Matthew participates in a study that is looking at how confident students at SUNY Albany are. The mean score on the scale is 50. The distribution has a standard deviation of 10 and is normally distributed. Matthew scores a 65. What percentage of people could be expected to score the same as Matthew or higher on this scale

Answer:

Step-by-step explanation:

Answer:

4:30

because 9:30 minus 4:30 = 5:00 and 5:00 minus 30 =4:30

11/4

Step-by-step explanation:

to find the minimum value we require to find the vertex and determine if max/min

for a quadratic in standard form ; ax² + bx + c

the coordinate of the vertex is..

xvertex = -b/2a

x² - 3x + 5 is in standard form with a = 1,b = - 3 and c = 5

xvertex = - , -3/2 = 3/2

substitute this value into the equation for y-coordinate

yvertex = ( 3/2 ) ² -3 (3/2) + 5 = 11/4

vertex = ( 3/2, 11/4 )

to determine whether max/min

• if a > 0 then minimum u

• ifa < 0 then maximum n

here a = 1 > 0 hence minimum

minimum value of x² - 3x + 5 is 11/4

hope you understand this :)

Answer:

51°,51°,78°

Step-by-step explanation:

The sum of angles in a triangle add up to 180°

9514 1404 393

Answer:

  B, C, H, D, F, A

Step-by-step explanation:

Starting with y = f(x), swap x and y to get x = f(y), then solve for y. The solution steps "undo" what is done to y, in reverse order. Y is ...

To "undo" these steps in reverse order, after swapping x and y, you must square both sides, add 21, then divide by 7.

If the left tiles are labeled A to H from top to bottom, the correct sequence of steps is ...

  B, C, H, D, F, A

Answer:

he rate it 16%

Step-by-step explanation:

64-80\100=16

Answer:

3^5

Step-by-step explanation:

On the iPad it looks like that but the five is on the top right smaller

Answer:

3⁵

every 3 has it own power that is 1 however that .3 confused us

Answer:

[tex]\frac{20}{40} \ and \ \frac{4}{8} \ is \ equivalent[/tex]

Step-by-step explanation:

1.

[tex]\frac{2}{3} \ and \ \frac{12}{9} \\\\\frac{2}{3} \ and \ \frac{4}{3}\\\\Not \ equivalent[/tex]

2.

[tex]\frac{20}{40} \ and \ \frac{45}{55}\\\\\frac{1}{2} \ and \ \frac{9}{11}\\\\Not\ equivalent[/tex]

3.

[tex]\frac{20}{40} \ and \ \frac{4}{8}\\\\\frac{1}{2} \ and \ \frac{1}{2} \\\\Equivalent[/tex]

4.

[tex]\frac{5}{5} \ and \ \frac{25}{50} \\\\\frac{1}{1} \ and \ \frac{1}{2} \\\\not \ equivalent[/tex]

Answer:

Part A

(1y^2+3y-6)+(4y-7+2y^2)+(3y^2-8+5y)

6y^2+12y-21

Answer:

a. A normal quantile plot of the data follows a diagonal line, and the t-procedure is appropriate to use.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

In this question:

Sample size of 100 > 30, which means that we use the Central Limit Theorem, and thus, the sampling distribution is approximately normal, following a diagonal line, and since the standard deviation of the population is not know, we use the t-procedure. Thus, the correct answer is given by option a.

Answer:

Take the picture you uploaded.

Click the rotate button twice.

Done

Answer:

The domain of the function is all real values of x, except [tex]x = 4[/tex] and [tex]x = 2[/tex]

Step-by-step explanation:

We are given the following function:

[tex]f(x) = \frac{x+1}{x^2-6x+8}[/tex]

It's a fraction, so the domain is all the real values except those in which the denominator is 0.

Denominator:

Quadratic equation with [tex]a = 1, b = -6, c = 8[/tex]

Using bhaskara, the denominator is 0 for these following values of x:

[tex]\Delta = (-6)^2 - 4(1)(8) = 36-32 = 4[/tex]

[tex]x_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4[/tex]

[tex]x_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2[/tex]

The domain of the function is all real values of x, except [tex]x = 4[/tex] and [tex]x = 2[/tex]

y=3× + 7 , y=×- 9 , 3×- 9 , 3×- y= 1 , 7× + 2y = 37.

The area of the shaded region is 294.5 m².

The area of the entire circle is calculated as follows;

A = πr²

where;

A = π ( 11.1² )

A = 387.1 m²

The area of the sector is calculated as follows;

A = ( θ/360 ) πr²

A = ( 130/360 ) x π ( 11.1² )

A = 139.8 m²

The area of the triangle is calculated as follows;

A = ¹/₂ ( sinθ )r²

A = ¹/₂ ( sin 130 ) (11.1²)

A = 47.2 m²

Area of the unshaded region is calculated as;

A' = 139.8 m²  -  47.2 m²

A' = 92.6 m²

The area of the shaded region is calculated as follow;

A'' = 387.1 m² - 92.6 m²

A'' = 294.5 m²

Learn more about area of shaded region here: https://brainly.com/question/14989383

#SPJ1

Answer:

y=¼x-6

Step-by-step explanation:

y=mx+c

y=¼x+-6

y=¼x-6

Answer:

1,773.33 Mexican pesos

Step-by-step explanation:

Create a proportion where x was how many Mexican pesos it was worth:

[tex]\frac{1}{0.075}[/tex] = [tex]\frac{x}{133}[/tex]

Cross multiply and solve for x:

133 = 0.075x

1773.33 = x

So, it was worth approximately 1,773.33 Mexican pesos

Given:

The graph that shows the ennoblement for college R between 1950 and 2000.

