Answer:
a) The probability that with heavy use, the battery life exceeds 11 hours is 0.4602.
b) Using the standard normal table, After 6.8 hours should you plan to recharge your phone.
Step-by-step explanation:
a) The probability that with heavy use, the battery life exceeds 11 hours:-
P(x > 11) = 1 - p( x< 11)
[tex]=1- p P[(x - \mu) / \sigma < (11 - 10.75) / 2.4]\\\\=1- P(z < 0.10)[/tex]
Using z table distribution,
= 1 - 0.5398
= 0.4602
b) Using the standard normal table,
[tex]P(Z < z) = 5%\\\\\\\\= P(Z < -1.645 ) = 0.05 \\z = -1.645[/tex]
Using the z-score formula,
[tex]x = z \times \sigma + \mu\\x = -1.645 * 2.4 + 10.75\\x = 6.8 hours.[/tex]
Help please!!!!!!!!!!!
Answer:
y = 14
Step-by-step explanation:
[tex] \frac{15}{21} = \frac{5}{7} [/tex]
[tex] \frac{10}{x} = \frac{5}{7} [/tex]
[tex]x = 14[/tex]
Now,
10/15 = y/21
15y = 10*21
y = 210/15
y = 14
This is a Right answer...
I hope you understand..
Mark me as brainliest...
An amusement park offers 2 options on tickets into the park. People can either buy 5 admission tickets for $130 or buy 1 admission ticket for $30. How much money will a group of 5 people save by buying 5 admission tickets for $130?
Answer:
You could save $20
Step-by-step explanation:
For buying them separately for $30 each for 5 people it would be $150 but if you buy the first option you would get 5 admission tickets for only $130
Answer:
20 dollars
Step-by-step explanation:
for the first deal is 5 for $130
and the second is for $30
$30 times 5 (the number of people) = $150
$150-$130= is 20
answer: $20
Uma pizzaria oferece em seu cardápio 12 sabores de pizza. Se um cliente pretende pedir 3 pizzas, então o número de maneiras que ele pode realizar esse pedido é;
•364
•220
•440
•1320
Answer:
Step-by-step explanation:
Partindo do pressuposto de que você pode ter coberturas duplas e triplas do mesmo item, o cálculo é relativamente simples. Para calcular as combinações possíveis; deve-se multiplicar as coberturas disponíveis pelo número total de coberturas permitidas. Este cálculo é semelhante a como olhamos para diferentes sistemas de contagem de base. Normalmente contamos com decimais (base 10), portanto, o número de combinações, se usar 3 dígitos, seria calculado por 10 x 10 x 10.
10x10 = 100
100x10 = 1000 combinações (0 a 999)
Sua pergunta sobre coberturas de pizza é a mesma, mas assumindo um sistema de numeração de base 12, então 12x12x12 ou 12³
Portanto, 1.728 combinações incluindo 0 (sem coberturas?) E também incluindo 12 ocasiões em que todas as 3 coberturas seriam iguais. Se esses cenários de pessoas forem restritos de modo que você só possa ter coberturas duplas máximas, etc., então essas combinações devem ser removidas (subtraídas do total de combinações permitidas).
Espero ter ajudado você a entender os princípios, então você deve ser capaz de trabalhar a partir disso, de muitas outras soluções semelhantes
How to solve and what is the answer
Answer:
5
Step-by-step explanation:
Suppose the composition of the 107th Senate is 45 Republicans, 50 Democrats, and 5 Independents. A new committee is being formed to study ways to benefit the arts in education. If 3 senators are selected at random to head the committee, find the probability of the following:
Part 1. The group of 3 consists of all Republicans.
Part 2. The group of 3 consists of all Democrats.
Part 3. The group of 3 consists of 1 from each party, including the Independent.
Answer:
1 : 0.088
2 : 0.12
3 : 0.07
Step-by-step explanation:
45 Rebullicans
50 Democrats
5 independents
Total = 100
Selection = 3
Part 1:
(45 C 3) / (100 C 3) = 0.088
Part 2:
(50 C 3) / (100 C 3) = 0.12
Part 3:
(45 C 1) x (50 C 1) x (5 C 1) / (100 C 3) = 0.07
Find the slope of the line graphed below.
Answer:
Step-by-step explanation:
two points are (-5,-2) and (-1,3)
slope=(3-(-2))/(-1-(-5))=(3+2)/(-1+5)=5/4
You paid $6.99 for a shirt that was 70% of what was the original price of the shirt?
