Please help me ASAP help

Answer:

No, because they are parallel.

Step-by-step explanation:

The lines [tex]p[/tex] and [tex]m[/tex] will not intersect, so Kevin is not correct.

It is given that planes A and B intersects. The plane A contains the line p, m and n on its plane. The lines p and m are parallel to each other. They are identical and move in the same direction.

Since the line p and m are parallel, they will not meet each other at any point because parallel lines does not intersect or meet at a point, they run parallelly along each other.

So, line p and m will not intersect.

Thus the answer is " No, because they are parallel."

Answer:

Step-by-step explanation:

no, because they are parrallel.

Answer:

I don't think so

Step-by-step explanation:

the length of the newspaper page=36cm

the advert will take 1/3 of the page=1/3*36=12

so the advert takes12 cm and he says it has to be 11 cm which is not right .

I hope this helps

Answer:

The correct answer of this question is( larger)

may this answer is helpful for you

Answer:

[tex]\frac{2(x+3)}{x+7}[/tex]

Step-by-step explanation:

Given

[tex]\frac{2x^2-18}{x^2+4x-21}[/tex] ← factorise numerator and denominator

2x² - 18 ( factor out 2 from each term )

= 2(x² - 9) ← difference of 2 squares

= 2(x - 3)(x + 3)

and

x² + 4x - 21 = (x + 7)(x - 3) , then

= [tex]\frac{2(x-3)(x+3)}{(x+7)(x-3)}[/tex] ← cancel common factor (x - 3) on numerator/ denominator

= [tex]\frac{2(x+3)}{x+7}[/tex]

Step-by-step explanation:

B ) |-12| < |-48|

because the signs are not taken on to consideration if we write in |

so hence B is right option

MARK AS BRAINLIST IF IT IS USEFUL

Answer:

4x² - 5x - 8 = 0

Step-by-step explanation:

Standard form of a quadratic: ax² + bx + c

Move all terms to one side and sort them based on the level of degree:

[tex]4x^2-9x-8=-4x\\4x^2-9x+4x-8=0\\4x^2-5x-8=0[/tex]

Answer:

4x^2 -5x-8 =0

Step-by-step explanation:

ax^2 + bx + c = 0 is the standard form

4x^2 -9x-8 =-4x

Add 4x to each side

4x^2 -9x+4x-8 =-4x+4x

4x^2 -5x-8 =0

Use main properties of powers

(a^m)^n=a^{m\cdot n};(am)n=am⋅n;

\dfrac{1}{a^n}=a^{-n}an1=a−n

to simplify given equation.

1.

4^x=(2^2)^x=2^{2x}.4x=(22)x=22x.

2.

\left(\dfrac{1}{8}\right)^{x+5}=\left(\dfrac{1}{2^3}\right)^{x+5}=(2^{-3})^{x+5}=2^{-3x-15}.(81)x+5=(231)x+5=(2−3)x+5=2−3x−15.

3. Then the equation is

2^{2x}=2^{-3x-15}.22x=2−3x−15.

The bases are the same, so equate the powers:

2x=-3x-15,

2x+3x=-15,

5x=-15,

x=-3.

Answer: for x=-3.

Answer:

5.6 km/hr 8500 n

so 1 km/hr 1517.857 n

Step-by-step explanation:

Answer:

x = 100

Step-by-step explanation:

(100-40)/2

= 60/2

= 30

So it's 100

Answered by GAUTHMATH

Answer:

see below

Step-by-step explanation:

take f(x)=5x-6, which is y=5x-6

switch the y for x and x for y and you get

x=5y-6

then add 6 on both sides and you get

x+6=5y

now divide both sides by 5 and you get

y=(x+6)/5

which is the inverse of the original function

Answer:

Solution given:

f(x)=5x-6

let f(x)=y

we get

y=5x-6

Interchanging role of x and y

x=5y-6

x+6=5y

y=[tex]\bold{\frac{x+6}{5}}[/tex]

so

f-¹=[tex]\bold{\frac{x+6}{5}}[/tex]

shown

Answer: D) 20/21

Explanation:

Recall that sin(theta) = opposite/hypotenuse.

sin(theta) = 20/29 tells us that 20 is the vertical side while 29 is the hypotenuse. Note how the vertical side is opposite the reference angle theta.

