Answers
Answer:
Question for number 3 is -3
Question for number 4 is 6
Step-by-step explanation:
Brainless please
Related Questions
4. Construct a quadrilateral ABCD in which AB=BC=3.5cm, AD=CD= 5.2 cm and ^ABC= 120°.
Answers
9514 1404 393
Explanation:
The attachment shows such a construction. Here are the steps.
1. Draw circle B with radius 3.5 cm
2. Mark a point X on the circle and draw circle X with the same radius. Mark the intersection points of circles B and X as points A and C.
3. Draw circles A and C with radii 5.2 cm. Mark the intersection point as point D so that X is on segment BD.
4. Finish by drawing kite ABCD.
Express the solution graphically of -1/3(2x+1) <3
Answers
Answer:
The first picture is the solution that I worked out and the second is the graph of the two solutions.
The graph of the solution of inequality [tex]-\frac{1}{3} (2x+1) < 3[/tex] is as shown below.
What is inequality?"It is a mathematical statement of an order relationship (greater than, greater than or equal to, less than, or less than or equal to) between two numbers or algebraic expressions."
For given question,
We have been given a inequality [tex]-\frac{1}{3} (2x+1) < 3[/tex]
We solve above inequality.
[tex]\Rightarrow -\frac{1}{3} (2x+1) < 3\\\\\Rightarrow \frac{1}{3} (2x+1) > -3\\\\\Rightarrow 2x+1 > -9\\\\\Rightarrow 2x > -10\\\\\Rightarrow x > -5[/tex]
so, the solution of the inequality [tex]-\frac{1}{3} (2x+1) < 3[/tex] is all points on the X-axis which are greater than x = -5.
The graph of the solution of inequality [tex]-\frac{1}{3} (2x+1) < 3[/tex] is as shown below.
Learn more about the inequality here:
https://brainly.com/question/19003099
#SPJ2
Aaron surveyed a group of students about the number of pets they own. He recorded the data in the dot plot below.
Answers
Answer:
Step-by-step explanation:
18, count the dots. The number line aka 0-7 is just showing the number of possible pets a person could have
Please Help!
find the value of x
round to the nearest tenth as needed
Answers
Answer:
237.9 yards
Step-by-step explanation:
90-23=67
cos 67⁰=x/610
x=610 cos 67
x= 610 x 0.39
x=237.9 yards
Please help i kinda need this fast
Answers
Answer:
the first page :
x =20
the second page :
x = 45
Step-by-step explanation:
first question
to find angle BOC subtract 110 from 180( because 180 degrees is a straight line)
angle BOC = 70 degrees
this means that the angle opposite to it is also 70 degrees ( DOA)
now to find x, add up 110, 70, 70, 90, x to get 360
110 + 70 + 70 + 90 + x = 360
x = 20
second question :
every thing adds up to 360 degrees.
90 + 5x + x = 360
6x = 270
x = 45
Find the slope and then an equation for each line.
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and for 2 the slope is -2/-8 or 1/4 and the equation is y-0=1/4(x-0)
Question 9 Pls if anyone knows the answer that will be greatly appreciated :)
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Answer:
All the angles on the bottom line are 60. The angles on the top line from left to right is 130, 60, 60, 130.
Step-by-step explanation:
hellppp................
Answers
Answer:
[tex]B)[/tex]
[tex](-1,1)(-3,3)\\\frac{3-1}{-3+1} =-1\\1=1+b\\b=0\\y=-x[/tex]
OAmayOHopeO
The null hypothesis and the alternate hypothesis are: H0: The frequencies are equal. H1: The frequencies are not equal. Category f0 A 10 B 30 C 30 D 10 State the decision rule, using the 0.05 significance level. (Round your answer to 3 decimal places.) Compute the value of chi-square. (Round your answer to 2 decimal place.) What is your decision regarding H0
Answers
Answer:
Reject H0
Step-by-step explanation:
Given :
H0: The frequencies are equal. H1: The frequencies are not equal
Category f0 A 10 B 30 C 30 D 10
Total f0 = (10 + 30 + 30 + 10) = 80
Expected frequency is the same for all categories :
Expected frequency = 1/4 * 80 = 20
χ² = Σ(observed - Expected)² / Expected
χ² = (10-20)^2 / 20 + (30-20)^2 /20 + (30-20)^2 / 20 + (10-20)^2 / 20
χ² = (5 + 5 + 5 + 5) = 20
Pvalue = 0.00017
Pvalue < α
Quanto é 7 × 5/2????
