THERE ARE 2 PARTS PLEASE ANSWER BOTH RIGHT TY HELPP!! There are 12 red cards, 17 blue cards, 14 purple cards, and 7 yellow cards in a hat.
Part A. What is the theoretical probability of drawing a purple card from the hat?

Part B.
In a trial, a card is drawn from the hat and then replaced 1,080 times. A purple card is drawn 324 times. How much greater is the experimental probability than the theoretical probability?

Enter the correct answers in the boxes.

A. The theoretical probability of drawing a purple card from the hat is ______.

B. The experimental probability of drawing a purple card is ____%
greater than the theoretical probability.

Answer: 2 meters

Step-by-step explanation:

The length of one train car is 80 millimeters. Therefore, the length of the entire train is:

25 cars × 80 mm per car = 2000 mm

To convert millimeters to meters, we need to divide by 1000:

2000 mm ÷ 1000 = 2 meters

Therefore, Venell's model train is 2 meters long.

Answer:

61°

Step-by-step explanation:

∠4 is the vertical angle to the 61° angle. This means they will have the same measure, so ∠4 is 61°.

a. The slope of AB is  [tex]m = 1[/tex] and slope of BC is [tex]m = -4/7.[/tex]

b. The best name for this quadrilateral would be a rectangle ABCD, as opposite sides and all angles are equal.

c. The mid-point of Diagonal AC is  [tex](0, -1/2)[/tex]

A clοsed shape nοted fοr having sides with variοus widths and lengths is a quadrilateral. It is a clοsed, two-dimensional pοlygοn with fοur sides, fοur angles, and fοur vertices. Quadrilaterals include the trapezium, parallelοgram, rectangle, square, rhοmbus, and kite, amοng οthers.

a.

Slope is given by

[tex]A = (-2, 3) and B = (-5, 0)[/tex]

[tex]m = 1[/tex]

[tex]B = (-5, 0) and C = (2, -4)[/tex]

[tex]m = -4/7[/tex]

Thus, The slope of AB is m = 1 and slope of BC is [tex]m = -4/7[/tex]  .

b. The best name for this quadrilateral would be a rectangle ABCD, as opposite sides and all angles are equal.

c. Midpoint of a segment is given by the 2 divided by of sum x and and sum of y

Thus, Diagonal  [tex]A = (-2, 3)[/tex] and [tex]C = (2, -4)[/tex]

Midpoint  [tex]= ((-2 + 2), (3 + -4))[/tex]

[tex]= ((0), (-1))[/tex]

Now divide them by 2

[tex]= ((0/2), (-1/2))[/tex]

[tex]= (0, -1/2)[/tex]

Therefore, the mid-point of Diagonal [tex]AC is (0, -1/2)[/tex]

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We can see here that in order to construct a triangle PQR in which angle Q = 30°, angle R=60° and PQ + QR + RP = 10cm​, here is a guide:

A triangle is a geometric shape that is defined as a three-sided polygon, where each side is a line segment connecting two of the vertices, or corners, of the triangle. The interior angles of a triangle always add up to 180 degrees.

Triangles can be classified into different types based on their side lengths and angles, such as equilateral triangles with three equal sides and three equal angles, isosceles triangles with two equal sides and two equal angles, and scalene triangles with no equal sides or angles.

Triangles are used in many areas of mathematics and science, including geometry, trigonometry, and physics.

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a) The first four nonzero terms of the power series for f(x) about x=0 are

e^6 - 2x^2 + (2x^4)/2! - (2x^6)/3!

The general term of the power series is (-2)^n (2x)^(2n) / (2n)!

b) The interval of convergence of the power series is (-∞, ∞).

c) To estimate the error between f(x) and its partial sum g(x) given by the sum of the first four nonzero terms of the power series, we can use the Lagrange form of the remainder

|R4(x)| = |f(x) - g(x)| ≤ M |x|^5 / 5!

a) To find the power series for f(x) about x = 0, we can use the Maclaurin series formula

f(x) = Σ[n=0 to ∞] (fⁿ(0)/n!) xⁿ

where fⁿ(0) denotes the nth derivative of f evaluated at x=0.

In this case, we have

f(x) = e^6(-2x^2)

fⁿ(x) = dⁿ/dxⁿ(e^6(-2x^2)) = (-2)^n(2x)^ne^6(-2x^2)

So, we can write the power series as

f(x) = Σ[n=0 to ∞] ((-2)^n(2x)^n e^6(0))/n!)

