Thank you for the help!

Answer:

more than 12

Step-by-step explanation:

because one of the numbers is already larger than 12

Answer:

Step-by-step explanation:

Even functions have symmetry about the y-axis, so the graphs of even functions are the bottom 2.

Answer:

plotting x = 2

see the x- axis look for the point x = 2(on right side of the origin ). Mark that point and draw a straight line parallel to the y- axis.

This is the graph of x = 2

plotting y = -4

see the y- axis and then look for the point y= -4 (that must be 4 units below the origin). Mark that point and draw a straight line parallel to the x- axis.

This is the graph of y = -4

we see that, the graph x = 2 is parallel to the y-axis whereas the graph y = -4 is parallel to the x- axis.

Answer:

:

Example Question #1:

Step-by-step explanation:

Which of the following is the equation of a line that is parallel to the line 4x – y = 22 and passes through the origin?

Possible Answers:

4x – y = 0

(1/4)x + y = 0

4x + 8y = 0

4x = 8y

y – 4x = 22

Correct answer:

4x – y = 0

Explanation:

We start by rearranging the equation into the form y = mx + b (where m is the slope and b is the y intercept); y = 4x – 22

Now we know the slope is 4 and so the equation we are looking for must have the m = 4 because the lines are parallel. We are also told that the equation must pass through the origin; this means that b = 0.

In 4x – y = 0 we can rearrange to get y = 4x. This fulfills both requirements.

', .

Answer:

Step-by-step explanation:

Total cost of plant:

Greg makes total of:

Since Greg mare than cost, he has a profit and the amount is:

Answer:

y=0

Step-by-step explanation:

Rewrite Evaluate Powers:

3[tex]3^{2y-1}+3^{-1}+2*3^{y}*3^{-1}=1[/tex]

Calculate:

[tex](3^{y})^{2}*\frac{1}{3} +2*3^{y}*\frac{1}{3}=1[/tex]

Solve using substitution:

[tex](3^{y})^{2}*\frac{1}{3} +\frac{2}{3} *3^{y}=1[/tex]     [tex]t=3^{y}[/tex]

Solve the equation for t:

[tex]t^{2}*\frac{1}{3}+\frac{2}{3}t=1[/tex]

t=-3

t=1

Substitute back to t=3^y

3^y=-3

3^y=1

y∉R

[tex]3^{y}=1[/tex]

y=0

Answer:

The answer is <AQS = BQS when AS=BQ and AQ=BQ

Step-by-step explanation:

Answer:

Step-by-step explanation:

(cos 4a*cos 2a+sin 4a*sin 2a)/sin 4a

=[cos (4a-2a)]/sin 4a

=(cos 2a)/sin 4a

=(cos 2a) /(2 sin 2a cos 2a)

=1/(2 sin 2a)

=1/2 csc 2a

Answer:

Answer:[tex]13c = 65 \ \ c = \frac{65}{13} \ \ c = 5[/tex]  More

i will solve it first i need full form

Answer:

When i tried solving it, there was no GCF except for 1.

However, the GCF of the numerator is 7

3:5

Step-by-step explanation:

change the kilogram into gram and then divide it

Answer:

3 : 5

Step-by-step explanation:

The quantities must have the same units

1 Kg = 1000 g , then

600 : 1000 ( divide both parts by 200 )

= 3 : 5 ← in simplest form

Answer:

Step-by-step explanation:

[tex]volume of cone=\frac{1}{3} \pi r^2h\\=\frac{1}{3} \pi (4)^2 \times 3\\=16 \pi \\\approx 50 in^3[/tex]

Answer:

answer is C 50 in³are you fine with it

Answer:

x = 11.7

Step-by-step explanation:

[tex]\frac{50}{39}[/tex] = [tex]\frac{15}{x}[/tex]

50x = 585

x = 11.7

Answer:

[tex] a_n = 2n^2 + n + 1 [/tex]

Step-by-step explanation:

4, 11, 22, 37, 56

11 - 4 = 7

22 - 11 = 11

37 - 22 = 15

56 - 37 = 19

After the first difference, 11 - 4 = 7, each difference is 4 more than the previous difference.

Difference of differences:

11 - 7 = 4

15 - 11 = 4

19 - 15 = 4

Since we need the difference of differences to find a constant, this must be a second degree function.

