List all the factors of 48. List all the
factors of 64. What are the common
factors of 48 and 64? What is the
greatest common factor of 48 and 64?

Answers

Answer 1

Answer:

the GCF of 64 and 48 is 16

Step-by-step explanation:

Factors of 64: 1, 2, 4, 8, 16, 32 and 64.

Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24 and 48.

Common factors of 48 and 64: 1,2,4,8,16

the GCF of 64 and 48 is 16

Answer 2

Answer:

the GCF of 64 and 48 is 16

Step-by-step explanation:

Step-by-step explanation:Factors of 64: 1, 2, 4, 8, 16, 32 and 64.Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24 and 48.Common factors of 48 and 64: 1,2,4,8,16the GCF of 64 and 48 is 16


Related Questions

Pls help I’m really confused on this last question

Answers

Answer:

i cant really see that bruv

Step-by-step explanation:

goodluck tho <3

Answer:

cant see it either but good luck, i tried to read it

Step-by-step explanation:

[ 6 × 2 + 2 - [ -6 ] ] [ -5 + | [ - 18 ÷ 6 ]|]

Answers

Answer:

-300

Step-by-step explanation:

[ 6 × 2 + 2 - [ -6 ] ] [ -5 + | [ - 18 ÷ 6 ]|]

[ 12 + 2 - [ -6 ] ] [ -5 + | [ - 3 ]|]

[ 12 + 2 - [ -6 ] ] [ -5 + 3]

[ 12 + 2  + 6  ] [ -5 + 3]

(20)(-15)

-300

Just want to make sure my answer is right

Answers

It would be the last one(3) my honey
the answer is #3, so the last answer

Help me on this math questionnn

Answers

where is the question?

Equation : 12v + 10v + 14 = 80
What is v equaled to?

Answers

Answer:

this can be simplified

12v + 10v + 14 = 80

22v + 14 = 80

22v = 66

v = 3

Answer:

v = 3

Step-by-step explanation:

12v + 10v = 22v

22v + 14 = 80

Subtract 14 from both sides.

80 - 14 = 66

22v = 66

now divide both sides by 22

66/22 = 3

v = 3

AYO HELP ME WITH THIS!!!!
Define the variables, write a system and solve.

Five tacos and three drinks cost $9.10. Three tacos and one drink cost $4.70. How much does one taco cost and how much does one drink cost?

Answers

Answer:

a taco is 1.25 and a drink is 0.95

Step-by-step explanation:

tacos = t

drinks = d

5t + 3d = 9.10

3t + d = 4.70

this is a simultaneous equation so times the first one by one and the second by 3 and then take them away from each other and solving to get

t = 1.25 and d=0.95

one drink is $0.95

one taco is $1.25

Hope this helps!!

The arithmetic mean (average) of five positive integers is 30. What is the greatest possible value of their median?

If your answer is right or applicable for the question, I'll give you brainliest :)

Answers

9514 1404 393

Answer:

  49

Step-by-step explanation:

The sum of 5 numbers that have an average of 30 is ...

  sum = 5×30 = 150

The numbers below the median need to be as small as possible, so that the remaining numbers can be as large as possible. If the two numbers below the median are both 1, then the sum of the remaining 3 must be ...

  150 -1 -1 = 148

The median will be as large as possible when the least of the remaining three numbers is as large as possible. That will be the case when those three numbers are all the same.

  148/3 = 49.333...

Since the numbers must be integers, the possible values for the high three numbers are 49, 49, 50.

In the set {1, 1, 49, 49, 50}, the mean is 30 and the median is 49. This value is the largest possible median for this set.

E
Initial Knowledge Check
Question
Find the surface area of a cylinder with a height of 5 m and a base radius of 3 m.
Use the value 3.14 for it, and do not do any rounding.
Be sure to include the correct unit.
5 m
Í
3 m
1

Answers

Bsbbsshhshshshbdbdbdbdbdbdbdhdbdbdhdhdhdhd. Hey mathunit

Julie is arranging pictures in a photo album one time she arranges them into six on each page she rearrange them with eight on each page what is the least number of photos Julie could have put in her album

Answers

Answer:

Step-by-step explanation:

IF U HELP ME I WILL MARK U BRAINLIEST

Answers

Range is Y. So the line hits -4 on Y.
Answer- -4

b+6/4 when b=1.5???????????????????????

Answers

Answer:

3

Step-by-step explanation:

SOMEONE HELP??????!!!!!!!

Answers

Answer: a = 300, b = b = 50.24

Step-by-step explanation:

A is Equivalent to 300, and B is equivalent to 50.24 .

Subtraction with Real Numbers (I need the equation on how to solve the answer)

-3-(-8)=

Answers

Answer:

5

Step-by-step explanation:

Given:

- 3 - (- 8)

Remember two subsequent negatives turn to positive:

- 3 + 8 = 8 - 3 = 5

Answer:

5

Step-by-step explanation:

[tex] - 3 - ( - 8)[/tex]

Remove the parentheses:

[tex] - 3 + 8[/tex]

= 5

Point B is the midpoint of AC. AB=3x and AC=5x+21 . What is the value of AB?

Answers

First, let's write down what we know.

AB = 3x

AC = 5x+21

Since B is the midpoint, AB is half the length of AC. The sum of AB + AB is equal to the length of AC.

AB + AB = AC

Let's plug in our values.

3x + 3x = 5x + 21

Simplify the left side.

6x = 5x + 21

Subtract 5x from both sides.

x = 21

Now, let's plug in 21 for x in AB

AB = 3x = 3(21) = 63

Two complex numbers are given, where m, n, p, and q are real numbers.

m+ni
p+qi

For what relationship among m, n, p, and q, will be the product of these two complex numbers have only an imaginary part?

This is Algebra 2.
Answer choices:
np mq
mp-np=0
mp+nq=-1

Answers

Answer:

[tex]\displaystyle pm - qn = 0\text{ and } pn + qm \neq 0[/tex]

Or:

[tex]pm = qn \text{ and } pn + qm \neq 0[/tex]

Step-by-step explanation:

We are given two complex numbers:

[tex]\displaystyle m + ni \text{ and } p + qi[/tex]

Where m, n, p, and q are real numbers.

And we want to determine the relationship among m, n, p, and q such that the product of the two complex numbers will only have an imaginary part.

Find the product:

[tex]\displaystyle \begin{aligned} (m+ni)(p+qi) &= p(m+ni) + qi(m+ni) \\ &= (pm + pni) + (qmi + qni^2) \\ &= (pm + pni) + (qmi - qn) \\ &= (pm - qn) + i(pn + qm) \end{aligned}[/tex]

Therefore, for the product to have only an imaginary part, the real part must be zero and the imaginary part must not be zero. That is:

[tex]\displaystyle pm - qn = 0\text{ and } pn + qm \neq 0[/tex]

In conclusion, the relationship between m, n, p, and q is:

[tex]\displaystyle pm - qn = 0\text{ and } pn + qm \neq 0[/tex]

Or:

[tex]pm = qn \text{ and } pn + qm \neq 0[/tex]

(Note: I couldn't understand the provided answer choices, but the above answer is indeed correct (and the second equation can be ignored).)

BRAINLIEST AWAITS!
Solve this question and you may get 15 points and brainliest!

Answers

Answer:

Step-by-step explanation:

a) Age of Jeff = j

Tina's age = j - 4

b) j = 15 years

Tina's age = 15 - 4 = 11 years

j = 20 years

Tina's age = 20 - 4 = 16 years

j = 58 years

Tina's age = 58 - 4 = 54 years

Answer this problem…..

Answers

Answer:

[tex]-13\frac{5}{7} x[/tex] or [tex]-\frac{96x}{7}[/tex]

Step-by-step explanation:

pls answer with steps <3

Answers

Answer:

Step-by-step explanation:

A - 2 + 3 = -2 pls answer

Answers

Answer:

-3

Step-by-step explanation:

Bring -2 to the other side and A to the other side

-2 Become 2 because of flipping

And A becomes -A because of flipping

2-2+3=-A

Flip the whole equation to avoid confusion

-A=2-2+3

-A=+3

Bring the minus sign to the other side,

A=-3

-3 -2 +3 = - 2

Which make the statement correct.

I hope this explanation helps, dont hesitate to ask for any question.Mark me as brainliest is appreciated.Tq!!

Answer: A = -3

Step-by-step explanation:

A - 2 + 3 = -2

...............+2..............

..... A + 3 = 0

................-3..............

............ A = -3

You withdraw $40 each month from your savings account. what integer represents the change in your balance after 4 months?

Answers

Answer:

The balance would be $160 from whatever it was before the 4 months.

Step-by-step explanation:

Since the bank balance is being added by 40 for each month for 4 months, 4 * 40 is just 4*4 with an extra zero on the end. so that would be $160.

So if the balance before was $40, then the new balance after 4 months would be $200.

If there's no money previously, then there is now $160 after 4 months.

If there's a value before the $40 for 4 months, let me know and I will explain and tell you what it is.

If 3x = y -5 and x = 4, then y =

Answers

Answer:

y = 17

Step-by-step explanation:

3x = y - 5, for x = 4

=> 3(4) = y - 5

=> 12 = y - 5

=> 12 + 5 = y

=> 17 = y

Judging by appearance, name an acute angle, an obtuse angle, and a right angle.

Answers

Answer:

Step-by-step explanation:


x=-4 +6+ (11 +4(-3))

Answers

Answer:

x=1

Step-by-step explanation:

x = -4 + 6 + (11 + 4(-3)).

First get the numbers in the parentheses

x = -4 + 6 + (11 - 12)

Since 11 - 12 = -1. We can replace (11-12) with -1

x = -4 + 6 -1

Now add and subtract

x = 1

How do you find the GCF of each?

Answers

The first step is to consider the GCF of the numbers (coefficients) separately from that of the x’s and that separately from the GCF of the y’s.

For the coefficients, take the smaller number (so 30 in the exercise #12) and find all the numbers that divide into 30:
1, 2, 3, 5, 6, 10, 15, 30
Then start with the largest of those and see which is the first to divide into 66.
30 does not divide evenly into 66.
15 does not divide evenly into 66.
10 does not divide evenly into 66.
6 does. You’ll use 6.

For the x’s, consider how many x’s each expression has.
66yx has 1 x
30x^2y has 2 x’s.
The greatest number they all have is 1 x.

For the y’s, do the same thing:
66xy has 1 y.
30x^2y has 1 y.
They both have 1 y in common.

So the greatest things they all have in common are 6xy. That’s your GCF.

Compare the Numbers in each exercise using an inequality symbol

Answers

5 2/3 > √29 i believe :)



5 2/3 is approximately 5.66
√29 is approximately 5.385

Part E
Now check your work by using the GeoGebra geometry tool to repeat parts A through D. Open GeoGebra, and complete each step below. If you need help, follow these instructions for using GeoGebra. You will take a screenshot of your work when you are through, so be sure to clearly label your construction as you work.

Plot points A, B, and C, and draw a polygon, ΔABC, through the points.
Draw a line perpendicular to A⁢C¯ through point B.
Label the intersection of the line perpendicular to A⁢C¯ through B and A⁢C↔ point D.
Measure and display the slopes of A⁢C↔ and B⁢D↔.
Display the equations of A⁢C↔ and B⁢D↔ in the Algebra margin.
Measure and display the lengths of A⁢C¯ and B⁢D¯.
Calculate and display the area of ΔABC.
Take a screenshot showing the geometric construction and the Algebra margin, save it, and insert the image in the space below.

Part F
Compare the calculations displayed in GeoGebra with the calculations you completed in parts A through D. Look in the Algebra margin too. Do the results in GeoGebra match the results you obtained earlier? If not, where do the discrepancies occur? You might have to rearrange equations algebraically to determine whether two equations match.

Part G
You’ve seen two methods for finding the area of ΔABC—using coordinate algebra (by hand) and using geometry software. How are the two methods similar? How are they different? Why might coordinate algebra be important in making and using geometry software?

Answers

Answer:Hopefully this is how you do it sorry if i am wrong

Step-by-step explanation:

4q verbal expression

Answers

Answer:

sum of two terms. So, the verbal expression 15 plus r can be used to describe the algebraic expression 15 + r

Step-by-step explanation:

If a=b+7 and b+7=9, then a=9

Answers

Answer:

a = 9

b = 2

Step-by-step explanation:

Given : a = 9

a = b + 7

9 = b + 7

b = 9 - 7 = 2

please helpppppp!!!!!!!!!

Answers

Answer:

64w^2

Step-by-step explanation:

Because 8w is in parentheses, you must apply the exponent to both the 8 and w.

So, it becomes (8*8)(x*x) which equals (64)(x^2).

Which then gives you your final answer, 64x^2.

If a substance is transported across a cell membrane from an area of low concentration to an area of high concentration, you know that

it is a type of active transport.

it is a type of passive transport.

it could be active or passive transport.

Answers

It is a type of active transport because it will require energy to move against the concentration gradient (low to high)
- option A

If a substance is transported across a cell membrane from an area of low concentration to an area of high concentration, you know that

it is a type of active transport.

 

What do pinocytosis and phagocytosis have in common?

They are both forms of endocytosis.

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