To find:

The two decades that has the greatest change in enrollment.

Solution:

From the given graph, it is clear that the change in the enrollment is:

From 1950 to 1960 is [tex]4-3.5=0.5[/tex] thousand.

From 1960 to 1970 is [tex]5-4.5=1.5[/tex] thousand.

From 1970 to 1980 is [tex]5.5-5=0.5[/tex] thousand.

From 1980 to 1990 is [tex]6.5-5.5=1[/tex] thousand.

From 1990 to 2000 is [tex]7-6.5=0.5[/tex] thousand.

The two decades 1960-1970 and 1980-1990 have the greatest change in enrollment.

Answer:1980 to 1990

Step-by-step explanation:

Answer:

15c + 70b < 64,000

Step-by-step explanation:

15c will represent the amount of ounces in the truck from the 15 ounce cans.

70b will represent the amount of ounces in the truck from the 70 ounce bottles.

These need to be added together in the inequality to represent the total weight in the truck.

Then, a less than inequality sign needs to be used, since the truck has to be carrying less than 64,000 ounces.

Put this all together:

15c + 70b < 64,000

So, the inequality is 15c + 70b < 64,000

Hi there!

[tex]\large\boxed{12/5}}[/tex]

tan (angle) = Opposite side / Adjacent side, so:

Tan (A) = opposite side / adjacent side

= 24 / 10

Simplify:

= 12 / 5

Answer:

Consider points (-1, 0) and (0, 1) :

[tex]{ \tt{slope = \frac{y _{2} - y _{1} }{x _{2} - x _{1} } }} \\ { \tt{slope = \frac{1 - 0}{0 - ( - 1)} }} \\ { \boxed{ \bf{slope = 1}}}[/tex]

Answer:

slope 1

Step-by-step explanation:

above ANS is correct mark it as branliest ANS

Answer:

4 places after the decimal.

the result is 0.0215

Step-by-step explanation:

I assume the expression is really

43 / (2⁴ × 5³)

this is the same as

(((((((43 / 2) / 2) / 2) / 2) / 5) / 5) / 5)

since the starting value is an odd number, the first division by 2 creates a first position after the decimal point, and it must be a 5, as the result is xx.5

the second division by 2 splits again the uneven end .5 in half, creating a second position after the decimal point again ending in 5, as the result is now xx.x5

the third division by 2 does the same thing with that last 5 and creates a third position after the decimal point ending again in 5, as the result is now xx.xx5

the fourth division by 2 does again the same thing, a fourth position after the decimal point is created ending in 5. now xx.xxx5

in essence, every division of the 0.5 part by 2 is the same as a multiplication by 0.5, which squares 0.5 leading to 0.5². the next division did the same thing leading to 0.5³.

and finally the fourth division to 0.5⁴.

0.5⁴ = (5/10)⁴ = 5⁴/10⁴

so, now we start to divide this result by 5. since the positions after the decimal point are divisible by 5 without remainder, as we have 5⁴ to work with.

every divisible by 5 takes one of these powers away.

so, we go from 5⁴/10⁴ to 5³/10⁴ to 5²/10⁴ to 5/10⁴.

all the time we maintain the 10⁴ in the denominator of the fraction. and that determines the positions after the decimal point.

so, after all the individual divisions we come to and end and are still limited to the 4 positions after the decimal point.

Answer:

265

Step-by-step explanation:

9514 1404 393

Answer:

  265

Step-by-step explanation:

Let t represent the number of tiles needed. Then the area covered by those t tiles will be ...

  area = t·0.34 ft²

We want that area to be 90 ft², so we can solve this equation for t:

  90 ft² = t·(0.34 ft²)

  90 ft²/(0.34 ft²) = t ≈ 264.71

About 265 tiles are needed to cover 90 ft².

Answer:

huh ano yan huhu paki ayos ng sagot

Step-by-step explanation:

hahahhaa

FINAL ANSWER:

1

Step-by-step explanation:

[tex]\frac{2}{3} +\frac{1}{3}[/tex]

the denominators are the same so all we need to do is add.

[tex]\frac{2}{3} + \frac{1}{3} =\frac{3}{3}[/tex]

[tex]\frac{3}{3} =[/tex] 1 whole

final answer: 1

hope this answer helps you :)

have a great day and may God Bless You!

Answer:

67. A

68. D

Step-by-step explanation:

I don't remember exactly the explanation, but I recommend you try to learn more about number lines sometime when you aren't under stress from schoolwork, because they're pretty simple questions to answer once you get a better understanding of them!

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

1)

a)

[tex]Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\[/tex]

b)

[tex]Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}[/tex]

c)

Probability of at least one black( means BB or BW or WB)

 [tex]=\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}[/tex]

d)

Probability of at most one black ( means WW or WB or BW)

[tex]=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}[/tex]

2)

a) Probability both black without replacement

  [tex]=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}[/tex]

b) Probability  of one black and one white

 [tex]=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}[/tex]

c) Probability of at least one black ( BB or BW or WB)

 [tex]=\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}[/tex]

d) Probability of at most one black ( BW or WW or WB)

 [tex]=\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}[/tex]

Answer:

Step-by-step explanation:

Answer:

15*.1=1.5

so either one or two people of the 15 would be left handed

Answer: 3

Step-by-step explanation: m=2 so 7.5x2 = 15

15/5 is 15 divided by 5 so the answer is 3