The list of ingredients for chocolate brownies given at right will make 16 brownies. Use the list to decide how much of each ingredient is needed to make 6 brownies.

Answer:

n(B) = 1350

Step-by-step explanation:

Using Venn sets, we have that:

[tex]n(A \cup B) = n(A) + n(B) - n(A \cap B)[/tex]

Three values are given in the exercise.

The other is n(B), which we have to find. So

[tex]n(A \cup B) = n(A) + n(B) - n(A \cap B)[/tex]

[tex]2290 = 1300 + n(B) - 360[/tex]

[tex]940 + n(B) = 2290[/tex]

[tex]n(B) = 2290 - 940 = 1350[/tex]

So

n(B) = 1350

Answer:

Step-by-step explanation:

every thing looks good,  except the question says  "round"   and soooooo,  if you are rounding to the 2nd decimal place,  then the next two decimal places are  54,      or  50.2654   so, to round that, round up , so your final answer would look like   50.27   :)  see?

9514 1404 393

Answer:

  50.24 inches  (or 50.2 inches)

Step-by-step explanation:

The formula for circumference in terms of radius is ...

  C = 2πr

Using the given values for radius and for pi, the circumference is ...

  C = 2(3.14)(8 in) = 50.24 in

__

Additional comment

If you use a more accurate value of pi, the rounded value is 50.27 in. That is not the value requested by this problem. It helps to follow directions.

If you like, you can round to 50.2, since only one decimal place is required in the result.

Answer:

D

Step-by-step explanation:

I have attached the explanation above. hopefully this will help

Answer: [tex]7\sqrt{42}[/tex]

Step-by-step explanation:

42 students divided equally into 7 groups means 42 divided by 7, and [tex]7\sqrt{42}[/tex] is the only choice that shows that.

7√42. is the expressions would represent a class of 42 students divided equally into 7 groups

A division is a process of splitting a specific amount into equal parts.

Given,

A class of forty two Forty two students divided equally into 7 groups.

Forty two students divided equally into seven groups means forty two divided by seven, and

this can be done by using 7√42.

42 students divided equally into 7 groups means forty two divided by seven

Hence  7√42. is the expressions would represent a class of 42 students divided equally into 7 groups

To learn more on Division click:

https://brainly.com/question/21416852

#SPJ2

Answer:

2 hours

Step-by-step explanation:

Since Tory and Emilio's motorboats travel at the same speed, they are traveling at the speed of 30 km/h. Therefore, it should take Tory two hours to travel 60 km.

Tory took 2 hours to navigate the 60 kilometers.

Velocity is the pace and direction of an item's movement, whereas speed is the time rate at which an object is travelling along a route.

Given:

Tory pilots her boat 60 km before docking.

Emilio continues for another 4 hours traveling, a total of 120 km before docking.

The speed of Emilio's boat = 120 / 4 = 30 kilometers per hour.

Tory and Emilio's motorboats travel at the same speed.

Tory's boat speed,

= 60/30 = 2 hours.

Therefore, Tory takes 2 hours.

To learn more about the speed;

https://brainly.com/question/7359669

#SPJ2

Answer:

10. CD + DE = CE

11. BC + CE = BE

Step-by-step explanation:

10. CD and DE lie on a straight line, therefore, CD + DE = CE based on the segment addition postulate.

11. BC and CE lie on a straight line, therefore, BC + CE = BE based on the segment addition postulate.

Answer:

[tex]T_n = \frac{1}{4^{n-1}}[/tex]

Step-by-step explanation:

Given

[tex]({)1, 1/4, 1/16, 1/64, 1/256, ... (})[/tex]

Required

The general term

The given sequence is geometric.

So first, we calculate the common ratio (r)

[tex]r = T_2/T_1[/tex]

So, we have:

[tex]r = 1/4 \div 1[/tex]

[tex]r = 1/4[/tex]

The function is then calculated using:

[tex]T_n =T_1 * r^{n-1}[/tex]

This gives

[tex]T_n =1 * 1/4^{n-1}[/tex]

[tex]T_n = \frac{1}{4^{n-1}}[/tex]

Answer:

2x - 1

Step-by-step explanation:

that is the procedure above

Step-by-step explanation:

The number of cases of a new disease may be modeled by the quadratic regression equation y=-2x^2+44x+8 , what is the best prediction for the number of cases after 20 years ( the carrot symbol (^) means the following number is the exponent)

Complete Question

Complete is Attached  Below

Answer:

Option D

Step-by-step explanation:

From the question we are told that:

Sample size [tex]n=26[/tex]

Student scoring [tex]65-100 n'=12[/tex]

Generally the equation for probability of a student having score between 65 and 100 is mathematically given by

 [tex]P(65-100)=\frac{12}{26}[/tex]

 [tex]P(65-100)=12/26[/tex]

 [tex]P(65-100)=0.462[/tex]

Option D

=================================================

Explanation:

We undo the "minus 6" by adding 6 to both sides.

