Answer:
T₂ = 1.2 s
Step-by-step explanation:
The time period of a simple pendulum is given by :
[tex]T=2\pi \sqrt{\dfrac{L}{g}}[/tex]
Where
L is length of the pendulum
g is acceleration due to gravity
We have,
T₁ = 1.4 s, L₁ = 0.49 m, L₂ = 0.36 m, T₂= ?
[tex]\dfrac{T_1}{T_2}=\sqrt{\dfrac{L_1}{L_2}} \\\\T_2=\dfrac{T_1}{\sqrt{\dfrac{L_1}{L_2}}}\\\\T_2=\dfrac{1.4}{\sqrt{\dfrac{0.49}{0.36}}}\\\\T_2=1.2\ s[/tex]
So, the new time period is equal to 1.2 seconds.
What is the value of x?
Enter your answer in the box.
x =
$\text{Basic}$
$x$$y$$x^2$$\sqrt{ }$$\frac{x}{ }$
$x\frac{ }{ }$
$x^{ }$$x_{ }$$\degree$$\left(\right)$$\abs{ }$$\pi$$\infty$
The figure shows 2 right triangles, triangle A B C with right angle B and triangle B D C with right angle D. The measure of angle B A C is 45 degrees. The measure of angle D B C is 60 degrees. The length of side C A is 6 square root 2. The length of side B D is x.
Answer:
That did not make sense
Answer:
x = 3
Step-by-step explanation:
Verified correct with test results.
Just had to delete the jibberish to find the actual question for this problem:
The figure shows 2 right triangles, triangle A B C with right angle B and triangle B D C with right angle D. The measure of angle B A C is 45 degrees. The measure of angle D B C is 60 degrees. The length of side C A is 6 square root 2. The length of side B D is x. What is the value of x?
Jesse makes a large wooden picture frame in the shape of a rectangle with a diagonal brace on the back, as shown in the diagram.
What is the length, in feet, of the diagonal brace that Jesse uses?
Answer Choices:
F. 5ft
G.15ft
H.60ft
J.7ft
Answer:5 ft
Step-by-step explanation: ( 36 x 36 ) + ( 48 x 48 ) = 3600 inches
Square root of 3600 is 60
Convert inches to feet: 60 / 12 = 5
i put 15 i think it’s wrongs please help
Answer:
[tex] \sqrt{( {0 - 12}) {}^{2} + (1 - 10) {}^{2} } \\ = \sqrt{0 + 81} \\ = \sqrt{81} \\ = 9[/tex]
[tex] \huge\mathfrak\pink{A} \huge\mathfrak\purple{n} \huge\mathfrak\blue{s} \huge\mathfrak\red{w} \huge\mathfrak\green{e} \huge\mathfrak\orange{r}\ [/tex]
9 is the correct answer
A bag of 33 tulip bulbs contains 11 red tulips, 12 yellow tulips, and 10 purple tulips. Suppose two tulip bulbs are randomly selected without replacement from the bag. What is the probability that two randomly selected tulip bulbs are both red
8
Determine the area
of the shaded
region.
2 ft
7.6.4
Answer:
3.44 ft ^2
Step-by-step explanation:
the box area is 4x4 =16
the circle is 4π = 12.57
16-12.57 = 3.46 this is rounded so 3.44 would work too
Find the area of this trapezoid:
Answer:
Pls add the image
Step-by-step explanation:
At 3:30 p.m., you have 15 megabytes of a movie. At 3:45 p.m., you have 75 megabytes. What is the download rate in megabytes per minute?
A support wire is being attached to a telephone pole as shown in the
diagram. To the nearest foot, how long does the wire need to be?
the answer is 4.565 JF$OFB#$UF
Which one is correct?
Find the point on a circle that has a radius of 8 with an angle of rotation of 130 degrees centered at (-3,5)?
Please answer the question and provide a solid definition of what an expression is, thank you :)
Answer:
Answers are: 2x - 7, and 2x -7 = 14
Step-by-step explanation:
An expression must have variables must have a coefficient, a number that is multiplied divided added or subtracted by our variable. The variable is a place holder.
