Answer:
Yes
Explanation:
We known that TCP is the connection [tex]\text{oriented}[/tex] protocol. So the TCP expects for the target host to acknowledge or to check that the [tex]\text{communication}[/tex] session has been established or not.
Also the End stations that is running reliable protocols will be working together in order to verify transmission of data so as to ensure the accuracy and the integrity of the data. Hence it is reliable and so the data can be sent A will still be delivered reliably and it is in-sequence at B.
Write a removeDuplicates() method for the LinkedList class we saw in lecture. The method will remove all duplicate elements from the LinkedList by removing the second and subsequent elements. If there is only one copy of an element, it is not removed. The list size should shrink accordingly based on the number of duplicates removed.
Answer:
removeDuplicates() function:-
//removeDuplicates() function removes duplicate elements form linked list.
void removeDuplicates() {
//declare 3 ListNode pointers ptr1,ptr2 and duplicate.
//initially, all points to null.
ListNode ptr1 = null, ptr2 = null, duplicate = null;
//make ptr1 equals to head.
ptr1 = head;
//run while loop till ptr1 points to second last node.
//pick elements one by one..
while (ptr1 != null && ptr1.next != null)
{
// make ptr2 equals to ptr1.
//or make ptr2 points to same node as ptr1.
ptr2 = ptr1;
//run second while loop to compare all elements with above selected element(ptr1->val).
while (ptr2.next != null)
{
//if element pointed by ptr1 is same as element pointed by ptr2.next.
//Then, we have found duplicate element.
//Now , we have to remove this duplicate element.
if (ptr1.val == ptr2.next.val)
{
//make duplicate pointer points to node where ptr2.next points(duplicate node).
duplicate = ptr2.next;
//change links to remove duplicate node from linked list.
//make ptr2.next points to duplicate.next.
ptr2.next = duplicate.next;
}
//if element pointed by ptr1 is different from element pointed by ptr2.next.
//then it is not duplicate element.
//So, move ptr2 = ptr2.next.
else
{
ptr2 = ptr2.next;
}
}
//move ptr1 = ptr1.next, after check duplicate elements for first node.
//Now, we check duplicacy for second node and so on.
//so, move ptr1 by one node.
ptr1 = ptr1.next;
}
}
Explanation:
Complete Code:-
//Create Linked List Class.
class LinkedList {
//Create head pointer.
static ListNode head;
//define structure of ListNode.
//it has int val(data) and pointer to ListNode i.e, next.
static class ListNode {
int val;
ListNode next;
//constructor to create and initialize a node.
ListNode(int d) {
val = d;
next = null;
}
}
//removeDuplicates() function removes duplicate elements form linked list.
void removeDuplicates() {
//declare 3 ListNode pointers ptr1,ptr2 and duplicate.
//initially, all points to null.
ListNode ptr1 = null, ptr2 = null, duplicate = null;
//make ptr1 equals to head.
ptr1 = head;
//run while loop till ptr1 points to second last node.
//pick elements one by one..
while (ptr1 != null && ptr1.next != null)
{
// make ptr2 equals to ptr1.
//or make ptr2 points to same node as ptr1.
ptr2 = ptr1;
//run second while loop to compare all elements with above selected element(ptr1->val).
while (ptr2.next != null)
{
//if element pointed by ptr1 is same as element pointed by ptr2.next.
//Then, we have found duplicate element.
//Now , we have to remove this duplicate element.
if (ptr1.val == ptr2.next.val)
{
//make duplicate pointer points to node where ptr2.next points(duplicate node).
duplicate = ptr2.next;
//change links to remove duplicate node from linked list.
//make ptr2.next points to duplicate.next.
ptr2.next = duplicate.next;
}
//if element pointed by ptr1 is different from element pointed by ptr2.next.
//then it is not duplicate element.
//So, move ptr2 = ptr2.next.
else
{
ptr2 = ptr2.next;
}
}
//move ptr1 = ptr1.next, after check duplicate elements for first node.
//Now, we check duplicacy for second node and so on.
//so, move ptr1 by one node.
ptr1 = ptr1.next;
}
}
//display() function prints linked list.
void display(ListNode node)
{
//run while loop till last node.
while (node != null)
{
//print node value of current node.
System.out.print(node.val + " ");
//move node pointer by one node.
node = node.next;
}
}
public static void main(String[] args) {
//Create object of Linked List class.
LinkedList list = new LinkedList();
//first we create nodes and connect them to form a linked list.
//Create Linked List 1-> 2-> 3-> 2-> 4-> 2-> 5-> 2.
//Create a Node having node data = 1 and assign head pointer to it.
//As head is listNode of static type. so, we call head pointer using class Name instead of object name.
LinkedList.head = new ListNode(1);
//Create a Node having node data = 2 and assign head.next to it.
LinkedList.head.next = new ListNode(2);
LinkedList.head.next.next = new ListNode(3);
LinkedList.head.next.next.next = new ListNode(2);
LinkedList.head.next.next.next.next = new ListNode(4);
LinkedList.head.next.next.next.next.next = new ListNode(2);
LinkedList.head.next.next.next.next.next.next = new ListNode(5);
LinkedList.head.next.next.next.next.next.next.next = new ListNode(2);
//display linked list before Removing duplicates.
System.out.println("Linked List before removing duplicates : ");
list.display(head);
//call removeDuplicates() function to remove duplicates from linked list.
list.removeDuplicates();
System.out.println("")
//display linked list after Removing duplicates.
System.out.println("Linked List after removing duplicates : ");
list.display(head);
}
}
Output:-
A cashier distributes change using the maximum number of five-dollar bills, followed by one-dollar bills. Write a single statement that assigns num_ones with the number of distributed one-dollar bills given amount_to_change. Hint: Use %.
Sample output with input: 19
Change for $ 19
3 five dollar bill(s) and 4 one dollar bill(s)
1 amount_to_change = int(input())
2
3 num_fives amount_to_change // 5
4
5 Your solution goes here
6 I
7 print('Change for $, amount_to_change)
8 print(num_fives, 'five dollar bill(s) and', num_ones, 'one dollar bill (s)')
Answer:
Explanation:
The code that was provided in the question contained a couple of bugs. These bugs were fixed and the new code can be seen below as well as with the solution for the number of one-dollar bills included. The program was tested and the output can be seen in the attached image below highlighted in red.
amount_to_change = int(input())
num_fives = amount_to_change // 5
#Your solution goes here
num_ones = amount_to_change % 5
print('Change for $' + str(amount_to_change))
print(num_fives, 'five dollar bill(s) and', num_ones, 'one dollar bill (s)')
Which symbol is used to identify edge-triggered flip-flops
Answer:
A triangle on the Clock input.
What Are the Benefits of Using Leads Automation Tool?
Answer:
Here are the top benefits of using the latest leads automation tool for your personal pursuit, professional service, and other types of businesses.
Frees Up A Lot of Time & ResourcesCompound Connection Growth StrategyViewing ProfilesSending Connection RequestsEndorses Skills of Your First Level ContactsBuild your networkImportance of Leads Automation Tool For LinkedIn
Unlike a traditional and non-automation approach, the best LinkedIn leads automation tool 2020 makes the process far more easier and efficient. It helps to win a good number of connections which would eventually make it easier for businesses to pitch their products and turn newly gained connections into potential customers.
Moreover, businesses will also get more views and new messages in your LinkedIn inbox. The best leads automation tool free are especially useful when you have multiple LinkedIn accounts as you will get rid of time-consuming hectic tasks.
Gray London is a retired race car driver who helped Dale Earnhardt, Jr. get his start. He is writing a book and making a video about the early days or Dale Earnhardt. He is trying to decide whether to market these items directly over the Internet or to use intermediaries. To make this decision, he needs to know the pros and cons of each route. Provide that information and make a recommendation to him.
Answer:
Explanation:
Marketing your product directly over the internet can lead to much greater profits and there are many options that you can choose from in order to target the correct audience. Unfortunately, doing so does require marketing knowledge and is basically like growing a business. If you were to use intermediaries they already have the knowledge necessary to market your product but will take a percentage of the profits, which will ultimately limit your gains. Since Gray London is a race car driver, I am assumming that he does not have any prior technological expertise or marketing expertise, therefore I would recommend using intermediaries.
Ms. Lawson, a primary school teacher, told her students that a photograph of the president is in the public domain. What does she mean by this?
Answer:
He belongs to the nation
Using the concepts of public and private domains, it means that the photograph of the president can be used by anyone without asking for permission.
---------------
Public and private domains:
If an image is of private domain, there is the need to ask the owner for the right to use the image.If it is of public domain, there is no need, as is the case for the president photo in this question.A similar question is given at https://brainly.com/question/12202794
????????????????????????????????
(c) 4
Explanation:The function strpos() is a function in php that returns the position of the first occurrence of a particular substring in a string. Positions are counted from 0. The function receives two arguments. The first argument is the string from which the occurrence is to be checked. The second argument is the substring to be checked.
In this case, the string is "Get Well Soon!" while the substring is "Well"
Starting from 0, the substring "Well" can be found to begin at position 4 of the string "Get Well Soon!".
Therefore, the function strpos("Get Well Soon!", "Well") will return 4.
Then, with the echo statement, which is used for printing, value 4 will be printed as output of the code.
3. When using the ohmmeter function of a digital multimeter, the leads are placed in what position relative to the component being tested?
A. Series
B. Parallel
C. Control
D. Line
Answer:
B. Parallel
Explanation:
When using the ohmmeter function of a digital multimeter, the leads are placed parallel to the component being tested. The digital multimeter is placed parallel to the component because, current has to flow into the component so as to be able to measure its resistance. Without the flow of current in the component, the resistance could not be measured.
If the component were placed in series, there would be no way to close the circuit because, we need a closed circuit so as to measure the resistance and use the ohmmeter function of the digital multimeter.
Only a parallel connection would close the circuit.
So, B is the answer.
Write a RainFall class that stores the total rainfall for each of 12 months into an array of doubles. The program should have methods that return the following: the total rainfall for the year the average monthly rainfall the month with the most rain the month with the least rain Demonstrate the class in a complete program and use java 8 examples to do so. Input Validation: Do not accept negative numbers for monthly rainfall figures.
Answer:
Explanation:
The following code is written in Java. It creates the Rainfall class with two constructors, one that passes the entire array of rainfall and another that initializes an array with 0.0 for all the months. Then the class contains a method to add rain to a specific month, as well as the three methods requested in the question. The method to add rain validates to make sure that no negative value was added. 8 Test cases were provided, and any methods can be called on any of the 8 objects.
class Brainly {
public static void main(String[] args) {
Rainfall rain1 = new Rainfall();
Rainfall rain2 = new Rainfall();
Rainfall rain3 = new Rainfall();
Rainfall rain4 = new Rainfall();
Rainfall rain5 = new Rainfall();
Rainfall rain6 = new Rainfall();
Rainfall rain7 = new Rainfall();
Rainfall rain8 = new Rainfall();
}
}
class Rainfall {
double[] rainfall = {0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0};
public Rainfall(double[] rainfall) {
this.rainfall = rainfall;
}
public Rainfall() {
}
public void addMonthRain(double rain, int month) {
if (rain > 0) {
rainfall[month-1] = rain;
}
}
public double totalRainfall() {
double total = 0;
for (double rain: rainfall) {
total += rain;
}
return total;
}
public double averageRainfall() {
double average = totalRainfall() / 12;
return average;
}
public double rainiestMonth() {
double max = 0;
for (double rain : rainfall) {
if (rain > max) {
max = rain;
}
}
return max;
}
}
Which of the following restricts the ability for individuals to reveal information present in some part of the database?
a. Access Control
b. Inference Control
c. Flow Control
d. Encyption
Answer:
it would have to be flow control which would be C.
Explanation:
Flow Control is restricts the ability for individuals to reveal information present in some part of the database. Hence, option C is correct.
What is Flow Control?The management of data flow between computers, devices, or network nodes is known as flow control. This allows the data to be processed at an effective rate. Data overflow, which occurs when a device receives too much data before it can handle it, results in data loss or retransmission.
A design concern at the data link layer is flow control. It is a method that typically monitors the correct data flow from sender to recipient. It is very important because it allows the transmitter to convey data or information at a very quick rate, which allows the receiver to receive it and process it.
The amount of data transmitted to the receiver side without any acknowledgement is dealt with by flow control.
Thus, option C is correct.
For more information about Flow Control, click here:
https://brainly.com/question/28271160
#SPJ5
Write a class Example() such that it has a method that gives the difference between the size of strings when the '-' (subtraction) symbol is used between the two objects of the class. Additionally, implement a method that returns True if object 1 is greater than object 2 and False otherwise when the (>) (greater than) symbol is used. For example: obj1
Answer:
Here the code is given as follows,
Explanation:
class Example:
def _init_(self, val):
self.val = val
def _gt_(self, other):
return self.val > other.val
def _sub_(self,other):
return abs(len(self.val) - len(other.val))
def main():
obj1 = Example('this is a string')
obj2 = Example('this is another one')
print(obj1 > obj2)
print(obj1 - obj2)
main()
Output:-
Write a RainFall class that stores the total rainfall for each of 12 months into an array of doubles. The program should have methods that return the following:
the total rainfall for the year
the average monthly rainfall
the month with the most rain
the month with the least rain
Demonstrate the class in a complete program.
Input Validation: Do not accept negative numbers for monthly rainfall figures.
import java.io.*;
import java.util.*;
public class Rainfall
{
Scanner in = new Scanner(System.in);
private int month = 12;
private double total = 0;
private double average;
private double standard_deviation;
private double largest;
private double smallest;
private double months[];
public Rainfall()
{
months = new double[12];
}
public void setMonths()
{
for(int n=1; n <= month; n++)
{
System.out.println("Enter the rainfall (in inches) for month #" + n + ":" );
months[n-1] = in.nextInt();
}
}
public double getTotal()
{
total = 0;
for(int i = 0; i < 12; i++)
{
total = total + months[i];
}
System.out.println("The total rainfall for the year is" + total);
return total;
}
public double getAverage()
{
average = total/12;
System.out.println("The average monthly rainfall is" + average);
return average;
}
public double getLargest()
{
double largest = 0;
int largeind = 0;
for(int i = 0; i < 12; i++)
{
if (months[i] > largest)
{
largest = months[i];
largeind = i;
}
}
System.out.println("The largest amout of rainfall was" + largest +
"inches in month" + (largeind + 1));
return largest;
}
public double getSmallest()
{
double smallest = Double.MAX_VALUE;
int smallind = 0;
for(int n = 0; n < month; n++)
{
if (months[n] < smallest)
{
smallest = months[n];
smallind = n;
}
}
System.out.println("The smallest amout of rainfall was" + smallest +
"inches in month " + (smallind + 1));
return smallest;
}
public static void main(String[] args)
{
Rainfall r = new Rainfall();
r.setMonths();
System.out.println("Total" + r.getTotal());
System.out.println("Smallest" + r.getSmallest());
System.out.println("Largest" + r.getLargest());
System.out.println("Average" + r.getAverage());
}
}
Answer:
Explanation:
The code provided worked for the most part, it had some gramatical errors in when printing out the information as well as repeated values. I fixed and reorganized the printed information so that it is well formatted. The only thing that was missing from the code was the input validation to make sure that no negative values were passed. I added this within the getMonths() method so that it repeats the question until the user inputs a valid value. The program was tested and the output can be seen in the attached image below.
import java.io.*;
import java.util.*;
class Rainfall
{
Scanner in = new Scanner(System.in);
private int month = 12;
private double total = 0;
private double average;
private double standard_deviation;
private double largest;
private double smallest;
private double months[];
public Rainfall()
{
months = new double[12];
}
public void setMonths()
{
for(int n=1; n <= month; n++)
{
int answer = 0;
while (true) {
System.out.println("Enter the rainfall (in inches) for month #" + n + ":" );
answer = in.nextInt();
if (answer > 0) {
months[n-1] = answer;
break;
}
}
}
}
public void getTotal()
{
total = 0;
for(int i = 0; i < 12; i++)
{
total = total + months[i];
}
System.out.println("The total rainfall for the year is " + total);
}
public void getAverage()
{
average = total/12;
System.out.println("The average monthly rainfall is " + average);
}
public void getLargest()
{
double largest = 0;
int largeind = 0;
for(int i = 0; i < 12; i++)
{
if (months[i] > largest)
{
largest = months[i];
largeind = i;
}
}
System.out.println("The largest amount of rainfall was " + largest +
" inches in month " + (largeind + 1));
}
public void getSmallest()
{
double smallest = Double.MAX_VALUE;
int smallind = 0;
for(int n = 0; n < month; n++)
{
if (months[n] < smallest)
{
smallest = months[n];
smallind = n;
}
}
System.out.println("The smallest amount of rainfall was " + smallest +
" inches in month " + (smallind + 1));
}
public static void main(String[] args)
{
Rainfall r = new Rainfall();
r.setMonths();
r.getTotal();
r.getSmallest();
r.getLargest();
r.getAverage();
}
}
Complete the calcAverage() method that has an integer array parameter and returns the average value of the elements in the array as a double.(Java program)
Ex: If the input array is:
1 2 3 4 5
then the returned average will be:
3.0
Answer:
Explanation:
The following Java program has the method calcAverage(). It creates a sum variable which holds the sum of all the values in the array and the count variable which holds the number of elements in the array. Then it uses a For Each loop to loop through the array and go adding each element to the sum variable. Finally it calculates the average by dividing the sum by the variable count and returns the average to the user. A test case has been created in the main method using the example in the question. The output can be seen in the image attached below.
class Brainly {
public static void main(String[] args) {
int[] myArr = {1, 2, 3, 4, 5};
System.out.println(calcAverage(myArr));
}
public static double calcAverage(int[] myArr) {
double sum = 0;
double count = myArr.length;
for (int x: myArr) {
sum += x;
}
double average = sum / count;
return average;
}
}
You know different types of networks. If two computing station high speed network link for proper operation which of the following network type should be considered as a first priority?
MAN
WAN
WLAN
LAN
All of these
Answer:
All of these.
PLZ MARK ME BRAINLIEST.
Select the correct statement(s) regarding decentralized (distributed) access control on a LAN. a. no centralized access process exists, and therefore each connected station has the responsibility for controlling its access b. data collisions are possible, therefore mechanisms such as CDMA/CD are required c. when a data collision occurs, the nearest station detecting the collision transmits a jamming signal d. all of the above are correct
Answer: D. all of the above are correct
Explanation:
The correct statements regarding the decentralized (distributed) access control on a LAN include:
• no centralized access process exists, and therefore each connected station has the responsibility for controlling its access
• data collisions are possible, therefore mechanisms such as CDMA/CD are required
• when a data collision occurs, the nearest station detecting the collision transmits a jamming signal.
Therefore, the correct option is all of the above.
Given main(), complete the Car class (in file Car.java) with methods to set and get the purchase price of a car (setPurchasePrice(), getPurchasePrice()), and to output the car's information (printInfo()).
Ex: If the input is:
2011
18000
2018
where 2011 is the car's model year, 18000 is the purchase price, and 2018 is the current year, the output is:
Car's information:
Model year: 2011
Purchase price: 18000
Current value: 5770
Note: printInfo() should use three spaces for indentation.
Answer and Explanation:
public class Main {
int Carmodel;
int Purchaseprice;
int Currentyear;
Public void setPurchasePrice(int Purchaseprice){
this.Purchaseprice=Purchaseprice;
}
Public void getPurchasePrice(){
return Purchaseprice;
}
static void printInfo(int Carmodel int Currentyear ){
this.Carmodel=Carmodel;
this.Currentyear=Currentyear;
System.out.println(getPurchasePrice() Carmodel Currentyear);
}
}
The above java program defines a class that has three methods, a get method that returns purchase price of the object, a set method that sets purchase price of the object, and a print method that print out the information about the car object(model, year, price). The print method also takes arguments and assigns values of the arguments/parameters to the object, then prints all.
(a) Define a goal for software product quality and an associated metric for that attribute. (b) Explain how you could show that the goal is validatable. (c) Explain how you could show that the goal is verifiable. 2. (a) Create a list of software product attributes and a list for software project attributes. (b) Rank these in the order of how difficult you consider them to be measured. (c) Discuss the reasons for your choices
How can COUNTIF, COUNTIFS, COUNT, COUNTA, and COUNTBLANK functions aide a company to support its mission or goals
Answer:
Following are the responses to these questions:
Explanation:
It employs keywords to autonomously do work tasks. Users can type numbers directly into the formulas or use the following formulae, so any data the cells referenced provide would be used in the form.
For instance, this leadership involves accounting, and Excel is concerned with organizing and organizing numerical data. In this Equation, I can discover all its information in the data. This idea is simple me count the number many cells containing a number, and also the number of integers. It counts integers in any sorted number as well. As both financial analysts, it is helpful for the analysis of the data if we want to maintain the same number of neurons.
Functions IN C LANGUAGE
Problem 1
Function floor may be used to round a number to a specific decimal place. The statement
y = floor( x * 10 + .5 ) / 10;
rounds x to the tenths position (the first position to the right of the decimal point). The
statement
y = floor( x * 100 + .5 ) / 100;
rounds x to the hundredths position (the second position to the right of the decimal
point).
Write a program that defines four functions to round a number x in various ways
a. roundToInteger( number )
b. roundToTenths( number )
c. roundToHundreths( number )
d. roundToThousandths( number )
For each value read, your program should print the original value, the number rounded to
the nearest integer, the number rounded to the nearest tenth, the number rounded to
the nearest hundredth, and the number rounded to the nearest thousandth.
Input Format
Input line contain a float number.
Output Format
Print the original value, the number rounded to the nearest integer, the number rounded
to the nearest tenth, the number rounded to the nearest hundredth, and the number
rounded to the nearest thousandth
Examples
Example 1
Input 1
24567.8
Output 1
24567.8 24568 24570 24600
If the signal is going through a 2 MHz Bandwidth Channel, what will be the maximum bit rate that can be achieved in this channel? What will be the appropriate signal level?
Answer:
caca
Explanation:
Write a programmer defined function that compares the ASCII sum of two strings. To compute the ASCII sum, you need to compute the ASCII value of each character of the string and sum them up. You will thus need to calculate two sums, one for each string. Then, return true if the first string has a larger ASCII sum compared to the second string, otherwise return false. In your main function, prompt the user to enter two strings with a suitable message and provide the strings to the function during function call. The user may enter multiple words for either string. Then, use the Boolean data returned by the function to inform which string has the higher ASCII sum.
Answer:
The program in Python is as follows:
def ASCIIsum(str1,str2):
asciisum1 = 0; asciisum2 = 0
for chr in str1:
asciisum1 += (ord(chr) - 96)
for chr in str2:
asciisum2 += (ord(chr) - 96)
if asciisum1 > asciisum2:
return True
else:
return False
str1 = input("Enter first string: ")
str2 = input("Enter second string: ")
if ASCIIsum(str1,str2) == True:
print(str1,"has a higher ASCII value")
else:
print(str2,"has a higher ASCII value")
Explanation:
This defines the function
def ASCIIsum(str1,str2):
This initializes the ascii sum of both strings to 0
asciisum1 = 0; asciisum2 = 0
This iterates through the characters of str1 and add up the ascii values of each character
for chr in str1:
asciisum1 += (ord(chr) - 96)
This iterates through the characters of str2 and add up the ascii values of each character
for chr in str2:
asciisum2 += (ord(chr) - 96)
This returns true if the first string has a greater ascii value
if asciisum1 > asciisum2:
return True
This returns false if the second string has a greater ascii value
else:
return False
The main begins here
This gets input for first string
str1 = input("Enter first string: ")
This gets input for second string
str2 = input("Enter second string: ")
If the returned value is True
if ASCIIsum(str1,str2) == True:
Then str1 has a greater ascii value
print(str1,"has a higher ASCII value")
If otherwise
else:
Then str2 has a greater ascii value
print(str2,"has a higher ASCII value")
what its the difference between Arduinos and Assembler?
