PQ and QR are 2 sides of a regular 12-sided polygon.
PR is a diagonal of the polygon.

Work out the size of angle PRQ.
You must show your working.

Answer:

Step-by-step explanation:

Answer:

a) x<0

Step-by-step explanation:

the circle is not solid so it’s just a less than a sign and the arrow is going less than 0 so x is less than 0 is the answer

hope this helps :)

Answer:

It is rational because 121 is a perfect square.

Answer:

a) x = 3

b) z = 10

c) p = 2

d) x = 7

e) u = 1

Step-by-step explanation:

a) 2x = 6

Despejamos x dividiendo por 2 a amabos lados de la eacuacion.

(2/2)x = 6/2

x = 3

Si remplazamos x en la ecuación original:

2(3)=6

6 = 6

Queda demostrado.

b) 10 + z = 20

Despejamos z restando 10 en amabos lados de la eacuacion.

10-10+z = 20-10

z = 10

Si remplazamos z en la ecuación original:

10 + 10=20

20 = 20

Queda demostrado.

c) p + 9 = 11

Despejamos p restando 9 en amabos lados de la eacuacion.

p + 9 - 9 = 11-9

p = 2

Si remplazamos p en la ecuación original:

2 + 9 = 11

11 = 11

Queda demostrado.

d) 3x + 8 = 29

Despejamos x restando 8 en amabos lados de la eacuacion y luego divideindo por 3 en ambos lados de la ecuación.

3x+8-8 = 29-8

3x = 21

(3/3)x = 21/3

x = 7

Si remplazamos x en la ecuación original:

3(7) + 8 = 29

21 + 8 = 29

29 = 29

Queda demostrado

e) 2u + 8 = 10

Despejamos u restando 8 en amabos lados de la eacuacion y luego divideindo por 2 en ambos lados de la ecuación.

2u+8-8 = 10-8

2x = 2

(2/2)x = 2/2

x = 1

Si remplazamos x en la ecuación original:

2(1) + 8 = 10

2 + 8 = 10

10 = 10

Queda demostrado

Espero te haya sido de ayuda!

Answer:

Step-by-step explanation:

Putting value of n = 12

f(12) = 128 + 15(12 - 1)

= 128 + 180 - 15

= 293

Answer:

The pentagon MNPQR has a perimeter of 22 units.

Step-by-step explanation:

Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

[tex]p = MN + NP + PQ + QR + RM[/tex] (1)

[tex]p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}[/tex] (1b)

If we know that [tex]M(x,y) = (2,4)[/tex], [tex]N(x,y) = (5,8)[/tex], [tex]P(x,y) = (8,4)[/tex], [tex]Q(x,y) = (8,1)[/tex] and [tex]R(x,y) = (2,1)[/tex], then the perimeter of the pentagon MNPQR is:

[tex]p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}[/tex][tex]p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}[/tex]

[tex]p = 22[/tex]

The pentagon MNPQR has a perimeter of 22 units.

The pentagon MNPQR has a perimeter of 22 units.

Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

p = MN + NP + PQ + QR + RMp=MN+NP+PQ+QR+RM (1)

p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}p=

MN

∙

MN

+

NP

∙

NP

+

PQ

∙

PQ

+

QR

∙

QR

+

RM

∙

RM

(1b)

If we know that M(x,y) = (2,4)M(x,y)=(2,4) , N(x,y) = (5,8)N(x,y)=(5,8) , P(x,y) = (8,4)P(x,y)=(8,4) , Q(x,y) = (8,1)Q(x,y)=(8,1) and R(x,y) = (2,1)R(x,y)=(2,1) , then the perimeter of the pentagon MNPQR is:

p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}p=

(5−2)

2

+(8−4)

2

+

(8−5)

2

+(4−8)

2

+

(8−8)

2

+(1−4)

2

+

(2−8)

2

+(1−1)

2

+

(2−2)

2

+(4−1)

2

p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}p=

3

2

+4

2

+

3

2

+(−4)

2

+

0

2

+(−3)

2

+

(−6)

2

+0

2

+

0

2

+3

2

p = 22p=22

The pentagon MNPQR has a perimeter of 22 units.

