​ solve it

[tex]4 \frac{1}{3} \times (3 \frac{1}{3} \times 3 \frac{1}{2} ) \ {}^{7} \div 9 \frac{3}{4} [/tex]
solve​ it fast

Using the binomial distribution, it is found that:

a) The expression is [tex]\left(\frac{364}{365}\right)^{n}[/tex]

b) You need to select at least 587 people.

For each person, there are only two possible outcomes, either they share your birthday, or they do not. The probability of a person sharing your birthday is independent of any other person, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

There are 365 days in a non-leap year, hence, the probability of each person sharing your birthday is [tex]p = \frac{1}{365}[/tex]

Item a:

This probability is P(X = 0), hence:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{n,0}.\left(\frac{1}{365}\right)^{0}.\left(\frac{364}{365}\right)^{n} = \left(\frac{364}{365}\right)^{n}[/tex]

Hence, the expression is [tex]\left(\frac{364}{365}\right)^{n}[/tex]

Item b:

The probability that at least one person shares your birthday is:

[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]

We want that:

[tex]P(X \geq 1) \geq 0.8[/tex]

Hence:

[tex]1 - P(X = 0) \geq 0.8[/tex]

[tex]P(X = 0) \leq 0.2[/tex]

Hence:

[tex]\left(\frac{364}{365}\right)^{n} \leq 0.2[/tex]

[tex]n\log{\left(\frac{364}{365}\right)} \leq \log{0.2}[/tex]

[tex]n \geq \frac{\log{0.2}}{\log{\left(\frac{364}{365}\right)}}[/tex]

[tex]n \geq 586.6[/tex]

Rounding up: You need to select at least 587 people.

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Answer:

The null hypothesis is [tex]H_0: \sigma = 0.3[/tex]

The alternative hypothesis is [tex]H_1: \sigma \neq 0.3[/tex]

Step-by-step explanation:

Test if the tar content of filtered​ 100-mm cigarettes has a standard deviation different from 0.30 ​mg.

At the null hypothesis, we test if the standard deviation is of 0.3, that is:

[tex]H_0: \sigma = 0.3[/tex]

At the alternative hypothesis, we test if the standard deviation is different of 0.3, that is:

[tex]H_1: \sigma \neq 0.3[/tex]

Answer:

13

Step-by-step explanation:

f(x) = 4x + 1

Let x= 3

f(3) = 4*3+1

    = 12+1

   = 13

Answer:

First one=120,138 Second one=477,900

Step-by-step explanation: For the first one use subtraction, and for the second one use multiplication. Such as multiplying each digit of 6,372 by 7 and by 5. The top one is pretty self explanatory.

Answer:

628 mi^3

Step-by-step explanation:

the volume of a cylinder is given by:

V = base area x height

thus,

V = (3.14)(5)^2(8)

V = (3.14)(25)(8)

V = 628 mi^3

the volume of the cylinder is 628 cubic miles

The volume of the cylinder is 628 cubic miles.

We have a cylinder of radius 5 mi and height 8 mi.

We have to find the volume of the figure and round it to nearest tenth.

The volume of cylinder is given by the formula -

Volume [tex]=\pi r^{2} h[/tex]

We can use the above formula to calculate the volume of cylinder. In our case -

r = 5 mi

h = 8 mi

Substituting the values in the formula -

Volume [tex]=\pi\times5^{2}\times 8\\\\[/tex] = 628 cubic miles.

Hence, the volume of the cylinder is 628 cubic miles.

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Answer:

x=10

Step-by-step explanation:

The whole figure is symmetric hence x=10

Answer:

0.045

Step-by-step explanation:

(0,4x0,5x0,3)-(0,2x0,5x0,15)

9514 1404 393

Answer:

  10.7 years

Step-by-step explanation:

The formula for the balance in an account earning compound interest is ...

  A = P(1 +r/n)^(nt)

where principal P is invested at annual rate r compounded n times per year for t years. We want to solve for t.

  5800 = 3500(1 +0.0475/4)^(4t)

  58/35 = 1.011875^(4t) . . .  divide by 3500 and simplify a bit

  log(58/35) = 4t·log(1.011875) . . . . take logs

  t = log(58/35)/(4·log(1.011875)) . . . . divide by the coefficient of t

  t ≈ 10.6966 ≈ 10.7

The person must leave the money n the bank for about 10.7 years for it to reach $5800.

Answer:

The rental rate for the Fords is of $12 per day.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the cost of a Nissan.

y is the cost of a Ford.

z is the cost of a Chevrolet.

Three Nissans, two Fords, and four Chevrolets can be rented for $106 per day.

This means that:

[tex]3x + 2y + 4z = 106[/tex]

Two Nissans, four Fords, and three Chevrolets cost $107 per day

This means that:

[tex]2x + 4y + 3z = 107[/tex]

Four Nissans, three Fords, and two Chevrolets cost $102 per day.

