Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Complete this number sentence so that it illustrates the identity property of multiplication? ____ x ____ = 57

Answers

Answer 1

Answer:

57 x 1 =57

Step-by-step explanation:

Please remember identity property of multiplication says

An integer * 1 = the same integer

Using this property

57 x 1 = 57


Related Questions

Which option correctly shows one row of a stem-and-leaf plot that displays this data set? 24,35,10,32,19,26,24,30,17,19,20,35

Answers

Answer:

STEM ___ LEAF

1 _______0_ 7 _ 9 _ 9

2_______0 _ 4 _ 4 _ 6

3_______0 _ 2 _ 5 _ 5

Step-by-step explanation:

Given the ordered version of the data:

10, 17, 19, 19, 20, 24, 24, 26, 30, 32, 35, 35

. The stem is the tens digit and leaf is the unit digit of each data.

STEM ___ LEAF

1 _______0_ 7 _ 9 _ 9

2_______0 _ 4 _ 4 _ 6

3_______0 _ 2 _ 5 _ 5

Since there isn't any option given, then the row could be any of row values above.

If a car is moving on a straight line with a velocity of 40 m/s and it changes its velocity to 60 m/s in 4 seconds, calculate its acceleration.

Answers

Answer:

5m/s²

Step-by-step explanation:

Given :-

Initial Velocity = 40m/s Final velocity = 60 m/sTime = 4s

To Find :-

The acceleration .

Solution :-

We know that the rate of change of velocity is called acceleration. Therefore ,

[tex]\sf\implies a = v - u / t \\ [/tex]

[tex]\sf\implies a = 60m/s - 40m/s/ 4 \\ [/tex]

[tex]\sf\implies a = 20m/s \div 4 \\[/tex]

[tex]\bf\implies a = 5m/s^2[/tex]

Grayson is 1.25 meters tall. At 12 noon, he measures the length of a tree's shadow to be 22.75 meters. He stands 17.6 meters away from the tree, so that the tip of his shadow meets the tip of the tree's shadow . Find the height of the tree to the nearest hundredth of a meter.

Answers

Answer:

5.52m

Step-by-step explanation:

First, we can see that two similar triangles are formed. One similar triangle is the big triangle, with the base being 22.75m and the height being the tree's height. Another triangle is formed with Grayson's height as the height and the and the difference between where he is standing and the edge of the tree's shadow (the red outline in the picture) .  We know that these are similar triangles because both the bases are parallel, as well as the heights and hypotenuses.

The base length for the triangle with Grayson as the height is 22.75-17.6 = 5.15 .

For similar triangles, we know that the ratios between sides are the same. For example, base₁/base₂ = height₁/height₂ . We can apply this here, making 5.15 base₁ and 1.25 height₁ (note that the same triangle's sides should be on top)

If we make the tree's height t, we thus have

5.15/22.75 = 1.25/t (height 2 is the tree's height

multiply both sides by t to remove one denominator

5.15 * t / 22.75 = 1.25

multiply both sides by 22.75 to remove the other denominator

5.15 * t = 1.25 * 22.75

          = 28.4375

divide both sides by 5.15 to isolate the t

t = 5.52m

Which of the following graphs represents the equation y=3x+2? A.Graph B. Graph B C. Graph C D. Graph D

Answers

from process of elimination, it’s graph c

To the nearest square metre, calculate the curved surface area of the half pipe if it is 9m long? (With a radius of 2.5m)

Answers

Answer:

70.686 [tex]m^{2}[/tex]

Step-by-step explanation:

A=2πrh (area of cylinder without top or bottom)

A = 2[tex]\pi[/tex](2.5)(9)

A = 141.372

divide by two for half of pipe.

A = 70.686

Can you help with 7-10

Answers

Answer:

7.Mean=Ex/n

= 88+96+92+84+86+92+98/7

=90

(b). Median = {84,86,88},92,{92,96,98}

=92

(C).Mode=92 ; it is the number with the highest frequency

9.Mean=Ex/n

=28+26+32+24+27+32+29/7

=28

(b).Median={24,26,27},28,{29,32,32}

=28

(c).Mode=32;it is the number with the highest frequency.

