The line shown in the graph passes through the points (2, 4) and (-1, 6). Which is the
equation of the line?

Answers

Answer 1
y2 -y 1 / x2 - x1
6 - 4 / -1 - 2
2 / - 3
m = -2/3 x (slope)

Related Questions

8. GradPoint question
Determine whether the given lengths can be sides of a right triangle. Which of the following are true statements?


A. The lengths 14, 24 and 26 cannot be sides of a right triangle. The lengths 30, 72, and 78 cannot be sides of a right triangle.

B. The lengths 14, 24 and 26 can be sides of a right triangle. The lengths 30, 72, and 78 can be sides of a right triangle.

C. The lengths 14, 24 and 26 can be sides of a right triangle. The lengths 30, 72, and 78 cannot be sides of a right triangle.

D. The lengths 14, 24 and 26 cannot be sides of a right triangle. The lengths 30, 72, and 78 can be sides of a right triangle.

Answers

Answer:

I'm sorry but I have no clue. Actually I think it's C.

Step-by-step explanation:

solve the following equation when x = 8
15x - 2 =

Answers

Answer:

118

Step-by-step explanation:

15(8)-2

120-2

118

Brainly plss?

Answer:

118

Step-by-step explanation:

you do 15 x 8 then subtract 2 from the product

[tex] \underline{ \underline{ \text{Question}}} : [/tex]
In the adjoining figure , ABC is an isosceles triangle. BO and CO are the bisectors of [tex] \angle[/tex] ABC and [tex] \angle[/tex] ACB respectively. Prove that BOC is an isosceles triangle.

~Thanks in advance !

Answers

GiveN :-In the given figure , ABC is an isosceles triangle.BO and CO are the bisectors of [tex] \angle[/tex] ABC and [tex] \angle[/tex] ACB respectively.

To ProvE :-

∆ BOC is isosceles.

ProoF :-

Here it's given that ∆ABC is a isosceles triangle. We know that in a isosceles triangle opposite angles are equal. And the angles opposite to equal sides are also equal.

Hence here ,

AB = AC ∠ ABC = ∠ACB .

Figure :-

[tex] \setlength{\unitlength}{1 cm}\begin{picture}(12,12)\put(0,0){\line(1,0){4}}\put(4,0){\line(-1,2){2}}\put(0,0.001){\line(1,2){2}}\put(0,0.01){\line(1,1){2}}\put(3.99,0){\line(-1,1){2}}\put(0,-0.3){$\bf B $}\put(4,-0.3){$\bf C$}\put(2,4.2){$\bf A$}

\put(1.8,2.2){$\bf o$}\end{picture}[/tex]

If LaTeX doesn't work on app kindly see the attachment .

Here we will use a theorem which is ,

[tex]\large\underline{\underline{\textsf{\textbf{\red{\blue{$\leadsto$} Theorem :- }}}}}[/tex]

Sides opposite to equal angles are equal.

Hence here,

[tex]\tt:\implies \angle ABC =\angle ACB \\\\\tt:\implies \dfrac{1}{2}\times \angle ABC = \dfrac{1}{2}\times \angle ACB \\\\\tt:\implies \boxed{\bf \blue{\angle OBC = \angle OCB} }[/tex]

Now in ∆OBC , we can see that ∠OBC = ∠OCB. (just proved ) . Hence we can say that sides OB and OC are equal. Since the sides opposite to equal angles are equal. Therefore in ∆OBC , two sides are equal.

Therefore OBC is an isosceles triangle.

Hence Proved !

Answer:

See Below.

Step-by-step explanation:

We are given the isosceles triangle ΔABC. By the definition of isosceles triangles, this means that ∠ABC = ∠ACB.

Segments BO and CO bisects ∠ABC and ∠ACB.

And we want to prove that ΔBOC is an isosceles triangle.

Since BO and CO are the angle bisectors of ∠ABC and ∠ACB, respectively, it means that ∠ABO = ∠CBO and ∠ACO = ∠BCO.

And since ∠ABC = ∠ACB, this implies that:

∠ABO = ∠CBO =∠ACO = ∠BCO.

This is shown in the figure as each angle having only one tick mark, meaning that they are congruent.

