Name the marked angle in 2 different ways.

Answer:

Step-by-step explanation:

(-5 , 2) here -5 is x coordinate and 2 is y coordinate since x coordinate is negative and y coordinate is positive it lies in II quadrant.

(2 , -5) here 2 is x coordinate whereas -5 is y coordinate and siince x coordiante is positive and y coordinate is negative it lies in IV quadrant.

(x^3 - 2)(x^2 + 11)

to find the degree of polynomial first u need to factor this out

x^3(x^2 + 11) -2(x^2 + 11)

x^3 * x^2 + x^3 * 11 - 2 * x^2 - 2 * 11

x^3+2 + 11x^3 - 2x^2 - 22

x^5 + 11x^3 - 2x^2 - 22

since the highest degree is 5 the degree of the polynomial is also 5.

Step-by-step explanation:

MARK ME BRAINLIEST THANKS MY ANSWER PLEASE

Answer:

Step-by-step explanation:

Let's call Joseph "J", Mark "M", and Kevin "K" for ease. We need a system of equations to solve this, 3 equations for 3 unknowns. The first equation is

J + M = 230. The second equation is

J + K = 130. The third equation is

M = 3K. Sub that 3K into the first equation and get

J + 3K = 230. Now take th second equation and solve it for J:

J = 130 - K. Now sub 130 - K into the re-written first equation to get a whole new equation in terms of K only:

130 - K + 3K = 230 and

2K = 100 so

K = 50

Kevin has $50

Answer: 52

Step-by-step explanation:

81 + 47 is 128.

180 - 128 =52 degrees.

:)

Answer:

LM = 24.3

Step-by-step explanation:

In terms of similar shapes, we know that the ratio of the value of one side to its corresponding side value is equal to another. In other words, we know that LK and HG are corresponding sides by looking at the quadrilaterals. The ratio of LK to HG is equal to the ratio of another pair of corresponding sides, such as LM and IH.

Therefore, the ratio of LK and HG (LK/HG) is equal to the ratio of LM and IH (LM/IH) . Make sure to keep the same quadrilateral's sides on top/bottom. In this example, LM and LK are on the same quadrilateral, and are therefore both on top. Similarly, IH and HG are of the same quadrilateral and are both on bottom. We can write this as

LK / HG = LM / IH

34/7 = LM / 5

Multiply both sides by 5

34*5/7 = LM

LM ≈ 24.2857

Rounding to the nearest tenth, LM = 24.3

Answer:

24.3

Step-by-step explanation:

Answer:

t-6=7 .................

Answer:

t - 6 = 7

Step-by-step explanation:

Step-by-step explanation:

Hey there!

Given;

Distance (d) = 450 km = 450*1000 = 450000 m

Time(t) = 5 hours = 5*60*60 = 18000s

Now;

Speed (s) = Distance (d) /Time(t)

Or, s = 450000/18000

Or, s = 25m/s.

Therefore, the speed is 25m/s.

Hope it helps!

Answer:

The car has a velocity of 25 m/s.

Step-by-step explanation:

There are two ways to solve this problem.

First way :

450km = 450.000m

5h = 5x 3.600s =18.000s

v = s/t = 450.000 / 18.000 = 25m/s

Second way :

Velocity = speed/time = 450 / 5 = 90 km/h

90/3.6 = 25 m/s

Either way, the car has a velocity of 25 m/s.

Answer:

x = 14

Step-by-step explanation:

Triagle GIA and Triangle GNT are congruent.

Step-by-step explanation:

I cannot see all the answer options.

square garden, side length x.

area = x² (or x×x)

new area r = (x-p)(x+q) = x² - px + qx - pq =

= x² + (q - p)x - pq

3D printer. costs p in general.

makes x figurines.

material per figurine costs q.

costs per figurine r = q + p/x

as the printer costs themselves need to be distributed equally across all produced figurines.

investment account. q% pretty year.

p dollars starting balance.

letting it sit for x years.

a0 = p

a1 = a0 + a0×q/100 = a0 × (1 + q/100)

a2 = a1 + a1×q/100 = a1×(1 + q/100) = a0×(1 + q/100)²

a3 = a2 + a2×q/100 = a2×(1 + q/100) = a0×(1 + q/100)³

...

ax = a0×(1 + q/100) to the power of x =

= p × (1 + q/100) to the power of x

account without interest. p dollars are already in it.

adding q dollars every month for x months.

balance after these x months

r = x×q + p = q×x + p

Answer: 28

Step-by-step explanation: 5(4)-4(-2) which is 20+8 and that is 28.

Answer:

B

Step-by-step explanation:

So if B is the midpoint of AC, AB must be 1/2 of AC.

