PLease help

Belinda is thinking about buying a house for $179,000. The table below shows the projected value of two different houses for three years:


Number of years 1 2 3
House 1 (value in dollars) 186,160 193,606.40 201,350.66
House 2 (value in dollars) 190,000 201,000 212,000


Part A: What type of function, linear or exponential, can be used to describe the value of each of the houses after a fixed number of years? Explain your answer. (2 points)

Part B: Write one function for each house to describe the value of the house f(x), in dollars, after x years. (4 points)

Part C: Belinda wants to purchase a house that would have the greatest value in 30 years. Will there be any significant difference in the value of either house after 30 years? Explain your answer, and show the value of each house after 30 years. (4 points)

Answers

Answer 1

There are several types of functions, but this question is limited to just 2 types, which are the exponential function and the linear function.

House 1 has an exponential function of [tex]f(x) = 179000 * 1.04^x[/tex] while house 2 has a linear function of [tex]f(x) =11000x+179000[/tex]. House 1 will have a greater value in 30 years and the difference between the values of the two houses is significant.

The given parameters can be represented as:

[tex]\begin{array}{cccc}{Years} & {1} & {2} & {3} & {House\ 1} & {186,160 } & {193,606.40 } & {201,350.66} & {House\ 2} & {190,000 } & {201,000 } & {212,000} \ \end{array}[/tex]

(a): The type of function

First, we check if the function is linear by calculating the difference between each year

House 1

[tex]d = 193606.40 - 186160 = 7446.4[/tex]

[tex]d = 201350.66 - 193606.40 = 7744.26[/tex]

The difference are not equal; hence, the function is not linear. So, we can assume that it is exponential

House 2

[tex]d = 201000 - 190000 =11000[/tex]

[tex]d = 212000 - 201000 =11000[/tex]

The difference are equal; hence, the function is linear.

(b): The function of each

House 1

An exponential function is represented as:

[tex]y = ab^x[/tex]

When [tex]x = 1;\ y =186,160[/tex]

We have:

[tex]186,160 =ab^1[/tex]

[tex]186,160 =ab[/tex] ---- (1)

When [tex]x = 2;\ y =193606.40[/tex]

We have:

[tex]193606.40 =ab^2[/tex] --- (2)

Divide (2) by 1

[tex]\frac{193606.40}{186160} =\frac{ab^2}{ab}[/tex]

[tex]1.04 = b[/tex]

[tex]b = 1.04[/tex]

Make a the subject in (1)

[tex]186,160 =ab[/tex]

[tex]a = \frac{186160}{b}[/tex]

[tex]a = \frac{186160}{1.04}[/tex]

[tex]a = 179000[/tex]

So, the function for house 1 is:

[tex]f(x) = 179000 * 1.04^x[/tex]

House 2

A linear function is represented as:

[tex]y = mx + b[/tex]

First, we calculate the slope (m)

[tex]m = \frac{y_2 -y_1}{x_2 - x_1}[/tex]

So, we have:

[tex]m = \frac{201000 - 190000}{2 - 1}[/tex]

[tex]m = \frac{11000}{1}[/tex]

[tex]m = 11000[/tex]

So, the equation is:

[tex]y =m(x-x_1) + y_1[/tex]

Substitute known values

[tex]y =11000(x-1) + 190000[/tex]

[tex]y =11000x-11000 + 190000[/tex]

[tex]y =11000x+179000[/tex]

So, the function for house 2 is:

[tex]f(x) =11000x+179000[/tex]

(c): House with the greatest value in 30 years

This means that:

[tex]x = 30[/tex]

For house 1, we have:

[tex]f(x) = 179000 * 1.04^x[/tex]

[tex]f(30) = 179000 * 1.04^{30}[/tex]

[tex]f(30) = 580568.15[/tex]

For house 2, we have:

[tex]f(x) =11000x+179000[/tex]

[tex]f(30) = 11000 * 30+ 179000[/tex]

[tex]f(30) = 509000[/tex]

By comparison;

[tex]580568.15> 509000[/tex]

House 1 will have a greater value in 30 years

And the difference between the values is significant

The difference is:

[tex]d =580568.15-509000[/tex]

[tex]d =71568.15[/tex]

Read more about functions at:

https://brainly.com/question/7296377


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Answer:

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Step-by-step explanation:

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Distribute on left side.

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Answers

Answer:

16.6

Step-by-step explanation:

The rectangle has an area of 105. It's width is 7.

1: Find the length

     [tex]\frac{area}{width}[/tex]=length

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Answers

Answer:

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Answers

By definition of conditional probability,

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3. Rita is applying for a job as an engineer. Hier starting salary at Company will be $30,000 a $300 yearly
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company for 5 years. Which company should she pick?

Answers

Answer:

The 65,000 salary

Step-by-step explanation:

Because the 30,000 salary after 5 years would be 31,500.

30,000+300=30,300

30,300+300=30,600

30,600+300=30,900

30,900+300=31,200

31,200+300=31,500

The 65,000 paying company

65,000x1.05=68,250

68,250x1.05=71.662.5

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Answers

Answer:

option A is write answer

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none of these

Step-by-step explanation:

it's 96000 so none

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Answers

Lets do

[tex] \\ \sf \longmapsto \: 3(x + 5) - 7 = 2(x +2) \\ \\ \sf \longmapsto \: 3x + 15 - 7 = 2x + 4 \\ \\ \sf \longmapsto \: 3x + 8 = 2x + 4 \\ \\ \sf \longmapsto \: 3x - 2x = 4 - 8 \\ \\ \sf \longmapsto \: x = - 4[/tex]

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Answers

Answer:

A

Step-by-step explanation:

A compressed by a factor of 1/4 in the y or vertical direction

Wages and salaries
Kelly earns a salary of $68 430 pa how much does he earn each week, each fortnight and each month?

Answers

Answer:

Each week = $ 1311.41

Each fortnight = $ 2622.84

Each month =  $ 5702.5

Step-by-step explanation:

Given that,

Annual salary of Kelly = $ 68,430

As we know,

There are 52.18 weeks in a year.

So,

Weekly income = Annual salary ÷ no. of weeks in the year

= $ 68,430 ÷ 52.18

= $ 1311.42

Fortnight income = 2 * weekly income

= 2 * $ 1311.42

= $ 2622.84

Each month's income = Annual income ÷ 12(no. of months)

= $ 68,430 ÷ 12

= $ 5702.5

Multiply. (Use photo). Enter your answer in simplest radical form.

Answers

Answer:

72√2

Step-by-step explanation:

3√2 × 2√8 × √3 × √6

The above can be simplified as follow:

3√2 × 2√8 × √3 × √6

Recall

a√c × b√d = (a×b)√(c×d)

3√2 × 2√8 × √3 × √6 = (3×2)√(2×8×3×6)

= 6√288

Recall

288 = 144 × 2

6√288 = 6√(144 × 2)

Recall

√(a×b) = √a × √b

6√(144 × 2) = 6 × √144 × √2

= 6 × 12 × √2

= 72√2

Therefore,

3√2 × 2√8 × √3 × √6 = 72√2

What is the answer? How to solve?

Answers

Answer:

a +73°=90°

a= 90°-73°

a =17°

d+18°=90°

d=90°-18°

d =72 °

ZEFG and ZGFH are a linear pair, mZEFG = 2n + 16, and mZGFH = 3n+24. What are mZEFG and mZGFH?
mZEFG =

Answers

Answer:

m<EFG = 72°

m<GFH = 108°

Step-by-step explanation:

m<EFG = 2n + 16

m<GFH = 3n + 24

Linear pairs are supplementary, therefore,

m<EFG + m<GFH = 180°

Substitute

2n + 16 + 3n + 24 = 180

Add like terms

5n + 40 = 180

5n + 40 - 40 = 180 - 40 (subtraction property of equality)

5n = 140

5n/5 = 140/5 (division property of equality)

n = 28

✔️m<EFG = 2n + 16

Plug in the value of n

m<EFG = 2(28) + 16 = 72°

✔️m<GFH = 3n + 24

Plug in the value of n

m<GFH = 3(28) + 24 = 108°

Simplify each of the following:
a) root25 + root50 - root24 + root49

b) root2(2root8 – 3root32 + 4roor50)
Show your work

Answers

Answer:

a)

√25 + √50 - √24 + √49 =5 + 5√2 - 2√6 + 7 = 12 + 5√2 - 2√6

b)

√2(2√8 – 3√32 + 4√50) =2√16 - 3√64 + 4√100 = 2*4 - 3*8 + 4*10 = 8 - 24 + 40 = 24

Answer:

a.) 12 + 5√2 - 2√6

b.) 24

Step-by-step explanation:

a) √25 + √50 - √24 + √49

√25 + √50 - √24 + √49

Calculate the square root .

5 + √50 - √24 + 7

Simplify the radical expression.

5 + 5√2 - 2√6 + 7

Combine like terms.

5 + 7 + 5√2 - 2√6 12 + 5√2 - 2√6

b.) √2 ( 2√8 - 3√32 + 4√50 )

√2 ( 2√8 - 3√32 + 4√50 )

Simplify the radical expression.

√2 ( 4√2 - 3 × √2 + 20√2)

Evaluate the power.

√2 ( 4√2 - 3 × 4√2 + 20√2)

Calculate the products.

√2 ( 4√2 -12√2 + 20√2)

Combine like terms.

√2 × (4 - 12 + 20 )√2√2 × 12 √ 2

Multiply.

2 × 12 24

An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the
object's height s at time t seconds after launch is s(t) = - 4.9t2 + 19.6t + 58.8, where s is in meters. Create a
table of values and graph the function. Approximately what is the maximum height that the object will get?
O 76.4 meters
113.5 meters
O 78.4 meters
58.8 meters

Answers

Answer:

Step-by-step explanation:

The easiest way to do this is to complete the square on the quadratic. This allows us to see what the vertex is and answer the question without having to plug in a ton of numbers to see what the max y value is. Completing the square will naturally put the equation into vertex form:

[tex]y=-a(x-h)^2+k[/tex] where h will be the time it takes to get to a height of k.

Begin by setting the quadratic equal to 0 and then moving over the constant, like this:

[tex]-4.9t^2+19.6t=-58.8[/tex] and the rule is that the leading coefficient has to be a 1. Ours is a -4.9 so we have to factor it out:

[tex]-4.9(t^2-4t)=-58.8[/tex] Now take half the linear term, square it, and add it to both sides. Our linear term is a -4, from -4t. Half of -4 is -2, and -2 squared is 4, so we add a 4 to both sides. BUT on the left we have that -4.9 out front there as a multiplier, so we ACTUALLY added on to the left was -4.9(4) which is -19.6:

[tex]-4.9(t^2-4t+4)=-58.8-19.6[/tex] and now we have to clean this up. The right side is easy, that is -78.4. The left side...not so much.

The reason we complete the square is to create a perfect square binomial, which is the [tex](x-h)^2[/tex] part from above. Completing the square does this naturally, now it's just up to us to write the binomial created during the process:

[tex]-4.9(t-2)^2=-78.4[/tex] Now, move the constant back over and set the equation back equal to y:

[tex]-4.9(t-2)^2+78.4=s(t)[/tex] and we see that the vertex is (2, 78.4). That means that 2 seconds after launch, the object reached its max height of 78.4 meters, the third choice down.

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