Answer:
$23.3
Step-by-step explanation:
you can use ratios to solve this:
$6.99/x=0.30/0.100 then cross multiply to get 0.3x=6.99
So, 6.99 divided by 0.3 = 23.3
so the original price is $23.3
Please guys help to solve this problem
9514 1404 393
Answer:
300
Step-by-step explanation:
Since nobody failed, the number who passed one or the other was 100%.
P(O + W) = P(O) +P(W) -P(O&W)
100% = 80% +70% -P(O&W)
P(O&W) = 50% = 150 students
If 150 students are 50% of the examinees, then 100% will be 300 students.
Answer:
[tex]300[/tex]hope it helps
#CARRYONLEARNINGNeed help with this one please
it right answer is Clovis 2.5% it answer
g A. (Points: 7) Compute (without using a calculator) 241^257 mod 12 B. (Points: 3) Compute Z*20 C. (Points: 6) Find the multiplicative inverse of 7 in Z19
Answer:
[tex]241^{257}\ mod\ 12 =1[/tex]
[tex]7 * 20 = 140[/tex]
[tex]\frac{1}{700}[/tex]
Step-by-step explanation:
Solving (a): 241^257 mod 12
To do this, we simply calculate [tex]241\ mod\ 12[/tex]
Because [tex]a\ mod\ b = a^n\ mod\ b[/tex]
The highest number less than or equal to 241 that is divisible by 12 is 240; So:
[tex]241\ mod\ 12 = 241- 240[/tex]
[tex]241\ mod\ 12 =1[/tex]
Hence:
[tex]241^{257}\ mod\ 12 =1[/tex]
Solving (b): 7 * 20
[tex]7 * 20 = 140[/tex]
Solving (c): Multiplicative inverse of 7 in 719
The position of 7 in 719 is 700
So, the required inverse is 1/700 ---- i.e. we simply divide 1 by the number
The 2010 GSS provides the following statistics for the average years of education for lower-, working-, middle-, and upper-class respondents and their associated standard deviations. Assume that years of education are normally distributed in the population. Mean Standard Deviation N Lower-class 11.61 2.67 123 Working-class 12.80 2.85 697 Middle-class 14.45 3.08 626 Upper-class 15.45 2.98 38 How many years of education correspond to a Z score of +1.2 for upper-class respondents?
Answer:
The answer is "18.087 years".
Step-by-step explanation:
For upper class:
[tex]\mu=15.45 \ years\\\\\alpha=2.98 \ years\\\\[/tex]
[tex]P(Z \leq 1.2)[/tex] from the standard normal distribution on the table:
[tex]P(Z \leq 1.2) =0.8849\\\\x=z_{\alpha}+\mu\\\\[/tex]
[tex]=0.8849 \times 2.98 +15.45\\\\ = 2.637002+15.45 \\\\=18.087 \ \ years\\[/tex]
what is the value of x?
what is the value of y?
type in an integer or decimal
9514 1404 393
Answer:
x = 5.6y = 65Step-by-step explanation:
There are a couple of relations that are applicable to these questions.
the product of segment lengths of crossed chords is the same for both chordsthe angle formed at crossed chords is the average of the intercepted arc measures__
The segment lengths relation tells us ...
10x = 8×7 . . . . . . products of segment lengths are equal
x = 56/10 = 5.6 . . . . divide by 10
__
The value of y° is the average of the intercepted arcs:
y° = (85° +45°)/2 = 65°
_____
Additional comment
This diagram does not have enough information to allow computation of z. We would need to know the intercepted arc, or the length of the secant that meets tangent z.
Will give brainliest answer
Answer:
1. log3 81 = 4
2. 4 3/2=8
Step-by-step explanation:
1. Convert the exponential equation to a logarithmic equation using the logarithm base (3)(3) of the right side (81)(81) equals the exponent (4)(4).
log3(81)=4
or
you can remember this
loga Y= X
so, a^x =y
2. Use the definition of a logarithm,
log
b
(
x
)
=
y
⟹
b
y
=
x
, to convert from the logarithmic form to the exponential form.
-3/8 divided by -1/4
Flip the -1/4, cross deduct and should get 3/2
Answer:
It might be 3/2 or 1 and 1/2.
