Math algebra 2 show you’re work plz

Math Algebra 2 Show Youre Work Plz

Answers

Answer 1

9514 1404 393

Answer:

  (t, u, w) = (1, -2, -2)

Step-by-step explanation:

A graphing calculator makes short work of this, giving the solution as ...

  (t, u, w) = (1, -2, -2)

__

There are many ways to solve this "by hand." Here's one of them.

Add the first and third equations. Their sum is ...

  -3t +4w = -11 . . . . . [eq4]

Add this to twice the second equation. That sum is ...

  (-3t +4w) +2(-4t -2w) = (-11) +2(0)

  -11t = -11

  t = 1

Substituting this into the second equation gives ...

  -4(1) -2w = 0

  w +2 = 0 . . . . divide by -2

  w = -2 . . . . add -2

Substituting for t in the third equation lets us find u.

  2(1) -2u = 6

  -1 +u = -3 . . . . . divide by -2

  u = -2 . . . . add 1

The solution is (t, u, w) = (1, -2, -2).


Related Questions

PLEASE HELP I DONT NEED EXPLANATION JUST THE EQUATION IM IN A TEST RN HELP ASAP THANK YOU SO MUCH :)))

Answers

Answer:

[tex]-x^{2}[/tex]

Step-by-step explanation:

It simple really its just a reflection over the x-axis making it a negative towards the parent function

Answer:

The answer is -x²

Step-by-step explanation:

Hope this helps :)

Suppose these data show the number of gallons of gasoline sold by a gasoline distributor in Bennington, Vermont, over the past 12 weeks.
Week Sales (1,000s of gallons)
1 17
2 22
3 20
4 24
5 18
6 17
7 21
8 19
9 23
10 21
11 16
12 23
(a) Using a weight of
1
2
for the most recent observation,
1
3
for the second most recent observation, and
1
6
for third most recent observation, compute a three-week weighted moving average for the time series. (Round your answers to two decimal places.)

Compute four-week and five-week moving averages for the time series.
Week Time Series Moving
Value Average Forecast

1 17
2 22
3 20
4 24
5 18
6 17
7 21
8 19
9 23
10 21
11 16
12 23
(b) Compute the MSE for the four-week moving average forecasts. (Round your answer to two decimal places.)
Compute the MSE for the five-week moving average forecasts. (Round your answer to two decimal places.)
(c) What appears to be the best number of weeks of past data (three, four, or five) to use in the moving average computation? MSE for the three-week moving average is 11.12.

Answers

Answer:

Use suitable identity to find the product (3-2x)(3+2x).Find the remainder when x³+ 3x²+3x+1 is divided by x+1.On a plane surface we can find straight lines.8√15 + 2√3The decimal form of 36 100(a-b)³ = a ³- ........ 3 + 3ab²-b³In the Cartesian plane the horizontal line is called .........The coefficient of x² in 2-x²+ x³ is -1.√225 is an irrational number.The coordinates of a point on x-axis is (y, 0).The coordinates of a point on x-axis is (y, 0).The coordinates of a point on x-axis is (y, 0).The coordinates of a point on x-axis is (y, 0).

What do the chi-square test for independence, the Pearson correlation, and simple linear regressions all have in common

Answers

Answer:

They all test relationship when it involves two variables

Explanation:

All of the statistical methods listed above all measure the relationship between two variables.

The Chi Square test tests the relationship between two nominal/categorical variable groups.

The Pearson correlation test tests relationship between two continuous variables using the Pearson correlation coefficient to determine statistical relationship between them.

The simple linear regression measures relationship between two variables: dependent/response variable and independent/explanatory variable, to see if a relationship exists between by way of influence of the independent variable on the dependent variable.

