Answer:
a - they should be large and sturdy
Step-by-step explanation:
The article states that artificial reefs can be made from materials such as concrete, or large pieces of waste such as subway cars, takes, and aircraft carriers. All of these items are large and sturdy.
Hope this helps, have a wonderful day :))
Pls help me im desperate bots are not supposed to post here
Answer:
y = [tex]\frac{1}{2}x+8[/tex]
Step-by-step explanation:
From the table given in the picture,
Two points lying on the graph are (-4, 6) and (-2, 7)
Let the linear function is,
y = mx + b
Here, m = slope of the line
b = y-intercept
Since, slope of a line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,
Slope (m) = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Therefore, slope of the line passing through (-4, 6) and (-2, 7) will be,
m = [tex]\frac{7-6}{-2+4}[/tex]
m = [tex]\frac{1}{2}[/tex]
y-intercept is a point for which x = 0
From the given table,
For x = 0, y = 8
Therefore, y-intercept (b) = 8
Equation of the linear function will be,
y = [tex]\frac{1}{2}x+8[/tex]
what its 600+600 pls help
Answer:
1200 hope this helps you;)
Answer:
1200 lol
Step-by-step explanation:
Represent the greatest common factor of 36 and 8 using the distributive property
36 + 8 =
0 4x(9+2)
O2 x (18+4)
O 8x (5+2)
0 11 x (3+1)
Can someone seriously help me!!!!!
Answer:
Step-by-step explanation:
This should help I hope
Students are voting on the color of T-shirts to wear on their field trip. There are 160 students-65 boys and 95 girls- going on the field trip. A random sample of students is chosen. Surveying the random sample produced a representative sample of the population. Which was most likely true of the representative sample? The representative sample contained all 160 students. The representative sample contained more boys than girls. The representative sample contained more girls than boys. The representative sample contained an equal number of boys and girls.
Answer:
The representative sample contained more girls than boys.
The true representative sample:
The representative sample contained more girls than boys.
The correct option is C.
What is sample space?A sample space is a set of potential results from a random experiment. The letter "S" is used to denote the sample space. Events are the subset of potential experiment results. Depending on the experiment, a sample area could contain a variety of results.
Given:
Students are voting on the color of T-shirts to wear on their field trip. There are 160 students-65 boys and 95 girls- going on the field trip.
A random sample of students is chosen.
Surveying the random sample produced a representative sample of the population.
The total number of students = 160
The number of girls = 95
The number of boys = 65
Clearly, the number of girls is more than the number of boys.
Therefore, the sample should contain more girls than boys.
To learn more about the sample space;
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If a rectangle has an area of 48 cm², what would be the area of a similar rectangle if
the dimensions are doubled?
A) 2304 cm^2
B) 192 cm^2
C)96 cm^2
D)216 cm^2
2.6x + 10.5 = 31.3
I need help ASPAP!!
the answer is on the picture
Answer: x=8
Step-by-step explanation: Hope this help :D
your backyard is shaped like a rectangle and measure's 45 1/2 feet by 50 feet. you want to put a fence around your backyard. how much fence will you need?
Answer:
191 ft
Step-by-step explanation:
If it's 45.5ft x 50ft, we'll need to put fence around two 45.5ft sides and two 50ft sides.
2*45.5ft + 2*50ft = 91ft + 100ft = 191ft
• 1 1 Write equivalent fractions for 3 and 1. using 12 as the common denominator. 3 -1- 12 12
Answer:
6 and 8
Step-by-step explanation:
Margot helps out at a horse farm. She spends 26 minutes one morning brushing a horse. She spends 39 minutes that same day brushing another horse. How many minutes does she brush horses in all?
Which choice is the slope-intercept equation of the line shown below?
(1,2)
(0, -1)
A. y = 3x - 1
B. y = 2x-1
C. y = 2x + 1
D. y = 3x
Answer:
C is my answer
Step-by-step explanation:
choose the expression that represents the fraction as a product of a whole number and a unit fraction 4/10
Answer:
69
Step-by-step explanation:
trust me
Sin 0= 8/17 determine the value of tan?
Answer:
tan theta = 8/15
Step-by-step explanation:
Sin is equal to opposite over hypotenuse. So it means that the side opposite from theta is 8, and the hypotenuse is 17.
To find the value of the adjacent side from theta, use the Pythagorean Theorem.
a^2 + b^2 = c^2
8^2 + b^2 = 17^2
64 + b^2 = 289
Subtract 64.
b^2 = 225
Take the square root.
b = 15.
So that means:
the side opposite from theta is 8,
the side adjacent from theta is 15,
the hypotenuse is 17.
Now we take tan, opposite over adjacent, and use the values from the triangle.
tan = opposite / adjacent
tan = 8/15.
19 of 22 participants (86.36%) from the high-power posing group took a gambling risk to double their money, while 12 of 20 (60%) from the low-power posing group took the gambling risk. Use a calculator tool from Module 10 to determine the p-value associated with the hypothesis test examining if there is a statistically significant difference between the proportion of people willing to take risks in the two groups. Round to 3 decimal places
Answer:
Step-by-step explanation:
19 of 22 participants (86.36%) from the high-power posing group took a gambling risk to double their money, while 12 of 20 (60%) from the low-power posing group took the gambling risk. Use a calculator tool from Module 10 to determine the p-value associated with the hypothesis test examining if there is a statistically significant difference between the proportion of people willing to take risks in the two groups. Round to 3 decimal places
H0 : P1 - P2 = 0
H1 : P1 - P2 ≠ 0
P1 = 0.8636
P2 = 0.6
q1 = 1 - P1 = 0.1364
q2 = 1 - P2 = 0.4
Tstatistic = (p1 - p2) ÷ √(p1q1)/n1 + (p2q2)/n2]
Tstatistic = (0.8636-0.6) ÷ √0.01735432]
Tstatistic = 0.2636 ÷ 0.1317357
Test statistic = 2.0009761
Test statistic = 2
The Pvalue from t statistics :
Tscore = 2 ; df = 20 + 22 - 2 = 40
Determine the amplitude or period as requested. Period of y = - 1/3 * sin 2x
Answer:
[tex]Period = \pi[/tex]
Step-by-step explanation:
Given
[tex]y = -\frac{1}{3} * \sin(2x)[/tex]
Required
The period
A sine function is represented as:
[tex]y =A \sin(Bx + C) + D[/tex]
Where
[tex]Period = \frac{2\pi}{B}[/tex]
By comparing:
[tex]y =A \sin(Bx + C) + D[/tex] and [tex]y = -\frac{1}{3} * \sin(2x)[/tex]
[tex]B = 2[/tex]
So, we have:
[tex]Period = \frac{2\pi}{2}[/tex]
[tex]Period = \pi[/tex]
Hence, the period of the function is [tex]\pi[/tex]
Meatball subs used to cost $5.40 at Mike's Sub Shop, but he just increased the price by $0.54.
How much do subs cost now?
Answer:
Step-by-step explanation: $5.40 + $0.54 now equals $5.94
A small country emits 130,000 kilotons of carbon dioxide per year. In
a recent global agreement, the country agreed to cut its carbon
emissions by 3.1% per year for the next 10 years. In the first year of the
agreement, the country will keep its emissions at 130,000 kilotons and
the emissions will decrease 3.1% in each successive year. How many
total kilotons of carbon dioxide would the country emit over the course
of the 10 year period, to the nearest whole number?
Answer:1132858
Step-by-step explanation:
The total carbon dioxide the country emit over the course of the 10 year period would be 1,132,858 kilotons.
What is rate of decrease?
The rate of decrease is a constant amount of deduction from a fixed or primary amount.
Here, the carbon dioxide emits by the country per year is 130,000 kilotons.
The rate of decrease of the carbon dioxide emission per year would be 3.1%.
In the 1st year, the carbon dioxide emission = 130,000 kilotons.
In the 2nd year, the carbon dioxide emission = 130,000 × (100-3.1)/ 100 kilotons = 125,970 kilotons.
In the 3rd year, the carbon dioxide emission = 125,970 × (100-3.1)/ 100 kilotons = 122,064.93 kilotons.
In the 4th year, the carbon dioxide emission = 122,064.93 × (100-3.1)/ 100 kilotons = 118,280.92 kilotons.
In the 5th year, the carbon dioxide emission = 118,280.92 × (100-3.1)/ 100 kilotons = 114,614.21 kilotons.
In the 6th year, the carbon dioxide emission = 114,614.21 × (100-3.1)/ 100 kilotons = 111,061.17 kilotons.
In the 7th year, the carbon dioxide emission = 111,061.17 × (100-3.1)/ 100 kilotons = 107,618.27 kilotons.
In the 8th year, the carbon dioxide emission = 107,618.27 × (100-3.1)/ 100 kilotons = 104,282.1 kilotons.
In the 9th year, the carbon dioxide emission = 104,282.1 × (100-3.1)/ 100 kilotons = 101,049.35 kilotons.
In the 10th year, the carbon dioxide emission = 101,049.35 × (100-3.1)/ 100 kilotons = 97,916.82 kilotons.
Hence, total carbon dioxide emission by that country over 10 years = (130,000 + 125,970 + 122,064.93 + 118,280.92 + 114,614.21 + 111,061.17 + 107,618.27 + 104,282.1 + 101,049.35 + 97,916.82) kilotons = 1,132,857.77 kilotons ≈ 1,132,858 kilotons.
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Mrs Mills buys 4 packs of treats for her cats, Fluff and tigger
she gives Fluff 1/6 of a pack each day
She gives tigger 1/5 of a pack each day
for how many complete days will the 4 packs of treats last
Answer: 10 days
Step-by-step explanation:
1/6 + 1/5 = 5/30 + 6/30 = 11/30 (total for the day)
4 / (11/30) = 10.90909091 (divide the total amount of packages by the daily total)
So 10 complete days.
How can you isolate the variable in this equation? x + 6 = 13 A Add 6 to 13. B Add 6 to both sides. C Subtract x from both sides. D Subtract 6 from both sides.
Answer:
the answer is D, im doiing the flocab rn
Step-by-step explanation:
What is the shape of
its bases?
A. Circle
B. Heptagon
C. Rectangle
D. Triangle
Answer:
C. Rectangle
Step-by-step explanation:
Hope it helps you in your learning process.
Which expression is equivalent to 3m(x) - 5n(x), if m(x) = 6x2 + 3x - 5 and n(x) = 2x2 + 7x - 1?
Answer:
8x^2 - 26x - 10
Step-by-step explanation:
3(6x2 + 3x - 5 ) = 18x^2 + 9 -15
5(2x2 + 7x - 1) = 10x^2 + 35 - 5
18^2 - 10x^2 = 8x^2
9x - 35x = - 26x
-15 -(-5) = -10
final answer = 8x^2 - 26x - 10
A data set includes data from student evaluations of courses. The summary statistics are n, , s. Use a significance level to test the claim that the population of student course evaluations has a mean equal to . Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
Complete question :
A data set includes data from student evaluations of courses. The summary statistics are nequals92, x overbarequals4.09, sequals0.55. Use a 0.10 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
Answer:
H0 : μ = 4.25
H1 : μ < 4.25
T = - 2.79
Pvalue =0.0026354
we conclude that there is enough evidence to conclude that population mean is different from 4.25 at 10%
Step-by-step explanation:
Given :
n = 92, xbar = 4.09, s = 0.55 ; μ = 4.25
H0 : μ = 4.25
H1 : μ < 4.25
The test statistic :
T = (xbar - μ) ÷ s / √n
T = (4.09 - 4.25) ÷ 0.55/√92
T = - 0.16 / 0.0573414
T = - 2.79
The Pvalue can be obtained from the test statistic, using the Pvalue calculator
Pvalue : (Z < - 2.79) = 0.0026354
Pvalue < α ; Hence, we reject the Null
Thus, we conclude that there is enough evidence to conclude that population mean is different from 4.25 at 10%
Answer:
Step-by-step explanation:
The null and alternative hypotheses are:
Null hypothesis: The population mean of student course evaluations is equal to 4.25.
Alternative hypothesis: The population mean of student course evaluations is not equal to 4.25.
The significance level is 0.01, so the test will be a two-tailed test.
The test statistic is calculated as:
t = (x - μ) / (s / √n) = (4.18 - 4.25) / (0.54 / √97) = -2.63
The degrees of freedom for the t-distribution is n-1 = 96. Using a t-table or a calculator, the P-value for a two-tailed test with 96 degrees of freedom and a t-value of -2.63 is approximately 0.010.
Since the P-value (0.010) is less than the significance level (0.01), we reject the null hypothesis. We have sufficient evidence to conclude that the population mean of student course evaluations is not equal to 4.25.
In other words, the data provides strong evidence to suggest that the average student course evaluation rating is significantly lower than 4.25.
what is a easier way to solve fractions
Answer: hewo, there! I hope I Made it easier to Understand
the first method is to equally divide the top and bottom of the fraction by whole numbers larger than 1 until you cannot go any further. As an example, let's take the fraction 24/108: Divide each number by 2 to get 12/54. Divide by 2 again to get 6/27
Step-by-step explanation:
To work out a fraction of a number, all you need to do is divide that number by the denominator of the fraction, then multiply your result by the numerator of the fraction
Hope this helps you!!
Have a great day!!!
What is the area of the green triangle?
Answer:
The answer is 65
Step-by-step explanation:
Formula for triangle: b x h x 1/2
base= 13cm height= 10cm
13 x 10 x 1/2 =65
The area of the green triangle is 65.
Rosalind made 969 donuts and put 8 donuts into each box. How many boxes of donuts were made
Answer:
121 donuts in each box
Step-by-step explanation:
969 divided by 8 = 121.125
(Ignore the remainder)
Step by step solution:
We know that there are 969 doughnuts, and there are 8 doughnuts per box. What we need to find out is how many boxes of doughnuts were made.
Step 1:
Set up an equation for Number of doughnuts (969) / Number of doughnuts per box (8) = Number of boxes made (x), which would look like this:
969/8 = x
Step 2:
Doing this, we can get 121.125, which leaves us with
121.125 = x
121.125 = 121.125
Which gives us the answer of 121.125, which we can shorten to 121, as the decimal is not necessary.
Checking our answer:
We can check our answer simply be rewording our 1st equation to solve for the number of doughnuts made. This would give us the equation Number of doughnuts per box (8) * Number of boxes made (121.125) = x. Solving this equation would look like
8 * 121.125 = x
969 = x
969 = 969
Answer: By completing the steps above we get 121, and we can check our work by rewording the problem to solve for the number of Doughnuts. Good Luck!
Which statement defines Suppose that farmers grew an unexpectedly large number of tomatoes this year. How would this increase in production affect the price of tomatoes?the term markup?
Answer:
The price would go down as people would be more willing to buy cheaper potatoes and the producers would want to sell them for a lower price to get rid of them easy and fast.
Step-by-step explanation:
Hope this helps you :)
Suzanne collected data on the weight of her classmates. She found that the range of the data she collected was 17
Which of the following BEST explains what a range of 17 indicates?
A
The average distance of each point from the mean is 17.
.
B
The distance between the minimum and the maximum is 17.
С
The distance between the lower quartile to the upper quartile is 17.
D
The distance between the mean and the median in a skewed data set is 17
Answer:
the answer is A.
Step-by-step explanation:
I need to know the answer!
Answer:
As it says he is incorrect.
Step-by-step explanation:
To start, if you were to multiply something such as 5*1, then you would get the same number. Another example would be 8*0. Anything multiplied by 0 IS zero. He does give some valid answers, but there are also ones with smaller numbers. That is why Jackson is incorrect.
Let's say you have a 4 gallon and a 10 gallon pailHow can you measure exactly 2 gallons of water?
You can fill the 10 gallon pail all the way up. After that, you can pour the water from the 10 gallon pail, into the 4 gallon pail 2 times. That will leave you with 2 gallons in the 10 gallon pail.
An article in Technometrics (Vol. 19, 1977, p. 425) presents the following data on the motor fuel octane ratings of several blends of gasoline:
88.5 98.8 89.6 92.2 92.7 91.8 91.0 91.0 94.7 88.3 90.4 83.4 87.9 88.4 87.5 90.9 84.3
90.4 91.6 91.0 93.0 92.6 87.8 89.9 90.1 91.2 90.7 88.2 94.4 93.7 88.3 91.8 89.0 90.6
88.6 88.5 90.4 96.5 89.2 89.7 89.8 92.2 88.3 93.3 91.2 84.3 92.3 92.2 91.6 87.7 94.2
87.4 91.2 93.2 88.9 90.3 91.1 85.3 91.1 86.7 88.6 89.8 90.0 86.7 90.1 90.5 94.2 88.7
92.7 91.5 93.4 89.3 100.3 90.8 92.7 93.3 89.9 96.1 91.1 87.6 90.1 89.3 86.7
Required:
Construct a stem-and-leaf display for these data. Calculate the median and quartiles of these data.
Answer:
[tex]Median = 90.4[/tex]
[tex]Q_1 = 88.6[/tex]
[tex]Q_3 = 92.2[/tex]
Step-by-step explanation:
Given
The above data
Required
- A stem and leaf display
- The median
- The quartiles
First, determine the range of the data
[tex]Smallest = 83.4[/tex]
[tex]Highest = 100.3[/tex]
Next, group each dataset base on common whole numbers.
