My second question for today :
Why do we ever have a blood moon?? What's the science behind it​

Answer:

The weight of the probe is 50 Newtons

Explanation:

Newtons second law states that F = ma

Given the mass of 25kg, and the acceleration of 2m/s^2, we can substitute both values into the equation to find the weight force.

[tex]F = ma[/tex]

[tex]F = 25 * 2[/tex]

[tex]F = 50N[/tex]

The weight of the probe is 50 Newtons

a. cool air warms as it mixes with denser air

Explanation:

c. warm air is displaced by cooler denser air

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Answer:

55

Explanation:95-40=55

i hope i did the math right if i didnt please tell me

Answer:

C.

Explanation:

Force = Mass * Acceleration

So 20 = 5* Acceleration

4 = Acceleration

The acceleration of the object is 4 m/s².

To find the acceleration, the given values are:

Force = 20 N

Mass = 5 kg

Definition:

     As it was given as the values of  Force and mass, here acceleration definition depends on the Newton's second law of motion.

Using the second law of motion, the force will be equal to the product of the mass and the acceleration.

As formula,

                               F = ma Newton

Here, to find acceleration,

                              a =f/ m

Substituting the values,

                              = 20 / 5

                            a = 4m/s².

So, the acceleration was 4 m/s². The Option C is the correct answer.

Learn more about acceleration,

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Answer:

Final volume, V2 = 3 Litres

Explanation:

Given the following data;

Initial volume, V1 = 1 litre

Initial temperature, T1 = 20°C

Final temperature, T2 = 60°C

To find the final volume, we would use Charles' law;

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles is given by;

V1/T1 = V2/T2

Making V2 as the subject formula, we have;

V1T2 = V2T1

V2 = (V1T2)/T1

Substituting into the formula, we have;

V2 = (1 * 60)/20

V2 = 60/20

Final volume, V2 = 3 Litres

Explanation:

The square meter is the SI-derived unit of area. It has a symbol m² (33A1 in Unicode). It is defined as the area of a square whose sides measure exactly one metre.

Answer:

1028 slits/mm

Explanation:

We are given that

Wavelength of light, [tex]\lambda=530nm=530\times 10^{-9} m[/tex]

1nm=[tex]10^{-9} m[/tex]

[tex]\theta=33^{\circ}[/tex]

n=1

We have to find the number of slits per mm are marked on the grating.

We know that

[tex]dsin\theta=n\lambda[/tex]

Using the formula

[tex]dsin33^{\circ}=1\times 530\times 10^{-9}[/tex]

[tex]d=\frac{530\times 10^{-9}}{sin33^{\circ}}[/tex]

[tex]d=9.731\times 10^{-7} m[/tex]

1m=[tex]10^{3}mm[/tex]

[tex]d=9.731\times 10^{-7}\times 10^3[/tex]mm

[tex]d=0.0009731mm[/tex]

Number of slits=[tex]\frac{1}{d}[/tex]

Number of slits=[tex]\frac{1}{0.0009731}[/tex]/mm

Number of slits=1028/mm

Hence, 1028 slits/mm are marked on the grating.

Answer:

1027.6 lines per mm.

Explanation:

wavelength = 530 nm

order, m= 1

Angle = 33 degree

Let the slits per mm is 1/d.

So,

[tex]m \lambda = d sin A\\\\1\times 530\times 10^{-6} = d sin 33\\\\\frac{1}{d} = 1027.6 lines per mm[/tex]

Answer:

B

Explanation:

Eff = output work/input work ×100

Hence, Eff = 10000/12000 × 100

Eff = 83.3%

Answer:

The total power they will consume in series is approximately 2.257 W

Explanation:

The connection arrangement of the headlight and the engine starter = Parallel to the battery

The voltage of the battery, V = 12.0 V

The power at which the headlight operates in parallel, [tex]P_{headlight}[/tex] = 38 W

The power at which the kick starter operates in parallel, [tex]P_{kick \ starter}[/tex] = 2.40 kW

We have;

P = V²/R

Where;

R = The resistance

V = The voltage = 12 V (The voltage is the same in parallel circuit)

For the headlight, we have;

R₁ = V²/[tex]P_{headlight}[/tex]  = 12²/38 = 72/19

R₁ = 72/19 Ω

For the kick starter, we have;

R₂ = V²/[tex]P_{kick \ starter}[/tex] = 12²/2.4 = 60

R₂ = 60 Ω

When the headlight and kick starter are rewired to be in series, we have;

Total resistance, R = R₁ + R₂

Therefore;

R = ((72/19) + 60) Ω = (1212/19) Ω

The current flowing, I = V/R

∴ I = 12 V/(1212/19) Ω = (19/101) A

We note that power, P = I²R

In the series connection, we have;