How to answer this question

Answers

Answer:

(0.3049 ; 0.3751)

Step-by-step explanation:

The confidence interval for proportion can be obtained using the relation :

Phat ± Zcritical * [√phat(1-phat) / n]

phat = x / n

Sample size, n = 700

x = 238

phat = 238/700 = 0.34

Zcritical at 95% = 1.96

C.I = 0.34 ± 1.96 * [√0.34(1-0.34) / 700]

C.I = 0.34 ± 1.96 * 0.0179045

C. I = 0.34 ± 0.0350928

Lower boundary = 0.34 - 0.0350928 = 0.3049

Upper boundary = 0.34 + 0.0350928 = 0.37509

(0.3049 ; 0.3751)

Allie rode her bike up a hill at an average speed of 12 feet/second. She then rode back down the hill at an average speed of 60 feet/second. The entire trip took her 2 minutes. What is the total distance she traveled. [Hint: use t = time traveling down the hill]

Answers

Answer:

The total distance Allie traveled was 0.81 miles.

Step-by-step explanation:

Since Allie rode her bike up a hill at an average speed of 12 feet / second, and she then rode back down the hill at an average speed of 60 feet / second, and the entire trip took her 2 minutes, to determine what is the total distance she traveled, the following calculation must be performed:

12 + 60 = 72

72 x 60 = 4320

1000 feet = 0.189394 miles

4320 feet = 0.8181818 miles

Therefore, the total distance Allie traveled was 0.81 miles.

5a2 + b(a2 + 5) + b2​

Answers

Given:

[tex]\rightarrow\sf {5a}^{2} + {b(a}^{2} + 5) + {b}^{2} [/tex]

Solution:

[tex]\rightarrow\sf {5a}^{2} + {b(a }^{2} + 5) + {b}^{2} \\ = \sf {5a}^{2} + {ba}^{2} + b \times 5 + {b}^{2} \\ = \large\boxed{\sf{\red{ {5a}^{2} + {ba}^{2} + 5b + {b}^{2} }}}[/tex]

Answer:

[tex]\rightarrow\large\boxed{\sf{\red{ {5a}^{2} + {ba}^{2} + 5b + {b}^{2} }}}[/tex]

[tex]\color{red}{==========================}[/tex]

✍︎ʜɴǫɴ

✍︎ʀʀʏɴʟʀɴɪɴɢ

if 8km=5miles.how many miles are in 56m?​

Answers

Answer:

89.6 miles

Step-by-step explanation:

[tex]\frac{8}{5}[/tex] = [tex]\frac{x}{56}[/tex]

5x = 448

x=89.6

Step-by-step explanation:

if 8km=5

x =56km

5x=8×56

5x=448

x=89.6 miles

On dividing 12x³ by 4x the quotient is …..​

Answers

Answer:

12x^3 is equivalent to

12x*12x*12x which if we multiply is

1728x

we divide by 4x

1728x divided by 4x=432x

Hope This Helps!!!

Answer:

3x^2

Step-by-step explanation:

when u divide 12x^3/4x....u divide 12/4=3 along with the x also..tat is x^3/x=x^2

please help i am stuck on this assignment

Answers

Answer:

answer

x = -13/ 15, 0

Step-by-step explanation:

15x^2 + 13 x = 0

or, x(15x + 13) = 0

either, x = 0

or, 15x + 13 = 0

x = -13/15

Answer:

The answer should be C...............

imma sorry if I'm wrong

A movie theater has a seating capacity of 283. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults. There are half as many adults as there are children. If the total ticket sales was $ 2060 on a sold out night, how many children, students, and adults attended

Answers

Answer: adults = 79

children = 158

student = 46

Step-by-step explanation:

Let a = adults

Let c = children

Let s = student

From the information given,

a + c + s = 283 ....... i

c/a = 2, c = 2a ....... ii

5c + 7s + 12a = 2060 ...... iii

Put the value of c = 2a into equation i

a + c + s = 283

a + 2a + s = 283

3a + s = 283

s = 283 - 3a

Note that c = 2a

From equation iii

5c + 7s + 12a = 2060

5(2a) + 7(283 - 3a) + 12a = 2060

10a + 1981 - 21a + 12a = 2060

10a + 12a - 21a = 2060 - 1981

a = 79

Note c = 2a

c = 2 × 79 = 158

Since a + c + s = 283

79 + 158 + s = 283

s = 283 - 237

s = 46

adults = 79

children = 158

student = 46

The population of retired citizens in Minneapolis is 86700. If the population increases at a rate of 8.9% each year. What will the population of retirees be in 7 years? Write an exponential growth model for the future population P(x) where r is in years: P(x) = What will the population be in 7 years? (Round to nearest person)​

