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The Goodman Tire and Rubber Company periodically tests its tires for tread wear under simulated road conditions. To study and control the manufacturing process, 20 samples, each containing three radial tires, were chosen from different shifts over several days of operation; the data collected are shown below. Assuming that these data were collected when the manufacturing process was believed to be operating in control, develop the R and charts.
R Chart: (to 2 decimals)
UCL =
LCL =
Chart: (to 1 decimal)
UCL =
LCL =
Answer:
Range:
UCL = 4.73
LCL = 18.08
MEAN :
UCL = 27.115
LCL = 31.219
Step-by-step explanation:
Given the data:
The mean and range of each sample :
Sample __ Thread wear __ xbar __ R
1 ___31 __ 42 ___ 28 ____ 33.67 _14
2___ 26 _ 18 ____35____ 26.33 _17
3___25 __30 ___ 34____29.67 _ 9
4 __ 17 __ 25 ___ 21 _____ 21 ___ 8
5 __ 38 _ 29 ___ 35 _____ 34 __ 9
6 __ 41 __42 ___36 _____39.67_ 6
7 __ 21 __ 17 ___29 _____22.33 _12
8 __ 32 __26___28 ____ 28.67 _ 6
9 __ 41 __ 34 __ 33 ______ 36 __8
10__29___17___30 _____25.33_ 13
11 __26 __ 31 __ 40 _____32.33_ 14
12__23 __ 19 __ 45 _____12.33 __6
13 __17 __ 24 __ 32_____24.33__15
14 __43__ 35___17_____ 31.67 _ 26
15__18 ___25__ 29_____ 24 ___ 11
16__30___42___31 ____34.33__ 12
17__28___36 __ 32____ 32 ____8
18__40 __ 29 __ 31 ____33.33 __ 11
19__18 ___29__ 28____ 25 ____11
20_ 22 __ 34 __ 26 ___ 27.33 __12
Size per sample, sample size, n = 3
Number of samples, k = 20
We calculate the sample mean and range average :
Sample mean, x-- = Σxbar/n = 29.167
Range average, Rbar = ΣR/n = 11.4
The mean control limit :
x-- ± A2Rbar
From the x chart ;
A2 for n = 20 is A2 = 0.180
29.167 ± 0.180(11.40)
LCL = 29.167 - 0.180(11.40) = 27.115
UCL = 29.167 + 0.180(11.40) = 31.219
The Range control limit :
Rbar(1 ± 3(d3/d2))
From the R-chart :
d2 at n = 20 ; d2 = 3.735
d3 at n = 20 ; d3 = 0.729
LCL = 11.40(1 - 3(0.729/3.735)) = 4.725
UCL = 11.40(1 + 3(0.729/3.735)) = 18.075
PLEASE HELP WILL MARK BRAINLIEST
Answer:
AB
Step-by-step explanation:
From the question given above, we were told that triangle ABC is similar to triangle PTG.
Since both triangles are similar, the following assumptions hold:
PG / AC = PT / AB = TG / BC
Comparing the equation above with those given in the question, the missing part of the equation is AB
Convert the equation (y + 2) = –1/3(x – 4) to the point-slope form. Then fill in the blanks below to describe how to graph the equation. Plot the point _______, move _______ unit(s) down, and _______ unit(s) over to find the next point on the line.
A. (–2, 4), one, three
B. (4, –2), one, three
C. (2, 4), one, three
D.(4, –2), three, one
Answer:
A. (–2, 4), one, three
Step-by-step explanation:
For a linear equation:
y = a*x + b
the point-slope form is:
(y - y₁) = m*(x - x₁)
Where we know that this line has the slope m, and passes through the point (x₁, y₁)
In this case, the equation:
(y + 2) = –1/3(x – 4)
is already in the point-slope form.
here we have:
y₁ = -2
x₁ = 4
then the point is (-2, 4)
m = -(1/3)
m = -1/3 means that when we move 3 units to the right, we need to move one unit down. (or the inverse, we can move one unit down and 3 to the right)
So, to complete the statement we have:
plot the point (-2, 4), move one unit down, and three units over to find the next point on the line.
The correct option is A.
Let P denote the set of primes and E the set of even integers. As always, Z and N denote the integers and natural numbers, respectively. Find equivalent formulations of each of the following statements using the notation of set theory
a. √2 is a real number but not a rational number.
b. Every integer is a rational number.
c. 2 is an even prime number.
Answer:
sorry i dont know this answer
Which angle is an adjacent interior angle?
