Answer:
[tex]Median = 15.80[/tex]
[tex]Mode = 15.20\ \&\ 15.25[/tex]
[tex]IQR = 2.35[/tex]
Step-by-step explanation:
Given
[tex]15.60,\ 18.75,\ 14.60,\ 15.80,\ 14.35,[/tex]
[tex]13.90,\ 17.50,\ 17.55,\ 13.80,\ 14.20,[/tex]
[tex]19.05,\ 15.35,\ 15.20,\ 19.45,\ 15.95,[/tex]
[tex]16.50,\ 16.30,\ 15.25,\ 15.05,\ 19.10,[/tex]
[tex]15.20,\ 16.22,\ 17.75,\ 18.40,\ 15.25.[/tex]
Solving (a): The median and the mode
First, we sort the data.
[tex]13.80,\ 13.90,\ 14.20,\ 14.35,\ 14.60,\ 15.05,\ 15.20,\ 15.20,\ 15.25,\ 15.25,[/tex]
[tex]15.35,\ 15.60,\ 15.80,\ 15.95,\ 16.22,\ 16.30,\ 16.50,\ 17.50,\ 17.55,\ 17.75,[/tex]
[tex]18.40,\ 18.75,\ 19.05,\ 19.10,\ 19.45.[/tex]
The median position is:
[tex]Median = \frac{n + 1}{2}th[/tex]
[tex]Median = \frac{25 + 1}{2}[/tex]
[tex]Median = \frac{26}{2}[/tex]
[tex]Median = 13th[/tex]
The 13th item is: 15.80
Hence:
[tex]Median = 15.80[/tex]
The modes are:
[tex]Mode = 15.20\ \&\ 15.25[/tex] --- they both have frequency of 2 while others occur once
Solving (b): The interquartile range
This is calculated as:
[tex]IQR = Q_3 - Q_1[/tex]
Since the median is at the 13th position, Q1 is:
[tex]Q_1 = \frac{1 + 13}{2}th[/tex]
[tex]Q_1 = \frac{14}{2}th[/tex]
[tex]Q_1 = 7th[/tex]
The 7th item is: 15.20
[tex]Q_1 = 15.20[/tex]
Similarly, Q3 is:
[tex]Q_3 = \frac{13+n}{2}[/tex]
[tex]Q_3 = \frac{13+25}{2}[/tex]
[tex]Q_3 = \frac{38}{2}[/tex]
[tex]Q_3 = 19th[/tex]
The 7th item is: 17.55
So:
[tex]Q_3 = 17.55[/tex]
Hence,
[tex]IQR = 17.55 - 15.20[/tex]
[tex]IQR = 2.35[/tex]
Write down in terms of n, an expression for the nth term
of the following sequences:
a) 6 2 -2 -6 -10
b) -8 -15 -22 -29 -36
Answer:
[tex]{ \bf{(a).}} \\ { \tt{ {n}^{th} = a + (n - 1)d }} \\ { \tt{ {n}^{th} = 6 + (n - 1) \times - 4 }} \\ {n}^{th} = 10 - 4n \\ \\ { \bf{(b).}} \\ { \tt{ {n}^{th} = - 8 + (n- 1) \times - 7 }} \\ { \tt{ {n}^{th} = -1 - 7n}}[/tex]
Find the value of each shape so that they will add up to give you the specified sums in each row and each column.
How does this solving problem relate to system of equations?
Answer:
Step-by-step explanation:
The manufacturer claims the mean bursting pressure for a certain type and size of PVC irrigation pipe to be at least 350 psi. A sample of 10 such pipes were experimentally determined to have the following bursting pressures: 401 359 383 427 414 415 389 463 394 428 State the null and alternative hypotheses:
Answer:
H0 : μ ≥ 350
H1 : μ < 350
Step-by-step explanation:
It is claimed that the mean is atleast 350 psi ;
10 such pipes were experimentally sampled ;
Here, the null hypothesis is the claim ; this means that the alternative hypothesis will be the opposite of the claim.
