Answer:
The car price decreased by $2,268.
The price of the car now is $33,732.
Step-by-step explanation:
Multiply 0.063 (6.3% in decimal form) by $36,000 to get $2,268, which is how much the price decreased.
Then subtract 2,268 from 36,000 to get $33,73, which is the price of the car after the decrease.
Answer:
Step-by-step explanation:
6.3 : 100 = x : 36000
x = (36000 * 6.3)/100 = $2268 (decrease in price)
Price of new model: 36000 - 2268 = $33732
P(-3,6), Q(-3,-6) and R(6,-2) are the vertices of a triangle. Calculate the perimeter of this triangle.
Answer:
33.89
Step-by-step explanation:
the side lengths are the distances between the corner points of the triangle.
P and Q have the same x value, and they therefore create a side parallel to the y-axis. and it is easy to find the length of this side : it is just the difference of the y values.
PQ = 6 - (-6) = 6 + 6 = 12
QR and RP are trickier.
we need Pythagoras to calculate the length of the direct connection between these points as the Hypotenuse of the right triangles with the differences in x and in y values as the other sides.
QR :
QR² = (-3 - 6)² + (-6 - -2)² = (-9)² + (-4)² = 81 + 16 = 97
QR = sqrt(97) ≈ 9.848857802
RP :
RP² = (6 - -3)² + (-2 - 6)² = 9² + (-8)² = 81 + 64 = 145
RP = sqrt(145) ≈ 12.04159458
the perimeter/circumference of the triangle is the sum of all 3 sides
= 12 + sqrt(97) + sqrt(145) ≈ 33.89
The probability that a certain football team wins a match is 2/3.Given that the team plays 4 matches, find the probability that the team wins 1)more than half of the number of matches played
Answer:
The probability is 32/81
Step-by-step explanation:
We know that:
The probability that the team wins is p = 2/3
Then the probability of not winning is q = 1 - p = 1 - 2/3 = 1/3
The team plays 4 matches.
We want to find the probability that the team wins 1 more than half of the number of matches played.
So if there are 4 matches, the half is 2 matches
one more than half is then 3 matches.
Let's assume that the team wins the first 3 matches, and does not win the last match.
match one, the team wins with prob: P₁ = 2/3
match two, the team wins with prob: P₂ = 2/3
match three, the team wins with prob: P₃ = 2/3
match four, the team wins with prob: P₄ = 1/3
The joint probability is the product of all the individual probabilities:
P = (2/3)*(2/3)*(2/3)*(1/3)
Now we must also considerate the permutations, we have the cases:
the team does not win the fourth match
the team does not win the third match
the team does not win the second match
the team does not win the first match
So we have just four permutations, then the total probability is:
probability = 4*P = 4*(2/3)*(2/3)*(2/3)*(1/3) = 4*(8/81) = (32/81)
Please help me lovee<3
Which best describes the relationship between the line that passes through the points (1, -6) and (3,-2) and the line
that passes through the points (4, 8) and (6, 12)?
A. parallel
B. neither perpendicular nor parallel
C. same line
D. perpendicular
B neither perpendicular nor parallel
Answer:
B
Step-by-step explanation:
B. neither perpendicular nor parallel
because, the line are not crossing nor are they aside from each other.
[tex] \frac{1.107}{123} \times \frac{1.998}{333} = [/tex]
Answer:
45Step-by-step explanation:
[tex]\frac{1.107}{123} \times \frac{1.998}{333} = [/tex]
[tex] = > 9 \times 6[/tex]
[tex] = 45[/tex]
Answer:
Step-by-step explanation:
[tex]\frac{1.107}{123}*\frac{1.998}{333}= 0.009 * 0.006 = 0.000054[/tex]
1107÷ 123 = 9
The dividend has 3 decimal places. So, take 3 decimal places from the right towards left in the result 0.009
1.107 ÷ 123 = 0.0009
0.009 * 0.006
First multiply 9 * 6 = 54
Now, count the number of decimal place in the multiplicands. 0.009 has 3 decimal places and 0.006 has 3 decimal places. So totally, 3+ 3 = 6 decimal places in the result
0.009 * 0.006 = 0.000054
Rami is solving the equation for x .
–6x – 1 = 5
–6x – 1 Empty square 1 = (5 Empty square 1)
–6x = 6
–6x Empty circle – 6 = 6 Empty circle –6
x = –1
Which operation symbols should Rami write in the Empty squareand the Empty circle?
Answer:
Empty square = +
Empty Circle = ÷
Step-by-step explanation:
In order to eliminate the extra numbers from the equation you have to do the opposite of the problem. So...
-6x-1=5
-6x -1+1 = 5+1 (eliminating the 1 from the -6x side and adding it to the other side)
-6x = 6
-6x ÷ -6 = 6 ÷ -6 ( eliminating the-6 so that one side just has x)
so... x= -1
Answer: Option B is your correct answer.
Please help…………………………
Answer:
Step-by-step explanation:
angle 2 is also 60 degree (being vertically opposite angles)
angle 3 is also 60 degree (being corresponding angles)
angle 4 is also 60 degree (being corresponding angles ) . sice angle 2 is 60 degree and relation between angle 2 and 4 is corresponding angle , angle 4 will also be 60 degree.
Show √7 , √5 on a number line.
please hurry up my cissy and oppa
Answer:
Draw the number line like in the picture.
Step-by-step explanation:
√5 is about 2.236, meaning it's kind of close to 2.25.
√7 is about 2.646, meaning it's very close to 2.625.
4. The expression (3x –8)(2x+5)-(x+1)(2x+5) can be written as the product of 2x+5
with what other binomial?
(1) 4x-7
(3) 2x-7
(2) 2x-9
(4) 4x-9
Answer:
option 3 : (2x - 7 )
Step-by-step explanation:
ax + bx = x(a+ b)
a(x+ y) + b(x+y) = (x+y)(a+b)
[tex](3x - 8 ) ( 2x + 5) - (x + 1)(2x + 5)\\\\(2x+5)[ (3x - 8) - (x+1) ][/tex] [ (2x + 5) is common is both terms ]
[tex](2x+ 5)(3x -8 -x + 1)\\\\(2x+ 5)(2x - 7)[/tex]
Therefore , the binomial is ( 2x - 7)
Rachel draws a trend line through the following data
points. Did she draw the line correctly?
Answer:
i think its A but im not sure its correct
Step-by-step explanation:
For what values of x is the expression below defined?
x +3 + x1 - x
O A. 35xs1
O B. 3 > XS-1
O C. 3 >x>1
O D. -3 sx< 1
Answer:
D. - 3 ≤ x < 1
Step-by-step explanation:
The numerator cannot be the square root of a neg. no.
So, x + 3 ≥ 0 or x ≥ -3
The denominator cannot be a neg. no. or 0.
So, 1 - x > 0
1 > x or x < 1
So, altogether - 3 ≤ x < 1
Therefore, D is the correct answer.
HOPE IT MAY HELP YOU
PLEASE MARK AS BRAINLIST
HELP PLEASEEEEE!!!!!!
If that answer doesn't work, then try 29 without the percent sign.
============================================================
Explanation:
We know with absolute certainty that the person ordered a hot drink, due to the "given".
This means we only focus on the values in the first row.
There are 5+48+22 = 75 hot drinks ordered. Of that total, 22 hot drinks are large.
The probability of getting a large drink, given it was a hot beverage, is 22/75 = 0.2933 approximately.
This converts to 29.33% and that rounds to 29%
What is the equation of the line that passes through the points
(-3, 6) and (-3, 8)?
Answer:
[tex]x=-3[/tex]
Step-by-step explanation:
Hi there!
Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0).
Typically, we would start with finding the slope of the line. However, notice how the two x-coordinates in the given points are both -3. This means that this is a vertical line, with an undefined slope.