Answers

Answer:

157,476 people

Step-by-step explanation:

the formula :

P(x) = 86700. (1+ 0.089)^r

for r = 7

=> P(x) = 86700 × (1+ 0.089)^7

= 86700 × (1.089)^7

= 86700 × 1.8163

= 157,476 people

Rajah / Diagram 5 (b) Dalam Rajah 6, PQ ialah tangen sepunya dua bulatan. AQ dan BQ ialah tangen bagi bulatan yang masing-masing berpusat E dan F. Cari nilai x dan y. In Diagram 6, PQ is the common tangent of two circles. AQ and BQ is the tangent to the circles with centre E and F respectively. Find the value of x and y. [3 markah.​

Answers

Answer:

36281629273781646181993836619946527189119292937467482919198$7473828191927364732818919283838292927383883829118661552621718919191019284746617171819001187373765252728

Step-by-step explanation:

173899918377+28910873638282

Suppose the age that children learn to walk is normally distributed with mean 12 months and standard deviation 2.5 month. 34 randomly selected people were asked what age they learned to walk. Round all answers to 4 decimal places where possible.

Answers

Answer:

Step-by-step explanation:

a.) it's just mean, variance

so here it's just 12,6.25

b.) For the x bar thing just divide the variance by the number of people (mean stay the same)

the variance is then (2.5²/34)= .1838

which makes it (12,.1838)

c.) here we don't use x bar (and so it's normal (12,2.5²))

p(11.6) = (11.6-12)/(2.5)= -.16 = .4364

p(12.4)= (12.4-12)/2.5 = .16= .5636

.5636-.4364= .1272

d.) here we use x bar because it's asking for an average so it's normal (12, .1838)

same deal

p(11.6)=(11.6-12)/√.1838= -.93295= .1762

p(12.4)= (12.4-12)/√.1838= .93295= .8238

.8238-.1762= .6476

d.) no because they're probably IID

f.) It's average so here we use x bar

q1 is just the 25th percentile

the 25th percentile is -.6745

-.6745=(x-12)/(√.1838)= 11.711

q3 is the 75th percentile

.6745=(x-12)/√.1838

x=12.289

The interquartile range is just the difference between the two

12.289-11.711= .5784

What is the greatest common factor of 3^3 x 5^4 and 2 x 5^3 x 11?

Answers

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{3^3 \times 5^4}[/tex]

[tex]\mathsf{3^3}[/tex]

[tex]\mathsf{= 3\times3\times3}[/tex]

[tex]\mathsf{= 9\times3}[/tex]

[tex]\mathsf{= \bf 27}[/tex]

[tex]\mathsf{5^4}[/tex]

[tex]\mathsf{= 5\times 5\times5\times 5}[/tex]

[tex]\mathsf{= 25\times25}[/tex]

[tex]\mathsf{= \bf 625}[/tex]

[tex]\mathsf{27 \times625}[/tex]

[tex]\mathsf{= \bf 16,875}[/tex]

[tex]\mathsf{2\times5^3\times11}[/tex]

[tex]\mathsf{5^3}[/tex]

[tex]\mathsf{= 5\times 5\times5}[/tex]

[tex]\mathsf{= 25\times 5}[/tex]

[tex]\mathsf{\bf = 125}[/tex]

[tex]\mathsf{2\times125\times11}[/tex]

[tex]\mathsf{= 250\times11}[/tex]

[tex]\mathsf{\bf = 2,750}[/tex]

[tex]\large\textsf{Find the Greatest Common Factor (GCF) of 16,875 \& 2,750}[/tex]

[tex]\large\textsf{16,875: 1, 3, 5, 9, 15, 25, 27, 45, 75, 125, 135, 225, 375, 625, 675, 1,125,}\\\\\large\textsf{1,875, 3,375, 5,625, \& 16,875}[/tex]