8.Mean=Ex/n

=3.5+5.7+9.8+7+12.4+10.2/6

=8.1

(b).Median={3.5,5.7},7,9.8,{10.2,12.4}

=7+9.8/2

=8.4

(c).Mode=no mode

10.Mean=Ex/n

=2+6+9+8+8+2+8+7+5+4/10

=5.9

(b).Median={2,2,4,5},6,7,{8,8,8,9}

=6+7/2

=6.5

(c).Mode= 8;it is the number with the highest frequency.

I hope this helps.

Which of the following quadratic regression equations best fits the data
shown below?
Х
-4
-3
-2
-1
0
1
N
3
4
y
35
20
10
5
00
10
15
30
48
O A. y = 0.98x2 +3.06x+ 6.02
O B. y = 2.23x2 + 1.62x+ 5.26
O c. y = 3.72x2 + 2.94x + 3.21
O D. y = 4.63x2 + 0.84x+ 4.14

Answers

Answer:

C

Step-by-step explanation:

The method that is not used on graphs to lead the reader to misinterpret the graph is - Comparing two sets of related data on the same graph for the sake of comparison.

What is graph?

A graph is a intersection of {x} and {y} axis. On the graph, the coordinate points can be plotted in the form (x, y). In this, {x} represents the horizontal distance along the {x} axis and {y} is the vertical distance along the {y} axis.

Given is to identify the methods that are not used on graphs to lead the reader to misinterpret the graph.

The method that is not used on graphs to lead the reader to misinterpret the graph is - Comparing two sets of related data on the same graph for the sake of comparison.

Therefore, the method that is not used on graphs to lead the reader to misinterpret the graph is - Comparing two sets of related data on the same graph for the sake of comparison.

To solve more questions on graphs, visit the link below-

https://brainly.com/question/17267403

#SPJ7

A claim is reviewed for MOHS surgery on the foot that was performed in 1 stage with 6 tissue blocks. The claim was reported with 17311, 17312-51, 17312-51. Is this correct

Answers

Answer:

17311, 17315  

Step-by-step explanation:

Explanation,

Mohs surgery, also known as chemosurgery, created by a general surgeon, Dr. Frederic E. Mohs, is performed to remove complex or ill-defined cutaneous malignancy.

List Of CPT Codes For Mohs Surgery

CPT Code 17311 and CPT Code 17313 are the base codes for the range of this surgery. CPT Code 17312, CPT Code 17314, and CPT Code 17315 are the add-on codes for this range.

Description Of CPT Code 17311

Moh’s micrographic technique, including removal of all gross tumor, surgical excision to tissue specimens, mapping, color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stain(s) (eg. Hematoxylin and eosin, toluidine blue), head, neck, hands, feet genitalia, or any location with surgery directly involving muscle, cartilage, bone, tendon, major nerves, or vessels; first stage, up to 5 tissue blocks

Description Of CPT Code 17315 (addon)

CPT Code 17315 may be used to report each block after the first 5 blocks for any single-stage.

Moh’s micrographic technique, including removal of all gross tumor, surgical excision of tissue specimens, mapping color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stains(s) (eg. Hematoxylin and eosin, toluidine blue), each additional block after the first 5 tissue blocks, any stage (List separately in addition to code for primary procedure)

Extras

Description Of CPT Code 17312 (addon)

Each additional stage after the first stage, up to 5 tissue blocks (List separately in addition to code for primary procedure)

Description of CPT Code 17313

Moh’s micrographic technique, including removal of all gross tumor, surgical excision of tissue specimens, mapping, color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stains(s) (eg. Hematoxylin and eosin, toluidine blue), of the trunk, arms, or legs; first stage, up to 5 tissue blocks

Description Of CPT Code 17314 (addon)

Each additional stage after the first stage, up to 5 tissue blocks (List separately in addition to code for primary procedure).