So our answers would be 2x - 7, and 2x -7 = 14
Solve for the letter t
Find the coefficient of the x^3 in the expansion of (2x-9)^5
Use the binomial theorem:
[tex]\displaystyle (2x-9)^5 = \sum_{k=0}^5 \binom5k (2x)^{5-k}(-9)^k = \sum_{k=0}^5 \frac{5!}{k!(5-k)!} 2^5 \left(-\frac92\right)^k x^{5-k}[/tex]
The x ³ terms occurs for 5 - k = 3, or k = 2, and its coefficient would be
[tex]\dfrac{5!}{2!(5-2)!} 2^5 \left(-\dfrac92\right)^2 = \boxed{6480}[/tex]
A and B are similar solid cylinders base area of A : base area of B = 9 : 25
complete these ratios
curved surface area of A : curved surface area of B : = ? : ?
height of A : height of B = ? : ?
Answer:
Two figures are similar if the figures have the same shape but different sizes.
Then if we have two figures X and X'
Such that one dimension of X is D, the correspondent dimension on X' will be:
D' = k*D
Such that k is the scale factor that relates the figures.
1:k
Because all the dimensions will be rescaled by the same scale factor k, we can conclude that any surface on X will be related to the same surface in X' by:
S' = k^2*S
then the ratio of the surfaces is:
1:k^2
While the relation between the volumes will be:
V' = k^3*V
Here the ratio is:
1:k^3
Ok, in this case we have two cylinders
We know that the ratio between the base area ( a surface) is:
9:25
a) We want to find the ratio: curved surface area of A : curved surface area of B
Because again we have a surface area, the ratio should be exactly the same as before, 9:25
b) height of A : height of B
In this case, we have a single dimension.
Because in the rescaling of a surface we need to use k^2, then we can conclude that the ratios:
9:25
is related to k^2
Then the ratio, in this case, is given by applying the square root to both sides of the previous ratio, so we get:
√9:√25
3:5
This is the ratio of the heights.
Also from this we could get the value of k, that is the right value when we leave the left value equal to 1, we can get that if we divide both sides by 3.
(3/3):(5/3)
1:(5/3)
Then:
k = 5/3
plssssss helppp last diagnostic
Answer:
9/20 square miles
Step-by-step explanation:
9/10× 1/2= 9/20 square miles
PLEASE HELP ME!!!!!!!!!ASAP!!!!!
Write down three integers, all less than 25, whose range is 8 and mean is 11.
Answer:
11,15,7
Step-by-step explanation:
11+15+7=33 33/3=11 the mean
then 15-7=8 the range
the ratio of the corresponding sides of two similar triangles is 2:5 the sides of the smaller triangle is 6mm 8mm and 12mm what is the perimeter of the larger triangle?
Answer:
65
Step-by-step explanation:
using the ratio we can find the side lengths of the other triangle.
since it is 2:5
6:x=2:5
so x = 15(first side)
8:x=2:5
so x = 20(second side)
12:x=2:5
x=30(third side)
so then we add them up
15+20+30
65
hope this was helpful
Fill in the blank
7.5 cm =_ m
A. 0.0075
B. 0.075
C. 0.75
D. 750
(6x-5)+(-7x+2)
and
(6x-5)-(-7x+2)
Need work
Answer:(6x-5)+(-7x+2)
1 Remove parentheses.
6x-5-7x+2
2 Collect like terms.
(6x-7x)+(-5+2)
3 Simplify.
-x-3
_____________________________
1 Remove parentheses.
6x-5+7x-2
6x−5+7x−2
2 Collect like terms.
(6x+7x)+(-5-2)
3 Simplify.
13x-7
Hope this helps
-Tobie the dog <3
6x - 5 + (-7x + 2) = ...
= 6x - 5 - 7x + 2
= (6x - 7x) + (-5 - 2)
= -x - 7
[tex]\:[/tex]
B)6x - 5 - (-7x + 2) = ...
= 6x - 5 + 7x + 2
= (6x + 7x) + (-5 + 2)
= 13x - 3
In ΔSTU, the measure of ∠U=90°, UT = 80, SU = 39, and TS = 89. What ratio represents the tangent of ∠S?