Use these two sides to find that the missing side is 21. You'll need the pythagorean theorem a^2+b^2 = c^2.

Once you determine that the adjacent side is 21 units long, we can then say,

tan(theta) = opposite/adjacent = 20/21

Answer:

D. 20/21

Step-by-step explanation:

9514 1404 393

Answer:

  x = (√2)/2

Step-by-step explanation:

The diagonal is √2 times the side length (x), so ...

  1 = x√2

  √2 = 2x . . . . . multiply by √2

  (√2)/2 = x . . . . divide by 2

The side length x is (√2)/2.

Answer:

HCF is 4

LCM is 336

Step-by-step explanation:

2/28 , 48

2/14 , 24

2/7 , 12

2/7 , 6

3/7 , 3

7/7 , 1

1 , 1

HCF is 2 × 2 =4

LCM is 2 × 2 × 2 × 2 × 3 × 7 = 336

Answer:

x=24 y=33

Step-by-step explanation:

If a diameter or radius is perpendicular to a chord, then it bisects the chord and its arc.

Answer:

h = 256 feet

Step-by-step explanation:

Given that,

The initial velocity of firework, v = 128 ft/s

The acceleration due to gravity is-16 ft/s².

We need to find the maximum height reached by the firework.

The equation for the firework is :

[tex]h(t) = -16t^2 + 128t[/tex]

To find the vertex's x-coordinate, we can use  

[tex]t=\dfrac{-b}{2a}\\\\t=\dfrac{-128}{2\times (-16)}\\\\t=4\ s[/tex]

Put all the values in the expression for h (t).

[tex]h(t) = -16(4)^2 + 128(4)\\\\h(t)=256\ ft[/tex]

So, the maximum height reached by the firework is 256 feet.

Answer:

I think Substitution

Step-by-step explanation:

Because x is already solved for in the second equation.

Answer:

-irrational

-rational

-rational

-irrational

__________________________________________________________quick and easy way is to see if the squares are perfect squares, like square root seven is irrational, so the answer is irrational. square root 9 is 3, which is rational, so its rational.

brainliest is appreciated :)

Answer:

{ -2,-1,0,1}

Step-by-step explanation:

The domain are the values for the input

Domain { -2,-1,0,1}

Answer:

x = 17

Step-by-step explanation:

-2x + 8 = -26

Subtract 8 from each side

-2x + 8-8 = -26-8

-2x = -34

Divide each side by -2

-2x/-2 = -34/-2

x = 17

Answer:

The answer is x=17

Step-by-step explanation:

−2x+8−8=−26−8

−2x=−34

−2x /−2 = −34 /−2

x=17

Perimeter simply represents the sum of all side lengths of a shape. The length of the missing side of the ticket is 5 cm; the length of gold line on each ticket is 20 cm, and 2 bottles of gold ink are required to draw gold lines on 200 tickets.

I've added the image of the ticket as an attachment.

(a) The missing side length

From the attachment, the 4 unknown side lengths are equal. Represent this side length with L.

So, we have:

[tex]Perimeter =2\times 11 + 4 \times L[/tex]

This gives

[tex]2\times11 + 4 \times L = 42[/tex]

[tex]22 + 4 \times L = 42[/tex]

Collect like terms

[tex]4 \times L = 42-22[/tex]

[tex]4 \times L = 20[/tex]

Divide both sides by 4

[tex]L =5cm[/tex]

(b) The length of the gold lines

There are 4 slant lines and the length of one of the slant lines is 5 cm (as calculated above).

So, the length of the gold line is:

[tex]Gold = 4 \times L[/tex]

[tex]Gold = 4 \times 5cm[/tex]

[tex]Gold = 20cm[/tex]

(c) The number of gold ink bottles.

[tex]n = 200[/tex] --- number of tickets

The length of all gold line in the 200 tickets is:

[tex]Length = 200 \times Gold[/tex]

[tex]Length = 200 \times 20cm[/tex]

[tex]Length = 4000 cm[/tex]

[tex]Length = 4000 \times 0.01m[/tex] ---- convert to meters

[tex]Length = 40m[/tex]

Given that:

[tex]Bottle = 20m[/tex] --- 1 bottle for 20 m

The number of bottles (n) is:

[tex]n = \frac{Length}{Bottles}[/tex]

[tex]n = \frac{40m}{20m}[/tex]

[tex]n = 2[/tex]

Hence, 2 bottles of gold ink are enough.

