Randy is walking home from school. According to the diagram above, what is his total distance from school to home? Show your work and include units. If he had a jet pack, would you use distance or displacement? Why?
Answers
Answer:
if he needs to walk, we can see that between the street and his house he must walk 4 times a distance of 0.5km, so this is a total of 4¨*0.5km = 2km.
Now he has a jet-pack, he can ignore the buildings and just travel in the shorter path, so we can draw a triangle rectangle, in such a way that the hypotenuse of this triangle is the distance between the home and the school.
One of the cathetus is the vertical distance, in this case, is 1km, and the other one is the horizontal distance, also 1km.
So the actual distance is given by the Pythagorean's theorem:
A^2 + B^2 = H^2
Where A and B are the cathetus, and H is the hypotenuse, then:
H^2 = 1km^2 + 1km^2
H = (√2)km = 1.41km.
Now, in the case that he has a jet-pack, he can actually go to the school using this hypotenuse line as his path, so in this case the distance and the displacement would be the same.
Distance: "how much ground an object has covered"
Displacement: "Difference between the final position and the initial position"
When he walks, the distance is 2km, but the displacement is 1.41km
When he uses the jet-pack, both the distance and the displacement are 1.41km
Answer and Step-by-step explanation:
The first thing is we can see in the image, when he walks, that between the house and his school he has to walk four times a distance of 0.5 km. The result of this is a total of 4¨*0.5 km = 2 km. The second thing is that he must walk 2 kilometers. On the other hand, if he has a jetpack, he can simply take the shorter path by ignoring all the buildings. This idea is where we can draw a triangular rectangle on the map in a way so that the hypotenuse of the triangle is the distance between the school and the home. As for the Catheti, it is a vertical distance which in this case is two blocks of 0.5 km. The result is that these catheti have a length of 2*0.5 km = 1 km. The other is the distance of the horizontal line, which is 1 km. The absolute distance of this path is given by Pythagorean's theorem, which is A^2 + B^2 = H^2. Here, A and B are the cathetus, and H is the hypotenuse, then, H^2 = 1 km^2 + 1 km^2. As well, H = (√2)km = 1.41 km. Currently, in the situation where he has a jetpack, he can literally fly to the school utilizing this hypotenuse line for the path he would need to follow. For this specific situation, the displacement, and the distance would be the exact same. The reason for this is that the definitions of displacement and distance are displacement is the difference between the final position and the initial position and distance is how much area an item has covered. Also, when he walks, the distance is 2 km and the displacement is 1.41 km. Also, when he utilizes the jet pack, the distance is equal to the displacement. Both of these are 1.41 km.
Related Questions
Log 1/10 how do you convert this without a calculator
Answers
Answer:
log(1/10) = -1
Step-by-step explanation:
Use the law of exponents and the meaning of logarithm.
1/10 = 10^-1
log(10^x) = x
So, you have ...
log(1/10) = log(10^-1)
log(1/10) = -1
Find the degree, leading coefficient, and the constant term of the polynomial.
Answers
[tex] \LARGE{ \boxed{ \purple{ \rm{Answers;)}}}}[/tex]
☃️ Degree of the polynomial- The highest degree of any term in a polynomial. Here the highest degree is 5.
⇛ 4x⁴ + 5 + 6x⁵ - 2x(° of polynomial = 5)
☃️ Leading coefficient- The coefficient of the term having the highest degree of the polynomial. Here, the highest degree is 5 and the term is 6x⁵
⇛ 4x⁴ + 5 + 6x⁵ - 2x (Leading coeff. = 6)
☃️ Constant term- It is the term having no coefficients, only a fixed real number. This remains constant in any value of polynomial.
⇛ 4x⁴ + 5 + 6x⁵ - 2x (Constant term = 5)
━━━━━━━━━━━━━━━━━━━━
If f(x)=4x-6 and g(x) vx+2 what is (f*g)(7)
Answers
Answer: The value of (f*g)(7) is 66.
Step-by-step explanation:
Given functions: [tex]f(x)= 4x-6\text{ and } g(x)=\sqrt{x+2}[/tex]
Since, product of two functions: [tex](u*v)(x)=u(x)\times v(x)[/tex]
[tex](f*g)(x)=f(x)\times g(x)\\\\=4x-6\times \sqrt{x+2}\\\\\Rightarrow\ (f*g)(x)=(4x-6) \sqrt{x+2}[/tex]
[tex](f*g)(7)=(4(7)-6)\sqrt{7+2}\\\\=(28-6)\sqrt{9}\\\\=22\times 3=66[/tex]
Hence, the value of (f*g)(7) is 66.
Anand needs to hire a plumber. He's considering a plumber that charges an initia
hourly rate of $28. The plumber only charges for a whole number of hours. Anar
more than $250, and he wonders how many hours of work he can afford.
Let H represent the whole number of hours that the plumber works.
1) Which inequality describes this scenario?
Choose 1 answer:
28 - 65H <250
Answers
Complete question :
Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an
hourly rate of $28. The plumber only charges for a whole number of hours. Anand would like to spend no more than $250, and he wonders how many hours of work he can afford.
Let H represent the whole number of hours that the plumber works.
1) Which inequality describes this scenario?
Choose 1 answer:
A. 28 + 65H < 250
B. 28 + 65H > 250
C. 65 + 28H < 250
D. 65 +28H > 250
2) What is the largest whole number of hours that Anand can afford?
Answer:
65 + 28H < 250
Number of hours Anand can afford = 6 hours
Step-by-step explanation:
Given the following information :
Initial hourly rate = $65
Hourly rate = $28
Number of hours worked (whole number) = H
Maximum budgeted amount to spend = $250
Therefore ;
(Initial charge + total charge in hours) should not be more than $250
$65 + ($28*H) < $250
65 + 28H < 250
Number of hours Anand can afford :
65 + 28H < 250
28H < 250 - 65
28H < 185
H < (185 / 28)
H < 6.61
Sinve H is a whole number, the number of hours he can afford is 6 hours
Answer:
65 + 28H < 250
6
Step-by-step explanation:
tried it, it worked.
the other answer is correct but hard to understand so give them thanks and 4 star :)
In a triangle ABC two points D,E are taken on BC so that angle BAD=angle DAE=angleCAE. Determine AE if AB=5,BC=10 angle BAC=90. PLEASE HELP I NEED HELP WITHIN TEN MINS PLEASE
Answers
Answer:
AE = 7.5
Step-by-step explanation:
Since <BAC = [tex]90^{0}[/tex], then;
<BAD = <DAE = <CAE = [tex]30^{0}[/tex] (complementary angles)
From ΔABC, applying the Pythagoras theorem to determine the length of side AC;
[tex]/BC/^{2}[/tex] = [tex]/AC/^{2}[/tex] + [tex]/AB/^{2}[/tex]
[tex]/10/^{2}[/tex] = [tex]/AC/^{2}[/tex] + [tex]/5/^{2}[/tex]
100 = [tex]/AC/^{2}[/tex] + 25
[tex]/AC/^{2}[/tex] = 100 - 25
[tex]/AC/^{2}[/tex] = 75
AC = [tex]\sqrt{75}[/tex]
Applying trigonometric function to ΔCAE,
Cos [tex]30^{0}[/tex] = [tex]\frac{AE}{\sqrt{75} }[/tex]
AE = [tex]\sqrt{75}[/tex] × Cos [tex]30^{0}[/tex]
= 7.5
Therefore, AE = 7.5
Olcquations
Week 5 Assignment: Mixture Problems and Systems of Equations
Due Sunday by 11:59pm
Points 10
Submitting an external tool
Solve interest applications using a system of equations
Question
Matthew invested $3,000 into two accounts. One account paid 3% interest and the other paid 8% interest. He earned 4%
interest on the total investment. How much money did he put in each account?
Sorry, that's incorrect. Try again?
3% amount: S 600
8% amount: S 2400
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Content attribution
Answers
Answer:
$600 at 8%$2400 at 3%Step-by-step explanation:
You have the right numbers, but the wrong accounts.
__
Let x represent the amount invested at 8% (the highest rate). Then the total interest is ...
.08x +.03(3000 -x) = .04(3000)
.05x = .01(3000) . . . . subtract .03(3000)
x = 3000/5 = 600
Matthew invested $600 at 8%, $2400 at 3%.
_____
Comment on checking your answer
You may notice that the overall interest rate is 4%, closer to 3% than to 8%. That means more of the money must be invested at 3% than at 8%.
Calculate the surface area of this composite shape.
Answers
Answer:
1284 m^2
Step-by-step explanation:
Front face and back face:
2 * [28 m * 5 m + (22 m - 5 m) * 6 m] = 484 m^2
Left face and right face:
2 * 22 m * 8 m = 352 m^2
Bottom face and top face:
2 * 28 m * 8 m = 448 m^2
total surface area = 484 m^2 + 352 m^2 + 448 m^2 = 1284 m^2
What is the area of polygon XYZ?
Answers
Answer:
B. 36 square units
Step-by-step explanation:
This is a triangle and to calculate the area of a triangle we multiply height with base and that divided by two
The height of this triangle is 8 units and the base is 9 units
9 × 8 ÷ 2 = 36 square units
I need help with this!
Answers
Answer:
i) [tex]\frac38\pi[/tex]
ii) n = 33
Step-by-step explanation:
For this question you can actually focus on the sine, and forget about the e power. The x-coordinates of the extremes of the curve will be the same as for y=sin(4x)
i) equivalent to solving sin(4x) = -1, so 4x = 3/2 pi, x=3/8 pi
ii) The Tn values are at x = (n·π - π/2)/4
solving (n·π - π/2)/4 > 25 gives:
n > 1/2 + 100/π, so n > 32.331, but n must be integer, so we get n=33
Find the length S of the spiral (t cos(t), t sin(t)) for 0 ≤ t ≤ 3π. (Round your answer to three decimal places.) S =
Answers
The arc length is
[tex]S=\displaystyle\int_C\mathrm ds[/tex]
where C is the given curve and ds is the line element. C is defined on 0 ≤ t ≤ 3π by the vector function,
[tex]\mathbf r(t)=(t\cos t,t\sin t)[/tex]
so the line element is
[tex]\mathrm ds=\left\|\dfrac{\mathrm d\mathbf r(t)}{\mathrm dt}\right\|\,\mathrm dt[/tex]
[tex]\mathrm ds=\sqrt{\left(\dfrac{\mathrm d(t\cos t)}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm d(t\sin t)}{\mathrm dt}\right)^2}\,\mathrm dt[/tex]
[tex]\mathrm ds=\sqrt{1+t^2}\,\mathrm dt[/tex]
So we have
[tex]S=\displaystyle\int_0^{3\pi}\sqrt{1+t^2}\,\mathrm dt\approx46.132[/tex]
Evaluate
1+5.3
2
please answer quickly
Answers
Answer:
1+5.3=6.3
Step-by-step explanation:
not sure what your asking for with the 2
explain what your looking for with the 2 and maybe we can help you further
(I have to do it the way I did it because the 2 in the question is confusing)
Answer:
For expression 1 + 5.32: 6.32
For expression 1 + 5.3 × 2: 11.6
Step-by-step explanation:
If the expression is 1 + 5.32:
Add 1 to 5.32: 1 + 5.32 = 6.32If the expression is 1 + 5.3 × 2:
5.3 × 2 = 10.6Plug in 10.6: 1 + 10.61 + 10.6 = 11.6
How do you evaluate this?