This means that:

[tex]4x + 3y + 2z = 102[/tex]

From the first equation:

[tex]4z = 106 - 3x - 2y[/tex]

[tex]2z = 53 - 1.5x - y[/tex]

[tex]z = 26.5 - 0.75x - 0.5y[/tex]

Replacing into the third equation:

[tex]4x + 3y + 53 - 1.5x - y = 102[/tex]

[tex]2.5x + 2y = 49[/tex]

From the second equation:

[tex]2x + 4y + 3z = 107[/tex]

[tex]2x = 107 - 4y - 3z[/tex]

[tex]x = 53.5 - 2y - 1.5z[/tex]

[tex]x = 53.5 - 2y - 1.5(26.5 - 0.75x - 0.5y)[/tex]

[tex]x - 1.125x = 53.5 - 2y - 39.75 + 0.75y[/tex]

[tex]-0.125x = 13.75 - 1.25y[/tex]

[tex]0.125x = 1.25y - 13.75[/tex]

[tex]x = \frac{1.25y - 13.75}{0.125}[/tex]

[tex]x = 10y - 110[/tex]

Find the rental rate for the Fords.

We have to find y, so:

[tex]2.5x + 2y = 49[/tex]

[tex]2.5(10y - 110) + 2y = 49[/tex]

[tex]25y - 275 + 2y = 49[/tex]

[tex]27y = 324[/tex]

[tex]y = \frac{324}{27}[/tex]

[tex]y = 12[/tex]

The rental rate for the Fords is of $12 per day.

Answer:

582-600

1,234-1,200

640-600

770-800

1,104-1,100

Answer:

3.5 inches

Step-by-step explanation:

Sample mean basically means that we need to find the average of the samples.

So the formula for finding average is

Number of observations/ Number of Occurrences

So when we add the values together we get

42.

So there are 12 numbers

So, 42/12 =

3.5 inches

The sample mean of the heights of the plants in Susan's garden is

3.5 inches.

Here,

Susan randomly selected a sample of plants to determine the average height of the total 35 plants in her garden.

She measured the heights (in inches) of 12 randomly selected plants and recorded the data:

1.0, 1.4, 1.8, 2.0, 2.5, 3.5, 4.2, 4.5, 4.8, 5.0, 5.3, 6.0

We have to find the sample mean of the heights of the plants in Susan's garden.

What is Average?

Average value in a set of given numbers is the middle value, calculate as dividing the total of all values by the number of values.

Now,

The recorded data is;

1.0, 1.4, 1.8, 2.0, 2.5, 3.5, 4.2, 4.5, 4.8, 5.0, 5.3, 6.0

To find the sample mean of the heights of the plants in Susan's garden we have to find the average of the recorded data.

Formula for average = [tex]\frac{sum of number of observation}{ number of occurrence}[/tex]

Hence, Average = [tex]\frac{1.0+ 1.4+1.8+2.0+ 2.5+3.5+4.2+4.5+ 4.8+ 5.0+ 5.3+ 6.0}{12} = \frac{42}{12} = 3.5[/tex]

Therefore, The sample mean of the heights of the plants in Susan's garden is 3.5 inches.

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Answer:

rationalising factor wud be

2 - root3

as on multiying both and applying identity we end up

2^2 - (root3)^2

4 - 3 = 1

we got a rational number so rationalisng factor is

2 - root3

Answer:

(-2,0)

Step-by-step explanation:

The x intercept is the value when it crosses the x axis ( the y value is zero)

x = -2 and y =0

(-2,0)

Question:- how many 50 cents coins are there in $10.50

Answer:-

Total amount-> $ 10.50

So amount in cents

$ 1 is equal to 100 cents

$10.50 is equal to 1050 cents

According to the question

[tex]Number \: of \: the \: 50 \: cents= \frac{ Total \: cents}{ 50 \: cents } \\ [/tex]

[tex]Number \: of \: the \: 50 \: cents = \frac{1050}{50} \\ Number \: of \: the \: 50 \: cents = 21 \: [/tex]

Answer:

(a) [tex]C(x) = 12 + 5x[/tex]

(b) [tex]C(x) = 8x[/tex]

(c) Tables

(d) See attachment for graph

(e) Banner newspaper

(f) Free press newspaper

Free Press

[tex]\begin{array}{cccccc}x & {1} & {2} & {3} & {4} & {5} & {C(x)} & {17} & {22} & {27} & {32} & {37} \ \end{array}[/tex]

Banner

[tex]\begin{array}{cccccc}x & {1} & {2} & {3} & {4} & {5} & {C(x)} & {8} & {16} & {24} & {32} & {40} \ \end{array}[/tex]

Step-by-step explanation:

Given

Free Press

[tex]Initial = 12[/tex]

[tex]Rate =5[/tex]

Banner

[tex]Initial=0[/tex]

[tex]Rate =8[/tex]

Solving (a): Free Press Equation

This is calculated as:

[tex]C(x) = Initial + Rate * x[/tex]

Where

[tex]x \to[/tex] days

So, we have:

[tex]C(x) = 12 + 5x[/tex]

Solving (b): Banner Equation

This is calculated as:

[tex]C(x) = Initial + Rate * x[/tex]

Where

[tex]x \to[/tex] days

So, we have:

[tex]C(x) = 0 + 8x[/tex]

[tex]C(x) = 8x[/tex]

Solving (c): Table of values

For free press, we have:

[tex]\begin{array}{cccccc}x & {1} & {2} & {3} & {4} & {5} & {C(x)} & {17} & {22} & {27} & {32} & {37} \ \end{array}[/tex]

C(x) is calculated as:

[tex]x = 1;\ C(1) = 12 + 5* 1 =17[/tex]

[tex]x = 2;\ C(2) = 12 + 5* 2 =22[/tex]

..

