please help me guys never mind the calculations ​

Answer:

A

Explanation:

i think a is the answer because if you take an example of group 1 and 2 metals on the periodic table you will notice that they are highly reactive but they have a few electrons in their outer most shells.

I hope this helps

Answer:

simple machine, any of several devices with few or no moving parts that are used to modify motion and the magnitude of a force in order to perform work. ... The simple machines are the inclined plane, lever, wedge, wheel and axle, pulley, and screw.

Answer:

6.34×10⁹ seconds

Explanation:

Applying,

V = d/t............. Equation 1

Where V = speed plate, d =  distance covered by the plate, t = time it takes the plate to travel

make t the subject of the equation

t = d/V............ Equation 2

From the question,

Given: d = 5 cm/yr = (5×3.154×10⁻⁹) = 1.577×10⁻⁸ m/s,  d = 100 meter

Substitute these values into equation 2

t = 100/1.577×10⁻⁸

t = 6.34×10⁹ seconds

Hence the time it takes the the plate to travel is 6.34×10⁹ seconds

Let m be the mass of both cubes. If the smaller cube has side length x, then its volume is x ³. The side lengths of the larger cube have length 4x, so the larger cube's volume is (4x)³ = 64x ³, or 64 times as large as the smaller cube.

The first cube has a density of m/x ³, while the larger one has a density of m/(64x ³) = 1/64 m/x ³, so the ratio of densities is (1/64):1, or 1:64 (larger cube to smaller cube).

Answer:

may be d)45°

Explanation:

Part A - The apparent displacement of the mark is 4 cm.

The refractive index of a material, n = real depth, D/apparent depth, L.

So, n = D/L

Since the refractive index of the triangular glass prism is 1.5, n = 1.5. Also, the triangular glass prism is 12 cm thick and placed on a mark on a piece of paper resting on a horizontal bench. So, the real depth of the mark on the piece of paper through the triangular prism is D = 12 cm and its apparent depth is L.

Since n = D/L,

making L, subject of the formula, we have

L = D/n

Substituting the values of the variables into the equation, we have

L = D/n

L = 12 cm/1.5

L = 8 cm

so, the apparent depth of the mark is 8 cm.

So, the apparent displacement of the mark is d = D - L = 12 cm - 8 cm = 4 cm

Thus the apparent displacement of the mark is 4 cm.

Part B - The refractive index of water, n = 1.33.

The refractive index of a material, n = real depth, D/apparent depth, L.

So, n = D/L

Since the depth of water in the jar is 24 cm, the real depth, D = 24 cm.

Also, the bottom of the jar appears to be raised by 6 cm. So, the apparent depth, L = 24 cm - 6 cm = 18 cm

Since n = D/L, the refractive index of water n = D/L

Substituting the values of the variables into the equation, we have

n = D/L

= 24 cm/18 cm

= 1.33

So, the refractive index of water, n = 1.33.

Learn more about refractive index here:

https://brainly.com/question/12768121

Answer:

distance between should be 1.25 × 10^6 m

Explanation:

Force is proportional to separation distance.

[tex]250 \: newtons = 2.5 \times {10}^{6} \: metres \\ ( \frac{1}{2} \times 250) \: newtons = d \\ \\ d = \frac{125 \times 2.5 \times {10}^{6} }{250} \\ d = 1.25 \times {10}^{6} \: metres[/tex]

Answer:

distance between should be 1.25×10^6.

Explanation:

force Is proportional to separation .

mrk above answer branilest .

Answer:

The answer is "[tex]1.2566 \times 10^{-5}\,rad[/tex]".

Explanation:

As per the Rayleigh Criterion the minimum angular spreading, for a circular aperture:

[tex]\theta_{\mathrm{min}}\approx \sin\theta=1.22\,\frac{\lambda}{d}[/tex]  

[tex]\theta_{\mathrm{min}}=\mathrm{1.22\,\frac{\left( 610\,nm \right)}{\left( 5.90\,cm \right)}=1.22\,\frac{\left( 610\times10^{-9}\,m \right)}{\left( 5.90\times10^{-2}\,m \right)}}[/tex]

                               [tex]=1.22\times 103.389 \times 10^{-7}\\\\=1.22\times 1.03 \times 10^{-5}\\\\=\mathrm{1.2566 \times 10^{-5}\,rad}[/tex]

Explanation:

tilting it will raise the height of its center of gravity.

Answer:

Explanation:

F = ma, so filling in:

15000 = 30000a and

a = .50 m/s/s

The acceleration of a train is 0.50 [tex]m/s^{2}[/tex].

Acceleration is the rate of change of the velocity of an object with respect to time.

F = ma

a = F/m

a = 15000/30000

a = 0.50 [tex]m/s^{2}[/tex]

To learn more about Acceleration here

https://brainly.com/question/12550364

#SPJ2

Explanation:

Density is mass in grams over volume in cubic centimeters.

So it is

[tex]\frac{4g}{5cm^{-3} }[/tex]  =  0.8 g/cm[tex]^{3}[/tex]  

The unit is grams per cubic centimeter.

NB - density can also be kilograms over cubic meters

Answer:

I don't even know can u tell me how to ask questions

Answer:

The height of the wave is determined by the wind strength and fetch.

Explanation:

The height of the wave is determined by the wind strength and fetch.

The more the strength and the more the fetch size the more will be the height of the wave.

Remember as the wave approaches the coast its wavelength decreases and the wave height increases, whereas when the wave goes away from the coast its wavelength increases and height decreases.

Answer:

(B)

Explanation:

the boy will fall away from the bus if the bus is moving.

Answer:

Weight = Mass × Gravitational field strength

Explanation:

The mass of the skydiver = 70 kg

The weight of the skydiver, W, is given as follows;

W = m × g

Where-

g = The gravitational field strength ≈ 9.81 m/s²

Therefore, the equation linking weight mass and gravitational field strength is presented as follows;

Weight = Mass × Gravitational field strength

The answer to the digits rounded to one significant figure is 100.

Significant figures are the most important figures in a number of digits.

The closer a digit is to the beginning of a number, the more important  or significant  it is.

But, the rule for rounding up a set of numbers to the first significant or to one significant figure is that:

From the numbers 98.907, 9 is the most significant digit followed by 8.

8 is greater than 5 so we should round up by adding one to 9 making the number 100.

learn more here:

https://brainly.com/question/11566364

Answer: a =0

Explanation:

Answer:

dog

Explanation:

Answer:

Explanation:

We are basically needing to solve for the time in the equation d = rt, where d is the distance around Mars (aka the circumference), r is the velocity, and t is time. We need to find the circumference and the velocity. We will begin with the velocity.

Because the gravitational attraction between Phobos and Mars provides the centripetal acceleration necessary to keep Phobos in its (sort of) circular path, the equation we use for this is:

[tex]F_g=F_c[/tex] which says that Force supplied by gravity is equal to the centripetal force. Expanding that:

[tex]\frac{Gm_{Phobos}m_{Mars}}{r^2}=\frac{m_{Phobos}v^2}{r}[/tex]

When we move that around mathematically to solve for the velocity value, what we end up with is:

[tex]v=\sqrt{\frac{Gm_{Mars}}{r}[/tex] and filling in:

[tex]v=\sqrt{\frac{(6.67*10^{-11})(6.42*10^{23})}{9.38*10^6} }[/tex] and we get that

v = 2100 m/s

Now for the circumference:

C = 2πr and

C = 2(3.1415)(9.38 × 10⁶) so

C = 5.9 × 10⁷

Putting that all together in the C = vT equation:

5.9 × 10⁷ = 2100T so

T = 2.8 × 10⁴ sec or 7.8 hours

Answer:

Explanation:

Suppose you have 3 resistors each with a value of 3. If you placed them in parallel, would you get 3

1/3 + 1/3 + 1/3 = 1/r

The denominator doesn't change. So add the numerators.

(1 + 1 + 1)/3 = 3/3 = 1

So the question is faulty.

1 = 1/r

1*r = 1

r = 1/1

r = 1

Answer:

not sure just need points

Explanation:

a+b+c

We know

[tex]\boxed{\sf K.E=\dfrac{1}{2}mv^2}[/tex]

[tex]\\ \sf\longmapsto K.E=\dfrac{1}{2}\times 2\times 40^2[/tex]

[tex]\\ \sf\longmapsto K.E=40^2[/tex]

[tex]\\ \sf\longmapsto K.E=1600J[/tex]

Answer:

250 Pa or N/m^2

Explanation:

Pressure(P)=F/A=500/2=250 Pa or N/m^2

Answer:

La materia es la sustancia de la que está hecho todo material. En física, el sistema es una de las propiedades de la materia. Se puede transferir entre objetos y convertir en forma. No se puede crear ni destruir.

espero que te ayude!

Answer:

75°C

Explanation:

175−25/225−25=x−0/100−0

150/200=x/100

x=150×100/200

= 75°C

Assuming the applied force is exerted parallel to the floor, by Newton's second law both the net vertical and net horizontal forces would be zero:

∑ F (horizontal) = p - f = 0 … … … because the desk is pushed at a constant speed

∑ F (vertical) = n - mg = 0 … … … because the desk doesn't move up or down

where p is the magnitude of the applied force, f is the mag. of kinetic friction, n is the mag. of the normal force due to contact between the floor and desk, and mg is the weight of the desk. We have

n = mg = (100 kg) g = 980 N

and the mag. of friction is proportional to n according to

f = 0.4 n = 392 N

Then the applied force p has magnitude

p = f = 392 N

Answer:It has 8550 j energy

When,a man stands still on a moving walkway that is going at a speed of 0.2 m/s to the west,then the velocity of the man according to a stationary observer would be 0.2 m/s west,Therefore, the correct answer would be option B.

The total displacement covered by any object per unit of time is known as velocity. The velocity of an object is depend on the magnitude as well as the direction of the object.

the mathematical expression for velocity is given by

velocity = total displacement /time

The speed and velocity of the object are very different from each other because speed does not depend upon the direction of the moving  object but velocity depends on the magnitude of speed as well as the direction of the moving object.

As per given in the problem a man stands still on a moving walkway that is going at a speed of 0.2 m/s to the west therefore from the perspective  of a stationary observer the velocity of man would be 0.2 m/s towards West.

Hence the correct options for the problem would be option B.

Learn more about Velocity from here

brainly.com/question/18084516

#SPJ2

Explanation:

The explosives changes Gerald the Human Cannonball and provides him with chemical energy.

Sulfur and carbon serve as fuels, whereas saltpetre serves as an oxidant. Gunpowder has long been employed as a propellant in weapons, artillery, rocketry, and fireworks, as well as a blasting ingredient in quarrying, mine, and road construction.