QUESTION 11 1. Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 85 individuals and H5/H5=24 individuals. Using the allele's frequencies experimentally derived, calculate the frequency of the H4/H5 genotype that would be expected if the class were a population in Hardy-Weinberg equilibrium. 1. 0.28 2. 0.51 3. 0.19 4. 0.72 5. 0.14 6. 0.24 7. 0.41 QUESTION 12 1. Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 85 individuals and H5/H5=24 individuals. Using the genotype frequencies derived assuming that the class were a population in Hardy-Weinberg equilibrium, calculate the number of H4/H4 individuals that would be expected in the class (rounded numbers). 1. 19 2. 57 3. 72 4. 147 5. 171 6. 120 7. 96 QUESTION 13 1. Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 85 individuals and H5/H5=24 individuals. Considering the Hardy Weinberg equilibrium and comparing the observed and the expected number of individuals for the three genotypes, calculate the value of the Chi-square statistic 1. 2.69 2. 0.05 3. 28.67 4. 14.59 5. 0.50 6. 22.31 7. 3.84 QUESTION 14 1. Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 85 individuals and H5/H5=24 individuals. Considering the Hardy Weinberg equilibrium, which is the (correct) null hypothesis tested by Chi-square? 1. The whole class represents a population that is in Hardy-Weinberg equilibrium 2. The whole class represents a population that may not be in Hardy-Weinberg equilibrium 3. The whole class represents a population that is not in Hardy-Weinberg equilibrium 4. The whole class represents a population that may be in Hardy-Weinberg equilibrium QUESTION 15 1. Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 85 individuals and H5/H5=24 individuals. Considering the Hardy Weinberg equilibrium and calculating the Chi-square statistic, do you reject or fail to reject the null-hypothesis? 1. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis. 2. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom, I conclude that P>0.05. Hence, I fail to reject the null hypothesis. 3. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom I conclude that P<0.05. Hence, I reject the null hypothesis. 4. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom I conclude that P<0.05. Hence, I fail to reject the null hypothesis.

Answers

Answer 1

According to Hardy-Weinberg, when a population is in equilibrium, it will have the same allelic frequencies generation after generation, meaning that they are stable, they are not evolving.

When any evolutive force is acting on the population, this equilibrium breacks, and allelic and genotypic frequencies change through generations, differing from the expected ones.  

A) Option 7 is the correct answer ⇒ 0.41

B) Option 6 is the correct answer ⇒ 120

C) Option 7 is the correct answer ⇒ 3.84

D) Option 1 is the correct answer ⇒ The class represents a population that is in H-W equilibrium

E) Option 1 is correct. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for  the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis.

-------------------------------------------

Allelic frequencies in a locus are represented as p and q, referring to the

allelic dominant or recessive forms. The genotypic frequencies after one generation are p² (H0m0zyg0us  dominant), 2pq (H3ter0zygous), (H0m0zyg0us recessive). Populations in H-W equilibrium will get the same

allelic frequencies generation after generation.

The sum of the allelic frequencies equals 1, this is p + q = 1.

In the same way, the sum of genotypic frequencies equals 1, this is

p² + 2pq + q² = 1

Being

 p the dominant allelic frequency,

 q the recessive allelic frequency,

 p² the h0m0zyg0us dominant genotypic frequency

 q² the h0m0zyg0us recessive genotypic frequency

 2pq the h3ter0zyg0us genotypic frequency

 

Situation: Through PCR, we have determined the PER3 genotypes for a class of students as follows:

 H4/H4 = 125 individuals;

 H4/H5 = 85 individuals;

 H5/H5=24 individuals.

⇒ Total number of individuals= 125 + 85 + 24 = 234

⇒ Genotypic frequencies, F(xx):

 F(H4/H4) = 125/234 =0.534

 F(H4/H5) = 85/234 = 0.363

 F(H5/H5) = 24/234 = 0.102

⇒ Allelic frequencies, f(x):

 f(H4) = p = F(H4/H4) + 1/2 F(H4/H5) = 0.534 + 0.363/2 = 0.534 + 0.182 = 0.716

 f(H5) = q = F(H5/H5) + 1/2 F(H4/H5) = 0.102 + 0.363/2 = 0.102 + 0.182 = 0.284

Questions:

A)  According to the theoreticall frame, we know that 2pq is the h3ter0zygous genotypic frequency. So,  

F(H4/H5) = 2pq = 2 x 0.716 x 0.284 = 0.408 ≅ 0.41 ⇒ Option 7 is the correct answer.