[tex]\large\textsf{2,750: 1, 2, 5, 10, 11, 22, 25, 50, 55, 110, 125, 250, 275, 550, 1,375, \& 2,750}[/tex]

[tex]\boxed{\boxed{\huge\textsf{Answer: the GCF is \bf 125 }}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Find the value of x in each case

Answers

The answer is 36 degrees

Step 1

Angle GEH=180-2x (angles on a a straight line are supplementary)

Step 2

4x= G^+GE^H(sum of exterior angle)

4x=x+(180-2x)

4x=180-x

4x+x=180

5x=180

x=36 degrees

Imagine that you need to compute e^0.4 but you have no calculator or other aid to enable you to compute it exactly, only paper and pencil. You decide to use a third-degree Taylor polynomial expanded around x =0. Use the fact that e^0.4 < e < 3 and the Error Bound for Taylor Polynomials to find an upper bound for the error in your approximation.

|error| <= _________

Answers

Answer:

0.0032

Step-by-step explanation:

We need to compute [tex]e^{0.4}[/tex] by the help of third-degree Taylor polynomial that is expanded around at x = 0.

Given :

[tex]e^{0.4}[/tex] < e < 3

Therefore, the Taylor's Error Bound formula is given by :

[tex]$|\text{Error}| \leq \frac{M}{(N+1)!} |x-a|^{N+1}$[/tex]   , where [tex]$M=|F^{N+1}(x)|$[/tex]

         [tex]$\leq \frac{3}{(3+1)!} |-0.4|^4$[/tex]

         [tex]$\leq \frac{3}{24} \times (0.4)^4$[/tex]

         [tex]$\leq 0.0032$[/tex]

Therefore, |Error| ≤ 0.0032

One number is 1/4 of another number. The sum of the two numbers is 5. Find the two numbers. Use a comma to separate your answer

Answers

Answer: 1, 4

Step-by-step explanation:

Number #1 = xNumber #2 = [tex]\frac{1}{4} x[/tex]

[tex]\frac{1}{4} x+x=5\\\\\frac{1}{4} x+\frac{4}{4} x=5\\\\\frac{5}{4} x=5\\\\5x=4*5\\5x=20\\x=4[/tex]

Number #1 = x = 4Number #2 = [tex]\frac{1}{4} x[/tex] = [tex]\frac{1}{4} *4=\frac{4}{4} =1[/tex]

In order for the parallelogram to be a
rhombus, x = [?].
(5x + 25)
(12x + 11)

Answers

A parallelogram is also a rhombus if the diagonal is a bisector of an angle enclosed by the two adjacent sides of a parallelogram.

In our case it means,

[tex]5x+25=12x+11[/tex]

[tex]7x=14\implies x=\boxed{2}[/tex]

Hope this helps.

In order for the parallelogram to be a rhombus, ,For the parallelogram to be a rhombus, x must be equal to 2.

To determine the value of x that would make the parallelogram a rhombus, we need to compare the lengths of its opposite sides. In a rhombus, all four sides are equal in length. So, we can equate the lengths of the opposite sides of the parallelogram and solve for x.

Given that one side has a length of (5x + 25) and the opposite side has a length of (12x + 11), we can set up the following equation: 5x + 25 = 12x + 11

To solve for x, we can start by isolating the x term on one side of the equation. We can do this by subtracting 5x from both sides: 25 = 12x - 5x + 11 Simplifying the equation further: 25 = 7x + 11 Next, we can isolate the x term by subtracting 11 from both sides: 25 - 11 = 7x 14 = 7x Finally, we can solve for x by dividing both sides by 7: 14/7 = x x = 2 Therefore, for the parallelogram to be a rhombus, x must be equal to 2.

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Suppose 46% of politicians are lawyers. If a random sample of size 662 is selected, what is the probability that the proportion of politicians who are lawyers will differ from the total politicians proportion by less than 4%

Answers

Answer:

0.9606 = 96.06% probability that the proportion of politicians who are lawyers will differ from the total politicians proportion by less than 4%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Suppose 46% of politicians are lawyers.