Triangle L M N. Angle L is 1, angle M is 2, angle N is 3. Side M N extends to form angle 4.
1
2
3
4
Step-by-step explanation:
Triangle LNM is an adjecent interior angle
Answer:
I think it's C
Step-by-step explanation:
Let me know if it's incorrect.
What is the HCF of 1280 and 630
Given:
The two numbers are 1280 and 630.
To find:
The HCF of the given numbers.
Solution:
First write the given numbers in prime factorization form.
[tex]1280=2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 5[/tex]
[tex]630=2\cdot 3\cdot 3\cdot 5\cdot 7[/tex]
Now the product of all the common prime factors is known as the HCF of 1280 and 630.
[tex]HCF=2\cdot 5[/tex]
[tex]HCF=10[/tex]
Therefore, the HCF of 1280 and 630 is 10.
The sum of 4 consecutive integers is 122. What is the third number in this sequence?
Answer:
31
Step-by-step explanation:
Let the smallest integer be x.
Since the 4 integers are consecutive (they come right after the other),
2nd integer= x +1
3rd integer= x +1 +1= x +2
4th integer= x +2 +1= x +3
Sum of the integers= 122
x +x +1 +x +2 +x +3= 122
4x +6= 122
4x= 122 -6
4x= 116
x= 116 ÷4
x= 29
3rd number
= 29 +2
= 31
Use the expression 9(7 + 2x) to answer the following:
Part A: Describe the two factors in this expression. (4 points)
Part B: How many terms are in each factor of this expression? (4 points)
Part C: What is the coefficient of the variable term? (2 points)
Step-by-step explanation:
Part A:
The two factors in 9(7+2x) are 9 and 7+2x
Part B:
First term: 9
Second term: 7+2x
Part C:
9(7+2x)
Open bracket
63+18x
The coefficient is 18x
A. The two factors are 9 and (7+2x).
B. In first factor, only one term and in second factor , two terms i.e. 7 and 2x are present.
C. The coefficient of the variable term is 18.
Algebraic expression:Given expression is;
[tex]9(7+2x)[/tex]
In given expression, there are two factors fist is 9 and second one is [tex](7+2x)[/tex]
In first factor, only one term and in second factor , two terms i.e. 7 and 2x are present.
To find the coefficient of variable term, we have to to expand given expression.
[tex]9(7+2x)=63+18x[/tex]
The coefficient of the variable term is 18.
Learn more about the algebraic expression:
https://brainly.com/question/4344214
When simplified (32/3125)^(2/5) is the same as 4/25 true or false?
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Answer:
True
Step-by-step explanation:
Your calculator can tell you this is true. Or, you can simplify the given expression:
[tex]\left(\dfrac{32}{3125}\right)^{2/5}=\left(\dfrac{2^5}{5^5}\right)^{2/5}=\dfrac{2^2}{5^2}=\boxed{\dfrac{4}{25}}[/tex]
__
The applicable rule of exponents is (a^b)^c = a^(bc).
The number of diners at a restaurant each day is recorded and a daily average is calculated every month (assume 30 days in a month). The number of diners each day has a mean of 107 and a standard deviation of 60, but does not necessarily follow a normal distribution.The probability that a daily average over a given month is greater than x is 2.5%. Calculate x. You may find standard normal table useful. Give your answer to 3 decimal places.x =
Answer:
x = 128.472
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The number of diners each day has a mean of 107 and a standard deviation of 60.
This means that [tex]\mu = 107, \sigma = 60[/tex]
Distribution of the daily average:
Over a month of 30 days, so [tex]n = 30, s = \frac{60}{\sqrt{30}} = 10.955[/tex]
The probability that a daily average over a given month is greater than x is 2.5%. Calculate x.
This is X when Z has a p-value of 1 - 0.025 = 0.975, so X when Z = 1.96. Then
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]1.96 = \frac{X - 107}{10.955}[/tex]
[tex]X - 107 = 1.96*10.955[/tex]
[tex]X = 128.472[/tex]
So x = 128.472
The scale of a map is 1/8 inch=10 miles. If two cities are 3 inches apart on the map how many miles are they from each other
No more than one state of nature can occur at a given time for a chance event. This indicates that the states of nature are defined such that they are
a. conservative events.
b. mutually exclusive.
c. independent outcomes.
d. collectively exhaustive.
Answer:
b. mutually exclusive.
Step-by-step explanation:
The given description is an illustration of mutually exclusive events.