If D is the midpoint of AB, it must be 1/2 of 1/2 of AC, which is 1/4 of AC.

So AC= 4 DB

Answer:

Tn = 75+25n

Step-by-step explanation:

The balance are in arithmetic progression

$100, $125, $150...

The formula for calculating the nth term of the sequence is expressed as;

Tn = a+(n-1)d

a =100

d = 125 - 100 = 150 - 125

d = 25

n is the number of terms

Substitute

Tn = 100+(n-1)*25

Tn = 100 + 25n-25

Tn = 75+25n

Hence the nth term of the sequence is Tn = 75+25n

Answer:

8. x = 16

9. x = 10

14.

m ∠RSU = 130°

m ∠UST = 50°

15.

m ∠RSU = 124°

m ∠UST = 56°

Step-by-step explanation:

8.

Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF

That is , (x + 15)° = 31°

                x = 31 - 15 =  16

9.

Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF

That is ,

           (6x - 4)° = 56°

            6x = 56 + 4

               6x = 60

                 x = 10

14.

13x + 5x = 180°                       [straight line angles ]

18x = 180

x = 10

m ∠RSU = 130°

m ∠UST = 50°

15.

4x + 12 + 2x = 180°                       [ straight line angles]

6x = 180 - 12

6x = 168

x = 28

m ∠RSU = 4(28) + 12 = 112 + 12 = 124°

m ∠UST = 2(28) = 56°

Answer:

14. 13x+5x

=18x

180(angles on a st. line)= 18x

180/18

=10

RSU=13*10=130

UST=5*10=50

Answer:

C 8.9

Step-by-step explanation:

all these lines (from the same point of origin, cutting into and through a circle, ending at the far end of the circle they are cutting into) have the same relation of their lengths :

a×(a+b) is the same for all these lines.

with a being the first segment from the point of origin to touching the outside of the circle, and b being the length of the line inside the circle.

so,

4×(4+16) = 8×(8+2) = 80

this is correct for these two lines.

now, the line with the length x is a special case, as it does not really go through a circle, it only touches them.

but the length relation applies also to this line. it is just that the length inside the circle is 0.

so,

x×(x+0) = 80 (the same value as for the other lines)

must be true here too.

=>

x² = 80

x = sqrt(80) ≈ 8.9

Answer:

55

Angle C is a inscribed angle of the of Arc Ba.

CA is the diameter so that means Arc BA equal 110 becuase

110+70=180.

Angle C is half of Arc BA so Angle C is

[tex]55[/tex]

Answer:

a= 16

b= 2

Step-by-step explanation:

edge 2021

Answer:

a=16 and b=2

Step-by-step explanation:

next one is B.

Answer:

Step-by-step explanation:

a = 7 ;  b = 1 ;  c = -5

D = b² - 4ac

  = 1 - 4*7*(-5)

  = 1 + 140

  = 141

x =( - b ± √D ) / 2a

 = (-1 ± √141)/2*7

 = (-1±√141) / 14

[tex]a = \frac{-1+\sqrt{141} }{14}= \frac{-1+11.87}{14}= \frac{10.87}{14}=0.78\\\\b = \frac{-1-\sqrt{141}}{14}= \frac{-1-11.87}{14}= \frac{-12.87}{14}=3.59\\\\\\[/tex]

(a -4 )(b -4) = (0.78 - 4)(-3.59-4) = (-3.22)(-7.59)

= 24.4398

Answer:

I've attached the Answer

Answer:

a = - 2

Step-by-step explanation:

Given x = a, y = 3 lies on the equation. That is the values satisfies the equation when substituted.

Find a :

Equation : 5x + 2y = - 4

                5 ( a ) + 2 ( 3) = - 4

                5a + 6 = - 4

                 5a + 6 - 6 = - 4 - 6               [ subtracting both sides by 6 ]

                 5a  + 0 = - 10

                   5a = - 10

                    a = - 2                               [ dividing both sides by 5]

[ fact check : If (-2 , 3 ) lies on the equation : 5x + 2y = - 4

                                                                    5(-2) + 2( 3 ) = - 4

                                                                   - 10 + 6 = - 4

                                                                         - 4 = - 4 ]

Answer:

20

Step-by-step explanation:

The numbers whose product are to be obtained :

(–24.98)(–1.29)

To use front end approximation, numbers are rounded to the greatest place value :

For :

(-24.98) is rounded to - 20 (4 is rounded here to 0)

(-1.29) is rounder to - 1 (2 is rounded to 0)

Then, the product of the two numbers will be :

-20 * - 1 = 20

Given:

[tex]\sin \theta <0[/tex]

[tex]\tan \theta <0[/tex]

To find:

The quadrant in which [tex]\theta[/tex] lie.