So, we know that:

[tex]\angle ABC=\angle ACB[/tex]

∠ABC is the sum of the angles ∠ABO and ∠CBO. Likewise, ∠ACB is the sum of the angles ∠ACO and ∠BCO. Hence:

[tex]\angle ABO+\angle CBO =\angle ACO+\angle BCO[/tex]

Since ∠ABO =∠ACO, by substitution:

[tex]\angle ABO+\angle CBO =\angle ABO+\angle BCO[/tex]

Subtracting ∠ABO from both sides produces:

[tex]\angle CBO=\angle BCO[/tex]

So, we've proven that the two angles are congruent, thereby proving that ΔBOC is indeed an isosceles triangle.

Find the volume of a cylinder with a radius of 3 inches and a height of 2

Answers

Answer:

56.55m³

Step-by-step explanation:

use a calculator, not brainly

The price of an item has been reduced by 95%. The original price was $33.

Answers

Answer:

25%

Step-by-step explanation:

See a solution process below: Explanation: We can use this formula to solve this problem: s=p−(d×p). Where: s is the sales price: what we are

i think it would be 14 i’m not sure.

Determine the slope of the line perpendicular to that of the function graphed below.


I AM IN DYING NEED OF HELP

Answers

It’s just the opposite of the original slope. If the original is 4/5, then the opposite would be -5/4

Answer:

y=4/5x -5

Step-by-step explanation:

the slope is x and x is on the point -5. and d

to find the y-intercept you do rise/run

Complete the steps to solve the equation 3x + 11 = 29.

Answers

Answer:

6

Step-by-step explanation:

3x+11 = 29

3x =  29 - 11 = 18

x = 18/3 = 6

A sequence is recursively defined as a(n)=2a(n-2) for values of n>2. Find the seventh term of the sequence if a(1)=0 and a(2)=1

Answers

Answer:

a(7) = 21

Step-by-step explanation:

Using the recursive formula and a(1) = 0, a(2) = 1 , then

a(3) = a(2) + 2a(1) = 1 + 2(0) = 1 + 0 = 1

a(4) = a(3) + 2a(2) = 1 + 2(1) = 1 + 2 = 3

a(5) = a(4) + 2a(3) = 3 + 2(1) = 3 + 2 = 5

a(6) = a(5) + 2a(4) = 5 + 2(3) = 5 + 6 = 11

a(7) = a(6) + 2a(5) = 11 + 2(5) = 11 + 10 = 21

28,46,25,76,18,25,47,83,44 what's the median,first quartile,third quartile, and interquartile range

Answers

Answer:

median: 44

first quartile: 25

third quartile: 61.5

interquartile range: 36.5

Step-by-step explanation:

For the given data set median is 44, first quartile is 25, third quartile is 61.5 and interquartile range is 36.5.

What is the interquartile range?

The Interquartile Range (IQR) formula is a measure of the middle 50% of a data set. The smallest of all the measures of dispersion in statistics is called the Interquartile Range. The difference between the upper and lower quartile is known as the interquartile range.

Formula to find the interquartile range is Interquartile range = Upper Quartile - Lower Quartile =Q2=Q3-Q1

The given date set is 28,46,25,76,18,25,47,83,44.

The data in order 18,25,25,28,44,46,47,76,83.

Here,

Median =44

First quartile=Q₁=25

Third quartile=Q₃= (47+76)/2

= 61.5

Now, interquartile range (IQR)

= Q₃-Q₁

= 61.5-25

= 36.5

Therefore, for the given data set median is 44, first quartile is 25, third quartile is 61.5 and interquartile range is 36.5.

Learn more about the interquartile range here:

https://brainly.com/question/4135956.

#SPJ5

Write the exponent for the expression.

15 × 15
The exponent for the expression is ___

Answers

Answer:

2. i think. correct me if im wrong.

Answer: The answer is 2

Step-by-step explanation:

pls help!!
what would the answer be when rounded to one significant figure.​

Answers

2.3^2+4.1^2= 22.1
That should be right my bad if it’s not

Guys I need help ASAP I am giving 55 points

Answers

Answer:

The answer is 80°

Step-by-step explanation:

pls give brainliest!

all angles = 360°

100+100+80=280°

360°-280°=80°

Tank B, which initially contained 80 liters of water, is being drained at a rate of 2.5 liters per minute. How many liters of water remain in the tank after 30 seconds?​

Answers

Answer:

78.75 ?

