The average age of a college is 21.8 years. The average age of students of college is 24.2 years and average age of lecturers of college is 20.6 years. Find the ratio of the number of students to that of lecturers?​

Answers

Answer 1

Answer:

22,2

Step-by-step explanation:

average also known as mean

so you find it by adding all the numbers together and dividing them by how many there are

so 21,8 + 24,2 + 20.6 = 66,6 divided by 3 equals 22,2


Related Questions

determine whether the lines are parallel or not with proper reasons.​

Answers

Answer:

Parallel

Step-by-step explanation:

Because of interior alternate angles

Angle ARS and Angle BRS are Interior alternate angles in this case ..

Students at a virtual school are allowed to sign up for one math class each year. The numbers of students signing up for various math classes for the next school
year are given in the following table:
Grade Geometry Algebra II Pre-Calculus AP Statistics Total
10th
150
75
25
5
255
11th
50
100
75
20
245
12th
10
50
100
65
225
Total 210
225
200
90
725
Part A: What is the probability that a student will take AP Statistics? (2 points)
Part B: What is the probability that a 12th-grader will take either Pre-Calculus or AP Statistics? (2 points)
Part C: What is the probability that a student will take Algebra II given that he or she is in the 11th grade? (2 points)
Part D: Consider the events "A student takes Algebra II and "A student is a 10th-grader. Are these events independent? Justify your answer. (4 points)

Answers

A well formatted table of the distribution is attached below :

Answer:

0.124

0.733

0.408

Step-by-step explanation:

Using the table Given :

1.) P(AP Statistics) = 90 / 725 = 0.124

2.) P(12th grade ; Precalculus or AP Statistics) = (100 + 65) / 225 = 165 /225 = 0.733

3.) P(Algebra 11 | 11th grade) = P(Algebara11 n 11th grade) / P(11th grade) = 100 / 245 = 0.408

Please help me with 9 I really need it

Answers

Answer:

605 boys.

Step-by-step explanation:

5:7 means 5 parts consists of boys and 7 parts consist of girls.

Since 7 parts = 847, 1 part = 121 and 5 parts = 605

Hence there are 605 boys.

Hope you have a nice day :)

Find the smallest number from which 3 is to be subtracted so that the difference is exactly divisible 18,24,36

Answers

Answer:

72

Step-by-step explanation:

look at the prime factors of each number.

18 = 2*3^2

24 = 2^3*3

36 = 2^2*3^2

The most factors of 2 in any of these numbers is 3: 2^3

The most factors of 3 in any of these numbers is 2: 3^2

2^3*3^2 is 8*9 or 72.

72 is the lowest number exactly divisible by 18, 24, and 36.

Question 5 of 10
Which of these groups of values plugged into the TVM Solver of a graphing
calculator will return the amount of a 20-year loan with an APR of 19.2%,
compounded monthly, that is paidoff with monthly payments of $510?
A. N=20; 1%=19.2; PV = ; PMT=-510; FV=0; P/Y=12; C/Y=12;
PMT:END
B. N=240; 1%=19.2; PV = ; PMT=-510; FV=0; P/Y=12; C/Y=12;
PMT:END
C. N=240; 1%=1.6; PV = ; PMT=-510; FV=0; P/Y=12; C/Y=12;
PMT:END
O D. N=20; 1%=1.6; PV = ; PMT=-510; FV=0; P/Y=12; C/Y=12; PMT:END

Answers

Answer:

N=240;I%=5.6=-205000;PMT=;Fv=0;P/Y=12;C/Y=12;PMT:END

Step-by-step explanation:

A P E X

The group of values to be plugged into TVM solver is

N=240 ; I % = 19.2% , P = -205000 , PMT= -$510, Fv =0 , P/Y =12.

We have 20  year loan then the number of periods will be

N = 20 x 12

N= 240

and, the Monthly payment is $510 then

PMT = - 510

and, Interest = 19.2%

and, PV = - 205, 000

Thus, N=240 ; I % = 19.2% , P = -205000 , PMT= -$510, Fv =0 , P/Y =12.

Learn more about TVM here:

brainly.com/question/5566317

#SPJ7

I need help ASAP please please please

Answers

Answer:

n=39/5

Step-by-step explanation:

24=5(n-3)

24=5n-15

-5n= -15-24

-5n=39

n= 39/5

Agyappng is three times as old as Atsu .three years ago ,he was four times as old as Atsu ..how old is each boy now​

Answers

9514 1404 393

Answer:

Atsu is 9Agyappng is 27

Step-by-step explanation:

Let x represent Atsu's current age. Then Agyappng is 3x. Three years ago the relationship was ...

  (3x -3) = 4(x -3)

  9 = x . . . . . . . . . . . . add 12-3x

Atsu is 9; Agyappng is 27.

What are the zeros of f(x) = x^2 - x - 12?

A. x= -4 and x= 3
B. x=-3 and x = 4
C. x=-2 and x = 6
D. x=-6 and x = 2

Answers

Answer:

B. x = -3 and x = 4

General Formulas and Concepts:

Algebra I

Terms/CoefficientsFactoringSolving quadratics

Step-by-step explanation:

Step 1: Define

Identify

f(x) = x² - x - 12

Step 2: Solve for x

Factor:                                                                                                               (x - 4)(x + 3) = 0Solve:                                                                                                                 x = 4, -3

Please help, if you can’t answer all just answer one

Answers

Answer:

Inverses

Step-by-step explanation:

One things I could tell about the earth from this graph is that the northern and southern hemispheres are inverses because when the temp of one goes up over the months, the other goes down.

1. (02.01)
Solve -4(x + 10) - 6 = -3(x - 2). (1 point)
-40
-46
-52
52

Answers

Answer:

-52

Step-by-step explanation:

-4(x + 10) - 6 = -3(x - 2)

Distribute the left side to get:

(-4x + -40) - 6

Now distribute the right side to get:

-3x + 6

Arrange the equation as the following:

-4x - 40 - 6 = -3x + 6

Add the like terms on each side:

-4x - 46 = -3x + 6

Do the inverse operation of each term:

-x = 52

Now we need to get x to become a positive, so we just divide -x by -1 to get x.

And 52/-1 to get our final answer of -52.

Answer: -52

Step-by-step explanation:

-4(x + 10) - 6 = -3(x - 2)

Distribute the left side to get:

(-4x + -40) - 6

Now distribute the right side to get:

-3x + 6

Arrange the equation as the following:

-4x - 40 - 6 = -3x + 6

Add the like terms on each side:

-4x - 46 = -3x + 6

Do the inverse operation of each term:

-x = 52

Now we need to get x to become a positive, so we just divide -x by -1 to get x.

And 52/-1 to get our final answer of -52.

The fraction model below shows the steps that a student performed to find a quotient. Which statement best interprets the quotient? A: There are 5 1/5 five-sixths in 4 1/3. B: There 6 1/6 five sixths-in 4 1/3. C: There are 5 1/5 four and one-thirds in 5/6. D: There are 6 1/6 four and one-thirds in 5/6.

Answers

Answer:

The answer is D  

Step-by-step explanation:

there are 8 1/6 five and one sixth in 2/3

How to do this question?

Answers

Answer:

40

Step-by-step explanation:

2x² - 5y + 7 when x = 2 and y = -5

2(2)² - 5(-5) + 7

= 2(4) -5(-5) + 7

= 8 + 25 + 7

= 40

I am planning to attend a company-paid conference. My charges will include $412.00 for airfare, $378.00 for conference registration, and $210.00 for food.”

Supervisor: “Please submit an expense form for a total of __________ when you return.”

Answers

Answer:

$1000.00

Step-by-step explanation:

The supervisor is asking for an expense form of a total (?) when you return.

Given the charges given in the word problem, it is only logical to assume the supervisor wants a expense form of how much you spent (total) on the trip. Thus, you add!

To draw a graph for y = 3/4x + 7, a person can draw a point at x of 0 and y of ___, a second point by going over 3 and up ___, and then draw a line through the points

Answers

I got b5
At least that’s what I got

For drawing the graph for y = 3/4x + 7, a person can draw a point at x of 0 and y of __7_, a second point by going over 3 and up __8.25__, and then draw a line through the points.

How to know if a point lies in the graph of a function?

All the points (and only those points) which lie on the graph of the function satisfy its equation.

Thus, if a point lies on the graph of a function, then it must also satisfy the function.

For this case, the equation given to us is:

[tex]y = \dfrac{3}{4}x + 7[/tex]

Any equation of the form [tex]y = mx + c[/tex] where m and c are constants and x and y are variables is the equation of a straight line.

For a straight line to be characterized, only two points are sufficient.

For x = 0, the y-coordinate would be such that it would satisfy the equation [tex]y = \dfrac{3}{4}x + 7[/tex]

Putting x = 0, we get:

[tex]y = \dfrac{3}{4} \times 0 + 7 = 7[/tex]

Thus, y-coordinate of the point on this line whose x-coordinate is 0 is 7. Thus, (0,7) is one of the point's coordinate on the considered line.

Putting x = 3, we get:

[tex]y = \dfrac{3}{4} \times 3 + 7 = 9.25[/tex]

Thus, y-coordinate of the point on this line whose x-coordinate is 0 is 9.25 . Thus, (0,9.25) is another of the point's coordinate on the considered line.

Thus, for drawing the graph for y = 3/4x + 7, a person can draw a point at x of 0 and y of __7_, a second point by going over 3 and up __8.25__, and then draw a line through the points.

Learn more about points lying on graph of a function here:

brainly.com/question/1979522

Consider the differential equation: 2y′′−13y′−7y = 0


a. Show that, for any constants A and B, the following is a solution to the above differential equation: y = Ae^(−9x)+Be^(x/3)

b. Find the values A and B that make the above general solution into a solution for the following initial value problem: 2y′′−13y′−7y = 0; y(0) = 3, y′(0) = −5

Answers

a) Finding the derivatives and replacing into the equation, we reach an identity, an thus, for any value of the constants, [tex]y = Ae^{-7x} + Be^{\frac{x}{2}}[/tex] is a solution.b) Solving a system of equations, according to the conditions, we find that: [tex]A = -\frac{7}{15}, B = \frac{52}{15}[/tex]

--------------------------------------------------

Just a correction, the characteristic roots of the equation are [tex]y = 7[/tex] and [tex]y = -\frac{1}{2}[/tex], thus, we should test for:

[tex]y = Ae^{7x} + Be^{-\frac{x}{2}}[/tex]

--------------------------------------------------

Question a:

First, we find the derivatives, thus:

[tex]y = Ae^{7x} + Be^{-\frac{x}{2}}[/tex]

[tex]y^{\prime} = 7Ae^{-7x} - \frac{1}{2}Be^{-\frac{x}{2}}[/tex]

[tex]y^{\prime\prime} = 49Ae^{-7x} + \frac{1}{4}Be^{-\frac{x}{2}}[/tex]

Now, we replace into the equation:

[tex]2y^{\prime\prime} - 13y^{\prime} - 7y = 0[/tex]

[tex]2(49Ae^{-7x} + \frac{1}{4}Be^{-\frac{x}{2}}) - 13(7Ae^{-7x} - \frac{1}{2}Be^{-\frac{x}{2}}) - 7(Ae^{7x} + Be^{-\frac{x}{2}}) = 0[/tex]

[tex]98Ae^{-7x} + \frac{1}{2}Be^{\frac{x}{2}} - 91Ae^{-7x} + \frac{13}{2}e^{-\frac{x}{2}} - 7Ae^{7x} - 7Be^{-\frac{x}{2}} = 0[/tex]

[tex]98Ae^{-7x} - 91Ae^{-7x} - 7Be^{-\frac{x}{2}} + \frac{1}{2}Be^{\frac{x}{2}}  + \frac{13}{2}e^{-\frac{x}{2}} - 7Be^{-\frac{x}{2}} = 0[/tex]

[tex]0A + 0B = 0[/tex]

[tex]0 = 0[/tex], thus, we found the identity, and for each constant A and B, the following is a solution.

--------------------------------------------------

Question b:

[tex]y = Ae^{7x} + Be^{-\frac{x}{2}}[/tex]

Since [tex]y(0) = 3[/tex]

[tex]A + B = 3 \rightarrow B = 3 - A[/tex]

--------------------------------------------------

[tex]y^{\prime} = 7Ae^{-7x} - \frac{1}{2}Be^{-\frac{x}{2}}[/tex]

Since [tex]y^{\prime}(0) = -5[/tex]

[tex]7A - \frac{1}{2}B = -5[/tex]

Using [tex]B = 3 - A[/tex]

[tex]7A - \frac{3}{2} + \frac{A}{2} = -5[/tex]

[tex]\frac{14A}{2} + \frac{A}{2} = -\frac{10}{2} + \frac{3}{2}[/tex]

[tex]\frac{15A}{2} = -\frac{7}{2}[/tex]

[tex]15A = -7[/tex]

[tex]A = -\frac{7}{15}[/tex]

--------------------------------------------------

Then, B is given by:

[tex]B = 3 - A = 3 - (-\frac{7}{15}) = \frac{45}{15} + \frac{7}{15} = \frac{52}{15}[/tex]

Thus, the values are: [tex]A = -\frac{7}{15}, B = \frac{52}{15}[/tex]

A similar problem is given at https://brainly.com/question/2456414

Calculate the volume pyramid whose height de Priangular by of a 20cm, and has base of 8cm by 12cm by 150mm


Answers

Answer:

see it

Step-by-step explanation:

Mila wants to buy a scooter for Rs 62,000 . She has only Rs 19,000 with her, so she decides to take a loan from a bank for the remaining amount. The bank offers Mini three loan schemes as shown below. Mini has to return the loan amount with interest in equal monthly instalments


1) How much money does mila take as loan from the bank?

a) Rs 62,000
b) Rs 44,000
c) Rs 45,000
d) Rs 43,000​

Answers

Answer:

Scheme a 45000 is the answer

Answer is D Rs.43,000I hope this answer may be right

Most brainiest for the right answer on this problem!

Answers

Answer:

82.8

Step-by-step explanation:

mean = sum of all points, over the total given number of points

84 * 26 = 2184

2184 + 69 + 66 = 2319

Now the total number of tests is 26 + 2 or 28

So divide 2319 by 28

2319/28 = 82.82142

rounded to the nearest tenth is 82.8

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Stuck on this problem

Answers

9514 1404 393

Answer:

  -8,257,536·u^5·v^10

Step-by-step explanation:

The expansion of (a +b)^n is ...

  (c0)a^nb^0 +(c1)a^(n-1)b^1 +(c2)a^(n-2)b^2 +... +(ck)a^(n-k)b^k +... +(cn)a^0b^n

Then the k-th term is (ck)a^(n-k)b^k, where k is counted from 0 to n.

The value of ck can be found using Pascal's triangle, or by the formula ...

  ck = n!/(k!(n-k)!) . . . . where x! is the factorial of x, the product of all positive integers less than or equal to x.

This expansion has 11 terms, so the middle one is the one for k=5. That term will be ...

  5th term = (10!/(5!(10-5)!)(2u)^(10-5)(-4v^2)^5

  = (252)(32u^5)(-1024v^10) = -8,257,536·u^5·v^10

Suppose that 25% of people own dogs If you pick three people at random, what
is the probability that they all three own a dog? (Let me add that we don’t know the
populations size so calculate the probability as if the population is infinite.)

Answers

Answer:

1/64

Step-by-step explanation:

25% own a dog, so picking one person has a probability of 1/4 (0.25) for that person to own a dog.

picking 3 people means combining (multiplying) the probabilities of the non-overlapping and non-depending events.

picking the third person has 1/4 chance of owning a dog (as the population is "infinite") combined with the chance that also the second pick owned a dog, which has to be combined with the chance of the first pick owning a dog.

so,

1/4 × 1/4 × 1/4 = 1/4³ = 1/64 = 0.015625

Find the exact area of this triangle: 10V3 30° 20 [?] [ square units​

Answers

Answer:

50√3 square units.

Step-by-step explanation:

Let the two sides of the triangle given be 'a' and 'b'.

Let the angle between them be θ

From the question given above, the following data were obtained:

Side a = 20 units

Side b = 10√3

Angle (θ) = 30°

Area (A) =?

A = ½ × ab × Sineθ

A = ½ × 20 × 10√3 × Sine 30

A = ½ × 20 × 10√3 × ½

A = 10 × 5√3

A = 50√3 square units

Therefore, the area of the triangle is 50√3 square units

solve for x please help (show ur work)

Answers

Answer:

x = -3

Step-by-step explanation:

12 -4x-5x = 39

Combine like terms

12 - 9x = 39

Subtract 12 from each side

12-9x-12 = 39-12

-9x = 27

Divide by -9

-9x/-9 = 27/-9

x = -3

Answer:

x = -3

Step-by-step explanation:

12 - 4x - 5x = 39

Combine like terms

12 - 9x = 39

Subtract 12 from both sides

12 - 12 - 9x = 39 - 12

-9x = 27

Divide both sides by -9

-9x/-9 = 27/-9

x = -3

SOMEONE PLEASE HELP ME!!!!!!!!

Answers

9514 1404 393

Answer:

  PQ = 46

Step-by-step explanation:

Midsegment ST is half the length of base segment PQ.

  2×ST = PQ

  2×(5x -22) = 3x +19

  10x -44 = 3x +19 . . . . . . . eliminate parentheses

  7x = 63 . . . . . . . . . . . . add 44-3x

  x = 9 . . . . . . . . . . . . divide by 7

PQ = 3x +19 = 3×9 +19

PQ = 46

PLSSS HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Answers

Answer:

I believe its  EG and NE but i might be wrong

Step-by-step explanation:

Suppose you choose a marble from a bag containing 4 red marbles, 2 white marbles, and 3 blue marbles. You return the first marble to the bag and then choose again. Find P(red then blue).

Answers

Answer:

4/27

Step-by-step explanation:

total number of marbles=9

probability of red=4/9

since you returned the first marble, the total number of marbles remains the same

prob(Blue)=(3/9)=1/3

P(red then blue)=(4/9)*(1/3)

=4/27

Please help me!
14
33
46
60
200

Answers

Answer:

46

Step-by-step explanation:

200/2 = 100, and the x coordinate that line up with the y-coordinate of 100 is 46.

the image is located at the bottom of the screen.

Answers

Answer:

..... surface area = 16 km^2.

Select the correct answer.

What is the value of this expression when x = -6 and ?
4(x2 + 3) − 2y

Answers

Answer:

D. 157

Step-by-step explanation:

4(x^2+3)-2y

4(6^2+3)-2(-1/2) add in given values

4(39)+1.     start with parentheses

156+1.        combine like terms

157.            answer

Answer:

D. 157

Step-by-step explanation:

Hi there!

We want to find the value of the expression 4(x²+3)-2y is when x=-6 and y=-1/2

Let's first simplify the expression, as that will likely make it easier

Distribute 4 to both x² and 3

4x²+12-2y

That's the expression

Substitute -6 as x into the expression

4(-6)²+12-2y

Raise (-6) to the second power

4*36+12-2y

Multiply 36 by 4

144+12-2y

Add 12 and 144 together

156-2y

Now the expression is 156-2y

But remember that we know that y=-1/2, and we haven't substituted it into the expression yet

Substitute -1/2  as y into the expression

156-2(-1/2)

Multiply

156+2/2

Simplify

156+1

Add

157

Hope this helps!

Which is the best way to write (8/x) as a verbal expression?

Answers

Answer:

None of these.

Step-by-step explanation:

8/x is the result when 8 is divided by x.

If the areas of the given pairs of shapes are equal, find the value of x.​

Answers

Answer:

X= 8cm

Step-by-step explanation:

area of the square = s×s = 16×16 = 256cm

area of the rectangle = l×b = 32×x = 32x

Given , area of triangle = area of square

32x = 256

x= 256/32

x= 8cm

Answer:

[tex]x = 8cm[/tex]

Step-by-step explanation:

we are given a square and rectangle.we want to figure out x which is the width of the rectangle. we are also given a condition i.e

the area of the square equal to the area of the rectangle

therefore,

[tex] \displaystyle \rm A _{square } = A _{rect}[/tex]

recall the formula of the area of square and rectangle so,

[tex] \displaystyle {s}^{2} = lw[/tex]

now assign variables

[tex]s \implies16cm[/tex][tex]l \implies32cm[/tex][tex]w \implies x[/tex]

thus substitute:

[tex] \displaystyle 32cmx = {16cm}^{2} [/tex]

simplify square:

[tex] \displaystyle 32cmx = 256cm^2[/tex]

divide both sides by 32:

[tex] \displaystyle \boxed{x = 8cm}[/tex]

and we're done!

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