The distributive property is used to change the following expression from 3(5+6) to 3(5) + 3(6)

Answer:

a) 25/35

b) 30/42

Step-by-step explanation:

a)

Variable x = denominator if numerator is 25

5/7 = 25/x

5 × x = 7 × 25

5x = 175

x = 35

b)

Variable y = numerator if denominator is 42

5/7 = y/42

5 × 42 = 7 × y

210 = 7y

30 = y

25/35

30/42

To get 25/35 multiply by 5

To get 30/42 multiply by 6

Answer:

-78

Step-by-step explanation:

Zinc group :

Mean, x1 = 3328

σ1 = 640

Sample size, n1 = 28

Placebo group :

Mean, x2 = 3406

σ2 = 851

Sample size, n2 = 31

The point estimate for the true difference between the population means is obtained as :

Mean difference between population :

x1 - x2 = 3328 - 3406 = - 78

Answer:

b + 5; when b = 3.4 the distance Sandra rode is 17 miles.

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

I guess that is it may be

The length of CV is 5 units

The length of C’V’ is 7.5 units

The scale factor is 7.5 / 5 = 1.5

Answer: 1.5

9514 1404 393

Answer:

  (x, y') = (-13, 13)

Step-by-step explanation:

At the given value of x, f(x) = 2. Then 9f(x)-5 = 9(2) -5 = 13.

The point on the scaled, translated graph will be ...

  (x, y') = (-13, 13)

_____

The graph shows a function f(x) with a distinct feature (vertex) at (-13, 2). It also shows where that distinct feature moves to when the function is scaled and translated.

Answer:

x=4

y=7

Step-by-step explanation:

12=3x

x=4

6=y-1

y=6+1

y=7

Answer:

x=4

Step-by-step explanation:

Answer:

6.22 sec

Step-by-step explanation:

h(t) = 105t-16t^2

For values of t for which height will be 34 feet can be obtained by substituting 34 in place of h(t) and solving for t

34=105t-16t^2, using quadratic formula we have t=1/32*(105±sqrt(8849)) which translates to - 0.34sec and 6.22sec but as time can't be negative, time is 6.22sec

Answer: Hello the table related to your question is attached below

answer:

a) attached below

b) The process is out of control because two ( 2 ) values from the defect rate table are out of the control limits at 95% as seen in the p-chart in question ( A )

Step-by-step explanation:

a) p-chart for 95% confidence

std = 1.96

Total defects = ∑ number of defective items in the sample = 10

number of samples = 10

sample size ( n ) = 15

The P value for the process is calculated as :

Total defects / ( number of sample * sample size )

= 10 / ( 15 * 10 ) = 10 / 150 = 0.067

standard deviation ( σ ) = [tex]\sqrt{\frac{p(1-p)}{n } } = \sqrt{\frac{0.067(1-0.067)}{15} }[/tex]  =  0.065

next we determine the limits ( i.e. upper and lower )

UCL = p + zSp = 0.067 + 1.96(0.065 ) = 0.194

LCL = p - zSp = 0.067 - 1.96(0.065) = -0.060 ≈ 0 ( because LCL ≠ negative)

attached below is the required p-chart

b) The process is out of control because two ( 2 ) values from the defect rate table are out of the control limits at 95% as seen in the p-chart in question ( A )

Answer:

y= 1/2x-3/2

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b  where m is the slope and b is the y intercept

y = 1/2x+b

Using the point for x and y we can find b

-3 = 1/2(-3)+b

-3 = -3/2 +b

-6/2 = -3/2+b

Add 3/2 to each side

-6/2 +3/2 = b

-3/2 = b

y= 1/2x-3/2

Answer:

Step-by-step explanation:

y + 3 = 1/2(x + 3)

y + 3 = 1/2x + 3/2

y + 6/2 = 1/2x + 3/2

y = 1/2x - 3/2

==========================================================

Explanation:

area of rectangle = L*W = 129

L*W = 129

x*(2x-9) = 129

2x^2-9x = 129

2x^2-9x-129 = 0

Apply the quadratic formula. We'll use a = 2, b = -9, c = -129.

[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-9)\pm\sqrt{(-9)^2-4(2)(-129)}}{2(2)}\\\\x = \frac{9\pm\sqrt{1113}}{4}\\\\x \approx \frac{9\pm33.36165464}{4}\\\\x \approx \frac{9+33.36165464}{4}\ \text{ or } \ x \approx \frac{9-33.36165464}{4}\\\\x \approx \frac{42.36165464}{4}\ \text{ or } \ x \approx \frac{-24.36165462}{4}\\\\x \approx 10.59041366\ \text{ or } \ x \approx -6.09041364\\\\[/tex]

We ignore the negative solution because a negative length makes no sense.

The length is approximately L = 10.5904 cm.

The width is 2L-9 = 2*10.5904-9 = 12.1808 cm approximately.

As a quick check,

L*W = 10.5904*12.1808 = 128.99954432

which isn't too far off from 129. We have rounding error which is why we don't perfectly land on the target area value. If you wanted to get closer to the value 129, then use more decimal digits in the approximations of L and W.

----------------------------

If you draw a diagonal in the rectangle, then you form two identical or congruent right triangles.

Focusing on one of those triangles, we have

Apply the pythagorean theorem

a^2+b^2 = c^2

c = sqrt( a^2 + b^2 )

c = sqrt( (10.5904)^2 + (12.1808)^2 )

c = 16.1408940520653

c = 16.14

The diagonal is roughly 16.14 cm long.

Answer:

Let us check these out one at a time:

1. x + y is odd.  FALSE.  The sum of 2 odd numbers is even.

2. xy is odd.  TRUE.  The product of 2 odd numbers is odd.

3. x/y is odd.  TRUE.  The ratio of 2 odd numbers is odd, if the ratio is an integer.

4. x - y is odd.  FALSE.  The difference of 2 odd numbers is even.

Only statements 2 and 3 are TRUE, so that makes (C) the correct answer.

This differential equation is separable:

(1 + y²) dx + (1 + x²) dy = 0

(1 + y²) dx = - (1 + x²) dy

dy/(1 + y²) = -dx/(1 + x²)

Integrating both sides gives

arctan(y) = -arctan(x) + C

and solving for y gives (over an appropriate domain)

y = tan(C - arctan(x))

(the domain being -1 ≤ y ≤ 1).

Complete question is;

The cost of producing x units of a particular commodity is C(x) = ⅔x² + 6x + 45 shillings and the production level t hours into a particular production run is x(t) = 0.3t² + 0.04t. At what rate is cost changing with respect to time after 5 hours?

Answer:

dC/dt = 49.45

Step-by-step explanation:

Since C(x) = ⅔x² + 6x + 45

And x(t) = 0.3t² + 0.04t

This means that;

C(x) = C(x(t))

The rate at what cost is changing with respect to time is given as;

dC/dt

Thus, from chain rule;

dC/dt = (dC/dx) × (dx/dt)

dC/dx = (4/3)x + 6

dx/dt = 0.6t + 0.04

Now, when t = 5, then;

x(5) = 0.3(5)² + 0.04(5)

x = 7.7

Thus;

dC/dx = (4/3)x + 6 = (4/3)(7.7) + 6 = 16.267

At 5 hours,

dx/dt = 0.6(5) + 0.04 = 3.04

Thus;

dC/dt = 16.267 × 3.04

dC/dt = 49.45

Answer:

[tex]y=4x[/tex]

Answer:

y = -4x

hope that helped.........

Answer:

no solution

Step-by-step explanation:

multiply 2 and get 2x^2+18-4=0

combine like terms

2x^2+14=0

subtract 14

2x^2=-14

there can't be a square root of a negative number so there's no solution

Answer:

x = ±i sqrt(7)

Step-by-step explanation:

2(x^2+9)-4=0

Add 4 to each side

2(x^2+9)-4+4=0+4

2(x^2+9)=4

Divide by 2

2(x^2+9)/2=4/2

(x^2+9)=2

Subtract 9 from each side

x^2 +9-9 = 2-9

x^2 = -7

Taking the square root of each side

sqrt(x^2) =sqrt(-7)

x = sqrt(-1 *7)

x = ±i sqrt(7)

Answer:

point s: (-2,6)

-2 is the x coordinate

6 is the y coordinate

Answer:

re send it

Step-by-step explanation:

ty

Answer:

a. 9 students

b. 20 students

c. 4 students

Answer

4.8 degrees to the nearest tenth.

Step-by-step explanation:

The slope = rise / run = opposite side / adjacent side.

So the angle of inclination is the angle whose tangent is 1/12.

To the nearest tenth of a degree it is 4.8 degrees.

5(2x^2-x-2)(x-2)

Step-by-step

Answer:  [tex]5(\frac{10x^3}{5}+\frac{-25x^2}{5}+\frac{20}{5}) \\\\5(2x^3-5x^2+4)\\\\5(2x^2-x-2)(x-2)[/tex]

9514 1404 393

Answer:

  1

Step-by-step explanation:

The slope is given by the formula ...

  slope = (y2 -y1)/(x2 -x1)

  slope = (5 -4)/(3 -2) = 1/1 = 1

The slope of MN is 1.

__

Dilation does not change the slope.

Answer:

x = 14

y = -7

z = -3

but this is none of the provided answer options !

Step-by-step explanation:

it's really easy by principle. it's just some work to do.

we try to find equations to express one variable in terms of the others.

but one thing there is : your teacher made a mistake.

the right solution is x = 14, y = -7, z = -3

your teacher made a typo at d.

but the right answer should be d.

just to give you an idea how this can be done (and also to prove that there is a mistake by the teacher):

we can directly try to transform one expression into one that describes x by y and z.

and then another to describe e.g. z by y. and then solve the third one just for y. and then we get the other 2 by these other expressions.

or we can e.g. add or subtract one equation to/from another. this is one of these cases, because we can find really simple expressions that way :

we do

5x + 6y + 7z = 7

- (3x + 4y + 3z = 5)

- (2x + 2y + 3z = 5)

---------------------------

0x + 0y + z = -3

=> z = -3

3x + 4y - 3×3 = 5

3x = -4y + 14

x = (-4y + 14)/3

2×(-4y + 14)/3 + 2y - 9 = 5

(-8y + 28)/3 + 2y = 14

-8y + 28 + 6y = 42

-2y = 14

y = -7

x = (-4×-7 + 14)/3 = (28+14)/3 = 42/3 = 14

Using Pythagorean Theorem

[tex]\\ \sf\longmapsto H^2=P^2+B^2[/tex]

[tex]\\ \sf\longmapsto H^2=8^2+15^2[/tex]

[tex]\\ \sf\longmapsto H^2=64+225[/tex]

[tex]\\ \sf\longmapsto H^2=289[/tex]

[tex]\\ \sf\longmapsto H=\sqrt{289}[/tex]

[tex]\\ \sf\longmapsto H=17[/tex]