Please answer this question now

Answer:

co-ordinates are (-3,7) and (5,7)

or

(-3,-5) and (5,-5)

length of diagonal=10 units

Step-by-step explanation:

[tex]length=\sqrt{(5+3)^2+(1-1)^2} =\sqrt{64} =8\\slope ~of~length=\frac{1-1}{5+3} =0\\\\length ~of~rectangle~is~parallel~to~x-axis\\ width~ is~ parallel ~to~y- axis~and~is~6~units~away~from~length.\\other co-ordinates ~of~rectangle are~(-3,1+6)~and ~(5,1+6)~or~(-3,7)~and~(5,7)\\and~other~co-ordinates~are~(-3,1-6)~and~(5,1-6)~or~(-3,-5)~and~(5,-5)[/tex]

length of diagonal

d=\sqrt{8^2+6^2} =\sqrt{64+36} =\sqrt{100} =10 ~units\\or\\d=\sqrt{(5+3)^2+(1-7)^2} =\sqrt{64+36} =\sqrt{100} =10~units.

Answer:

1 day = 24 hours

we cam divide in 6 periods of 4 hours

if bacteria triples in size every four hours

3 millions at begining

3^7 = 2'187'000'000 bacteria

Espero que te sirva

Answer: Geometric progression

Step-by-step explanation:

0h -> 3x10^6 /4h-> 9x10^6 / 8h-27x10^6 / 12h->81x10^6 / 16h->243x10^6 / 20h-> 729x10^6 / 24h->2187x10^6 = 2.187.000.000.:

Answer:

4x(x+2) - x(3x+5)

Step-by-step explanation:

the area of the whole box is 4x(x+2)

to find the area of the shaded portion you have to subtract the area of the tiny box from the big box

the area of the tiny box is x(3x+5)

so, 4x(x+2) - x(3x+5) is the expression you can use to find the area of the shaded portion

Hello, please consider the following.

[tex]x^2 + 10x + 25 = 8\\\\\text{\bf We can notice that } x^2+10x+25=(x+5)^2 \text{ so}\\\\x^2 + 10x + 25 = (x+5)^2=8\\\\\text{\bf We take the root.}\\\\x+5=\pm\sqrt{8}\\\\\text{\bf We subtract 5}\\\\\boxed{x=-5-\sqrt{8}} \ \ or \ \ x=-5+\sqrt{8}[/tex]

In the box, you can find the smallest solution.

Thank you.

Answer:

c. 5.333...

Step-by-step explanation:

When converting fractions into decimals, all you have to do is that you have to divide the numerator by the denominator. In this case, we will get 16 divided by 3. If we do this, we will get 5 and 1/3. One third in decimals is 0.3333... so the answer is 5.333...

The decimal 5.33 will be equivalent to 16/3 so option (A) will be correct.

Arithmetic operators are four basic mathematical operations in which summation, subtraction, division, and multiplication involve.,

Summation = addition of two or more numbers or variable

For example = 2 + 8 + 9

Subtraction = Minus of any two or more numbers with each other called subtraction.

For example = 4 - 8

Division = divide any two numbers or variable called division.

For example 4/8

Multiplication = to multiply any two or more numbers or variables called multiplication.

For example 5 × 7.

Given the fraction of 16/3

So divide 16 by 3

16/3 = (15 + 1 )3

⇒ 15/3 + 1/3

⇒ 5 + 0.333

⇒5.3

Hence "The decimal 5.33 will be equivalent to 16/3".

To learn more about the arithmetic operators,

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Answer:

84%

Step-by-step explanation:

percentage of score in English=18/25*100

=72%.

72+p/2=78

72+p=156

p=84%

Mark me BRAINLIEST if helped

Tysm!

Answer:

y=3

Step-by-step explanation:

Answer:

[tex]\dfrac{1}{6561}[/tex]

Step-by-step explanation:

Given the expression [tex][(2^{-2})(3^{4})]^{-3} * [(2^{-3})(3^2)]^{2}[/tex], Using the laws of indices to simplify the expression. The following laws will be applicable;

[tex]a^m*a^n = a^{m+n}\\(a^m)^n = a^{mn}\\[/tex]

[tex]a^{-m} = 1/a^m[/tex]

Given [tex][(2^{-2})(3^{4})]^{-3} * [(2^{-3})(3^2)]^{2}[/tex]

open the parenthesis

[tex]= (2^{-2})^{-3}(3^{4})^{-3}* (2^{-3})^2(3^2)^2\\\\= 2^{-2*-3}* 3^{4*-3} * 2^{-3*2} * 3^{2*2}\\\\= 2^6 * 3^{-12} * 2^{-6} * 3^4\\\\collecting \ like \ terms\\\\= 2^6 * 2^{-6} * 3^{-12} * 3^4\\\\= 2^{6-6} * 3^{-12+4}\\\\= 2^0 * 3^{-8}\\\\= 1 * \frac{1}{3^8}\\ \\= \frac{1}{6561}[/tex]