Vertical lines have their equations organized differently: [tex]x=d[/tex] where d is the x-intercept, or the value of x when y is 0.
Because the x-coordinates in all the points a vertical lines passes through are the same, the x-intercept would therefore be -3. Plug this into the equation [tex]x=d[/tex]:
[tex]x=-3[/tex]
I hope this helps!
Chris had 3/4 of a jug of milk left. He used 2/5 of it to bake a cake how much of the jug of milk did he use in his cake
Answer:
5 pints of milk
Step-by-step explanation:
took the test
120 to 150 find the percentage of increase
Answer:
25%
Step-by-step explanation:
increase by = 150 - 120
=30
increase percent = 30/120 * 100%
=3000/120
=25 %
Answer:
25%
Step-by-step explanation:
Percentage increase=(new value-original value)/(original value) x 100%
Percentage increase=(150-120)/120 x 100%
Percentage increase=30/120 x 100%
Percentage increase=1/4 x 100%
Percentage increase=25%
HELP ME!
Line segment EQ consists of the points ____________. ???
Answer:
{F, G, H, I, J, K, L, M, N, O, P}
are the points between segment EQ :)
Name the identical triangles and measurement of side BA
Step-by-step explanation:
BE/BC=BD/BA
tHE TWO SIMILAR TRIANGLES ARE BED AND BC. tHE PROPORTION ABOVE REPRESENTS USE OF THE TWO SIMILAR TRIANGLES.
4/(4 + 10) = 5/(5+X) Cross Multiply
4(5+x) = 5(4+10)m
20 +4x=20 +50 subtract 20 from both sides
4x = 50 divide by 4
x =12.5
PLEASE HELP Assume the line of best fit for a data set is given by y = 32x+ 25. What data
points are predicted by the line of best fit? Check all that apply.
A. (9,326)
B. (10,345)
C. (7,224)
D. (6,217)
Answer:
B
Step-by-step explanation:
the answer is B
If you substitute 10 in the equation
32(9)+25=345
Answer:
B and D
Step-by-step explanation:
Substitute the values in y = 32x+ 25
A. 9, 326
326=32(9)+25
326 don't equal to 315
A is not
B. 10, 345
345=32(10)+25
345=345
B is a point on the line of best fit.
C. (7,224)
244= 32(7)+ 25
244 don't equal to 249
D. (6,217)
217= 32(6)+ 25
217=217
D is a point on the line of best fit.
Brainliest please
Help NOW RIGHT NOW
Which equation shows the distributive property? (a) 6 x 3 + 6 x 8 = 6 x (3 + 8) (b) 5 + (22 + 19) = (5 + 22) + 19 (c) 20 x 10 = 10 x 20 (d) 45 + 7 = 7 + 45
help me please
Solve -2x + 6 = -20. -7 -13 7 13
Answer:
13
Step-by-step explanation:
-2x + 6 = -20
Step 1 subtract 6 from both sides
6 - 6 cancels out
-20 - 6 = -26
We now have -2x = -26
Step 2 divide both sides by -2
-2x/-2 = x
-26/-2 = 13
We're left with x = 13
The diagram shows a rectangle PQRS.
PQ = 14 cm and QR = 9 cm.
The point A lies on PS so that PA = 5 cm.
The point Blies on SR so that BR = 8 cm.
Answer:
a) The area of the triangle AQB is 43 square centimeters.
b) The length of the line segment AQ is approximately 14.866 centimeters.
