PLEASE HELP ASAP PLS!!! WILL MARK BRAINLIEST

Answer:

(a) The mean is 0

(b) The median is -30

(c) The mode is unimodal

Step-by-step explanation:

Given

[tex]Data: 15,-4,-10,8,14,-10,-2,-11[/tex]

Solving (a): The mean.

This is calculated using:

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x =\frac{15-4-10+8+14-10-2-11}{8}[/tex]

[tex]\bar x =\frac{0}{8}[/tex]

[tex]\bar x =0[/tex]

Solving (b): The median

First, arrange the data

[tex]Sorted: -11,-10, -10, -4, -2,8,14,15[/tex]

There are 4 elements in the dataset. So, the median is the mean of the 4th and 5th item.

[tex]Median = \frac{-4-2}{2}[/tex]

[tex]Median = \frac{-6}{2}[/tex]

[tex]Median = -3[/tex]

Solving (c): The mode

The item that has occurs most is -10.

Hence, the mode is -10. The dataset is unimodal because it has only 1 mode (-10).

Answer:

1,736 chocolate cover peanuts

Step-by-step explanation:

do 28×62 hope this helps

Answer:

1736 chocolate-covered peanuts

Step-by-step explanation:

[tex]\frac{1}{62} :\frac{28}{y}[/tex]

1 · y = 62 · 28

y = 1736

Answer:

Area of the given sector = 130.9 cm²

Step-by-step explanation:

Area of a sector is given by the formula,

Area of the sector = [tex]\frac{\theta}{2\pi }\times (\pi r^{2})[/tex]

Area of the sector of the circle given in the picture = [tex]\frac{\frac{5\pi }{6} }{2\pi }[\pi (10)^{2}][/tex]

                                                                               = [tex]\frac{5}{12}(100\pi )[/tex]

                                                                               = 130.8996

                                                                               ≈ 130.9 cm²

Answer:

The distance between A(-8, 4) and B(4, -1) is 13 units.

Step-by-step explanation:

To find the distance between any two points, we can use the distance formula given by:

[tex]\displaystyle d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2[/tex]

We have the two points A(-8, 4) and B(4, -1). Let A(-8, 4) be (x₁, y₁) and let B(4, -1) be (x₂, y₂). Substitute:

[tex]d=\sqrt{(4-(-8))^2+(-1-4)^2}[/tex]

Evaluate:

[tex]d=\sqrt{(12)^2+(-5)^2}[/tex]

So:

[tex]d=\sqrt{144+25}=\sqrt{169}=13\text{ units}[/tex]

The distance between A(-8, 4) and B(4, -1) is 13 units.

___________________________________

[tex]\quad\quad\quad\quad\tt{A.) x\tiny{1}\small{=-8}, y\tiny{1}\small{=4}}[/tex]

[tex]\quad\quad\quad\quad\tt{B.) x\tiny{2}\small{=4}, y\tiny{2}\small{=-1}}[/tex]

[tex]\quad\quad\quad\quad\tt{d = \sqrt{(x \tiny{2} \small{ - x \tiny{1} \small {)}^{2} + (y \tiny{2} \small{ - y \tiny{1} \small{)}^{2} } }}} [/tex]

[tex]\quad\quad\quad\quad\tt{d = \sqrt{(4 - \small{ (- 8}{))}^{2} + ( \small{- 1)}\small{ - {4)}}^{2} }}[/tex]

[tex]\quad\quad\quad\quad\tt{d = \sqrt{ ( {12)}^{2} + {( -5)}^{2} }}[/tex]

[tex]\quad\quad\quad\quad\tt{d = \sqrt{ {144} + {25}}}[/tex]

[tex]\quad\quad\quad\quad\tt{d = \sqrt{ 169}}[/tex]

[tex]\quad\quad\quad\quad\tt{d = 13}[/tex]

[tex]\quad\quad\quad\quad\boxed{\boxed{\tt{\color{magenta}d = 13}}}[/tex]

___________________________________

#CarryOnLearning

✍︎ C.Rose❀

Answer:

The amount of interest he paid at the end of the loan is $ 311.85.