Answers
[tex]_6C_3=\dfrac{6!}{3!3!}=\dfrac{4\cdot5\cdot6}{2\cdot3}=20[/tex]
General solution of equation sin x + sin 5x = sin 2x + sin 4x is
Answers
Answer:
x=nπ3, n∈I
Step-by-step explanation:
sin x + sin 5x = sin 2x + sin 4x
⇒⇒ 2 sin 3x cos 2x = 2 sin 3x cos x
⇒⇒ 2 sin 3x(cos 2x - cos x) = 0
⇒ sin 3x=0 ⇒ 3x=nπ ⇒ x=nπ3⇒ sin 3x=0 ⇒ 3x=nπ ⇒ x=nπ3 , n∈I, n∈I
or cos 2x−cos x=0 ⇒ cos 2x=cos xcos 2x-cos x=0 ⇒ cos 2x=cos x
⇒ 2x=2nπ±x ⇒ x=2nπ, 2nπ3⇒ 2x=2nπ±x ⇒ x=2nπ, 2nπ3 , n∈I, n∈I
But solutions obtained by x=2nπx=2nπ , n∈I, n∈I or x=2nπ3x=2nπ3 , n∈I, n∈I are all involved in x=nπ3x=nπ3 , n∈I
6. If the equations kx - y = 2 and 6x - 2y = 3 have a solution then state the value of k a) K = 3 b) k 3 c ) K 0 d) k = 0 7.
Answers
Answer:
k ≠ 3Step-by-step explanation:
Given the system of equation;
kx - y = 2 ------------------- 1
6x - 2y = 3 -------------------- 2
Rewriting the equations in the format ax+by+c = 0
Equation 1 becomes kx - y - 2 = 0
Equation 2 becomes 6x - 2y - 3 = 0
where a₁ = k, b₁ = -1 and c₁ = -2 and a₂ = 6, b₂ = -2 and c₂ = -3
For the system of equation to have a unique solution the following must be true;
a₁/a₂ ≠ b₁/b₁
Substituting the coefficients into the condition, we will have;
k/6 ≠ -1/-2
k/6 ≠ 1/2
Cross multiplying we will have;
2k ≠ 6
k ≠ 6/2
k ≠ 3
This means that k can be any other real values except 3 for the system of equation to have a unique solution.
Please help! I’ll mark you as brainliest if correct.
Answers
Answer:
160 liters of 25%, 20 liters of 40%, 60 liters of 60%
Step-by-step explanation:
x + y + z = 240
0.25x + 0.4y + 0.6z = 0.35*240 = 84
z = 3y
x = 160
y = 20
z = 60
A signal light is green for 4 minutes, yellow for 10 seconds, and red for 3 minutes. If you drive up to this light, what is the probability that it will be green when you reach the intersection? Round your answer to two decimal places.
Answers
Answer:
0.56 is the required probability.
Step-by-step explanation:
Time for which signal shows green light = 4 minutes
Time for which signal shows yellow light = 10 seconds
Time for which signal shows red light = 3 minutes
To find:
Probability that the signal will show green light when you reach the destination = ?
Solution:
First of all, let us convert each time to same unit before doing any calculations.
Time for which signal shows green light = 4 minutes = 4 [tex]\times[/tex] 60 seconds = 240 seconds
Time for which signal shows yellow light = 10 seconds
Time for which signal shows red light = 3 minutes = 3 [tex]\times[/tex] 60 seconds = 180 seconds
Now, let us have a look at the formula for probability of an event E:
[tex]P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}[/tex]
Here, E is the event that green light is shown by the signal.