a drinks company use 76.8 kg of sugar in April .How much sugar the day use each day?​

Answers

Answer:

2.56 kgs

Step-by-step explanation:

76.8kg ÷ 30 days = 2.56 kgs

SoLuTiOn☞

Amount of sugar used - 76.8 kg

No. Of Days in Month of April - 30 days

∴ Sugar used each day is = 76.8 ÷ 30

[tex]76.8 \div 30 \\ \\ = \frac{76.8}{30} \\ \\ = \frac{768}{30 \times 10} \\ \\ = \frac{ \cancel{768}}{ \cancel{30} \times 10} \fbox{cancelling by 3} \\ \\ = \frac{256}{10 \times 10} \\ \\ = \frac{256}{100} \\ \\ = 2.56 \: kg[/tex]

So 2.56 kg is used everyday.

Hope This Helps You

HELP PLEASE

how do i put this into a piecewise function?

Answers

Answer:

Step-by-step explanation:

2 functions start by making a domain

Function 1: -3≤x<1

Function 2: -1≤x≤1

Now come up with equations

Function 1= x+3

Function 2= 5

Now put it all together

f(x)= x+3 for -3≤x<1 and 5 for -1≤x≤1

someone help me please with this algebra problem

Answers

Answer:

x=44-y

Step-by-step explanation:

In this problem, there are 44 glasses in total. Additionally, we want to know how many ice teas she can have; therefore, we must find x. The problem tells us that when x and y are added together they should equal 44. One way to solve this is to write the equation, x+y=44, because we know it is true and then solve for x. To find x subtract y from both sides. This equals x=44-y, the final answer.

x=44-y
explanation: y is the lemonade, and every time a glass of it is poured it is taking away from the 44 glasses. after the lemonade is poured it leaves x iced tea glasses. you can eliminate half of the answers off the bat because you know you’re looking for iced tea glasses, so whatever equation is there must equal x which elimates option 1 and 3.

Determine the value of x.

8 2
8 3
4
8

Answers

Answer:

Step-by-step explanation:

HELP ME ASAP NO LINKS
Which student's expression results in a quotient of 12.5?
KWAN
VERA
16.25 : 1.3
- 11.25 = (-9)
Mark only one oval.
0000
a. Kwan's only
b. Vera's only
c. Both Kwan and Vera's
d. Neither Kwan nor Vera's

Answers

Answer:

I wanna say its B. Vera's only

It should be B Vera’s only

The table below represents a linear function f(x), and the equation represents a function g(x): X) -1, 0, 1 F(x) -5, -1, 3 G(x)=4x+3

Part A. Write a sentence to compare the slope of the two functions and shows the steps you used to determine the slope of f(x) and g(x)

Part B which functions has greater y-intercept. Justify

Answers

Answer:

(a) g(x) has a greater slope

(b) g(x) has a greater y intercept

Step-by-step explanation:

Given

[tex]x \to -1,0,1[/tex]

[tex]f(x) \to -5,-1,3[/tex]

[tex]g(x) = 4x + 3[/tex]

Solving (a): Compare the slopes

Slope (m) is calculated as:

[tex]m =\frac{y_2 - y_1}{x_2 - x_1}[/tex]

So, for f(x), we have:

[tex]m =\frac{-1- 0}{-5- -1}[/tex]

[tex]m =\frac{-1}{-4}[/tex]

[tex]m =\frac{1}{4}[/tex]

For g(x), we have:

Assume [tex]g(x) = mx + c[/tex] then the slope is m

Compare the above to [tex]g(x) = 4x + 3[/tex]

Then the slope of g(x) is 4

g(x) has a greater slope

Solving (b): Function with greater y intercept

Here we set [tex]x= 0[/tex]

From the table of f(x)

[tex]f(x) = -1[/tex] when [tex]x = 0[/tex]

From [tex]g(x) = 4x + 3[/tex]

[tex]g(0) = 4 * 0 + 3[/tex]

[tex]g(0) = 3[/tex]

Hence:

g(x) has a greater y intercept

What is the common difference between successive terms in the sequence 0.36, 0.26,0.16,0.06,-0.04,-0.14

Answers

Answer:

- 0.1

Step-by-step explanation:

please someone help I know the answer but I don't know how to place it on the scales below. (15 Points)

Answers

Given:

a. 35% of 150 g

b. 113% of $55

To find:

The correct values for the given blanks.