The hypothesis
H0 : μ ≥ 350
H1 : μ < 350
What is the smallest number you should subtract from 456 to make it divisible by 9?
Will mark Brainlest formula of (x+y)cube
Answer:
(x+y) ³
= x³+3x²y+3xy²+y³
=x³+y³+3xy(x+y)
Brainliest please~
(x+y)3= x^3+3x^2y+3xy^2+y^3
A minority representation group accuses a major bank of racial discrimination in its recent hires for financial analysts. Exactly 16% of all applications were from minority members, and exactly 15% of the 2100 open positions were filled by members of the minority.
Required:
a. Find the mean of p, where p is the proportion of minority member applications in a random sample of 2100 that is drawn from all applications.
b. Find the standard deviation of p.
Answer:
a) The mean is of [tex]\mu = 0.16[/tex]
b) The standard deviation is of [tex]s = 0.008[/tex]
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Question a:
Exactly 16% of all applications were from minority members
This means [tex]p = 0.16[/tex], and thus, the mean is of [tex]\mu = p = 0.16[/tex]
b. Find the standard deviation of p.
2100 open positions, thus [tex]n = 2100[/tex].
[tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
[tex]s = \sqrt{\frac{0.16*0.84}{2100}}[/tex]
[tex]s = 0.008[/tex]
The standard deviation is of [tex]s = 0.008[/tex]
Factor completely, then place the factors in the proper location on the grid. a8 - 12a4 + 36
Answer:
[tex]{ \tt{ {a}^{8} - {12a}^{4} + 36}} \\ = { \tt{ {a}^{4} ( {a}^{2} - 12) + 36 }} \\ = ( {a}^{2} - 12)( {a}^{4} + 36) \\ [/tex]
25. Approximate the sample variance and standard deviation given the following frequency distribution: Class Frequency 0–9 13 10–19 7 20–29 10 30–39 9 40–49 11
Sample variance = 228.408
Standard deviation = 15.113
Step-by-step explanation:The well formatted frequency table has been attached to this response.
To calculate the sample variance and standard deviation of the given grouped data, follow these steps:
i. Find the midpoint (m) of the class interval.
This is done by adding the lower bounds and upper bounds of the class intervals and dividing the result by 2. i.e
For class 0 - 9, we have
m = (0 + 9) / 2 = 4.5
For class 10 - 19, we have
m = (10 + 19) / 2 = 14.5
For class 20 - 29, we have
m = (20 + 29) / 2 = 24.5
For class 30 - 39, we have
m = (30 + 39) / 2 = 34.5
For class 40 - 49, we have
m = (40 + 49) / 2 = 44.5
This is shown in the third column of the attached table.
ii. Find the product of each of the frequencies of the class intervals and their corresponding midpoints. i.e
For class 0 - 9, we have
frequency (f) = 13
midpoint (m) = 4.5
=> f x m = 13 x 4.5 = 58.5
For class 10 - 19, we have
frequency (f) = 7
midpoint (m) = 14.5
=> f x m = 7 x 14.5 = 101.5
For class 20 - 29, we have
frequency (f) = 10
midpoint (m) = 24.5
=> f x m = 10 x 24.5 = 245
For class 30 - 39, we have
frequency (f) = 9
midpoint (m) = 34.5
=> f x m = 9 x 34.5 = 310.5
For class 40 - 49, we have
frequency (f) = 11
midpoint (m) = 44.5
=> f x m = 11 x 44.5 = 489.5
This is shown in the fourth column of the attached table.
iii. Calculate the mean (x) of the distribution i.e
This is done by finding the sum of all the results in (ii) above and dividing the outcome by the sum of the frequencies. i.e
x = ∑(f x m) ÷ ∑f
Where;
∑(f x m) = 58.5 + 101.5 + 245 + 310.5 + 489.5 = 1205
∑f = 13 + 7 + 10 + 9 + 11 = 50
=> x = 1205 ÷ 50
=> x = 24.1
Therefore, the mean is 24.1
This is shown on the fifth column of the attached table.
iv. Calculate the deviation of the midpoints from the mean.
