Answer:
11.5
Step-by-step explanation:
plug 3 in for x
then solve
What is the surface area of the regular pyramid below?
What is a Parrel line?
Answer:
parrel line never meet
Given the functions:
g(n) = 3n - 5
f(n) = n2 + 50
Find:
(g+f)(8)
Answer:
[tex](g + f)(8) =133[/tex]
Step-by-step explanation:
Given
[tex]g(n) = 3n - 5[/tex]
[tex]f(n) = n^2 + 50[/tex]
Required
[tex](g + f)(8)[/tex]
This is calculated as:
[tex](g + f)(n) =g(n) + f(n)[/tex]
So, we have:
[tex](g + f)(n) =3n - 5 + n^2 +50[/tex]
[tex]Substitute[/tex] 8 for n
[tex](g + f)(8) =3*8 - 5 + 8^2 +50[/tex]
[tex](g + f)(8) =24 - 5 + 64 +50[/tex]
[tex](g + f)(8) =133[/tex]
Which of the following is NOT a solution to the linear equation y=3x+2?
Select the correct answer below:
(1,5)
(2,8)
(3,10)
(4,14)
Answer:
(3,10)
Step-by-step explanation:
When x is 3
[tex]{ \bf{y = 3x + 2}} \\ { \bf{y = (3 \times 3) + 2}} \\ { \bf{y = 11}}[/tex]
y is 11, and this is invalid because it is not at accord.
The correct coordinates which is NOT a solution to the linear equation
y = 3x+2 is,
⇒ (3, 10)
What is Equation of line?The equation of line in point-slope form passing through the points
(x₁ , y₁) and (x₂, y₂) with slope m is defined as;
⇒ y - y₁ = m (x - x₁)
Where, m = (y₂ - y₁) / (x₂ - x₁)
Given that;
Linear equation is,
⇒ y = 3x + 2
We know that;
The solution of linear equation is satisfy the eqaution.
Hence, We can check as;
⇒ y = 3x + 2
Put x = 1. y = 5
⇒ 5 = 3 × 1 + 2
⇒ 5 = 5
Thus, It is solution of linear equation.
⇒ y = 3x + 2
Put x = 2. y = 8
⇒ 8 = 3 × 2 + 2
⇒ 8 = 8
Thus, It is solution of linear equation.
⇒ y = 3x + 2
Put x = 3, y = 10
⇒ 10 = 3 × 3 + 2
⇒ 10 ≠ 11
Thus, It is not solution of linear equation.
Thus, The correct coordinates which is NOT a solution to the linear equation y = 3x+2 is,
⇒ (3, 10)
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In the number 1326308 is between which two numbers in a million?
Answer:
1326308 is in between 1326307 and 1326309
what is the sum factor of 3600
Answer:
Step-by-step explanation:
Answer:
24
Step-by-step explanation:
Find the prime factorization of the number 3,600. Factor Tree.
2|3,600.
2|1,800.
2|900.
2|450
5|225
5|45
3|9
3|3
|1
Setup the equation for determining the number of factors or divisors.
3600=2x2x2x2x3x3x5
Sum factors=2+2+2+2+2+3+3+5=24
José tiene 30 años menos que su padre y 27 más que su hijo. entre los 3 suman 135 años ¿ cuántos años tiene cada uno?
Answer:
44 años tiene jose . el padre 74 y el hijo 17 años.
Step-by-step explanation:
Compute the product AB by the definition of the product ofmatrices, where Ab1 and Ab2 are computed separately, and by therow-column rule for computing AB.
Matrix A= [2 -2]
[3 4]
[4 -3]
Matrix B =
[4 -1]
[-1 2]
Answer:
[tex]A * B = \left[\begin{array}{ccc}10&-6\\8&5\\19&-10\end{array}\right][/tex]
Step-by-step explanation:
Given
[tex]A =\left[\begin{array}{cc}2&-2\\3&4\\4&-3\end{array}\right][/tex]
[tex]B = \left[\begin{array}{cc}4&-1\\-1&2\end{array}\right][/tex]
Required
[tex]AB[/tex]
To do this, we simply multiply the rows of A by the column of B;
So, we have:
[tex]A * B = \left[\begin{array}{ccc}2*4 + -2*-1&2*-1+-2*2\\3*4+4*-1&3*-1+4*2\\4*4-3*-1&4*-1-3*2\end{array}\right][/tex]
[tex]A * B = \left[\begin{array}{ccc}10&-6\\8&5\\19&-10\end{array}\right][/tex]
To the nearest degree, find the measure of angle A.