Read more about perimeters at:

https://brainly.com/question/6465134

Answer:

You ordered 5 tickets for a show on line...

The cost was $5 a ticket Plus a one time ordering fee of $15.

you total cost was $45 ....

Solving for x will determine the cost of one ticket

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

a taxi charges $5 a mile plus $15 "pull fee" ...

you ride cost a total of $45 ... x is the number of miles that you got driven

Step-by-step explanation:

You rent a car for a down payment of $15 and $5 is charged per mile driven. The total charge is therefore, $45. In essence, x is the no. of miles driven.

According to the question;

In essence, x is the no. of miles driven in this scenario.

By solving for x in 5x + 15 = 45, we may determine the no. of miles driven.

Read more:

https://brainly.com/question/2319353

Answer:

pagal man

Step-by-step explanation:

tumko Answer Nahi Aata Padhte Likhte Nahi hoo kya

Answer:

I assume you'd already figured out the other questions so you just don't understand the question E

Step-by-step explanation:

The product of the first 2 numbers its stating is -28 and 48, and it's asking if the product (multiply -28 by 48 to get the product) is equal to the HCF and LCM you got in the previous answer.

Answer:

The proportion of the pooled samples is 0.54.

Step-by-step explanation:

We have that:

70% of men own cats.

The proportion of men in the sample is:

[tex]\frac{170}{170+190} = 0.4722[/tex]

40% of women own cats.

The proportion of women in the sample is: 1 - 0.4722 = 0.5278

Proportion of the pooled samples

[tex]p = 0.7*0.4722 + 0.4*0.5278 = 0.54[/tex]

The proportion of the pooled samples is 0.54.

Answer:

x = 1, x = 2

Step-by-step explanation:

Given

3x(x - 2) = x² - 4 ← distribute parenthesis on left side

3x² - 6x = x² - 4 ( subtract x² - 4 from both sides )

2x² - 6x + 4 = 0 ( divide through by 2

x² - 3x + 2 = 0 ← in standard form

Consider the factors of the constant term (+ 2) which sum to give the coefficient of the x- term (- 3)

The factors are - 1 and - 2 , since

- 1 × - 2 = + 2 and - 1 - 2 = - 3 , then

(x - 1)(x - 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x - 2 = 0 ⇒ x = 2

Step-by-step explanation:

Hi there!

According to the question;

The sum of two number is 59. And the Smaller number is less than the bigger one by 7,

Let the bigger number be "X" then smaller number will be x-7.

Then;

x + (x-7) = 59

2x = 59+7

X = 66/2

Therefore, the bigger number (X) is 33 and smaller number (x-7) is 26.

Hope it helps!

Answer: [tex]7.48\ cm[/tex]

Step-by-step explanation:

Given

The equal side of two isosceles triangle are [tex]9\ cm[/tex] long

Base of the triangle is [tex]10\ cm[/tex] long

Median divides the base into two equal halves

from the figure, it can be written

[tex]\Rightarrow 9^2=5^2+h^2\\\Rightarrow h^2=9^2-5^2\\\Rightarrow h=\sqrt{81-25}\\\Rightarrow h=\sqrt{56}\\\Rightarrow h=7.48\ cm[/tex]

The length of the segment is [tex]7.48\ cm[/tex]

Answer:

Step-by-step explanation:

Nearest thousandth = 5693.251

Nearest tenths = 5693.3

[tex]\\ \sf\longmapsto b^2x^2+a^2y^2[/tex]

[tex]\\ \sf\longmapsto b^2(asin\Theta)^2+a^2(bcos\Theta)^2[/tex]

[tex]\\ \sf\longmapsto b^2a^2sin^2\Theta+a^2b^2cos^2\Theta[/tex]

[tex]\\ \sf\longmapsto a^2b^2(sin^2\Theta+cos^2Theta)[/tex]

[tex]\\ \sf\longmapsto a^2+b^2(1)[/tex]

[tex]\\ \sf\longmapsto a^2b^2[/tex]