= Σ[n=0 to ∞] ((-2)^n (2x)^n /n!)

To find the first four nonzero terms, we substitute n = 0, 1, 2, and 3 into the above formula

f(0) = e^6

f'(0) = 0

f''(0) = 24

f'''(0) = 0

So, the first four nonzero terms of the power series are:

e^6 - 2x^2 + (2x^4)/2! - (2x^6)/3!

The general term of the power series is

(-2)^n (2x)^(2n) / (2n)!

b) To find the interval of convergence of the power series, we can use the ratio test

lim [n→∞] |((-2)^(n+1) (2x)^(2n+2) / (2n+2)! ) / ((-2)^n (2x)^(2n) / (2n)!)|

= lim [n→∞] |-4x^2/(2n+1)(2n+2)|

= lim [n→∞] 4x^2/(2n+1)(2n+2)

Since this limit depends on the value of x, we need to consider two cases

i) If x = 0, then the power series reduces to the constant term e^6, and the interval of convergence is just x=0.

ii) If x ≠ 0, then the series converges absolutely if and only if the limit is less than 1 in absolute value

|4x^2/(2n+1)(2n+2)| < 1

This is true for all values of x as long as n is sufficiently large. So, the interval of convergence is the entire real line (-∞, ∞).

c) We can use the Lagrange form of the remainder to estimate the error between f(x) and its partial sum g(x) given by the sum of the first four nonzero terms of the power series

|R4(x)| = |f(x) - g(x)| ≤ M |x|^5 / 5!

where M is an upper bound for the fifth derivative of f(x) on the interval [-0.6, 0.6].

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Step-by-step explanation:

There are many possible solutions to this problem, but one possible set of values for P, Q, R, S, T, and U is:

P = 2

Q = 5

R = 1

S = 8

T = 9

U = 9

With these values, we have:

PQR = 251

STU = 156

And the sum of PQR and STU is indeed 407.

The joint probability density function for the random variables Y1 and Y2 E(Y1+Y2) and V(Y1+Y2) is 41/144.

To find E(Y1+Y2), we need to integrate the sum of Y1 and Y2 over their joint probability density function:

E(Y1+Y2) = ∫∫ (y1 + y2) f(y1,y2) dy1 dy2

= ∫∫ (y1 + y2) (2) dy1 dy2, where the limits of integration are 0 to 1 for both y1 and y2 and y1+y2 <=1

= ∫[tex]0^1[/tex] ∫[tex]0^{(1-y1)}[/tex](y1 + y2) (2) dy2 dy1

= ∫[tex]0^1[/tex] (2y1 + 1) (1-y1)² dy1

= 5/12

To find V(Y1+Y2), we can use the formula V(Y1+Y2) = E[(Y1+Y2)²] - [E(Y1+Y2)]².

First, we need to find E[(Y1+Y2)^2]:

E[(Y1+Y2)²] = ∫∫ (y1+y2)² f(y1,y2) dy1 dy2

= ∫∫ (y1² + y2² + 2y1y2) (2) dy1 dy2, where the limits of integration are 0 to 1 for both y1 and y2 and y1+y2 = 1

= ∫[tex]0^1[/tex] ∫[tex]0^{(1-y1)}[/tex] (y1² + y2² + 2y1y2) (2) dy2 dy1

= ∫[tex]0^1[/tex] (1/3)y1³ + (1/2)y1² + (1/2)y1

(1/3)y1 + (1/4) dy1

= 7/12

Next, we need to find [E(Y1+Y2)]²:

[E(Y1+Y2)]² = (5/12)² = 25/144

Therefore, V(Y1+Y2) = E[(Y1+Y2)²] - [E(Y1+Y2)]² = (7/12) - (25/144) = 41/144.

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Answer:

The answer is brand B

Step-by-step explanation:

You divide $14.88 by 24 which equals 68 cents per item.

Then brand B is 60 cents per item which is the better buy!

On the 7th day after the videο was pοsted, 640 peοple will see the videο.

Statistics is the discipline that cοncerns the cοllectiοn, οrganizatiοn, analysis, interpretatiοn, and presentatiοn οf data.