-------------------------------------------------------------------------------------------------------------

B)  According to the theoreticall frame, we know that p² is the h0m0zyg0us genotypic frequency. So,

p = 0.716

p² = 0.5126 ≅ 0.513 ⇒ This is the genotypic frequency.

To calculate the number of individuals carrying this genotype, we need to multiply it by the total number of

individuals.

H4/H4 individuals = p² x total number of individuals = 0.513 x 234 = 120

Option 6 is the correct answer.

-----------------------------------------------------------------------------------------------------------

C)  Up to here we know that 2pq = 0.41 and p² = 0.513

Now we need to calculate q ²

q = 0.284, then q² = 0.284² = 0.08

These are the expected frequencies if the population was in H-W equilibrium.

The expected number of individuals with each genotype are:

 H4/H4 = 0.513 x 234 = 120 individuals

 H4/H5 = 0.41 x 234 = 96 individuals

 H5/H5= 0.08 x 234 = 18 individuals

The observed number of individuals with each genotype are:

 H4/H4 = 125 individuals

 H4/H5 = 85 individuals

 H5/H5=24 individuals

X² = ∑ (Observed - Expected)²/Expected)

X² = ((125-120)²/120) + ((85 - 96)²/96) + ((24-18)²/18)

X² = 0.21 + 1.26 + 2 =

X² = 3.47

The clossest option is option 7 = 3.84. The difference might be related to decimals and rounding.

-------------------------------------------------------------------------------------------------------------

D)  The correct answer is  1 ⇒ The whole class represents a population that is in Hardy-Weinberg equilibrium

The null hypothesis always predict that populations are in H-W equilibrium.

-----------------------------------------------------------------------------------------------------------

E)  

 X² = 3.47

 Freedom degrees = n - 1 = 3 - 1 = 2

 Table p value: 7.82

 Significance level, 5% = 0.05

 Table value/Critical value = 5.991

5.991 > 0.347

Meaning that the difference between the observed individuals and the expected individuals is statistically  significant. Not probably to have differe by random chances. There is enough evidence to reject the null

hypothesis.

Option 1 is correct. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for  the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis.

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Related Questions

An element has an atomic mass number of 16 and an atomic number of 7. The element has protons and neutrons. Reset Next

Answers

the answer of this question is answer b

Fill in the bottom line of DNA with the complementary base pair:

Answers

Answer: ACCTGATCGTAGCT

Explanation:

Keep in mind that in DNA replication, the matching base pairs are A and T (adenine and thymine) and C and G (Cytosine and Guanine). This means that for DNA complementary strands, A's can ONLY bind with T's and C's can only bind with G's , and vice versa. So, your answer for the picture you have given is ACCTGATCGTAGCT

which of the following is a major determinant of the distribution pattern of a population?
1 social interactions
2 habitat area
3 rate of population growth
4 the ages of the individuals

Answers

Answer:

rate of population growth

what did Rudolf virchow discovered?

Answers

Answer:

Explanation:

In 1855 Virchow published a statement based on his observations Omnis cellula e cellula, which means that all cells arise from pre-existing cells. This was not a new theory.

For which of the following phenomena is intrinsic affinity necessarily more important than functional affinity?
A. Antibody-mediated opsonization of encapsulated bacterial pathogens
B. Assay using antibodies to detect small drugs in solution
C. Binding of C1q to immunoglobulin G (IgG) or IgM
D. Binding of neutralizing IgG antibodies to nonenveloped viruses​

Answers

Explanation:

B. Assay using antibodies to detect small drugs in solution

hope this helps you

have a nice day

Two organisms, AABBCCDDEE and aabbccddee, are mated to produce an F1 that is self-fertilized. If all of these genes are on the same chromosome, and there is no recombination, how many different genotypes will occur in the F2

Answers

Answer:

2 genotypes: AABBCCDDEE; aabbccddee

Explanation:

