Please help me with this

Answer:

Hope you find it helpful and usef

Given:

Kendra charges $8.00 for two puzzles and a piece of candy.

She charges $4.50 for one puzzle and a piece of candy.

To find:

The cost of each puzzle.

Solution:

Let x be the cost of a puzzle and y be the cost of piece of candy.

Kendra charges $8.00 for two puzzles and a piece of candy.

[tex]2x+y=8[/tex]               ...(i)

She charges $4.50 for one puzzle and a piece of candy.

[tex]x+y=4.50[/tex]             ...(ii)

Subtracting (ii) from (i), we get

[tex]2x+y-(x+y)=8-4.50[/tex]

[tex]2x+y-x-y=3.50[/tex]

[tex]x=3.50[/tex]

The cost of puzzle is $3.50. Therefore, the correct option is A.

Answer:

y = x + 4

Step-by-step explanation:

y = mx + b

y = 1x + b

5 = 1 + b

b = 4

y = x + 4

Answer:

Following are the responses to the given question:

Step-by-step explanation:

For point a:

Following are the null and alternative hypotheses:

[tex]H_0 : \mu_1 \leq \mu_2\\\\H_1 : \mu_1 > \mu_2[/tex]

For point b:

By using the Excel we obtained the output of the 2 sample t-test that is defined in the attached file.  

These point estimately are the difference among the mean for the two populations:

[tex]\to \mu_{\bar{x_1}-\bar{x_2}} = \mu_{\bar{x_1}}-\mu{\bar{x_2}} ={\bar{x_1}-\bar{x_2}}=573-491=82[/tex]

Answer:

345

Step-by-step explanation:

The velocity of a car over five hours is given by:

[tex]\displaystyle v(t)=60\ln(t+1),\, 0 \leq t \leq 5[/tex]

And we want to find the total distance traveled from t = 0 to t = 5.

Recall that distance is the integral of the absolute value of the velocity function. Since we want to find the total distance traveled from t = 0 to t = 5, our limits of integration are t = 0 and t = 5. Hence:

[tex]\displaystyle D=\int_0^5 |\underbrace{60\ln(t+1)}_{v(t)}|\, dt[/tex]

Since v(t) ≥ 0 for all t in the interval [1, 5], we can remove the absolute value. Use a calculator:

[tex]\displaystyle D=60\left(6\ln(6)-5)=345.0334...\approx 345[/tex]

Answer:

x = 2/3

Step-by-step explanation:

-3x + 4 = 2

-3x = -2

x = 2/3

y = 2

(plug it into original equation)

(2/3. 2)

Ax

B

Step-by-step explanation:

.....

...

..

Answer:

The plotting are correct .

HOPE IT HELPED!!

Answer:

The surface area is 116.

Step-by-step explanation:

Answer:

r = 30°

Step-by-step explanation:

According to the Exterior Angle Sum Theorem, the exterior angle, which is 90°, is equal to the 2 interior angles, which are 60° and r°. We know that the angle next to the exterior angle is 90°, and since all angle sums add up to 180°, r = 30°.

The three inside angles of a triangle equal 180.

Subtract the two known angles from 180.

180 - 118.6 - 42.3 = 19.1

The third angle is 19.1

Answer:

281 different committees can be formed if the number of boys is more than the number of girls​.

Step-by-step explanation:

The order in which the people are chosen to the committee is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

Number of boys more than the number of girls:

3, 4 or 5 boys.

3 boys:

3 boys from a set of 6.

2 girls from a set of 5. So

[tex]C_{6,3}C_{5,2} = \frac{6!}{3!3!} \times \frac{5!}{2!3!} = 200[/tex]

4 boys:

4 boys from a set of 6.

1 girl from a set of 5. So

[tex]C_{6,4}C_{5,1} = \frac{6!}{4!2!} \times \frac{5!}{1!4!} = 75[/tex]

5 boys:

5 boys from a set of 6. So

[tex]C_{6,5} = \frac{6!}{5!1!} = 6[/tex]

Total:

200 + 75 + 6 = 281

281 different committees can be formed if the number of boys is more than the number of girls​.

Answer:

9 possible values of length and breadth.

Step-by-step explanation:

Given that the area of the rectangle is 18cm² . And the lengths of the sides are whole numbers. We need to tell the possible dimensions of the rectangle .

Let :-

[tex]\rm\implies Length = x [/tex]

[tex]\rm\implies Breadth = y [/tex]

We know that :-

[tex]\rm\implies Area = length \times breadth [/tex]

[tex]\rm\implies Area = x y \\\\\rm\implies xy = 18cm^2 [/tex]

Now look out for the possible factors of 18 . That is , ( 1 × 18 ) , ( 2 × 9) , ( 3 × 6 ) , ( 6 × 3 ) , ( 9 × 2 ) , (18 × 1 ) . That is total 9 possible values .

