Answer:
The percentage of people that could be expected to score the same as Matthew or higher on this scale is:
= 93.3%.
Step-by-step explanation:
a) Data and Calculations:
Mean score on the scale, μ = 50
Distribution's standard deviation, σ = 10
Matthew scores, x = 65
Calculating the Z-score:
Z-score = (x – μ) / σ
= (65-50)/10
= 1.5
The probability based on a Z-score of 1.5 is 0.93319
Therefore, the percentage of people that could be expected to score the same as Matthew or higher on this scale is 93.3%.
How do I solve this?
Answer: 3
Step-by-step explanation: m=2 so 7.5x2 = 15
15/5 is 15 divided by 5 so the answer is 3
The mean of a data set is observed to be very different from its median, representing a strong skewness. However, the 1.5 IQR rule reveals that there are no outliers. Which of the following is correct, if the sample size is 100?
a. A normal quantile plot of the data follows a diagonal line, and the t-procedure is appropriate to use.
b. A normal quantile plot of the data does not follow a diagonal line, and the t- procedure is not appropriate to use.
c. A normal quantile plot of the data follows a diagonal line, and the t-procedure is not appropriate to use.
d. A normal quantile plot of the data does not follow a diagonal line, and the t- procedure is appropriate to use.
Answer:
a. A normal quantile plot of the data follows a diagonal line, and the t-procedure is appropriate to use.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
In this question:
Sample size of 100 > 30, which means that we use the Central Limit Theorem, and thus, the sampling distribution is approximately normal, following a diagonal line, and since the standard deviation of the population is not know, we use the t-procedure. Thus, the correct answer is given by option a.
show that 43\2^4×5^3 will terminate after how many places of the decimal
Answer:
4 places after the decimal.
the result is 0.0215
Step-by-step explanation:
I assume the expression is really
43 / (2⁴ × 5³)
this is the same as
(((((((43 / 2) / 2) / 2) / 2) / 5) / 5) / 5)
since the starting value is an odd number, the first division by 2 creates a first position after the decimal point, and it must be a 5, as the result is xx.5
the second division by 2 splits again the uneven end .5 in half, creating a second position after the decimal point again ending in 5, as the result is now xx.x5
the third division by 2 does the same thing with that last 5 and creates a third position after the decimal point ending again in 5, as the result is now xx.xx5
the fourth division by 2 does again the same thing, a fourth position after the decimal point is created ending in 5. now xx.xxx5
in essence, every division of the 0.5 part by 2 is the same as a multiplication by 0.5, which squares 0.5 leading to 0.5². the next division did the same thing leading to 0.5³.
and finally the fourth division to 0.5⁴.
0.5⁴ = (5/10)⁴ = 5⁴/10⁴
so, now we start to divide this result by 5. since the positions after the decimal point are divisible by 5 without remainder, as we have 5⁴ to work with.
every divisible by 5 takes one of these powers away.
so, we go from 5⁴/10⁴ to 5³/10⁴ to 5²/10⁴ to 5/10⁴.
all the time we maintain the 10⁴ in the denominator of the fraction. and that determines the positions after the decimal point.
so, after all the individual divisions we come to and end and are still limited to the 4 positions after the decimal point.
Use the relationship among the three angles of any triangle to solve. Two angles of a triangle have the same
measure and the third angle is 27° greater than the measure of the other two. Find the measure of each angle.
Please help :)
Answer:
51°,51°,78°
Step-by-step explanation:
The sum of angles in a triangle add up to 180°
1. Write 3.3.3.3.3 as a power.
Answer:
3^5
Step-by-step explanation:
On the iPad it looks like that but the five is on the top right smaller
Answer:
3⁵
every 3 has it own power that is 1 however that .3 confused us
In July 2014 one Mexican peso was worth 0.075 U.S. dollars. How many Mexican pesos was $133.00 U.S. dollars worth?