The law of segregation (also called Mendel's First Law) describes how genes on different chromosomes segregate into gametes independently of each other. Moreover, recombination (also known as crossing over) is the interchange of genetic material between non-sister chromatids during meiosis. In this case, the five genes are on the same chromosome (i.e., they are linked together and do not segregate) and there is no recombination, thereby they are inherited as a haplotype block to the next generation:

- Genotypes parental (P) lines: AABBCCDDEE; aabbccddee

- Cross P1: ABCDE X abcde

- Genotype F1: AaBbCcDdEe (100%)

- Gametes F1: ABCDE; abcde

- Genotypes F2: AABBCCDDEE; aabbccddee (ratio 1:1)

Porque voy a estudiar nutrición y dietética?

Answers

Answer:

La carrera de nutrición y dietética forma profesionales altamente capacitados en el campo de la salud desde una perspectiva de la alimentación

Explanation:

La alimentación es un aspecto clave en la vida que se encuentra relacionado directamente con la cantidad y calidad de los alimentos que ingerimos, lo cual es fundamental para tener una vida saludable y desarrollar un estado de bienestar tanto físico como emocional. La carrera de nutrición y dietética pertenece al área de la salud y tiene como objetivo formar profesionales que se encuentren altamente especializados para el desarrollo de programas de alimentación adecuados, teniendo en cuenta las características intrínsecas de los grupos de alimentos, sus propiedades y los requerimientos personalizados para cada paciente. En consecuencia, los profesionales en nutrición y dietética desarrollan un conocimiento profundo acerca de cuales son los requerimientos en macronutrientes (proteínas, hidratos de carbono y lípidos) y micronutrientes (vitaminas y minerales) para cada individuo, esto con la finalidad de adaptar la alimentación de acuerdo a su edad, peso corporal, estatura, etc. Los profesionales en este campo poseen además conocimientos avanzados en biología humana, bioquímica, química orgánica, como así también desarrollan aptitudes en psicología y salubridad alimentaria.

Which of the following factors would LIMIT carrying capacity?
A. Far from factories or roads
B. A large nearby river
C. Abundant food
D. A small space to live in

Answers

Answer:

D. A small space to live in

Explanation:

Having a small space to live in would directly limit carrying capacity.

Since there is a small space, only a few organisms would be able to live in that space.

This means that carrying capacity is limited, because the space does not have enough room to sustain more people.

So, the correct answer is D. A small space to live in

ASAP
A species of Coral snake has a red, yellow and black stripe pattern. One
gene controls if the stripes are thick or thin. Thin (T) is dominant over
thick (t). If two snakes heterozygous for this gene are crossed, what will
be the genotype(s) of their offspring? You may need to use a Punnett
square to answer the question.
Question Progress
OA. TT and Tt
B. TT, Tt, and tt
C. TT and tt
D. All Tt

Answers

B . , because I remember this

The genetic attributes of the organism are determined by the genotype. The cross of the heterozygous genes in Coral snakes results in offsprings with TT, Tt, and tt. Thus, option B is correct.

What are genes?

Genes are the functional and physical basis of the inheritance that passes from generation to offspring with various traits and attributes. The gene contains a recessive and a dominant allele.

Heterozygous genes are represented as Tt as it contains one dominant and one recessive allele. The cross between the two heterozygous (Tt) Coral snakes is attached to the image below.

From the cross, it can be seen that 75 % of the coral snakes have thin strips while the 25 % of the species have thick strips. The ratios are:

Genotype = 1 : 2 : 1

Phenotype = 1 : 3

Therefore, option b. the genotype(s) of the offspring will be TT, Tt, and tt.

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What are the following is considered a receptive a fine touch

Answers

Explanation:

This system is responsible for all the sensations we feel – cold, hot, smooth, rough, pressure, tickle, itch, pain, vibrations, and more. Within the somatosensory system,there are four main types of 1.receptorsme chanoreceptors, 2.thermoreceptors,3. pain receptors, and 4. proprioceptors.

Which of these is the best definition of sustainable development?
A. Development that makes sure buildings are strong enough to sustain large hurricanes and earthquakes
B. Development that's typical of underdeveloped nations that derive their products directly from nature
C. Development that's supported by public opinion
D. Development that ensures the protection of the environment in the long term

Answers

Answer:

option D

Explanation:

is the correct answer

Development which basically ensures the protection of the environment in the long term is sustainable development. The correct option is D.

What is sustainable development?

Sustainable development is defined as growth that fulfills the requirements of the moment without jeopardizing future generations' capacity to meet their own needs.

The financial, social, and environmental measurements of sustainable development are examined.

The authors contend that material-intensive conventional productivity recovery is unsustainable in the long term unless environmental and social factors are prioritized equally.

Environmental protection aims to preserve as well as restore a healthy natural environment.

Sustainable development incorporates ecologic, social, and economic goals in order to achieve long-term equitable growth that benefits both the present and the future.

Thus, the correct option is D.

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What theory explains why the Uranian system is on its side?

Answers

Answer:

Astronomers have always assumed that Uranus must have been knocked onto its side by a collision. Now a new idea suggests that the planet's remarkable tilt could have another explanation.

Explanation:

I just know it

Answer:

Astronomers have always assumed that Uranus must have been knocked onto its side by a collision. Now a new idea suggests that the planet’s remarkable tilt could have another explanation.

by Emerging Technology from the arXivarchive page

December 3, 2009

One of the great mysteries of our Solar System is why Uranus is tilted on its side. Surely, if the solar system formed from the same rotating cloud of dust and gas, then all the bodies within it should rotate in the same way. And yet Uranus’ axis of rotation lies at 97 degrees to the plane of the solar system.

If you were given the power to control the United States government and policy what changes would you make regarding the environment and how would you fund these? You can consider your response to the question and/or include other issues.

Answers

Answer:

i would probably fund different jails using taxes. there's absolutely no reason someone who accidently committed tax fraud should be sitting in the same cell as aconvicted murderer. & abd I would make harder consequences for hate crimes. like jail time.

You classified organisms based on anatomical structure and development. Scientists also use DNA to classify organisms. Considering the basic process of evolution, why do you think it’s important to also consider DNA and gene patterns during the classification of organisms?

Answers

Answer:

By studying genetics and DNA, we can get the best idea of how species are related to each other, and therefore how to classify them. The genetic code of a species is not fixed, however. It changes over time! This is why we also need to factor in evolution.

It is important to also consider DNA and gene patterns during the classification of organisms because,

Through genetics and DNA study, we can get the idea of how species are related to each other and how to classify them. The genetic code of a species is not fixed. So, it need in evolution.

How organism classified ?The organism classified on the basis of shared characteristics.The classification of living organism includes seven levels, kingdom, phylum, classes, order, families, genus and species.

What is evolution?It is witness in the living species and change in heritable traits of biological population over successive generation.The process of development of complex organism from simpler one with time is called an evolution.

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How would you
change the hypothesis if mussels died in
both aquariums?

Answers

The new hypothesis could be that there is another alternative factor that is negativey afecting dwarfs survivorship.

The previous hypothesis of high levels of phosphate killing mussels is not necessarily disproved.  But the death of mussels from both the control and the treatment groups might be related to one of the controlled variables that could be actually afecting them.      

----------------------

Probably different levels of phosphate are also affecting invididuals´ survivor rates. However, the fact that mussels from all the aquariums died suggests that there is something else going on that caused the death of all the individuals.    

The control group is used to identify any other factors influencing the results obtained in the study, apart from the modified variables of the treatment.  Individuals of the control group are selected from the same population as the treatment group. These two groups are identical in all aspects except for the independent variable, which changes in the treatment group but remains constant in the control group.

We know that mussels in this experiment were taken from the same population and grown under the same controlled conditions. Only the treatment group received phosphate, but all mussels died, not only the ones that receive phosphate. This result turns to be useful because it is indicating that there is another variable that is killing mussels. Phosphate might be a cause of death, but there is also something else. So the researchers should pay attention to the controlled variables, such as water quality, temperature, pH, food supply, light exposure, or others.  

These variables might be reflecting the real conditions under which mussels live. The results tell that one of these is related to individual death and could be a consequence of climate change or soil use, among other causes.    

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From a chemical view, how is an amino acid is being recognized by its specific aminoacyl tRNA synthetase?

Answers

Answer:

An aminoacyl-tRNA synthetase (aaRS or ARS), also called tRNA-ligase, is an enzyme that attaches the appropriate amino acid onto its corresponding tRNA. It does so by catalyzing the transesterification of a specific cognate amino acid or its precursor to one of all its compatible cognate tRNAs to form an aminoacyl-tRNA.

hi, define chemistry and mention the three branches of chemistry answer it fast .Good night​

Answers

Explanation:

Branches of inorganic chemistry include: ... Nuclear chemistry — the study of radioactive substances. Organometallic chemistry — the study of chemical compounds containing bonds between carbon and a metal. Solid-state chemistry — the study of the synthesis, structure, and properties of solid materials.

Answer:

The five primary branches of chemistry are physical chemistry, organic chemistry, inorganic chemistry, analytical chemistry, and biochemistry.

what are three characteristics of life that archaea bacteria have?

Answers

Answer:

The common characteristics of Archaebacteria known to date are these:

(1) the presence of characteristic tRNAs and ribosomal RNAs.

(2) the absence of peptidoglycan cell walls, with in many cases, replacement by a largely proteinaceous coat.

(3) the occurrence of ether linked lipids built from phytanyl chains.

Suppose a researcher introduces a mutation into the glucosidase domain of the mammalian glycogen debranching enzyme. The mutation inhibits the activity of the glucosidase but does not affect the other functions of the enzyme. The researcher then introduces the mutated enzyme into mammalian cells that do not express wild type glycogen debranching enzyme. Predict the effect of the mutation on glycogen metabolism.

Answers

Answer:

cells will have glycogen molecules with branches of a single glucose residue

Explanation:

Glycogen debranching enzymes are proteins that catalyze the removal of branching from glycogen, which is a multibranched polysaccharide composed of glucose units and serves as a form of energy storage. These enzymes have two catalytic activities on a single polypeptide chain: glucosyltransferase and glucosidase activities, which are both required for glycogen breakdown. Glycogen degradation requires both glycogen phosphorylase and glycogen debranching enzymes. First, a glycogen phosphorylase acts to digest a glycogen branch down to four glucose residues. Subsequently, the debranching enzyme through its glucosyltransferase activity acts to transfer three glucose residues to a nearby branch of the glycogen chain. Finally, through its glucosidase activity, the debranching enzyme cleaves the remaining α-1,6 linkage in order to release free glucose.

packaging methods of watermelon ​

Answers

Answer:

The packing process consists of:

The workers remove the watermelons from the bulk cardboard bins and place them onto the packing line.

The watermelons pass through three different brush steps (without the use of any wash water)

The watermelons are labeled and packed into large cardboard bins once again.

Explanation:

1. Biochemical and differential tests can be incorporated into growth media or performed on isolated colonies after they have been cultured. Give three examples of a differential test that is incorporated into media and three examples that are applied after the colonies have been cultured.

Answers

Answer:

Biochemical and differential tests can be incorporated into growth. media or performed on isolated colonies after they have been cultured. ... Three examples of biochemical tests that are done on the colonies are catalase test, indole test, and urease test.

Which of the following counteracts the movement of bicarbonate ions from the RBC?
A) chloride shifting
B) the Haldane effect
C) release of hydrogen ion
D) the Bohr effect​

Answers

Answer:

A) chloride shifting

Explanation:

because in movement of bicarbonate ion, there. is exchange of carbonic acid and chloride ion in RBC which is called chloride shift.

Answer: A. chloride shifting

Please help me with this.

Answers

Answer:

D

Explanation:

Gene pool is the total genetic diversity within a population or species

Answer:

D

Explanation:

hope it helps.

discuss the reaction in tricarboxylic acid cycle​

Answers

The tricarboxylic acid cycle​ also known as the Kreb's cycle consists of eight cycle wherein a molecule of acetylCoA is used to produce three NADH, one FADH2 and one GTP/ATP molecule.

What is the tricarboxylic acid cycle?

The tricarboxylic acid cycle is a sequence of reactions in which acetylCoA molecules from the glycolytic pathway are used to produce the reducing equivalents NADH ad FADH2 which are used to produce ATP in the electron transport chain.

