This graph shows the solution to which inequality?
(32)
(-3.-6);
A ys 1/x - 2
B. y> fx-2
C. yzfx-2
***-2
Answers
y>4/3x-2
Related Questions
Drag the tiles to the correct boxes to complete the pairs.
Match each division of rational expressions with its quotient.
Answers
Answer:
Step-by-step explanation:
Um where is the diagrahm
Two factors of x² +5x+6 are ….. and …..
Answers
Hello!
[tex]\large\boxed{(x + 2)(x + 3)}[/tex]
x² + 5x + 6
Find two numbers that add up to 5 and multiply to 6. We get:
2, 3
Therefore:
(x + 2)(x + 3)
Please help asap i will give brainliest. Find the exact perimeter and area of the triangle.
Answers
Answer:
perimeter=9cm
Area=2cm^2
step by step explanation:
Firstly solve the sides that don't have figures using trigonometry
#1..sin15°=opposite/hypotenuse
sin15=opposite/4
opposite=sin15×4
=1.035, round off to 1cm
Then find the value of the base
tan15=opposite/adjacent
tan15=1/adjacent
1=tan15adjascent
1/tan15=adjacent
adjacent or base=3.7 round off to 4cm
After finding these values find the perimeter
p=side+side+side
p=4cm+4cm+1cm
p=9cm
Find the area
1/2bh
1/2×4×1
A=2cm2
How do I solve this?
Answers
The answer for the first line segment : (-3,-7) (-4,0)
The answer for 2nd line segment is :(-3,8) (-9,-5)
Step-by-step explanation:
Let do line segment QR and ST. first.
Step 1: Find a line that contains a points that is perpendicular to the line of reflection
"A reflection of a pre image and new image is perpendicular to the line of reflection.
This means for points Q,S,T and R, there is a line that. contains one point that is perpendicular to the line of reflection.
A line that is perpendicular to the line of reflection is the negative reciprocal of the slope so this means all 4 lines must be on a different slopes but the slopes must be 1/2.
To simplify, things, here are the lines that will all 4 points be on
Point R will be on line y=1/2x-11/2Point Q will be on line y=1/2x+2Point S will be on line y=1/2x+19/2Point T will be on line y=1/2x-1/2Step 2: Find a point where both the line and line of reflection intersect at.
Now we need to find a line where both the line of reflections and the 4 lines will intersect at separately.
The line with Point R will intersect with the line of reflection at point (1,-5)The line with Point Q will intersect with line of reflection at Point (-2,1)The line with Point S will intersect at point (-5,7)The line worth Point T will intersect at Point(-1,-1).Step 3: Find the endpoints given the midpoint and the originally endpoint.
A reflection per and new image is equidistant from the point of reflection. So we. an say that the point where the line intersect is the midpoint of the pre and new image.
Using this info,
The endpoint for R prime is (-3, -7).The endpoint for Q prime is (-4,0). The endpoint of S prime is (-3,8).The endpoint of T prime is (-9,-5).Connect R prime and Q prime. And that the new line segments
Connects S prime and T prime and that the new line segments.
A 27% solution ( 27mg per 100 mL of solution) is given intravenously. Suppose a total of 1,36 L of the solution is given over a 10 -hour period. Complete parts (a) through (c) below.
a. What is the flow rate in units of mL/hr?
nothing mL/hr (Type an integer or decimal rounded to the nearest thousandth as needed.)
What is the flow rate in per hour?
nothing mg/hr (Type an integer or decimal rounded to the nearest thousandth as needed.)
b. If each mL contains 13 drops (the drop factor is expressed as gtt/mL), what is the flow rate in units of 13gtt/hr?
nothing gtt/hr (Type an integer or decimal rounded to the nearest thousandth as needed.)
c. During the 10 -hour period, how much is delivered?
nothing mg (Type an integer or decimal rounded to the nearest thousandth as needed.)
Answers
Answer:
Step-by-step explanation:
a.
