Answer:
1. B
2. A
3. C
Explanation:
1. Boyle's law is one of the gas laws that states that the pressure of a gas is inversely proportional to its volume at a constant temperature. PV = K. Hence, this gas law compares the properties of the pressure (P) and the volume (V)
2. Avogadro's law states that the volume of a gas is directly proportional to the number of molecules of that gas, at a constant temperature and pressure. K = Vn. Hence, this gas law compares the properties of the number of moles (n) and the volume (V).
3. Gay-Lussac's law states that the pressure of a gas is directly proportional with the temperature of the gas at a constant volume. K = PT. Hence, this law compares the properties of the pressure (P) and the temperature (T)
The properties compared by Boyle's law are pressure and volume, Avogadro's law is volume and moles, and Gay-Lussac's law is pressure and temperature.
What are the variations of ideal gas law?The ideal gas has the absence of interatomic collisions and follows the ideal gas equation.
The ideal gas law at constant pressure and temperature is termed Boyle's and Gay Lussac's law. The laws can be given as:
Boyle's law was the nature of ideal gas at a constant temperature and compares the pressure and volume of the gas.Avogadro's law was the ideal nature of gas, with the moles of gas and volume in specific value at constant temperature and pressure.Gay-Lussac's law compares the pressure and temperature of the gas at constant volume.Learn more about ideal gas laws, here:
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A student calculates the empirical formula of a compound to be C1.5H3.5. Express this as a correct empirical formula.
Answer:
No, the correct empirical formula is [tex]C_3H_7[/tex].
Explanation:
Hello there!
In this case, according to the given information, it turns out necessary for us to bear to mind the fact that empirical formulas must not be expressed in decimal numbers, for that reason, we need to multiply the given empirical formula by 2 to get the correct one:
[tex]C_3H_7[/tex]
Which is now possible.
Regards!
there are tiny plants growing on rock fence after the several year . you observe something happened on the rock which of the following describes your observations ? the plants the rock
it is moss
Explanation:
For a particular chemical reaction the rate (g/hr) at which one of the reactants changes is proportional to the amount of that reactant present. If y represents the amount of that reactant at time t, StartFraction dy Over dt EndFraction equals minus0.7y. If there were 70 grams of the reactant when the process started (tequals 0), how many grams will remain after 4 hours?
Answer:
Amount of reactant after four hours = 4,26 grams
Explanation:
Suppose y denotes the amount of reactant at the time (t)
The given function:
[tex]\dfrac{dy}{dt} = -0.7 y[/tex]
[tex]\dfrac{dy}{y} = -0.7 dt[/tex]
Taking integral on both sides
㏑(y) = -0.7t + c¹
[tex]e^{In(y)}= e^{-0.7t + c^1}[/tex]
[tex]y(t) = Ce ^{-0.7t}[/tex]
At t = 0 ; y (t) = 70
∴
[tex]70 = Ce^{-0.7(0)}[/tex]
C = 70
As such; [tex]\mathtt{y(t) = 70 e^{-0.7*t}}[/tex]
After four hours, the amount of the reactant is:
[tex]\mathtt{y(t) = 70 e^{-0.7*4}}[/tex]
[tex]\mathtt{y(t) = 70 e^{-2.8}}[/tex]
[tex]\mathtt{y(t) = 4.26}[/tex]
Amount of reactant after four hours = 4,26 grams
Match each term to the best description.
a. Blue-gray color
b. Chelating agent
c. EBT
d. EDTA
e. Pale purple-pink color
1. Eriochrome Black T
2. Starting color, before titration
3. Molecule that has a high affinity for ions
4. Ethylenediaminetetracetlc acid
5. Color at the completion of titration
Solution :
Term Best description
Eriochrome Black T EBT
Starting color, before titration Pale purple-pink color
Molecule that has a high affinity for metal ions Chelating agent
Ethylenediaminetetracetic acid EDTA
Color at the completion of titration Blue-gray color
Which is the balanced version of the half-reaction below?
H2S → S+H+
Answer:
C. [tex]H_2S\rightarrow S+2H^++2e^-[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction, it turns out possible to realize there is one sulfur atom on each side of the chemical equation but two hydrogen atoms on the left and one on the right, which means the latter must be balanced in agreement to the law of conservation of mass.
In such a way, by setting a 2 on H⁺, the reaction will be balanced:
[tex]H_2S\rightarrow S+2H^+[/tex]
Now, we count the transfer electrons for sulfur from -2 to 0 as 2e⁻ on the right, which will match with the option C.