Number of favorable cases mean the time for which green light is shown and Total number of cases is the total time (Time for which green light is shown + Time for which Yellow light is shown + Time for which red light is shown)
So, the required probability is:
[tex]P(E) = \dfrac{240}{240+10+180}\\\Rightarrow P(E) = \dfrac{240}{430}\\\Rightarrow \bold{P(E) \approx 0.56 }[/tex]
a ball is thrown upward with an initial height of 3 feet with an initial upward velocity 37 ft/s the balls heigh in feet after t second is given by h=3=+37t-16t^2
Answers
Answer:
[tex]t = 1.45[/tex] or [tex]t = 0.86[/tex]
Step-by-step explanation:
Given
[tex]h=3+37t-16t^2[/tex]
Required
Find all values of t when height is 23 feet
To solve this, we simply substitute 23 for h
[tex]23=3+37t-16t^2[/tex]
Collect like terms
[tex]16t^2 - 37t - 3 + 23=0[/tex]
[tex]16t^2 - 37t +20=0[/tex]
Solve t using quadratic formula;
[tex]t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]
Where a = 16, b =-37 and c = 20
[tex]t = \frac{-(-37)\±\sqrt{(-37)^2 - 4*16*20}}{2*16}[/tex]
[tex]t = \frac{37\±\sqrt{(-37)^2 - 4*16*20}}{2*16}[/tex]
[tex]t = \frac{37\±\sqrt{1369 - 1280}}{32}[/tex]
[tex]t = \frac{37\±\sqrt{89}}{32}[/tex]
[tex]t = \frac{37\±9.43}{32}[/tex]
[tex]t = \frac{37+9.43}{32}[/tex] or [tex]t = \frac{37-9.43}{32}[/tex]
[tex]t = \frac{46.43}{32}[/tex] or [tex]t = \frac{27.57}{32}[/tex]
[tex]t = \frac{46.43}{32}[/tex] or [tex]t = \frac{27.57}{32}[/tex]
[tex]t = 1.45[/tex] or [tex]t = 0.86[/tex]
Show all work to solve 3x2 − x − 2 = 0.
Answers
Answer:
x=-2/3 and 1
Step-by-step explanation:
3x^2-x-2=0
(3x+2)(x-1)
3x=-2
x=-2/3
x=1
Consider the age distribution in the United States in the year 2075 (as projected by the Census Bureau). Construct a cumulative frequency plot and describe what information the plot communicates about the distribution of ages in the future.
Answers
Answer:
The cumulative frequency plot is also attached below.
Step-by-step explanation:
The data provided is as follows:
Age Group Frequency
0 - 9 34.9
10 - 19 35.7
20 - 29 36.8
30 - 39 38.1
40 - 49 37.8
50 - 59 37.8
60 - 69 34.5
70 - 79 27.2
80 - 89 18.8
90 - 99 7.7
100 - 109 1.7
Consider the Excel output attached.
The cumulative frequency are computed in the Excel sheet.
The cumulative frequency plot is also attached below.
From the cumulative frequency plot it can be seen that in the future most people will belong to a higher age group rather then the lower ones.
Simplify (3n - 2m)^2 = Can someone break this down for me? I don't understand why I'm having issues with this.
Answers
Answer:
9n² - 12mn + 4m²
Step-by-step explanation:
(a+b)² = a² + 2ab + b²
(3n - 2m )² = (3n-2m)(3n-2m) = 3n*3n + 3n*-2m -2m*3n - 2m*-2m
= 9n² - 6nm -6mn + 4m²
= 9n² - 12mn + 4n²
Answer:
Once you simplify the given expression, your answer will be 9n² - 12mn + 4m
Step-by-step explanation:
In this problem, we are given an expression.
(3n - 2m)²
when an expression or equation is raised to the power of 2, then you are going to multiply the base term by itself. For example, if you have 2² or 16², then would you do 2 × 2 and 16 × 16 in order to solve the expressions. We will do the same for this expression.
(3n - 2m)² = (3n - 2m) × (3n - 2m)
We will use the foil method to solve this expression
(3n - 2m)(3n - 2m)
9n² - 6mn - 6mn + 4m
Combine like terms together.
9n² - 12mn + 4m
So, the simplified form of the expression is 9n² - 12mn + 4m
HELPPPPP ASAPPPP
Select the correct answer.
A volleyball player sets a volleyball straight up into the air. The height of the volleyball, h(t), is modeled by this equation, where e represents the
time, in seconds, after that ball was set.