So, we have:
[tex]83.4[/tex]
[tex]84.3\ 84.3[/tex]
[tex]85.3[/tex]
[tex]86.7\ 86.7\ 86.7[/tex]
[tex]87.4\ 87.5\ 87.6\ 87.7\ 87.8\ 87.9[/tex]
[tex]88.2\ 88.3\ 88.3\ 88.3\ 88.4\ 88.5\ 88.5\ 88.6\ 88.6\ 88.7\ 88.9[/tex]
[tex]89.0\ 89.2\ 89.3\ 89.3\ 89.6\ 89.7\ 89.8\ 89.8\ 89.9\ 89.9[/tex]
[tex]90.0\ 90.1\ 90.1\ 90.1\ 90.3\ 90.4\ 90.4\ 90.4\ 90.5\ 90.6\ 90.7\ 90.8\ 90.9[/tex]
[tex]91.0\ 91.0\ 91.0\ 91.1\ 91.1\ 91.1\ 91.2\ 91.2\ 91.2\ \ 91.5\ 91.6\ 91.6\ 91.8\ 91.8[/tex]
[tex]92.2\ 92.2\ 92.2\ 92.3\ 92.6\ 92.7\ 92.7\ 92.7[/tex]
[tex]93.0\ 93.2\ 93.3\ 93.3\ 93.4\ 93.7[/tex]
[tex]94.2\ 94.2\ 94.4\ 94.7[/tex]
[tex]96.1\ 96.5[/tex]
[tex]98.8[/tex]
[tex]100.3[/tex]
Next, we construct the stem and leaf plot.
The whole numbers will be the stem while the decimal parts will be the leaf.
So, we have:
[tex]\begin{array}{ccc}{Stem} & {} & {Leaf} & {83} & {|} & {.4} & {84} & {|} & {.3\ .3} & {85} & {|} & {.3} & {86} & {|} & {.7\ .7\ .7} & {87} &{|} & {.4\ .5\ .6\ .7\ .8\ .9} & {88} & {|} & {.2\ .3\ .3\ .3\ .4\ .5\ .5\ .6\ .6\ .7\ .9} &{89} & {|} & {.0\ .2\ .3\ .3\ .6\ .7\ .8\ .8\ .9\ .9} & {90} & {|} &{.0\ .1\ .1\ .1\ .3\ .4\ .4\ .4\ .5\ .6\ .7\ .8\ .9} & {91} &{|}&{.0\ .0\ .0\ .1\ .1\ .1\ .2\ .2\ .2\ .5\ .6\ .6\ .8\ .8} &{92} &{|} &{.2\ .2\ .2\ .3\ .6\ .7\ .7\ .7} \ \end{array}[/tex]
[tex]\begin{array}{ccc} {93} & {|} & {.0\ .2\ .3\ .3\ .4\ .7} & {94} &{|} & {.2\ .2\ .4\ .7} &{96} & {|} & {.1\ .5} & {98} & {|} & {.8} & {100} &{|} &{.3} \ \end{array}[/tex]
From the above plot,
[tex]n = 83[/tex]
The median is calculated as:
[tex]Median = \frac{n+1}{2}th[/tex]
[tex]Median = \frac{83+1}{2}th[/tex]
[tex]Median = \frac{84}{2}th[/tex]
[tex]Median = 42nd[/tex]
i.e. the median is at the 42nd position.
From the above stem and leaf plot.
The 42nd position is at stem 90 and the leaf .4
So the median is:
[tex]Median = 90.4[/tex]
The lower quartile (Q) is calculated as:
[tex]Q_1 = \frac{n+1}{4}th[/tex]
[tex]Q_1 = \frac{83+1}{4}th[/tex]
[tex]Q_1 = \frac{84}{4}th[/tex]
[tex]Q_1 = 21st[/tex]
i.e. the lower quartile is at the 21st position.
From the above stem and leaf plot.
The 42nd position is at stem 88 and the leaf .6
So the lower quartile is:
[tex]Q_1 = 88.6[/tex]
The upper quartile (Q3) is calculated as:
[tex]Q_3 = 3 * \frac{n+1}{4}th[/tex]
[tex]Q_3 = 3 * \frac{83+1}{4}th[/tex]
[tex]Q_3 = 3 * \frac{84}{4}th[/tex]
[tex]Q_3 = 3 * 21th[/tex]
[tex]Q_3 = 63rd[/tex]
i.e. the upper quartile is at the 63rd position.
From the above stem and leaf plot.
The 63rd position is at stem 92 and the leaf .2
So the upper quartile is:
[tex]Q_3 = 92.2[/tex]