[tex]H_2S\rightarrow S+2H^++2e^-[/tex]
Regards!
Chair and Boat Conformers of Cyclohexane (C6H12). Note it is impossible to place all the carbons in the same plane without straining the bonds. Take two opposite carbons and pull both of them up to make one conformation and then pull one of them down to make the other conformation.
a. Can you interconvert one conformer into the other without breaking any bonds?
b. Explain why these represent conformers and not isomers.
Answer:
See explanation
Explanation:
Conformation refers to the various spatial arrangements of atoms in a molecule that result from free rotation across the carbon-carbon single bond.
There are two possible conformations of cyclohexane. They are; the chair and boat conformations.
We can convert the molecule from one conformation to another by rotation of single bonds.
These conformations are not isomers. Isomers are different molecules while conformers are different spatial arrangements of the same molecule obtained by rotation across carbon-carbon single bonds. Isomers are not obtained by rotation across carbon-carbon single bonds.
Hence, the chair and boat conformers of cyclohexane are obtained by rotation across the carbon-carbon single bond hence they are conformers and not isomers.
An organelle that is not found in this illustration of a cell would be
A. the cell wall
B. chromosome
C. mitochondria
D. the cell membrane
Answer:
The answer is cell wall
Explanation:
Because it is
An ether and alkene are formed as by products in this reaction. draw the structures of these by-products and give mechanisms for their formation
Answer:
sim eu também preciso desta respota
An ether and alkene are formed as by products in the reaction which is a electrophilic addition reaction.
What is electrophilic addition reaction?An addition reaction known as an electrophilic addition reaction occurs when a chemical molecule having a double or triple bond has one of its bonds broken and two new bonds are formed. The interconversion of C=C and CC into a variety of significant functional groups, such as alkyl halides and alcohols, is made possible via the key.
The following describes the general mechanism: Hydrogen bromide produces an electrophile, H+, which attacks the double bond to create a carbocation. The production of ions is dominated by secondary carbocation because it is more stable than primary carbocation.
Thus, an ether and alkene are formed as by products in the reaction which is a electrophilic addition reaction.
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When 10.0 g of sulfur is combined with 10.0 g of oxygen, 20.0 g of sulfur dioxide is formed. What mass of oxygen would be required to convert 10.0 g of sulfur into sulfur trioxide?
Answer:
Actually, we can answer the problem even without the first statement. All we have to do is write the reaction for the production of sulfur trioxide.
2 S + 3 O₂ → 2 SO₃
The stoichiometric calculations is as follows:
6 g S * 1 mol/32.06 g S = 0.187 mol S
Moles O₂ needed = 0.187 mol S * 3 mol O₂/2 mol S = 0.2805 mol O₂
Since the molar mas of O₂ is 32 g/mol,
Mass of O₂ needed = 0.2805 mol O₂ * 32 g/mol = 8.976 g O₂
The normal freezing point of a certain liquid Xis-7.30°C but when l02. g of iron(III) chloride (FeCl3) are dissolved in 650. g of Xthe solution freezes at -9.9°C instead. Use this information to calculate the molal freezing point depression constant Kf of X.
Answer:
2.7 °C.kg/mol
Explanation:
Step 1: Calculate the freezing point depression (ΔT)
The normal freezing point of a certain liquid X is-7.30°C and the solution freezes at -9.9°C instead. The freezing point depression is:
ΔT = -7.30 °C - (-9.9 °C) = 2.6 °C
Step 2: Calculate the molality of the solution (b)
We will use the following expression.
b = mass of solute / molar mass of solute × kilograms of solvent
b = 102. g / (162.2 g/mol) × 0.650 kg = 0.967 mol/kg
Step 3: Calculate the molal freezing point depression constant Kf of X
Freezing point depression is a colligative property. It can be calculated using the following expression.
ΔT = Kf × b
Kf = ΔT / b
Kf = 2.6 °C / (0.967 mol/kg) = 2.7 °C.kg/mol
Identify each of the following sets of quantum numbers as allowed or not allowed in the hydrogen atom.
a. n=3 , l= 2 , ml =2
b. n=4 , l= 3 , ml =4
c. n=0 , l= 0 , mb =0
d. n=2 , l= 1 , mb =1
Answer:
See explanation.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to firstly recall the electron configuration of hydrogen:
[tex]1s^1[/tex]
To realize that the principal quantum number is 1, the angular is 0 as well as the magnetic one; therefore we infer that all the given n's are not allowed, just l=0 is allowed as well as ml=0 yet the rest, are not allowed.