Answer:

x + y = -12

Step-by-step explanation:

x - y = 2

2x – 3y = 11

-2x +2y = -4

2x – 3y = 11

-y = 7

y  = -7

x = -5

x + y = -12

Answer:

A. 55%

Step-by-step explanation:

First we should make these into fractions

A. 33/60

B. 36/78

C. 40/89

D. 24/59

these are the fractions, The question wants us to pick the Park with the Greatest Percentage, Not The Greatest Amount, so Lets look at these fractions A. 33/60 Is 55%   B. 36/78 is  46% .   C. 40/89 is 44%   D. 24/59 is about 40%

I also remember doing this on a quiz!!

Answer:

See figure below.

Step-by-step explanation:

See the figure below.

Answer:

The inequality form is -4<x<-2

The Interval Notation is (-4, -2]

I hope this helps!

Answer:

y < -7

Step-by-step explanation:

You balance it like a normal equation:

8y + 3 > 15y + 52

8y + 3 (-8y) > 15y + 52 (-8y)

3 (-52) > 7y + 52 (-52)

-49 (÷7) > 7y (÷7)

y < -7

Answer:

0.4 or 0.40

Step-by-step explanation:

There are 10 total numbers. 4 of them are in set B.

So, 4/10 are in set B.

The probability is 0.4 because 4 divided by 10 is 0.4.

Answer:

y=n^2+3n+4

Step-by-step explanation:

Sequence,S: 8,14,22,32 ,44, 58, 74...

First differences of S: 6,8,10,12,14,16,...

Second differences of S: 2,2,2,2,2,2,....

It is indeed a quadratic since the 1st differences that are the same are the second differences.

So the 1st term is 8. If the 0th term was listes it would be 4 since 8-4=4 and 6-4=2.

This means our quadratic it is in the form

y=an^2+bn+c where c=4.

So we have y=an^2+bn+4.

Now we can find a and b using two points from our sequence to form a system of equations to solve.

(1,8) gives us 8=a(1)^2+b(1)+4

Simplifying gives 8=a+b+4

Subtracting 4 on both sides gives: 4=a+b

(2,14) gives us 14=a(2)^2+b(2)+4

Simplifying gives 14=4a+2b+4

Subtracting 4 on both sides gives 10=4a+2b

So we have the following system to solve:

4=a+b

10=4a+2b

I'm going to solve using elimination/linear combination style.

Dividing second equation by 2 gives the system as:

4=a+b

5=2a+b

Subtract the 2nd equation from the first gives:

-1=-1a

This implies a=1 since -1=-1(1) is true.

If a+b=4 and a=1, then b=3. Because 3+1=4.

So the equation is y=1n^2+3n+4 or y=n^2+3n+4.

Answer:

(8,2.40)

Step-by-step explanation:

Step-by-step explanation:

C. represent the number line for x

where x ix

Answer:

30 ,,,,,,,, I hope it's helpful for you

3 text messages = 5 cents

So,

1 text messages

= 5 cents/3

= 5/3 cents

So,

150 text messages

= 150 × (5/3 cents)

= 50 × 5 cents

= 250 cents

Answer:

Step-by-step explanation:

( 2 , 3 ) , ( 6 , - 5) , ( - 1 , 3 ) - is a function

( 1 , 9 ) , ( -3 , - 2 ) , ( 1 , - 4 )  - is a function

( 7 , - 4 ) , ( 0 , 9 ) ,  ( 2 , - 2 ) - is a  function

( 0 , 3 ) , ( 0 , 7 ) , ( 4 , 0 ) - is a function

( -6 , 5 ) , ( -5 , 6 ) , ( 8 , 2 ) - is a function

Answer:

the horizontal are called x-axis, while the vertical are called y-axis

Answer:

y=0

Step-by-step explanation:

Rewrite Evaluate Powers:

3[tex]3^{2y-1}+3^{-1}+2*3^{y}*3^{-1}=1[/tex]

Calculate:

[tex](3^{y})^{2}*\frac{1}{3} +2*3^{y}*\frac{1}{3}=1[/tex]

Solve using substitution:

[tex](3^{y})^{2}*\frac{1}{3} +\frac{2}{3} *3^{y}=1[/tex]     [tex]t=3^{y}[/tex]

Solve the equation for t:

[tex]t^{2}*\frac{1}{3}+\frac{2}{3}t=1[/tex]

t=-3

t=1

Substitute back to t=3^y

3^y=-3

3^y=1

y∉R

[tex]3^{y}=1[/tex]

y=0

Answer:

A

Step-by-step explanation:

slope=(1-0)/(5-4)=1

eq. of line through (4,0) with slope 1 is

y-0=1(x-4)

put y=f(x)

f(x)=x-4

Given :-

To Find :-

Solution :-

We know that ,

→ Distance = Speed × Time

So that ,

→ Distance = 40 km/hr × 0.5 hr

→ Distance = 40km/hr × 1/2 hr

→ Distance = 20km .

Hence the required answer is 20km .