Solution:

Quadrant concept:

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II, only [tex]\sin\theta[/tex] and [tex]\csc\theta[/tex] are positive.

In Quadrant III, only [tex]\tan\theta[/tex] and [tex]\cot\theta[/tex] are positive.

In Quadrant IV, only [tex]\cos\theta[/tex] and [tex]\sec\theta[/tex] are positive.

We have,

[tex]\sin \theta <0[/tex]

[tex]\tan \theta <0[/tex]

Here, [tex]\sin\theta[/tex] is negative and [tex]\tan\theta[/tex] is also negative. It is possible, if [tex]\theta [/tex] lies in the Quadrant IV.

Therefore, the correct option is D.

Answer: 1/8, 0.13, 1/2, 7/8

Step-by-step explanation: Mental Math

Step-by-step explanation:

0.13,1/2,1/8,and 7/8

hope it is helpful to you

Answer:

the answer is the second option

Step-by-step explanation:

it is

Answer:

Step-by-step explanation:

The equation of blue line A is x = 1.

That of blue line B is y = 4.

Answer:

let's use Pythagoras theorem,

h²=b²+l²

so,

ad²=ac²+dc²

6²=ac²+3²

36-9=ac²=27

√27 can be written as 3√3,

hence ac= 3√3

Answer:D - mean>median

Step-by-step explanation:

There are no repeating variables to have a mode so median and mean are the only options. The mean of this data set is 7.4 and the median is 6. Therefore mean greater than median

Answer:

[tex]2x^{2} +bx-3=0[/tex]

Step-by-step explanation:

General form. A quadratic function [tex]f(x)[/tex] is of the form [tex](ax^2+bx+c)[/tex] where [tex]a,b,c[/tex] ∈ R or C and [tex]a[/tex] ≠ [tex]0[/tex].

We obtain an equation when [tex]f(x)=0[/tex]

⇒ [tex]ax^{2} +bx+c=0[/tex] is an quadratic equation.

Solution.

Given, [tex]a=2,c=-3[/tex], but b is not given

Thus the quadratic function with leading coefficient [tex]a=2[/tex] and constant term [tex]c=-3[/tex] is given by

[tex]f(x)=2x^{2} +bx-3[/tex]

∴ the required quadratic equation is

[tex]2x^{2} +bx-3=0[/tex]

Answer:

[tex](\frac{u+s}{2} , \frac{v+t}{2} )[/tex] (the first option)

Step-by-step explanation:

The midpoint of a segment connecting two points [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] can be described by the following formula: [tex]\frac{x_1 + x_2}{2} = x_{mid}[/tex] and [tex]\frac{y_1 + y_2}{2} = y_{mid}[/tex]. As you can see, the formula essentially takes the average of the x- and y-coordinates to find the point in the middle.

With points (u, v) and (s, t), the midpoint becomes [tex](\frac{u+s}{2} , \frac{v+t}{2} )[/tex] (the first option).

Answer:

7 5/6

Step-by-step explanation:

16 2/3 - 8 5/6

16 4/6- 8 5/6

7 5/6

129° + x = 180°. [Linear pair]

=> x = 180° - 129°

=> x = 51°

Answer:

option A

Step-by-step explanation:

   [tex]y - 9 = \frac{2}{3} (x + 7)\\\\ y - 9= \frac{2}{3} x + \frac{14}{3}\\\\ y = \frac{2}{3} x + \frac{14}{3} + 9\\\\y = \frac{2}{3}x + \frac{14 +27}{3}\\\\y = \frac{2}{3}x + \frac{41}{3}\\\\[/tex]

Therefore, slope of the given line is

                                                    [tex]m_ 1 = \ \frac{2}{3}[/tex]

Find the slope of the new line

The product of slope of  lines perpendicular to each other = - 1

That is ,

            [tex]m_ 1 \times m_2 = - 1\\\\\frac{2}{3} \times m_ 2 = - 1\\\\m_ 2 = - \frac{3}{2}[/tex]

Find the equation of the line.

[tex]Let \the \ given \ points \ be \ ( x_ 2 , y _ 2 ) = ( 2 , 3 ) \\\\(y- y_2) = m_2 (x - x_ 2)\\\\( y - 3 ) = - \frac{3}{2}(x - 2)\\\\y = -\frac{3}{2}x + \frac{3 \times 2}{2} + 3\\\\y = - \frac{3}{2} x +3+3\\\\y = - \frac{3}{2} x +6\\\\[/tex]