1 Let's start by finding the pattern in the number οf viewers. We knοw that οn the first day, 5 peοple watched the videο. On the next day, the number οf viewers dοubled tο 5 x 2 = 10. On the third day, the number οf viewers dοubled again tο 10 x 2 = 20. We can see that the number οf viewers is dοubling each day, which means we can write the number οf viewers as:

[tex]V = 5 x 2^n[/tex]

where n is the number οf days after the videο was pοsted.

Nοw we want tο find οn which day the number οf viewers will be 640. Sο we can set V equal tο 640 and sοlve fοr n:

[tex]640 = 5 x 2^n[/tex]

[tex]2^n = 128[/tex]

n = lοg2(128) = 7

2.   Tο find the first day when mοre than 20,000 peοple will see the videο, we can set V equal tο 20,000 and sοlve fοr n:

[tex]20,000 = 5 x 2^n[/tex]

2^n = 4,000

n = lοg2(4,000) ≈ 11.29

Since n represents the number οf days after the videο was pοsted, we can rοund up tο the next whοle number tο find the first day when mοre than 20,000 peοple will see the videο. Therefοre, οn the 12th day after the videο was pοsted, mοre than 20,000 peοple will see the videο if the trend cοntinues

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Since Kingsley wanted an equation to convert from inches to centimeters, the correct answer is B) c = 2.54i.

What is equation ?

An equation is a statement that asserts the equality of two expressions, usually separated by an equals sign (=). The expressions on either side of the equals sign may contain one or more variables, which are unknown values that can be determined by solving the equation.

Kingsley wants to convert a given length in inches to centimeters. He knows that 1 inch is about 2.45 centimeters.

Let's call the length in inches "i" and the length in centimeters "c".

We want to find an equation that relates i and c. We know that 1 inch is about 2.45 centimeters, so we can write:

1 inch = 2.45 centimeters

To convert from inches to centimeters, we can multiply the length in inches by 2.45. So:

c = 2.45i

This is the equation Kingsley can use to convert any given length in inches to centimeters.

Alternatively, we can rearrange this equation to solve for i:

c = 2.45i

Divide both sides by 2.45:

c/2.45 = i

So the equation for converting from centimeters to inches is:

i = c/2.45

Therefore,  since Kingsley wanted an equation to convert from inches to centimeters, the correct answer is B) c = 2.54i.

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Answer:

{y,x}={-1,1}

to leave and take

Answer:

x = 4

Step-by-step explanation:

using the rule of exponents

• [tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex] , then

[tex]4^{-x}[/tex] = [tex]\frac{1}{4^{x} }[/tex]

and 256 = [tex]4^{4}[/tex]

then

[tex]\frac{1}{4^{x} }[/tex] = [tex]\frac{1}{4^{4} }[/tex]

so

[tex]4^{x}[/tex] = [tex]4^{4}[/tex]

since bases on both sides are equal, bot 4 then equate exponents

x = 4

Answer:

D

Step-by-step explanation:

If their reflections are congruent to each other then looking at the diagram we can see a reflection just like a mirror where its flipped on the other side of the dotted line. When flipping it and aligning one triangle to the other we find that BC is congruent to DF

The system of equation is now written as:

y = −2x−8

y = x+ 1

First, we will plotting two system of  equations on the same axis, and then we'll explore the different factors to consider when plotting two linear inequalities on the same axis. The technique for drawing a system of linear equations is the same as for drawing a single linear equation. We can draw two lines on the same axis system using an array of values, slope and y-intercept or x-y-intercept.

Now,

these using slope-intercept form on the same set of axes. Remember that slope-intercept form looks like

y = mx+ b,  so we will want to solve both equations for y.

First, solve for y in 2x+y=−8

2x+ y = −8

OR, y = −2x− 8

Second, solve for y in

x− y = −1

Or, y = x+1

The system is now written as

y = -2x - 8

y = x + 1

Now you can plot the two equations using their slope and intercept on the same set of axes as shown in the figure below. Note that these charts have one thing in common. It is their intersection, the point that lies on the two lines. In the next section we will verify that this point is the solution of the system.

Complete Question:

Graph each system of equations. Solve each system and clearly mark the solutions on your graph and consider the following system of linear equations in two variables.

                            2x+ y = −8 and x− y = −1

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Days when change in temperature more than 10° F are Option B)Tuesday and E) Friday.

calculating the difference by deducting the end temperature from the initial temperature. The temperature difference is therefore 75 degrees Celsius - 50 degrees Celsius = 25 if something begins at 50 degrees Celsius and ends at 75 degrees Celsius.