[tex] a_1 = 4 = 2^2 + 1(0)[/tex]

[tex] a_2 = 11 = 3^2 + 2 = 3^2 + 2(1) [/tex]

[tex] a_3 = 22 = 4^2 + 6 = 4^2 + 3(2) [/tex]

[tex] a_4 = 37 = 5^2 + 12 = 5^2 + 4(3) [/tex]

[tex]a_5 = 56 = 6^2 + 20 = 6^2 + 5(4)[/tex]

[tex] a_n = (n + 1)^2 + (n)(n - 1) [/tex]

[tex] a_n = (n + 1)^2 + (n)(n - 1) [/tex]

[tex] a_n = n^2 + 2n + 1 + n^2 - n [/tex]

[tex] a_n = 2n^2 + n + 1 [/tex]

SSS (side-side-side) requires that all three sides of the potentially congruent triangles be congruent.

Triangle WVU & Triangle UBW are our two triangles.

The middle line, UW and WU are congruent by the reflexive property, so that is not the information we need to prove SSS.

For SSS, we need to know that sides WV and UB are congruent.

Hope this helps!

Answer:

a shipping container ,the ones they use in large cargo ships

Answer:

y=-3×5

so'n

y=-15ans

another has no number only one number 2 alphabets

Answer:

22x 28 x 25 x 30 = 462000

whats are the units.....cm or m

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{22(28)(25)(30)}\\\large\textsf{22(28) = \bf 616}\\\large\textsf{616(25)(30)}\\\large\textsf{616(25) = \bf 15,400}\\\large\textsf{15,400(30)}\\\large\textsf{ = \bf 462,000}\\\\\\\\\\\\\boxed{\boxed{\large\textsf{Answer: \huge \bf 462,000}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

A √202km

Step-by-step explanation:

x²=11²-9²

x²=121-81

x²=202

√x²=√202

x=√202

Answer:

x+115=180 x=65

90+65+y=180 y=25

Step-by-step explanation:

Answer:

The surface area is 80.9.

Step-by-step explanation:

Answer:

Assume x greater-than-or- equal-to 0 and y ... 0 StartRoot x squared y cubed EndRoot + 2 StartRoot x cubed y Superscript 4 Baseline EndRoot + x y StartRoot y EndRoot.

Step-by-step explanation:

Option (b) is correct.

The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy is  2xy\sqrt{y}+2xy^2\sqrt{x}2xyy+2xy2x

Step-by-step explanation:

Given:Expression \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy

We have to find the sum of the given expression and choose the correct from the given options.

Consider the given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy .

\sqrt{x^2y^3}x2y3 can be written as \sqrt{x^2y^2y}=xy\sqrt{y}x2y2y=xyy

Also, 2\sqrt{x^3y^4}2x3y4 can be written as 2\sqrt{x^3y^4}=2\sqrt{x^2x(y^2)^2}=2xy^2\sqrt{x}2x3y4=2x2x(y2)2=2xy2x

Now, the given expression becomes,

x2y3+2x3y4+xyy

=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}=xyy+2xy2x+xyy .

Now, adding like term, terms having same variable with same degree.

=2xy\sqrt{y}+2xy^2\sqrt{x}=2xyy+2xy2x .

Thus, The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy is  2xy\sqrt{y}+2xy^2\sqrt{x}2xyy+2xy2x

Answer:

Yeah, so that is right, just put it into a formula.

[tex]9.07*10x^{-2}[/tex]

Answer:

2

Step-by-step explanation:

a2 = a1×3

a3 = a2×3 = a1×3×3

=>

an = an-1 × 3 =

[tex]a1 \times {3}^{n - 1} [/tex]

a5 = 162 = a1×3⁴ = a1×81

a1 = 162/81 = 2

Answer:

26

Step-by-step explanation:

We have the average rate of change on the interval [a,b] as

f(b)-f(a)/(b-a)

b = 1 and a = -4

f(b) = f(1) = -2(1)^3 -5 = -2-5 = -7

f(a) = f(-4) = -2(-4)^3 -5 = 128 -5 = 123

so we have;

(123 + 7)/(1+4) = 130/5 = 26

Answer:

11

Step-by-step explanation:

(2x -9) + (x + 2) = 23

2x + x -9 + 2 = 23

3x - 7 = 23

3x = 23 + 7

x = 10

RS = 2x - 9

RS = (2 * 10) - 9

RS = 20 - 9

RS = 11

Answer:

14 students walk

Step-by-step explanation:

40 total

22 girls

18 boys - 7 boys who cycle = 11 boys - 6 who take the bus. That leaves 5 boys who walk.

9 girls walk

5 + 9 = 14 total.