The tricarboxylic acid cycle​ also known as the Kreb's cycle consists of eight cycle wherein a molecule of acetylCoA is used to produce three NADH, one FADH2 and one GTP molecule.

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White Leaf Disease is a devastating disease that
affects sugar cane crops in Thailand and has become a
major issue for farmers. The disease starts with a white
line forming in the center of the sugar cane's leaves,
which can change in size and shape as it develops.The sugar cane's new leaves will become increasingly whiter, often having stunted growth, and resulting in the sugar cane being less productive than the non-
infected plants, Scientists are trying to determine
what organelle must be damaged to produce the
observed results,

Answers

White leaf disease is caused by phytoplasma. The disease infects the leaves and create white spots in them.

The farmers in Thailand are facing this issue with sugarcane crops. The organisms infect phloem tissues in sugar cane and cause the leaves to turn white.

The size and shape can change as sometimes there are fine white lines created while sometime there are white spots.

Scientists are trying to deal with such disease and an spray of liquid copper has been found beneficial to treat this disease. The white spot fungus stops to spread with the spray.

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the different between microspores and pollen grain

Answers

The key difference between microspore and pollen grain is that microspore is the small spore that develops into the male gametophyte in plants while pollen grain is the small grain that contains the male gametophyte.

What is the correct order of amino acid if the sequence of bases on DNA were as follows: C-C-T-C-G-A-T-T-C-A-T-G
glycine, alanine, lysine, tyrosine

2)

alanine, proline, lysine, tyrosine

3)

valine, aspartate, glycine, proline

4)

aspartate, glycine, serine, valine

Answers

Answer:

it should be G-G-A-G-C-T-A-A-G-T-G-C

Explanation:

A=T

C=G

think of them as opposites. invert them and you'll have the answer (its easier if you write the answer right underneath)

The amino acid sequence should be G-G-A-G-C-T-A-A-G-T-G-C

G-G-A: glycine

G-C-T: alanine

A-A-G: lysine

T-G-C:  tyrosine

What are amino acids?

Amino acids are molecules that combine to form proteins. Amino acids and proteins are the building blocks of life.

The nucleotide triplet that encodes an amino acid is called a codon. Each group of three nucleotides encodes one amino acid. There are 64 combinations of 4 nucleotides taken three at a time and only 20 amino acids, the code is degenerate (more than one codon per amino acid, in most cases).

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Researchers note that a plant closes its stomata on a hot, dry, windy day. What statement describes the plant response to these
conditions?
A)
The stomatal closings and the environmental conditions are unrelated for this plant.
B)
The stomatal closings and the environmental conditions are unrelated for
this plant.
Water loss and water stress is highest on hot, dry, windy days, so the plant
closes stomata to conserve water.
Hot, dry, windy days are not conducive to pollen spread, so the plant closes
its stomata to prevent pollination.
Photosynthesis is decreased on hot, dry, windy days, so the plant closes its
stomata to prevent carbon dioxide diffusion.
a
D)

Answers

Answer:

It is B

Explanation:

i just took it

If a plant closes its stomata on a hot, dry, and windy day, the plant response to these conditions is water loss and water stress is highest on hot, dry, windy days. So, the plant closes its stomata to conserve water.

What do you mean by Stomata?

Stomata are the tiny pores present on the surface of the leaves. A huge amount of gaseous exchange may take place in the leaves through these pores for the purpose of photosynthesis.

During photosynthesis, these stomatal pores take carbon dioxide and water is gradually lost, in order to prevent this water loss in hot and humid conditions, the plant closes its stomata.

Therefore, if a plant closes its stomata on a hot, dry, and windy day, the plant response to these conditions is water loss and water stress is highest on hot, dry, windy days. So, the plant closes its stomata to conserve water.

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Exchange of gases in plants occur through:
(A): Stomata.
(B):Lenticels.
(C):Root surface.
(D):Choloroplast.

(1)A,B and D
(2)A,B,CandD
(3)AandC
(4)A,BandC

Answers

Answer:

(A): through the stomata

__________Are the subunits making up nucleic acids

Answers

Answer:

Nucleotides.

Explanation:

Nucleic acids (DNA, RNA) are large polymers, made out of monomer building blocks called nucleotides. The nucleotides have a similar structure with three 'subunits': A phosphate group

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