(1.36 L)/(10 hr) = (0.136 L)/(hr)
Flow rate = (0.136 L)/(hr) × (1000 mL)/L = (136 mL)/(hr)
136 mL × (27 mg)/(100 mL) = 36.72 mg
Delivery rate = (36.72 mg)/(hr)
b.
(136 mL)/(hr) × (13 gtt)/(mL) = (1868 gtt)/(hr)
c.
10 hr × (36.72 mg)/)hr) = 367.2 mg
Which function has the following characteristics?
- A vertical asymptote at x=3
- A horizontal asymptote at y=2
- Domain: {x ≠ ±3}
A. y= (2x-8) / (x-3)
B. y= (2x^2 - 8) / (x^2 - 9)
C. y= (x^2 - 9) / (x^2 - 4)
D. y= (2x^2 - 18) / (x^2 - 4)
Answers
The function has the characteristics is (b) y= (2x^2 - 8) / (x^2 - 9)
How to determine the function?The features are given as:
A vertical asymptote at x=3A horizontal asymptote at y=2Domain: {x ≠ ±3}The function that has the above features is (b).
This is proved as follows:
y= (2x^2 - 8) / (x^2 - 9)
Set the denominator not equal to 0, to determine the domain
x^2 - 9 ≠ 0
Add 9 to both sides
x^2 ≠ 9
Take the square roots
x ≠ ±3 --- domain
Replace ≠ with =
x = ±3 --- vertical asymptote
Set the numerator to 0
2x^2 - 8 = 0
Divide through by 2
x^2 - 4 = 0
This gives
x^2 = 4
Take the square roots
x = 2 ---- horizontal asymptote
Hence, the function has the characteristics is (b) y= (2x^2 - 8) / (x^2 - 9)
Read more about functions at:
https://brainly.com/question/4138300
#SPJ1
x(x-y) - y( x- y) simplify
Answers
Step-by-step explanation:
x²-xy-xy+y²
x²+2xy+y²
hope it helps
add 10ft 3in + 3ft 9in + 8ft 10in
Answers
Which ordered pair (a, b) is the solution to the given system of linear equations? 3a+b= 10 -4a-2b=2
(1,7)
(3, 1)
(11, -23)
(23, -11)
Answers
Hello,
answer C (11,-23)
[tex]\left\{\begin{array}{ccc}3a+b&=&10\\-4a-2b&=&2\end{array}\right.\\\\\\\left\{\begin{array}{ccc}6a+2b&=&20\\-4a-2b&=&2\end{array}\right.\\\\\\\left\{\begin{array}{ccc}3a+b&=&10\\2a&=&22\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&11\\b&=&10-3*11\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&11\\b&=&-21\end{array}\right.\\[/tex]
Answer: C. (11,-23)
Step-by-step explanation:
Can someone help and explain this to me ,much appreciated thankyouuu
Answers
Answer:
A. 2x + 1
Step-by-step explanation:
f(x) = 2x + 7
g(x) = x - 3
To find f(g(x)), substitute x = x - 3 into f(x) = 2x + 7
Thus:
f(g(x)) = 2(x - 3) + 7
f(g(x)) = 2x - 6 + 7
Add like terms
f(g(x)) = 2x + 1
Please HELP!
How many pairs (A, B) are there where A and B are subsets of {1, 2, 3, 4, 5, 6, 7, 8} and A ∩ B has exactly two elements?
Answers
Answer:
There are 256 pairs in all.
HELP
-5(2m-3)-4<81
I need the steps also well
Answers
Answer:
m>-7
Step-by-step explanation:
expand
-10m+15-4<81
-10m+11<81
collect like terms
-10m<81-11
-10m<70
m>-7
Write an algebraic expression for the situation. 28 divided by a number n An algebraic expression for the situation is
Answers
Answer:
[tex]\frac{28}{n}[/tex]
Step-by-step explanation:
The variance of the scores on a skill evaluation test is 143,641 with a mean of 1517 points. If 343 tests are sampled, what is the probability that the mean of the sample would differ from the population mean by less than 36 points
Answers
Answer:
The probability that the mean of the sample would differ from the population mean by less than 36 points=0.9216
Step-by-step explanation:
We are given that
The variance of the scores on a skill evaluation test=143,641
Mean=1517 points
n=343
We have to find the probability that the mean of the sample would differ from the population mean by less than 36 points.
Standard deviation,[tex]\sigma=\sqrt{143641}[/tex]
[tex]P(|x-\mu|<36)=P(|\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}|<\frac{36}{\frac{\sqrt{143641}}{\sqrt{343}}})[/tex]
[tex]=P(|Z|<\frac{36}{\sqrt{\frac{143641}{343}}})[/tex]
[tex]=P(|Z|<1.76)[/tex]
[tex]=0.9216[/tex]
Hence, the probability that the mean of the sample would differ from the population mean by less than 36 points=0.9216
A school contains 140 boys and 160 girls. what is the ratio of boys to girls?
I need full working out please
Answers
Answer:
7 : 8
Step-by-step explanation:
that is the procedure above
The sum of the first ten terms of an arithmetic progression consisting of
positive integer terms is equal to the sum of the 20th, 21st and 22nd term.
If the first term is less than 20, find how many terms are required to give
a sum of 960.
Answers
Answer: [tex]n=13[/tex]
Step-by-step explanation:
Given
Sum of the first 10 terms is equal to sum of 20, 21, and 22 term
[tex]\Rightarrow \dfrac{10}{2}[2a+(10-1)d]=[a+19d]+[a+20d]+[a+21d]\\\\\Rightarrow 5[2a+9d]=3a+60d\\\Rightarrow 10a+45d=3a+60d\\\Rightarrow 7a=15d[/tex]
No of terms to give a sum of 960
[tex]\Rightarrow 960=\dfrac{n}{2}[2a+(n-1)d]\\\\\Rightarrow 1920=n[2a+(n-1)\cdot \dfrac{7}{15}a]\\\\\Rightarrow 28,800=n[30a+7a(n-1)]\\\\\Rightarrow a=\dfrac{28,800}{n[30+7n-7]}\\\\\Rightarrow a=\dfrac{28,800}{n[23+7n]}[/tex]
Value of first term is less than 20
[tex]\therefore \dfrac{28,800}{n[23+7n]}<20\\\\\Rightarrow 28,800<20n[23+7n]\\\Rightarrow 0<460n+140n^2-28,800\\\Rightarrow 140n^2+460n-28,800>0\\\\\Rightarrow n>12.79\\\\\text{For integer value }\\\Rightarrow n=13[/tex]
Answer:
15
Step-by-step explanation:
In the previous answer halfway through they used the equation: 960 = (n÷2)×(2a+(n-1)×(7a÷15))
Using this equation we can substitute an number to replace n, the higher the number is the smaller a would be.
When we substitute 15 into a, then it leaves us with the answer to be a = 15 which is a positive integer and also is smaller than 20, this then let’s us know that 15 is how many terms can be summed up to make 960.
To double check this answer you can find that d = 7 by changing the a into 15 in the formula 7a/15 (found in the previous answer.
Then in the expression: (n÷2)×(2a+(n-1)×d)
substitute:
n = 14 (must be an even number for the equation to work)
a = 15
d = 7
This will give you an answer of 847, but this is only 14 terms as we changed n into 14. To add the final term you need to complete the following equation: 847+(a+(n-1)×d)
substituting:
n = 15
a = 15
d = 7
This will give you the answer of 960, again proving that it takes 15 terms to sum together to make the number 960.
I hope this has helped you.
P.S. Everything in the previous solution was right apart from the start of the last section and the answer
Please help me >_< will give out brainliest
Answers
====================================================
Explanation:
We have an octagon because there are n = 8 sides. The diagram below shows one way to number the sides so you can count them efficiently (without missing any or double counting any).
----------------
Plug n = 8 into the formula below
S = 180(n-2)
S = 180(8-2)
S = 180(6)
S = 1080
The 8 interior angles add up to 1080 degrees.
Let f(x)
2x + 8, g(x) = x2 + 2x – 8, and h(x) = 3x – 6.
Perform the indicated operation. (Simplify as far as possible.)
(h · f)(3) =
Answers
Answer:
36
Step-by-step explanation:
(h · f)(x) = h(f(x))
h(f(x)) = h(2x+8)
h(f(x))= 3(2x+8) - 6
h(f(x)) = 6x + 24 - 6
h(f(x))= 6x + 18
If x = 3
h(f(x))= 6(3) + 18
h(f(x))= 18 + 18
h(f(x))= 36
Hence (h · f)(3) = 36
Write down 4 pairs of integers a and b such that a divided by b is -5
Answers
2. 15 and -3
3. 10 and -2
4. 5 and -1
3. university dean of students wishes to estimate the average number of hours students spend doing homework per week. The standard deviation from a previous study is 4 hours. How large a sample must be selected if he wants to be 96% confident of finding whether the true mean differs from the sample mean by 2 hours
Answers
Answer:
A sample of 17 must be selected.
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.96}{2} = 0.02[/tex]
Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].
That is z with a pvalue of [tex]1 - 0.02 = 0.98[/tex], so Z = 2.054.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
The standard deviation from a previous study is 4 hours.
This means that [tex]\sigma = 4[/tex]
How large a sample must be selected if he wants to be 96% confident of finding whether the true mean differs from the sample mean by 2 hours?
A sample of n is required.
n is found for M = 2. So
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
[tex]2 = 2.054\frac{4}{\sqrt{n}}[/tex]
[tex]2\sqrt{n} = 2.054*4[/tex]
Simplifying both sides by 2:
[tex]\sqrt{n} = 2.054*2[/tex]
[tex](\sqrt{n})^2 = (2.054*2)^2[/tex]
[tex]n = 16.88[/tex]
Rounding up:
A sample of 17 must be selected.
Subtract the given numbers in the indicated base.
41 five
tes
24 five
-
The difference is
five
Answers
9514 1404 393
Answer:
12
Step-by-step explanation:
In base-5 arithmetic, ...
41 -24 = 12
_____
If we use : to separate columns with different place value, this can be looked at a couple of ways.
Subtraction by addition
2 : 4 + 0 : 2 = 3 : 1 . . . . . make the 1s place match
3 : 1 + 1 : 0 = 4 : 1 . . . . . . make the 5s place match
The total amount added was 0:2 +1:0 = 1:2.
Subtraction using borrowing
4 : 1 - 2 : 4 = (4-1) : (5+1) - 2 : 4
= (4-1-2) : (5+1)-4 = 1:2
If 19,200 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the box.
Answers
Step-by-step explanation:
√19200cm²
=138.56cm
then the highest possible volume
=(138.56)³
=2660195.926cm³
The largest possible volume of the box is; V = 25600 cm³
Let us denote the following of the square box;
Length = x
Width = y
height = h
Formula for volume of a box is;
V = length * width * height
Thus; V = xyh
but we are dealing with a square box and as such, the base sides are all equal and so; x = y. Thus;
V = x²h
The box has an open top and as such, the surface are of the box is;
S = x² + 4xh
We are given S = 19200 cm². Thus;
19200 = x² + 4xh
h = (19200 - x²)/4x
Put (19200 - x²)/4x for h in volume equation to get;
V = x²(19200 - x²)/4x
V = 4800x - 0.25x³
To get largest possible volume, it will be dimensions when dV/dx = 0. Thus;
dV/dx = 4800 - 0.75x²
At dV/dx = 0, we have;
4800 - 0.75x² = 0
0.75x² = 4800
x² = 4800/0.75
x² = 6400
x = √6400
x = 80 cm
From h = (19200 - x²)/4x;
h = (19200 - 80²)/(4 × 80)
h = (19200 - 6400)/3200
h = 4 cm
Largest possible volume = 80² × 4
Largest possible volume = 25600 cm³
Read more at; https://brainly.com/question/19053087
Last softball season, Pamela had 46 hits, a combination of singles (1 base), doubles (2 bases), and triples (3 bases). These 46 hits totaled 66 bases, and she had 4 times as many singles as doubles. How many doubles did she have?
Answers
Answer:
She had 8 doubles.
Step-by-step explanation:
This question is solved by a system of equations.
I am going to say that:
x is the number of singles.
y is the number of doubles
z is the number of triples.
46 hits
This means that [tex]x + y + z = 46[/tex]
46 hits totaled 66 bases
This means that:
[tex]x + 2y + 3z = 66[/tex]
4 times as many singles as doubles
This means that [tex]x = 4y[/tex]
So
[tex]x + 2y + 3z = 66[/tex]
[tex]4y + 2y + 3z = 66[/tex]
[tex]6y + 3z = 66[/tex]
And
[tex]x + y + z = 46[/tex]
[tex]4y + y + z = 46[/tex]
[tex]5y + z = 46 \rightarrow z = 46 - 5y[/tex]
Then
[tex]6y + 3z = 66[/tex]
[tex]6y + 3(46 - 5y) = 66[/tex]
[tex]6y + 138 - 15y = 66[/tex]
[tex]9y = 72[/tex]
[tex]y = \frac{72}{9}[/tex]
[tex]y = 8[/tex]
She had 8 doubles.
What is the inverse of function f?
Answers
9514 1404 393
Answer:
D. f^-1(x) = 3 -7x
Step-by-step explanation:
Solve x = f(y) for y to find the inverse function.
x = f(y)
x = (3 -y)/7 . . . . . . use the function definition
7x = 3 -y . . . . . . . .multiply by 7
y = 3 -7x . . . . . . . add y-7x to both sides
Then the inverse function is ...
[tex]\boxed{f^{-1}(x)=3-7x}[/tex]
The parametric equations for the paths of two projectiles are given. At what rate is the distance between the two objects changing at the given value of t? (Round your answer to two decimal places.) x1 = 10 cos(2t), y1 = 6 sin(2t) First object x2 = 4 cos(t), y2 = 4 sin(t) Second object t = π/2
Answers
Answer:
- [tex]\frac{4}{\sqrt{29} }[/tex]
Step-by-step explanation:
The equations for the 1st object :
x₁ = 10 cos(2t), and y₁ = 6 sin(2t)
2nd object :
x₂ = 4 cos(t), y₂ = 4 sin(t)
Determine rate at which distance between objects will continue to change
solution Attached below
Distance( D ) = [tex]\sqrt{(10cos2(t) - 4cos(t))^2 + (6sin2(t) -4sin(t))^2}[/tex]
hence; dD/dt = - [tex]\frac{4}{\sqrt{29} }[/tex]
In studying the sampling distribution of the mean, you were asked to list all the different possible samples from a small population and then find the mean
of each of them. Consider the following:
Personal phone calls received in the last three days by a new employee were 2. 4, and 7. Assume that samples of size 2 are randomly selected with replacement from
this population of three values
What different samples could be chosen? What would be their sample means?
O A. Possible samples 2-4, 2-74-2: 4-7, 7-2,7-4
Sample means: 3,45,55
O B. Possible samples: 2-2.2-4,2-74-2, 4-4 4-7,7-2,7-4.7-7
Sample means: 2, 3, 4, 4.5,55,7
OC. Possible samples: 2-4 2-7, 4-7
Sample means: 3.4,45
a
Q
rd
Answers
The number of measles cases increased 26.3% to 321 cases this year. What was the number of cases prior to the increase? Express your answer rounded correctly to the nearest whole number.
Answers
Answer:
The right answer is "[tex]x\simeq 254[/tex]".
Step-by-step explanation:
Let the number of earlier case will be "x".
Now,
⇒ [tex]x+x\times \frac{26.3}{100}=321[/tex]
or,
⇒ [tex]x+x\times 0.263=321[/tex]
By taking "x" common, we get
⇒ [tex]x(1+0.263)=321[/tex]
⇒ [tex]x=\frac{321}{1.263}[/tex]
⇒ [tex]=254.15[/tex]
or,
⇒ [tex]x\simeq 254[/tex]
Find the solution of the differential equation that satisfies the given initial condition. (dP)/(dt)
Answers
Answer:
[tex]P = (\frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3})^2[/tex]
Step-by-step explanation:
Given
[tex]\frac{dP}{dt} = \sqrt{Pt[/tex]
[tex]P(1) = 2[/tex]
Required
The solution
We have:
[tex]\frac{dP}{dt} = \sqrt{Pt[/tex]
[tex]\frac{dP}{dt} = (Pt)^\frac{1}{2}[/tex]
Split
[tex]\frac{dP}{dt} = P^\frac{1}{2} * t^\frac{1}{2}[/tex]
Divide both sides by [tex]P^\frac{1}{2}[/tex]
[tex]\frac{dP}{ P^\frac{1}{2}*dt} = t^\frac{1}{2}[/tex]
Multiply both sides by dt
[tex]\frac{dP}{ P^\frac{1}{2}} = t^\frac{1}{2} \cdot dt[/tex]
Integrate
[tex]\int \frac{dP}{ P^\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]
Rewrite as:
[tex]\int dP \cdot P^\frac{-1}{2} = \int t^\frac{1}{2} \cdot dt[/tex]
Integrate the left hand side
[tex]\frac{P^{\frac{-1}{2}+1}}{\frac{-1}{2}+1} = \int t^\frac{1}{2} \cdot dt[/tex]
[tex]\frac{P^{\frac{-1}{2}+1}}{\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]
[tex]2P^{\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]
Integrate the right hand side
[tex]2P^{\frac{1}{2}} = \frac{t^{\frac{1}{2} +1 }}{\frac{1}{2} +1 } + c[/tex]
[tex]2P^{\frac{1}{2}} = \frac{t^{\frac{3}{2}}}{\frac{3}{2} } + c[/tex]
[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + c[/tex] ---- (1)
To solve for c, we first make c the subject
[tex]c = 2P^{\frac{1}{2}} - \frac{2}{3}t^\frac{3}{2}[/tex]
[tex]P(1) = 2[/tex] means
[tex]t = 1; P =2[/tex]
So:
[tex]c = 2*2^{\frac{1}{2}} - \frac{2}{3}*1^\frac{3}{2}[/tex]
[tex]c = 2*2^{\frac{1}{2}} - \frac{2}{3}*1[/tex]
[tex]c = 2\sqrt 2 - \frac{2}{3}[/tex]
So, we have:
[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + c[/tex]
[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + 2\sqrt 2 - \frac{2}{3}[/tex]
Divide through by 2
[tex]P^{\frac{1}{2}} = \frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3}[/tex]
Square both sides
[tex]P = (\frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3})^2[/tex]
The function f is defined by the following rule. f(x) = 5x+1 Complete the function table.
Answers
Answer:
[tex]-5 \to -24[/tex]
[tex]-1 \to -4[/tex]
[tex]2 \to 11[/tex]
[tex]3 \to 16[/tex]
[tex]4 \to 21[/tex]
Step-by-step explanation:
Given
[tex]f(x) = 5x + 1[/tex]
Required
Complete the table (see attachment)
When x = -5
[tex]f(-5) = 5 * -5 + 1 = -24[/tex]
When x = -1
[tex]f(-1) = 5 * -1 + 1 = -4[/tex]
When x = 2
[tex]f(2) = 5 * 2 + 1 = 11[/tex]
When x = 3
[tex]f(3) = 5 * 3 + 1 = 16[/tex]
When x = 4
[tex]f(4) = 5 * 4 + 1 = 21[/tex]
So, the table is:
[tex]-5 \to -24[/tex]
[tex]-1 \to -4[/tex]
[tex]2 \to 11[/tex]
[tex]3 \to 16[/tex]
[tex]4 \to 21[/tex]
How would 0.42 be shown as a percent?
A. 0.42%
B. 4%
C. 4.2%
D. 42%
Answers
Answer:
42%
Step-by-step explanation:
to find percentages, you move the decimal point twice to the right