Answer:

I think the answer is both

Answer

hope this helps

Answer:

Step-by-step explanation:

Let the mass of the metal be x

From the question

5/9 of the metal is 7kg

That's

[tex] \frac{5}{9} x = 7[/tex]

Multiply through by 9

We have

5x = 7 × 9

5x = 63

Divide both sides by 5

[tex] \frac{5x}{5} = \frac{63}{5} [/tex]

We have the final answer as

x = 12.6 kg

Hope this helps you

======================================================

Explanation:

The given exterior angle 97 is adjacent to the interior angle 180-97 = 83. This is the base angle of the isosceles triangle. The other base angle is directly above it. The base angles are always opposite the congruent sides.

The missing interior angle (adjacent to the blue angle x) is unknown, so we'll call it angle y. This angle adds to the other two base angles (83 each) to get a sum of 180. Adding any three interior angles of a triangle always gets you 180

y+83+83 = 180

y+166 = 180

y = 180-166

y = 14

Angle x and y are supplementary. They form a 180 degree angle

x+y = 180

x = 180-y

x = 180-14

x = 166

As you can see, the base angles combine to form the exterior angle we're after. This is because of the remote interior angle theorem.

Answer:

y = 64(0.5)ˣ

Step-by-step explanation:

We can write this as an exponential decay function. The formula for that is y = a(1 - b)ˣ where a is the initial value and b is the decay factor. In this case, a = 64 and b = 1/2 or 0.5 so the final answer is y = 64(0.5)ˣ.

Answer: 0

Work Shown:

Factors of 48 = {1, 2, 3, 4, 6, 8, 12, 16, 24, 48}

Erase the odd numbers of that list to get {2, 4, 6, 8, 12, 16, 24, 48}

Then highlight stuff that is greater than 24, and less than 48 at the same time.

No factors fit this description since 24 cannot be larger than itself, and 48 cannot be smaller than itself.

Answer: 0

Step-by-step explanation:

There is no number greater than 24 and less than 48.

Step-by-step explanation: look so if you have

shcool A its 8v+4b=12

and

School B: 12v+4b= 16

since both classes used 4 busses we can use elimination by subtracting the A class Equation from the b class equation to solve from v for its value Then, use either equation and the now found value for v to solve for b.

You should find part of the process to be

12v+4b-(8v+4b)=12-16 which shows the van holds only a few people even before continuing the solution.

Answer -4

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Answer: Please Give Brainliest. Thank You!

10 more

The number of seventh-graders that must join the club in order to meet the president's wishes is 10.

Since there are 45 eighth graders and 20 seventh graders in a school club and the president of this club wants 40% of the club’s members to be seventh graders, we need to find the number of seventh graders that will be added to the school club to make their percentage 40 %.

Let the number of seventh-graders to be added be x.

So, the new number of seventh-graders is 20 + x and the new number of people in the club is 45 + 20 + x = 65 + x

Thus, the percentage of seventh graders in the club is thus

[tex]\frac{20 + x}{65 + x} X 100[/tex] %

Since this percentage equals 40 %, we have that

[tex]\frac{20 + x}{65 + x} X 100[/tex]% = 40 %

[tex]\frac{20 + x}{65 + x} = \frac{40}{100} \\\frac{20 + x}{65 + x} = 0.4[/tex]

Cross-multiplying we have

[tex]20 + x = 0.4(65 + x)[/tex]

Expanding the bracket, we have

[tex]20 + x = 26 + 0.4x[/tex]

Subtracting 20 from both sides we have

[tex]x = 26 - 20 + 0.4x\\x = 6 + 0.4x[/tex]

Subtracting 0.4x from both sides, we have

[tex]x - 0.4x = 6\\0.6x = 6[/tex]

dividing both sides by 0.6, we have

x = 6/0.6

x = 10

So, the number of seventh-graders that must join the club in order to meet the president's wishes is 10.

Learn more about percentages here:

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Answer:

the value of x = 9  and y =11.

Given the system of equation:

12x + 4y =152                  .......[1]

32x + 12y = 420              ......[2]

Multiply equation [1] by 3 we get;

Using distributive property:  

            ......[3]

On solving equation [2] and [3] simultaneously we get;

x = 9

Substitute the value of x= 9 in [1] to solve for y;

108 + 4y = 152

Subtract 108 from both sides we have;

108 + 4y -108 = 152- 108

Simplify:

4y = 44

Divide both sides by 4 we get;

Simplify:

y= 11

therefore, the value of x = 9  and y =11.

Answer:

x=62

Step-by-step explanation:

a triangle equals 180

so knowing that you subtract 56 from 180

That gives you 124

Then you divide it by 2 because the sides are equal.

That gives you 62

so x=62

Answer:

131 1/4 in.²

Step-by-step explanation:

To find the area of the figure, you would have to divide the figure into two parts.  The figure can be divided into two rectangles.