Step-by-step explanation:

calculator..

The volume of water remain in the tank after 30 seconds is 78.75 liters.

The given parameters;

initial volume of water in Tank B, V₀ = 80 litersrate at which water is being drained, R = 2.5 liters per minute.time of water drain, t = 30 seconds

The amount of water drained after 30 seconds is calculated as follows;

[tex]V_1 =2.5 \ \frac{liters}{\min} \times \frac{1 \min}{60 \ s} \times 30 \ s\\\\V_1 = 1.25 \ liters[/tex]

The volume of water remain in the tank after 30 seconds is calculated as follows;

V₂ = V₀ - V₁

V₂ = 80 liters - 1.25 liters

V₂ = 78.75 liters

Thus, the volume of water remain in the tank after 30 seconds is 78.75 liters.

Learn more here: https://brainly.com/question/13559135

HELP ASAP I’ll GIVE BRAINLIEST :))))
Which of the following does -

Answers

Answer:

Step-by-step explanation:

A

The only that makes sense to me is d
Good luck

Work out the following and give your answer in it's simplest form:

[tex]\frac{9}{10}[/tex] ÷ [tex]\frac{3}{5}[/tex]
Plz help!!

Answers

Answer:

[tex]\frac{9}{10}[/tex] ÷ [tex]\frac{3}{5}[/tex]

=3/5

=1.5

here's your answer!! hopefully it's readable! have a great day :)

Graph the line.
Y+4=1/5(x-1)

Answers

Answer:

graph the point (0, -5) and from that point go up 1 unit and to the right 5 units (5, -4) and plot that point; connect the two points

Step-by-step explanation:

A 29-meter ladder is sliding down a vertical wall so the distance between the top of the ladder and the ground is decreasing at 7 meters per minute. At a certain instant, the bottom of the ladder is 21 meters from the wall.

Answers

Complete question

A 29-meter ladder is sliding down a vertical wall so the distance between the top of the ladder and the ground is decreasing at 7 meters per minute. At a certain instant, the bottom of the ladder is 21 meters from the wall.

What is the rate of change of the distance between the bottom of the ladder and the wall at that instant(in meters per minute)

Answer:

[tex]\frac{dx}{dt}=11.94m/min[/tex]

Step-by-step explanation:

From the question we are told that

Slant height [tex]z=29m[/tex]

Change in Vertical height  [tex]\triangle y=7m/s[/tex]

Horizontal length [tex]x=21[/tex]

Generally in finding the distance form the  top to the bottom of the wall it is mathematically given by

 [tex]x^2+y^2=z^2[/tex]

 [tex]21^2+y^2=29^2[/tex]

 [tex]y^2=29^2+21^2[/tex]

 [tex]y=35.81[/tex]

Generally solving for the differential equation is mathematically represented as

 [tex]x^2+y^2=29^2[/tex]

 [tex]2x*\frac{dx}{dt} +2y*\frac{dy}{dt} =0[/tex]

 [tex]x*\frac{dx}{dt} +y*\frac{dy}{dt} =0[/tex]

 [tex](21)*\frac{dx}{dt} +(35.81)*(-7) =0[/tex]

 [tex](21)*\frac{dx}{dt} -250.64 =0[/tex]

 [tex]\frac{dx}{dt}=\frac{250.64}{21}[/tex]

 [tex]\frac{dx}{dt}=11.94m/min[/tex]

The rate of change of the distance between the bottom of the ladder and the wall at that instant is 6.67 meter per minute.

Let us consider that distance between the top of the ladder and the ground is x meter and distance between the bottom of the ladder and the wall is y meter.

So, A right angle triangle is formed.

Since, the bottom of the ladder is 21 meters from the wall.

So,    [tex]y=21[/tex]

Applying Pythagoras theorem,

                         [tex]x^{2} +y^{2}=(29)^{2} \\\\x^{2} +(21)^{2}=(29)^{2} \\\\\\x^{2} =841-441=400\\\\x=\sqrt{400} =20[/tex]

Given that,   the distance between the top of the ladder and the ground is decreasing at 7 meters per minute.