Step-by-step explanation:
a) The procedure consist in subtracting the areas of triangles APQ, ASB and BRQ of the area the rectangle, that is to say:
[tex]A = (9\,cm)\cdot (14\,cm) - \frac{1}{2}\cdot (5\,cm)\cdot (14\,cm) - \frac{1}{2}\cdot (8\,cm)\cdot (9\,cm) -\frac{1}{2}\cdot (4\,cm) \cdot (6\,cm)[/tex]
[tex]A = 43\,cm^{2}[/tex]
The area of the triangle AQB is 43 square centimeters.
b) The length of the line segment AQ is determined by Pythagorean Theorem:
[tex]AQ = \sqrt{AP^{2}+PQ^{2}}[/tex] (1)
[tex]AQ = \sqrt{(5\,cm)^{2}+(14\,cm)^{2}}[/tex]
[tex]AQ \approx 14.866\,cm[/tex]
The length of the line segment AQ is approximately 14.866 centimeters.
Tính :
a) (a+b+c)^2
b) (a-b-c)^2
c) (a+b-c)^2
d) (a-b+c)^2
Answer:
a.) a² + b² + c ² + 2ab + 2ac + 2bc
b.) a² + b² + c² - 2ab - 2 ac + 2bc
c ) a² + b² + c² + 2ab - 2ac - 2bc
d.) a² + b² + c² - 2ab + 2ac - 2bc
Step-by-step explanation:
Use ( a + b + c )² = a² + b² + c² + 2 × ab + 2 × ac + 2 × bc to expand all these expressiona) ( a + b + c )²
= a² + b² + c² + 2 × ab + 2 × ac + 2 × bc
= a² + b² + c ² + 2ab + 2ac + 2bc
b.) ( a - b - c )
= a² + ( - b )² + ( - c)² + 2a ( -b ) + 2a(-c) + 2(-b)(-c)
= a² + b² + c² - 2ab - 2 ac + 2bc
c.) ( a + b - c )²
= a² + b² + ( -c)² + 2ab + 2a ( - c) + 2 b( -c)
= a² + b² + c² + 2ab - 2ac - 2bc
d.) (a - b + c ) ²
= a² + ( -b)² + c² + 2a(-b) + 2ac + 2c( -b)
= a² + b² + c² - 2ab + 2ac - 2bc
PLEASE HELP ASAP ILL MARK BRAINLIEST.!!!
i only need these 2 and I’m done with math.!!!
Answer:
663902.4
11 pavers
Step-by-step explanation:
V = l × w × h
V = 164 × 82 × 6.6
V =
**********************************
The Swimming pool is a
rectangular prism. Write
the formula for its volume
and calculate it.
l...length of this prism
w...width of this prism
h...height of this prism
V ...volume
*********************************
To know how many
gallons are in the pool,
multiply the volume by
the number of gallons
in gal...number of
gallons
********************************
gal = 88757 × 7.48
gal = 663902.4
********************************
First to not confuse
anybody on this, we need
to convert the meters into
centimeters.
Rule: 1 m = 100 cm
3 m = 300 cm
2.5 m = 250 cm
********************************
so for every meter, we
multiply 100 to get the
amount of centimeters
********************************
so then add the
centimeters of 3 m and
2.5 m
Answer: 550 cm
so then now compare
the measurings...
3 m = 300 cm
50cm × y = 300cm
50cm × 6 = 300cm
y = 6
2.5 m = 250 cm
50cm × y = 250cm
50cm × 5 = 250cm
y = 5
6 + 5 = 11 pavers
so Oliver will need 11 pavers
Which of the following are solutions to the quadratic equation? Check all that
apply.
x2 + 8x + 16 = 7
Answer:
x=-9/10
Step-by-step explanation:
2x+8x+16=7
Step 1: Simplify both sides of the equation.
2x+8x+16=7
(2x+8x)+(16)=7(Combine Like Terms)
10x+16=7
10x+16=7
Step 2: Subtract 16 from both sides.
10x+16−16=7−16
10x=−9
Step 3: Divide both sides by 10.