This means that [tex]p = 0.46[/tex]

Sample of size 662

This means that [tex]n = 662[/tex]

Mean and standard deviation:

[tex]\mu = p = 0.46[/tex]

[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.46*0.54}{662}} = 0.0194[/tex]

What is the probability that the proportion of politicians who are lawyers will differ from the total politicians proportion by less than 4%?

p-value of Z when X = 0.46 + 0.04 = 0.5 subtracted by the p-value of Z when X = 0.46 - 0.04 = 0.42. So

X = 0.5

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.5 - 0.46}{0.0194}[/tex]

[tex]Z = 2.06[/tex]

[tex]Z = 2.06[/tex] has a p-value of 0.9803

X = 0.42

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.42 - 0.46}{0.0194}[/tex]

[tex]Z = -2.06[/tex]

[tex]Z = -2.06[/tex] has a p-value of 0.0197

0.9803 - 0.0197 = 0.9606

0.9606 = 96.06% probability that the proportion of politicians who are lawyers will differ from the total politicians proportion by less than 4%

kxndjdkdkdkkdkskskdkdjdjdjskskskdjdjddjd​

Answers

Answer:

Not a functionFunctionFunctionNot a functionNot a function

Hope this helps!

The distribution of the number of apples trees a farmer can plant each day is bell-shaped and has a mean of 62 and a standard deviation of 8. Use the empirical rule to help you answer the following. What is the approximate percentage of trees planted between 38 and 68

Answers

Answer:

The empirical rule, the approximate percentage of trees planted between 38 and 68 is 99.7%.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 62, standard deviation of 8.

What is the approximate percentage of trees planted between 38 and 86?

38 = 62 - 3*8

86 = 62 + 3*8

So within 3 standard deviations of the mean, which, by the empirical rule, the approximate percentage of trees planted between 38 and 68 is 99.7%.

A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression. How many people clicked on the banner ad

Answers

Answer:

300

Step-by-step explanation:

[tex] \frac{1.5}{100} = 20000 \\ 20000 \div 100 = 200 \\ 200 \times 1.5 = 300[/tex]

if A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression then 300 people clicked on the banner ad

What is Percentage?

percentage, a relative value indicating hundredth parts of any quantity.

A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression.

We need to find how many people clicked on the banner ad.

Let us find the value of  1.5%  of 20000

Convert 1.5 % to decimal

1.5/100=0.015

Now multiply 0.015 with 20000

0.015×20000

300

Hence, if A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression then 300 people clicked on the banner ad

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help i’ll give brainliest please hurry

Answers

oceans crust inner outer mantle

find the place value of 1 in 382619.​

Answers

Answer:

Place value of 1 = 1 × 10 = 10

Step-by-step explanation:

In 382619,

Place of 1 = Tens

Place value of 1 = 1 × 10 = 10

The place value of 1 is 10 as it is in the tens column.

* Insert a digit to make numbers that are divisible by 6 if it is possible:
234_6

Answers

Answer:

i put in 3 to make 23436 because 36 is divisible by 6

Solve the inequality and write the solution set using both set-builder notation and interval notation. -3a-15≤-2a+6

Answers

Answer:

[tex]\{a[/tex][tex]R\ -21 \le a \le \infty \}[/tex] --- set builder

[tex][-21,\infty)[/tex] --- interval notation

Step-by-step explanation:

Given

[tex]-3a - 15 \le -2a + 6[/tex]

Required

Solve

Collect like terms

[tex]-3a + 2a \le 15 + 6[/tex]

[tex]-a \le 21[/tex]

Divide by -1

[tex]a \ge - 21[/tex]

Rewrite as:

[tex]-21 \le a[/tex]

Using set builder

[tex]\{a[/tex][tex]R\ -21 \le a \le \infty \}[/tex]

Using interval notation, we have:

[tex][-21,\infty)[/tex]

A trough is 10 ft long and its ends have the shape of isosceles triangles that are 4 ft across at the top and have a height of 1 ft. If the trough is being filled with water at a rate of 15 ft3/min, how fast is the water level rising when the water is 8 inches deep

Answers

Answer:

7.5 ft³/min

Step-by-step explanation:

Let x be the depth below the surface of the water. The height, h of the water is thus h = 10 - x.

