PLS HELP PLS In the diagram below, ΔABC ≅ ΔDEF. Complete the statement ∠B ≅

A. ∠D
B. ∠A
C. ∠C
D. ∠E

PLS HELP PLS In The Diagram Below, ABC DEF. Complete The Statement B A. DB. AC. CD. E

Answers

Answer 1

Answer:

Angle B is congruent to Angle E.

Step-by-step explanation:

Also, if youve read Romeo and Juliet, please help me! My essay is due tomorrow. I just need informal help, no specific lines or anything

Answer 2

In the diagram below, ΔABC ≅ ΔDEF. Therefore, by CPCT, ∠B = ∠E.

What is CPCT?

Corresponding parts of congruent triangles or CPCT is used to denote the relation between the sides and the angles of two congruent triangles.

Since, ΔABC ≅ ΔDEF,

AB = DE

BC = EF

AC = DF

∠A = ∠D

∠B = ∠E

∠C = ∠F

Learn more about CPCT here

https://brainly.com/question/21360865

#SPJ2


Related Questions

What is the image of (10, -12) after a
dilation by a scale factor of centered at the
origin?

Answers

Answer:

-5, -3

Step-by-step explanation:

what is the answer for 10(x-7)=y

Answers

x intercepts- (7,0)
y intercepts- (0,-70)

45
24
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AM
51

15
17
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Hope this help!!!

Have a nice day!!!!

Given csc(A) = 60/16 and that angle A is in Quadrant I, find the exact value of sec A in simplest radical form using a rational denominator . Someone please help me!

Answers

Answer:

[tex] \frac{15 \sqrt{209} }{209} [/tex]

Step-by-step explanation:

Objective: Understand and work with trig identies.

Recall multiple trig identies and manipulate them to get from cosecant to secant.

Given

[tex] \csc(a) = \frac{60}{16} [/tex]

Apply reciprocal identity csc a = 1/sin a.

[tex] \sin(a) = \frac{16}{60} [/tex]

Apply pythagorean identity to find cos a.

[tex]( \frac{16}{60}) {}^{2} + \cos(x) {}^{2} = 1[/tex]

[tex] \frac{256}{3600} + \cos(x) {}^{2} = 1[/tex]

[tex] \cos(x) {}^{2} = \frac{3600}{3600} - \frac{256}{3600} [/tex]

We can simplify both expression

[tex] \cos(x) {}^{2} = \frac{225}{225} - \frac{16}{225} [/tex]

[tex] \cos(x) = \frac{ \sqrt{209} }{15} [/tex]

Cosine is positve on quadrant 1 so that cos(a)

Apply reciprocal identity sec a= 1/ cos a.

The answer is

[tex] \sec(a) = \frac{15}{ \sqrt{209} } [/tex]

Rationalize the denominator.

[tex] \frac{15}{ \sqrt{209} } \times \frac{ \sqrt{209} }{ \sqrt{209} } = \frac{15 \sqrt{209} }{209} [/tex]

please help me answer this!!

Answers

Answer:

(x, y) = (10, 290)

Step-by-step explanation:

From the table

Total fees = fixed + variable

Fixed:

When number of times Ahmed mowed, x = 0

y = 40

When x = 2, y = 65

Rate of change = y2 - y1

= 65 - 40

= 25

y = 40 + 25x

Where,

y = total fees charged

40 = fixed fee

25x = variable fee

Total amount Ahmed will make for mowing 10 times

when x = 10

y = 40 + 25x

y = 40 + 25(10)

= 40 + 250

= 290

y = 290

(x, y) = (10, 290)

Sara sees some notebooks she likes in a shop. They cost 35p each. This is the money she has. Look in the image

a. How many notebooks can Amy buy? _________

b. How much money will she have left? __________

NEED ANS ASAP giving u 50points

Answers

Answer:

Sara can buy 2 notebooks with the money that she has and she will have a remainding 23.1

Step-by-step explanation:

93.1-35-35=23.1

Select ALL the functions whose graphs include the point (16, 4).

Answers

Answer:

D

Step-by-step explanation:

x=16

y=4

4=16-12

4=4

Answer:

D

Step-by-step explanation:

Suppose you roll a cube 30 times, what is a to describe the theoretical of rolling a 1, 4, 6, 7 Please help me!

Answers

Answer:

[tex]Pr(x) = \frac{1}{6}[/tex]

Step-by-step explanation:

Given

[tex]n = 30[/tex] --- number of rolls

Required

The theoretical probability of rolling: (a) 1    (b) 4    (c) 6    (d) 7

Assume the cube is 6 sided.

The sample space is:

[tex]S = \{1,2,3,4,5,6\}[/tex]

And the probability of each is:

[tex]Pr(x) = \frac{1}{6}[/tex]

Irrespective of the number of rolls, the theoretical probability of (a). (b), (c) and (d) is:

[tex]Pr(x) = \frac{1}{6}[/tex]

The probability of spinning an odd number, flipping heads and then spinning a 3 is?

Answers

Answer:  5/162

===================================================

Work Shown:

A = probability of landing on an odd number

A = 5/9 because there are 5 odd numbers out of 9 total

B = probability of getting heads

B = 1/2

C = landing on 3 on the spinner

C = 1/9

Multiply the values of A,B,C

A*B*C = (5/9)*(1/2)*(1/9) = (5*1*1)/(9*2*9) = 5/162

Note: The fraction 5/162 converts to the approximate decimal 0.03086 which then converts to 3.086%, when rounding to the nearest tenth of a percent we get 3.1%

Can anyone help me on this I would appreciate it

Answers

Answer:

14

Step-by-step explanation:

Triangle=180

180-90 (RA) = 90

90-41= 39

(2x+11)=39

2x=28

x=14

Insee its finna be 14

Factorize the following 3x + 12

Answers

Answer:

if this was a equation you would first subtract 12 from the other number then divide it by 3

Answer:

3(x+4)

Step-by-step explanation:

Check 3(x+4), when you use the distributive property, you get 3x + 12, so this is correct. (sorry, I'm really bad at explaining...)

is this a reasonable estimate? Why?

Answers

Answer:

See below.

Step-by-step explanation:

No, a reasonable estimate is around 7 * 6 = 42.

Round $6.99 to $7 and multiply by the 6 family members.

Which set of numbers does not contain the value below?


Select one:

a. Complex Numbers
b. Pure Imaginary Numbers.
c. Rational Numbers.
d. Integers.​

Answers

Answer:

b. Pure Imaginary Numbers.

Step-by-step explanation:

[tex] (i \sqrt{3})^2 = i^2 \times (\sqrt{3})^2 = -1 \times 3 = -3 [/tex]

-3 is an integer, a complex number, and a rational number.

Answer: b. Pure Imaginary Numbers.

What is the value of c?
30°
с

Answers

Answer:

c = 60°

Step-by-step explanation:

Since the measures are among a 90° angle, we need to subtract 30° from 90° which equals 60°

c = 60°

The correct answer is 60 degrees

8 out of every 14 children in a school are boys. What is the ratio of boys to girls in the school?

Answers

Answer:

8:6

Step-by-step explanation:

If 8 out of 14 students are boys then the remaining number of students must be girls

So

14-8= 6

There are 6 girls out of the 14

So as a ratio of boys to girls

8:6

Answer:

8 : 6 <or> 4 : 3

Step-by-step explanation:

8 : 6 <or> 4 : 3

Since there are 8 boys out of 14, if you minus them , the answer will be the number of girls out of 14.

please help me oh my lord

Answers

Answer:

A

Step-by-step explanation:

C my father owns cloud9 so I know I’m right

The length of the ladder that will run from the ground to the door of the tree house is nine feet. The plan recommends that the rungs of the ladder be spaced at 8-inch intervals. The first and last rung should be 6 inches from the respective ends. How many rungs will the tree house ladder have?

Answers

Answer:

13 Rungs

Step-by-step explanation:

According to the Question,

Given, The length of the ladder that will run from the ground to the door of the treehouse is 9 feet ( 9 × 12 = 108 inches).

The plan recommends that the rungs of the ladder be spaced at 8-inch intervals.

And, The first and last rung should be 6 inches from the respective ends.

Thus, the rungs Cover on 108 -(6+6) = 96 inches with 8-inch gaping between each rung.

Therefore, the Total Rungs on the treehouse ladders have (96/8)+1 ⇒ 13 Ladders.

4a. Solve the inequality 3(2x - 4) + 6 > 18 + 2x , for x*​

Answers

Answer:

x>6

Step-by-step explanation:

I know I’m not good at writing.

a right triangle has legs of lengths 7 and 2, what is the length of the hypotenuse to the nearest tenth

Answers

Answer:

hypotenuse = 7.3

Step-by-step explanation:

here 7 and 2 are the legs og the right triangle .we should find hypotenuse.

let the legs of the right triangle be a nd b respectively . And c be hypotenuse

using pythagoras theorem to find hypotenuse

a^2 + b^2 = c^2

7^2 + 2^2 = c^2

49 + 4 = c^2

53 = c^2

[tex]\sqrt{53}[/tex] = c

7.28 = c

7.3 =c

Answer:

7.3

Step-by-step explanation:

[tex]7^{2} + 2^{2} = x^{2} \\ 53 = x^{2}\\\sqrt{53} = \sqrt{x^{2}} \\x = 7.3[/tex]

Help me down below

PLEASE

Answers

Answer:

there is one more zero

Step-by-step explanation:

now it's 8 million rather than 800 thousand.

Find the 25th term of the sequence -7,-22,-37.

Answers

Answer:

a₂₅ = - 367

Step-by-step explanation:

There is a common difference d between consecutive terms, that is

d = - 22 - (- 7) = - 37 - (- 22) = - 15

This indicates the sequence is arithmetic with nth term

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 7 and d = - 15 , then

a₂₅ = - 7 + (24 × - 15) = - 7 - 360 = - 367

Acircle with radius of 2 cm sits inside a llcm x 12 cm
rectangle.
What is the area of the shaded region?
Round your final answer to the nearest hundredth.

Answers

Meowing meow meow explain: meow meow

Answer:

119.4

Step-by-step explanation:

The Area of the Rectangle : 132 cm

Area of the Circle : 12.6 cm

Shade=  MINUS - 132 cm  - 12.5 cm = 119.4!

Happy To Help! :)

PLS ANSWER ASAP DUE 9:35

Answers

Answer:

c) 72

hope this helps!

please give brainiest<3

Answer:

72

Step-by-step explanation:

Substitution:

4^3 + 4 x 6 - 16

64+24-16=72

28 Marks
.
Two numbers have these properties.
Both numbers are greater than 6.
Their highest common factor (HCF) is 6.
Their lowest common multiple (LCM) is 60.
Find the two numbers, writing your answers on one line in the form,
The two numbers are ... and..

Answers

Answer:

HCF×LCM=a×b

6×60=a×b

a×b=360

So the numbers are whose product is 360 and LCM is 60

These two numbers can be 6,60 or 12,30

PLEASE HELP!! This is timed, but I don't recall ever learning this info T-T
I'll mark brainliest!!

Answers

Answer:

c

Step-by-step explanation:

i hope it helped ᘳ◕ᴥ◕ᘰ

A company sold 3,000 computers in one month, but 12 were returned. If 3,500 were sold the next month, the company would expect 14 to be returned.

What is a valid proportion to represent the problem?​

Answers

Answer:

the last one is correct

Step-by-step explanation:

because 3000/12 = 250 and 3500/14 = 250 so they are porportional.

write the expression in expanded form
3h^3(k+3)^2

Answers

Answer:

3h³k² + 18h³k + 27h³

Step-by-step explanation:

Given

3h³(k + 3)² ← expand factor using FOIL

= 3h³(k² + 6k + 9) ← distribute parenthesis

= 3h³k² + 18h³k + 27h³

The following box plot represents the average heights of the students in Mrs. Hill's sixth grade math class.



Which of the following statements can you determine from the graph? Select all that apply.

Half of the students in Mrs. Hill's class are between 147 centimeters and 154 centimeters tall.
The median height of the students in Mrs. Hill's class is 152 centimeters.
The interquartile range of this data set is 15 centimeters.
The mean height of the students in Mrs. Hill's class is 152.5 centimeters.

Answers

Answer:

152 and 9

Step-by-step explanation:

Type the correct answer in each box. The reflection of point S across the y-axis is point . The reflection of point Q across the x-axis and the y-axis is point , whose coordinates are (, ).

Answers

Answer:

[tex]S' = (-5,-5)[/tex]

[tex]Q"=(-5,-5)[/tex]

Step-by-step explanation:

Given

[tex]S = (5,-5)[/tex]

[tex]Q= (5,5)[/tex]

Solving (a): Reflect S across y-axis

The rule to reflect across y-axis is:

[tex](x,y) \to (-x,y)[/tex]

So, we have:

[tex]S(5,-5) \to S'(-5,-5)[/tex]

Hence:

[tex]S' = (-5,-5)[/tex]

Solving (b): Reflect Q across x and y-axis

The rule to reflect across x-axis is:

[tex](x,y) \to (x,-y)[/tex]

So:

[tex]Q(5,5) \to Q'(5,-5)[/tex]

The rule to reflect across y-axis is:

[tex](x,y) \to (-x,y)[/tex]

So:

[tex]Q'(5,-5) \to Q"(-5,-5)[/tex]

Hence:

[tex]Q"=(-5,-5)[/tex]

i dont get it either

Step-by-step explanation:

What is the solution to the linear equation? 2/5 + p = 4/5 + 3/5p ​

Answers

Answer:

p=1

Step-by-step explanation:

2/5 + p = 4/5 + 3/5p

Multiply each side by 5 to clear the fractions

5(2/5 + p) = 5(4/5 + 3/5p)

2 +5p = 4 + 3p

Subtract 3p from each side

2+5p-3p = 4+3p-3p

2+2p = 4

Subtract 2 from each side

2+2p -2 = 4-2

2p =2

Divide by 2

2p/2 = 2/2

p=1

[tex]\huge\mathbb{\fcolorbox{red}{lavenderblush}{✰Answer}}[/tex]

[tex]\sf{\dfrac{2}{5}+p=\dfrac{4}{5}+\dfrac{3p}{5}   }[/tex] 

[tex]\sf{ \dfrac{2}{5}+p=\dfrac{4+3p}{5}   }[/tex] 

[tex]\sf{5(\dfrac{2}{5}+p)=4+3p }[/tex] 

[tex]\sf{ 2+5p=4+3p  }[/tex] 

[tex]\sf{5p-3p=4-2   }[/tex] 

[tex]\sf{ 2p=2  }[/tex] 

[tex]\sf{p=\dfrac{2}{2}   }[/tex] 

[tex]\bold{p=1   }[/tex] 
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