Someone please help me with this question

Answer:

105mm

Step-by-step explanation:

To find the rainfall during the month of April simply multiply the number of days in April times the average daily rainfall

Number of days in April: 30

Average daily rainfall: 3.5mm

Rainfall during the month = 30 * 3.5 = 105mm

Answer:

set ={Sunday,Monday,Tuesday,Wednesda,Thursda,Friday, Saturday} and set={1,2,3,4,5}

Step-by-step explanation:

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {21}}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex]3 \: ( \: x + 2 \: )[/tex]

Plugging in the value [tex]x = 5[/tex] in the above expression, we have

[tex] = 3\:( \: 5 + 2 \: )[/tex]

[tex] = 3 \: ( \: 7 \: )[/tex]

[tex] = 3 \times 7[/tex]

[tex] = 21[/tex]

[tex]\sf\pink{PEMDAS\: rule.}[/tex]

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35☂}}}}}[/tex]

answer is

B. 6√2

hope this helps!

Answer:

Work done = 150 x 5  = 750 J

Step-by-step explanation:

Work done is the measure of energy transferred to an object when a force is added causing the object to move a distance in the direction of the force.

The equation for work done is force time the distance and is measured in Joules. Therefore the formula is W = F x D

work done (W) is measured in joules (J)

force (F) is measured in newtons (N)

distance (d) is in the same direction as the force and is measured in

metres (m)

W = F x D

w = 150 x 5

W = 750 J

Answer:

Diameter : 22.568 cm

Step-by-step explanation:

Hope this Helps!

Answer:

1/ 3^6

Step-by-step explanation:

We know that a^b / a^c = a^(b-c)

3^-7 / 3^-1 = 3^(-7 - -1) = 3^(-7+1) = 3^(-6)

We know that a^ -b = 1/ a^b

3^-6 = 1/ 3^6

Answer:

224

Step-by-step explanation:

Hello!

To find f(-7) you simply plug the value, -7, into the function.

This will get you:

f(-7) = 4(-7)^2 - 4(-7)

Remember that the square of a negative number is a positive! Also, remember to use the order of operations (PEMDAS)!

This will get you:

f(-7) = 4(49) - 4(-7)

f(-7) = 196 - (-28)

f(-7) = 224

Hope this helps!

Answer:

-10

Step-by-step explanation:

y-5y+2

=3-5 x 3+2

Using the rule of BODMAS

=3-15+2

=3-13

= -10

Answer:

2a³

Step-by-step explanation:

2a³ can divide all these without living a remainder

Answer:

Quadrant III

Step-by-step explanation:

-180° is a 180° rotation clockwise, which will end up between Quadrant II and III. -90° is a 90° rotation clockwise, which will end up between Quadrant III and Quadrant IV. The range of possible angles are contained in Quadrant III, in conclusion.

Answer: 5 Units

Step-by-step explanation:

Answer:

S={(1,),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6),}n(S)=36

E = { (1,1), (1,2), (1,4), (1,6), (2,1), (2,3), (2,5), (3,2), (3,4), (4,1), (4,3), (5,6), (6,1), (6,5)}, n(E) = 15

Step-by-step explanation:

thats the answer

Answer:

[tex]\sqrt{x+6}[/tex]

Step-by-step explanation:

So, there are a few things we need to go over to graph a function,

When a number is outside of a root, it changes the y value. For example:

y=[tex]\sqrt{x}+6[/tex]

With the +6, y will always be 6 higher than normal.

If it was -6, then y will always be 6 lower than normal.

What if the number is inside the root? Well, it works a little differently.

Instead of changing the y value, it changes the x value. For example:

y=[tex]\sqrt{x+6}[/tex]

So if you put a number in for x, lets say -6, wht would you get?

You would get -6+6=0

The square root of 0 is 0, so when x=-6, y=0

Normally, x would have to equal 0 for the y value to be 0.

So basically, when we see the number isnide of the root, we can think the our x coordinate being subtracted by that number.

This makes since, because if we subtract the +6 from x:

x-(+6)= x-6, and -6 is our x coordinate.

If it was -6 at the start, this would also work:

x-(-6)= x+6. So our x coordinate would start at 6.

Now, lets look at our graph.

As we can see, the x values start at -6, and the y values starts at 0.

This eliminates A and D, since the +6 would change the y value, not the x.

Remember that x-6 would make x a postive 6.

x+6 however, would make x a negative 6.

So we need x+6 in a square root.

This eliminates B, since it has a x-6, making the x coordinate postive 6, not negative 6.

So c is our answer.

Hope this helps!

Answer:

X=2, y=-1

Step-by-step explanation:

-4x +8y=-16 equation 1

4x +3y=5 equation 2

     11y=-11 add two equations to eliminate x

y=-1

solve for x by inputting y value into either equation

4x+3y=5

4x+3(-1)=5

4x-3=5

4x=8

x=2

Answer:

English

Step-by-step explanation:

can you speak English plzzz

we need that

Answer:

i dont speak taco ask again in english

Step-by-step explanation:

Answer:

I believe its 63°......,.,..,.,.,.,

Answer:

(0,4)

Step-by-step explanation:

Here, we want to find the y-intercept of the quadratic function

g(x) = 5x^2 + 9x + 4

Mathematically, we know that the y-intercept is the position on the graph where we have x = 0

so, to find the y-intercept value, we have to find g(0)

simply put, we have to substitute the value of 0 for x

Mathematically, we have this as;

g(0) = 5(0)^2 + 9(0) + 4

g(0) = 0 + 0 + 4

g(0) = 4

thus, we have the y-intercept point as (0,4)

Answer:

116

Step-by-step explanation:

116 is parallel to y so that are the same its called corresponding angles

When a transversal cuts two parallel lines, the corresponding angles are equal.

In the given figure, the corresponding angles are 116° and y

So, they are equal

⇒   y = 116°

Answer: [tex]\dfrac{\sqrt{2}}{2}[/tex]

Step-by-step explanation:

Given

The fraction is [tex]\dfrac{2}{2\sqrt{2}}[/tex]

Making denominator a number, multiply and divide by [tex]\sqrt{2}[/tex]

[tex]\Rightarrow \dfrac{2}{2\sqrt{2}}\times \dfrac{\sqrt{2}}{\sqrt{2}}\\\\\Rightarrow \dfrac{2\sqrt{2}}{2\sqrt{2}\times \sqrt{2}}=\dfrac{2\sqrt{2}}{2\sqrt{2\times 2}}\\\\\text{cancel out the common term 2}\\\\\Rightarrow \dfrac{\sqrt{2}}{2}[/tex]

Answer:

OA . -6

Step-by-step explanation:

correct me if I'm wrong

Answer:

160 is the answer pls mark me as brainlist

Answer:

3rd model

Step-by-step explanation:

Well 125-35=90 and the 3rd model shows 125-35=90 so the correct answer is the t3rd model

Answer:

C/3rd one. (y=2x+4)

Step-by-step explanation:

In the equation y=mx+b, m=slope of the line and b=y-intercept. From the graph, we know the y-intercept is 4 so we can write y=mx+4. To find the slope: (0-4)/(-2-0) = (-4)/(-2) = 2. We can replace the m with 2 to get the final equation of y=2x+4 which is also the third answer.

Given the expression below:

[tex] \large{ \frac{ {7}^{ \frac{3}{2} } }{ {7}^{ \frac{1}{2} } } }[/tex]

Use the following property:

[tex] \large \boxed{ {a}^{ \frac{m}{n} } = \sqrt[n]{ {a}^{m} } }[/tex]

Therefore:

[tex] \large{ \frac{ {7}^{ \frac{3}{2} } }{ {7}^{ \frac{1}{2} } } = \frac{ \sqrt{ {7}^{3} } }{ \sqrt{7} } } \\ \large{ \frac{ \sqrt{ {7}^{3} } }{ \sqrt{7} } = \frac{ \sqrt{7 \times 7 \times 7} }{ \sqrt{7} } \longrightarrow \frac{7 \sqrt{7} }{ \sqrt{7} } } \\ \large{ \frac{7 \cancel{ \sqrt{7} }}{ \cancel{ \sqrt{7} }} = 7}[/tex]

Note that a¹ = a. Therefore, 7¹ = 7.

Answer

Answer:

y=2

Step-by-step explanation:

3 = (y+7)/3

Multiply each side by 3

3*3 = (y+7)/3 *3

3*3 = y+7

9 = y+7

Subtract 7 from each side

9-7 = y+7-7

2 =y

Answer:

2 = y

Step-by-step explanation:

3 = y + 7 ÷ 3

multiply both side of equation by 3

3 × 3 = y + 7 ÷ 3 / 3

9 = y + 7

subtract 7 from both side

9 - 7 = y + 7 - 7

2 = y

Answer:

11 unit

Step-by-step explanation:

Applying,

s = √[(y₂-y₁)²+(x₂-x₁)²]...................... Equation 1

Where s = length of the side formed.

From the question,

Given: x₁ = -2, x₂ = 9, y₁ = 5, y₂ = 5

Substitute these values into equation 1

s = √[(9+2)²+(5-5)²]

s = √(11²)

s = 11 unit.

Hence the length of the side formed by the vertices is 11 unit