Change in temperature on Monday from High to low

=15-10=5°F

Change in temperature on Tuesday from High to low

=8-(-4)=12°F

Change in temperature on Wednesday from High to low

=-2-(-5)=3°F

Change in temperature on Thursday from High to low

=-3-(-7)=4°F

Change in temperature on Friday from High to low

=-1-(-12)=11° F

Days when change in temperature more than 10° F are Tuesday and Friday.

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The Complete question is attached below:

The equation of the plane passing through the point (-1,0,1) and containing the lines x = 5t, y=1+t, z= -t is y + z = 1 .

We substitute , t=0 in the given line equations ,

we get; x=0 , y = 1 and z = 0 ;

So, the plane contain the line , Thus plane will also pass through (0,1,0);

Now, we have that plane passes through (-1,0,1) and (0,1,0), direction ratios of line joining these 2 points are ;

⇒ DR₁ = (-1-0 , 0-1 , 1-0) = (-1,-1,1);

So , the line can be written as x/5 = (y-1)/1 = z/-1 = t;

So, the direction ratio of this line will be :

⇒ DR₂ = (5 , 1 , -1);

The Direction Ratio of normal to the plane is = DR₁ × DR₂;

= (-1,-1,1) × (5,1,-1);

= [tex]\left|\begin{array}{ccc}i&j&k\\-1&-1&1\\5&1&-1\end{array}\right|[/tex]

On solving ,

We get;
= 4j + 4k = (0,4,4) ;

We know that for a normal with direction ratios (a,b,c), equation of plane is written as ax + by + cz = d;

We got direction ratio for plane normal = (0,4,4);

So, equation of plane is 0x+ 4y + 4z = d;

the plane passes through the point (-1,0,1) ;

⇒ 4(0) + 4(1) = d ⇒ d = 4;

we get the equation of plane is 4y + 4z = 4;

⇒ y + z = 1.

Therefore, the equation of the required plane is  y + z = 1.

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4775 g968r648 747474874 483892874 23773259635y84b2375789325 7437594365825 4378574937587 49388959365n 98437858746587 32o4iy548569

Answer:

?

Step-by-step explanation:

The employee will contribute 4% of the first $1000, which is $40. Then, the employee will contribute 3% of the next $1000, which is $30. Following that, the employee will contribute 2% of the next $1000, which is $20. Finally, the employee will contribute 1% of the remaining $17,000, which is $170. Therefore, the employee will contribute a total of $260 to the fund.

An employee who earned $20,000 will contribute $260 to the welfare fund.

To calculate the contribution to the welfare fund for an employee who earned $20,000, we can break down the earnings into different tiers based on the given rates.

The first $1000 will have a contribution rate of 4%.

Contribution for the first $1000 = 4% of $1000 = $40.

The next $1000 will have a contribution rate of 3%.

Contribution for the next $1000 = 3% of $1000 = $30.

The next $1000 will have a contribution rate of 2%.

Contribution for the next $1000 = 2% of $1000 = $20.

The remaining amount above $3000 ($20,000 - $3000 = $17,000) will have a contribution rate of 1%.

Contribution for the remaining amount = 1% of $17,000 = $170.

Now, let's sum up the contributions for each tier:

$40 + $30 + $20 + $170 = $260.

Therefore, an employee who earned $20,000 will contribute $260 to the welfare fund.

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The equation can be rearranged to the form y = -qx + r. This is the equation of a straight line, which can be graphed. The point of intersection of the two lines, ak + bl = 0 and y = -qx + r, is the solution for the two variables (k and l).

The equation ak + bl = 0 is a linear equation in two variables and is solved using the method of elimination. The equation can be written in the form ax + by = c, where a, b, c are constants. To solve this equation, both sides of the equation should be divided by the coefficient of one of the variables (a or b). This will result in a equation of the form x + qy = r, where q and r are constants. Then, the equation can be rearranged to the form y = -qx + r. This is the equation of a straight line, which can be graphed. The point of intersection of the two lines, ak + bl = 0 and y = -qx + r, is the solution for the two variables (k and l). The two variables can then be calculated using the point of intersection by substituting the x and y values into the two equations. In this way, the two variables k and l can be found such that ak + bl = 0.

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What are the integers k and l such that ak + bl = 0?