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Can someone help me with this question plz
Answers
Answer:
Volume is 167.6 yd³
Step-by-step explanation:
[tex]{ \boxed{ \bf{volume = \frac{1}{3}\pi {r}^{2} h}}} \\ { \sf{volume = \frac{1}{3} \times 3.14 \times {(4)}^{2} \times 10}} \\ \\ { \sf{volume = 167.6 \: {yd}^{3} }}[/tex]
help me with my work pls
Answers
Answer:
-75/4
Step-by-step explanation:
75 x 100 = 7500
4 x 100 = 400
Seeds are often treated with fungicides to protect them in poor-draining, wet environments. A small-scale trial, involving six treated and six untreated seeds, was conducted prior to a large-scale experiment to explore how much fungicide to apply. The seeds were planted in wet soil, and the number of emerging plants were counted. If the solution was not effective and five plants actually sprouted.
Required:
What is the probability that all five plants emerged from treated seeds?
Answers
Answer:
0.0076 = 0.76% probability that all five plants emerged from treated seeds
Step-by-step explanation:
The plants were chosen without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x successes is given by the following formula:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
In which:
x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this question:
6 + 6 = 12 seeds, which means that [tex]N = 12[/tex]
6 treated, which means that [tex]k = 6[/tex]
Five sprouted, which means that [tex]n = 5[/tex]
What is the probability that all five plants emerged from treated seeds?
This is P(X = 5). So
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 5) = h(5,12,5,6) = \frac{C_{6,5}*C_{6,0}}{C_{12,5}} = 0.0076[/tex]
0.0076 = 0.76% probability that all five plants emerged from treated seeds
The diameter of a circle is 10 meters what is the angle of an arc 3pie meters long
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Answer:
10 meaters yes these answer is correct
Z = { x:x is an integer, x ≥ - 3 and x ≤ + 3}
Answers
Answer:
If this is asking for the set:
Z = {-3, -2, -1, 0, 1, 2, 3}
Step-by-step explanation:
Z is the set of all integers and it appears that you are being asked for the values in the set Z that are within the range: -3 ≤x ≤ 3
Danielle stayed in three different cities (Washington, D.C., Atlanta, Georgia, and Dallas, Texas) for a total of 22 nights. She spent twice as many nights in Dallas as she did in Washington. The total cost for 22 nights (excluding tax) was $3,100. Determine the number of nights that she spent in each city.
Answers
Answer:
C. 6 nights in Washington, 4 nights in Atlanta, and 12 nights in Dallas
Step-by-step explanation:
Plz help me find x and show work
Answers
Answer:
9^2 + 12^2 = x^2
81 + 144 = 225
225 ÷ 15 = 15
the answer for this question is 15
Step-by-step explanation:
Evaluate 4log4(3,100)
Answers
Answer:
[tex]{ \tt{4 log_{4}(3100) }} \\ = { \tt{4 log_{4}(775 \times 4) }} \\ = { \tt{4 log_{4}(775) + 4 log_{4}(4) }} \\ = { \tt{4( (\frac{ log_{10}775 }{ log_{10}4 } ) +1)}} \\ = { \tt{4(4.8 + 1)}} \\ = { \tt{23.2}}[/tex]
Bonnie volunteers to bring bags of candy to her child’s class for the Halloween party this year. She buys one bag of candy A containing 150 pieces of candy, one bag of candy B containing 210 pieces of candy, and one bag of candy C containing 330 pieces of candy. She needs to use all the candy to create identical treat bags. How many treat bags can Bonnie make so that each one has the same number and variety of candy? How many of each type of candy will be in each bag?