[tex]x = 5;\ C(5) = 12 + 5* 5 =37[/tex]

For banner, we have:

[tex]\begin{array}{cccccc}x & {1} & {2} & {3} & {4} & {5} & {C(x)} & {8} & {16} & {24} & {32} & {40} \ \end{array}[/tex]

C(x) is calculated as:

[tex]x = 1;\ C(1) = 8* 1 =8[/tex]

[tex]x = 2;\ C(2) = 8* 2 =16[/tex]

..

[tex]x = 5;\ C(5) = 8* 5 =40[/tex]

Solving (d): Graph of both using rapidtable

See attachment

Solving (e) Newspaper to use for 1 day

From the graph, when [tex]x = 1[/tex]

[tex]Free\ press = 17[/tex]

[tex]Banner = 8[/tex]

So, we use Banner newspaper because it is cheaper

Solving (f) Newspaper to use for 12 days

From the graph, when [tex]x = 12[/tex]

[tex]Free\ press = 72[/tex]

[tex]Banner = 96[/tex]

So, we use free press newspaper because it is cheaper

Answer:

D

Step-by-step explanation:

Assuming that the expression is referring to sin²(2πft) and not sin²(2)πft, we can solve as follows:

One trigonometric identity states that sin²x+cos²x = 1. We want to express this in terms of cos²x, so we need to solve for sin²x. Subtracting cos²x from both sides, we get 1-cos²x = sin²x. Plugging (2πft) for x, we get

1-cos²(2πft) = sin²(2πft)

We can plug that into our equation to get

P = I₀²R(1-cos²(2πft)), or D

Answer:

Perimeter

[tex]202 = x + x + 26 + 4x + 26 + 4x\\202-26-26=10x\\150=10x\\x=15[/tex]

Therefore, the dimensions are

Answer:

4y

They would have the same value if a number was substituted for y

Step-by-step explanation:

y+y+2y =

Combine like terms

4y

These are all like terms

They would have the same value if a number was substituted for y

Let y = 5

5+5+2(5) = 5+5+10 = 20

4(5) =20

Answer:

C. 2x+11

Step-by-step explanation:

2x+11≈21 -55

2x+11≈21 -55

2x+11≈21 -55

2x+11≈21 -55

2x+11≈21 -55

Answer:

Step-by-step explanation:

Assuming the system is solvable in the first place, create an augmented matrix of coefficients from the equations. Then put the matrix into reduced row echelon form.

Example is attached.

"Demonstrate by solving the following system."

You need to provide the system of equations.

Answer:

-2.7 < y

Step-by-step explanation:

2.9 < 5.6+y

Subtract 5.6 from each side

2.9-5.6 < 5.6-5.6+y

-2.7 < y

Solution :

Given information :

A sample of n = 10 adults

The mean failure was 24 and the standard deviation was 3.2

a). The formula to calculate the 95% confidence interval is given by :

[tex]$\overline x \pm t_{\alpha/2,-1} \times \frac{s}{\sqrt n}$[/tex]

Here, [tex]$t_{\alpha/2,n-1} = t_{0.05/2,10-1}$[/tex]

                       = 2.145

Substitute the values

[tex]$24 \pm 2.145 \times \frac{3.2}{\sqrt {10}}$[/tex]

(26.17, 21.83)

When the [tex]\text{sampling of the same size}[/tex] is repeated from the [tex]\text{population}[/tex] [tex]n[/tex] infinite number of [tex]\text{times}[/tex], and the [tex]\text{confidence intervals}[/tex] are constructed, then [tex]95\%[/tex] of them contains the [tex]\text{true value of the population mean}[/tex], μ in between [tex](26.17, 21.83)[/tex]

b). The formula to calculate 95% prediction interval is given by :

    [tex]$\overline x \pm t_{\alpha/2,-1} \times s \sqrt{1+\frac{1}{n}}$[/tex]

   [tex]$24 \pm 2.145 \times 3.2 \sqrt{1+\frac{1}{10}}$[/tex]

   (31.13, 16.87)

Answer:

it simple as look

Step-by-step explanation:

He y I a m r a v I t ha n k S

Wowowowowowowowowk

Answer:

5%

Step-by-step explanation:

Bank amount=PA*(1+r/100)^t

4410=4000*(1+x/100)^2

1.05=(1+x/100), x=5%