Cosine(angle) = adjacent leg/ hypotenuse
Cosine( angle ) = 18/20
Angle = arccos(18/20)
Angle = 26 degrees
Answer:
26°
Step-by-step explanation:
For a right triangle, we can use trigonometry equations :-
In this case we need to use cosine equation .
cos A = adjacent side / hypotenuse
cos A = 18 / 20
A = cos × 18/20
A = arccos × 18/20
A = 26°
What are the center and radius of the circle defined by the equation x^2 + y^2 -6x + 8y + 21=0
Answer:
Step-by-step explanation:
(x²-6x)+(y²+8y)=-21
(x²-6x+9)+(y²+8y+16)=-21+9+16
(x-3)²+(y+4)²=4
center=(3,-4),radius=√4=2
FLIGHT TO TOKYO TAKE 2 HOURS 20 MINUTES U ARRIVE AT 4:15PM WHICH TIME DID HE SET OFF
Answer: 1:55 PM
Step-by-step explanation:
Turn 4:15 to 24-hr clock system which is 1615hrs
16:15 - 02:20 = 1355hrs
Somebody please help asap
Answer:
B. [tex] 4x^2 + \frac{3}{2}x - 7 [/tex]
Step-by-step explanation:
[tex] f(x) = \frac{x}{2} - 3 [/tex]
[tex] g(x) = 4x^2 + x - 4 [/tex]
(f + g)(x) = f(x) - g(x)
= [tex] \frac{x}{2} - 3 + 4x^2 + x - 4 [/tex]
Add like terms
[tex] = 4x^2 + \frac{x}{2} + x - 3 - 4 [/tex]
[tex] = 4x^2 + \frac{3x}{2} - 7 [/tex]
[tex] = 4x^2 + \frac{3}{2}x - 7 [/tex]
If 21% of kindergarten children are afraid of monsters, how many out of
each 100 are afraid?
Answer:
The appropriate answer is "21".
Step-by-step explanation:
Given:
Afraid percentage,
p = 21%
or,
= 0.21
Sample size,
n = 100
As we know,
⇒ [tex]X=np[/tex]
By putting the values, we get
[tex]=0.21\times 100[/tex]
[tex]=21[/tex]
How many solutions does the nonlinear system of equations graphed below have?
Answer:
2
Step-by-step explanation:
2 is the answer because the circle touches the line only 2 times.
Hope this helps.
A custodian has 5 and 1/2 gallons of paint each of the book cases she is painting requires 1/2 gallon of paint how many book cases will the custodian be able to paint with that amount of paint A.3 B.4 C.11 D.15
Answer:
Option C.
Step-by-step explanation:
Annual windstorm losses, X and Y, in two different regions are independent, and each is uniformly distributed on the interval [0, 10]. Calculate the covariance of X and Y, given that X+ Y < 10.