This is done by finding the difference between the midpoints and the mean. i.e m - x where x = mean = 24.1 and m = midpoint
For class 0 - 9, we have
midpoint (m) = 4.5
=> m - x = 4.5 - 24.1 = -19.6
For class 10 - 19, we have
midpoint (m) = 14.5
=> m - x = 14.5 - 24.1 = -9.6
For class 20 - 29, we have
midpoint (m) = 24.5
=> m - x = 24.5 - 24.1 = 0.4
For class 30 - 39, we have
midpoint (m) = 34.5
=> m - x = 34.5 - 24.1 = 10.4
For class 40 - 49, we have
midpoint (m) = 44.5
=> m - x = 44.5 - 24.1 = 20.4
This is shown on the sixth column of the attached table.
v. Find the square of each of the results in (iv) above.
This is done by finding (m-x)²
For class 0 - 9, we have
=> (m - x)² = (-19.6)² = 384.16
For class 10 - 19, we have
=> (m - x)² = (-9.6)² = 92.16
For class 20 - 29, we have
=> (m - x)² = (0.4)² = 0.16
For class 30 - 39, we have
=> (m - x)² = (10.4)² = 108.16
For class 40 - 49, we have
=> (m - x)² = (20.4)² = 416.16
This is shown on the seventh column of the attached table.
vi. Multiply each of the results in (v) above by their corresponding frequencies.
This is done by finding f(m-x)²
For class 0 - 9, we have
=> f(m - x)² = 13 x 384.16 = 4994.08
For class 10 - 19, we have
=> f(m - x)² = 7 x 92.16 = 645.12
For class 20 - 29, we have
=> f(m - x)² = 10 x 0.16 = 1.6
For class 30 - 39, we have
=> f(m - x)² = 9 x 108.16 = 973.44
For class 40 - 49, we have
=> f(m - x)² = 11 x 416.16 = 4577.76
This is shown on the eighth column of the attached table.
vi. Calculate the sample variance.
Variance σ², is calculated by using the following relation;
σ² = ∑f(m-x)² ÷ (∑f - 1)
This means the variance is found by finding the sum of the results in (vi) above and then dividing the result by one less than the sum of all the frequencies.
∑f(m-x)² = sum of the results in (vi)
∑f(m-x)² = 4994.08 + 645.12 + 1.6 + 973.44 + 4577.76 = 11192
∑f - 1 = 50 - 1 = 49 {Remember that ∑f was calculated in (iii) above}
∴ σ² = 11192 ÷ 49 = 228.408
Therefore, the variance is 228.408
vii. Calculate the standard deviation
Standard deviation σ, is calculated by using the following relation;
σ =√ [ ∑f(m-x)² ÷ (∑f - 1) ]
This is done by taking the square root of the variance calculated above.
σ = [tex]\sqrt{228.408}[/tex]
σ = 15.113
Therefore, the standard deviation is 15.113
Find the interest earned on $1,000 for 1 year at a 6% rate of interest when the interest is compounded quarterly.
Answer:
1060
Step-by-step explanation:
Find each missing length to the nearest tenth.
[tex]\huge\bold{Given:}[/tex]
Length of the perpendicular = 7
Length of the base = 10
[tex]\huge\bold{To\:find:}[/tex]
The length of the missing side (hypotenuse).
[tex]\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}[/tex]
[tex]\longrightarrow{\purple{x\:=\: 12.21}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
Let the length of the missing side be [tex]x[/tex].