= -16t2 + 20t + 6
The volleyball reaches its maximum height after 0.625 seconds. What is the maximum height of the volleyball
A. 11.625 feet
B. 12.25 feet
C. 8.5 feet
D. 1.625 feet
Answers
Answer:
The maximum height of the volleyball is 12.25 feet.
Step-by-step explanation:
The height of the volleyball, h(t), is modeled by this equation, where t represents the time, in seconds, after that ball was set :
[tex]h(t)=-16t^2+20t+6[/tex] ....(1)
The volleyball reaches its maximum height after 0.625 seconds.
For maximum height,
Put [tex]\dfrac{dh}{dt}=0[/tex]
Now put t = 0.625 in equation (1)
[tex]h(t)=-16(0.625)^2+20(0.625)+6\\\\h(t)=12.25\ \text{feet}[/tex]
So, the maximum height of the volleyball is 12.25 feet.
Answer:
The correct answer is B. 12.25 feet.
Step-by-step explanation:
I got it right on the Edmentum test.
are:
4. Suppose that the distance of fly balls hit to the outfield (in baseball) is normally
distributed. We randomly sample 27 fly balls. Their recorded distances in feet
234, 310, 285, 249, 210, 311, 265, 290, 308,
254, 295, 287, 231, 302, 325, 308, 221, 237,
312, 277, 259, 223, 340, 204, 214, 303, 309
Let X be the distance of a fly ball.
Use Excel to calculate the following:
a. (1 pt) mean of the sample, x =
b. (1 pt) standard deviation of the sample, s =
C. (2 pts) Calculate the t-score at a 96% confidence level:
d. (2 pts) Calculate the Error Bound (EBM), using the formula, EBM =
(t)(s//n)
e. (1 pt) At 96% confidence level, provide the confidence interval (CI) for the
mean distance in feet of a fly ball.
hantor 92
D
Answers
Step-by-step explanation:
a. The mean can be found using the AVERAGE() function.
x = 272.7
b. The standard deviation can be found with the STDEV() function.
s = 39.9
c. The t-score can be found with the T.INV.2T() function. The confidence level is 0.04, and the degrees of freedom is 26.
t = 2.162
d. Find the lower and upper ends of the confidence interval.
Lower = 272.7 − 2.162 × 39.9 = 186.5
Upper = 272.7 + 2.162 × 39.9 = 358.9
What is the number of square units in the area of the triangle whose vertices are points A(2,0), B(6,0), and C(8,5)?
Answers
10 units squared. Hope this helped.
The area of the triangle is 10 square units.
The given coordinates are A(2,0), B(6,0), and C(8,5).
What is the formula to find the area of a triangle?The formula of area of triangle formula in coordinate geometry is the area of the triangle in the coordinate geometry is: [tex]A=\frac{1}{2} |x_{1} (y_{2}-y_{3})+x_{2} (y_{3}-y_{1})+x_{3} (y_{1}-y_{2})|[/tex]
Now, Area=1/2|2(0-5)+6(5-0)+8(0-0)|=0.5|20|
=10 square units
Therefore, the area of the triangle is 10 square units.
To learn more about the area of the triangle visit:
https://brainly.com/question/11952845.
#SPJ2
One side of a right triangle is known to be 12 cm long and the opposite angle is measured as 30°, with a possible error of ±1°. Use differentials to estimate the error in computing the length of the hypotenuse. (Round your answer to two decimal places.)
Answers
Answer:
estimated error=±0.725
Step-by-step explanation:
Side of the triangle= 12cm
Opposite of triangle x= 30
h= hypotenose side
Error= =±1
From trigonometry
Sin(x)=opposite/hypotenose
hypotenose=opposite/sin(x)
h=12/sin(x)
h=12Csc(x)
dh=-12Csc(x)Cot(x) dx...............eqn(1)
dx is the possible error in angle measurements
So we need to convert to radius
dx=±1°× (π/180)
=±1°(π/180)
Substitute x and dx into equation (1)
dh= - 12Csc30°Cot30°×[±(π/180)]
= -12(2)(√3)(±(π/180)
==±0.725
Therefore, estimated error=±0.725
Evaluate the expresión 6c-d when c=2 and d=10 I need help?