Answer:
[tex]Cov(X,Y) = -\frac{ 25}{9}[/tex]
Step-by-step explanation:
Given
[tex]Interval =[0,10][/tex]
[tex]X + Y < 10[/tex]
Required
[tex]Cov(X,Y)[/tex]
First, we calculate the joint distribution of X and Y
Plot [tex]X + Y < 10[/tex]
So, the joint pdf is:
[tex]f(X,Y) = \frac{1}{Area}[/tex] --- i.e. the area of the shaded region
The shaded area is a triangle that has: height = 10; width = 10
So, we have:
[tex]f(X,Y) = \frac{1}{0.5 * 10 * 10}[/tex]
[tex]f(X,Y) = \frac{1}{50}[/tex]
[tex]Cov(X,Y)[/tex] is calculated as:
[tex]Cov(X,Y) = E(XY) - E(X) \cdot E(Y)[/tex]
Calculate E(XY)
[tex]E(XY) =\int\limits^X_0 {\int\limits^Y_0 {\frac{XY}{50}} \, dY} \, dX[/tex]
[tex]X + Y < 10[/tex]
Make Y the subject
[tex]Y < 10 - X[/tex]
So, we have:
[tex]E(XY) =\int\limits^{10}_0 {\int\limits^{10 - X}_0 {\frac{XY}{50}} \, dY} \, dX[/tex]
Rewrite as:
[tex]E(XY) =\frac{1}{50}\int\limits^{10}_0 {\int\limits^{10 - X}_0 {XY}} \, dY} \, dX[/tex]
Integrate Y
[tex]E(XY) =\frac{1}{50}\int\limits^{10}_0 {\frac{XY^2}{2}}} }|\limits^{10 - X}_0 \, dX[/tex]
Expand
[tex]E(XY) =\frac{1}{50}\int\limits^{10}_0 {\frac{X(10 - X)^2}{2} - \frac{X(0)^2}{2}}} }\ dX[/tex]
[tex]E(XY) =\frac{1}{50}\int\limits^{10}_0 {\frac{X(10 - X)^2}{2}}} }\ dX[/tex]
Rewrite as:
[tex]E(XY) =\frac{1}{100}\int\limits^{10}_0 X(10 - X)^2\ dX[/tex]
Expand
[tex]E(XY) =\frac{1}{100}\int\limits^{10}_0 X*(100 - 20X + X^2)\ dX[/tex]
[tex]E(XY) =\frac{1}{100}\int\limits^{10}_0 100X - 20X^2 + X^3\ dX[/tex]
Integrate
[tex]E(XY) =\frac{1}{100} [\frac{100X^2}{2} - \frac{20X^3}{3} + \frac{X^4}{4}]|\limits^{10}_0[/tex]
Expand
[tex]E(XY) =\frac{1}{100} ([\frac{100*10^2}{2} - \frac{20*10^3}{3} + \frac{10^4}{4}] - [\frac{100*0^2}{2} - \frac{20*0^3}{3} + \frac{0^4}{4}])[/tex]
[tex]E(XY) =\frac{1}{100} ([\frac{10000}{2} - \frac{20000}{3} + \frac{10000}{4}] - 0)[/tex]
[tex]E(XY) =\frac{1}{100} ([5000 - \frac{20000}{3} + 2500])[/tex]
[tex]E(XY) =50 - \frac{200}{3} + 25[/tex]
Take LCM
[tex]E(XY) = \frac{150-200+75}{3}[/tex]
[tex]E(XY) = \frac{25}{3}[/tex]
Calculate E(X)
[tex]E(X) =\int\limits^{10}_0 {\int\limits^{10 - X}_0 {\frac{X}{50}}} \, dY} \, dX[/tex]
Rewrite as:
[tex]E(X) =\frac{1}{50}\int\limits^{10}_0 {\int\limits^{10 - X}_0 {X}} \, dY} \, dX[/tex]
Integrate Y
[tex]E(X) =\frac{1}{50}\int\limits^{10}_0 { (X*Y)|\limits^{10 - X}_0 \, dX[/tex]
Expand
[tex]E(X) =\frac{1}{50}\int\limits^{10}_0 ( [X*(10 - X)] - [X * 0])\ dX[/tex]
[tex]E(X) =\frac{1}{50}\int\limits^{10}_0 ( [X*(10 - X)]\ dX[/tex]
[tex]E(X) =\frac{1}{50}\int\limits^{10}_0 10X - X^2\ dX[/tex]
Integrate
[tex]E(X) =\frac{1}{50}(5X^2 - \frac{1}{3}X^3)|\limits^{10}_0[/tex]
Expand
[tex]E(X) =\frac{1}{50}[(5*10^2 - \frac{1}{3}*10^3)-(5*0^2 - \frac{1}{3}*0^3)][/tex]
[tex]E(X) =\frac{1}{50}[5*100 - \frac{1}{3}*10^3][/tex]
[tex]E(X) =\frac{1}{50}[500 - \frac{1000}{3}][/tex]