Answers
Answer:
345 bags and would each have 2
7 8/6 = 9.3?
Please explain your answer
Answers
Answer:
7×(8/6)=9.33
Step-by-step explanation:
7 is whole number
8/6 is the fraction
8/6 is 1.333
so, 7×1.333=9.33
solve the inequality.. help me out asap plss
Answers
Answer:
[tex]x<\frac{6}{5}[/tex]
Refer to picture for number line
Step-by-step explanation:
To solve this inequality, we want to isolate the variable. We can do this my getting like terms onto one side
[tex]6x-7<2-\frac{3x}{2}[/tex] [add both sides by 7]
[tex]6x<9-\frac{3x}{2}[/tex] [add both sides by 3x/2]
[tex]6x+\frac{3x}{2}<9[/tex] [multiply both sides by 2]
[tex]12x+3x<18[/tex] [add]
[tex]15x<18[/tex] [divide both sides by 15]
[tex]x<\frac{18}{15}[/tex] [simplify]
[tex]x<\frac{6}{5}[/tex]
Now that we have out inequality, we want to graph it. Since we know that [tex]x<\frac{6}{5}[/tex], that means we have an open circle. Since x is less than, the arrow would be pointing left.
In an effort to cut costs and improve profits, any US companies have been turning to outsourcing. In fact, according to Purchasing magazine, 54% of companies surveyed outsourced some part of their manufacturing process in the past two to three years. Suppose 555 of these companies are contacted.
Required:
a. What is the probability that 338 or more companies outsourced some part of their manufacturing process in the past two or three years? Write your answer as a percentage rounded to two decimal places.
b. What is the probability that 285 or more companies outsourced some part of their manufacturing process in the past two or three years? Write your answer as a percentage rounded to two decimal places.
c. What is the probability that 48% or less of these companies outsourced some part of their manufacturing process in the past two or three years? Write your answer as a percentage rounded to two decimal places.
Answers
Answer:
a) 0.06% probability that 338 or more companies outsourced some part of their manufacturing process in the past two or three years.
b) 90.15% probability that 285 or more companies outsourced some part of their manufacturing process in the past two or three years.
c) 0.23% probability that 48% or less of these companies outsourced some part of their manufacturing process in the past two or three years.
Step-by-step explanation:
For questions a and b, the normal approximation to the binomial is used, while for question c, the central limit theorem is used.
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Normal probability distribution
Problems of normally distributed distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
54% of companies surveyed outsourced some part of their manufacturing process in the past two to three years.
This means that [tex]p = 0.54[/tex]
555 of these companies are contacted.
This means that [tex]n = 555[/tex]
Mean and standard deviation: Normal approximation to the binomial:
[tex]\mu = E(X) = np = 555*0.54 = 299.7[/tex]
[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{555*0.54*0.46} = 11.74[/tex]
a. What is the probability that 338 or more companies outsourced some part of their manufacturing process in the past two or three years?
Using continuity correction, this is [tex]P(X \geq 338 - 0.5) = P(X \geq 337.5)[/tex], which is 1 subtracted by the p-value of Z when X = 337.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{337.5 - 299.7}{11.74}[/tex]
[tex]Z = 3.22[/tex]
[tex]Z = 3.22[/tex] has a p-value of 0.9994.
1 - 0.9994 = 0.0006
0.0006*100% = 0.06%
0.06% probability that 338 or more companies outsourced some part of their manufacturing process in the past two or three years.
b. What is the probability that 285 or more companies outsourced some part of their manufacturing process in the past two or three years?
Using continuity correction, this is [tex]P(X \geq 285 - 0.5) = P(X \geq 284.5)[/tex], which is 1 subtracted by the p-value of Z when X = 284.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{284.5 - 299.7}{11.74}[/tex]
[tex]Z = -1.29[/tex]
[tex]Z = -1.29[/tex] has a p-value of 0.0985.
