Question 14 Choco Worth 3 points)
FW The graph below shows the trends in water use in the United States from 1950 to 2000,
300
250
500
450
1400
2001-
-Total withdrawaly
1350
MOUNT OF WATER WITHDRAWN
PER DAY FOR IRRIGATION
(IN SILLION GALLONS
1501
300
250
TOTAL AMOUNT OF WATER WITHDRAWN
PER DAY (IN BILLION GALLONS)
100
-200
1500
150
100
50
1950 1955 1960 1965 1970 1975 1980 1985 1990 1995 2000
YEARS
Based on the graph, a student would most likely conclude that, from 1950 to 2000, the total amount of Water used for irrigation is approximately
half of the total water withdrawn
one fifths of the total water withdrawn
one sixths of the total water withdrawn
two fifths of the total water withdrawn

Answer:

191.4K

Explanation:

Using the ideal gas law equation as follows:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question:

n = 4.2moles

P = 5.5atm

V = 12.0 L

T = ?

Using PV = nRT

5.5 × 12 = 4.2 × 0.0821 × T

66 = 0.345 T

T = 66/0.345

T = 191.4K

Answer:

4

Explanation:

because it has 3 carbons  and 6 hydrogen

hope this helps :)

Answer:

The solute is salt and the solvent is water

Explain:

Because salt is a component the dissolves in the solvent

Where is ur question ⁉️

Answer:

2

Explanation:

You write your answer with the same number of significant figures as the number with the smallest amount of figures, in this case, that number is 2.1 so your answer should be written with 2 significant figures.

Answer: There are 5.2 moles of Cl are present in 2.6 mol  [tex]CaCl_{2}[/tex].

Explanation:

Given: Moles of [tex]CaCl_{2}[/tex] = 2.6 mol

In a molecule of [tex]CaCl_{2}[/tex] there are 2 atoms of chlorine present. Therefore, moles of chlorine are present as follows.

[tex]2.6 mol CaCl_{2} \times \frac{2 mol Cl_{2}}{1 mol CaCl_{2}}\\5.2 mol Cl_{2}[/tex]

Thus, we can conclude that there are 5.2 moles of Cl are present in 2.6 mol  [tex]CaCl_{2}[/tex].

Answer:

18.45 g of C

Explanation:

This is a problem of rules of three:

1 mol of C₃H₈ contains 3 moles of C and 8 moles of H

If 8 moles of H are contained in 1 mol of propane

4.10 moles of H are contained in (4.1 . 1) /8 = 0.5125 moles

Now, If 1 mol of propane contains 3 moles of C

0.5125 moles of propane may contain (0.5125 . 3) / 1 = 1.5375 moles of C

Let's convert the moles to mass:

1.5375 mol . 12 g /mol = 18.45 g

Answer:

a

Explanation:

Answer:

the correct answer is four decimal places

Answer:

I don't no answer sorry

Explanation:

you follow me

Answer:

IUPAC, which stands for International Union of Pure and Applied Chemistry, has a rules that guides the naming of aliphatic compounds these are explained below.

Explanation:

The International Union of Pure and Applied Chemistry ( IUPAC) has put forward a system of nomenclature which relates the me of the compound to its molecular structure. In this system, every name consists of:

--> A ROOT: This is generally the aliphatic hydrocarbon.

--> the SUFFIX: This is added to the root to indicate the presence of the principal substituent. For example the names of alkanes ends with '-ane'.

--> as many PREFIXES as necessary.

The systematic name of a compound is formed from the root hydrocarbon by adding a suffix and prefixes to denote the substitution of the hydrogen atoms.

Basic rules in to name aliphatic compounds include:

--> Take the longest continuous carbon chain as the root hydrocarbon and name it according to the number of carbon atoms it contains, adding the appropriate suffix to indicate the principal substituent group.

--> Number the carbon atoms in the root hydrocarbon from the end which will give the lowest number to the suffix, and then the prefixes.

--> Indicate the other substituents by prefixes preceded by numbers to show their positions on the carbon chain.

Equilibrium shifts to the right.

OPTION A

Answer:

Explanation:

a

Answer:

Wearing gloves

Explanation:

it helps on not touching chemicals

Answer:

Global Warming

Explanation:

The biggest concern for environmental scientists is Global Warming. Our Earth is getting warmer which is having drastic effects on our planet. Such effects include increased natural fires, decreased water supply, decreased farm yields, increased floodings, etc. Global Warming poses a huge threat to humanity and it is because of humanity's constant and ever growing usage of fossil fuels that Global Warming is becoming such a threat. This is what environmental scientists are mainly focused on.