[tex]E(X) = 10- \frac{20}{3}[/tex]
Take LCM
[tex]E(X) = \frac{30-20}{3}[/tex]
[tex]E(X) = \frac{10}{3}[/tex]
Calculate E(Y)
[tex]E(Y) =\int\limits^{10}_0 {\int\limits^{10 - X}_0 {\frac{Y}{50}}} \, dY} \, dX[/tex]
Rewrite as:
[tex]E(Y) =\frac{1}{50}\int\limits^{10}_0 {\int\limits^{10 - X}_0 {Y}} \, dY} \, dX[/tex]
Integrate Y
[tex]E(Y) =\frac{1}{50}\int\limits^{10}_0 { (\frac{Y^2}{2})|\limits^{10 - X}_0 \, dX[/tex]
Expand
[tex]E(Y) =\frac{1}{50}\int\limits^{10}_0 ( [\frac{(10 - X)^2}{2}] - [\frac{(0)^2}{2}])\ dX[/tex]
[tex]E(Y) =\frac{1}{50}\int\limits^{10}_0 ( [\frac{(10 - X)^2}{2}] )\ dX[/tex]
[tex]E(Y) =\frac{1}{50}\int\limits^{10}_0 [\frac{100 - 20X + X^2}{2}] \ dX[/tex]
Rewrite as:
[tex]E(Y) =\frac{1}{100}\int\limits^{10}_0 [100 - 20X + X^2] \ dX[/tex]
Integrate
[tex]E(Y) =\frac{1}{100}( [100X - 10X^2 + \frac{1}{3}X^3]|\limits^{10}_0)[/tex]
Expand
[tex]E(Y) =\frac{1}{100}( [100*10 - 10*10^2 + \frac{1}{3}*10^3] -[100*0 - 10*0^2 + \frac{1}{3}*0^3] )[/tex]
[tex]E(Y) =\frac{1}{100}[100*10 - 10*10^2 + \frac{1}{3}*10^3][/tex]
[tex]E(Y) =10 - 10 + \frac{1}{3}*10[/tex]
[tex]E(Y) =\frac{10}{3}[/tex]
Recall that:
[tex]Cov(X,Y) = E(XY) - E(X) \cdot E(Y)[/tex]
[tex]Cov(X,Y) = \frac{25}{3} - \frac{10}{3}*\frac{10}{3}[/tex]
[tex]Cov(X,Y) = \frac{25}{3} - \frac{100}{9}[/tex]
Take LCM
[tex]Cov(X,Y) = \frac{75- 100}{9}[/tex]
[tex]Cov(X,Y) = -\frac{ 25}{9}[/tex]
the second difference 4;x;8;y;20;.... is 2
9514 1404 393
Answer:
x = 5y = 13Step-by-step explanation:
First differences are ...
x -4, 8 -x, y -8, 20 -y
Then second differences are ...
(8 -x) -(x -4)
(y -8) -(8 -x)
(20 -y) -(y -8)
Each of these is said to be 2, so we have ...
12 -2x = 2 ⇒ x = 5
28 -2y = 2 ⇒ y = 13
And an equation we can use to check:
x +y -16 = 2 ⇒ 5 +13 -16 = 2 . . . . true
_____
The explicit formula for the sequence is ...
an = n^2 -2n +5
2x-5y=22n y=3x-7 Use substitution to solve the system.
Answer:
x = 1 , y = -4
Step-by-step explanation:
2x - 5y = 22 ------- ( 1 )
y = 3x - 7 ------- ( 2 )
Substitute ( 2 ) in ( 1 ) :
2x - 5 (3x - 7) = 22
2x - 15x + 35 = 22
- 13x = 22 - 35
- 13x = - 13
x = 1
Substitute x in ( 1 ) :
2x - 5y = 22
2 ( 1 ) - 5y = 22
- 5y = 22 - 2
-5y = 20
y = - 4
The length of a rectangle should be 9 meters longer than 7 times the width. If the length must be
between 93 and 163 meters long, what are the restrictions for the width, p?
Write the solution set as an algebraic inequality solved for the variable.
Answer:
If we define W as the width:
12m ≤ W ≤ 22m
Step-by-step explanation:
We have a rectangle with length L and width W.
We know that:
"The length of a rectangle should be 9 meters longer than 7 times the width"
Then:
L = 9m + 7*W
We also know that the length must be between 93 and 163 meters long, so:
93m ≤ L ≤ 163m
Now we want to find the restrictions for the width W.
We start with:
93m ≤ L ≤ 163m
Now we know that L = 9m + 7*W, then we can replace that in the above inequality:
93m ≤ 9m + 7*W ≤ 163m
Now we need to isolate W.
First, we can subtract 9m in the 3 sides of the inequality
93m - 9m ≤ 9m + 7*W -9m ≤ 163m -9m
84m ≤ 7*W ≤ 154m
Now we can divide by 7 in the 3 sides, so we get:
84m/7 ≤ 7*W/7 ≤ 154m/7
12m ≤ W ≤ 22m
Then we can conclude that the width is between 12 and 22 meters long.
The profits in hundreds of dollars, P(c), that a company can make from a product is modeled by a function of the price, c, they charge for the product: P(c) = –20c2 + 320c + 5,120. What is the maximum profit the company can make from the product?
Answer:
6400
Step-by-step explanation:
Given the profit function ;
P(c) = –20c2 + 320c + 5,120
The maximum value is given by :
f(h) ; where, h = - b /2a
From P(C) ; a = - 20 ; b = 320
h = - b / 2a = - 320 / 2(-20) = - 320 / 40 = 8
c = h
P(8) = –20(8)² + 320(8) + 5,120
P(8) = - 1280 + 2560 + 5120
= 6400
Answer:
B.) $640,000
Step-by-step explanation:
Which best explains whether a triangle with side lengths 2 in., 5 in., and 4 in. is an acute triangle?
The triangle is acute because 22 + 52 > 42.
The triangle is acute because 2 + 4 > 5.
The triangle is not acute because 22 + 42 < 52.
The triangle is not acute because 22 < 42 + 52.
9514 1404 393
Answer:
The triangle is not acute because 2² + 4² < 5²
Step-by-step explanation:
The square of the hypotenuse of a right triangle with the given short sides would be 2² +4² = 20. So, that hypotenuse would be √20, about 4.47. The long side of this triangle is longer than that, so the angle opposite is larger than 90°. The triangle with sides 2, 4, 5 is an obtuse triangle.
The triangle is not acute because 2² + 4² < 5²
The triangle is not acute because 22 + 42 < 52.
Option C is the correct answer.
What is a triangle?A triangle is a 2-D figure with three sides and three angles.
The sum of the angles is 180 degrees.
We can have an obtuse triangle, an acute triangle, or a right triangle.
We have,
To determine if a triangle is acute, we need to check whether all three angles of the triangle are acute angles (less than 90 degrees).
Pythagorean theorem,
- If the square of the length of the hypotenuse is greater than the sum of the squares of the other two sides, then the triangle is acute.
- If the square of the length of the hypotenuse is less than the sum of the squares of the other two sides, then the triangle is obtuse.
Now,
The triangle with side lengths 2 in., 5 in., and 4 in. is not a right triangle.
So we can't use the Pythagorean theorem directly.
Now,
We can check if the sum of the squares of the two shorter sides is greater than the square of the longest side.
2² + 4² = 4 + 16 = 20
5² = 25
Since 20 < 25, we know that the triangle is not acute.
Therefore,
The triangle is not acute because 22 + 42 < 52.
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Which graph represents the function f(x) = 2^x+ 3?
Answer:
Where's the graph?
Step-by-step explanation:
In The Diagram, P, Q, R, Are Points On The Circle With Centre 0 And Diameter 14cm. Angle PQR=35 Degree. Find, Correct To One Decimal Place A. The Length Of The Minor Are PQ; B. The Chord PQ.
This question hasn't been solved yet
Ask an expert
in the diagram, P, Q, R, are points on the circle with centre 0 and diameter 14cm. angle PQR=35 degree. find, correct to one decimal place
a. The length of the minor are PQ;
B. The chord PQ.
Answer:
a
Step-by-step explanation:
because the diagram the length decimal place degree
A trailer is 22 feet long. 9 feet wide,
and 7 feet high. What is the volume of
the trailer?
Answer:
1386
Step-by-step explanation:
22 × 9 × 7 = 1386 cubic feet
First,i would rewrite 3/4 as an equivalent fraction with a denominator of ____
The equivalent fraction is ____ Then, I would compare the equivalent fraction to 7/12\
PLEASE TELL ME THE ANSWERS IN THE BLANKS!!!