Take for instance, when you roll a die;
It is impossible to have an outcome of 2 and 6 at the same time; these means that 2 and 6 are mutually exclusive.
In a nutshell, when two or more sates of events/states of nature can not happen at the same time; such events/states of nature are mutually exclusive.
If the fixed cost is 9000 per year. Variable costs are estimated to be Tk. 60.75 / item. The firm wants to break even if 80 items are sold per year. What should be the unit price of the item?
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Answer:
Tk 173.25
Step-by-step explanation:
The firm will break even if its cost is equal to its revenue. That is, the price of each item sold must equal the cost of producing it. To cover the fixed cost, a share of it must be added to each of the items sold. Then the break-even price for 80 items is ...
price = variable cost + share of fixed cost
price = Tk 60.75 +9000/80 = Tk 60.75 +112.50 = Tk 173.25
The force F (in pounds) needed on a wrench handle to loosen a certain bolt varies inversely with the length L (in inches) of the handle. A force of 40 pounds is needed when the handle is 7 inches long. If a person needs 20 pounds of force to loosen the bolt, estimate the length of the wrench handle. Round answer to two decimal places if necessary.
in inches
Answer:
14 inches
Step-by-step explanation:
Since F is inversely proportional to L,
[tex]f = \frac{k}{l} \\ when \: f = 40 \: l \: = 7 \\ \frac{k}{7} = 40 \\ k = 280 \\ when \: f = 20 \\ 20 = \frac{280}{l} \\ l = 14[/tex]
SOMEONE HELP ASAP PLES NO EXPLANATOIN NEEDED PLS LEAVE UR ANSWER AS TEXT (SOME TIMES I CAN'T SEE IMAGES) THANK YOU SO MUCH!!!
Answer:
i cant see the image
Step-by-step explanation:
I WILL MARK BRAINLIEST:))
Please translate this expression into a verbal expression 4(5j+2+j). (5 points)
Please help
Find the value of x,
m∠5 = x-6, m∠4 = 2x+4, m∠2 = 2x-26
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Answer:
x = 30 2/3
Step-by-step explanation:
Angles 4 and 5 are complementary, so we have ...
m∠4 +m∠5 = 90°
(2x +4) +(x -6) = 90
3x -2 = 90 . . . . . . . . . collect terms
3x = 92 . . . . . . . . . . add 2; next, divide by 3
x = 92/3 = 30 2/3
helppp
True or false: f(x) represents a function.
When 100 engines are shipped, all of them are free of defects. Select a written description the complement of the given event
A) At most one of the engines is defective.
B) All of the engines are defective.
C) At least one of the engines is defe
D) None of the engines are defective
Answer:
Option C
Step-by-step explanation:
Suppose that we have a given proposition p
We define the complement as:
"NOT p" or ¬p
So, if p is:
the dog is red
the complement is
the dog is NOT red.
The principal rule to work with this is:
if p is true, then ¬p is false
if p is false, then ¬p is true.
Here the proposition is:
p = "When 100 engines are shipped, all of them are free of defects."
When this is this is true, ¬p must be false.
when this is false, ¬p must be true.
Let's analyze the given options, first the incorrect ones:
A: "At most one of the engines is defective."
here if we have for example, two defective engines, then this proposition and the original proposition are false.
B: " All of the engines are defective."
Here if there is one defective engine, then this is false, and also is the original proposition.
D: "None of the engines are defective"
When the original proposition is true "When 100 engines are shipped, all of them are free of defects.", this proposition is also true (because none of the engines are defective)
Finally, the corrrect one
C "At least one of the engines is defective"
When the original proposition is true, there are no defective engines, so this is false.
While, if this is true, there is at least one defective engine, so the original proposition is false.
Then this is the correct option:
¬p = "At least one of the engines is defective"
Amy has 2$, Jack has 3 times as much as Amy. Catherine has twice as much as Jack. How much does Catherine have?
Answer: 12 dollars
Step-by-step explanation:
2x3x2=12
Easy math
CHECK MY ANSWERS PLEASE
____
The sequence is geometric:
3, 13, 23, 33,...
True
False***
_____________________
The sequence is geometric:
5, -25, 125, -625,...
True***
False
Step-by-step explanation:
For a geometric sequence,
[tex]\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}[/tex]
1. The sequence is :
3, 13, 23, 33,...
[tex]\dfrac{13}{3}\ne \dfrac{23}{13}[/tex]
It is not geometric. It is false
2. The sequence is :
5, -25, 125, -625
[tex]\dfrac{-25}{5}=\dfrac{125}{-25}\\\\-5=-5[/tex]
So, the sequence is geometric as the common ratio is same. It is true.
