sum of the two numbers.
Answer: 8
Step-by-step explanation: numbers are 5 and 3.
5²·3 =75
Change the decimal to a percent. 1.3=
Answer:
Im pretty sure its 130%
Step-by-step explanation:
In the past year and a half, Gnarly the dog lost an average of 2/9 pound each month. Today, Gnarly weighs 14 pounds. How much did Gnarly weigh a year and a half ago?
Answer:
Weight before 18 month = 18 pound
Step-by-step explanation:
Given:
Current weight of dog = 14 pound
Weight lose each month = 2/9 pound
Total number of month = [tex]1\frac{1}{2}[/tex] year = 18 month
Find:
Weight before 18 month
Computation:
Total weight lose = Weight lose each month x Total number of month
Total weight lose = 2/9 x 18
Total weight lose = 4 pound
Weight before 18 month = Current weight of dog + Total weight lose
Weight before 18 month = 14 + 4
Weight before 18 month = 18 pound
A set of data is summarized by the stem and leaf plot below.
Stem Leaf
1 1 2 3 4 4 5 5 7 8 8 9 0 1 2
2 4 6 8 9 9 0 3 4
3 4 4 4 6 7 7 8 9
Provide your answer below:
There are __________ values in the data set which are greater than or equal to 20 and less than or equal to 29. There are _____________ values in the data set which are greater than or equal to 30 and less than or equal to 39. There are ___________ values in the data set which are greater than or equal to 10 and less than or equal to 19.
Answer:
30 values ; greater than or equal to 10 and less Than or equal to 39
Step-by-step explanation:
Counting the number of leaves in the plot, we have 30 leaf values. This gives the number of dataset.
The minimum value is the number created by the combination of the least stem value and the lowest leaf value, which is 10
The maximum value is obtained from the combination of the highest stem and leaf value. The highest value is 39
expanded form :32,456
Answer:
30,000 + 2,000 + 400 + 50 + 6
Step-by-step explanation:
[tex]\text{The expanded form of 32,456 would be 30,000 + 2,000 + 4,000 + 50 + 6.}[/tex]
[tex]\text{We would have to identify what each number stands for.}[/tex]
[tex]\text{For example, 3 in 32,456 stands for 30,000.}[/tex]
[tex]\text{Hence, following this rule, we can conclude that the answer above is correct.}[/tex]
[tex]\text{I hope I helped you suceed!}[/tex]