Answer:
denominator of 12 (first blank) making the numerator 9. equivalent fraction 9/12 (second blank)
Step-by-step explanation:
lowest common denominator is 12. make sure what you do to the denominator (4times3)= 12, you do to the numerator (3times3)=9
Answer:
The first blank is the denominator of 12 so the numerator is 9. Which makes the answer 9/12
Step-by-step explanation:
Hope this helps! :)>
reflectiion across y=x
9514 1404 393
Answer:
see attached
Step-by-step explanation:
The reflection across y=-x swaps the coordinates and negates both of them. The first-quadrant figure becomes a third-quadrant figure.
(x, y) ⇒ (-y, -x)
The box plots show the weights, in pounds, of the dogs in two different animal shelters.
Weights of Dogs in Shelter A
2 box plots. The number line goes from 6 to 30. For the weights of dogs in shelter A, the whiskers range from 8 to 30, and the box ranges from 17 to 28. A line divides the box at 21. For shelter B, the whiskers range from 10 to 28, and the box ranges from 16 to 20. A line divides the box at 18.
Weights of Dogs in Shelter B
Which is true of the data in the box plots? Select three choices.
The median weight for shelter A is greater than that for shelter B.
The median weight for shelter B is greater than that for shelter A.
The data for shelter A are a symmetric data set.
The data for shelter B are a symmetric data set.
The interquartile range of shelter A is greater than the interquartile range of shelter B.
Answer:
The median weight for shelter A is greater than that for shelter B.
The data for shelter B are a symmetric data set.
The interquartile range of shelter A is greater than the interquartile range of shelter B.
Step-by-step explanation:
The median weight for shelter A is greater than that for shelter B.
The median of A = 21 and the median of B = 18 true
The median weight for shelter B is greater than that for shelter A.
The median of A = 21 and the median of B = 18 false
The data for shelter A are a symmetric data set.
False, looking at the box it is not symmetric
The data for shelter B are a symmetric data set.
true, looking at the box it is symmetric
The interquartile range of shelter A is greater than the interquartile range of shelter B.
IQR = 28 - 17 = 11 for A
IQR for B = 20 -16 = 4 True
After a certain number of football matches , a footballer averages 1 goal per game.He only scored 2 goals in the next 10 games and his average dropped to 0.8 goals per game .How many football matches did he play altogether?
Answer:
He played 40 matches in total, scoring 32 goals.
Step-by-step explanation:
Since after a certain number of football matches, a footballer averages 1 goal per game, and he only scored 2 goals in the next 10 games and his average dropped to 0.8 goals per game, to determine how many football matches did he play altogether you must perform the following calculation:
10/10 + 2/10 = 12/20 = 0.6
8/8 + 2/10 = 10/18 = 0.55
12/12 + 2/10 = 14/22 = 0.64
20/20 + 2/10 = 22/30 = 0.73
24/24 + 2/10 = 26/34 = 0.76
30/30 + 2/10 = 32/40 = 0.8
Thus, he played 40 matches in total, scoring 32 goals.
someone plz help me porfavor!!!!!
Answer:
c. y = ¼x - 2
Step-by-step explanation:
Find the slope (m) and y-intercept (b) then substitute the values into y = mx + b (slope-intercept form)
Slope = change in y/change in x
Using two points on the graph, (0, -2) and (4, -1):
Slope (m) = (-1 - (-2))/(4 - 0) = 1/4
m = ¼
y-intercept = the point where the line intercepts the y-axis = -2
b = -2
✔️To write the equation, substitute m = ¼ and b = -2 into y = mx + b:
y = ¼x - 2
Wayne is picking out some movies to rent, and he is primarily interested in dramas and horror films. He has narrowed down his selections to 7 dramas and 16 horror films. How many different combinations of 3 movies can he rent if he wants at least two dramas
Answer:
The number of selections is 49.
Step-by-step explanation:
drama = 7
horror films = 16
Select 3 movies at least two dramas
For 2 drama and 1 horror film
(3 C 2) x (16 C 1) = 48
For 3 drama
(3 C 3) = 1
So, total number of selections is 48 + 1 = 49.