Also, we undo the "+s" by subtracting s from both sides

-----------

So we have these steps

P = r+s-6

P+6 = r+s-6+6 .... adding 6 to both sides

P+6 = r+s

r+s = P+6

r+s-s = P+6-s ..... subtracting s from both sides

r = P + 6 - s

Answer:

P+6-s=r

Step-by-step explanation:

Hi there!

We are given the equation P=r+s-6 and we need to solve for r

To do that, we need to isolate r onto one side, and have everything else on the other.

Here is the equation:

P=r+s-6

start by adding 6 to both sides to clear it from the right side

P+6=r+s

now subtract s from both sides to clear it from the right side

P+6-s=r

now everything that isn't r is on the left side, and r is by itself on the right side. P+6-s=r is the answer.

Hope this helps!

Answer:

The answer is "sometimes".

Step-by-step explanation:

A one-way ANOVA was merely performed on one collected data and the null hypothesis was rejected after an ANOVA F test. Assume we could randomize ANOVA block design with the same information. This null hypothesis for full equality is sometimes rejected for the randomized complete block design ANOVA. Therefore we understand the use of randomized ANOVA block if the null hypothesis is denied of a one-way ANOVA but the rejection of a null RBD ANOVA hypothesis isn't conditional mostly on denial of the yet another ANOVA null.

Hello,

P(A)=0.4

P(B)=0.3

P(AUB)+P(A∩B)=P(A)+P(B)

P(AUB)=0.4+0.3-0.1=0.6

Answer C

The correct answer is option (C).

P(A ∪ B) = 0.6

If A, B are two different events then P(A U B) = P(A) + P(B) - P(A ∩ B)

We have been given, P(A) = 0.4, P(B) = 0.3

From given Venn diagram,

P(A ∩ B) = 0.10

Now, P(A U B) = P(A) + P(B) - P(A ∩ B)

⇒ P(A U B) = 0.4 + 0.3 - 0.10

⇒ P(A ∪ B) = 0.6

Therefore, the correct answer is option (C) .6

Learn more about here:

https://brainly.com/question/1605100

#SPJ2

Answer:

a) r ⋀~p

b)(r⋀p)⟶q

c) ~r ⟶ ~q

d) (~p ⋀r) ⟶q

Step-by-step explanation:

To solve this question we will make use of logic symbols in truth table.

We are told that;

p means "The user enters

a valid password,”

q means “Access is granted,”

r means “The user has paid the

subscription fee”

A) The user has paid the subscription fee, but does not enter a valid

password.”

Fist part of the statement is correct and so it will be "r". Second part of the statement is a negation and will be denoted by ~p. Since both statements are joined together in conjunction, we will use the conjuction symbol in between them which is "⋀" Thus, we have; r ⋀~p

B) Still using logic symbols, we have;

(r⋀p)⟶q

⟶ means q is true when r and p are true.

C) correct symbol is ~r ⟶ ~q

Since both statements are negation of the question. And also, if ~r is true then ~q is also true.

D) Similar to answer A to C above, applying similar conditions, we have (~p ⋀r) ⟶q

Answer:

Area of the given regular pentagon is 61.5 cm².

Step-by-step explanation:

Area of a regular polygon is given by,

Area = [tex]\frac{1}{2}aP[/tex]

Here, a = Apothem of the polygon

P = Perimeter of the polygon

Apothem of the regular pentagon given as 4.1 cm.

Side of the pentagon = 6 cm

Perimeter of the pentagon = 5(6)

                                             = 30 cm

Substituting these values in the formula,

Area = [tex]\frac{1}{2}(4.1)(30)[/tex]

        = 61.5 cm²

Therefore, area of the given regular pentagon is 61.5 cm².

Answer:

[tex]E(x) = 1.5\\[/tex]

Step-by-step explanation:

Given

[tex]n = 9[/tex] -- number of rolls

Required

The mean of 2's

The distribution follows binomial distribution where:

[tex]X \to Binomial(n,p)[/tex]

In this case:

[tex]p= \frac{1}{6}[/tex] ---- the theoretical probability of rolling 2

So, the mean of 2's is calculated using:

[tex]E(x) = np[/tex]

[tex]E(x) = 9 * \frac{1}{6}[/tex]

[tex]E(x) = \frac{9}{6}[/tex]

Simplify

[tex]E(x) = \frac{3}{2}[/tex] or

[tex]E(x) = 1.5\\[/tex]

Answer:

f(h(x)) = 2•(x²-1)² -4•(x²-1)

Answer: 24 ft I think

Step-by-step explanation:

There are more compact cars (4*10 = 40) compared to trucks (2*10 = 20); however, the pictogram might make it appear that there are more trucks because the individual truck icon is larger compared to an individual compact car icon.