Answer:
[tex]\frac{80}{39}[/tex]
Step-by-step explanation:
SOHCAHTOA
O =Opposite
A = Adjacent
H = Hpotenuse
If we draw it out we can see that the opposite side is the UT and adjacent side is SU for ∠S.
When an angle is asked for like here is S so the opposite side of the angle is the opposite side. and the angle close to it is the adjacent. The biggest side is the hypotenuse.
5(2 + 2m). Simplify the expression
Answer:
10m+10
Step-by-step explanation:
5x2=10
5x2m=10m
10m+10
An elephant can travel 30 km in 2 hours. How fast is the elephant moving?
Historically, about 53% of the population of a certain country believed that the planet's temperature was rising ("global warming"). A March 2010 poll wanted to determine whether this proportion had changed. The poll interviewed adults in the population, and said they believed that global warming was real. (Assume these adults represented a simple random sample.)
Required:
a. What percentage in the sample believed global warming was real in 2010?
b. Is this more or less than the historical 57%?
Answer:
(a) The proportion is 61.23%
(b) It is more than the historical 57%
Step-by-step explanation:
This question has missing details, and they are:
[tex]n = 926[/tex] ---- The Sample Adults
[tex]x = 567[/tex] -- Those that believe global warming was real
Solving (a): The proportion of those that believe.
This is calculated as:
[tex]p = \frac{x}{n}[/tex]
Substitute values for x and n
[tex]p = \frac{567}{926}[/tex]
[tex]p = 0.6123[/tex]
Express as percentage
[tex]p = 0.6123 * 100\%[/tex]
[tex]p = 61.23\%[/tex]
Solving (b) More or less than 57%
By comparison:
[tex]61.2\% > 57\%[/tex]
Hence, it is more than the historical 57%
add 2 please add
[tex]2 \frac{3}{4} + 5 \frac{4}{5} = [/tex]
Answer:
Step-by-step explanation:
19/4 + 29/5
2.75 + 5.8
= 8.55
Explain what the vertical line test is and how it is used.
What is the range of the given function?
{(–2, 0), (–4, –3), (2, –9), (0, 5), (–5, 7)}
{x | x = –5, –4, –2, 0, 2}
{y | y = –9, –3, 0, 5, 7}
{x | x = –9, –5, –4, –3, –2, 0, 2, 5, 7}
{y | y = –9, –5, –4, –3, –2, 0, 2, 5, 7}
✧ [tex] \underline{ \underline{ \pink{\large{ \tt{E \: X \: P \: L\: A \: N \: A \: T \: I \: O \: N}}}}}: [/tex]
Part 1 :
☃ [tex] \underline{ \large{ \sf{Vertical \: Line \: Test}}} : [/tex] ⇾ All the relations are not functions. We can determine ( identify ) whether a relation is function or not by drawing a vertical line intersecting the graph of the relation. This is called the vertical line test.
If the vertical line intersects the graph of a relation at one point , the relation is a function.If it cuts at more than one point , it is not a function. It means that if there are more points of the graph of a relation of a vertical line , same first component ( pre - image ) has more images ( second component ) which is not the function by definition.( See the attached picture )
In the picture ' 1 ' , The vertical line ( dotted line ) cuts the graph at one point ( P ). Thus the graph represents a function.In the picture ' 2 ' , The vertical line ( dotted line ) cuts the graph at two points P & Q. So, the graph does not represent a function.Part 2 :
☂ The set of all the images of the elements of domain under the function ' f ' is called the range of a function. In other words , the set of second components of a function is called range. We are given the function :
{(–2, 0), (–4, –3), (2, –9), (0, 5), (–5, 7)}The above numbers [ in bold ] are the range of given function. Now, If we arrange these numbers in ascending order, we get ( -9 , -3 , 0 , 5 , 7 ).
Hence , Choice B [ {y | y = –9, –3, 0, 5, 7} ] is correct.
♕ Hope I helped! ♡
☄ Have a wonderful day / night ! ☼
✎ [tex] \underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}[/tex] ☥
▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
Sample Response:
The vertical line test is a way to determine if a relation is a function. This test determines if one input has exactly one output on the graph. If any vertical line passes through more than one point on the graph, then the relation is not a function because two different outputs have the same input.
if y varies inversely as x and y=3 when x=14, find x when y=6
write an expression that represents the quotient of a number and 3 multiplied by 4
Answer:
N (3×4) or (N×3) 4
Step-by-step explanation:
please help (no links) or i will report you i just need answers
Answer:
15.) 104 ... I hope angles are not drawn to scale
16.) 144
17.) 37
Step-by-step explanation:
15.)
3x + 10 = 4x -12
22 = x
so 3x +10 = 76
180 - 76 = t = 104
16.)
2(21) + 36 + 90 + bcd + a = 360
a = 90 - 21 = 69
360 - (2(21) + 36 + 90 + 69) = bcd
bcd = 360 - 237 = 123
angle acd = 21 + bcd = 21 + 123 = 144
17.)
(5x - 7) + 90 + (3x + 1) = 180
8x -6 = 90
8x = 96
x = 12
so 5x - 7 = 53
90 - 53 = angle lmn = 37
If l || m, determine what type of angles they are and find the value of x.
Access the hourly wage data on the below Excel Data File (Hourly Wage). An economist wants to test if the average hourly wage is less than $29.
Hourly EDUC EXPER AGE Gender
Wage
37.85 11 2 40 1
21.72 4 1 39 0
34.34 4 2 38 0
21.26 5 9 53 1
24.65 6 15 59 1
25.65 6 12 36 1
25.45 9 5 45 0
20.39 4 12 37 0
29.13 5 14 37 1
27.33 11 3 43 1
28.02 8 5 32 0
20.39 9 18 40 1
24.18 7 1 49 1
17.29 4 10 43 0
15.61 1 9 31 0
35.07 9 22 45 0
40.33 11 3 31 1
20.39 4 14 55 0
16.61 6 5 30 1
16.33 9 3 28 0
23.15 6 15 60 1
20.39 4 13 32 0
24.88 4 9 58 1
23.88 5 4 28 0
37.65 6 5 40 1
15.45 6 2 37 0
26.35 4 18 52 1
19.15 6 4 44 0
16.61 6 4 57 0
18.39 9 3 30 1
25.45 5 8 43 0
28.02 7 6 31 1
23.44 4 3 33 0
17.66 6 23 51 1
26.33 4 15 37 0
34.34 4 9 45 0
35.45 6 3 55 0
37.43 5 14 57 0
35.89 9 16 36 1
20.39 4 20 60 1
31.81 4 5 35 0
35.45 9 10 34 0
37.66 5 4 28 1
23.87 6 1 25 0
36.35 7 10 43 1
25.45 9 2 42 1
23.67 4 17 47 0
26.02 11 2 46 1
23.15 4 15 52 0
24.18 8 11 64 0
a) Choose the null and the alternative hypotheses for the test.
A. H0:μ≥29;HA:μ<29
B. H0:μ=29;HA:μ≠29
C. H0:μ≤29;HA:μ>29
b) Use the Excel function Z. TEST to calculate the p-value. Assume that the population standard deviation is $6.
c) At α = 0.01 what is the conclusion?
A. Do not reject H0; the hourly wage is not less than $29.
B. Do not reject H0; the hourly wage is less than $29.
C. Reject H0; the hourly wage is not less than $29.
D. Reject H0; the hourly wage is less than $29.
Answer:
A. H0:μ≥29;HA:μ<29
Pvalue < 0.01
D. Reject H0; the hourly wage is less than $29
Step-by-step explanation:
The null hypothesis will negate the claim which will be the hypothesis to be tested. Therefore, since the claim is to test if hourly wage is less Than 29 ; then the null will be that hourly wage is equal to or greater than 29
H0:μ≥29;HA:μ<29
The Pvalue measure the probability that the extremity of our finding against a certain α level. The Pvalue obtained using the Excel function should be 0.00058
When Pvalue is < α ; We reject the null hypothesis
Hence, Reject H0; the hourly wage is less than $29 and conclude that hourly wage is less Than $29