4g+r=2r-2x
I need someone’s help if you can help me
Answer:
4g+2x=r
Step-by-step explanation:
4g+r=2r-2x
collecting like terms
4g+2x=2r-r
4g+2x=r
a. The first five terms of n^2 + 5 are
Given:
The nth term of a sequence is:
[tex]n^2+5[/tex]
To find:
The first five terms of the given sequence.
Solution:
The given sequence is:
[tex]a_n=n^2+5[/tex]
For n=1,
[tex]a_1=1^2+5[/tex]
[tex]a_1=1+5[/tex]
[tex]a_1=6[/tex]
For n=2,
[tex]a_2=2^2+5[/tex]
[tex]a_2=4+5[/tex]
[tex]a_2=9[/tex]
For n=3,
[tex]a_3=3^2+5[/tex]
[tex]a_3=9+5[/tex]
[tex]a_3=14[/tex]
For n=4,
[tex]a_4=4^2+5[/tex]
[tex]a_4=16+5[/tex]
[tex]a_4=21[/tex]
For n=5,
[tex]a_5=5^2+5[/tex]
[tex]a_5=25+5[/tex]
[tex]a_5=30[/tex]
Therefore, the first five terms of the given sequence are 6, 9, 14, 21, 30.
Some number times 7 is equal to the number increased by 9
Answer:
.
Step-by-step explanation:
.
Solve the following equation or inequality for the unknown variable. Round answer to two decimal places if necessary.
(3x)2 - 10 = 56
4
x =
Answer:
x = 2.7
Step-by-step explanation:
The given equation is :
[tex](3x)^2-10=56[/tex]
We need to solve it for x.
It can be rewrite as follows:
[tex]9x^2-10=56[/tex]
Adding 10 to both sides,
[tex]9x^2-10+10=56+10\\\\9x^2=66\\\\x=\sqrt{\dfrac{66}{9}}\\\\x=2.70[/tex]
So, the value of x is equal to 2.7.
Can someone help me solve this? Thanks!
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Answer:
p(x) = x³ -3x²+4x -2
Step-by-step explanation:
When the polynomial has real coefficients, the complex roots come in conjugate pairs. You are given one root as 1+i, so there is another that is 1-i.
Each root r gives rise to a factor (x -r). Then the three roots tell you the factorization is ...
p(x) = (x -1)(x -(1+i))(x -(1-i))
The last two factors can be recognized as the factors of the difference of squares:
((x -1) +i)((x -1) -i) = (x -1)² -i²
= (x² -2x +1) -(-1) = x² -2x +2
Now the whole polynomial can be seen to be ...
p(x) = (x -1)(x² -2x +2) = x(x² -2x +2) -1(x² -2x +2)
p(x) = x³ -2x² +2x -x² +2x -2 . . . . eliminate parentheses
p(x) = x³ -3x²+4x -2
Latoya paid $12.24 for a 6.35 kg bag of food. a few weeks later, she paid $13.99 for a 7.48 kg bag at a different store. Find the unit price for each bag.
Answer:
1.92755 ,1.870320 i hope it will help you
Answer:
First bag's unit price=$1.92 per kg Second bag's unit price=$1.87 per kg
Step-by-step explanation:
1.92 becomes 1.93
Sam thinks of a 4 digit number. The digit in the one’s place is 3 less than the digit in the ten’s place and digit in thousand’s place is 5 less than the digit in hundred’s place. The value of the hundred’s place is 800. The digit in ten’s place is the greatest even number. What is the number Sam is thinking of?
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Answer:
3885
Step-by-step explanation:
The hundreds digit is 8, and the thousands digit is 5 less, so is 3.
The tens digit is 8 (the largest even digit), and the ones digit is 3 less, so is 5.
The number is ...
3885
Which of the following statements about points are false?
Check all that apply.
A. Their sizes vary.
B. They have no size and no dimensions,
C. They have no length or height.
D. Their size depends on their dimensions.
Answer:
their sizes vary
Step-by-step explanation:
their sizes vary
List all factors of the number 52. SHOW ALL WORK!!!
Answer:
Factors of number 52
Factors of 52: 1, 2, 4, 13, 26 and 52.
Negative Factors of 52: -1, -2, -4, -13, -26 and -52.
Prime Factors of 52: 2, 13.
Prime Factorization of 52: 2 × 2 × 13 = 22 × 13.
Sum of Factors of 52: 98.
