Se tiene un objeto que oscila con MAS. Si la amplitud del movimiento es de 15 cm y el periodo es de 2 seg, encontrar las magnitudes de la velocidad y la aceleración cuando: a) x= 0 cm b) x=7,5 cm Por favor, ayúdenme es para hoy :c

Answers

Answer 1

Answer:

a)   v = 0,  a = - 15 pi²

b) v = - 40.8 cm / s,  a = -74.2 cm / s

Explanation:

the simple harmonic motion is described by the expression

        x = A cos (wt + Ф)

in that case they indicate the amplitude of the movement

        A = 15 cm

angular velocity and period are related

        w = 2π / T

         w = 2π/ 2

         w = π rad / s

speed is defined by

         v = dx / dt

          v = -A w sin (wt + Ф)

acceleration is defined by

         a = dv / dt

         a = - A w² cos (wt + Ф)

In order to evaluate this expression we must know the value of the phase constant (Ф) that meets the initial conditions, the most common thing is that the system is released, v = 0 for y = 0 s, let's use the speed equation

          v = -A w sin (0+ Ф)

           

for this expression to be zero, the sine must be zero, so

         Ф= 0

now let's write the equations for our case

         v = - 15 π sin (π t)

         a = - 15 π² cos (π t)

a) for x = 0

          v = 0

          a = - 15 pi²

b) for x = 7.5 cm

Let's find out how long it takes to get to this position

          x = 15 cos (π t)

          7.5 / 15 = cos π t

          pi t = cos⁻¹ 0.5

          t =  1.047/π

don't forget that the angles are in radians

          t = 0.333 s

now let's look for speed and acceleration

         v = - 15 π sin (π 0.333)

         v = - 40.8 cm / s

         a = - 15 π² cos (π 0.333)

         a = -74.2 cm / s


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