10x/10
=
−9/10
x=-9/10
Answer:
x = - 4 ± [tex]\sqrt{7}[/tex]
Step-by-step explanation:
Given
x² + 8x + 16 = 7 ( subtract 16 from both sides )
x² + 8x = - 9
Using the method of completing the square
add ( half the coefficient of the x- term)² to both sides
x² + 2(4)x + 16 = - 9 + 16
(x + 4)² = 7 ( take the square root of both sides )
x + 4 = ± [tex]\sqrt{7}[/tex] ( subtract 4 from both sides )
x = - 4 ± [tex]\sqrt{7}[/tex]
Then
solutions are x = - 4 - [tex]\sqrt{7}[/tex] , x = - 4 + [tex]\sqrt{7}[/tex]
maths help pls.......
Answer: (C) 308 cm^2
Step-by-step explanation: Flat surface area is the surface area that is not curved; in this case, it would be the two circular bases. The height is arbitrary as the height is not needed to calculate the area of the bases. The formula for the area of circular bases is πr^2. Let's plug the given values into the formula. (22/7)(7)^2=(22/7)(49)=154. 154 cm^2 is the area of one base. To find the area of both bases, simply multiply the area of one base by two. 154*2 is 308, therefore the answer is (C) 308 cm^2.
Work out the sum of 1/4 1/6 and 1/3
Answer:
[tex]\frac{3}{4}[/tex]
Step-by-step explanation:
[tex]\frac{1}{4} +\frac{1}{6} +\frac{1}{3}[/tex]
4 = 2 × 2 × 1
6 = 2 × 3 × 1
3 = 3 × 1
GCF = 1
4 × 6 × 3 = 72
[tex]\frac{18}{72} +\frac{12}{72} +\frac{24}{72}[/tex]
[tex]\frac{18+12+24}{72}[/tex]
[tex]\frac{54}{72}[/tex]
54 = 2 × 3 × 3 × 3
72 = 2 × 2 × 2 × 3 × 3
GCF = 2 × 3 × 3
GCF = 18
[tex]\frac{\frac{54}{18} }{\frac{72}{18} }=\frac{3}{4}[/tex]
[tex]\huge\textsf{Hey there!}[/tex]
[tex]\large\textsf{Looking for your LCD (Least Common Denominator) of each fraction}\downarrow\\\\\\\mathsf{\dfrac{1}{4}=\dfrac{3}{12}}\\\\\\\mathsf{\dfrac{1}{6}=\dfrac{2}{12}}\\\\\\\mathsf{\dfrac{1}{3}=\dfrac{4}{12}}\\\\\\\\\\\large\textsf{The LCD is \underline{12}}[/tex]
[tex]\mathsf{\dfrac{1}{4}+\dfrac{1}{6}+\dfrac{1}{3}}[/tex]
[tex]\mathsf{= \ \dfrac{1\times3}{4\times3}+\dfrac{1\times2}{6\times2}+\dfrac{1\times4}{3\times4}}[/tex]
[tex]\large\textsf{Solving for the numerators (TOP numbers)}\downarrow\\\\\mathsf{1\times3=\boxed{\bf 3}}\\\\\mathsf{1\times2=\boxed{\bf 2}}\\\\\mathsf{1\times4=\boxed{\bf 4}}[/tex]
[tex]\large\textsf{Solving for the denominators (BOTTOM numbers)}\downarrow\\\\\mathsf{4\times3=\boxed{\bf 12}}\\\\\mathsf{6\times2=\boxed{\bf 12}}\\\\\mathsf{3\times4=\boxed{\bf 12}}[/tex]
[tex]\mathsf{=\ \dfrac{3+2+4}{12}}[/tex]
[tex]\large\textsf{Solving for your numerator (TOP number) }\downarrow\\\\\\\mathsf{3+2+4}\\\\\mathsf{= 5+4}\\\\\mathsf{= \boxed{\large\textsf{\bf 9}}}[/tex]
[tex]\mathsf{=\ \dfrac{9}{12}}[/tex]
[tex]\mathsf{\dfrac{9\div3}{12\div3}}\\\\\\\\\mathsf{9\div3= \boxed{\large\textsf{\bf 3}}}\\\\\mathsf{12\div3=\boxed{\large\textsf{\bf 4}}}[/tex]
[tex]\mathsf{= \dfrac{3}{4}}[/tex]
[tex]\boxed{\boxed{\large\textsf{Answer: }\boxed{\mathsf{\bold{ \dfrac{9}{12}\ or\ \dfrac{3}{4}}\ either\ of\ those\ fractions\ should\ work\ because}}}}\\\boxed{\boxed{\large\textsf{they are equal to each other!}}}\huge\checkmark[/tex]
[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
Question 7 of 27
Which of the following is an element in the sample space for first rolling a
number cube and then tossing a coin?