Answer:
The Arduino boards can be programmed in assembly. All you need is an ICSP Cable (In Circuit Serial Programmer) and the AVR toolchain (free from ATMEL) to write to the board. You then get the advantage of on board debugging.
As you suggested, you can just slap an ATMEL chip on a breadboard and go to town.
Explanation: cause i said so
Using Python suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]).
You are given a target value to search. If found in the array return its index, otherwise return “The input is not on this list”
You may assume no duplicate exists in the array.
Hint: Use a function. Use the built in method .index( ) and/or for loops.
Answer:
Explanation:
class Solution {
public int search(int[] nums, int target) {
int n = nums.length;
int low = 0 , high = n - 1;
While(low < high){//Set virtual node
int mid = (low + high) / 2;
if(nums[mid] > nums[high]){
low = mid + 1;
}else{
high = mid;
}
}
int rot = low;
low = 0;
high = n - 1;
while(low <= high){
int mid = (low + high) / 2;
Int real = (mid + rot) % n;//The virtual node is mapped to the real node.
if(nums[real] == target){
return real;
}else if(nums[real] < target){
low = mid + 1;
}else{
high = mid - 1;
}
}
return -1;
}
}
Large computer programs, such as operating systems, achieve zero defects prior to release. Group of answer choices True False PreviousNext
Answer:
The answer is "False"
Explanation:
It is put to use Six Sigma had 3.4 defects per million opportunities (DPMO) from the start, allowing for a 1.5-sigma process shift. However, the definition of zero faults is a little hazy. Perhaps the area beyond 3.4 DPMO is referred to by the term "zero faults.", that's why Before being released, large computer programs, such as operating systems, must have no faults the wrong choice.
Write a program that launches 1,000 threads. Each thread adds 1 to a variable sum that initially is 0. You need to pass sum by reference to each thread. In order to pass it by reference, define an Integer wrapper object to hold sum. Run the program with and without synchronization to see its effect. Submit the code of the program and your comments on the execution of the program.
Answer:
Following are the code to the given question:
import java.util.concurrent.*; //import package
public class Threads //defining a class Threads
{
private Integer s = new Integer(0);//defining Integer class object
public synchronized static void main(String[] args)//defining main method
{
Threads t = new Threads();//defining threads class object
System.out.println("What is sum ?" + t.s);//print value with message
}
Threads()//defining default constructor
{
ExecutorService exe = Executors.newFixedThreadPool(1000);//defining ExecutorService class object
System.out.println("With SYNCHRONIZATION........");//print message
for(int i = 1; i <= 1000; i++)//defining a for loop
{
exe.execute(new SumTask2());//calling execute method
System.out.println("At Thread " + i +" Sum= " + s + " , ");//print message with value
}
exe.shutdown();//calling shutdown method
while(!exe.isTerminated())//defining while loop that calls isTerminated method
{
}
}
class SumTask2 implements Runnable//calling SumTask2 that inherits Runnable class
{
public synchronized void run()//defining method run
{
int value = s.intValue() + 1;//defining variable value that calls intvalue which is increment by 1
s = new Integer(value);//use s to hold value
}
}
}
Output:
Please find the attached file.
Explanation:
In this code, a Threads class is defined in which an integer class object and the main method is declared that creates the Threads class object and calls its values.
Outside the method, the default constructor is declared that creates the "ExecutorService" and prints its message, and use a for loop that calls execute method which prints its value with the message.
In the class, a while loop is declared that calls "isTerminated" method, and outside the class "SumTask2" that inherits Runnable class and defined the run method and define a variable "value" that calls "intvalue" method which is increment by 1 and define s variable that holds method value.
Write an application that finds the smallest of several integers. Assume that the first value read specifies the number of values to input from the user. C
Answer:
Following are the code to the given question:
#include<stdio.h>//include header file
int main() //defining a main method
{
int a[100],k,x,s; //defining integer variable and an array
printf("Input the number of element want to insert array: "); //print message
scanf("%d",&x); //input value
printf("Enter array value: \n"); //print message
for(k = 0; k<x; k++) //defining a loop that inputs values
{
scanf("%d",&a[k]); //use array to input value
}
s = a[0]; //holding first array value in array
for(k=0;k<x;k++) //use for loop
{
if(a[k]<s) //use if block to check the smallest array value
{
s=a[k];//holding smallest array value
}
}
printf("smallest number= %d",s);//print smallest value
}
Output:
Please find the attached file.
Explanation:
In this code an array and another integer variable "a[100], i,n, and s" is is declared, in which the array and n for input the value from the user-end.
In the next step, an "s" variable is declared that inputs the first array element value in s and use a loop to check the smallest array element and prints its value.
SQLite is a database that comes with Android. Which statements is/are correct?
The content of an SQLite database is stored in XML formatted files because XML is the only file format supported by Android OS.
A SQLite database is just another name for a Content Provider. There is no difference as the SQLite implementation implements the Content Provider interface.
If an app creates an SQLite database and stores data in it, then all of the data in that particular database will be stored in one, single file.
A database query to an SQLite database usually returns a set of answers
To access individual entries, SQLite provides a so-called Cursor to enumerate all entries in the set.
This is yet another example of the Iterator pattern.
Answer:
1. Wrong as per my knowledge, SQLite may be an electronic database software that stores data in relations(tables).
2. Wrong. Content provider interface controls the flow of knowledge from your android application to an external data storage location. Data storage is often in any database or maybe it'll be possible to store the info in an SQLite database also.
3.Right. SQLite uses one file to store data. It also creates a rollback file to backup the stored data/logs the transactions.
4. Wrong. The queries are almost like a traditional electronic database system, the queries are going to be answered as per the conditions given and should return a group of answers or one answer depending upon the info and sort of query used.
5. Right. A cursor helps to point to one entry within the database table. this may be very helpful in manipulating the present row of the query easily.
what is a mirror site?
A recursive method may call other methods, including calling itself. A recursive method has:
1. a base case -- a case that returns a value or exits from a method without performing a recursive call.
2. a recursive case -- calling the method again with a smaller case..
Study the recursive method given below.
For example, this call recursiveMethod (5); returns 15:
public static int recursiveMethod (int num) (
if (num == 0)
return 1;
else {
if (numX2!=0)
return num * recursiveMethod (num -1);
else
return recursiveMethod (num-1);
}
}
1 What is the base case?
2. What does the following statement check?
3. What does the method do?
Answer:
Hence the answer is given as follows,
Explanation:
Base Case:-
If (num == 0) //This is the base case for the given recursive method
return 1;
If(num % 2!=0) checks whether num is odd.
The above condition is true for all odd numbers and false for even numbers.
if the remainder is not equal to zero when we divide the number with 2 then it is odd.
The method:-
The above recursive method calculates the product of odd numbers up to the given range(that is num)
For num=5 => 15(5*3*1).
For num=7 => 105(7*5*3*1).
For num=10 => 945(9*7*5*3*1).
Write a function that takes six arguments of floating type (four input arguments and two output arguments). This function will calculate sum and average of the input arguments and storethem in output arguments respectively. Take input arguments from the user in the main function.
Answer:
Answer:Functions in C+
The integer variable n is the input to the function and it is also called the parameter of the function. If a function is defined after the main() .....