Step-by-step explanation:

Given that Juan borrowed $ 1500 from a credit union for 7 years and was charged simple interest at a rate of 2.97%, to determine what is the amount of interest he paid at the end of the loan, the following calculation must be performed:

(1500 x 0.0297) x 7 = X

44.55 x 7 = X

311.85 = X

Therefore, the amount of interest he paid at the end of the loan is $ 311.85.

Answer:

4.5 hours

Step-by-step explanation:

8t + 10(7-t) = 61

8t +70-10t=61

-2t = 61-70

-2t= -9

t = -9/-2

t = 4.5

Answer:- Hey Buddy! Hope this helps:-

12.5%= 125/10 and when simplified becomes 25/2

pls mark brainliest

Answer:

94

Step-by-step explanation:

We know that a straight line adds up to 180 degrees, and angle QPS, summed up by angles QPR and RPS, equals that.

Therefore,

angle QPS = QPR + RPS

180 = QPR + RPS

180 = 7x-4+9x-40

180 = 16x-44

224= 16x

x = 222/16 = 14

QPR  = 7x-4 = 94

Answer:

[tex]x\approx 5.48[/tex]

Step-by-step explanation:

Draw a line from the center of the circle O to the end of either side of the line marked as 4. This line represents two things:

In this case, both are important. Since [tex]x[/tex] is also a radius of the circle, the line must be equal to [tex]x[/tex], since all radii of a circle are equal. To find the length of this line, use the Pythagorean Theorem:

[tex]a^2+b^2=c^2[/tex], where [tex]c[/tex] is the hypotenuse of the triangle and [tex]a[/tex] and [tex]b[/tex] are the two legs of the triangle.

Since we're solving for the hypotenuse and the two legs are 5.1 and 2, we have:

[tex]5.1^2+2^2=c^2,\\26.01+4=c^2,\\c^2=30.01,\\c=5.47813836992\approx \boxed{5.48}[/tex] (round as necessary).

Answer:

84

Step-by-step explanation:

god bless stay safe po

Answer:

38

Step-by-step explanation:

Answer:

(f+g)(2)  = 4

(f-g)(4) = 8

(f ÷g)(2) = 7

(f x g)(1) = 0

Step-by-step explanation:

We are given these following functions:

[tex]f(x) = 2x + 3[/tex]

[tex]g(x) = x - 1[/tex]

(f+g)(2)

[tex](f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2[/tex]

At [tex]x = 2[/tex]

[tex](f+g)(2) = 3(2) - 2 = 6 - 2 = 4[/tex]

Then

(f+g)(2)  = 4

(f-g)(4)

[tex](f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4[/tex]

At x = 4

[tex](f-g)(4) = 4 + 4 = 8[/tex]

Then

(f-g)(4) = 8

(f ÷g)(2)

[tex](f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}[/tex]

At x = 2

[tex](f \div g)(2) = \frac{7}{1} = 7[/tex]

Then

(f ÷g)(2) = 7

(f x g)(1)

[tex](f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3[/tex]

Then

[tex](f \times g)(1) = 2(1)^2 + 1 - 3 = 3 + 1 - 3 = 0[/tex]

So

(f x g)(1) = 0

Answer:

x=3

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

This identity holds as long as [tex]\displaystyle \theta \ne k\, \pi + \frac{\pi}{2}[/tex] for all integer [tex]k[/tex].

For the proof, make use of the fact that:

[tex]\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}[/tex] (definition of tangents,) and

[tex]\cos(\theta) = \sqrt{1 - \sin^{2}(\theta)}[/tex] (Pythagorean identity,) which is equivalent to [tex]1 - \cos^{2}(\theta) = \sin^{2}(\theta)[/tex].