A film distribution manager calculates that 9% of the films released are flops. If the manager is right, what is the probability that the proportion of flops in a sample of 469 released films would be greater than 6%
Answer:
0.9884 = 98.84% probability that the proportion of flops in a sample of 469 released films would be greater than 6%.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
A film distribution manager calculates that 9% of the films released are flops.
This means that [tex]p = 0.09[/tex]
Sample of 469
This means that [tex]n = 469[/tex]
Mean and standard deviation:
[tex]\mu = p = 0.09[/tex]
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.09*0.91}{469}} = 0.0132[/tex]
What is the probability that the proportion of flops in a sample of 469 released films would be greater than 6%?
1 subtracted by the p-value of Z when X = 0.06. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.06 - 0.09}{0.0132}[/tex]
[tex]Z = -2.27[/tex]
[tex]Z = -2.27[/tex] has a p-value of 0.0116
1 - 0.0116 = 0.9884
0.9884 = 98.84% probability that the proportion of flops in a sample of 469 released films would be greater than 6%.
X is a normally distributed random variable with a mean of 22 and a standard deviation of 5. The probability that x is less than 9.7 is:_________
a. 0.0069
b. 0.000
c. 0.4931
d. 0.9931
Answer:
0.0069
Step-by-step explanation:
According to the Question,
Given That, X is a normally distributed random variable with a mean of 22 and a standard deviation of 5. The probability that x is less than 9.7We have, μ=22 , σ= 5 , P(X<9.7)=Area to the left of 9.7.
Z = (x-μ)/σ
Z = (9.7-22) / 5 ⇒ -2.46
Thus,
P(X<9.7)=P(Z < -2.46) ⇒ 0.0069 (From z-table)Calculate 20% of 15,998
Answer:
3,199 approximately
Step-by-step explanation:
to find how much 20% of 15,998 does we multiply 15,998 with 20 and then divide it by 100
15,998 x 20 / 100 = 3,199
What is this expression in simplified form?
Answer:
16 √(3)
and then the decimal form if needed is: 27.7128129211
Step-by-step explanation:
Find the length of an arc of a circle with a 8-cm radius associated with a central angle of 240 degrees. Give your answer in exact and approximate form to the nearest hundredth.
Answer:
l = 1920 cm
Step-by-step explanation:
Given that,
The radius of circle, r = 8 cm
The central angle is 240 degrees
We need to find the length of the arc. We know that,
[tex]l=r\theta[/tex]
Where
l is the length of the arc
So,
[tex]l=8\times 240[/tex]
[tex]\implies l=1920\ cm[/tex]
so, the length of the arc is equal to 1920 cm.
PLEASE BE RIGHT AND SOLVE PLEASE
Answer:
That transformation that happened was B rotation since b is rotated 180 degrees from A
Hope This Helps!!!
Thane Company is interested in establishing the relationship between electricity costs and machine hours. Data have been collected and a regression analysis prepared using Excel. The monthly data and the regression output follow:
Month Machine Hours Electricity Costs
January 2,300 $ 19,100
February 2,700 $ 22,400
March 1,700 $ 14,200
April 2,900 $ 24,400
May 3,600 $ 28,950
June 3,100 $ 23,400
July 3,900 $ 25,450
August 3,300 $ 23,450
September 1,800 $ 16,900
October 3,500 $ 27,400
November 4,500 $ 32,400
December 4,000 $ 28,450
Summary Output
Regression Statistics
Multiple R 0.957
R Square 0.917
Adjusted R2 0.908
Standard Error 1,586.26
Observations 12.00
Coefficients Standard Error t Stat P-value Lower 95% Upper 95%
Intercept 5,970.52 1,766.77 3.38 0.01 2,033.90 9,907.13
Machine Hours 5.76 0.55 10.49 0.00 4.54 6.98
The percent of the total variance that can be explained by the regression is:
Answer:
0.924
Step-by-step explanation:
R² = 0.854
R = √0.854
R = 0.924
Hence, the correlation Coefficient of electricity tarrif is 0.924 ; this correlation Coefficient value, depicts a strong positive correlation between machine hours and cost of electricity. And can he interpreted to mean that ; Electricity tarrif increases as machine hours increases and also decreases as machine hours decreases.