                           [tex]\frac{dx}{dt}=-7meter/min[/tex]

Differentiate below equation with respect to time.

                     [tex]x^{2} +y^{2}=(29)^{2} \\\\2x\frac{dx}{dt}+2y\frac{dy}{dt}=0 \\\\2(20)(-7)+2(21)\frac{dy}{dt}=0\\\\\frac{dy}{dt}=\frac{280}{42}=6.67meter/min.[/tex]

Thus, the rate of change of the distance between the bottom of the ladder and the wall at that instant is 6.67 meter per minute.

Learn more about Differentiation here:

https://brainly.com/question/14023950


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Expand and simplify 4(2x - 1) + 3(2x + 5)
F
AB
Type here to search

Answers

Step-by-step explanation:

4(2x-1)+3(2x+5)

8x-4+6x+15

8x+6x-4+15

14x+11

Answer:

14x +11

Step-by-step explanation:

4(2x-1)+3(2x+5)=8x-4+6x+15

=14x+11

Is this congruent, or not congruent? And is it
SSS
SAS
SSA
AAS
ASA
HL

Answers

Answer:

Step-by-step explanation:

The two triangles are congruent. The diagonal is equal to itself in both triangles.

Triangle XYW = Triangle XYZ  by SSS

Water boils at 100LaTeX: ^\circ∘ Celsius or 212LaTeX: ^\circ∘ Fahrenheit. Water freezes at 0LaTeX: ^\circ∘ Celsius or 32LaTeX: ^\circ∘ Fahrenheit. If the weather forecaster says it will be 30LaTeX: ^\circ∘ Celsius today, write and solve a linear equation to find what Fahrenheit temperature this is.

Answers

Answer:

[tex]F = 1.8C +32[/tex]

[tex]F = 86^{\circ}F[/tex]

Step-by-step explanation:

Represent Celsius with C and Fahrenheit with F.

So, we have:

[tex](C_1,F_1) = (100,212)[/tex]

[tex](C_2,F_2) = (0,32)[/tex]

Solving (a): Represent as a linear equation

First, we calculate the slope:

[tex]m = \frac{F_2 - F_1}{C_2 - C_1}[/tex]

This gives:

[tex]m = \frac{32 - 212}{0 - 100}[/tex]

[tex]m = \frac{-180}{- 100}[/tex]

[tex]m = 1.8[/tex]

The linear equation is then calculated using:

[tex]F - F_1 = m(C -C_1)[/tex]

Where

[tex](C_1,F_1) = (100,212)[/tex]

[tex]m = 1.8[/tex]

[tex]F - 212 = 1.8(C -100)[/tex]

[tex]F - 212 = 1.8C -180[/tex]

Make F the subject

[tex]F = 1.8C -180+212[/tex]

[tex]F = 1.8C +32[/tex]

Solving (b): The value of F when C = 30

Substitute 30 for C in [tex]F = 1.8C +32[/tex]

[tex]F = 1.8 * 30 + 32[/tex]

[tex]F = 54 + 32[/tex]

[tex]F = 86[/tex]

Answer:

person above me is wrong

need help with this thanks

Answers

Answer:

15.51

Step-by-step explanation:

Answer:

15.51

Step-by-step explanation:

The calculator is $49.50.

The radio is $114.99.

First, we add them together.

49.50+114.99 = 164.49

that is the total cost of both the radio and calculator.

Next, we subrtact  180.00-164.49= 15.51.

Please help me with this quadratic equation question! I always give out 5 stars, thanks and brainliest to people that help me with a good explanation.

Find the values of p and q given that 12x² - 13x - 7175 = (x-p) (qx + 287)

Answers

Answer:

[tex]p=25,\\q=12[/tex]

Step-by-step explanation:

In [tex](ax+b)(cx+d)=acx^2+bcx+dax+bd[/tex], notice the third term of the quadratic in standard form is formed entirely by [tex]b\cdot d[/tex].