Answer:

14/20 times 6/20=84/400=21/100

Step-by-step explanation:

Answer:

f(x) = 10x - 27. I can't find the answer anywhere

Step-by-step explanation:

(-∞,-10)∪(-10,-2)∪(-2,∞)

Or

[tex]\left\{x|x\ne-2,-10\right\}[/tex]

Both are correct.

Answer:

18/18 is fractions

16/16 is fractions

Step-by-step explanation:

18/18x16/16=1

Theres your answer.

Answer:

78 is the range of high temperature

Answer:

33

Step-by-step explanation:

f(3) = 8(3) + 9 = 24 + 9 = 33

Answer:

33 is the answer.

Step-by-step explanation:

9514 1404 393

Answer:

  C

Step-by-step explanation:

Both inequalities have y ≤ ( ), so will be bounded by solid lines, and shaded below that line (where y-values are lower). The first inequality has a boundary line with a steeply negative slope; the second has a shallow positive slope.

Since both are shaded below, the doubly-shaded area (AB) will be in the bottom quadrant, below the point of intersection of the lines. The graph attached below shows the correct shading.

Answer:

C≈34.56, C≈25.13 and C≈18.85

Step-by-step explanation:

Using the formulas

C=2πr

d=2r

Solving for C

C=πd=π·11≈34.55752

Using the formulas

C=2πr

d=2r

Solving for C

C=πd=π·8≈25.13274

Using the formulas

C=2πr

d=2r

Solving for C

C=πd=π·6≈18.84956

Answer:

75

Step-by-step explanation:

Scores for his first tests were 65, 67, 69.

Rate of change: +2

y=2x+63; 63 is the 0th test he took, his first test was 65, so 65-2=63. 2x is the rate of change, his tests scores increase by 2 each time.

x=6, 6th test score

y=2(6)+63

y=12+63

y=75

So, on his 6th test he will get a score of 75

Answer:

The numbers are blurry on the graph

Answer:

50.6

Step-by-step explanation:

MA=46.2-14=32.2

We have similar triangles.

That is, triangle MNP is similar to MAB.

This means, we have the following proportion to solve:

32.2/46.2=x/72.6

Multiply both sides by 72.6

32.2/46.2*72.6=x

50.6=x

Answer:

[tex]3d^3[/tex]

Step-by-step explanation:

The contents of the box must make

[tex]7d^3 - \text{ BOX } = 4d^3[/tex]

To get [tex]7d^3[/tex] down to [tex]4d^3[/tex], you have to subtract [tex]3d^3[/tex]

Answer:

706.86m

Step-by-step explanation:

Square the radius, then multiply by pi.

Answer:

17) 135 degrees

Step-by-step explanation:

An octagon contains six triangle, or 1080 degrees, meaning each angle is 135 degrees.

Step-by-step explanation:

1. an octagon contain 6 triangles or 1080 degrees this means with 8 angles each angle is 135 degrees

Answer:

850

Step-by-step explanation:

500 times 0.7 plus 500

Answer:

∠ X = 80° , ∠ V = 60°

Step-by-step explanation:

(a)

Since XY and WX are congruent then the triangle is isosceles and the 2 base angles are congruent, that is

∠ W = ∠ Y = 50° , so

∠ X = 180° - (50 + 50)° ← sum of angles in triangle

∠ X = 180° - 100° = 80°

(b)

Since the 3 sides are congruent then the triangle is equilateral with the 3 angles congruent, each 60°

∠ V = 60°

Let's solve your system by elimination.

8x+y=−16;3x−y=5

8x+y=−16

3x−y=5

Add these equations to eliminate y:

11x=−11

Then solve: 11x=−11 for x:

11x=−11

11x

11

=

−11

11

(Divide both sides by 11)

x=−1

Now that we've found x let's plug it back in to solve for y.

Write down an original equation:

8x+y=−16

Substitute: −1 for x in 8x+y=−16:

(8)(−1)+y=−16

y−8=−16(Simplify both sides of the equation)

y−8+8=−16+8(Add 8 to both sides)

y=−8

Answer:

x=−1 and y=−8

Answer:Multiply each equation by a suitable number so that the two equations have the same leading coefficient.

Subtract the second equation from the first.

Solve this new equation for y.

Substitute y = 2 into either Equation 1 or Equation 2 above and solve for x.

Step-by-step explanation: