The histogram below represents a data distribution with uniform class
widths. Which of the following is the median of the data distribution?
6
5
4
3
2
1
9 10
A. 4
B. 6
C. 5
c
D. 7

Answer:

14

Step-by-step explanation:

7*4*1/2=14

Answer:

Choice A

Step-by-step explanation:

An arithmetic sequence is one which has an incremental change.

for our answer, our change is +5

Answer:

see explanation

Step-by-step explanation:

Using the identities

cotA = [tex]\frac{1}{tanA}[/tex]

cot²A = cosec²A - 1

tan²A = sec²A - 1

Consider the left side

(cotA + tanA)² ← expand using FOIL

= cot²A + 2cotAtanA + tan²A

= cosec²A - 1 + 2 .[tex]\frac{1}{tanA}[/tex] . tanA + sec²A - 1

= cosec²A - 1 + 2 + sec²A - 1

= sec²A + cosec²A - 2 + 2

= sec²A + cosec²A

= right side, thus proven

Answer:

The LCM of 100 and 120 is 600.

The LCM of 5 and 120 is 120.

LCM of 5 and 100 is 100.

Step-by-step explanation:

I think this is the answer . If it is not sorry .

Answer:

B: 63

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

X^2 - 7 =

Since we need to evaluate the expression when X = 5, we replace X with 5.

= 5^2 - 7

Now, according to the correct order of operations, we need to do the exponent first. 5^2 = 5 * 5 = 25

= 25 - 7

Finally, we subtract.

= 18

Answer: 18

Answer:

leg = 18

hypotenuse = 18 sqrt(2)

Step-by-step explanation:

We know that sin theta = opp side / hypotenuse

sin 45 = 18 / hyp

hyp sin 45 = 18

hyp = 18 / sin 45

hyp = 18 sqrt(2)

Since this is an isosceles triangle ( the two angles are the same measure), the two legs have to be the same length

leg = 18

the lengths of the other leg and the hypotenuse

is 18 units and 18[tex]\sqrt{2}[/tex]units respectively.

Answer:

Solution given:

Let <C=<B=45°

AB=18 units

BC=?

AC=?

again

By using

By usingspecial right triangle ratios

sin C=opposite/hypotenuse=AB/AC=18/AC

Sin 45=18/AC

AC=18/sin45

AC=hypotenuse=18[tex]\sqrt{2}[/tex]units

again

Tan A=opposite/adjacent=BC/AB=BC/18

Tan45=BC/18

BC=Tan45*18

BC=length of another leg=18 units.

Answer:

Actually the answer is "A"

this is a very strange way to present a problem...

this issue her is that [tex](x^{a}) ^{b} = x^{a*b}[/tex]

so you need 1/3 * 3 in the answer... none of them have 1/3 * 3

BUT !!!!! 1/3 + 1/3 + 1/3  is the same as  1/3 * 3 So "A" is the solution

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

cosA = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{12}{13}[/tex]

cosC = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{5}{13}[/tex]

sinC = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{12}{13}[/tex]

tanC = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{AB}{BC}[/tex] = [tex]\frac{12}{5}[/tex]

Then

cosA = sinC → B

Answer:

(C) 2x^3 - 3x^2 - 35x + 36

Step-by-step explanation:

First multiply 2x by x^2 + 3x - 4:

(2x)(x^2 + 3x - 4)

2x^3 + 6x^2 - 8x

Next multiply -9 by x^2 + 3x - 4:

(-9)(x^2 + 3x - 4)

-9x^2 - 27x +36

Now add the two polynomials by adding like terms:

(2x^3 + 6x^2 - 8x) + (-9x^2 - 27x +36)

2x^3 + 6x^2 - 9x^2 - 8x - 27x + 36

2x^3 - 3x^2 - 35x + 36

Hope this helps (●'◡'●)

Answer:

y = 1/2x - 3 (option - d)

Step-by-step explanation:

The lines are parallel if they have the same slope/gradient. So by comparing with y = mx + c (where 'm' is the slope and 'c' is the y-intercept).

Line y = 1/2 x - 6 has the slope m = 1/2

and the line in option 'd'

y = 1/2 x -3 has the slope m = 1/2

Slopes are equal and lines are parallel.

Thank-you.

#Muhib

Answer:

Choice D. [tex]F(x)=x^2-4[/tex]

Step-by-step explanation:

Answers:

t is the number of seconds after the rocket is released

V(r) is the volume of the ball with radius r.

====================================================

Explanation:

There isn't much to say in terms of explanation. These variables are simply definitions.

Answer:

Step-by-step explanation:

5.1, please this is just a guess from using my head to calculate

Answer:

s4 = 270

18+36+72+144 = 270

-- convergent sums to a single value

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Note that x is opposite to the given angle and we are also given the hypotenuse.

Since we have an angle and the side opposite to it and the hypotenuse, we can use the sine ratio. Recall that:

[tex]\displaystyle \sin \theta =\frac{\text{opposite}}{\text{hypotenuse}}[/tex]

The opposite side is x, the hypotenuse is 15, and the angle is 53. Substitute:

[tex]\displaystyle \sin 53^\circ = \frac{x}{15}[/tex]

Solve for x:

[tex]x=15\sin 53^\circ[/tex]

Use a calculator (make sure you're in Degrees Mode!). Hence:

[tex]x=11.9795...\approx 12[/tex]

Our answer is C.

Answer:

C. 12

Step-by-step explanation:

Pythagoras Theorem

Answer:

The answer is 3x=50-10y

Answer:

0.75 → 0.5 → 1/3(0.33) → 1/4(0.25)

Answer:

1.5×10^17

Step-by-step explanation:

it would be better to first multiply the two then divide the answer by 9.4×10^-3

I hope this helps

Answer:welcome

Step-by-step explanation: sorry I jsit really needed the points

Answer:

Step-by-step explanation:

That 3 sitting outside there in that little "box" thing is a root/solution/zero of the polynomial. The numbers underneath the line are the coefficients of the depressed polynomial, which means that the polynomial is 1 degree lower than the degree with which we started. If we started with an x-squared, this degree is a single x, better known as linear (a line). Anyway, (x - 3) is a zero of the polynomial, which also means that it's a factor. So A applies. x = 3 is a root, so C applies. And F also because the depressed polynomial, the remainder, is 2x + 4.

Answer:

Step-by-step explanation:

1). WXYZ is a rectangle,

  Properties of a rectangle,

  i). Opposite sides are equal and parallel.

  ii). All interior angles measure 90°.

  iii). Diagonals are equal in measure.

a). WY = ZX = 30

 Therefore, ZT = [tex]\frac{1}{2}(ZX)[/tex]

                    [tex]ZT=15[/tex]

b). WY = ZX = 45

c). Since, WY = ZX,

    (4b - 16) = (3b + 5)

    4b - 3b = 16 + 5

     b = 21

2). GOAT is a rhombus and m∠OGA = 35°,

    a). m∠TGA = m∠OGA = 35°

    b). m∠GXO = 90°

    c). m∠GXT = 90°

    d). Since adjacent angles of a rhombus are supplementary,

         m∠OGT + m∠GTA = 180°

         70° + m∠GTA = 180°

         m∠GTA = 110°

         m∠GTO = [tex]\frac{1}{2}(m\angle GTA)[/tex]

                        = [tex]\frac{1}{2}(110^{\circ})[/tex]

                        = 55°

     e). Since, opposite angles of a rhombus are equal,

          m∠OGT = m∠OAT = 70°

     f). m∠GOA = m∠GTA = 110°

Answer:

see below

Step-by-step explanation:

Part 1:

(512) ^ 1/3

-------------------

(2197) ^ 1/3

8

-----

13

The scale factor is 8:13

Part 2

The ratios of the areas is related by scale factor squared

8^2

-----

13^2

64      

------  

169

Part 3

64       960

------  = ----------------

169     SA larger

Using cross products

64 * SA = 169 * 960

64 SA = 162240

Divide each side by 64

64 SA/ 64 = 162240 / 64

SA = 2535

2535 cm^2

Answer:

100

Step-by-step explanation:

0.2*500=100

Answer:

Which subject is this . please tell

Answer:

see explanation

Step-by-step explanation:

1

(a)

Calculate slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁  = (8, 3) and (x₂, y₂ ) = (10, 7)

m = [tex]\frac{7-3}{10-8}[/tex] = [tex]\frac{4}{2}[/tex] = 2

(b)

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{2}[/tex]

(c)

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - [tex]\frac{1}{2}[/tex] , then

y = - [tex]\frac{1}{2}[/tex] x + c ← is the partial equation

To find c substitute (8, 3) into the partial equation

3 = - 4 + c ⇒ c = 3 + 4 = 7

y = - [tex]\frac{1}{2}[/tex] x + 7 ← equation of perpendicular line

--------------------------------------------------------------------------

2

(a)

with (x₁, y₁ ) = (3, 5) and (x₂, y₂ ) = (4, 4)

m = [tex]\frac{4-5}{4-3}[/tex] = [tex]\frac{-1}{1}[/tex] = - 1

(b)

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{-1}[/tex] = 1

(c)

y = x + c ← is the partial equation

To find c substitute (3, 5) into the partial equation

5 = 3 + c ⇒ c = 5 - 3 = 2

y = x + 2 ← equation of perpendicular line

Answer:

1 kg

Step-by-step explanation:

Number of chickadees = 100

Quantity of seed eaten = 100 kg

Number of days = 100

Quantity of seeds each chickadee eats per day =Number of chickadees ÷ Quantity of seed eaten ÷ Number of days

= 100 ÷ 100 ÷ 100

= 1 ÷ 100

= 0.01 kg of seed

How many kg of seeds can 10 chickadees eat in 10 days?

= Quantity of seeds each chickadee eats per day × number of chickadee × number of days

= 0.01 kg × 10 × 10

= 1 kg

10 chickadees eat 1 kg of seeds in 10 days

Answer:

Step-by-step explanation:

The percents here make this more tricky than it originally seems to be. We'll make a table and see where it takes us:

                          original                 new

length

width

And we'll fill it in according to our rules given. Starting with the original, we are told that the width is twice as long as the length. We don't know the length, so we'll call that L, and if the width is twice that, the width is 2L:

                           original                  new

length                       L

width                       2L

Now here's the tricky part. What I'm going to do is fill in the "new" column with the expressions and then we'll simplify them in the next step.

The length is increased by 50%. So we have 100% of the original length and we are adding another 50% to that:

                            original                        new

length                      L                       100%L + 50%L

width                       2L

The width is decreased by 20%, so we have 100% of 2L and we are subtracting 20% of 2L from that:

                             original                       new

length                        L                     100%L + 50%L

width                        2L                  100%(2L) - 20%(2L)

And now we'll simplify that "new" column:

                              original                         new

length                        L                         150%L = 1.5L

width                         2L               80%(2L) = 160%L = 1.6L

Now we're ready for the perimeter part. The formula for the perimeter of a rectangle is P = 2L + 2w, so filling in from our "new" column, since 248 is the perimeter given for AFTER the rectangle's length and width are manipulated:

248 = 2(1.5L) + 2(1.6L) and

248 = 3L + 3.2L and

248 = 6.2L so

L = 40 and that means that w = 80 (because in the "original" column, the width is twice the length)

Answer:

Remember that a triangle rectangle of length L and width W has an area:

A = W*L

In our rectangle, we have two sides along the x and y axes.

So one of the vertices of our triangle rectangle is the point (0, 0)

And the other vertex, is along the line:

y = -4x + 20

So, if the opposite vertex is at the point:

(x₁, y₁)

We can define the length as the difference between the x-values of each vertex.

L = (x₁ - 0) = x₁

And the width, similarly, as:

W = (y₁ - 0) = y₁

Such that the point (x₁, y₁) is a solution for the equation y = -4x + 20, then we have:

y₁ = -4x₁ + 20

Then we can rewrite the width as:

W = -4x₁ + 20

Now, we can write the area of our rectangle as:

A = (x₁)*(-4x₁ + 20)

A = -4*x₁^2 + 20*x₁

Now we want to maximize the area, notice that the area is given by a quadratic equation with a negative leading coefficient.

Thus, the maximum will be at the vertex of that quadratic equation.

Remember that for a general quadratic equation:

y = a*x^2 + b*x + c

The x-value of the vertex is:

x = -b/(2*a)

so, in our case, the x-value of the vertex will be:

x₁ = -20/(-4*2) = 20/8 = 5/2

Now we can evaluate this in our area equation:

A = -4*(5/2)^2 + 20*(5/2)  = 49.36

This is the maximum area of the rectangle.