Therefore, in [tex]12x^2 - 13x - 7175 = (x-p) (qx + 287)[/tex]:

[tex]-p\cdot287=-7175,\\-p=\frac{-7175}{287},\\p=\fbox{$25$}[/tex].

Now that we found [tex]p[/tex], we must find [tex]q[/tex]. The first term of the quadratic in standard form is formed entirely by [tex]ax\cdot cx[/tex]. Therefore:

[tex]1\cdot q=12, \\q=\fbox{$12$}[/tex].

Help ill mark u brainliest

Answers

Answer:

We conclude that:

m∠XWY = 41°

Step-by-step explanation:

Given

m∠VWX = 139°

m∠YWZ = 23°

To determine

m∠XWY = ?

We know the measure of the angle of a straight is 180°.

As m∠VWX and m∠XWY lie on a straight line.

Thus, the sum of m∠VWX and m∠XWY must be 180°

so we get the equation

m∠VWX + m∠XWY =  180°

Given that m∠VWX = 139°

so substituting m∠VWX = 139° in the equation m∠VWX + m∠XWY =  180°

139° + m∠XWY = 180°

m∠XWY = 180° - 139°

m∠XWY = 41°

Therefore, we conclude that:

m∠XWY = 41°

A store advertises 15% off an item that regularly sells for $300

what is the price of the item?

Answers

The item would sell for $255 if it had a 15 percent discount

For this problem, we're finding the percent of 300. To do that we:

1. Multiply 300 by 15.

300 x 15 = 4500

2. Divide 4500 by 100. (% = 100)

4500 / 100 = 45

Therefore, the unit price is 45. But we're not done. We need to subtract 45 by 300.

300 - 45 = 255

Now, our answer is 255 and the unit price is 45.

Let me know of any questions!

Suppose you invest $2000 at a rate of 3.25% continuously, determine the worth of the investment after 10 years.

Answers

Answer:

$2650

Step-by-step explanation:

= 2000 × 0.0325 × 10 = 650

= $ 650.00

The sum of two numbers is 30 and their difference is 12, what are the two numbers

Answers

Answer:

Sum: 21 + 9 = 30

Difference: 21 - 9 = 12

Step-by-step explanation:

Let the number is a and b

The sum of two numbers =30

so,a+b=30 ............(1)

The difference of two number =12

so,a-b=12 .................(2)

If we add two equation (1) and (2)

we get,

a+b+a-b=30+12

2a=42

[tex]\tt{ a=\dfrac{42}{2} }[/tex]

[tex]\tt{ a=21 }[/tex]

so,one number is a=21

if we put the value a in (2) equation

we get,

a-b=12

21-b=12

b=21-12

b=9

so,the another number is=b=9

[tex]\tt{ the~two~ number~ are~ 21 ~and~ 9 }[/tex]

A relation is given below.
{(0, 0), (2, 0.5), (4, 1), (3, 1,5), (4, 2), (5, 1.5), (6, 8)}
Which ordered pair can be removed to make this relation a function?
Why would removing this ordered pair make the relation a function?

Answers

(4,1) can be taken out.

The input and output values cannot be the same.

Hope this helps!

Jorge Claims that the distance between his house and the library is 13 miles. His city is placed on a coordinate plane. Jorge's House is at the coordinates (5, 1), the mall is at coordinates (2, 11) and hte Library is at cordinates (10, 13). What equation verifies his claim?

Answers

Answer:

House coordinate = (5, 1)

Library coordinate = (10, 13)

Step-by-step explanation:

Given :

House coordinate = (5, 1)

Library coordinate = (10, 13)

Distance between house snd library :

Distance = sqrt[(x2 - x1)² + (y2 - y1)]

x1 = 5, x2 = 10, y1 = 1, y2 = 13

Distance = sqrt[(10 - 5)² + (13 - 1)²]

Distance = sqrt[(5² + 12²)]

Distance = sqrt(25 +144)

Distance = sqrt(169)

Distance = 13

pls answer asap pls pls​

Answers

your answer is b and c :)

Answer:

A

Hindi po ako sigurado po ahhhh

2x² + 3 × (-x²) + 6x + 2

Answers

Answer:

1x²+5 x 6x

Step-by-step explanation:

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