[tex]P_{headlight}[/tex] = I² × R₁

∴ [tex]P_{headlight}[/tex] = ((19/101) A)² × 72/19 Ω = 1368/10201 W ≈ 0.134 W

The power at which the headlight operates in series, [tex]P_{headlight, S}[/tex] ≈ 0.134 W

[tex]P_{kick \ starter}[/tex] = ((19/101) A)² × 60 Ω = 21660/10201 W ≈ 2.123 W

The power at which the kick starter operates in series, [tex]P_{kick \ starter, S}[/tex] ≈ 2.123 W

The total power they will consume, [tex]P_{Total}[/tex] = [tex]P_{headlight, S}[/tex] + [tex]P_{kick \ starter, S}[/tex]

Therefore;

[tex]P_{Total}[/tex] ≈ 0.134 W + 2.123 W = 2.257 W

Answer:

Explanation:

The direction of the applied force has to be parallel to the distance an object moved in order to say that work has been done.

Answer: 8000N

Explanation: since it is frictionless that means it has 100% efficiency therefore the mechanical advantage is 1 meaning the load equals to the effort

Answer:

Gpe = 15680 Joules

Explanation:

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

G.P.E = mgh

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Given the following data;

Mass = 20 kg

Height = 80 m

We know that acceleration due to gravity is equal to 9.8 m/s²

To find the gravitational potential energy;

Gpe = mgh

Gpe = 20 * 80 * 9.8

Gpe = 15680 Joules

Answers:

The values are approximate.

==========================================================

Explanation:

When near the surface of the earth, the acceleration of gravity is roughly 9.81 m/s^2. This means that after each second passes, the velocity increases by roughly 9.81 m/s.

After 2.5 seconds, the velocity increases by 2.5*9.81 = 24.525 m/s = 24.5 m/s

If it was already going 25.0 m/s, then it bumps up to 25.0+24.5 = 49.5 m/s which is also approximate.

The acceleration of gravity stays the same when the object is close to the surface of the earth, so it stays at roughly 9.81 m/s^2

Side note: I'm ignoring air resistance (aka air friction or drag) since that greatly complicates things, and we would need to know the shape and surface area of the object. The material type would also be relevant info as well.

Answer:

A flower emits only visible light

A flower reflects much of the light that hits it

By the work-energy theorem, the total work done on the mass as it swings is

W = ∆K = 1/2 (18 kg) (17 m/s)² = 153 J

No work is done by the tension in the string, since it's directed perpendicular to the mass at every point in the arc. Similarly, the component of the mass's weight mg pointing perpendicular to the arc also performs no work.

If we ignore friction/drag for the moment, the only remaining force is the parallel component of weight, which performs mgh = (176.4 N) h of work, where h is the vertical distance between points A and B.

Now, if w is the amount of work done by friction/air resistance, then

(176.4 N) h - w = 153 J

If you know the starting height h, then you can solve for w.

[tex]\boxed{ \sf{Answer}} [/tex]

____________________

(a) A = 5 kgwt

B = 10 N

First convert 5 kgwt to N,

[tex]5 \times 9.8 \\ = 49 \: N[/tex]

Net force [the forces are acting in 2 opposite directions]

[tex]A - B \: \\ = 49 - 10 \\ = 39 \: N[/tex]

____________________

(b) Since, the force is greater by A ↦the block will move towards B, i.e, to the right.

____________________

(c) Frictional force will try to oppose the motion of the block but since A has greater force than B, the frictional force will be resisted.

____________________

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ ツ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Answer:

A.

A battery in a pair of headphones

Explanation:

Potenial energy - the energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.

Answer:

6.9 m/s

Explanation:

1000m = 1km

3600s = 1hr

25000m/3600s

6.9m/s

Answer:

D. A

General Formulas and Concepts:

Simple Harmonic Motion

Parts of a wave

Explanation:

The amplitude is the distance from the horizon to either the crest or trough of a wave.

In layman's terms, it is how high the wave is.

The "highest" wave would be wave A.

∴ our answer is D.

Topic: AP Physics 1 Algebra-Based

Unit: SMH

Answer:

A (The wave)

Explanation:

Wave A

Answer: Symbol is I and unit A

Explanation: A represents Amperes

HOPE THIS HELPS!!!!!!!!

Answer:

The maximum height reached is 413.27 m.

Explanation:

How long will it take for a body to reach its maximum height, knowing that it was thrown, vertically upwards, with a velocity whose value was 90 m / s?

initial velocity , u = 90 m/s

gravity, g = 9.8 m/s^2

Let the maximum height is h.