Now, the volume of water V = Ah where A = area of isosceles base of trough = 1/2bh' where b = base of triangle = 4 ft and h' = height of triangle = 1 ft. So, A = 1/2 × 4 ft × 1 ft = 2 ft²

So, V = Ah = 2h = 2(10 - x)

The rate of change of volume is thus

dV/dt = d[2(10 - x)]/dt = -2dx/dt

Since dV/dt = 15 ft³/min,

dx/dt = -(dV/dt)/2 = -15 ft³/min ÷ 2 = -7.5 ft³/min

Since the height of the water is h = 10 - x, the rate at which the water level is rising is dh/dt = d[10 - x]/dt

= -dx/dt

= -(-7.5 ft³/min)

= 7.5 ft³/min

And the height at this point when x = 8 inches = 8 in × 1 ft/12 in  = 0.67 ft is h = (10 - 0.67) ft = 9.33 ft

what are the coordinates of the point that is 1/6 of the way from a(14 -1) to b(-4 23)

Answers

9514 1404 393

Answer:

  (11, 3)

Step-by-step explanation:

That point is ...

  P = a + (1/6)(b -a) = (5a +b)/6

  P = (5(14, -1) +(-4, 23))/6 = (70-4, -5+23)/6 = (11, 3)

The point of interest is (11, 3).

Answer:

The coordinates of the point that is 1/6 of the way from a to b is thus (11, 3)

Step-by-step explanation:

Let's look first at the x coordinates of the two given points:  14 and -4.  From 14 to -4 is a decrease of 18.  Similarly, from y = -1 to y = 23 is an increase of 24.

Starting at a(14, -1) and adding 1/6 of the change in x, which is -18, we get the new x-coordinate 14 + (1/6)(-18), or 14 - 3, or 11.  Similarly, adding 1/6 of the increase in y of 24 yields -1 + 4, or 3.

The coordinates of the point that is 1/6 of the way from a to b is thus (11, 3)

Suppose a research company takes a random sample of 45 business travelers in the financial industry and determines that the sample average cost of a domestic trip is $1,192, with a sample standard deviation of $279. Construct a 98% confidence interval for the population mean (for domestic trip) from these sample data. Round your answers to 3 decimal places.

Answers

Answer:

98% confidence interval for the population mean =(1095.260,1288.740)

Step-by-step explanation:

We are given that

n=45

[tex]\mu=1192[/tex]

Standard deviation,[tex]\sigma=279[/tex]

We have to construct a 98% confidence interval for the population mean.

Critical value of z at 98% confidence, Z =2.326

Confidence interval is given by

[tex](\mu\pm Z\frac{\sigma}{\sqrt{n}})[/tex]

Using the formula

98% confidence interval is given by

[tex]=(1192\pm 2.326\times \frac{279}{\sqrt{45}})[/tex]

[tex]=(1192\pm 96.740)[/tex]

=[tex](1192-96.740,1192+96.740)[/tex]

=[tex](1095.260,1288.740)[/tex]

Hence, 98% confidence interval for the population mean (1095.260,1288.740)

Which of the following equations describes this graph?
A. y=(x-1)^2-
B. y=(x-3)^2+2
C. y=(x+1)^2-2
D. y=(x-2)^2+3

Answers

Answer:

The choose (A)

y=(x-1)²-2

Other Questions
Cost outlays are recorded as an expense when they are incurred to earn revenue in the _______________ accounting period Which text feature would best clarify the information in this part of Javiers paper? an illustrated diagram of a samurai in full battle gear a chart showing the time warriors spent in training a bulleted list itemizing the samurai's codes of conduct a time line with dates and events leading to the rise of the samurai A recursive method may call other methods, including calling itself. A recursive method has: 1. a base case -- a case that returns a value or exits from a method without performing a recursive call. 2. a recursive case -- calling the method again with a smaller case..Study the recursive method given below. 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