What is the number of degrees of freedom that should be used for finding the critical value
Answer:
tow degree of freedom.
this inform I know that from vibration method
What is the slope of the line?
can someone tell me where i can get a graph that shows this:
Weight Not Over (lbs.) Price
0 $0
1 $2.69
2 $3.17
3 $3.65
4 $4.13
5 $4.61
6 $5.09
7 $5.57
8 $6.03
9 $6.49
10 $6.95
Answer:
Note: See the attached photo for the graph showing Weight Not Over (lbs.) vs Price($). The attached excel file also shows the same graph with the data used to draw it in the excel.
Step-by-step explanation:
In the attached graph, Weight Not Over (lbs.) is on the horizontal axis while Price ($) is on the vertical axis.
From the attached, it can be observed that the graph shows an upward trend. That implies that there is a positive relation between Weight Not Over (lbs.) and Price. That is, as Weight Not Over (lbs.) rises, the Price also rises.
8. Calculate the Perimeter AND Area of
the RIGHT Triangle below.
17 m
10 m
21 m
Answer:
[tex]\text{Perimeter: }48\:\mathrm{m},\\\text{Area: }84\:\mathrm{m^2}[/tex]
Step-by-step explanation:
The area of a triangle with side lengths [tex]a[/tex], [tex]b[/tex], and [tex]c[/tex] is given by:
[tex]A=\sqrt{s(s-a)(s-b)(s-c)}[/tex], where [tex]s=\frac{a+b+c}{2}[/tex]
Substituting [tex]a=21, b=17, c=10[/tex], we have:
[tex]A=\sqrt{24(24-21)(24-17)(24-10)},\\A=\sqrt{24(3)(7)(14)},\\A=\sqrt{7,084},\\A=\boxed{84\:\mathrm{m^2}}[/tex]
The perimeter of a polygon is given by the sum of its sides. Since the triangle has sides 10, 17, and 21, its perimeter is [tex]10+17+21=\boxed{48\:\mathrm{m}}[/tex].
Mr. Pinter's class has twice as many students as Mrs. Rupert's class. Mrs. Althouse's class has 20 less than three times Mrs. Rupert's class. Together they have 106 students. How many are in each class?
Answer:
Mr. Pinter's class has 42 students, Mrs. Rupert's class has 21 students, and Mrs. Althouse's class has 43 students.
Step-by-step explanation:
This question is solved using a system of equations.
I am going to say that:
Mr. Pinter's class has x students.
Mrs. Rupert's class has y students.
Mrs. Althouse's class has z students.
Mr. Pinter's class has twice as many students as Mrs. Rupert's class.
This means that:
[tex]x = 2y[/tex]
Mrs. Althouse's class has 20 less than three times Mrs. Rupert's class.
This means that:
[tex]z = 3y - 20[/tex]
Together they have 106 students.
This means that:
[tex]x + y + z = 106[/tex]
We have x and z has a function of y, so:
[tex]2y + y + 3y - 20 = 106[/tex]
[tex]6y = 126[/tex]
[tex]y = \frac{126}{6}[/tex]
[tex]y = 21[/tex]
And:
[tex]x = 2y = 2(21) = 42[/tex]
[tex]z = 3y - 20 = 3(21) - 20 = 63 - 20 = 43[/tex]
Mr. Pinter's class has 42 students, Mrs. Rupert's class has 21 students, and Mrs. Althouse's class has 43 students.
Solve the rational equation x+3/3x-2-x-3/3x+2=44/9x^2-4
Answer:
[tex]x=2[/tex]
Step-by-step explanation:
When given the following equation;
[tex]\frac{x+3}{3x-2}-\frac{x-3}{3x+2}=\frac{44}{9x^2-4}[/tex]
One has to solve for the variable (x). Remember, when working with fractions, one must have a common denominator in order to perform operations. Since the denominators on the left side of the equation are unlike, one must change them so that they are like denominators. Multiply each fraction by the other fraction's denominator on the respective side. Remember to multiply both the numerator and denominator by the value to ensure that the equation remains true.
