The hardware store where you work charge 80 cents including tax, for a pound of nails. A customer purchases 5 3/4 pound of nails. How much should you charge the customer for nails?​

Answer:

3/10

Step-by-step explanation:

If we have two points on a line, we can find the slope using the slope formula

m= ( y2-y1)/(x2-x1)

   = ( -1 - -4)/( 5 - -5)

   = ( -1 +4)/ ( 5 + 5)

  = 3/10

Answer:

A and D

Step-by-step explanation:

Total ice cream bars sold = sum of chocolate sold , vanilla and strawberry ice-creams sold.

=(1/2)x2 + (6/11)x + 8 + (5/9)x2 + (2/3) +(1/3)x2 + 4x +(4/3) (Given in the question)

=(25/18)x2 + (50/11)x + 10 (Adding terms corresponding to x2,x ,constant respectively)

Difference in chocolate and strawberry bars =[ (1/2)x2 + (6/11)x + 8] - [(1/3)x2 + 4x +(4/3)]

= (1/6)x2 - (38/11)x +(20/3)

So, the correct options are A and D

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ ([tex]z_{\alpha /2[/tex] × σ ) / E ]²

given that confidence level = 95%, so [tex]z_{\alpha /2[/tex]  = 1.96

Now,

a) Margin of error E = 500

n = [ ([tex]z_{\alpha /2[/tex] × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ ([tex]z_{\alpha /2[/tex] × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ ([tex]z_{\alpha /2[/tex] × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Answer:

pls give me brainliest plzzzzz

Step-by-step explanation:

the answer is in the above image

Answer:

my answer is 225/5 sorry comments for wrong

Answer:

[tex] \frac{4}{9} [/tex]

Step-by-step explanation:

[tex]p = \frac{favorable \: outcomes}{total \: outcomes} = \frac{4}{9} [/tex]

=============================================================

Explanation:

The probability you get a black marble on the first selection is 2/3 since we have 2 black marbles out of 2+1 = 3 total.

We put the marble back and then we have 2/3 as the probability of selecting another black marble on the second try. Nothing has changed because we put the marble back. That means the events are independent.

So we get (2/3)*(2/3) = 4/9 as the probability of selecting 2 black marbles in a row (with replacement).

Answer:

I think. . . sphere? SO SORRY IF IM WRONG!!

Step-by-step explanation:

Answer:

2/3

Step-by-step explanation:

P ( 8 or more) = number that are 8 or more) / total

                        = (6+4) / ( 2+3+6+4)

                         = 10/15

                          =2/3

Answer:

A)

Step-by-step explanation:

Answer:

77,786.251

Step-by-step explanation:

Answer:

77,786.251 is the answer that equals $42,690e(0.03)×(20)

Step-by-step explanation:

hey mate hope this help you...!

Answer:

square pyramid...........

Answer:

SQUARE PYRAMID

Step-by-step explanation:

Answer:

31.3

Step-by-step explanation:

Reference angle given = 56.1°

Hypotenuse = 56.1

Adjacent side = x = ?

We would apply CAH, which is:

Cos 56.1° = Adj/Hyp

Cos 56.1° = x/56.1

56.1 × Cos 56.1° = x

31.2895006 = x

x = 31.3 (approximated to the nearest tenth)

Answer:

Below in bold.

Step-by-step explanation:

a. SA = 2π r^2 + 2πrh

2πrh = SA - 2π r^2

h = (SA - 2πr^2)/2πr

When π = 3.14 we have

h = (SA - 6.28r^2)/ 6.28r

b. SA = 6.28*1.5^2 + 6.28*1.5* 5

= 61.23 in^2

Given:

Chung has 6 trucks and 5 cars in his toy box.

Brian has 4 trucks and 5 cars in his toy box.

To find:

The correct comparison of their ratios of trucks to cars.

Solution:

The ratio of trucks to cars is defined as:

[tex]\text{Ratio}=\dfrac{\text{Number of trucks}}{\text{Number of cars}}[/tex]

Chung has 6 trucks and 5 cars in his toy box. So, the ratio of trucks to cars is:

[tex]\text{Ratio}=\dfrac{6}{5}[/tex]

Brian has 4 trucks and 5 cars in his toy box.

[tex]\text{Ratio}=\dfrac{4}{5}[/tex]

We know that,

[tex]6>4[/tex]

[tex]\dfrac{6}{5}>\dfrac{4}{5}[/tex]

Therefore, the correct option is D.

Answer:

what the guy above me said

Step-by-step explanation:

so yeah he is right points

Answer:

4.91e-2 in decimal form is 0.0491

Answer:

Hence,

a)

Test statistic [tex]X^{2}[/tex] = 9.269.  

p value = 0.148

b)

Sunday=  15.23%, Monday= 12.62%, Tuesday= 13.10%, Wednesday=11.67%,

Thursday= 13.10%, Friday= 16.19%, Saturday= 18.09%.

Step-by-step explanation:

a)

                    relative observed    Expected       Chi square

Category   frequency(p)      [tex]O_{i}[/tex]    Ei=total*p    [tex](O-E)^{2}[/tex] [tex]R^{2}_{i} =(O_{i} -E_{i} )^{2} /E_{i}[/tex]

     1           0.142857143      64.0         60.00    16.00          0.267

    2           0.142857143      53.0       60.00     49.00         0.817

    3           0.142857143      55.0         60.00     25.00        0.417

    4           0.142857143      49.0       60.00     121.00        2.017

    5           0.142857143      55.0         60.00     25.00        0.417

    6           0.142857143      68.0         60.00     64.00        1.067

    7           0.142857143      76.0         60.00    256.00        4.267

  Total         1.000      420        420             556       9.269

Test statistic [tex]X^{2}[/tex] = 9.269.  

p value = 0.148 from excel: chidist(9.269,6)  

b)

Percentage %= Frequency of traffic occur on category x 100 / Total number of frequency given.

Category          Percentage%

Sunday                   15.23%

Monday                    12.62%

Tuesday                   13.10%

Wednesday           11.67%

Thursday           13.10%

Friday                   16.19%

Saturday                   18.09%

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The attachment shows the table of point values and the graph.

Answer:

1. 8

2 . 11

[tex]3 . \sqrt{128} \ or \ 8 \sqrt2[/tex]

Step-by-step explanation:

[tex]Distance = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2 }[/tex]

1 . ( 5 , - 2 ) and ( 5 , 6 )

  [tex]Distance = \sqrt{(5 -5)^2 + ( 6-(-2))^2} = \sqrt{ 0 + 8^2 } = \sqrt{64} = 8[/tex]

2 . ( 8 , 6 ) and ( - 3 , 6 )

  [tex]Distance = \sqrt{( -3 -8)^2 + ( 6 - 6)^2 } = \sqrt{ (-11)^2 + 0 } = \sqrt { 121 } = 11[/tex]

3. ( 5 , - 2 ) and ( -3 , 6 )

  [tex]Distance = \sqrt{(-3 - 5)^2 + ( 6 --2)^2} = \sqrt{(-8)^2 + ( 8)^2} = \sqrt{ 64 + 64 } = \sqrt{128}[/tex]

          [tex][ \ \sqrt{128} = \sqrt{ 2 \times 64} = \sqrt{ 2 \times 8^2 } = 8 \sqrt{2} \ ][/tex]

Answer:

The Area of the Enclosed Region Is 64/3.

Step-by-step explanation:

As Given in Question

We have, Curve 4x+[tex]Y^{2}[/tex]=12

& X=Y

Solution.

4Y+[tex]Y^{2}[/tex]=12   (X=Y)

[tex]Y^{2}[/tex]+4Y-12=0

[tex]Y^{2}[/tex]+6Y-2Y-12=0

Y(Y+6)-2(Y+6)=0

(Y-2)*(Y+6)=0

Y=2 & -6  (X=Y)

Now at (2,2) & (-6,-6) both curves intersect each other.

The Area Of Enclosed Region is    [tex]\int\limits^2_{-6} [(3-Y^{2}/4 )-Y] \, dy[/tex]

by Solving This Equation we get Area of Region = 64/3 .    

this equation Solution & Curve Diagram please see In Attachment .  

Answer:

yes but can be simplified

Step-by-step explanation:

area of shaded part = ( area of square - area of circle ) / 4

= [tex]\frac{12^2-\pi (6)^2}{4}[/tex]

= [tex]\frac{144-36\pi }{4}[/tex]

= [tex]\frac{144}{4}[/tex] - [tex]\frac{36\pi }{4}[/tex]

= 36 - 9π

Answer:

Area = 156 square cm

Step-by-step explanation:

9514 1404 393

Answer:

  (64x^28)/(5y^22)

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)^c = a^(bc)

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

__

First, eliminate the outside exponent on the left factor. Then use the above rules to combine factors with the same base.

  [tex]\displaystyle\left(\frac{4x^4}{5y^6}\right)^5\cdot\left(\frac{5^4y^8}{4^2x^{-8}}\right)=\frac{(4^5x^{20})(5^4y^8)}{(5^5y^{30})(4^2x^{-8})}=4^{5-2}5^{4-5}x^{20-(-8)}y^{8-30}\\\\=4^35^{-1}x^{28}y^{-22}=\boxed{\frac{64x^{28}}{5y^{22}}}[/tex]

Answer:

The one that's include a rows 2 1 1 2

Answer:

A

Step-by-step explanation:

they wanted the reduced echelon form.

On Edge. btw

Answer:

(0,6)

Step-by-step explanation:

Answer:

(0,6)

Step-by-step explanation:

We need to find the midpoint of the line segment having end points (-4,5) and (4,7). So, here we can use the Midpoint Formula :-

Points :- (-4,5) and (4,7).

Using Midpoint Formula ,

[tex]\rm\implies Midpoint =\bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)[/tex]

Substitute the respective values ,

[tex]\rm\implies Midpoint =\bigg(\dfrac{-4+4}{2},\dfrac{7+5}{2}\bigg)[/tex]

Simplify the numbers ,

[tex]\rm\implies Midpoint =\bigg(\dfrac{0}{2},\dfrac{12}{2}\bigg)[/tex]

This equals to ,

[tex]\rm\implies \boxed{\blue{\rm Midpoint =\bigg( 0,6\bigg)}}[/tex]

Hence the midpoint is (0,6) .

Answer:

[tex]a_n = 8(-5)^{n-1}[/tex]

The fifth term of the sequence is 5000.

Step-by-step explanation:

Geometric sequence:

In a geometric sequence, the quotient between consecutive terms is always the same, called common ratio. The nth term of a geometric sequence is:

[tex]a_n = a_1(r)^{n-1}[/tex]

a = 8; r = -5

Thus:

[tex]a_n = a_1(r)^{n-1}[/tex]

[tex]a_n = 8(-5)^{n-1}[/tex]

Fifth term:

This is [tex]a_5[/tex]. So

[tex]a_5 = 8(-5)^{5-1} = 5000[/tex]

The fifth term of the sequence is 5000.

Answer:

Scale factor = ½

Step-by-step explanation:

The original image is the preimage = ∆ACB

The new image is the image = ∆DFE

The scale of factor of dilation = image/preimage = DF/AC

DF = 6 cm (given)

AC = 12 cm (given)

Plug in the values into the equation to find the scale factor of dilation:

Scale factor = 6/12

Scale factor = ½

Answer:i love you

Step-by-step explanation:

Answer:

Step-by-step explanation:

1.4 m = 1.4 * 100 = 140.0  = 140 cm