Answer:
TH is an element on the sample space for first rolling a die and then tossing a coin. A coin has both heads and tails.
The sample space for rolling a number cube and then tossing a coin is:
{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)}
The elements can be any of the elements in the sample space.
What is sample space?It is the total number of possible outcomes from a given set.
We have,
The sample space for rolling a number cube and then tossing a coin consists of all possible outcomes from rolling the number cube and tossing the coin.
Each outcome is a pair consisting of a number from 1 to 6 (the possible outcome from rolling the number cube) and a head or tail (the possible outcome from tossing the coin).
Therefore, an element in the sample space can be represented as an ordered pair (n, h/t), where n is the number rolled on the number cube and h/t is the outcome of the coin toss (either head or tail).
So,
The sample space for rolling a number cube and then tossing a coin is:
{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)}
For example, (3, H), (6, T), (1, H), and (4, T) are all elements in the sample space.
Thus,
The sample space for rolling a number cube and then tossing a coin is:
{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)}
Learn more about sample space here:
https://brainly.com/question/24273864
#SPJ7
Si: Tg θ =√2 ∧ θ es agudo √7 Calcular: A = 3(Sen θ + Cos θ) - √7
Answer:
[tex]A \approx 1.488[/tex]
Step-by-step explanation:
Por definición de razones trigonométricas, tenemos las siguientes identidades:
[tex]\tan \theta = \frac{y}{x} = \sqrt{2}[/tex] (1)
[tex]\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}[/tex] (2)
[tex]\cos \theta = \frac{x}{\sqrt{x^{2}+y^{2}}}[/tex] (3)
Si [tex]\theta[/tex] es agudo, entonces [tex]x, y > 0[/tex].
De (1), suponemos [tex]x = 1[/tex] que [tex]y = \sqrt{2}[/tex], entonces los valores de las funciones seno y coseno:
[tex]\sin \theta = \frac{\sqrt{2}}{\sqrt{5}} = \sqrt{\frac{2}{5} }[/tex]
[tex]\sin \theta = \frac{\sqrt{10}}{5 }[/tex]
[tex]\cos \theta = \sqrt{\frac{1}{5} }[/tex]
[tex]\cos \theta = \frac{\sqrt{5}}{5}[/tex]
Por último, calculemos [tex]A[/tex]:
[tex]A = 3\cdot \left(\frac{\sqrt{10}}{5} + \frac{\sqrt{5}}{5} \right) - \sqrt{7}[/tex]
[tex]A \approx 1.488[/tex]
Atividade 12 Observe o sistema de equações abaixo. {m−3n=16m+5n=−8 Quais são os valores de "m" e "n" que satisfazem esse sistema de equações? m=1en=3. m=7en=–3. m=52en=–12. m=–20en=–12.
Responder:
m = 7; n = - 3
Explicação passo a passo:
Dada a equação:
m − 3n = 16m + 5n = −8
Resolvendo a equação:
m − 3n = 16 - - - (1)
m + 5n = - 8 - - - (2)
Subtraia 1 de 2
m - m - 3n - 5n = 16 - - 8
-3n - 5n = 16 + 8
-8n = 24
n = 24 / - 8
n = - 3
Coloque n = - 3 em (1)
m − 3n = 16
m - 3 (-3) = 16
m + 9 = 16
m = 16 - 9
m = 7