1 - 0.0985 = 0.9015
0.9015*100% = 90.15%
90.15% probability that 285 or more companies outsourced some part of their manufacturing process in the past two or three years.
c. What is the probability that 48% or less of these companies outsourced some part of their manufacturing process in the past two or three years?
Now we use the sampling distribution of the sample proportions, which have:
[tex]\mu = p = 0.54[/tex]
[tex]s = \sqrt{\frac{0.54*0.46}{555}} = 0.0212[/tex]
The probability is the p-value of Z when X = 0.48. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.48 - 0.54}{0.0212}[/tex]
[tex]Z = -2.84[/tex]
[tex]Z = -2.84[/tex] has a p-value of 0.0023.
0.0023*100% = 0.23%
0.23% probability that 48% or less of these companies outsourced some part of their manufacturing process in the past two or three years.
Which of these shapes have the same area?
Answers
Answer:
wheres the picture?
Step-by-step explanation:
Suppose an annuity pays 6% annual interest, compounded semi-annually. You invest in this annuity by contributing $4,500 semiannually for 6 years. What will the annuity be worth after 6 years?
Answers
Answer:
$3240
Step-by-step explanation:
hope it is well understood
Answer: 59300
Step-by-step explanation:
A passenger car will go 455 miles on 17.5 gallons of gasoline in city driving what is the rate in miles per gallon ?
Answers
Answer:
26 gallons
Step-by-step explanation:
Take the miles and divide by the gallons
455 miles / 17.5 gallons
26 miles per gallon
Find the midpoint of the line segment with endpoints (7, -12) and (-5, -15).
Answers
Answer:
The midpoint is (1,-13.5)
Step-by-step explanation:
To find the x coordinate of the midpoint, add the x coordinates of the endpoints and divide by 2
(7+-5) /2 = 2/2 =1
To find the y coordinate of the midpoint, add the y coordinates of the endpoints and divide by 2
(-12+-15) /2 = -27/2 =-13.5
The midpoint is (1,-13.5)
Midpoint formula
(X1+x2/2, y1+y2/2)
PLEASE HELP AND BE CORRECT BEFORE ANSWERING
Answers
9514 1404 393
Answer:
3
Step-by-step explanation:
The length of A'B' is 3 units.
The length of AB is 1 unit.
The scale factor is A'B'/AB = 3/1 = 3.
5x³y³z³×6a³x³z²
Find the product
Answers
I need help solving this problem
Answers
Answer:
300
Step-by-step explanation:
The shiny silver mouse has a population mean size of 8.3 cm and and a population standard deviation of 1.2 cm. If one individual is sampled from the population what is the probability that it will be greater than 9 cm
Answers
Answer:
41.67%
Step-by-step explanation:
[tex]Z = \frac{x-\alpha}{\sigma}[/tex] 9-8.3 = 0.7/1.2 = 0.5833 1-0.5833 = 0.4167*10 = 41.67%
The probability of the individual sample which is greater then 9 cm is 0.2799601 .
What is probability?
'Probability is the extent to which an event is likely to occur, measured by the ratio of the favorable cases to the total number of cases possible.'
According to the given problem,
μ = 8.3 cm
σ = 1.2 cm
X ≈ N[tex](0,1)P(X < x )[/tex]
= P(Z = X - μ / σ)
here , X ≈ N (8.3 , [tex](1.2)^2)P(X > 9)[/tex]
= P[tex](Z > \frac{9-8.3}{1.2})[/tex]
⇒ P[tex](Z>0.583333)[/tex]
⇒ 1 - P[tex](Z<0.583333)[/tex]
⇒ 1 - 0.7200399 [ for greater surface area of the bell-curve ]
⇒ 0.2799601
Hence, we can conclude, the probability of individual sample is 0.2799601 .
Learn more about the probability here :brainly.com/question/23211929?#SPJ2