Answer:
1,773.33 Mexican pesos
Step-by-step explanation:
Create a proportion where x was how many Mexican pesos it was worth:
[tex]\frac{1}{0.075}[/tex] = [tex]\frac{x}{133}[/tex]
Cross multiply and solve for x:
133 = 0.075x
1773.33 = x
So, it was worth approximately 1,773.33 Mexican pesos
Hello!
i need help with question 67 & 68
Answer:
67. A
68. D
Step-by-step explanation:
I don't remember exactly the explanation, but I recommend you try to learn more about number lines sometime when you aren't under stress from schoolwork, because they're pretty simple questions to answer once you get a better understanding of them!
a bag contain 3 black balls and 2 white balls.
1. A ball is taken from the black and then replaced, a second is taken. what is the probabilities that.
(a) there are both black,
(b)one is black one is white,
(c) at lease one is black,
(d) at most one is one is black.
2. find out if all the balls are chosen without replacement.
please kindly solve with explanation. thank you.
Answer:
Step-by-step explanation:
Total number of balls = 3 + 2 = 5
1)
a)
[tex]Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\[/tex]
b)
[tex]Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}[/tex]
c)
Probability of at least one black( means BB or BW or WB)
[tex]=\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}[/tex]
d)
Probability of at most one black ( means WW or WB or BW)
[tex]=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}[/tex]
2)
a) Probability both black without replacement
[tex]=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}[/tex]
b) Probability of one black and one white
[tex]=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}[/tex]
c) Probability of at least one black ( BB or BW or WB)
[tex]=\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}[/tex]
d) Probability of at most one black ( BW or WW or WB)
[tex]=\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}[/tex]
Given right angle ABC, what the value of tan(A)?
5/13
12/13
12/5
13/12
need answer asap
Hi there!
[tex]\large\boxed{12/5}}[/tex]
tan (angle) = Opposite side / Adjacent side, so:
Tan (A) = opposite side / adjacent side
= 24 / 10
Simplify:
= 12 / 5
09:30 am - 4:30 pm minus 30 minutes?
Answer:
4:30
because 9:30 minus 4:30 = 5:00 and 5:00 minus 30 =4:30
which pair of fractions are equivalent? 2/3 and 12/9 20/40 and 45/ 55 20/40 and 4/8 5/5 and 25/50
Answer:
[tex]\frac{20}{40} \ and \ \frac{4}{8} \ is \ equivalent[/tex]
Step-by-step explanation:
1.
[tex]\frac{2}{3} \ and \ \frac{12}{9} \\\\\frac{2}{3} \ and \ \frac{4}{3}\\\\Not \ equivalent[/tex]
2.
[tex]\frac{20}{40} \ and \ \frac{45}{55}\\\\\frac{1}{2} \ and \ \frac{9}{11}\\\\Not\ equivalent[/tex]
3.
[tex]\frac{20}{40} \ and \ \frac{4}{8}\\\\\frac{1}{2} \ and \ \frac{1}{2} \\\\Equivalent[/tex]
4.
[tex]\frac{5}{5} \ and \ \frac{25}{50} \\\\\frac{1}{1} \ and \ \frac{1}{2} \\\\not \ equivalent[/tex]
Let f(x) = 2x + 8, g(x) = x² + 2x – 8, and h(x)
Perform the indicated operation. (Simplify as far as possible.)
(g - f)(2) =
write an equation in slope intercept form for the line with slope 1/4 and y-intercept -6.
Answer:
y=¼x-6
Step-by-step explanation:
y=mx+c
y=¼x+-6
y=¼x-6
if i need 90 square feet of tile and each piece of tile covers 0.34 square feet, how much do i need in pieces
Answer:
265
Step-by-step explanation:
9514 1404 393
Answer:
265
Step-by-step explanation:
Let t represent the number of tiles needed. Then the area covered by those t tiles will be ...
area = t·0.34 ft²
We want that area to be 90 ft², so we can solve this equation for t:
90 ft² = t·(0.34 ft²)
90 ft²/(0.34 ft²) = t ≈ 264.71
About 265 tiles are needed to cover 90 ft².
