The amount of solar radiation received by Earth from the sun, known as _______________________, is greatest when the sun is directly overhead a location. (Answer must be correctly spelled and is case sensitive).

Answers

Answer 1

The amount of solar radiation received by Earth from the sun, known as insolation, is greatest when the sun is directly overhead a location.

Answer 2

The amount of solar radiation received by Earth from the sun is known as insolation, solar insolation is greatest when the sun is directly overhead a location.

What is solar energy?

The energy transferred from the Sun in the form of electromagnetic radiation is known as the solar energy

It can be used as thermal energy for various life purposes as well as for electricity conversion with the help of solar photovoltaic cells

The ratio of total electrical energy generated by a solar photovoltaic panel to its total thermal energy is known as solar energy efficiency. The solar panel's area and design have an impact on how energy-efficient it is.

Thus, the term "insolation" refers to the amount of solar radiation that Earth receives from the sun. Solar insolation is highest when the sun is directly overhead a location.

Learn more about solar energy from here, refer to the link;

brainly.com/question/9704099

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Related Questions

The standard metric unit of volume is the _____.

cubic centimeter
liter
milliliter
cubic meter

Answers

Answer:

. The SI unit of volume is the cubic meter (m3), which is a derived unit.

Liter (L) is a special name for the cubic decimeter (dm3).

Why Newton's law of gravitation also called universal law?

Answers

Answer:

Explanation:

Newton's law of gravitation states that every particle of matter attracts any other particle in the universe with a force directly proportional to the product of there masses and inversely proportional to the square of the distance between them.

This law is also called universal law because it is applicable to all masses at all distances irrespective of the medium.

physics class 9 chapter 8 please tell​ please

Answers

Answer:

(a) The motion is uniform

(b)  11.11 m/s

Explanation:

(a)

From the table below, the motion of the bus is uniform.

(b)

Speed(s) = Δd/Δt

s = Δd/Δt............. Equation 1

From the table,

Given: Δd = 10 km = 10000 m, Δt = 15 minutes = (15×60) = 900 seconds

Substitute these values into equation 1

s = 10000/900

s = 11.11 m/s

what happens to gravitational force when distance is quarter from the original
please answer it faster help me

Answers

Answer:

The force of gravitational attraction between them also decreas

URGENT
A student runs at 4.5 m/s [27° S of W] for 3.0 minutes and then he turns and runs at 3.5 m/s [35° S of E] for 4.1 minutes.

a. What was his average speed?

b. What was his displacement?

PLEASE SHOW ALL WORK​

Answers

Answer:

(a) 3.93 m/s

(b) 861.66 m

Explanation:

A = 4.5 m/s  [27° S of W] for 3.0 minutes

B = 3.5 m/s [35° S of E] for 4.1 minutes

Distance A = 4.5 x 3 x 60 = 810  m

Distance B = 3.5 x 4.1 x 60 = 861 m

(a) The average speed is defined as the ratio of the total distance to the total time.

Total distance, d = 810 + 861 = 1671 m

total time, t = 3 + 4.1 = 7.1 minutes = 7.1 x 60 = 426 seconds

The average speed is

[tex]v=\frac{1671}{426}=3.93 m/s[/tex]

(b)

[tex]\overrightarrow{A} = 810(- cos 27 \widehat{i} - sin 27 \widehat{j})=- 721.7 \widehat{i} - 367.7 \widehat{j}\\\\\overrightarrow{B} = 861( cos 35 \widehat{i} - sin 35 \widehat{j})= 705.3 \widehat{i} - 493.8 \widehat{j}\\\\\overrightarrow{C} = (- 721.7 + 705.3) \widehat{i} - (367.7 + 493.8) \widehat{j} \\\\\overrightarrow{C}= - 16.4 \widehat{i} - 861.5 \widehat{j}[/tex]

The magnitude is

[tex]C =\sqrt{16.4^2+861.5^2} = 861.66 m[/tex]

what do you think will happen to the people in the airplane if their location is unknown?​

Answers

Question:

What do you think will happen to the people in the airplane if their location is unknown?

My opinion:

I mean what are the circumstances? Is it just a rogue pilot that takes a random plane with all the passengers Hostage or is It bad whether an they lose connection to the airport? I Mean either way, If I was on a plane being held hostage, or the plane crashing, I Would be a in a panic type state of mind. I Would be worried about what will happen when the plane crashes, I would worry about my friends or family that is aboard the plane with me, I Would be scared for my life because I Don't know if i would make it out alive.

Also:

How would they know their location is unknown wouldn't the Pilot be the only one to know exactly where there with their navigating system, But then again there was this time I headed to Florida an They had mini tv's on the seats of each chair, where you could: Watch movies, listen to music, an Also see exactly where you are in the world. It was really amazing actually.

coulomb what is the meaning in physics??​

Answers

Answer:

Coulomb, unit of electric charge in the metre- kilogram- second- ampere system, the basis of SI system of physics unit. The coulomb is defined as the quantity of electricity transported in one second by a current of one ampere.


The designer tested how the number of cells affected the number of steps that could
be taken before the lights stopped working.
Figure 2 shows the results.
Figure 2
1600
1400
1200
1000
Number of
steps in
800
thousands
600
400
200
0
1
5
2 3 4
Number of cells
1
3
Determine how many more steps could be taken when the number of cells was
increased from 3 to 5
[2 marks
Number of steps
=
thousand

Answers

Answer:

1000.

Explanation:

Thousand more steps could be taken when the number of cells was  increased from 3 to 5 because in the data, the number of cells i.e. 5 was achieved on 1000 steps. According to the data, the number of cells i.e. 1 was achieved on 800 steps, the number of cells i.e. 5 was achieved on 1000 steps, the number of cells i.e. 2 was achieved on 600 steps, the number of cells i.e. 3 was achieved on 400 steps and the number of cells i.e. 4 was achieved on 200 steps. So we can say that 1000 steps are needed for the number of cells increased from 3 to 5.


A box has a mass of 4kg and surface area 4m². Calculate the
pressure exerted by the box on the floor.

Answers

Answer:

10 pa

Explanation:

4kg* 10 (or 9.8m/s2) = 40

40N /4m2 =10

An object weighs 2.2 pounds on Earth and has a mass of 1 kilogram. What are the weight and mass of the same object in space where there is no gravity acting on it?

Answers

Answer:

Heavier than 2.2 pounds

Explanation:

your initial speed is zero. if you increased your speed by 4 m/s after only 2 seconds and continue to accelerate at the same rate, what will your speed be after 10 seconds?

Answers

Answer:

20 m/ s

Explanation:

change in velocity = 4m/ s

[tex]acceleration = \frac{rate \: of \: change \: of \: velocity}{time} [/tex]

[tex]acc = \frac{4}{2} \\ = 2[/tex]

initial velocity = 0m/ s

let velocity after 10s be v

[tex]2 = \frac{v - 0}{10} [/tex]

cross multiplying

[tex]20 = v[/tex]

so the velocity after 10s will be 20m/s

Glass lenses are practically opaque to an emission source with the wavelength shorter than 400nm. (True or False)

Answers

Answer:

the statement is TRUE

Explanation:

Most lenses are made of glass that has a strong absorption below 400 nm,

Only special evaporation lenses are made of quartz and fused silica which has a high absorption below 200 nm.

therefore the statement is TRUE

A dart is thrown horizontally with an initial speed of 19 m/s toward point P, the bull's-eye on a dart board. It hits at point Q on the rim, vertically below P, 0.19 s later. (a) What is the distance PQ

Answers

Answer:

Explanation:

The dart will go forward horizontally with velocity of 19 m/s. It will also fall downwards with initial velocity of zero and gravitational acceleration of 9.8 m/s².

Distance PQ covered by the dart can be calculated using the following formula.

s = ut + 1/2 at²

u is initial velocity , a is acceleration and t is time.

Putting the values

s = 0 + 1/2 x 9.8 x .19²

= .1769 m

= 17.69 cm.

Please help
Will give the brainliest!​

Answers

Answer:

both answer is option C

Explanation:

tag me brainliest

The idea that the universe began from a single point and expanded to its current size explains a large number of observations, including those in the table below.

Observations Explained
The universe consists mostly of low-mass elements.
Cosmic microwave background is nearly the same in all directions.
Light from other galaxies shows that these galaxies are moving away from Earth.
In addition, many predictions based on the idea have led to additional observations that support it. Which best describes this idea of the origin of the universe?

Answers

Answer:

theory

Explanation:

took the quiz

Stellar nucleosynthesis a. produces elements with an atomic number greater than 26 (iron). b. is a process that happens during the death of stars. c. is the process by which stars create the heavier elements. d. is a stream of atoms emitted from a star.

Answers

Answer:

C: the process by which stars create the heavier elements

Explanation:

Stellar nucleosynthesis is defined as the process of nuclear fusion by which heavier elements are formed within stars by from the combination of protons and neutrons gotten from the nuclei of lighter elements.

Looking at the options, the correct one is Option C

A child is playing on a swing. As long as he does not swing too high the time it takes him to complete one full oscillation will be independent of

Answers

Answer:

We know that for a pendulum of length L, the period  (time for a complete swing) is defined as:

T = 2*pi*√(L/g)

where:

pi = 3.14

L = length of the pendulum

g = gravitational acceleration = 9.8 m/s^2

Now, we can think on the swing as a pendulum, where the child is the mass of the pendulum.

Then the period is independent of:

The mass of the child

The initial angle

Where the restriction of not swing to high is because this model works for small angles, and when the swing is to high the problem becomes more complex.

(12 points) Analysis from the point where the block is released to the point where it reaches the maximum height i) Calculate the highest height reached by the block (or the largest distance travelled along the ramp.) ii) Calculate the work done by the gravitational force. iii) Calculate the work done by the normal force. iv) Calculate the work done by the friction force.

Answers

Answer:

i) a₁ = -g (sin θ + μ cos θ), x = v₀² / 2a₁

ii) W = mg L sin  θ ,  iii)     Wₙ = 0

iv)  W = - μ m g  L cos  θ x

Explanation:

With a drawing this exercise would be clearer, I understand that you have a block on a ramp and it is subjected to some force that makes it rise, for example the tension created by a descending block.

The movement is that when the system is released, the tension forces are greater than the friction and the component of the weight and therefore the block rises up the ramp

At some point the tension must become zero, when the hanging block reaches the ground, as the block has a velocity it rises with a negative acceleration to a point and stops where the friction force and the weight component would be in equilibrium along the way. along the plane

i) Let's use Newton's second law

the reference system is with the x axis parallel to the ramp

Axis y

      N - W cos θ = 0

X axis

      T - W sin θ - fr = ma

the friction force is

      fr = μ N

      fr = μ mg cos θ

we substitute

      T - m g sin sin θ - μ mg cos θ = m a

      a = T / m - g (sin θ + μ cos θ)

With this acceleration we can find the height that the block reaches, this implies that at some point the tension becomes zero, possibly when a hanging block reaches the floor.

      T = 0

       a₁ = -g (sin θ + μ cos θ)

       v² = v₀² - 2a1 x

       v = 0       at the highest point

       x = v₀² / 2a₁

ii) the work of the gravitational force is

       W = F .d

       W = mg sin  θ   L

iii) the work of the normal force

the force has 90º with respect to the displacement so cos 90 = 0

         Wₙ = 0

iv) friction force work

friction force always opposes displacement

         W = - fr d

         W = - μ m g cos  θ L

What will happen to the gravitational force when the distance between the centre of the two bodies is halved ?​

Answers

Explanation:

when the distance between the 2 objects is halved, the gravitational force between the 2 objects is doubled. when the distance between the 2 objects is doubled then the gravitational force doubles.

A car is stationary. It accelerates at 0.8 ms^2
for 10 s and then at 0.4 ms^2
for a further 10 s. Use
the equations of motion to deduce the car’s final displacement. You will have to split the journey
into two parts, since the acceleration changes after 10 s.

Answers

Answer:

the car’s final displacement is 60 m

Explanation:

Given;

initail velocity of the car, u = 0

acceleration of the car, a = 0.8 m/s²

time of motion, t = 10 s

The first displacement of the car:

[tex]x_1 = ut + \frac{1}{2} at^2\\\\x_1 = 0 + \frac{1}{2} (0.8)(10)^2\\\\x_1 = 40 \ m[/tex]

The second displacement of the car;

acceleration, a = 0.4 m/s²,   time of motion, t = 10 s

[tex]x_2 = ut + \frac{1}{2} at^2\\\\x_2 = 0 + \frac{1}{2} (0.4)(10)^2\\\\x_2 = 20 \ m[/tex]

The final displacement of the car;

x = x₁  +  x₂

x = 40 m  +  20 m

x = 60 m

Therefore, the car’s final displacement is 60 m

the suns energy comes from which nuclear reaction?

Answers

Nuclear fusion is the answer

100 POINTS !!! PLEASE HELP !!!!
What is the independent variable?
What is the dependent variable?
I
Materials

1. 4 antacid tablets
2. 2 clear cups labeled Hot and Cold
3. Water
4. Timing device

Answers

Answer:

dependent: the outcome of the experience

independent variable: everything literaly.

Independent is where you change some variables and see the result

Dependent is literaly the result, or the outcome dependent on the exprience.

Explanation:

I got u.

a stone of mass 250kg and another stone of mass 400 kg are kept at a distance of 100m what amount of gravitational force develops between them?​

Answers

Explanation:

Hey there!

Given;

Mass of one object (m1) = 250kg

Mass of another object (m2) = 400 kg

Distance (d) = 100 m

Gravitational constant (g) = 6.67*10^-11

Now;

[tex]f = \frac{g.m1.m2}{ {d}^{2} } [/tex]

Keep all values;

[tex]f = \frac{6.67 \times {10}^{ - 11} \times 250 \times 400}{ {(100)}^{2} } [/tex]

Simplify

[tex]f = \frac{6.67 \times {10}^{ - 11} {10}^{5} }{10000} [/tex]

[tex]f = \frac{6.67 \times {10}^{ - 6} }{10000} [/tex]

Therefore, gravitational force is 6.67*10^-10.

Hope it helps!

Find the moment of inertia of a hoop (a thin-walled, hollow ring) with mass MMM and radius RRR about an axis perpendicular to the hoop's plane at an edge.

Answers

Answer:

I = sum m *r^2    where m represents the (small) individual masses and r is the distance of that mass from center of rotation

Note:  sum m = M

For the hoop given all masses are at a distance RRR from the center of rotation

I = MMM * RRR^2

In the hydraulic system depicted, the cylinder on the left has a diameter of 2 inches and the cylinder on the right has a diameter of 6 inches. If 100 lbs of force was applied to the cylinder on the left, what force would be exerted on the cylinder on the right

Answers

Answer:

F2 = 900 lbs

Explanation:

From pascal principle;

F1/A1 = F2/A2

Force on cylinder at left; F1 = 100 lbs

Diameter of cylinder at left; d1 = 2 inches

Diameter of cylinder at right; d2 = 6 inches

Formula for area of top of cylinder = πr²

Thus;

Area of top of left cylinder; A = π × 2² = 4π

Area of top of right cylinder; A = π × 6² = 36π

Thus;

100/4π = F2/36π

F2 = (36π × 100)/4π

F2 = 900 lbs

A boy im50kg at rest on a skateboard is pushed by another boy who exerts a force of 200 N on him. If the first boy's
final velocity is 8 m/s, what was the contact time?
seconds

Answers

Answer:

Time, t = 2 seconds

Explanation:

Given the following data;

Mass, m = 50 kg

Initial velocity, u = 0 m/s (since it's starting from rest).

Final velocity, v = 8 m/s

Force, F = 200 N

To find the time, we would use the following formula;

[tex] F = \frac {m(v - u)}{t} [/tex]

Making time, t the subject of formula, we have;

[tex] t = \frac {m(v - u)}{F} [/tex]

Substituting into the formula, we have;

[tex] t = \frac {50(8 - 0)}{200} [/tex]

[tex] t = \frac {50*(8)}{200} [/tex]

[tex] t = \frac {400}{200} [/tex]

Time, t = 2 seconds

Two uses of static electricity and dangers of static electricity

Answers

Answer: The uses of static electricity include:

--> photocopying machines

--> precipitators

The dangers of static electricity include:

--> sparks that can lead to explosion

--> Damage to electronic equipment

Explanation:

STATIC electricity is defined as the imbalance that exists between a positive and a negative charge either within or outside an object. This is because all physical objects are made up of atoms which contains protons, electrons and neutrons. The protons are positively charged, the electrons are negatively charged, and the neutrons are neutral. This shows that physical objects are made up of charges.

Opposite charges attract each other (negative to positive). Like charges repel each other (positive to positive or negative to negative). Most of the time positive and negative charges are BALANCED in an object, which makes that object neutral.

Applications( uses) of static electricity include:

--> photocopying machines: Inkjet photocopiers and printers use static electricity to guide a minute jet of ink to the page’s precise position.

--> precipitators: the static electricity is applied in an electrostatic precipitator whereby they remove smoke from waste gases before they pass out of the chimneys in power stations that burn fossil fuels.

The disadvantages (dangers) of static electricity include:

--> Sparks that can lead to explosion: sparks generated from static electricity can cause fires or explosions due to the ignition of flammable or explosive mixtures.

--> Damage to electronic equipment: this is due to components from electrostatic discharge.

When should a line graph be used?

Answers

Line graphs are used to track changes over short and long periods of time. When smaller changes exist, line graphs are better to use than bar graphs. Line graphs can also be used to compare changes over the same period of time for more than one group.

In a science museum, a 130 kg brass pendulum bob swings at the end of a 14.4 m -long wire. The pendulum is started at exactly 8:00 a.m. every morning by pulling it 1.7 m to the side and releasing it. Because of its compact shape and smooth surface, the pendulum's damping constant is only 0.010kg/s. You may want to review (Pages 405 - 407) . Part A At exactly 12:00 noon, how many oscillations will the pendulum have completed

Answers

Answer:

The time in which the pendulum does a complete revolution is called the period of the pendulum.

Remember that the period of a pendulum is written as:

T = 2*pi*√(L/g)

where:

L = length of the pendulum

pi = 3.14

g = 9.8 m/s^2

Here we know that  L = 14.4m

Then the period of the pendulum will be:

T = 2*3.14*√(14.4m/9.8m/s^2) = 7.61s

So one complete oscillation takes 7.61 seconds.

We know that the pendulum starts moving at 8:00 am

We want to know 12:00 noon, which is four hours after the pendulum starts moving.

So, we want to know how many complete oscillations happen in a timelapse of 4 hours.

Each oscillation takes 7.61 seconds.

The total number of oscillations will be the quotient between the total time (4 hours) and the period.

First we need to write both of these in the same units, we know that 1 hour = 3600 seconds

then:

4 hours = 4*(3600 seconds) = 14,400 s

The total number of oscillations in that time frame is:

N = 14,400s/7.61s = 1,892.25

Rounding to the next whole number, we have:

N = 1,892

The pendulum does 1,892 oscillations between 8:00 am and 12:00 noon.

An acceleration of 2m/s^2 is produced on a body by applying an effort of 50N. calculate mass of the body​

Answers

Answer:

25 kg

Explanation:

Given,

Acceleration ( a ) = 2 m/s^2

Force ( F ) = 50 N

To find : Mass ( m ) = ?

Formula : -

F = ma

m = F / a

= 50 / 2

m = 25 kg

So, the mass of the body is 25 kg.

Use the formula force = mass x acceleration

Your force = 50 Newton’s and your acceleration = 2 meters per second
So the equation should look like this
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