Answer: The two positive numbers that satisfy the given requirements are 25 and 50.

Step-by-step explanation:

Let's call the two positive numbers x and y. We want to maximize their product while satisfying the condition that "the sum of the first and twice the second is 100", or mathematically:

x + 2y = 100

We can use algebra to solve for one of the variables in terms of the other:

x = 100 - 2y

Now we want to maximize the product xy:

xy = x(100 - 2y) = 100x - 2xy

Substituting x = 100 - 2y:

xy = (100 - 2y)y = 100y - 2y^2

To find the maximum value of this expression, we can take the derivative with respect to y and set it equal to zero:

d(xy)/dy = 100 - 4y = 0

Solving for y gives:

y = 25

Substituting y = 25 into the equation x + 2y = 100, we get:

x + 2(25) = 100

x = 50

Therefore, the two positive numbers that satisfy the given requirements are x = 50 and y = 25, and their product is:

xy = 50(25) = 1250

A quadratic function in standard form that passes through the points [tex](-8,0), (-5,-3), and (-2,0)[/tex] is equals to the [tex]f(x) = (1/3)( x^{2} + 10x + 16)[/tex].

f(x) = ax2 + bx + c, in which a, b, and c are integers and an is not equal to zero, is a quadratic function. A parabola is the shape of a quadratic function's graph.

In other terms, you have a quadratic equation if a times the squares of the expression after b plus b twice that same equation not square plus c equals 0.

[tex]f(x) = ax^{2} + bx + c ----(1)[/tex]

is determined by three points and must be [tex]a[/tex] not equal [tex]0[/tex]. That is for determining the f(x) we have to determine value of three values a, b, and c. Now, we have three ordered pairs [tex](-8,0), (-5,-3)[/tex], and [tex](-2,0)[/tex] and we have to determine quadratic function passing through these points. So, firstly, plug the coordinates of point[tex]( -8,0), x = -8, y = f(x) = 0[/tex] in equation [tex](1)[/tex],

[tex]= > 0 = a(-8)^{2} + b(-8) + c[/tex]

[tex]= > 64a - 8b + c = 0 -------(2)[/tex]

Similarly, for second point [tex]( -5,-3) , f(x) = -3, x = -5[/tex]

[tex]= > - 3 = a(-5)^{2} + (-5)b + c[/tex]

[tex]= > 25a - 5b + c = -3 --(3)[/tex]

Continue for third point [tex](-2,0)[/tex]

[tex]= > 0 = a(-2)^{2} + b(-2) + c[/tex]

[tex]= > 4a -2b + c = 0 --(4)[/tex]

So, we have three equations and three values to determine.

Subtract equation [tex](4)[/tex] from [tex](2)[/tex]

[tex]= > 64 a - 8b + c - 4a + 2b -c = 0[/tex]

[tex]= > 60a - 6b = 0[/tex]

[tex]= > 10a - b = 0 --(5)[/tex]

subtract equation [tex](4)[/tex] from [tex](3)[/tex]

[tex]= > 21a - 3b = -3 --(6)[/tex]

from equation (4) and (5),

[tex]= > 3( 10a - b) - 21a + 3b = -(- 3)[/tex]

[tex]= > 30a - 3b - 21a + 3b = 3[/tex]

[tex]= > 9a = 3[/tex]

[tex]= > a = 1/3[/tex]

from [tex](5)[/tex] , [tex]b = 10a = 10/3[/tex]

from [tex](4)[/tex], [tex]c = 2b - 4a = 20/3 - 4/3 = 16/3[/tex]

So,[tex]f(x)= (1/3)( x^{2} + 10x + 16)[/tex]

Hence, required values are [tex]1/3, 10/3,[/tex] and [tex]16/3[/tex].

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Answer:

-------------------------------------

Given 3 points of a quadratic function and two of them lie on the x-axis:

These two points are representing the roots of the function. With known roots we can show the function in the factor form:

Substitute the roots into the equation and use the third point with coordinates x = - 5, f(x) = - 3, find the value of a:

This gives us the function in the factor form:

Convert this into standard form of f(x) = ax² + bx + c:

The experimental probability that at least one of the first three customers that walks into the store will make a purchase is 60%.

It is determined by counting the number of times an event occurs in a given experiment and dividing the total number of trials by the number of successful outcomes.

The experimental probability that at least one of the first three customers that walks into the store will make a purchase is calculated by dividing the total number of customers who make a purchase by the total number of customers who enter the store.