Which of the following is the minimum value of the equation y = 2x2 + 5?
5
0
−5
2
rotation 180 degrees about the origin.
Answer:
Take the picture you uploaded.
Click the rotate button twice.
Done
halla la suma y el producto de la PG 3,9,27,81,243
Answer:
huh ano yan huhu paki ayos ng sagot
Step-by-step explanation:
hahahhaa
Mai drives a truck for a soft drink company. Her truck is filled with 15-ounce cans and 70-ounce bottles. Let c be the number of 15-ounce cans the
truck is carrying, and let b be the number of 70-ounce bottles.
The truck must be carrying less than 4000 pounds (64,000 ounces). Using the values and variables given, write an inequality describing this.
Answer:
15c + 70b < 64,000
Step-by-step explanation:
15c will represent the amount of ounces in the truck from the 15 ounce cans.
70b will represent the amount of ounces in the truck from the 70 ounce bottles.
These need to be added together in the inequality to represent the total weight in the truck.
Then, a less than inequality sign needs to be used, since the truck has to be carrying less than 64,000 ounces.
Put this all together:
15c + 70b < 64,000
So, the inequality is 15c + 70b < 64,000
I litterally don't understand how to do this-
Answer:
Consider points (-1, 0) and (0, 1) :
[tex]{ \tt{slope = \frac{y _{2} - y _{1} }{x _{2} - x _{1} } }} \\ { \tt{slope = \frac{1 - 0}{0 - ( - 1)} }} \\ { \boxed{ \bf{slope = 1}}}[/tex]
Answer:
slope 1
Step-by-step explanation:
above ANS is correct mark it as branliest ANS
in the past year bill watch 64 movies that he thought were very good he watched 80 movies over the whole year of the movies he watched what percentage did he rate as very good
Answer:
he rate it 16%
Step-by-step explanation:
64-80\100=16
Place the steps for finding f-1(x)
9514 1404 393
Answer:
B, C, H, D, F, A
Step-by-step explanation:
Starting with y = f(x), swap x and y to get x = f(y), then solve for y. The solution steps "undo" what is done to y, in reverse order. Y is ...
multiplied by 721 subtracted from the productthe square root of the differenceTo "undo" these steps in reverse order, after swapping x and y, you must square both sides, add 21, then divide by 7.
If the left tiles are labeled A to H from top to bottom, the correct sequence of steps is ...
B, C, H, D, F, A
help pls, stuck on this
Answer:
Step-by-step explanation:
According to the graph above, College R showed
the greatest change in enrollment between which
two decades?
Given:
The graph that shows the ennoblement for college R between 1950 and 2000.
To find:
The two decades that has the greatest change in enrollment.
Solution:
From the given graph, it is clear that the change in the enrollment is:
From 1950 to 1960 is [tex]4-3.5=0.5[/tex] thousand.
From 1960 to 1970 is [tex]5-4.5=1.5[/tex] thousand.
From 1970 to 1980 is [tex]5.5-5=0.5[/tex] thousand.
From 1980 to 1990 is [tex]6.5-5.5=1[/tex] thousand.
From 1990 to 2000 is [tex]7-6.5=0.5[/tex] thousand.
The two decades 1960-1970 and 1980-1990 have the greatest change in enrollment.
Answer:1980 to 1990
Step-by-step explanation:
Approximately 10% of all people are left-handed. Consider a grouping of fifteen people.
Write the probability distribution
Answer:
Step-by-step explanation:
Answer:
15*.1=1.5
so either one or two people of the 15 would be left handed
ANSWER ASAP IM BEING TIMED
IF I GET AN A ON THIS I WILL DO ANOTHER POINT FREE DROP, PLEASE SHOW YOUR WORK
The lengths of three sides of a quadrilateral are shown below:
Side 1: 1y2 + 3y − 6
Side 2: 4y − 7 + 2y2
Side 3: 3y2 − 8 + 5y
The perimeter of the quadrilateral is 8y3 − 2y2 + 4y − 26.