Answers
Answer:
the answer is 18
Step-by-step explanation:
8 is the answer
I have no idea what to do here.
Answers
Answer:
15.5846.>
Step-by-step explanation:
Please answer this correctly without making mistakes
Answers
Answer:
10 9/20
Step-by-step explanation:
Hey there!
If Hillsboro to Campbell is 16 2/20 and Hillsboro to Oxford is 5 13/20,
we’ll do
16 2/20 - 5 13/20
Imrpoper form
322/20 - 113/20
322 - 113
209/20
10 9/20 miles from Oxford to Campbell.
Hope this helps :)
When determining the sample size necessary for estimating the true population mean, which factor is NOT considered when sampling with replacement
Answers
Answer:
Population Size
Step-by-step explanation:
When sampling with replacement, we can expect that the population size will remain the same. Sampling with replacement occurs when a unit or subject for research is chosen from a population at random. This chosen unit can be returned to the population and another random selection done with the possibility that a unit that was chosen before could be chosen again. So in applying this system of selection, the population size is not taken into consideration. When samples are chosen in this form, it can be referred to as a simple random sample.
So, when determining the sample size necessary for estimating the true population mean, using the sampling with replacement method, the population size is not considered.
Stepwise regression is a variable screening method, not a model building method.
A. True
B. False
Answers
Answer:
A. True
Step-by-step explanation:
Stepwise regression is a variable-selection method for independent variables.
Stepwise regression helps us to recognize and choose the most handy descriptive variables from a list of several reasonable independent variables.
It entails a series of steps that is drafted to locate the most handy X-variable to incorporate in a regression model. During each step of the course of action or method, each X - variable is estimated by applying a set criterion to determine if it is meant to exist in the model.
The basis for selection can be choosing a variable which satisfies the stipulated criterion or removing a variable that least satisfies the criterion. A typical illustration of such criterion is the t value.
F
19) The points (6,5), (7,2), (9,6), and (10,3) are vertices of an inscribed square.
A)(x - 8)2-(y - 4)2 = 5
B) (x – 8)2 + (y - 4)2 = 15
C) (X + 8)2 + (y + 4)2 = 5
D) (x - 8)2 + (y - 4)2 = 5
Find an equation for the circle
Answers
Answer:
The equation of circle is [tex](x-8)^2+(y-4)^2=5[/tex]
(D) is correct option.
Step-by-step explanation:
Given that,
Points (6,5), (7,2), (9,6) and (10,3) are vertices of an inscribed square.
We need to calculate the distance between (7,2) and (9,6)
Using formula of distance
[tex]d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}[/tex]
Put the value into the formula
[tex]d^2=(9-7)^2+(6-2)^2[/tex]
[tex]d^2=20\ m[/tex]
The radius will be
[tex]r^2=\dfrac{20}{4}[/tex]
[tex]r^2=5[/tex]
We need to calculate the center of the point (7,2) and (9,6)
Using formula of center point
For x axis,
[tex]h=\dfrac{x_{2}+x_{1}}{2}[/tex]
Put the value into the formula
[tex]h=\dfrac{9+7}{2}[/tex]
[tex]h=\dfrac{16}{2}[/tex]
[tex]h=8[/tex]
For y axis,
[tex]k=\dfrac{y_{2}+y_{1}}{2}[/tex]
Put the value into the formula
[tex]k=\dfrac{6+2}{2}[/tex]
[tex]k=\dfrac{8}{2}[/tex]
[tex]k=4[/tex]
We need to find the equation for the circle
Using formula of equation of circle
[tex](x-h)^2+(y-k)^2=r^2[/tex]
Put the value into the formula
[tex](x-8)^2+(y-4)^2=5[/tex]
Hence, The equation of circle is [tex](x-8)^2+(y-4)^2=5[/tex]
(D) is correct option.