In this case, there are 3 trials and 2 customers who make a purchase.

The experimental probability is 3 by 5 which is the total number of trials.

Thus, the experimental probability

=3/5

= 60%.

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Samir's new balance is $5,044.17.

To calculate Samir's new balance, add the previous balance, subtract the payment, add the new transaction, and multiply by the interest rate for one period. The following formula can be used to calculate the interest for a single period:

balance * APR / 12 = interest

where APR stands for annual percentage rate and 12 represents the number of months in a year.

When we apply this formula to Samir's balance and APR, we get:

5336.22 * 0.29 / 12 = 128.95 in interest

As a result, the total new balance is:

5336.22 - 607 + 186 + 128.95 = 5044.17

We get the following when we round to the nearest hundredth:

$5,044.17

As a result, Samir now has a balance of $5,044.17.

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Answer:

To find the probability that a randomly selected person is a meat-eater, we need to add up the number of meat-eaters and divide by the total number of individuals surveyed. From the given table, we can see that there are 72 meat-eaters out of a total of 190 individuals surveyed:

Total meat-eater = 72

Total surveyed = 190

So the probability of selecting a meat-eater is:

P(meat-eater) = Total meat-eater / Total surveyed

P(meat-eater) = 72 / 190

P(meat-eater) = 0.38 (rounded to the hundredths place)

Therefore, the probability that a randomly selected person is a meat-eater is 0.38 or 38%.

Answer:

To simplify F1 × F2 - F3 in terms of y, we need to first find the product of F1 and F2, and then subtract F3.

F1 × F2 can be expanded using the distributive property:

F1 × F2 = (4y - 6) × (9y + 3) = 4y × 9y + 4y × 3 - 6 × 9y - 6 × 3

= 36y^2 + 12y - 54y - 18

= 36y^2 - 42y - 18

Now we can subtract F3 from the result:

F1 × F2 - F3 = (36y^2 - 42y - 18) - (-y - 8)

= 36y^2 - 42y - 18 + y + 8

= 36y^2 - 41y - 10

Therefore, F1 × F2 - F3 in terms of y is 36y^2 - 41y - 10.

(please mark my answer as brainliest)

The correct option for this question is (d) "No, none of the sides are parallel."

why it is and what is a Quadrilateral?

To determine if quadrilateral CDEF is a trapezoid, we need to check if it has exactly one pair of parallel sides.

We can find the slopes of the line segments CD and EF as follows:

slope of CD = (5 - (-6)) / (-8 - (-1)) = 11 / (-7) = -1.57 (approx.)

slope of EF = (8 - 5) / (3 - 4) = 3 / (-1) = -3

Since the slopes are different, CD and EF are not parallel, and therefore, CDEF is not a trapezoid.

Alternatively, we can also find the slopes of the line segments CF and DE as follows:

slope of CF = (-5 - (-6)) / (4 - (-1)) = 1/5

slope of DE = (8 - 5) / (3 - (-8)) = 3/11

Since the slopes are different, CF and DE are not parallel, and therefore, CDEF is not a trapezoid.

Therefore, the answer is option (d) "No, none of the sides are parallel."

A quadrilateral is a geometric shape that has four straight sides and four vertices (corners). It is a two-dimensional polygon with four sides and four angles. The sum of the interior angles of a quadrilateral is always 360 degrees.

There are many types of quadrilaterals, including squares, rectangles, rhombuses, parallelograms, trapezoids, and kites.

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Answer: 39

39 is the only answer option greater than 17

The Davenports' medical expenses contribute to their total itemized deductions are $375 (7.5% for 2019).

The costs you incurred for state and local income or sales taxes, real estate taxes, personal property taxes, mortgage interest, and disaster losses are all included in itemised deductions. You can also count charitable donations and a portion of your out-of-pocket medical and dental costs.

Currently for the 2019 (due 2020), you can deduct medical expenses that exceed 7.5% of your AGI, but back then in 2019, the threshold was 7.5%, not 10%.

So the Davenports can only deduct

$5,250 - ($65,000 x 7.5%) = $375

if they decided to itemize their deductions.

The threshold will increase back to 10% starting 2020 (due 2021) tax returns.

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Answer: numbers 1,3 and 4

Step-by-step explanation:

Answer:

Answer: C. f(x) = 2x²+x+6