Using Pythagoras theorem, we have
(Hypotenuse)² = (Perpendicular)² + (Base)²
[tex]\longrightarrow{\blue{}}[/tex] [tex]{x}^{2}[/tex] = (7)² + (10)²
[tex]\longrightarrow{\blue{}}[/tex] [tex]{x}^{2}[/tex] = 49 + 100
[tex]\longrightarrow{\blue{}}[/tex] [tex]{x}^{2}[/tex] = 149
[tex]\longrightarrow{\blue{}}[/tex] [tex]x[/tex] = [tex]\sqrt{149}[/tex]
[tex]\longrightarrow{\blue{}}[/tex] [tex]x[/tex] = 12.206
[tex]\longrightarrow{\blue{}}[/tex] [tex]x[/tex] = 12.21.
Therefore, the length of the missing side [tex]x[/tex] is [tex]12.21[/tex].
[tex]\huge\bold{To\:verify :}[/tex]
[tex]\longrightarrow{\green{}}[/tex] (12.21)² = (7)² + (10)²
[tex]\longrightarrow{\green{}}[/tex] 149 = 49 + 100
[tex]\longrightarrow{\green{}}[/tex] 149 = 149
[tex]\longrightarrow{\green{}}[/tex] L.H.S. = R. H. S.
Hence verified.
[tex]\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{ヅ}}}}}[/tex]
A professor has been teaching introductory statistics for many years and the final exam performance has been very consistent from class to class and the scores have been normally distributed. Overall, the whole data base (i.e. population) of final scores has a mean (μ) of 24 points (out of a maximum of 30 points) and a standard deviation (Ï) of 5 points. The professor would like to revise the course design to see if student performance on the final could be improved.
The new course design was implemented in the most recent academic year. There were 100 students and the average final exam score was 24.7. The professor would like to run a hypothesis test to see if this sample of students in the recent academic year performed significantly better than the past population. In other words, the hypothesis was a comparison between the population taking the course with the new design (represented by the sample of 100 students) with the population taking the course with the old design. The professor is predicting an increase of final score with the new design, so the hypotheses should be directional, and the test should be one-tailed. The significance level is set at α = .1.
Required:
a. Identify the dependent variable for this study.
b. State the null hypothesis and alternative hypothesis using both words and symbol notation
Answer:
a) Independent variable - Design of the course
Dependent variable - Final score of the students
b) H0 - Final score >24.7
Alternate hypothesis - Final score is less than or equal to 24.7
Step-by-step explanation:
a) Independent variable - Design of the course
Dependent variable - Final score of the students
b) Null Hypothesis : Performance of student taking course with the new design is better as compared to the population of student taking the course with the old design.
H0 - Final score >24.7
Alternate hypothesis - Final score is less than or equal to 24.7
6
Which expression is equivalent
Answer:
I thimk it is B
Step-by-step explanation:
Help me pls I don’t know how to do this
Answer:
[tex]radius=6.68cm[/tex]
Step-by-step explanation:
Formula to find radius:
[tex]r=\frac{C}{2\pi }[/tex]
[tex]r=42/2\pi[/tex]
[tex]r=42/2(3.14)[/tex]
[tex]r=6.68cm[/tex]
hope this helps......
A rancher has 360 yards of fencing with which to enclose two adjacent rectangular corrals, one for horses and one for cattle. A river forms one side of the corrals. If the width of each corral is x yards.
Required:
a. Express the total area of the two corrals as a function of x.
b. Find the domain of the function.
c. Determine the dimensions that yield the maximum area.
Answer:
a) A(x) = 360*x - 3*x²
b) The Domain of the function is ( 0 : ∞ )
c) x = 60 yards
y = 180 yards
c) A(max) = 10800 yd²
Step-by-step explanation:
Two rectangular corrals, with sides y and x ( y is the side parallel to the river) having a river as one side of the corrals means:
L length to be fenced
L = y + 3*x 360 = y + 3*x y = 360 - 3*x
The total areaof the two corrals as a function of x is
A(t) = x*y as y = 360 - 3*x by substitution we get
A(x) = x * ( 360 - 3*x)
A(x) = 360*x - 3*x²
Tacking derivatives on both sides of the equation we get:
A´(x) = 360 - 6*x A´(x) = 0 360 - 6*x = 0
x = 60 yards
and y = 360 - 3*x y = 360 - 180 y = 180 yards
A(max) = 60*180 = 10800 yd²
To find out if the value x = 60 is the x value for a maximum of A we go to the second derivative
A´´(x) = - 6 A´´(x) < 0 then there is a maximum value for function A in x = 60
The Domain of the function is ( 0 : ∞ )
What is this function’s input if its output is 11?
f(x) = 2x + 5
Answer:
the input x is 3
Step-by-step explanation:
2x+5=11
2x=6
x=3
Question 11 of 40
Factor this polynomial completely.
x2 - 6x + 9
A. (x+3)(x+3)
B. Does not factor
C. (x-3)(x - 3)
D. (x+3)(x-3)
Suppose 2500 dollars is invested at 4% for 5 years. Find the account balance if it is
compounded daily, monthly, quarterly?
answer step by step
Answer:
Kindly check explanation
Step-by-step explanation:
Using the compound interest formula :
A = P(1 + r/n)^nt
A = final amount ; r = rate ; n = number of compounding times per period ; t = period ; P = principal
P = 2500 ; r = 4% = 0.04 ; t = 5 years
Daily compounding, n = 365
Yearly compounding, n = 1
Quarterly compounding, n = 4
Daily compounding :
A = 2500(1 + 0.04/365)^(5*365)
A = 2500(1.0001095)^1825
A = $3053.4734
Yearly :
A = 2500(1 + 0.04/1)^(5*1)
A = 2500(1.04)^5
A = $3041.6323
Quarterly:
A = 2500(1 + 0.04/4)^(5*4)
A = 2500(1.01)^20
A = $3050.4751
f(x)=|x-6| written as piecewise function
simplification please
Answer:
5
Step-by-step explanation:
WHen we raise a power to a power, we multiply them, in this case 5 is the base so we can just ignore it for now and replace it with x.
(X^1/3)^3
Multiply 1/3 by 3 and we get 1
So:
X^1
Which does nothing, so we can simplify to just:\
X
Remember x is 5 so the answer is:
5
Solve for T: 10t-4x=3S Explanation plz
Which expression is equivalent to the given expression?
6ab/(a^0b^2)^4
Answer:
,here is the answer
Step-by-step explanation:
here is your answer
Find the 23rd term of the arithmetic sequence with the terms a1 27 and d = 16.
Answer:
379
Step-by-step explanation:
a23 = 27 + (23-1)(16)
= 27 + (22)(16)
= 27 + 352
= 379
Anyone plz show how to work it out step by step.
Answer:
168cm^3
Step-by-step explanation:
Q to P is going to be 3cm. it is identical to the length T to U.
R to T , W to Q, S to U is going to be identical to P to V. P to V has been identified as 12 cm.
in the middle of the shape, there are 4 identical triangles. the height time length will give us the area of that one shape:
e.g for shape P to V to W to Q and back to P is one rectangle. the length is 12 cm and the width is 3 cm.
12 x 3= 36
36cm^3 is one rectangles surface area, we have 4 identical triangles that means we need to times 36 by 4.
so 36x4=144.
now on the left and right side, we have two squares. on the right, we have T to U to V to W back to T this has the height of 3 width of 4 then we do 3 X 4 which is 12, we times it by 2 because we have two identical squares.
12 X 2=24
finally we add 24 and 144 = 168cm^3.
hope this helps :)
solve for x 6(x-3)=8(x-4)
Answer:
7=x
Step-by-step explanation:
6(x-3)=8(x-4)
Distribute
6x -18 = 8x-32
Subtract 6x from each side
6x-18 -6x = 8x-32-8x
-18 = 2x-32
Add 32 to each side
-18+32 = 2x-32+32
14 = 2x
Divide by 2
14/2 =2x/2
7=x
[tex]\sf\purple{x= 7}[/tex]
[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}[/tex]
[tex]➺\:6(x - 3) = 8(x - 4)[/tex]
[tex]➺ \: 6x - 18 = 8x - 32[/tex]
[tex]➺ \: 6x - 8x = - 32 + 18[/tex]
[tex]➺ \: - 2x = - 14[/tex]
[tex]➺ \: x = \frac{ - 14}{ - 2} [/tex]
[tex]➺ \: x = 7[/tex]
Therefore, the value of [tex]x[/tex] is 7.
[tex]\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}[/tex]
[tex]➺ \: 6(x - 3) = 8(x - 4)[/tex]
[tex]➺ \: 6(7 - 3) = 8(7 - 4)[/tex]
[tex]➺ \: 6 \times 4 = 8 \times 3[/tex]
[tex]➺ \: 24 = 24[/tex]
➺ L. H. S. = R. H. S.
Hence verified.
[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}[/tex]
Determine the value of x for which r is parallel to s if m angle 1 = 60-2x and m angle 2=70-4x
Answer: r = 5
Step-by-step explanation:
1. Rita is hiking along a trail that is 113.7 miles long. On the first day she hiked of 1 10 the distance of the trail. On the second day she hiked the same distance as the first day. How much of the trail does she have left to hike?
Answer:
She has 90.96 miles of the trail to hike.
Step-by-step explanation:
Length of the trail:
The length of the trail is of 113.7 miles.
On the first day she hiked of 1/10 the distance of the trail.
Thus:
[tex]\frac{1}{10(113.7) = 11.37[/tex]
On the first day she hiked 11.37 miles.
On the second day she hiked the same distance as the first day.
Also 11.37 miles on the second day, and thus, 2*11.37 = 22.74 miles on the first two days.
How much of the trail does she have left to hike?
113.7 - 22.74 = 90.96
She has 90.96 miles of the trail to hike.
Solve for x round to the nearest tenth if necessary
Answer:
x = 2.8
Step-by-step explanation:
sin = opp/hyp
hyp = opp/sin
x = 2.4/sin60
x = 2.771281292110204
rounded
x = 2.8
brainliest answer po yung tama
nk tym for nega NEED HELP PK TALAG
A
A
B
C
A
D
B
C
May choices po yan saamen
Step-by-step explanation:
Love you
The perimeter of a parallelogram must be no less than 40 feet. The length of the rectangle is 6 feet. What are the possible measurements of the width? Write an inequality to represent this problem. Use w to represent the width of the parallelogram. [Hint: The formula for finding the perimeter of a parallelogram is P = 2 l + 2 w . What is the smallest possible measurement of the width? Justify your answer by showing all your work.
Answer: [tex]14\ ft[/tex]
Step-by-step explanation:
Given
Length of rectangle is [tex]6\ ft[/tex]
Perimeter must be greater than 40 ft
Suppose l and w be the length and width of the rectangle
[tex]\Rightarrow \text{Perimeter P=}2(l+w)\\\Rightarrow P\geq 40\\\Rightarrow 2(l+w)\geq40\\\Rightarrow l+w\geq20\\\Rightarrow w\geq20-6\\\Rightarrow w\geq14\ ft[/tex]
So, the smallest width can be [tex]14\ ft[/tex]
Find the x- and y intercepts in the table write your answers as separate coordinates
Answer:
1: x intercept:2 y intercept:5
2: x intercept:-7 y intercept:1
3: x intercept:2 y intercept:-2
4: x intercept: 1 y intercept: -2
Step-by-step explanation:
The y intercept is whenever the x unit is at 0, and the x intercept is whenever the y intercept is at 0.
(-5/2;5) (1/7;1) (1;-2) (2;-2)