Part A: What is the total length of sides 1, 2, and 3 of the quadrilateral? (4 points)
Part B: What is the length of the fourth side of the quadrilateral? (4 points)
Part C: Do the answers for Part A and Part B show that the polynomials are closed under addition and subtraction? Justify your answer. (2 points)
Answer:
Part A
(1y^2+3y-6)+(4y-7+2y^2)+(3y^2-8+5y)
6y^2+12y-21
Find the area of the shaded region. Round to the nearest tenth. 11.1m 130°
Area = [ ? ] m²
The area of the shaded region is 294.5 m².
What is the area of the entire circle?The area of the entire circle is calculated as follows;
A = πr²
where;
r is the radius of the circleA = π ( 11.1² )
A = 387.1 m²
The area of the sector is calculated as follows;
A = ( θ/360 ) πr²
A = ( 130/360 ) x π ( 11.1² )
A = 139.8 m²
The area of the triangle is calculated as follows;
A = ¹/₂ ( sinθ )r²
A = ¹/₂ ( sin 130 ) (11.1²)
A = 47.2 m²
Area of the unshaded region is calculated as;
A' = 139.8 m² - 47.2 m²
A' = 92.6 m²
The area of the shaded region is calculated as follow;
A'' = 387.1 m² - 92.6 m²
A'' = 294.5 m²
Learn more about area of shaded region here: https://brainly.com/question/14989383
#SPJ1
What is the domain of the function f(x) =x+1/
X^2-6x+8?
Answer:
The domain of the function is all real values of x, except [tex]x = 4[/tex] and [tex]x = 2[/tex]
Step-by-step explanation:
We are given the following function:
[tex]f(x) = \frac{x+1}{x^2-6x+8}[/tex]
It's a fraction, so the domain is all the real values except those in which the denominator is 0.
Denominator:
Quadratic equation with [tex]a = 1, b = -6, c = 8[/tex]
Using bhaskara, the denominator is 0 for these following values of x:
[tex]\Delta = (-6)^2 - 4(1)(8) = 36-32 = 4[/tex]
[tex]x_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4[/tex]
[tex]x_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2[/tex]
The domain of the function is all real values of x, except [tex]x = 4[/tex] and [tex]x = 2[/tex]
slove the following systems of equations using any method. y= 3x + 7 , y= x- 9 , 3x- y= 1 , 7x + 2y = 37.
y=3× + 7 , y=×- 9 , 3×- 9 , 3×- y= 1 , 7× + 2y = 37.
²/₃ + ¹/₃ please answer
FINAL ANSWER:
1
Step-by-step explanation:
[tex]\frac{2}{3} +\frac{1}{3}[/tex]
the denominators are the same so all we need to do is add.
[tex]\frac{2}{3} + \frac{1}{3} =\frac{3}{3}[/tex]
[tex]\frac{3}{3} =[/tex] 1 whole
final answer: 1
hope this answer helps you :)
have a great day and may God Bless You!
the least value of x²-3x+5 is..
11/4
Step-by-step explanation:
to find the minimum value we require to find the vertex and determine if max/min
for a quadratic in standard form ; ax² + bx + c
the coordinate of the vertex is..
xvertex = -b/2a
x² - 3x + 5 is in standard form with a = 1,b = - 3 and c = 5
xvertex = - , -3/2 = 3/2
substitute this value into the equation for y-coordinate
yvertex = ( 3/2 ) ² -3 (3/2) + 5 = 11/4
vertex = ( 3/2, 11/4 )
to determine whether max/min
• if a > 0 then minimum u
• ifa < 0 then maximum n
here a = 1 > 0 hence minimum
minimum value of x² - 3x + 5 is 11/4
hope you understand this :)