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A weak acid is titrated with 0.1236 M NaOH. From the titration curve you determine that the equivalence point occurs after exactly 12.42 mL of NaOH have been added. What is the volume of NaOH at the half-equivalence point (a.k.a. the midpoint)
Answer: The volume of NaOH required at the half-equivalence point is 6.21 mL
Explanation:
The chemical equation for the reaction of a weak acid with NaOH follows:
[tex]HA+ NaOH\rightarrow NaA+H_2O[/tex]
From the equation, we can say that NaOH and weak acid is present in a 1 : 1 ratio.
We are given:
Volume of NaOH required at equivalence point = 12.42 mL
The volume of NaOH required at half-equivalence point will be = [tex]\frac{12.42mL}{2}=6.21mL[/tex]
Hence, the volume of NaOH required at the half-equivalence point is 6.21 mL
The volume of NaOH at the half-equivalence point is 6.21 mL
What is equivalence point?The equivalence point is the point at which equal amount of the acid and base have reacted.
How to determine the half-equivalence pointVolume at equivalence point = 12.42 mLVolume at half-equivalence point =?Half equivalence point = Equivalence point / 2
Half equivalence point = 12.42 / 2
Half equivalence point = 6.21 mL
Therefore, we can conclude that the volume of NaOH at the half-equivalence point is 6.21 mL.
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Compare the solubility of silver chloride in each of the following aqueous solutions:
a. 0.10 M AgNO3 More soluble than in pure water.
b. 0.10 M NaCI Similar solubility as in pure water
c. 0.10 M KNO3 Less soluble than in pure water.
d. 0.10 M NH4CH3COO
Answer:
Compare the solubility of silver chloride in each of the following aqueous solutions:
a. 0.10 M AgNO3 More soluble than in pure water.
b. 0.10 M NaCI Similar solubility as in pure water
c. 0.10 M KNO3 Less soluble than in pure water.
d. 0.10 M NH4CH3COO
Explanation:
This is based on common ion effect.
According to common ion effect, the solubility of a sparingly soluble salt decreases in a solution containing common ion to it.
The solubility of AgCl(s) is shown below:
[tex]AgCl(s) <=> Ag^{+}(aq)+Cl^-(aq)[/tex]
So, when it is placed in:
a. 0.10 M AgNO3
Due to common ion effect Ag+, its solubility is less in this solution than in pure water.
b. 0.10 M NaCI :
Due to common ion effect Cl-, its solubility is less in this solution than in pure water.
c. 0.10 M KNO3 :
In this solution there is no presence of common ion.
So, the solubility of AgCl in this solution is similar to that of pure water.
d. 0.10 M NH4CH3COO:
In this solution, AgCl forms a precipitate.
So, the solubility of AgCl is more in this solution compared to pure water.
Complete a chair conformation of trans-1-bromo-3-methylcyclohexane by placing the hydrogen, bromine, and methyl groups in the appropriate positions.
Place the bromine on the carbon that is more to the right.
Answer:
Explanation:
The most highly stable cycloalkane is cyclohexane. It does not suffer from an angle or torsional strain, and it has the appropriate stability as chain alkanes. Because of the peculiar conformation it takes, this stability leads to the cyclohexane conformation popularly known as the "chair" conformation.
However, from the information given;
The chair conformation structure of trans-1-bromo-3-methylcyclohexane is carefully drawn and the substituents are appropriately attached in the image below.
Which of the following is a protein source of plant origin
Answer:
soy....plant protein also is found in vegtables and grain products.
The protein that is derived from the plant is soyabean. Protein-rich foods have a rich source of amino acids. Amino acids are required by the body for different cellular activities.
What are proteins?
Proteins are present in plant-based foods and animal-based foods. In nature, the plant-based foods that are rich in proteins are soybeans, beans etc. Animal products such as dairy products, milk, and cheese are rich sources of proteins.
Animal-based foods such as eggs, meat, and fish have a good amount of protein. The proteins are made up of amino acids. Peptide bonds connect each amino acid to the next.
Proteins are necessary for the body, as cells need amino acids for both structural and functional support. Not all cells of the body synthesise all amino acids. Some essential amino acids are required by the body and can be taken from external sources such as plants.
Hence, the plant-based protein is soyabean.
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The question is incomplete; the complete question may be the following:
1) Which of the following is a protein source of plant origin?
A)egg
B) Soyabean
C)cheese
D)Milk
Explain why ethanol and water are miscible yet tetrachloride and water are immiscible.
Answer:
CCl4 can neither form H-bonds with water molecules nor can it break H-bonds in water molecules. Therefore, it is insoluble in water. Ethanol is a polar compound and can form H-bonds with water, which is a polar solvent. Therefore,it is miscible with water in all proportions
Explanation:
FIRSTLY WATER MOLECULES CONTAIN ONE OXYGEN AND TWO HYDROGEN(H2O) .HENCE IN THIS STRUCTURE THE BOND BETWEEN OXYGEN AND HYDROGEN IS COVALENT AND POLARIZABLE .HENCE OXYGEN ATOM ATTRACTS ELECTRONS MORE STRONGLY TOWARDS INWARDS AS COMPARE TO 2 HYDROGEN ATOMS. DUE TO WHICH OXYGEN ATOM GET SLIGHTLY NEGATIVE CHARGE AND 2 HYDROGEN OCCUPY SLIGHTLY POSITIVE CHARGE THAT MAKE WATER A POLAR MOLECULE. :NOW IN ETHANOL(CH3CH2OH),ETHANOL MOLECULE IS FORMED BY 2 CARBON ATOM JOINED BY SINGLE BOND WHICH IS NOT POLAR.IN β CARBON OF ETANOL CARBON IS BONDED TO 3 HYDROGEN ATOMS WHICH MAKES IT NON POLAR DUE TO SYMMETRY BUT α CARBON HAS 2 HYDROGEN AND 1 OH- ION (SAME AS IN THE CASE OF WATER MOLECULE) SO THIS CARBON ATOM BECAMES POLAR AND HENCE ETHANOL MOLECULES BECAMES POLAR. NOW WE KNOW THAT SAME CHARGE REPEL EACH OTHER AND UNLIKE CHARGES ATTRACTS EACH OTHER SO THE SLIGHTHLY POSITIVE CHARGE OF WATER MOLECULE MAKES A BOND WITH THE.
The weak ionization constant (Ka)
for HCN is equal to:
Answer:
Ka = [H⁺] × [CN⁻] / [HCN]
Explanation:
Cyanhydric acid is a weak acid, according to the following equation:
HCN(aq) ⇄ H⁺(aq) + CN⁻(aq)
The acid ionization constant (Ka) is equal to the product of the concentrations of the ions raised to the stoichiometric coefficients divided by the concentration of the undissociated acid raised to its stoichiometric coefficient.
Ka for HCN is:
Ka = [H⁺] × [CN⁻] / [HCN]
CAN SOMEONE HELP ME PLZ AND THANKS WILL MARK U AS BRAINLIEST
Explanation:
2. [tex]2C_2H_6 + 7O_2 \rightarrow 4CO_2 + 6H_2O[/tex]
First, we need to find the number of moles of [tex]CO_2[/tex] at 300K and 1.5 atm using the ideal gas law:
[tex]n= \dfrac{PV}{RT}= \dfrac{(1.5\:\text {atm})(33\:L)}{(0.082\:\text{L-atm/mol-K})(300K)}[/tex]
[tex]=2.0\:\text{mol}\:CO_2[/tex]
Now use the molar ratios to find the number of moles of ethane to produce this much [tex]CO_2[/tex].
[tex]2.0\:\text{mol}\:CO_2 \times \left(\dfrac{2\:\text{mol}\:C_2H_6}{4\:\text{mol}\:CO_2}\right)[/tex]
[tex]=1.0\:\text{mol}\:C_2H_6[/tex]
Finally, convert this amount to grams using its molar mass:
[tex]1.0\:\text {mol}\:C_2H_6 \times \left(\dfrac{30.07\:\text g\:C_2H_6}{1\:\text{mol}\:C_2H_6} \right)[/tex]
[tex]=30.1\:g\:C_2H_6[/tex]
3. [tex]3Zn + 2H_3PO_4 \rightarrow 3H_2 + Zn_3(PO_4)_2[/tex]
Convert 75 g Zn into moles:
[tex]75\:\text g\:Zn \times \left(\dfrac{65.38\:\text g\:Zn}{1\:\text{mol}\:Zn}\right)=1.1\:\text{mol}\:Zn[/tex]
Then use the molar ratios to find the amount of H2 produced.