Solution:

a. 35% of 150 g

Here, the percent part is 35% and percent whole is 100%.

35% of 150 g is:

[tex]\dfrac{35}{100}\times 150=52.5[/tex]

So, the number part is 52.5 g and the whole number is 150 g.

Therefore, the percent part is 35%, number part is 52.5 g and the whole number is 150 g.

b. 113% of $55 g

Here, the percent part is 113% and percent whole is 100%.

113% of $55 is:

[tex]\dfrac{113}{100}\times 55=62.15[/tex]

So, the number part is $62.15 and the whole number is $55.

Therefore, the percent part is 113%, number part is $62.15 and the whole number is $55.

-3 raised to the power 0=

Answers

Given:

The statement is "-3 raised to the power 0".

To find:

The value of the given expression.

Solution:

We know that [tex]a[/tex] raised to the power [tex]b[/tex] can be written as [tex]a^b[/tex].

Any non zero number raised to the power 0 is always 1. It means,

[tex]a^0=1[/tex], where [tex]a\neq 0[/tex].

-3 raised to the power 0 [tex]=(-3)^0[/tex]

                                         [tex]=1[/tex]

Therefore, the value of the given statement is 1.

Hi guys can please help me


using a calculator or otherwise evaluate each of the following giving Your answer to two decimal place .

(i) 73.18-5.23×90







Answers

Answer: 26.11

Step-by-step explanation:

73.18 - 5.23 × 90 = 73.18 - 47.07 = 26.11

question is in the pucture

Answers

Answer:

Aiden earned less money for his 8th than he earned for his 4th drive.

[tex]ANSWER:C[/tex]

-------------------------------

HOPE IT HELPS

HAVE A GREAT DAY!!

A discount site decreases the price of cell phones by . Select the two expressions that represent the discounted price of a phone costing dollars.
A
0.40ddd
B
0.60ddd
C
d−d-d−0.60
D
d−d-d−0.60ddd
E
1−-−0.60ddd

Answers

The percentage discount given on the prove is not supplied ; Assume the percentage discount given on the phone is 60%

Answer:

0.4d

d - 0.6d

Step-by-step explanation:

Given that :

Percentage Discount given on phone = 60%

The discounted pice :

Initial percentage = 100%

Discount percentage = 60%

(100% - 60%) of price

(100% - 60%) * d

40%*d

0.4d

Also ;

(100% - 60%) * d

100%*d - 60%d

d - 0.6d

what is the quotient of 3/4 ÷ 5/12​

Answers

Answer:

1  4/5

Step-by-step explanation:

3/4 ÷ 5 /12

Copy dot flip

3/4 * 12/5

Rewriting

3/5 * 12/4

3/5 * 3

9/5

1 4/5

Multiply the following rational expressions and simplify the result

Answers

Answer:

Step-by-step explanation:

We have to solve the given expression,

[tex]\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}[/tex]

[tex]\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}[/tex] = [tex]\frac{-y(-9+33y+3y^3)}{100-49y^2}.\frac{7y^2+17y+10}{14y(y+2)}[/tex]

                                   = [tex]\frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{7y^2+10y+7y+10}{14y(y+2)}[/tex]

                                   = [tex]\frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{y(7y+10)+1(7y+10)}{14y(y+2)}[/tex]

                                   = [tex]\frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{(y+1)(7y+10)}{14y(y+2)}[/tex]

                                   = [tex]\frac{-3y(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14y(y+2)}[/tex]

                                   = [tex]\frac{-3(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14(y+2)}[/tex]

                                   = [tex]\frac{3(3-11y-y^3)(y+1)}{(10-7y)(14(y+2)}[/tex]

In a triangle ABC, b=13cm c=17cm A=86 degree. Find B,C and a​

Answers

Step-by-step explanation:

went to a calculator

it said

Side a = 20.66803

Side b = 13

Side c = 17

Angle ∠A = 86°

Angle ∠B = 38.863°

Angle ∠C = 55.137°

can you help me do this Question if you can?