[tex]=\frac{x+3}{3x-2}*(\frac{3x+2}{3x+2})-\frac{x-3}{3x+2}*(\frac{3x-2}{3x-2})=\frac{44}{9x^2-4}[/tex]
Simplify,
[tex]=\frac{(x+3)(3x+2)}{(3x-2)(3x+2)}-\frac{(x-3)(3x-2)}{(3x+2)(3x-2)}=\frac{44}{9x^2-4}\\\\=\frac{3x^2+11x+6}{9x^2-4}-\frac{3x^2-11x+6}{9x^2-4}=\frac{44}{9x^2-4}[/tex]
Distribute the negative sign to simplify the left side of the equation;
[tex]=\frac{3x^2+11x+6}{9x^2-4}-\frac{3x^2-11x+6}{9x^2-4}=\frac{44}{9x^2-4}\\\\=\frac{3x^2+11x+6-(3x^2-11x+6)}{9x^2-4}=\frac{44}{9x^2-4}\\\\=\frac{3x^2+11x+6-3x^2+11x-6}{9x^2-4}=\frac{44}{9x^2-4}\\\\=\frac{22x}{9x^2-4}{=\frac{44}{9x^2-4}[/tex]
Since the denominators on opposite sides of the equation are like, one can now ignore the denominators,
[tex]=22x=44[/tex]
Inverse operations,
[tex]=22x=44[/tex]
÷[tex]2[/tex] ÷[tex]2[/tex]
[tex]x=2[/tex]
Write 0.851 as a fraction in simplest form.
Answer:
[tex]\frac{851}{1000}[/tex]
Step-by-step explanation:
First, we can simply multiply that number by 1000, and divide again by 1000 to get a base fraction:
[tex].851\\\\= \frac{1000}{1000} \times .851\\\\= \frac{1000 \times .851}{1000}\\\\= \frac{851}{1000}[/tex]
851 is a secondary prime, having only two factors, both of which are prime. Those factors are 23 and 37, neither of which is a factor of 1000, so this is already in simplest form.
Test the claim that the mean GPA of night students is larger than the mean GPA of day students at the 0.10 significance level. The null and alternative hypothesis would be: H 0 : p N ≥ p D H 1 : p N < p D H 0 : p N ≤ p D H 1 : p N > p D H 0 : p N = p D H 1 : p N ≠ p D H 0 : μ N ≤ μ D H 1 : μ N > μ D H 0 : μ N ≥ μ D H 1 : μ N < μ D H 0 : μ N = μ D H 1 : μ N ≠ μ D The test is: two-tailed right-tailed left-tailed The sample consisted of 30 night students, with a sample mean GPA of 3.34 and a standard deviation of 0.02, and 30 day students, with a sample mean GPA of 3.32 and a standard deviation of 0.08. The test statistic is: (to 2 decimals) Use the conservative degree of freedoms. The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Answer:
H0 : μN ≤ μD
H1 : μN > μD
Right tailed
Test statistic = 1.33
Pvalue = 0.097
Fail to reject the Null
Step-by-step explanation:
H0 : μN ≤ μD
H1 : μN > μD
The test is right tailed ; culled from the direction of the greater than sign ">"
Night students :
n1 =30 x1= 3.34 s1 = 0.02
Day students:
n2 = 30 x2 = 3.32 s2 = 0.08
The test statistic :
(x1 - x2) / √(s1²/n1) + (s2²/n2)
T= (3.34 - 3.32) / √(0.02²/30) + (0.08²/30)
T = 0.02 / 0.0150554
Test statistic = 1.328
Using the conservative approach ;
df = Smaller of n1 - 1 or n2 - 1
df = 30 - 1 = 29
Pvalue(1.328, 29) = 0.097
At α = 0.10
Pvalue < α ; Hence, we reject H0 ; and conclude that there is significant evidence that GPA of night student is greater than GPA of day student
Write a polynomial f(x) that satisfies the given conditions. Polynomial of lowest degree with zeros of -2 (multiplicity 3), 3 (multiplicity 1), and with f(0) = 120.
Answer:
Step-by-step explanation:
Polynomial f(x) has the following conditions: zeros of -2 (multiplicity 3), 3 (multiplicity 1), and with f(0) = 120.
The first part zeros of -2 means (x+2) and multiplicity 3 means (x+2)^3.
The second part zeros of 3 means (x-3) and multiplicity 1 means (x-3).
The third part f(0) = 120 means substituting x=0 into (x+2)^3*(x-3)*k =120
(0+2)^3*(0-3)*k = 120
-24k = 120
k = -5
Combining all three conditions, f(x)
= -5(x+2)^3*(x-3)
= -5(x^3 + 3*2*x^2 + 3*2*2*x + 2^3)(x-3)
= -5(x^4 + 6x^3 + 12x^2 + 8x - 3x^3 - 18x^2 - 36x - 24)
= -5(x^4 + 3x^3 - 6x^2 - 28x -24)
= -5x^4 - 15x^3 + 30x^2 + 140x + 120