[tex]1.1\:\text{mol}\:Zn \times \left(\dfrac{3\:\text{mol}\:H_2}{3\:\text{mol}\:Zn}\right)=1.1\:\text{mol}\:H_2[/tex]
Now use the ideal gas law [tex]PV=nRT[/tex] to find the volume of H2 produced at 23°C and 4 atm:
[tex]V= \dfrac{nRT}{P}= \dfrac{(1.1\:\text{mol}\:H_2)(0.082\:\text{L-atm/mol-K})(296K)}{4\:\text{atm}}[/tex]
[tex]=8.9\:\text L\:H_2[/tex]
10. What is the mass of SO3 when -8753 kJ of energy are used according
to the following equation?2S + 302 - 2003 AH = -791.4kJ Is this
Endothermic or Exothermic -8735kJ x mols03/kJ x gSO3/
molSO3
Answer:
Exothermic
1771 g
Explanation:
Step 1: Write the balanced thermochemical equation
2 S(s) + 3 O₂(g) ⇒ 2 SO₃(g) ΔH° = -791.4 kJ
Since ΔH° < 0, the reaction is exothermic.
Step 2: Calculate the moles of SO₃ produced when 8753 kJ of energy are released
According to the thermochemical equation, -791.4 kJ are released every 2 moles of SO₃ that are formed.
-8753 kJ × 2 mol/(-791.4 kJ) = 22.12 mol
Step 3: Calculate the mass corresponding to 22.12 moles of SO₃
The molar mass of SO₃ is 80.06 g/mol.
22.12 mol × 80.06 g/mol = 1771 g
what is a property of every mixture
Explanation:
can u post a picture of the question ?
Boiling point-methanol (65.0) 66.8c.Boiling point-unknown (record from video)——-c
Identify of unknown:
Possibilities are:Mathanol65.0c;Ethanol 78.5c; Acetone 56.0C
g A solution contains 100mM NaCl, 20mM CaCl2, and 20mM urea. We would say this solution is __________ compared to a 300 mOsM solution and ___________ compared to a cell with 300 mOsM (non-penetrating solutes) interior.
Answer:
A solution contains 100mM NaCl, 20mM CaCl2, and 20mM urea. We would say this solution is hypotonic compared to a 300 mOsM solution and hypotonic compared to a cell with 300 mOsM (non-penetrating solutes) interior.
Explanation:
The osmolarity is calculated from the molar concentration of the active particles in the solution. We have a solution that is composed of NaCl, CaCl₂ and urea.
When they are dissolved in water, they dissociate into particles as follows:
NaCl → Na⁺ + Cl⁻ (2 particles per compound)
CaCl₂ → Ca²⁺ + 2 Cl⁻ (3 particles per compound)
urea: not dissociation (1 particle per compound)
Then, we have to calculate the osmolarity of the solution. We multiply the molarity of each compound by the number of particles produced by the compound in water:
Osm = (100 mM NaCl x 2) + (20 mM CaCl₂ x 3) + (20 mM urea x 1) = 280 mOsm
Compared with 300 mOsm, 280 mOsm has a lower osmolarity, so it is a hypotonic solution.
To compare with a cell's osmolarity, we have to consider only the non-penetrating solutes. Urea is considered a penetrating solute for mammalian cells. So, the osmolarity of non-penetrating solutes (NaCl and CaCl₂) is calculated as:
Osm (non-penetrating solutes) = (100 mM NaCl x 2) + (20 mM CaCl₂ x 3) = 260 mOsm
Therefore, we have:
Compared to 300 mOsm solution ⇒ 280 mOsm solution is a hypotonic solution
Compared to a cell with 300 mOsm ⇒ 260 mOsm solution is hypotonic
In the following neutralization reaction, which substance is the acid?
HCI + NaOH - NaCl + H20
ОА.
НСІ
OB.
NaOH
OC.
NaCl
OD. H20
Answer:
HCl is a acid
Explanation:
NaOH is base
Nacl is salt
Problem PageQuestion A chemist makes of magnesium fluoride working solution by adding distilled water to of a stock solution of magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to significant digits. Clears your work. Undoes your last action. Provides information about entering answers.
Answer:
5.37 × 10⁻⁴ mol/L
Explanation:
A chemist makes 660. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a 0.00154 mol/L stock solution of magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.