To anyone giving this image a quick glance, they may erroneously conclude that there are more trucks since their eye would notice the trucks first. Also, the person might think there are more trucks because bigger sizes tend to correspond to more proportion.

In real life, a truck is larger than a compact car, but the icons need to be the same size to have the figure not be misleading.

A very similar issue happens with the mid-size cars vs the compact cars as well. The three mid-size car icons span the same total width as the compact cars do, indicating that a reader might mistakenly conclude that there are the same number of mid-size cars compared to compact ones (when that's not true either).

Step-by-step explanation:

we cannot see the diagram, so we don't know how many layers of bricks are used. and therefore it is impossible to tell the height of the wall.

Answer:

[tex]\sigma = 121.53[/tex]

Step-by-step explanation:

Required

The population standard deviation

First, calculate the population mean

[tex]\mu = \frac{\sum x}{n}[/tex]

This gives:

[tex]\mu = \frac{148+ 329+ 491 +167+ 228+285+ 441}{7}[/tex]

[tex]\mu = \frac{2089}{7}[/tex]

[tex]\mu = 298.43[/tex]

The population standard deviation is:

[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}[/tex]

So, we have:

[tex]\sigma = \sqrt{\frac{(148 - 298.43)^2 + ..........+ (441- 298.43)^2}{7}}[/tex]

[tex]\sigma = \sqrt{\frac{103387.7143}{7}}[/tex]

[tex]\sigma = \sqrt{14769.6734714}[/tex]

[tex]\sigma = 121.53[/tex]

Answer:

[tex]y = -\frac{3}{4}x + 5[/tex]

Step-by-step explanation:

Given equation  y = -3/4x  - 5

Step 1 : Find slope.

           Since the lines are parallel to each other, the slopes are same.

          [tex]therefore, m = \frac{-3}{4}[/tex]

Step 2 : Find the equation of the line.

           [tex]( y - y_1) = m ( x - x_ 1) \ \ \ where \ x_ 1 = 4 \ and \ y_ 1 = 2[/tex]

            [tex]( y - 2 ) = -\frac{3}{4}( x - 4)\\\\y - 2 = -\frac{3}{4}x + 3\\\\y = -\frac{3}{4}x + 3 + 2\\\\y = -\frac{3}{4}x + 5[/tex]

Answer:

not true....

assume $100 start.

in year 1 you are at $108 (up 8%)

in year 2  $108(.98) ... that is 2% down = 105.84...

thus your profit is up only 5.84% over the two years

Step-by-step explanation:

Answer:

the magnitude of a real number without regard to its sign.

Step-by-step explanation:

For example, |-3| would just be a 3 in general, no negative sign in the front.

hope this answers your confusion.

Answer:

[tex]\begin{array}{ccc}{Class} & {Frequency} & {Relative\ Frequency} &{30-39} & {1} & {0.025} & {40-49} & {1} & {0.025} & {50 - 59} & {2} & {0.050} & {60 - 69} & {5} & {0.125} & {70 - 79} & {13} & {0.325} & {80 - 89} & {10} & {0.250} & {90 - 99} & {8} & {0.200} &{Total} & {40} & {1}\ \end{array}[/tex]

[tex]P(x < 70) = 0.225[/tex]

Step-by-step explanation:

Given

[tex]Lower = 30[/tex]

[tex]Width = 10[/tex]

Solving (a): The relative frequency table

First, we construct the frequency table using the given parameters.

[tex]\begin{array}{cc}{Class} & {Frequency} &{30-39} & {1} & {40-49} & {1} & {50 - 59} & {2} & {60 - 69} & {5} & {70 - 79} & {13} & {80 - 89} & {10} & {90 - 99} & {8} & {Total} & {40}\ \end{array}[/tex]

The relative frequency (RF) is calculated as:

[tex]RF = \frac{Frequency}{Total}[/tex]

Using the above formula to calculate the relative frequency, the relative frequency table is:

[tex]\begin{array}{ccc}{Class} & {Frequency} & {Relative\ Frequency} &{30-39} & {1} & {0.025} & {40-49} & {1} & {0.025} & {50 - 59} & {2} & {0.050} & {60 - 69} & {5} & {0.125} & {70 - 79} & {13} & {0.325} & {80 - 89} & {10} & {0.250} & {90 - 99} & {8} & {0.200} &{Total} & {40} & {1}\ \end{array}[/tex]

Solving (b): [tex]P(x < 70)[/tex]

To do this, we add up the relative frequencies of classes less than 70.

i.e.

[tex]P(x < 70) = [30 - 39] + [40 - 49] + [50 - 59] + [60 - 69][/tex]

So, we have:

[tex]P(x < 70) = 0.025 + 0.025 + 0.050 + 0.125[/tex]

[tex]P(x < 70) = 0.225[/tex]