Explanation:

U can use molar ratio of

Li : Li2SO3

2 : 1

so 3.33÷2=1.665 so 1.67 moles

then u can use the

moles = mass ÷ mr

= 12.33÷ 100.08

= 0.123 moles of CuSO3 then use the molar ratio

CuSO3 : Cu

1:1

so 0.123 moles of cu

hope this make sense:)

Answer:

Volume of the reaction vessel is increased - shift to the left

The reaction is cooled down - shift to the right

H2 is added to the system - shift to the right

The pressure of the system is decreased - shift to the left

A catalyst is added to the system - no change

Water is removed from the system - shift to the right

Explanation:

When a constraint such as a change in temperature, pressure or volume is imposed on a reaction system in equilibrium, the equilibrium position will shift in such a way as to annul the constraint.

When the volume of a reaction system is increased, the equilibrium position shifts in the direction in which there is the highest total volume. This is the left hand side.

Since the reaction is exothermic (heat is given out) when the reaction is cooled down, the forward reaction is favoured.

Adding of reactants shifts the equilibrium position to the right hand side hence when H2 is added, the equilibrium position shifts to the right.

Decreasing the pressure shifts the equilibrium position to the direction of higher total volume hence the equilibrium shifts to the left when pressure is decreased.

A catalyst has no effect on the equilibrium position. It increases the rate of forward and reverse reaction to the same extent hence the equilibrium position is unaffected.

Removal of water from the system increases the rate of forward reaction since a product is being removed from the reaction system.

The question is incomplete, the complete question is;

1.000 atm of Oxygen gas, placed in a container having apinhole opening in its side. leaks from the container 2.14 timesfaster thatn 1.000 atm of an unknown gas placed in this sameapparatus. Which of the following species could be theunknown gas?

A. CL2

B. SF6

C. Kr

D. UF6

E. Xe

Answer:

SF6

Explanation:

From Graham's law;

Let the rate of diffusion of oxygen be R1

Let the rate of diffusion of unknown base be R2

Let the molar mass of oxygen by M1

Let the molar mass of unknown gas be M2

Hence;

R1/R2 = √M2/M1

So;

2.14/1 = √M2/32

(2.14/1)^2 = M/32

M= (2.14/1)^2 × 32

M= 146.6

This is the molar mass of SF6 hence the answer above.

Answer:

biochemist is both life science and a chemical . it explores the chemistry of the living organisms and the molecular basis for the changes occurring in the living organisms. it uses the method of chemistry . BIOCHEMIST has become the foundation for understanding all biological processes

Answer: The concentration of the solution is 55.66g[tex]KNO_3[/tex]/100g[tex]H_2O[/tex]

Explanation:

A solution consists of solute and solvent. A solute is defined as the component present in a smaller proportion while the solvent is defined as the component that is present in a larger proportion.

We are given:

Mass of [tex]KNO_3[/tex] = 2.31 g

Mass of water = 4.15 g

To calculate the concentration in g[tex]KNO_3[/tex]/100 g [tex]H_2O[/tex], we apply unitary method:

In 4.15 g of water, the mass of [tex]KNO_3[/tex] present is 2.31 g

So, in 100 g of water, the mass of [tex]KNO_3[/tex] present will be [tex]\frac{2.31}{4.15}\times 100=55.66g[/tex]

Hence, the concentration of the solution is 55.66g[tex]KNO_3[/tex]/100g[tex]H_2O[/tex]

Answer:

71.1

Explanation:

Plato

Answer:

16974J of energy are required

Explanation:

The energy required is:

* The energy to heat solid water from -15°C to 0°C using:

q = m*S*ΔT

* The energy to convert the solid water to liquid water:

q = dH*m

* The energy required to increase the temperature of liquid water from 0°C to 75°C

q = m*S*ΔT

The first energy is:

q = m*S*ΔT

m = Mass water = 25g

S is specific heat of ice = 2.03J/g°C

ΔT is change in temperature = 0°C - (-15°C) = 15°C

q = 25g*2.03J/g°C*15°C

q = 761.3J

The second energy is:

q = dH*m

m = Mass water = 25g

dH is heat of fusion of water = 80cal/g

q = 80cal/g*25g

q = 2000cal * (4.184J/1cal) = 8368J

The third energy is:

q = m*S*ΔT

m = Mass water = 25g

S is specific heat of water= 4.184J/g°C

ΔT is change in temperature = 75°C-0°C = 75°C

q = 25g*4.184J/g°C*75°C

q = 7845J

The energy is: 7845J + 8368J + 761J =

16974J of energy are required

Answer:

[tex]molar \: mass \: of \: copper(ii)nitrate = 64 + (14 + 48) \times 3 \\ = 250 \: g \\ 64 \: g \: of \: copper \: produces \: 250 \: g \: of \: copper \: nitrate \\ 10.36 \: g \: of \: copper \: will \: produce \: ( \frac{10.36 \times 250}{64} ) \: g \\ = 40.7 \: g[/tex]

Answer:

Light can be treated like particles because it is made of chunks like things called protons.