Step 1: Given data
Initial concentration (C₁): 0.00154 mol/LInitial volume (V₁): 230. mLFinal concentration (C₂): ?Final volume (V₂): 660. mLStep 2: Calculate the concentration of the final solution
We want to prepare a dilute solution from a concentrated one. We can calculate the concentration of the final solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
C₂ = C₁ × V₁ / V₂
C₂ = 0.00154 mol/L × 230. mL / 660. mL = 5.37 × 10⁻⁴ mol/L
What is the major organic product obtained from the sequence of reactions 2-phenyl-4 bomobutane and NaN3?
Answer:
(E)-1-phenylbut-1-ene
Explanation:
2-phenyl-4 bromobutane is an amphetamine that contains a phenyl group. It forms a major stable product with other reacting agents.
The major organic product that is obtained from the sequence of the reactions of the 2-phenyl-4 bomobutane when it reacts with [tex]NaN_3[/tex] is the (E)-1-phenylbut-1-ene.
Thus the answer is 2-phenyl-4 bromobutane is an amphetamine that contains a phenyl group. It forms a major stable product with other reacting agents.
The major organic product that is (E)-1-phenylbut-1-ene.
In centigrade bromine has a melting point of -7 and a boiling point of 58. Room temperature is 20. What is bromine at this temperature? Answers- Solid Liquid Gas
Solid with some liquid. It has to be one of those/
Answer:
Bromine will be a liquid
An experiment was performed under identical conditions as yours. The absorbance of the penny solution was recorded as 0.219 absorbance units. A calibration plot of absorbance vs. concentration of Cu(II) (M) yielded the following trendline equation:
y= 11.589x - 0.0002
Required:
What is the concentration (mol/L) of the penny solution?
Answer:
Concentration C = 0.0189 mol/L
Explanation:
From the given information:
Let consider the formula used in calculating the concentration according to Beer's law:
[tex]\mathtt{A =\varepsilon \times L \times C}[/tex] --- (1)
here;
A = absorbance
ε = coefficient of molar absorptivity
L = path length
C = concentration (mol/L)
Also, from Beer law plot:
y = mx+b
where,
y represent absorbance A
b represents intercept
m represents the coefficient of molar absorptivity ε
and x represents the concentration(C).
replacing the substituted entities
A = ε × C + b ---- (2)
Making the concentration the subject of the above formula:
[tex]C = \dfrac{A-b}{\varepsilon}[/tex]----(3)
From y = 11.589x - 0.0002
A = 11.589 *C - 0.0002
Given that:
A = 0.219
∴
0.219 = 11.589 *C - 0.0002
0.219 + 0.0002 = 11.589 *C
C = 0.2192/11.589
C = 0.0189 mol/L
Based on your knowledge of factors affecting the rate of reaction, why is there a danger of explosions in places such as flour mills and coal mines where there are large quantities of powdered, combustible materials?
Answer:
See Explanation
Explanation:
Rate of reaction refers to how quickly or slowly a reaction proceeds. The rate of reaction depends on certain factors.
Two among the factors that affect the rate of reaction are the concentration of reactants and the surface area of reactants.
The more the concentration of reactants, the faster the rate of reactants because there is a high possibility of collision between reactants. Also, the higher the surface area of reactants, the greater the rate of reaction.
In flour mills and coal mines where there is a large amount (concentration) of combustible materials and the particles are powdered (high surface area), there is a greater risk of explosion due to a high rate of reaction owing to a combination of the two factors discussed above.
which is the correct orbital diagram for carbon
Answer:
Below
Explanation:
Got it right
Check the periodic table, then click electrons
HELP PLZ SND THANKS WILL MARK YOU AS BRAINLIEST
Answer:
See explanation
Explanation:
For the first question, we can see that the pressure is constant so we apply Charles law;
V1/T1 =V2/T2
V1T2 = V2T1
V1= 4.5 L
T1= 27 + 273 = 300 K
V2= ?
T2= 127 + 273 = 400 K
V2= V1T2/T1
V2= 4.5 × 400/300
V2= 6L
For question 2, Charles law is also used;
V1/T1 =V2/T2
V1T2 = V2T1
T1= 338 K
V1= 0.480 L
T2= ?
V2= 9.2 L
T2= V2T1/V1
T2= 9.2 × 338/0.480
T2= 6478.3 K