At maximum height the velocity v = 0

Use third equation of motion

[tex]v^2 = u^2 - 2 gh\\\\0 = 90\times 90 - 2 \times 9.8 \times h\\\\h = 413.27 m[/tex]

The book's position is changing linearly with time, so its velocity is constant. This means that the net force acting on the book in the direction parallel to the surface is

∑ F = 10.0 N - n = 0

where n is the magnitude of the normal force on the book due to the wall, and the net force perpedicular to the surface is

∑ F = f - (0.550 kg) g = 0

where f is the mag. of kinetic friction, and f = µn where µ is the coefficient of kinetic friction.

Then

• n = 10.0 N

• f = (0.550 kg) g = 5.39 N

• 5.39 N = µ (10.0 N)

==>   µ = 0.539

Answer:

Above answer

Explanation:

The book's position is changing linearly with time, so its velocity is constant. This means that the net force acting on the book in the direction parallel to the surface is

∑ F = 10.0 N - n = 0

where n is the magnitude of the normal force on the book due to the wall, and the net force perpedicular to the surface is

∑ F = f - (0.550 kg) g = 0

where f is the mag. of kinetic friction, and f = µn where µ is the coefficient of kinetic friction.

Then

• n = 10.0 N

• f = (0.550 kg) g = 5.39 N

• 5.39 N = µ (10.0 N)

==>   µ = 0.539

Answer:

0.6 m/s

Explanation:

The details of the masses and velocities are;

The mass of the ice skater, m₁ = 80 kg

The mass of the ball, m₂ = 8 kg

The speed with which the skater tosses the ball forward, v₂ = 6 m/s

Therefore;

According to the principle of conservation of linear momentum, we have;

m₁·v₁ = m₂·v₂

Where;

v₁ = The skater's reactive velocity

Therefore, we get;

80 kg × v₁ = 8 kg × 6 m/s

v₁ = 8 kg × 6 m/s/(80 kg) = 0.6 m/s

The skater's reactive velocity, v₁ = 0.6 m/s.

Answer:

The height reached is 20m, The time taken to reach 20m is 2 seconds

Explanation:

Observing the equations of motion we can see that the following equation will be most helpful for this question.

[tex]v^{2} = u^{2} + 2as[/tex]

We are given initial velocity, u

We know that the stone will stop at its maximum height, so final velocity, v

Acceleration, a

And we are looking for the displacement (height reached), s

Substitute the values we are given into the equation

[tex]0^{2} = 20^{2} + 2(10)s[/tex]

Rearrange for s

[tex]0^{2} -20^{2} =20s[/tex]

[tex]-400=20s[/tex]

[tex]\frac{-400}{20} =s[/tex]

s = -20 (The negative is just showing direction, it can be ignored for now)

The height reached is 20m

Use a different equation to find the time taken

[tex]s = vt - \frac{1}{2} at^{2}[/tex]

Substitute in the values we have

[tex]-20=(0)t - \frac{1}{2} (10)t^{2}[/tex]

Rearrange for t

[tex]-20 =0 -5 t^{2}[/tex]

[tex]\frac{-20}{-5} =t^{2}[/tex]

[tex]4 = t^{2}[/tex]

t = 2s

The time taken to reach 20m is 2 seconds

Answer:

C. C

Explanation:

A wave can be defined as a disturbance in a medium that progressively transports energy from a source location to another location without the transportation of matter.

In Science, there are two (2) types of wave and these include;

I. Electromagnetic waves: it doesn't require a medium for its propagation and as such can travel through an empty space or vacuum. An example of an electromagnetic wave is light.

II. Mechanical waves: it requires a medium for its propagation and as such can't travel through an empty space or vacuum. An example of a mechanical wave is sound.

A crest can be defined as the highest (vertically) point on a waveform.

On a related note, a trough is the lowest (vertically) on a waveform.

An amplitude can be defined as a waveform that's measured from the center line (its origin or equilibrium position) to the bottom of a trough or top of a crest. Thus, the vertical axis (y-axis) is the amplitude of a waveform i.e it's measured vertically.

In this scenario, waveform C which is represented by a blue curvy line has the smallest amplitude in comparison with the other waveforms because it has the minimum height when measured from the origin.

In contrast, waveform A represented by a purple line has the highest amplitude because it has the maximum height when measured from the origin.

Mathematically, the amplitude of a wave is given by the formula;

x = Asin(ωt + ϕ)

Where;

Answer:

The answer is indeed D as the comment above suggests.

Explanation:

Simply put, wave D's highest point is closer to the line than all of the other high points of A, B and C

Answer:

The answer should be: 1.20 A

Explanation: