Triangle OPR has length OR=5m, angle OPR = 90, find length QP​

Three million three hundred eighty-eight thousand one hundred ninety-eight - 3388198

Answer:

x = 16.4

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp / hyp

sin 66 = 15/x

x sin 66 = 15

x = 15/sin 66

x=16.41954

Rounding to the nearest tenth

x = 16.4

Answer:

7

Step-by-step explanation:

Going from -5 to 2 we get

1) -4

2) -3

3) -2

4) -1

5) 0

6) 1

7) 2

So, in total, there are 7 numbers between -5 and 2

Answer:

d no.

Step-by-step explanation:

because in my my personal opinion the function shown on the graph has a smaller rate of change, but a higher starting point

Answer:

2 or tricky answer 11

Answer:

Step-by-step explanation:

Answer:

There are 0.454 kg in one pound.

So, in 120 pounds there are 0.454 x 120 kgs.

This is equal to 54.48, and the answer is 54.48 kg.

Let me know if this helps!

Answer:

27/20

Step-by-step explanation:

[tex]\frac{13.5}{10} = \frac{13.5 * 2}{10 * 2} = \frac{27}{20}[/tex]

Answer:

a= [tex]\sqrt{19}[/tex]

Step-by-step explanation:

Pythagorean Theorem: a^2+b^2=c^2

a^2+9^2=10^2

a^2+81=100

a^2=19

a=[tex]\sqrt{19}[/tex]

Answer:

b = 4.4 meters

Answer:

[tex]a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]

[tex]b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

[tex]\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}[/tex]

By expanding the expression, we get;

[tex]\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}[/tex]

Collecting like terms gives;

[tex]\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]

[tex]\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}[/tex]

(b) The given expression is presented as follows;

[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4[/tex]

Therefore, we get;

[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}[/tex]

Collecting like terms gives;

[tex]x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )[/tex]

[tex]x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]

[tex]x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}[/tex]

Answer:

50°

Step-by-step explanation:

Angles in a triangle always add up to 180°.

The square (bottom left of triangle) is a right angle and right angles always equal 90° and the other one is 40°, so you would add them up. This equals 130°.

To find y, you would have to do 180° minus 130° which is 50°.

Hope this helps :)

Answer:

i hope it will help

Step-by-step explanation:

I did not get the equation so I solve it with two methods

Answer:

$420

.8 x = 336

x = 336/.8

X=$420

Step-by-step explanation:

Answer:

Step-by-step explanation:

In a parallelogram, this one in particular:

KR = RM

JR = RL

We are looking in the end for the length of JR, but that means that we need to solve for x somehow to plug in the expression for JL, and then split that in half. Here's how we're going to go about it. I know that

KM = KR + RM, but since KR and RM are the same length, the equation becomes

KM = 2KR. Filling that in with the expressions I'm given for KM and KR:

3x - 5 = 2(x + 7) and

3x - 5 = 2x + 14 and

x = 19. Now I can find the length of JL:

JL = 4x - 10 so

JL = 4(19) - 10 and

JL = 66

Knowing that JR = RL and JL is 66 units long, JR = RL = 33 units each.

Answer:

364 days

Step-by-step explanation:

Magic bean will take 364 days to grow 14.56 m tall.

A conversion factor exists as a ratio that expresses how many of one unit stand equal to another unit. For example, there exist 12 in. in 1 ft, 1609 m in 1 mi, 100 cm in 1 m, 60 s in 1 min, and so on.

Unit conversion exists as a multi-step procedure that involves multiplication or division by a numerical factor, choosing the accurate number of significant digits, and rounding.

First we need to convert the height in m into cm.

14.56 m=14.56*100=1456 cm

If it grows 4 cm in one day then:

It will take 1456/4=364 days (a year) to grow completely.

To know more about unit conversion refer:

https://brainly.com/question/6243489

#SPJ2

Answer:

0.63 ÷ 0.3 = 63 x 10^-2 ÷ 3 x 10^-1 = 63 / 3  x 10^(-2--1) = 21 x 10^-1 = 2.1

Answer:

2.1.

Step-by-step explanation:

63/3 = 21

0.63 = 63 / 100

and 0.3 = 3 / 10

so 0.63/0.3 = 63 /100 / 3/10 = 63/100 * 10/3

= 63/3 / 10

So the answer is 21 / 10 = 2.1.

Answer:

x = 53°

Step-by-step explanation:

The angle 115° and the angle formed by the sum of x+62° are external alternates angles, so it means they have the same measure, and you can find the value of x doing:

115°- 62° = 53°

Answer:

x=1

Step-by-step explanation:

log2( x^2 -x+2) = 1+2log2(x)

Rewriting 1 as log2(2)

log2( x^2 -x+2) = log2(2)+2log2(x)

We know that a log b = log a^b

log2( x^2 -x+2) = log2(2)+log2(x^2)

we know log a + log b = log (ab)

log2( x^2 -x+2) = log2(2*x^2)

Since the bases are the same the terms inside must be equal

x^2 -x+2 = 2x^2

Subtract 2x^2 from each side

-x^2 -x+2 = 0

Multiply by -1

x^2 +x-2 = 0

Factor

(x+2)(x-1)=0

Using the zero product property

x+2 = 0  x-1=0

x=-2  x=1

Checking the solutions

log2( x^2 -x+2) = 1+2log2(x)

X cannot be negative because 2 log2(x) cannot be negative

log2( 1^2 -1+2) = 1+2log2(1)

x=1

[tex]\\ \rm\Rrightarrow log_2(x^2-x+2)=1+2log_2x[/tex]

[tex]\\ \rm\Rrightarrow log_2(x^2-x+2)=log_22+2log_2x[/tex]

[tex]\\ \rm\Rrightarrow log_2(x^2-x+2)=2log_2(2x)[/tex]

[tex]\\ \rm\Rrightarrow log_2(x^2-x+2)=log_2(2x^2)[/tex]

[tex]\\ \rm\Rrightarrow x^2-x+2=2x^2[/tex]

[tex]\\ \rm\Rrightarrow x^2+x-2=0[/tex]

[tex]\\ \rm\Rrightarrow (x+2)(x-1)=0[/tex]

log is always positive so x=1

Laws used

Answer:

where are the numbers

Step-by-step explanation:

Answer:

continuous, continuous

Step-by-step explanation:

El área del cuadrado es de 3 centímetros cuadrados.

Dado que se desea pintar un cuadrado inscrito en una circunferencia de radio R=3cm como se muestra en la figura, para calcular el área del cuadrado se debe realizar el siguiente cálculo:

Aplicando teorema pitagórico: lado al cuadrado mas lado al cuadrado es igual a hipotenusa al cuadrado.

Por lo tanto, el área del cuadrado es de 3 centímetros cuadrados.

Aprende más en https://brainly.com/question/16405529

El área del cuadrado es de 18 centímetros cuadrados.  

El procedimiento de resolución se basa en conocer que la Medida de la Diagonal de un Cuadrado inscrito es igual a la Medida del Radio del Círculo, lo cual permite determinar el valor de la medida del Cuadrado en función del Radio del Círculo. Finalmente, determinamos el Área del Cuadrado mediante su fórmula conocida.

Dado que existe un cuadrado inscrito en un círculo, la medida de la diagonal del cuadrado es igual a la medida del radio del círculo. Además, conocemos que un cuadrado está formado por 4 triángulos rectángulos con configuración angular 45-45-90. Entonces, la medida del lado del cuadrado se calcula mediante la siguiente relación geométrica:

[tex]l = \sqrt{2}\cdot R[/tex] (1)

Donde:

[tex]R[/tex] - Radio del círculo, en centímetros.

[tex]l[/tex] - Longitud del lado del cuadrado, en centímetros.

Por otra parte, la ecuación de área del cuadrado es igual a:

[tex]A = l^{2}[/tex] (2)

Donde [tex]A[/tex] es el área del cuadrado, en centímetros cuadrados.

Si sabemos que [tex]R = 3\,cm[/tex], entonces el área del cuadrado es:

[tex]l = \sqrt{2}\cdot (3\,cm)[/tex]

[tex]l = 3\sqrt{2}\,cm[/tex]

[tex]A = (3\sqrt{2}\,cm)^{2}[/tex]

[tex]A = 18\,cm^{2}[/tex]

El área del cuadrado es de 18 centímetros cuadrados.  

He aquí una pregunta relacionada sobre el área del cuadrado: https://brainly.com/question/23915250

Answer: 79

Concept:

Here, we need to understand the idea of evaluation.  

When encountering questions that gave you an expression with variables, then stated: "If x = a, y = b, z = c" (a, b, c are all constants), this means you should substitute the value given for each variable back to the expression.

Solve:

Given information

10x² - 7x + 10

x = 3

Substitute the value into the expression

= 10 (3)² - 7 (3) + 10

Simplify by multiplication

= 10 (9) - 21 + 10

= 90 - 21 + 10

Simplify by subtraction

= 69 + 10

Simplify by addition

= 79

Hope this helps!! :)

Please let me know if you have any questions

Answer:

92

Step-by-step explanation:

The variable 'x' shows up twice in this expression.  Replace each instance of 'x' with 3:

10(3)^2 - 7(3) + 10  =  10(9) - 21 + 19  =  92

Answer:

18

Step-by-step explanation:

RQ = (22+14)/2 = 36/2 = 18

Answer:

QR = 18

Step-by-step explanation:

The midsegment QR is half the sum of the parallel bases, that is

QR = [tex]\frac{JM+KL}{2}[/tex] = [tex]\frac{22+14}{2}[/tex] = [tex]\frac{36}{2}[/tex] = 18

Answer:

C. 7 units

Step-by-step explanation:

The given parameters are;

The length of the chord of the circle, [tex]\overline{AC}[/tex] = 14 units

The orientation of the radius and the chord = The radius is perpendicular to the chord

We have in ΔAOC, [tex]\overline{AO}[/tex] = [tex]\overline{OC}[/tex] = The radius of the circle

[tex]\overline{OB}[/tex] ≅ [tex]\overline{OB}[/tex]  by reflexive property

The angle at point B = 90° by angle formed by the radius which is perpendiclar to the chord [tex]\overline{AC}[/tex]

ΔAOB and ΔCOB are right triangles (triangles having one 90° angle)

[tex]\overline{AO}[/tex] and [tex]\overline{OC}[/tex] are hypotenuse sides of ΔAOB and ΔCOB respectively and [tex]\overline{OB}[/tex] is a leg to ΔAOB and ΔCOB

Therefore;

ΔAOB ≅ ΔCOB, by Hypotenuse Leg rule of congruency

Therefore;

[tex]\overline{AB}[/tex] ≅ [tex]\overline{BC}[/tex] by Congruent Parts of Congruent Triangles are Congruent, CPCTC

[tex]\overline{AB}[/tex] = [tex]\overline{BC}[/tex] by definition of congruency

[tex]\overline{AC}[/tex] = [tex]\overline{AB}[/tex] + [tex]\overline{BC}[/tex] by segment addition postulate

∴ [tex]\overline{AC}[/tex] = [tex]\overline{AB}[/tex] + [tex]\overline{BC}[/tex] =  [tex]\overline{AB}[/tex] + [tex]\overline{AB}[/tex] = 2 ×  [tex]\overline{AB}[/tex]

∴  [tex]\overline{AB}[/tex] = [tex]\overline{AC}[/tex]/2

[tex]\overline{AB}[/tex] = 14/2 = 7

[tex]\overline{AB}[/tex] = 7 units.

Answer:

7 units

Step-by-step explanation:

Answer:

Rhombus, Square, Parallelogram :)

Step-by-step explanation:

I just did this question and I got the three answers above right. I hope this helps!

Answer:

Step-by-step explanation:

This is a geometric means problem. Namely, n is the geometric mean between the 2 smaller triangles within that larger one. Set up the problem accordingly:

[tex]\frac{28}{n}=\frac{n}{7}[/tex] and cross multiply:

[tex]n^2=196[/tex] so

n = 14

Answer:

x = 2

Step-by-step explanation:

Answer:

If Point A (8,4) is reflected over point (6,−2), then that point becomes (4, -8).

Let me know if this helps!