Rectangle 1

The length is 11 3/4 in.  The width is 6 in.

A = lw

A = (11 3/4 in.)(6 in.)

A = 70 1/2 in.²

Rectangle 2

The length is 9 in.  The width is 6 3/4 in.

A = lw

A = (9 in.)(6 3/4 in.)

A = 60 3/4 in.²

Add the two areas together.

70 1/2 in.²  +  60 3/4 in.²  =  131 1/4 in.²

Answer:

B, C, A.

Step-by-step explanation:

A = C + 3A = C + 3

A = C + 3

A = C + 3A

C + 3A = C + 3

3A = 3

A = 1

A = C + 3

1 = C + 3

C + 3 = 1

C = -2

B = 2C

B = 2(-2)

B = -4.

So, from least to greatest, B = -4, C = -2, and A = 1.

Hope this helps!

Answer:

1/12

Step-by-step explanation:

3/4 + z = 5/6

Subtract 3/4 from each side

3/4 -3/4+ z = 5/6-3/4

z = 5/6 -3/4

Get a common denominator of 12

z = 5/6 *2/2 -3/4 *3/3

z = 10/12 - 9/12

z = 1/12

Answer:

[tex] \boxed{\sf {18}^{2} + {24}^{2} = {x}^{2}} [/tex]

To Find:

Length of hypotenuse of the right triangle i.e. x

Step-by-step explanation:

Pythagoras theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides”.

[tex] \therefore [/tex]

[tex] \sf \implies {18}^{2} + {24}^{2} = {x}^{2} [/tex]

Answer:

18²+24²=x²

Step-by-step explanation:

to answer this question you must know Pythagorean theorem

a^ 2+b^2 =c^2

a and b stands for the sides with length 24 and 18 and c stands for the HYPOTENUSE . so the correct answer for the above question is 18²+24²=x²

Answer:

Use this formula:

a = b * h

Where: "a", the area of the rectangle is equal to its "b" (base), multiplied by "h" (height)

Step-by-step explanation:

Usa esta formula:

a = b * h

Donde: "a", el área del rectángulo es igual a su "b" (base), multiplicado por "h" (su altura).

Answer:

The total number of cups in arranged in an hexagonal area = 19 cups

Step-by-step explanation:

The pack the most circles within an area, the arrangement with the densest packing is the hexagonal lattice structure similar to the bee's honeycomb as has been proved Gauss and Fejes Toth.

Therefore, we pack the circles in an hexagonal lattice structure in an assumed hexagonal area where we have;

The longest straight line is five cups the next on either side are four cups and the final line on either side has three cups

The total number of cups = 3 + 4 + 5 + 4 + 3 = 19 cups

The total number of cups = 19 cups.

Answer:

5/6 pounds

Step-by-step explanation:

A group of people buys 5 pounds of corn meal to divide equally among 6 families write a fraction or mixed number that shows how many pounds of corn meal each family gets'.

Given the following :

Amount of corn meal purchased = 5 pounds

Number of people to share = 6 families

Assume, it is divided equally among them;

Then; each family gets ;

(Pounds of corn meal purchased/number of families) ;

5 / 6 pounds of corn meal will be distributed to each family.

Answer:

354.20 + 50.60w ≥ 1099.51

Step-by-step explanation:

354.20 + 50.60w ≥ 1099.51

Answer:

x= -11

Step-by-step explanation:

the coefficient is variable that appears before a number . bearing this in mind, the coefficient of x is therefore 2 .

the value of x is:

>32+2x=10

>2x=10-32

>2x= -22

>x= -11

Answer:

Step-by-step explanation:

Coefficient of x = 2

32 + 2x  = 10

Subtract 32 from both side

32 + 2x -32 = 10 - 32

              2x =  - 22

Divide both sides by 2

            2x/2 = -22/2

x = -11

Answer:

[tex]\huge\boxed{\sf \frac{a^2+b^2}{2(a^2-b^2)}}[/tex]

Step-by-step explanation:

=> [tex]\sf \frac{a}{2(a+b)} + \frac{b}{2(a-b)}[/tex]

LCM = 2(a+b)(a-b)

=> [tex]\sf \frac{a(a-b)+b(a+b)}{2(a+b)(a-b)}[/tex]

Simplifying further

=> [tex]\sf \frac{a^2-ab+ab+b^2}{2(a^2-b^2)}[/tex]

=> [tex]\sf \frac{a^2+b^2}{2(a^2-b^2)}[/tex]

[tex]\dfrac{a}{2(a+b)}+\dfrac{b}{2(a-b)}=\\\\\dfrac{a(a-b)}{2(a+b)(a-b)}+\dfrac{b(a+b)}{2(a+b)(a-b)}=\\\\\dfrac{a^2-ab}{2(a^2-b^2)}+\dfrac{ab+b^2}{2(a^2-b^2)}=\\\\\dfrac{a^2+b^2}{2(a^2-b^2)}[/tex]