Answers

Answer:

A

Step-by-step explanation:

given g(x) = square root of x - 4 and h(x) = 2x - 8 What is g(h10))?

Answers

Step-by-step explanation:

First find h(10)

h(10)=2(10)-8

h(10)=12

Now plug in 12 as the value of x in g(x) ie.g(12)

So g(12)=√12-4=√8=2√2

what is the maximum value of y=-x^2-x+6 ?

Answers

Answer:

[tex]{ \tt{y = - {x}^{2} - x + 6 }} \\ { \tt{ \frac{dy}{dx} = - 2x - 1}} \\ f {}^{'} (x) = - 2x - 1 \\ f {}^{'}(1) = - 2 - 1 \\ = - 3 [/tex]

solve for
 (6x + 9)/3 =​

Answers

Hello!

(6x + 9)/3 =

= 3(2x + 3)/3 =

= 2x + 3

Good luck! :)

What is the value of this exspession when c=-4 and d=-10 1/4(c^3+d^2)

Answers

Answer:

2

Step-by-step explanation:

1/4(-4×3 + 10×2)

1/4(-12 + 20)

THERE ARE 2 WAYS YOU COULD SOLVE THIS!

1. 1/4( -12) + 1/4( 20) = -3 + 5 = 2

2. 1/4 ( -12+20) = 1/4(8) = 2

Answer:

[tex]9[/tex]

Step-by-step explanation:

Given:-

Expression:  [tex]\frac{1}{4} (c^3+d^2)[/tex]

Value of c = [tex]-4[/tex]

Value of d = [tex]-10[/tex]

Solution:-

Add the given values in the expression, writing them inside the bracket:

[tex]\frac{1}{4} ((-4)^3+(-10)^2)[/tex]

[tex](\frac{1}{4}) ((-4)^3)+(\frac{1}{4} )((-10)^2)[/tex]

[tex]-16+25[/tex]

[tex]9[/tex]

Maths Aryabhatta

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Solve the following pair of linear equations using substitution method :-

2x+3y + 5 = 0 ; 5x-3y+9=0​

Answers

Answer:

(- 2, - [tex]\frac{1}{3}[/tex] )

Step-by-step explanation:

Given the 2 equations

2x + 3y + 5 = 0 → (1)

5x - 3y + 9 = 0 → (2)

Rearrange (1) expressing 3y in terms of x by subtracting 2x + 5 from both sides

3y = - 2x - 5

Substitute 3y = - 2x - 5 into (2)

5x - (- 2x - 5) + 9 = 0 ← distribute parenthesis on left side and simplify

5x + 2x + 5 + 9 = 0

7x + 14 = 0 ( subtract 14 from both sides )

7x = - 14 ( divide both sides by 7 )

x = - 2

Substitute x = - 2 into either of the 2 equations and solve for y

Substituting into (1)

2(- 2) + 3y + 5 = 0

- 4 + 3y + 5 = 0

1 + 3y = 0 ( subtract 1 from both sides )

3y = - 1 ( divide both sides by 3 )

y = - [tex]\frac{1}{3}[/tex]

solution is (- 2, - [tex]\frac{1}{3}[/tex] )

the lateral surface area of right circular cylinder is 120 pi cm squared and the circumference is 12 cm find the height ​

Answers

Answer:

h=31.4 cm

Step-by-step explanation:

A=lateral surface area

c=circumference

h=height

A= c*h

solving for h we get:

h=A/c=120pi/12=10pi

Answer : h= 31.4cm
Y
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R
R
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