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Answer:

Step-by-step explanation:

[tex]2\sqrt{8}+3\sqrt{50}=2\sqrt{2*2*2} + 3\sqrt{5*5*2}\\\\= 2*2\sqrt{2}+3*5\sqrt{2}\\\\=4\sqrt{2}+15\sqrt{2}\\\\= 19\sqrt{2}[/tex]

[tex]3\sqrt{12}+4\sqrt{27}=3\sqrt{2*2*3}+4\sqrt{3*3*3}\\\\=3*2\sqrt{3}+4*3\sqrt{3}\\\\=6\sqrt{3}+12\sqrt{3}\\\\=(6+12)\sqrt{3}\\\\= 18\sqrt{3}[/tex]

Answer:

9 hours worked after school and 4 hours worked on saturday

Step-by-step explanation:

x = amount of hours worked after school

y = amount of hours worked on saturday

x + y = 13 or x = 13 - y

and

3x + 4y = 43

plug:

3 · (13 - y) + 4y = 43

39 - 3y + 4y = 43

y = 4

plug:

x = 13 - y

x = 13 - 4 = 9

9 hours worked after school and 4 hours worked on saturday

Step-by-step explanation:

cost per day

= $1500 / week

= $1500 / 7 days

= $1500 ÷ 7 / 7 ÷ 7

≈ $214,29 / day

Answer:

2x+y=s

2x\2+y\2=s\2

therefore x= s\2-y\2

Answer:  

The difference between the longest and shortest sides of the triangle is 4 cm.

Explanation:

Step Number One:

Let the shortest side of the triangle have a length of x.

The middle side of the triangle has a length that is half of 3 times the length of the shortest side. This can be written as 1/2*3x, which equals 3/2x.

The longest side of the triangle has a length that is 2 centimeters longer than the length of the middle side. This can be written as 3/2x + 2.

Step Number Two:

The perimeter of the triangle, which can be found by adding the lengths of all of the sides of the triangle, is 18 centimeters. This can be shown by the following equations:

Shortest Side + Middle Side + Longest Side = Perimeter

x + 3/2x + 3/2x + 2 = 18

4x + 2 = 18

4x = 16

x = 16/4

x = 4

Step Number Three:

This means that the shortest side of the triangle has a length of 4 centimeters and the longest side of the triangle has a length of 8 centimeters.

8 cm - 4 cm = 4 cm

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Are you still confused? Not feeling confident in your ability to solve these types of problems? Some helpful topics to practice are listed below!

Still confused on ...

Step 1 - Practice equation solving!

Step 2 - Practice perimeter!

Step 3 - Practice addition and subtraction!

Remember: Certain problems may be tricky, but practice makes perfect!

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Answer by Math_Is_Me_123         

Answer: 70.4÷11 = 6.4

Step-by-step explanation:

__6.4__

11/70.4

-66 |

04 4

- 4 4

_____

=0

Answer:

.......................

Answer: The second bubble thing is correct you have picked the wrong one.

Answer: 9

Step-by-step explanation:

36 ÷ 4 = 9

Answer:

10 + 28 / 35

= 38 / 35

= 1.0875

Answer:

Step-by-step explanation:x

Answer:

|-4| < |-5|

Step-by-step explanation:

because if modules is given sub sign will be deducate

Answer:

18

Step-by-step explanation:

3/6 =1/2

1/2 of 36 is 18

Answer:

Step-by-step explanation:

To find the y-intercept, set x=0 and evaluate the function.

  f(0) = -3/(0 -4) = 3/4

The y-intercept is (0, 3/4).

__

To find the x-intercept(s), set f(x) = 0 and solve for x.

  0 = -3/(x^2 -4)

  0 = -3 . . . . . . . . . . multiply by (x^2 -4), x ≠ ±2

There are no values of x that will make this true. There are no x-intercepts.

_____

Additional comments

In general, you find the x-intercepts of a rational function by finding the zeros of the numerator. Here, the numerator is -3, so cannot ever be zero.

I find a graphing calculator to be a useful tool for showing where to look for x-and y-intercepts. The attached graph shows y=0 (the x-axis) is a horizontal asymptote, so there are no x-intercepts.

Answer:

6/5

Step-by-step explanation:

(2/5)/(1/3) ⇔ (2/5)(3) = 6/5

Answer:

6/5 or 1 and 1/5

Step-by-step explanation:

To divide fractions use KFC

Using KFC, 2/5 ÷ 1/3 becomes 2/5 × 3/1.

We can now multiply the numerators and multiply the denominators:

Answer: 6/5 or 1 and 1/5

Hope this helps!

Answer: i solved on my channel

Step-by-step explanation: https://youtu.be/rTgj1HxmUbg

Answer:

x=g-c

Step-by-step explanation:

Answer:

The equation to represent number of years in score is 5x = 1005x=100,

The number of years in score is 20

Step-by-step explanation:

CAN YOU GIVE ME BRAINliEST

Answer:

Below.

Step-by-step explanation:

–10m4n3 + 8m2n6 + 3m4n3  – 2m2n6 – 6m2n6

= 8m2n6 – 2m2n6 – 6m2n6 – 10m4n3 + 3m4n3

= 8m2n6 - 8m2n6 – 7m4n3

= –7m4n3.

It is a mononomial.

Answer:

ok so.u grit da he on 40/ rock cause u got a andriodnh on gf

Answer:

x = 49

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are in proportion, that is

[tex]\frac{DN}{KJ}[/tex] = [tex]\frac{DG}{KM}[/tex] , substitute values

[tex]\frac{5}{35}[/tex] = [tex]\frac{8}{x+7}[/tex] ( cross- multiply )

5(x + 7) = 280 ( divide both sides by 5 )

x + 7 = 56 ( subtract 7 from both sides )

x = 49

Answer:

a)7x-3x

b)4+28y

Step-by-step explanation:

first one follow bidmas

2nd one just do 4 times 1 =4 and 7y times 4 equals 28y

Step-by-step explanation:

= f( g(2) )

= 3(2x + 1) + 1

= 6x + 3 + 1

= 6x + 4

= 6(2) + 4

= 12 + 4

= 16

f(g(2)) = 16

Answer:

20

Step-by-step explanation:

20*20 = 400

OR

[tex]20 {}^{2} = 400[/tex]

Answer:

-5,3

Step-by-step explanation:

find the middle of it and simplify until you reach the point

Answer:

[tex]\frac{\sqrt{70} }{5}[/tex]

Step-by-step explanation:

[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]

[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]

[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]

[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]

[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]

[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]

[tex]\large\underline{\sf{Solution-}}[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

We can write as :

27 = 3 × 3 × 3 = 3³

8 = 2 × 2 × 2 = 2³

243 = 3 × 3 × 3 × 3 × 3 = 3⁵

32 = 2 × 2 × 2 ×2 × 2 = 2⁵

[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

Now, we can write as :

(3³/2³) = (3/2)³

(3⁵/2⁵) = (3/2)⁵

[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

Now using law of exponent :

[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]

[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]

[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]

[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]

[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]

[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]