Step-by-step explanation:

Assume that [tex]\displaystyle \theta \ne k\, \pi + \frac{\pi}{2}[/tex] for all integer [tex]k[/tex]. This requirement ensures that the [tex]\tan(\theta)[/tex] on the left-hand side takes a finite value. Doing so also ensures that the denominator [tex]\sqrt{1 - \sin^2(\theta)}[/tex] on the right-hand side is non-zero.

Make use of the fact that [tex]\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}[/tex] to rewrite the left-hand side:

[tex]\begin{aligned} & \tan(\theta) \cdot \sin(\theta) \\ =&\; \frac{\sin({\theta})}{\cos({\theta})} \cdot \sin(\theta) \\ =&\; \frac{\sin^{2}(\theta)}{\cos(\theta)}\end{aligned}[/tex].

Apply the Pythagorean identity [tex]\sin^{2}(\theta) = 1 - \cos^{2}(\theta)[/tex] and [tex]\cos(\theta) = \sqrt{1 - \sin^{2}(\theta)}[/tex] to rewrite this fraction:

[tex]\begin{aligned} & \frac{\sin^{2}(\theta)}{\cos(\theta)}\\ =\; &\frac{1 - \cos^{2}(\theta)}{\cos(\theta)}\\ =\; & \frac{1 - \cos^{2}(\theta)}{\sqrt{1 - \sin^{2}(\theta)}}\end{aligned}[/tex].

Hence, [tex]\displaystyle \tan(\theta) \cdot \sin(\theta) = \frac{1 - \cos^{2}(\theta)}{\sqrt{1 - \sin^{2}(\theta)}}[/tex].

Answer:

The answer is C

Step-by-step explanation:

3    :    4

^          ^

II          II

red    blue

Answer:

x=9

Step-by-step explanation:

Answer:

the answer is 10

Step-by-step explanation:

Answer:

[tex]\displaystyle -x^3+10x^2-48x+64[/tex]

Step-by-step explanation:

We want to find the minimum-degree polynomial with real coefficients and zeros at:

[tex]x= 4+4i\text{ and } x = 2[/tex]

As well as a y-intercept of 64.

By the Complex Root Theorem, if a + bi is a root, then a - bi is also a root.

So, a third root will be 4 - 4i.

The factored form of a polynomial is given by:

[tex]P(x)=a(x-p)(x-q)...[/tex]

Where a is the leading coefficient and p and q are the zeros. More factors can be added if necessary.

Substitute:

[tex]P(x)=a(x-(2))(x-(4+4i))(x-(4-4i))[/tex]

Since we want the minimum degree, we won't need to add any exponents.

Expand the second and third factors:

[tex]\displaystyle \begin{aligned} (x-(4+4i))(x-(4-4i))&=(x-4-4i)(x-4+4i) \\ &= x(x-4-4i)-4(x-4-4i)+4i(x-4-4i)\\ &=x^2-4x-4ix-4x+16+16i+4ix-16i-16i^2\\ &= x^2-8x+32\end{aligned}[/tex]

Hence:

[tex]P(x)=a(x-2)(x^2-8x+32)[/tex]

Lastly, we need to determine a. Since the y-intercept is y = 64, this means that when x = 0, y = 64. Thus:

[tex]64=a(0-2)(0^2-8(0)+32)[/tex]

Solve for a:

[tex]-64a=64\Rightarrow a=-1[/tex]

Our factored polynomial is:

[tex]P(x)=-(x-2)(x^2-8x+32)[/tex]

Finally, expand:

[tex]\displaystyle \begin{aligned} P(x) &=-(x^2(x-2)-8x(x-2)+32(x-2)) \\&=-(x^3-2x^2-8x^2+16x+32x-64)\\&=-(x^3-10x^2+48x-64)\\&= -x^3+10x^2-48x+64\end{aligned}[/tex]

Answer: wheres the photo ?

Step-by-step explanation:

Answer:

-3-4=-7

-3+(-4)

hope this helps

have a good day :)

Step-by-step explanation:

Answer: 90

Step-by-step explanation:

c = 2πr

r = 15

d = 30

30π = 90

Answer:

C≈90

Step-by-step explanation:

remember circumference formula

[tex] \displaystyle C = 2\pi r[/tex]

given that,r=15 thus substitute:

[tex] \displaystyle C = 2\pi .15[/tex]

simplify mutilation:

[tex] \displaystyle C = 30\pi [/tex]

substitute the given value of π:

[tex] \displaystyle C = 30.3[/tex]

simplify multiplication:

[tex] \displaystyle C = 90[/tex]

and we are done!

Answer:

A. Acute

B. 80 degrees

Step-by-step explanation:

Answer: Hello your question is poorly written attached below is the complete question

answer : 101.8

Step-by-step explanation:

Given data :

Standard deviation ( б ) = 14

55% have IQ scores > 100

45% have IQ scores < 100

Determine the mean IQ score for the region

P ( X > x ) =

P ( Z ≥ ( 100 - μ ) / 14 ) = 0.55    also

P ( Z ≤ ( 100 - μ ) / 14 ) = 0.45

using standard normal calculator

100 - μ  / 14  = Z₀.₄₅ = - 0.126

resolving the relation above

100 - μ  / 14  = - 0.126

μ = 100 - 14 ( -0.126 )

   = 101.764 ≈ 101.8

Answer:

Hence when the radius is halved the area is divided by 4

2.5 inches^2

Step-by-step explanation:

Given data

Area= 10inches^2

We know that the expression for the area of  a circle is given as

Area= πr^2

10= 3.142*r^2

10/3.142= r^2

r^2= 3.18

Square both sides

r= √3.18

r= 1.78 inches

Now let us half the radius and find the area of the new circle

r/2= 1.78/2

r= 0.89

Area of the new circle is

Area= 3.142*0.89^2

Area= 3.142*0.7921

Area= 2.5 inches^2

Answer:

The probability that the mean number of holding penalties per game is of X or less is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is the mean number of penalties per game, [tex]\sigma[/tex] is the standard deviation and n is the number of games that will be sampled.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have that:

The mean number of penalties per game is [tex]\mu[/tex] and the standard deviation is [tex]\sigma[/tex].

Sample of n games:

This means that [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

What is the probability that, for a sample of college games to be played next week, the mean number of holding penalties will be X penalties per game or less?

The probability that the mean number of holding penalties per game is of X or less is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is the mean number of penalties per game, [tex]\sigma[/tex] is the standard deviation and n is the number of games that will be sampled.

Answer:

[tex]y=2[/tex]

Step-by-step explanation:

In [tex]y=a\cos(bx-c)+d[/tex], [tex]d[/tex] represents the vertical shift. The midline of the function is given by [tex]y=d[/tex], because the parent function [tex]y=\cos x[/tex] has a midline at [tex]y=0[/tex]. Therefore, the midline of the function [tex]y=\cos (\frac{2\pi}{3}x)+2[/tex] is [tex]\boxed{y=2}[/tex]

Answer:

Where is the equation?

Step-by-step explanation:

Answer:

I don't understand

Step-by-step explanation:

Are you Issac?

What is the question?

Answer:

56.52 cm³

Step-by-step explanation:

[tex]\boxed{volume \: of \: cone = \frac{1}{3} \pi {r}^{2}h }[/tex]

Diameter= 2 ×radius

Radius

= 6 ÷2

= 3cm

Height, h= 6cm

Volume of the cone

[tex] = \frac{1}{3} (3.14)( {3}^{2} )(6)[/tex]

= 56.52 cm³

9514 1404 393

Answer:

  x = 25

Step-by-step explanation:

The parallel lines divide the triangle sides proportionally.

  x/40 = 15/24

  x = 40(15/24) . . . . multiply by 40

  x = 25